a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W

The correct answer is 600 ampere-turns

We shall first get the expression that provides the magnetomotive force. It is calculated by multiplying the number of spins on the wire by the current flowing through it. To get the solution, we shall alter and substitute the necessary values.

It is crucial to keep in mind that magnetomotive force (mmf), which is similar to electromotive force (emf), drives a current of electrical charge through magnetic circuits. The phrase "magnetomotive force" is deceptive, though, as it neither denotes a force nor something that moves.

M.M.F = NI

N= 50

I = 12 at a current of 1 ampere

M.M.F = NI

= 50 × 12

=600 ampere-turns

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Answer: Lungs

Explanation:

The distance covered is 56 m.

We define acceleration as the rate at which the velocity changes with time. We can find the position of the bus by the use of the equations of kinematics.

Using the equation;

s = ut + 1/2at^2

u = initial velocity

a = acceleration

t = time taken

Since the bus started from rest u = 0 m/s

s = 1/2at^2

s = 0.5 * 2 * (7.5)^2

s = 56 m

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We know that Formula to calculate Pressure is Pressure = Force/Area.

                                        => Force = 100000000 N

                                      => Pressure = 48000 Pascal

                                     => F = 0.0063 N

                                    => P = 500000000 Pa

               Area = 400/20000   => Area = 0.02 m²

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Answer:

20000J or 20kJ

Explanation:

Given parameters:

Efficiency of the battery = 80%

Amount of energy transferred  = 16000J

Unknown:

How much energy was transferred to the battery = ?

Solution:

Since the battery is 80% efficient, it loses 20% of energy anytime it wants to store energy.

 Now, 16000J of energy is contained in the battery, the original amount of energy sent to the battery;

   Let the amount of energy sent to the battery be y

  80% of y  = 16000

       0.8y  = 16000

            y  = 20000J or 20kJ

Answer:

q(ice) = -q(warm water)

Explanation:

Ice removes energy if ice is put in warm water and ice retains the very same amount of energy. Thus the water temperature heat sign is negative, and the ice heat sign is positive.

Answer:

because some waste heat is always produced produced in a heat engine.

Explanation:

the fraction of heat input that is converted to a net work output is a measure of the performance of the heat engine and is called the thermal efficiency.Since the machine does not contain a source of energy ,nor can it store energy ,from this conversation of energy the power output of machine can never be greater than its input,so efficiency can be less than 100%.

Explanation:

The efficiency of heat engine is always less than 100% most of the times because of waste energy in form of heat.

Answer:

[tex]F=10\ N[/tex]

Explanation:

[tex]We\ are\ given\ that,\\Mass\ of\ the\ bowling\ bowl=5\ kg\\Acceleration\ of\ the\ ball=2\ m/s^2\\Hence,\\As\ we\ know\ that\ F=ma\\Here,\\Force\ of\ the\ bowling\ ball\ when\ it\ hits\ the\ pins=Mass\ of\ the\ bowling\ bowl* its\ Acceleration.\\Hence,\\F=5*2\\F=10\ Newtons\\[/tex]

Answer: the cyclist traveling at 12.96 m/s

Explanation:

Given that;

diameter = 0.59 m

radius = 0.295 m

the wheel makes 7 rotations in a second,

in every rotation, it travels a distance of 2πr

so

total distance

= 7 × 2πr

= 7 × 2 × 3.14 × 0.295

= 12.96 m

Therefore velocity = 12.96 m/s

so the cyclist traveling at 12.96 m/s

Answer:

Acceleration = Δv/t

Acceleration = (8 m/s - 0 m/s)/ 3 s

Acceleration = 8 m/s / 3s

Acceleration = 2.667 m/s²

Explanation:

Answer:

c 2.67

Explanation:

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

Answer:

Using, s=ut+

2

1

at

2

s

1

=u+

2

1

a

or, 3=u+

2

a

∴a=6−2u

s

2

=2u+

2

1

a×4

8=2u+2a

Solving the equations

8=2u+2(6−2u)

8=2u+12−4u

2u=4

u=2m/s

∴a=6−2u=6−4=2m/s

2

Answer:

true

Explanation:

noble gases are octet meaning they they have eight electrons in their outer shell so the are stable

Answer:

The value is  [tex]S_a = 72.56 \ dB[/tex]

Explanation:

From the question we are told that

     The sound level is  [tex]S = 60 dB[/tex]

     The distance from the source is d = 1 m  

     The number of sources  is  n =  18

Generally the sound which the person is been exposed to is mathematically represented as

            [tex]S_a = S + 10log(18)[/tex]

=>         [tex]S_a = 60 + 10log(18)[/tex]

=>         [tex]S_a = 72.56 \ dB[/tex]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]

Hence the force constant of the spring is 17.71N/m

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Answer:

The number of crate to be lifted is 27

Explanation:

Given;

mass of the crates, m = 25 kg

height in which the crate is lifted, h = 1.0 m

power output, P = 110 W

time to complete the task, t = 1 minutes = 60 s

The input energy is equal to the gravitational energy due to height the crate is lifted is given as;

E(input) = mgh

E(input)  = 25 x 9.8 x 1

E(input)  = 245 J

Output energy is given as;

E(output) = P x t

E(output) = 110 x 60

E(output) = 6600 J

Let the number of crate to be lifted = n

n x E(input)  = E(output)

n x 245 = 6600

n = 6600 / 245

n = 27 crates

Answer:

 In space, it is possible to create "artificial gravity" by spinning your spacecraft or space station

The distance between the cities along the route is 87.95 Km

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 82.1 × (30.1 / 60)

Distance = 41.19 Km

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 83.1 × (9.11 / 60)

Distance = 12.62 Km

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 41.3 × (49.6 / 60)

Distance = 34.14 Km

Total distance = 41.19 + 12.62 + 34.14

Total distance = 87.95 Km

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Answer:

The increase in pressure inside the lungs is 0.09 atm

Explanation:

From the Pressure law

Pressure law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature provided that the volume remains constant.

That is,

P ∝ T

Where P is the Pressure and T is the temperature.

Then, we can write that

P = kT

Where k is the proportionality constant

∴ [tex]\frac{P}{T} = k[/tex]

Then,

[tex]\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }[/tex]

From the question, [tex]P_{1}[/tex] = 1.0 atm

[tex]{T_{1}[/tex] = 12 °C = (12 + 273.15) K = 285.15K

[tex]{T_{2}[/tex] = 37 °C = (37 + 273.15) K = 310.15K

Therefore,

[tex]\frac{1.0}{285.15} = \frac{P_{2} }{310.15}[/tex]

[tex]P_{2} = \frac{1.0 \times 310.15}{285.15}[/tex]

[tex]P_{2} = 1.09[/tex] atm

Increase in pressure = [tex]P_{2} - P_{1}[/tex] = 1.09 atm - 1.0 atm

Increase in pressure = 0.09 atm

Hence, the increase in pressure inside the lungs is 0.09 atm

At constant volume, pressure of the gas is directly proportional to the temperature of the gas. The increased pressure inside the lungs is 0.9 atm.

From Gas law,

[tex]\bold {\dfrac {P_1} {T_1 } = \dfrac {P_2} {T_2 } }[/tex]

Where,

P1 - initial pressure = 0.1 atm

P2 - final pressure = ?

T1 - initial temperature = 12 °C = (12 + 273.15) K = 285.15 K

T2 - final temperature = 37 °C = (37 + 273.15) K = 310.15 K

Put the values in the formula,

[tex]\bold {\dfrac {1.0} {285.15 } = \dfrac {P_2} {310.15 } }[/tex]

[tex]\bold {P_2 = 1.09\ atm}[/tex]

Thus, increased pressure in the lungs

= 1.9 - 1.0

= 0.9 atm

Therefore, the increased pressure inside the lungs is 0.9 atm.

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Answer:

14.69

Explanation:

The circle of radius R = 11.0m

Force f = 3 times her Weight

= 3W = 3mg

Then the net force acting on her

F = W + F(centripetal)

= mg + mv²/r

= Mg + mv²/r = 3mg

Then her speed is going to be

V = √2gr

Where g =9.81m/s²

R = 11.0

When we put these values into the formula we get:

V = √2x9.81x11.0

V = √215.82

V = 14.69

Answer:

d is answer because w to between 10 to plus 10 more answers d

Answer:

for 10 some advantages are that it has a much better bandwidth,low power loss, and it allows for longer transmission distance.

Answer:

As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.

Explanation:

Answer: The main cause of sea floor spreading are the directions and force of the moving tectonic plates.

Explanation:

[tex]acslerishne[/tex]

Answer:

38.5

Explanation:

Answer:

You would have to do four times the work W₁ to make the box go the same distance in half the time.

Explanation:

By definition work is:

[tex] W = F*d [/tex]    (1)

Where:

F: is the force and d: is the distance

On the other hand, the force is given by:              

[tex] F = ma [/tex]    (2)

By entering equation (2) into (1):

[tex] W = F*d = m*a*d [/tex]     (3)  

Also, we can express the acceleration in terms of distance and time by using the following kinematic equation:

[tex] d_{f} = d_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]    (4)

Where:

[tex]d_{f}[/tex]: is the final distance

[tex]d_{0}[/tex]: is the initial distance = 0

[tex]v_{0}[/tex]: is the initial speed = 0 (the box starts at rest)

t: is the time  

[tex] d_{f} = \frac{1}{2}at^{2} [/tex]  

Solving for a:

[tex] a = \frac{2d_{f}}{t^{2}} [/tex]   (5)  

Initially we have:

t = T₁, W = W₁, [tex]d_{f}[/tex] = d      

[tex] a_{1} = \frac{2d}{T_{1}^{2}} [/tex]

[tex] W_{1} = m*a_{1}*d = m*d*\frac{2d}{T_{1}^{2}} = 2m(\frac{d}{T_{1}})^{2} [/tex]

And when the box goes the same distance in half the time:

[tex] t = \frac{T_{1}}{2} [/tex]    

The acceleration is (from equation 5):

[tex]a_{2} = \frac{2d_{f}}{t^{2}} = \frac{2d}{(\frac{T_{1}}{2})^{2}} = \frac{8d}{T_{1}^{2}}[/tex]    (6)        

Finally, the work W₂ in terms of W₁ is:

[tex]W_{2} = m*a_{2}*d = m*d*\frac{8d}{T_{1}^{2}} = 8m(\frac{d}{T_{1}})^{2} = 4*[2m(\frac{d}{T_{1}})^{2}] = 4W_{1}[/tex]    

Therefore, you would have to do four times the work W₁ to make the box go the same distance in half the time.

I hope it helps you!    

Finding average speed distance

avg = distance/time

time1 – 30 ml + 30 ml

240 s60 m240 s= 0.25m/s

The correct answer is:

• average velocity = 0 m/s

• average speed = 0.25 m/s

The pace at which an object's direction changes as it is traveling is referred to as its velocity and is measured by a particular unit of time and from a particular point of view.

Greta returns to his house after realizing she forgot her tea 30 meters from her pickup. Her journey takes 240 seconds in all.

Avg = distance/time time for calculating average speed distance

1 - 30 ml + 30 ml

240 s60 m

240 s= 0.25m/s

The right response is:

• Average speed: 0 m/s

• The typical speed is 0.25 m/s

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Given :

A copper rod has a length of 1.7 m and a cross-sectional area of [tex]3.2 \times 10^{-4} \ m^2[/tex].

One end of the rod is in contact with boiling water and the other with a mixture of ice and water.

To Find :

The mass of ice per second that melts.

Solution :

Amount of heat transfer from boiling water to ice through the copper bar is :

[tex]Q = \dfrac{kA\Delta T }{L}\\\\Q = \dfrac{390\times 3.2 \times 10^{-4} \times 100}{1.7}\\\\Q = 7.34 \ J/s[/tex]

Let, amount of ice melts per second is :

[tex]m=\dfrac{Q}{L_f}[/tex]

Here, [tex]L_f[/tex] is the latent of fusion of water and is equal to [tex]L_f = 3.34\times 10^5 \ J/s[/tex].

Putting all values in above equation, we get :

[tex]m=\dfrac{7.34}{3.34\times 10^5}\\\\m = 2.19 \times 10^{-5} \ kg/s[/tex]

Hence, this is the required solution.

The altitude of the triangle is 10.1 m.

We can see that the triangle is a right angled triangle as we can see in the image. The altitude of the triangle is the highest point of the triangle. Let us label the angles A B C

C = 50 degrees

B = 90 degrees

A = 180 - (90 + 50) = 40 degrees

Then;

tan 40 = altitude/ 12 m

altitude = tan 40 degrees * 12 m

= 10.1 m

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