A fish introduces more air into its swim bladder so that it rises toward the surface of the water. Which of the following statements best describes the situation? A The fish decreased its buoyant force by decreasing its density. B The fish increased its buoyant force by increasing its density. с The fish increased the buoyant force by reducing its density.

Answer:

Explanation:

If you are not told otherwise, you have to assume that the voltage source is ideal, meaning that it can maintain its voltage regardless of what resistances (or other loads) are in the circuit, and that it has the means to provide whatever current is necessary to maintain that voltage.

0

Okay, it's an interesting question. Your problem is right: the brightness stays the same.

First of all, I can't resist saying that I would expect 0 brightness haha. Because the circuit, as it is drawn, has no power sources. I guess the upper element is meant to be a voltage source. However, if you write "V" in the circle, that's the symbol of a volt-meter, not a power source. Consider changing the symbol for a battery or a voltage source.

After that comment, let's suppose the circuit consists in two lamps, a resistor and a voltage source, all of them in parallel.

The key is that

A voltage source provides a fixed voltage, but the current it provides is unknown, as it depends on the circuit to which it is attached.

That's the first idea. The second one is:

A lightbulb can be regarded as a resistance, at first level approximation.

That means that we have 3 resistances in paralell.

Two of those resistances are fixed (light bulbs). Constant voltage, and constant resistance, imply constant current.

[tex]IP=VRP;IQ=VRQ;[/tex]

The variable resistance allows changing the current through that resistance. Ivar=V/Rvar

But the total current is IP+IQ+Ivar. This is the current powered by the source. But the source is a voltage source, not a current one. A voltage source can have any current allowed by its components.

What is happening is that the current supplied by the source varies, in order to keep the voltage constant, which is the source's mission.

In other words,

Keeping the voltage constant requires a sacrifice: the current supplied by the source might vary.

But, as the voltage is the same for the bulbs, and intensities of the bulbs depend on the bulbs themselves (I=V/R), and they do not depend on the source, then of course the power dissipated in the bulbs is the same, and thus they have the same brightness.

This means that IP+IQ+Ivar=ITotal. Only Ivar and ITotal can vary. The bulbs' ones are fixed by Ohm's law.

Some more comments:

Of course, this is the ideal case. There is actually a range of currents that the source and the components can handle. Ideally, a voltage source can provide any current needed. In real life, this is not true. Real sources have a maximum current value.

Also, bulbs have a resistance that depends on the current, because their R depends on temperature.

If we didn't consider light bulbs as resistance, it would be a little more complicated, and different.

Hope this helps if not im sorry

According to the question linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface is 30.682× [tex]10^{10}[/tex].

Astronomically speaking, an orbit is the curved path—typically elliptical—that a planet, satellite, comet, etc. takes when it revolves around another celestial body as a result of gravitation.

By Newton's second law

GMm/[tex]r^{2}[/tex] m[tex]v^{2}[/tex] /r.

Since the radius of Earth is 6.37 × [tex]10^{6}[/tex] m,

the orbit radius is r=(6.37×[tex]10^{6}[/tex] m+204×[tex]10^{3}[/tex] m)=1.3×[tex]10^{3}[/tex] m.

The solution for v is

v= [tex]\sqrt{\frac{GM}{r} }[/tex]​ ​ = (6.67×[tex]10^{-11}[/tex]× 5.98×[tex]10^{24}[/tex]/1.3×[tex]10^{3}[/tex])^1/2

⇒ v= 30.682× [tex]10^{10}[/tex]

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Answer:

well, the opposed friction is caused because of the weight of the crate,so if the weight is been added more and becomes heavier the friction between the floor and the crate will increase

Friction is the one that opposes motion. Increase in the weight of the body causes an increase friction offered to the relative motion of the surfaces in contact. It is clear that the frictional force will change.

There are several factors that can affect friction either increase or decrease the resistance.

Some of them are:

The friction is directly proportional to the weight of the body on a horizontal surface and hence an increase in weight increases friction.

Thus, the frictional force will change as the crate gets heavier.

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This sample tends to break into cubes and is not extremely hard, perhaps just slightly harder than or as hard as a fingernail.

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Galena is not very hard, maybe slightly harder than or as hard as a fingernail and seems to break into cubes.

The main source of lead is galena, which is frequently mined for its silver content. In ceramic glaze, it can serve as a source of lead.

Galena was designated as Missouri's official mineral in 1967. The Joplin-Granby region in southwest Missouri, which is a part of the Tri-State Mining District, saw a boom in galena mining. Crawford, Washington, Iron, and Reynolds Counties all have rich deposits.

Galena is lead sulfide with a specific gravity of 7.4 to 7.6 and a Moh's hardness of 2.5, making it actually rather soft. However, it is VERY heavy. It weighs roughly 700 pounds per cubic foot, for comparison.

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The value of Young's modulus will be 6.78*10^8 N/m^2

Linear elastic solid materials have a mechanical characteristic called Young's modulus (Y), which is also referred to as the elastic modulus. It explains how strain (proportional deformation) and stress (force per unit area) interact with one another in a material.

The stiffness of a solid or its resistance to elastic deformation under stress is measured by the Young's modulus (E or Y). It connects strain (proportional deformation) along an axis or line to stress (force per unit area).

Given elongation delta L=1.10 m

Mass of A=65.0 kg,

L=45.0 m

D=7 mm

radius =  r=7/2=3.5 mm

Since we know the Young's Modulus (Y) Can be defines as [tex]Y=\frac{\text { stress }}{\text { strain }}=\frac{\mathrm{F} / \mathrm{A}}{\Delta l / L}[/tex]

Now, (4/{L)=(1.10 m/45.0 m)=0.0244

[tex]\begin{aligned}\ \frac{F}{A}=\frac{M g}{A} & =\frac{65 \mathrm{~kg} \times 9.8 \mathrm{~m} / \mathrm{sec}^2}{\pi r^2} \\& =\frac{65 \mathrm{~g} \times 9.8 \mathrm{~m} / \mathrm{sec}^2}{3.14 \times\left(3.5 \times 10^{-3}\right)^2} \\& =\frac{65 \times 9.8}{3.14 \times 12.25 \times 10^{-6}} \mathrm{~N} / \mathrm{m}^2 \\& =\frac{637}{38.465} \times 10^6 \mathrm{~N} / \mathrm{m}^2 \\\frac{F}{A} & =16.56 \times 10^6 \mathrm{~N} / \mathrm{m}^2\end{aligned}$$[/tex]

Therefore, the value of Young's modulus will be

[tex]$$\begin{aligned}& Y=\frac{F / A}{\Delta l / L}=\frac{16.56 \times 10^{-6} \mathrm{~N} / \mathrm{m}^2}{0.0244}=\left(678.688 \times 10^6\right) \mathrm{N} / \mathrm{m}^2 \\& Y=6.78 \times 10^8 \mathrm{~N} / \mathrm{m}^2\end{aligned}$$[/tex]

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The first question is asking which phase change occurs when steam is cooled to 100°C. The answer is condensation.

The second question is asking for the term that refers to the amount of energy needed to change a liquid into a gas, without changing its temperature. The answer is heat of vaporization.

The third question is asking in which phase change hydrogen bonds are formed. The answer is freezing.

The fourth question is asking for the amount of energy required to raise the temperature of 20 g of a substance from 72°C to 88°C, given that the specific heat of the substance is 0.215 J/g°C. To solve this problem, you can use the formula Q = m * c * delta T, where Q is the energy required, m is the mass of the substance, c is the specific heat, and delta T is the change in temperature. Plugging in the given values, you get Q = 20 g * 0.215 J/g°C * (88°C - 72°C) = 68.8 J. Therefore, the answer is 68.8 J.

We can calculate the speed of an object rolling motion a ramp by using the equation of motion in which we consider rolling and a tangential force acting on it.

Rolling motion occurs when an object rolls down over a height from the ramp or from any other sloppy or rough surface. the surface can be both smooth or rough, depending on it the friction acts on the object that is rolling over the ramp. we also consider the rolling tangential force in our calculation along with other forces when we tend to calculate the rest of the things. We can calculate the speed of an object rolling motion a ramp by using the equation of motion in which we consider rolling and a tangential force acting on it. Hence by this we can consider that we can calculate the rolling of any object by the equation of motion.

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The mass of the pilot flying a small plane is 75.74 kg.

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Speed of the small plane: v = 130 m/s.

Radius of circular path: r = 400 meter.

Hence, centripetal acceleration: a = v²/r = (130)²/400  m/s² = 42.25 m/s²

Required force: F = 3200 N.

Hence, from Newton's 2nd law of motion:

The pilot's mass  = force/acceleration

= 3200/42.25 kg

= 75.74 kg.

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Answer:

  A.  35 °C

Explanation:

You want to know which of the temperatures 5, 10, 15, or 35 °C is most favorable to mosquito breeding.

Mosquitos are nonfunctional below 50 °F (10 °C), and are lethargic at 60 °F (15.6 °C). They prefer 29 °C, and their breeding falls off at higher and lower temperatures.

Of the temperature choices offered, mosquitos would breed fastest at 35 °C.

Answer:

In parallel combination each appliance gets the full voltage.

If one appliance is switched on/of others are not affected.

The parallel circuit divide the current through the appliances.

In a parallel combination it is very easy to connect or disconnect a new appliance without affecting the working of other appliances.

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Explanation:

Answer:

Explanation:

56) A

57) E

To throw out a runner, the catcher must toss the ball 130 feet out, 3 feet behind home plate, up to second base.

In order to throw out a runner, the catcher must throw the ball a distance of c=84.85 ft from home base to second base.

The distance between second base and the back tip of home plate shall be 127 feet, 3 inches.

As a result, although though the bases' "points" are 90 feet apart, the actual distance between each subsequent set of base markers is more like 88 feet (26.8 m).

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The time it takes the sound wave to travel to and fro through 2000 m is 11.66 seconds.

A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium.

To calculate the time it takes the sound wave to travel, we use the formula below

Formula:

Where:

From the question,

Substitute these values into equation 1

The time it takes is 11.66 seconds.

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Answer:

i hope it helps mapriend

Answer:

a. hydrogen sulfide.

Answer:

i dont know

Explanation:

Answer:

Option D. It quadruples

Explanation:

Let the initial voltage be V.

Let the initial power be P.

We shall determine the final power of the circuit as follow:

Initial voltage (V₁) = V

Initial power (P₁) = P

Final voltage (V₂) = double the initial voltage = 2P

Final power (P₂) =?

NOTE: Resistor (R) is constant

P = V² / R

Cross multiply

PR = V²

Divide both side by P

R = V² / P

Thus

V²₁ / P₁ = V²₂ / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

P₂ = 4P

Thus, the power will be four times the initial power i.e quadruple.

The height will the ball rise when a 0.50-kilogram ball is thrown upward is 5.1 meters.

Given,

Mass = 0.5 kg

Kinetic energy = 25 joules

Potential energy = mgh = 25

                              = 0.5 × 9.8 × h = 25

                               = 5.1 meters

In general, the work done by a force on an object between two points does depend on the path taken by the object between the two points. For the special case of conservative forces, we have seen that the work does not depend on the path.

Therefore, we can define, for conservative forces, an associated potential energy that, for a given object, depends only on its location. In particular, when a conservative force acts on an object as it moves between two points, we define the define the change in potential  energy associated with that force as minus the work done by that force between those two  points.

kinetic energy of the ball was equal to the work done by the gravitational force. By our definition, the change in gravitational potential energy is equal to minus the work done by the gravitational force.

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The force experienced by the ball to get accelerated was found to be 3.65.

The rate of change in velocity is defined as acceleration. The magnitude of acceleration at every point along a trajectory is provided by the rate of change of velocity in both magnitude and direction at that location. The real acceleration at time t is determined in the limit as a time interval.

Time = 20s

The initial velocity is 0m/s.

Final speed = 73m/s

Unknown: Experience with forcing the ball =?

To answer this problem, we use Newton's second law of motion's equation:

formula for force was :

F=ma

The mass is denoted by m.

The final velocity is denoted by v.

The starting velocity is denoted by u.

It is the amount of time spent

So;

F = m (v - u / t)

F = m (73-0/20)

= 3.65 times mass

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As Projectile range is independent of mass, so They all will have same range.

When an object is close to Earth's surface, its gravitational attraction is calculated using the formula F = mg, where m is the object's mass and g is a constant whose value varies depending on the location. On the surface of the earth, it averages 9.81 meters per second. And when one moves away from the surface in either an inner or an outward direction, this value drops.

Although the strength of the earth's gravitational pull changes depending on the mass of the object, the acceleration caused by it is constant (of course close to the surface). Consequently, when two items of different masses are dropped from the same height, they hit the ground simultaneously (neglect air resistance).

Any motion of a projectile simply consists of vertical and horizontal motion. Regardless of the direction the projectile is going in, gravity controls vertical motion since it only acts in that direction. Additionally, the acceleration caused by gravity is not reliant on the mass of the item. Therefore, the mass has no bearing on the vertical motion.

A projectile moves horizontally in a very straightforward manner. A projectile is not affected by horizontal forces. As a result, its horizontal velocity does not change. Additionally, the range is influenced by horizontal velocity and flying time. Flight time is influenced by vertical motion.

We now know that mass has no bearing on flying duration or range. And if you run into a projectile motion problem, simply divide the problem into horizontal and vertical motions. And handle it the same way you would a single-direction motion. greatly simplifies matters.

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The velocity at Point P is 1.72 x 10^(6) m/s.

Mass of proton is Mp = 1.67x10^(-27)

Initial velocity Vo = 2.1x10^6 m/ s

As the proton is moving its Total energy should remain constant throughout the motion to point P.

Conserving the energy,  

Initial energy = Final energy

(1\2)MpVo^2 + (kQ1Q2)/R1 = (1/2)MpV^2 +(kQ1Q2)/R2  

Given R1 = 3.0 mm  

R2 = 4.0 mm  

2kQ1Q2( 1/R1 - 1/ R2) = Mp( V^2 - Vo^2)

2x9x10^9x(-10x10^(-9))x1.6x10^(-19) x {(1000/3)-(1000/4)} = 1.67x10^(-27){ V^2 - Vo^2}  

-2.4x10^(-15) = 1.67x10^(-27){V^2- Vo^2}  

-1.44x10^12 + Vo^2 = V^2  

-1.44x10^12 + (2.1x10^6)^2. = V^2  

2.97x10^(12) = V^2

V = 1.72x10(^6) m/s  

Hence velocity at Point P is 1.72 x 10^(6) m/s.

Proton's speed is dependent on a variety of factors, such as its energy and environment. When protons are released from an accelerator, their speed can be as high as nearly the speed of light, or roughly 300 million meters per second. When protons are found in an environment such as space or the Earth’s atmosphere, their speed is much lower.

In space, protons typically move at around 100 km/s or 0.1% of the speed of light. Within Earth’s atmosphere, protons tend to move much slower, usually around 10 km/s. In the upper atmosphere, protons may be accelerated by solar wind or cosmic rays to speeds of up to 400 km/s. Protons may also be slowed down by collisions with other particles, such as electrons or atoms. In general, the speed of a proton is determined by its energy and the environment it is in.

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Complete Question:

A proton follows the path shown in (Figure 1). Its initial speed is

[tex]V_0[/tex] = 2.1x10^6 m/s.

Part A What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units.

[tex]V_P[/tex][tex]= ?[/tex]

The turtle traveled 10 meters in 3,918.6 seconds using simple subtraction.

In mathematics, to subtract is to eliminate something from set of things or a group of things. When we remove from the group, the number of items falls or gets less. The minuend, forces at play, and difference are the elements of a subtraction problem.

It involves calculating the distinction between two numbers. The icon looks like this: (minus). In this operation, we take a particular number then split it by a fewer group. In other words, we divide one integer by another. Click here for some difficult addition and subtraction sums.

He gets a value of 4218.6 s

he discovers that the stopwatch had already been running for about 300 s

Time taken by turtle = 4218.6 - 300

= 3918.6 s

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A = (v-u)/t, where an is acceleration, v is final speed, u is initial speed, and t is time, is the equation for acceleration. When the values are filled in, we obtain a = (60-20)/5 or an is 8 m/s2.

The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s2).

+2 m/s2

If there is no change in velocity between 2 and 3 seconds, the acceleration is 0 m/s2. The acceleration is +2 m/s2 over the first 0 to the second interval. The acceleration is zero between seconds two and three. The acceleration is -3 m/s2 throughout the three to six-second period.

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Answer:

False

Explanation

Poaching, habitat loss and diseases are contributing to the death of animals there, example: Gorilla

Answer:

false

Explanation:

For pendulum A, the period of oscillation is T = 2π × √(L/g). For pendulum B, the period of oscillation is T = 2π × √(2L/g). As we can see from the formula, Pendulum B takes longer for a swing as its period of oscillation is longer than pendulum A due to the fact that half the mass is distributed along the uniform bar.

The period of a pendulum is given by the formula T = 2π × √(L/g) where L is the length of the pendulum and g is the acceleration due to gravity.

For pendulum A, the total mass is concentrated in the small ball at the end of the massless bar, so the period of oscillation is T = 2π × √(L/g)

For pendulum B, half the mass is in the small ball, and half is distributed along the uniform bar, so the period of oscillation will be T = 2π × √(2L/g)

In both cases, the length of the pendulum is the same, so the period of oscillation for pendulum A is shorter than the period of oscillation for pendulum B. Therefore pendulum B takes longer to swing.

It's worth noting that these calculations are based on small oscillations, when the angle of oscillation is small, as the period of a pendulum is dependent on the angle of oscillation.

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Answer:

B and D

Explanation:

B (not the answer choice) is a hyperbole

Optical devices B and D can form only virtual images. Option C is correct.

When light beams from an object reflect off a mirror, they intersect with the picture of that thing, called an image. Real and virtual images are the two sorts of images.

The following parameters can be used to describe an image:

1. It is possible for an image to be real or virtual.

2. Left-right reversal is possible or not.

3. The image can be inverted or upright.

4. The image can be enlarged, shrunk, or made the same size as the object.

The image characteristic is described by the descriptive words will be;

1. image type.

2. image orientation.

3. image location.

4. image size.

Optical devices B and D can constitute only virtual images.

Hence, option C is correct.

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Answer:

Explanation:

First establish the POSITIVE direction.  We'll say to the RIGHT is positive, and UP is positive.  All you have to do is add forces in the positive direction and subtract forces in the negative direction.  If your answer is positive, the net force is to the right or up;  if your answer is negative, the net force is to the left or down.

Here are your answers:

25-15-15 = -5N left

84-60-10 = 14N up

75-60-2 = 13N right

25+25-25 -15 = 10N right

44+44-100= -12N down

67-76 = 9N right