A dollar bill weighs one gram. How many pounds do one million dollar bills weigh? (1000 grams
is equal to 1 kilogram and 1 kilogram is equal to about 2.205 pounds.)

Answer:

  19.9 days

Step-by-step explanation:

The amount remaining after d days is ...

  a = (1/2)^(d/7)

We want to find d when a = 0.14

  log(a) = (d/7)log(1/2)

  d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9

The farmers need to wait about 19.9 days for it to be safe.

Answer:

(a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

B. 168 students

Step-by-step explanation:

Given that there are a total of 600 students.

28% of the students pack their lunch.

To find:

Total number of students who pack their lunch = ?

Solution:

Percentage of a given number is calculated using the following method.

[tex]y\%[/tex] of a number [tex]x[/tex] is given by:

[tex]x \times \dfrac{y}{100}[/tex]

i.e. multiply the number by percentage to be found and divide by 100.

So, we have to find 28% of 600 here, to find the answer to the question.

[tex]\therefore[/tex] Number of students who pack their lunch is given as: (Multiply the given number 600 with 28 and divide by 100.)

[tex]600 \times \dfrac{28}{100}\\\Rightarrow 6 \times 28\\\Rightarrow \bold{168}[/tex]

So, the correct answer is:

B. 168

Answer:

17 lanterns.

Step-by-step explanation:

There are 13 campers with one lantern each, so that will be 13 * 1 = 13 lanterns.

The company supplies 4 extra lanterns for the whole group.

So, they will bring 13 + 4 = 17 lanterns.

Hope this helps!

Answer:

[tex] x^3 - 6x + 2 [/tex]

Step-by-step explanation:

The given polynomials can be added together by adding like terms together as shown below:

=> Add together, the coefficient of all terms that have the power of 3.

[tex] (2x^3) + (x^3) + (-3x^3) [/tex]

[tex] 2x^3 + x^3 - 3x^3 [/tex]

[tex] 3x^3 - 3x^3 [/tex]

[tex] x^3 [/tex]

=> [tex] (-4x^2) + (6x^2) + (2x^2) [/tex]

[tex] -4x^2 + 8x^2 [/tex]

[tex] 4x^2 [/tex]

=> [tex] (6x) + (-8x) + (-4x) [/tex]

[tex] 6x - 8x - 4x [/tex]

[tex] -6x [/tex]

=> [tex] (-3) + (12) +(-7) [/tex]

[tex] -3 + 12 - 7 [/tex]

[tex] 2 [/tex]

The answer = [tex] x^3 - 6x + 2 [/tex]

Answer:

4x^2-6x+2

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] \mathrm{Given}[/tex],

[tex] \mathrm{Discount\% = 20\%}[/tex]

[tex] \mathrm{Marked \: price = 1250}[/tex]

[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]

[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]

[tex] \mathrm { = 20\% \: of \: 1250}[/tex]

[tex] \mathrm{ = 250}[/tex]

[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]

[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]

[tex] \mathrm{ = 1250 - 250}[/tex]

= $ [tex] \mathrm{1000}[/tex]

[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]

[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]

[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]

= $ [tex] \mathrm{ 125}[/tex]

[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]

[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]

[tex] \mathrm{ = 1000 + 125}[/tex]

= $ [tex] \mathrm{1125}[/tex]

Therefore, The final sale of the necklace is $ 1125

Hope I helped

Best regards!

Answer:

18.8 cubic inches

Step-by-step explanation:

1. Solve for the volume of Cup A. (volume of a cone = 1/3πr² · h)

1/3 · 3.14 · 1² · 3 = 3.14 in³

2. Solve for the volume of Cup B (volume of a cylinder = πr² · h)

3.14 · 1² · 7 = 21.98 in³

3. Subtract the volume of Cup A from Cup B

21.98 - 3.14 = 18.84

4. Round 18.84 to the nearest tenth

18.84 → 18.8 in.³

Answer:

18 .8

Step-by-step explanation:

got it right on test

Answer:

The sampling is dependent because an individual selected for one sample does dictate about which individual to be selected in the second sample.

The variable is qualitative because it classifies the individual.

Step-by-step explanation:

The sample is dependent as the second individual selected in the sample is dependent on the first individual selection. The sample selection is not random and is dictated. The variables selected are qualitative in nature because they identify the quality of response variable which is non numerical in nature.

Step-by-step explanation:

Intersecting secant angles theorem: The angle between two secants is half the difference of the intersected arcs.

52 = ½ (x − 38)

x = 142

Arc angles add up to 360.

360 = 80 + 38 + z + x

z = 100

Tangent-chord theorem: The angle between a tangent and a chord is half the intercepted arc angle.

y = x/2

y = 71

Work Shown:

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\[/tex]

Answer:

√91/10

Step-by-step explanation:

sin 0.3 is equal to 18(approximate value)

cos18°=0.951

which is √91/10

Answer:  C

Step-by-step explanation:

h · k(x) = 2(3x - 5)(-2x + 1)

           = (6x - 10)(-2x + 1)

           = -12x² + 6x + 20x - 10

           = -12x² + 26x - 10

Answer:

C

Step-by-step explanation:

h(x) × k(x)

= 2(3x - 5)(- 2x + 1) ← expand factors using FOIL

= 2(- 6x² + 3x + 10x - 5)

= 2(- 6x² + 13x - 5) ← distribute parenthesis by 2

= - 12x² + 26x - 10 → C

Answer:

Original price is $1610

Step-by-step explanation:

2737=1.7*Original price

divide each side by 1.7

Original price=1610

Hope this helps!

Answer:

Step-by-step explanation:

The square root of 7066 is 84.0595....

Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...

That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.

84 isn't prime. But 83 is prime.

Therefore, the greatest prime that needs to be considered for divisibility is 83.

Answer:

The numbers 7066 is not prime .

But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.

Step-by-step explanation:

It is known with certainty that a number is prime when it is only divisible by and by unity.

But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.

for example; 7066/2=3533 , the remainder is zero;

Answer:

Step-by-step explanation:

Given,

AD = 38

EB = 7x - 4

FC = 6x - 6

Now, we have to find the value of X

[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )

Plug the values

[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]

Calculate the difference

[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]

Remove the parentheses

[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]

[tex]7x - 4 = 16 + 3x[/tex]

Move variable to L.H.S and change its sign

Similarly, Move constant to R.H.S and change its sign

[tex]7x - 3x = 16 + 4[/tex]

Collect like terms

[tex]4x = 16 + 4[/tex]

Calculate the sum

[tex]4x = 20[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{20}{4} [/tex]

Calculate

[tex]x = 5[/tex]

The value of X is 5

Now, let's find the value of EB

EB = 7x - 4

Plug the value of X

[tex] = 7 \times 5 - 4[/tex]

Calculate the product

[tex] = 35 - 4[/tex]

Calculate the difference

[tex] = 31[/tex]

The value of EB is 31

Hope this helps..

Best regards!!

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 0.5 \ in[/tex]

Generally the Null hypothesis is  [tex]H_o : \mu = 0. 5 \ in[/tex]

                The Alternative hypothesis is  [tex]H_a : \mu \ne 0.5 \ in[/tex]

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]

We are making use of this  [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that  [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that  t  lies in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

Answer:

Option B

an increasing exponential graph

Answer:

my best answer for this is B. False.

I calculated as fast as i can.

Answer:

YTM = 5.45%

Step-by-step explanation:

Here, we are interested in calculating the yield to maturity.

Mathematically;

Annual coupon=1000*4.3%=43

YTM=[Annual coupon+(Face value-Present value)/time to maturity]/(Face value+Present value)/2

=[43+(1000-870)/18]/(1000+870)2

=5.45%

Answer:

(a) 3:5

(b) 15

Step-by-step explanation:

Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.

It is asking for unshaded first so our ratio will be,

3:5

(a) 3:5

So if there is 9 unshaded how many shaded is there.

Well we can just make the following ratio 9:x

So 9/3 = 3

Meaning 3*5 = 15

So x = 15

(b) 15

Answer:

a) 3/5

b) 15

Step-by-step explanation:

(a)

unshaded: 3

shaded: 5

unshaded to shaded: 3/5

(b)

There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.

Add two more lines just like the given line.

Each new line will have 5 shaded and 3 unshaded squares.

Now you have a total of 9 unshaded and 15 shaded squares.

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

The CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

It is given that the objective that central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds.

It is required to describe the above theorem.

It is defined as the in statistics the assumption holds that the sample means distribution of arbitrary variables follows a normal distribution or close to normal distribution if the sample size is big.

We have an objective:

The CLT is the factor to be considered when assessing if the CLT holds a large sample size.

If we draw the random sample data and its measures, the Central limit theorem explains the distribution will explain the normal bell curve, the mean of the parameters and the distribution will be the same.

Thus, the CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

Learn more about the Central limit theorem here:

https://brainly.com/question/5027686

Answer:

Step-by-step explanation:

[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]

Squaring on both sides:

[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]

Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]

[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]

Combine like terms.

[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]

[tex] - 3x + 2x = 7[/tex]

Calculate

[tex] - x = 7[/tex]

[tex]x = - 7[/tex]

Hope this helps...

Good luck on your assignment..

Answer:

-7

Step-by-step explanation:

Khan academy

6 1/10

Step-by-step explanation:

4 + 1/2+1+3/5

5+1+1/10=6 1/10

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

[tex]f(x) = \sqrt{x}[/tex]

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

[tex]f^i(c) = \frac{f(b) - f(a)}{b -a }[/tex]

After this,

[tex]f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}[/tex]

[tex]f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\[/tex]

After this,

Put the values of a and b to the above equation

[tex]f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}[/tex]

= 2.25

Answer:

A. The median represents the center.

Step-by-step explanation:

In statistics and probability theory, the median value is the middle value or center value in a group of data values or numbers. To find the median, the values have to be placed in value order, from smallest to largest. The center number would be the median. The number lies between the higher half and the lower half. Therefore the median represents the center of the data values.

Answer:

D. 6

Step-by-step explanation:

here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}

and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }

so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.

Answer:

7 children

Step-by-step explanation:

Answer:

7 children is the correct answer

and you follow me if you can't I will unfollow you

Answer:

29.4≤μ≤32.6

Step-by-step explanation:

The datas given from the questions are as shown:

Number of people n = 24

Mean xbar= $31

Standard deviation σ = $6

Confidence Interval formula is expressed as:

CI = xbar ± Z(σ/√n)

Z value for 80% confidence interval is 1.282

Substituting the values into the Confidence Interval formula will give;

CI = 31 ± 1.282{6/√24}

CI = 31 ± 1.282(1.225)

CI = 31 ± 1.57045

CI = 31+1.57045 and 31-1.57045

CI = (29.42955, 32.57045)

CI = (29.4, 32.6) to 1dp

The confidence interval will be within the range 29.4≤μ≤32.6

Answer:

hope you get it....sorry for any mistake calculations