A group of students formed a circle during a game. The circumference of the circle was about 50.24 feet, and the diameter of the circle was 16 feet. Which expression best represents the value of π?

Answer:

What type of question is this

Answer:

The area of a rectangle is given by A = l × w, where l is the length and w is the width.

The length (l) and width (w) of the small rectangle are 14 feet and 6 feet, respectively, so the area of the small rectangle (As) is:

AS  =  14 ft. × 6 ft.

= 84 sq. ft.

The length (l) and width (w) of the large rectangle are 20 feet and 7 feet, respectively, so the area of the large rectangle (Al) is:

Al  =  20 ft. × 7 ft.

= 140 sq. ft.

The area of a triangle is given by , where b is the base and h is the height of the triangle.

The base and height of the triangle both measure 6 feet, so the area of the triangle (At) is:

   ft.  ft.

  sq. ft.

  sq. ft.

Step-by-step explanation:

The area of a trapezium with the given dimensions is: 198 cm²

Area of a trapezium = 1/2(a + b)h, where h is the heght of the trapezium and a and b are the length of its bases.

Given the following:

Area of a trapezium = 1/2(12 + 21)12

Area of a trapezium = 198 cm²

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Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

It is defined as the interest on the principal value or deposit and the interest which is gained on the principal value in the previous year.

We have:

Principal amount(Loan principal) = $10,675

Interest rate  = 4.75 %

Monthly rate = 4.75/12% ⇒0.39583% ⇒ 0.00395

Additional amount she paid in service charge = $939.25

Number of months = 9×12 = 108 months

We can find the total finance charge as follows:

Finance charge = Total amount repaid +service charge - Loan principal

The formula for the monthly payment of the loan is given by:

[tex]\rm Monthly \ payment = \frac{Loan \ principal }{\frac{(1-(1+r)^-^n)}{r} }[/tex]

[tex]\rm Monthly \ payment = \frac{10675}{\frac{(1-(1+0.00395)^-^{108})}{0.00395} }[/tex]    

After calculating, we get:

Monthly payment = $121.66

For 108 months, Tamora paid:

= 121.66×108

= $13,139.23

The finance charge will be:

= $13,139.23+$939.25-$10,675

= $3,403.53

Thus, Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

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Answer:

Step-by-step explanation:

1 is in the tenth place

[tex]\sf 1's \ value = \dfrac{1}{10}[/tex]

Answer:

Step-by-step explanation:

I think the answer is 0-1, but i will have to see the answers to determine.

Hope it helps!

Answer: 32c-1 is one of them

Step-by-step explanation:

Answer:

Step-by-step explanation:

The graph shown is the second derivative

   ⇒ first derivative equals the area between

          - the second derivative function from 0 to 2

          - the axis

Thus the first derivative f(2) equals [tex]8 + c[/tex]

However there is an inital position for the first derivative ⇒ f(0) = 2.5

Therefore we must add the initial position to the first derivative found

  f(2) = 8 + 2.5 = 10.5

Hope that helps!

Answer:

2.13

Step-by-step explanation:

cos 62⁰=10/x=0.47

x=10/0.47≈2.13

Answer:

If it is x squrared the answer would be (x+3)²+5. If it is 2 times x then it would be (2x+3)+5

Step-by-step explanation:

By using Pythagoras theorem.

Therefore ML= 17...

Step-by-step explanation:

Hope it helps....Mark me brilliant

The value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

The standard form of the quadratic equation is,

[tex]ax^2+bx+c=0[/tex]

The quadratic equation has two real number solutions when the value of the following equation is positive.

[tex]b^2-4ac[/tex]

The quadratic equation given in the problem is,

[tex]x^2 +bx+ 5 = 0[/tex]

The value of b has to be found out such that the equation have two real number solutions. For this equation,

[tex]a=1\\c=5[/tex]

Put this value in the above equation as,

[tex]b^2-4\times1\times5\\b^2-20[/tex]

The value of the above expression to be positive, the value of b should be at least 5 or -5.

[tex](-5)^2-20\\25-20\\5[/tex]

Thus, the value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

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Answer:

Which value of [tex]b[/tex] will cause the quadratic equation [tex]x^2 + bx + 5 = 0[/tex] to have two real number solutions?

B) -3

C) 3

D) 4

There one Thing That would got to 0 so it A) -5

Have a Nice Day .

Answer:

the patters is that they are multiple of 7.. so next number is 42.

which means option D The missing number is even is correct..

Answer:

$52.5

Step-by-step explanation:

Since 25% is the sale, we subtract 100% (the whole) by the discount, 25%. That leads us to say that we are paying for 75% of the product's price.

We multiply $70 by 0.75 and you get $52.5!

Please mark brainiest if this helped you!

Answer:

23.5

Step-by-step explanation:

So this is a parallelogram so the area formlula is b*h=47? That's a no go. It is saying that if the base is 1/4th and the height is increasing by 2 so basically 1/4b*2h=1/2bh bh so it will be represented as 47 so 1/2*47=23.5

Answer:

4(5+8)

Step-by-step explanation:

The GCF of 20 and 32 is 4. Then you divide 20 and 34 by 4.

Area of the figure is 171 cm²

See the attachment......

Area of triangle:-

Area of square:-

Area of rectangle:

Total:-

Answer:

Step-by-step explanation:

(i) a^a + b^b

for a=3 and b= -2

3^3 + -2^(-2)

          -2^(-2) = -(1/2^2)

3^3  -(1/2^2)

27 - (1/4)

26 3/4

ii) a^b + b^a

a^b + b^a

for a=3 and b= -2

3^(-2) + (-2)^3

1/3^2 + (-2)(-2)(-2)

1/9 - 8

-7 8/9

Answer:

22 vegetables

Step-by-step explanation:

Set the #number of molded vegatables in dumpster 1 as X

The number of molded vegetables in 2 is x + 45 and the number of molded vegies in 3 is x + 45 + 80

x + x + 45 + x + 45 + 80 = 236 (combine similar terms)

         Thats 3x = 66

Which equas 22

Answer:

its A

Step-by-step explanation:

8-3=5 and 9/10-4/10=5/10=1/2

Answer:

A. 5 1/2

Step-by-step explanation:

[tex]8\frac{9}{10}-3\frac{4}{10}\\\text{Convert the mixed numbers into improper fractions.}\\(\frac{80}{10}+\frac{9}{10})-(\frac{30}{10}+\frac{4}{10})\\\text{Combine the fractions.}\\\frac{89}{10}-\frac{34}{10}\\\text{Since the denominators are the same, simply subtract the numerators.}\\\frac{89-34}{10}\\\frac{55}{10}\\\text{Split the fraction into two so one part becomes a whole number.}\\\frac{50}{10}+\frac{5}{10}\\\text{Evaluate 50 over 10.}\\5+\frac{5}{10}\\\text{Simplify the fraction 5/10.}\\[/tex]

[tex]5+\frac{5/5}{10/5}\\5+\frac{1}{2}\\\text{Combine the mixed number.}\\5\frac{1}{2}[/tex]

Answer:

seek god

Step-by-step explanation:

dang maybe the 2nd one

Answer:

Emmanuel will need 8 scoops to get 2 tablespoons

you need 12 1/2 tablespoons for 6 tablespoons

Step-by-step explanation:

Answer:

1.

r = 12 m.

d = 24 m.

circumference: 75.36 m² or 24π m²

2.

r = 10 cm.

d = 20 cm.

circumference: 62.8 cm² or 20π cm²

3.

r = 4 dm.

d = 24 dm.

circumference: 25.12 dm² or 8π dm²

Step-by-step explanation:

Substitute the the values of the table into the formula:

1.

r = 12 m.

d = 24 m.

circumference: 75.36 m² or 24π m²

2πr

2 * 3.14 * 12

3.14 * 24

75.36 m² or 24π m² <== circumference

12 * 2 = 24 m <== diameter

2.

r = 10 cm.

d = 20 cm.

circumference: 62.8 cm² or 20π cm²

r = 20/2 = 10 cm <== radius

2πr

2 * 3.14 * 10

3.14 * 20

62.8 cm² or 20π cm² <== circumference

3.

r = 4 dm.

d = 24 dm.

circumference: 25.12 dm² or 8π dm²

2πr

2 * 3.14 * 4

3.14 * 8

25.12 dm² or 8π dm² <== circumference

4 * 2 = 8 dm <== diameter

Hope this helps!

Answer:

I didn't understood your question. But,

I×100/P×T

Answer:

[tex]10 \frac{5}{6}\\\\5 \frac{5}{6}[/tex]

Step-by-step explanation:

[tex]5 \times 2 \frac{1}{6} \\ \\ = 5 \times \frac{13}{6} \\ \\ = \frac{65}{6} \\ \\ = 10 \frac{5}{6} \\ \\ \\ 3 \frac{1}{2} \times 1 \frac{2}{3} \\ \\ = \frac{7}{2} \times \frac{5}{3} \\ \\ = \frac{35}{6} \\ \\ = 5 \frac{5}{6} [/tex]

Consider the first radical :

[tex]{:\implies \quad \sf 5\times 2\dfrac16}[/tex]

Using the properties of mixed fraction, writing the mixed fraction as an improper fraction, we will be having

[tex]{:\implies \quad \sf 5\times \bigg(\dfrac{6\times 2+1}{6}\bigg)}[/tex]

[tex]{:\implies \quad \sf 5\times \bigg(\dfrac{12+1}{6}\bigg)}[/tex]

[tex]{:\implies \quad \sf 5\times \dfrac{13}{6}}[/tex]

[tex]{:\implies \quad \sf \dfrac{65}{6}}[/tex]

[tex]{:\implies \quad \boxed{\bf{10\dfrac56}}}[/tex]

Hence, Option D) is correct

Now, coming to the 2nd question :

[tex]{:\implies \quad \sf 3\dfrac{1}{2}\times 1\dfrac{2}{3}}[/tex]

[tex]{:\implies \quad \sf \bigg(\dfrac{3\times 2+1}{2}\bigg)\times \bigg(\dfrac{3\times 1+2}{3}\bigg)}[/tex]

[tex]{:\implies \quad \sf \bigg(\dfrac{6+1}{2}\bigg)\times \bigg(\dfrac{3+2}{3}\bigg)}[/tex]

[tex]{:\implies \quad \sf \dfrac{7}{2}\times \dfrac{5}{3}}[/tex]

[tex]{:\implies \quad \sf \dfrac{35}{6}}[/tex]

Now, Rewriting this improper fraction as mixed fraction, we will be having :

[tex]{:\implies \quad \boxed{\bf{5\dfrac56}}}[/tex]

Hence, Option C) is correct

Answer:

its b

Step-by-step explanation:

just took the test

Answer:

Its C

Step-by-step explanation:

Have a good day!

Answer:

i think 31

Step-by-step explanation: