a hallow steel tube 3.5m long has external diameter of 120mm. in order to determine the internal diameter the tube was subjected to a tensile load of 400KN and extension was measured to be 2 mm. if the modulus of elasticity for the tube material is 200 GPa. determine the internal diameter of the tube.​

The basic characteristic of the taxi service is that some taxi services are as extensive in range as either urban mass transit or commercial airlines.

A taxi is a cab that one hired b a single person or a group and they have a nonshared ride. The taxi service is found in various international destinations all over the world and especially at the airports, restaurants and hotels. Some place's taxi services are extensive and include the urban transits.

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Answer:

1700 kg

Explanation:

Determine the total mass of the oil, m, by multiplying the density,

p= 850 kg/m3

to the volume, V = 2m3 or m=p x v.

m=pxv.

m= p x v = 850 kg / m3 x 2

m3 = 1700 kg

check all the photos

Answer:

resistance = 2.52 ohms

Explanation:

from the formula

V =IR

Voltage = (current)(resistance)

Resistance =

R=

R= 2.52 ohms

Answer:

voltage

Explanation:

because it is used with a moving pointer to display readings.

this looks like its the different phases of a single cylinder 4 stroke engine what are you doing in the picture or assignment though matching the numbers to the descriptions on the side?

Answer:

Amends the FMVSS on air brake systems to improve the stopping distance performance of truck tractors. The rule requires the vast majority of new heavy truck tractors to achieve a 30 percent reduction in stopping distance compared to currently required levels. For these heavy truck tractors (approximately 99 percent of the fleet), the amended standard requires those vehicles to stop in not more than 250 feet when loaded to their gross vehicle weight rating (GVWR) and tested at a speed of 60 miles per hour (mph). For a small number of very heavy severe service tractors, the stopping distance requirement will be 310 feet under these same conditions. In addition, this final rule requires that all heavy truck tractors must stop within 235 feet when loaded to their “lightly loaded vehicle weight” (LLVW).

Amends the FMVSS on air brake systems to improve the stopping distance performance of truck tractors. The rule requires the vast majority of new heavy truck tractors to achieve a 30 percent reduction in stopping distance compared to currently required levels. For these heavy truck tractors (approximately 99 percent of the fleet), the amended standard requires those vehicles to stop in not more than 250 feet when loaded to their gross vehicle weight rating (GVWR) and tested at a speed of 60 miles per hour (mph). For a small number of very heavy severe service tractors, the stopping distance requirement will be 310 feet under these same conditions. In addition, this final rule requires that all heavy truck tractors must stop within 235 feet when loaded to their “lightly loaded vehicle weight” (LLVW).

Answer:

power window controls

Explanation:

Answer:

  Quantity B is greater.

Explanation:

Given:

  (x -2y)(x +2y) = 4

  A = x² -4y²

  B = 8

Find:

  the relationship between A and B

Solution:

The given expression can be expanded to give ...

  x(x +2y) -2y(x +2y) = x² +2xy -2xy -4y² = x² -4y²

This is precisely the expression designated as A. Its value is 4.

  4 < 8

  A < B

Quantity B is greater.

Answer:

Engine bearings are lubricated by motor oils constantly supplied in sufficient amounts to the bearings surfaces. Lubricated friction is characterized by the presence of a thin film of the pressurized lubricant

Explanation:

Answer:

Alvaro designs machinery and equipment for ships. His job title is best described as Marine Engineer.

Jeanette draws maps and plans for freeway projects. Her job title is best described as Civil Drafter.

Joseph designs a new airport. His job title is best described as Transportation Engineer.

Geraldine designs imaging systems that use light. Her job title is best described as Photonics Engineer.

Hope this helps sorry I am late to respond, but anyone else who needs the answer it is here.

Based on the above, Alvaro is a Marine Engineer;

Machinery and Equipment are known to be a type of industrial tools, devices, and items that aids facilities.

Conclusively, They are said to be tangible personal property that are used as a tool for repair parts, etc. Professions in ship jobs includes, Marine Engineer, Photonics Engineer, etc.

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Explanation:

This means that for every 1 cm on the drawing, there is 80 cm in reality. To put it another way, take this

1:80 means that the building is 80 times the size of the drawing

80:1 means that the drawing is 80 times the size of the building

If it were 80:1, the drawing itself would be over 100m long.

analyzing building materials???????????? but i can try i think it is analyzing the materials of the building

Answer:

a) 62460 kg/hr

(b) 17,572.95 kW

(c) 3,814.57 kW

Explanation:

Explanation:

is an example of an electrical device.

Cable

Answer:

This is not a clear indication of the hot zone as the information of the radioactivity of the background is not provided clearly.

Explanation:

According to IAEA as well as NRCP, the hot area is defined on the basis of the radioactivity reading it shows instead of contrast or comparative reading from the background. The value of radiation activity which will be required to declare an area as hot zone is if it is greater than 0.1 mSv/h or [tex]1.5091\times 10^{29} kg^{-1} s^{-1}[/tex].

Answer:

I am not sure it's confusing

Answer:

volunteer coordinator

Explanation:

because they are volunteering for that and in most of the cases they do not expect to be paid

RAM is called “random access” because any storage location on the computer can be accessed directly (as opposed to randomly).

Answer: A small block A is placed on the disk in its lowest position P at a distance r from the axis when the disk is at rest. The angular velocity

Explanation:

check photo (answer)

The angular velocity of the water bath as the crank is driven clockwise is 6.66rpm/ms.

From the complete information, we are to use the relative velocity method to determine the angular velocity of the water bath.

This will be:

60/V = 1085.4/120.58

Cross multiply.

(1085.4 × V) = (120.58 × 60)

V = (120.58 × 60/1085.4)

V = 6.66rpm/ms

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#SPJ2

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

[tex]A_1 \ and \ A_2[/tex]

Thus, using the summation rule, the view factor [tex]F_{11[/tex] and [tex]F_{12[/tex] is as follows:

[tex]F_{11}+F_{12}=1[/tex]

Let assume the surface (1) is flat, the [tex]F_{11} = 0[/tex]

Now:

[tex]0+F_{12}=1[/tex]

[tex]F_{12}=1[/tex]

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder [tex]A_2[/tex] to the flat base surface [tex]A_1[/tex]; we have:

[tex]A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}[/tex]

Suppose, we replace DL for [tex]A_1[/tex] and

[tex]A_2[/tex] =  [tex]\dfrac{\pi D}{2}[/tex]

Then:

[tex]F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\ =\dfrac{2}{\pi} \\ \\ =0.64[/tex]

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

[tex]Q_{21} = Q_{evaporation}[/tex]

But, before that;  let's find the radian heat exchange occurring among the dome and the flat base surface:

[tex]Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)[/tex]

where;

[tex]\sigma = Stefan \ Boltzmann's \ constant[/tex]

[tex]T_1 = base \ temperature[/tex]

[tex]T_2 = temperature \ of \ the \ dome[/tex]

∴

[tex]Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m[/tex]

Recall the energy balance formula;

[tex]Q_{21} = Q_{evaporation}[/tex]

where;

[tex]Q_{evaporation} = mh_{fg}[/tex]

here;

[tex]h_{fg}[/tex] = enthalpy of vaporization

m = the water mass flow rate

∴

[tex]83899.15 = m \times 2257 \times 10^3 \\ \\ m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}[/tex]

The drying rate per unit length is 0.037 kg/S.m

Given data;

From the attached diagram, the surface 1 is flat, it is a view factor, f[tex]_1_1[/tex] = 0.

Applying summation rule and solving the view factor from the base surface A[tex]_1[/tex] to the cylindrical dome A[tex]_2[/tex].

[tex]f_1_1+f_1_2=1[/tex]

Put F[tex]_1_2=0[/tex]

[tex]0+f_1_2=1[/tex]

This makes [tex]f_1_2=1[/tex]

Applying reciprocal rule and solving the view factor from the cylindrical dome A[tex]_2[/tex] to the base surface A[tex]_1[/tex].

[tex]A_2F_2_1=A_1F_1_2\\F_2_1=(\frac{A_1}{A_2})F_1_2[/tex]

Where A is the area of the surface.

Substitute DL for A[tex]_1[/tex] and [tex]\frac{\pi D}{2}[/tex] for A[tex]_2[/tex]

[tex]F_2_1 = \frac{DL}{(\frac{\pi D}{2}})L *1 = \frac{2 }{\pi } =2/3.14 = 0.64[/tex]

Using the energy balance equation to the dryer,

[tex]Q_2_1=Q_e_v_a_p[/tex]

Let's calculate the radiation heat exchange between the dome and the base surface per unit length by using the equation below

[tex]Q_2_1=F_2_1A_2[/tex]δ[tex](T_2^4-T_1^4)[/tex]

[tex]Q_2_1= F_2_1 * \frac{\pi D}{2}[/tex]δ[tex](T_2^4-T_1^4)[/tex]

substitute the respective values into the equation

[tex]Q_2_1=0.64*(\frac{\pi }{2}*1.5)*5.67*10^-^8*(1000^4-370^4)\\Q_2_1=8.3899.15W/m[/tex]

Let's calculate the mass flow rate of water using the amount of heat required for drying up.

[tex]Q_2_1=Q_e_v_a_p\\Q_e_v_a_p=mh_f_g\\[/tex]

where [tex]h_f_g= 2257*10^3J/kg[/tex]

and this is the enthalpy of vaporization and mass flow rate of water.

[tex]83899.15=m*2257*10^3\\m=0.037kg/S.m[/tex]

The drying rate per unit length is 0.037kg/S.m

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I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.

Now hear me out: Steel-Coated Coconuts

If you want to make a coconut harder you can take that shell up to heights its natural husk never even knew it could reach! Combining the raw, brown scraglley-ness with the tough, durable properties of steel would most definitely make a coconut harder.

Valid answer? Probably not.

Thank you for coming to TedTalk :))

Answer:

medium sized ears

Explanation:

Answer:

A jackhammer.

Explanation:

A jackhammer is a pneumatic device that was invented by William Mcreavy. Later, Mcreavy sold the patent of jackhammer to Charles Brady King. The tool is a combination of chisel and hammer.  The tool is powered by compressed air to tighten or loosen an object. By using pressurized air, jackhammers help workers to drill and lossen an object.

Therefore, option A is correct.

Answer:

Impact Driver

Explanation:

An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

[tex]V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3[/tex]

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

[tex]C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}[/tex]

At the minimum value, we have;

Which gives;

16·π·r³ = 6·V

Which gives;

[tex]h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r[/tex]

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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