The statement that a doctor who is monitoring the health of astronauts in space has just received a signal that indicates one of the astronauts may be experiencing low blood sugar. The mission control personnel that would communicate this to the astronaut on board the space craft is CAPCOM is true. So the correct option is A.
What is CAPCOM?When there is a mission in which astronauts do space exploration, there will be mission control on the ground made up of members who will take over from the astronauts on earth, this will be the CAPCOM. These people will transmit the decision-making of the mission director who will be from the ground and will also communicate the needs of the astronauts to the people who control the mission.
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Which situation would deplete freshwater?
Answer:
If freshwater consumption was greater than freshwater renewal.
Explanation:
Similar to another Brainly answer :O
Which would help you perform a basketball skill well with
speed?
A cannonball is launched with an initial speed of 20 m/s. Calculate the maximum height the ball could reach.
Answer:
During its trajectory the cannon ball will have kinetic and potential energy
E = KE + PE
The maximum value of PE will occur when the cannon ball was fired straight up - for other trajectories PE will be less because of translational KE
So E = M g h = 1/2 M v^2 for maximum height
h = v^2 / (2 * g) = 400 / (2 * 9.8) = 20.4 m
Check the attached image for the question~
Answer:
put the full thin g
Explanation:
Two equally charged pith ball are 3cm apart in air and repel each other with a force of 4X105N - Comput the charge on each bali-
TheThe charge applied on each ball is 2 X 10∧-9 C.
Define force ?
An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The pitch balls repent each other with force
F= 4 X 10^-5N
Let the charge on each ball be Q.
4 X 10^-5= k(Q)(Q) / (3 X 10^-2)^2
Q^2= 4*10^-5X 9*10^-4 / 9*10^9
Q^2 = 4 X 10^-18
Q= √4 X 10^-18
Q = 2 X 10^-9 C.
Therefore, the charge on each ball is 2X10^-9C.
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Each ball has been charged with 2 X 10⁹ C. When a product is held in electrostatic energy, its properties referred to as electric discharge allows it to feel force.
What is force?A force can compel a heavily armored item to increase or modify overall velocity. A push or a pull is a simple and effective method to explain force. That's because a force has both magnitude and direction it is a dimensionless number.
The pitch balls repent each other with force
F = 4 X 10⁻⁵N
4 X 10⁻⁵ = k(Q)(Q) / (3 X 10⁻²)²
⇒ Q² = 4 × 10⁻⁵ X 9 × 10⁻⁴ / 9 × 10⁹
⇒ Q² = 4 X 10⁻¹⁸
⇒ Q = √4 X 10⁻¹⁸
⇒ Q = 2 X 10⁻⁹ C.
Therefore, the charge on each ball is 2 X 10⁻⁹C.
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how to prepare a trading stock account
Answer:
Opening stock details of raw material, semi-finished goods and finished goods.
Closing stock details of raw material, semi-finished goods, and finished goods.
Total purchases of goods fewer Purchase Returns.
Total sales of goods fewer Sales Returns.
How far from the earth must a body be along a line toward the sun so that the sun’s
gravitational pull balances the earth’s? The sun is 9.3 × 107 miles away and its mass is
3.24 × 105 Me.
Answer:
r = 1.63×10^5 mi
Explanation:
Let r = distance of object from earth
Rs = distance between earth and sun
Ms = mass of the sun
= 3.24×10^5 Me (Me = mass of earth)
At a distance R from earth, the force Fs exerted by the sun on the object is equal to the force Fe exerted by the earth on the object. Using Newton's universal law of gravitation,
Fs = Fe
GmMs/(Rs - r)^2 = GmMe/r^2
This simplifies to
Ms/(Rs - r)^2 = Me/r^2
(3.24×10^5 Me)/(Rs - r)^2 = Me/r^2
Taking the reciprocal and then its square root, this simplifies further to
Rs - r = (569.2)r ----> Rs = 570.2r
or
r = Rs/570.2 = (9.3×10^7 mi)/570.2
= 1.63×10^5 mi
Six vectors (a through f ) have the magnitudes and directions indicated in the figure. (Figure 1)
1.Rank the vector combinations on the basis of their magnitude.
Rank from largest to smallest. To rank items as equivalent, overlap them.
a+c
f+c
d
a+b
a+e
a+d
2.Rank the vector combinations on the basis of their angle, measured counterclockwise from the positivexaxis. Vectors parallel to the positivexaxis have an angle of0^\circ. All angle measures fall between0^\circand360^\circ.
Rank from largest to smallest. To rank items as equivalent, overlap them.
a+d
f+c
a+b
a+e
a+c
d
1. The rank of the vector combinations on the basis of their magnitude
a+b = a +d > a+c > f +c = d > a + e.
2. The rank of the vector combinations on the basis of their magnitude
a+d = a +b > a+c > f +c =d > a+e.
What is vector quantity?Any physical quantity having both magnitude and direction is called vector quantity.
According to figure:
a = 2 unit b = 2 unit c = 1 unit d = 2 unit e = 1 unit and f = √5 unit.
a + c = 2+1 unit = 3 unit
a + b = 2√2 unit
a + e = 2 -1 = 1 unit
a +d = 2√2 unit
f+ c = 2 unit
a+d = 2√2 unit
f+c = 2 unit
a+b = 2√2 unit
a+e = 1 unit
a+c = 3 unit
Hence, rank of the vector combinations on the basis of their magnitude
a+b = a +d > a+c > f +c = d > a + e.
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Two long straight parallel wires separated by 1m carry 20A current each in the same direction. Find the magnitude and direction of the magnetic field at a) point midway between the wires; b) point 25cm to the right of point midway between the wires; c) point 75cm to the right of point midway between the wires; d) point 25 cm above one of the wires.
Answer:
Explanation:
a )
At a point midway between the wires , magnetic field due to two wires will be equal and opposite so they will cancel each other . Therefore , net magnetic field will be zero .
b )
At a point 25cm to the right of point midway between the wires
distance of this point will be .25 m from one wire and .75 m from other wire .
Magnetic field due to a current carrying wire can be given by the following expression .
B = (μ₀ / 4π ) x 2I / R where I is current and R is distance of the point
= 10⁻⁷ x 2I / R
For the wire at a distance of .25 m
magnetic field B₁ = 10⁻⁷ x 2 x 20 / .25
= 160 x 10⁻⁷ T .
For the wire at a distance of .75 m
magnetic field B₂ = 10⁻⁷ x 2 x 20 / .75
= 53.33 x 10⁻⁷ T .
These fields are opposite to each other , so
net magnetic field = 160 x 10⁻⁷ T - 53.33 x 10⁻⁷ T
= 106.67 x 10⁻⁷ T .
If the wires are horizontal and current is flowing away from the observer , net magnetic field will be in vertically upward direction .
c )
At a point 75cm to the right of point midway between the wires
The point will be .25 m from one wire and 1 .25 m from other wire . And the magnetic field will be aligned in the same direction .
For the wire at a distance of .25 m
magnetic field B₁ = 10⁻⁷ x 2 x 20 / .25
= 160 x 10⁻⁷ T
For the wire at a distance of 1.25 m
magnetic field B₂ = 10⁻⁷ x 2 x 20 / 1.25
= 32 x 10⁻⁷ T
As the fields are aligned in the same direction
Net magnetic field = 160 x 10⁻⁷ T + = 32 x 10⁻⁷ T
= 192 x 10⁻⁷ T .
If the wires are horizontal and current is flowing away from the observer , net magnetic field will be in vertically downward direction.
a boy is swinging a toy on apiece of string in a vertical circle. the toy has mass 150g and the radius of circle is 0.8m. a) he swings the toy with a linear velocity 2m/s. will the top move in a circle? explain your answer.
The top move will in a circle because there is tension at the top which will add up with the weight of the toy to maintain equal centripetal force providing the circular motion.
What is tension of the top of the vertical circle?
The tension experienced by the top of the vertical circle is calculated by using the following formula.
T = Fc - W
where;
Fc is the centripetal force of the toyW is the weight of the toyT = mv²/r - mg
where;
m is the mass of the toyv is the linear speed of the toyg is acceleration due to gravityr is the radius of the vertical circleThe tension experienced by the toy at the top of the vertical circle is calculated as follows;
T = ( 0.15 x 2² / 0.8 ) - ( 0.15 x 9.8 )
T = 0.75 - 1.47
T = -0.72 N
Thus, with the negative tension at the top of the vertical circle, the sum of the tension force and the weight of the toy will be equal to the centripetal force to maintain the orbit of the toy in a circular path.
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Which of the following best illustrates an application of the principles of behaviorism?
A therapist is helping a client explore feelings about past events.
O A parent is using "time out" as a consequence for bad behavior.
O A friend is listening intently and showing concern for another.
O A mechanic is developing a mental map of the engines she routinely fixes.
The statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
What is behaviorism?The theory that human and animal behaviour can be explained in terms of conditioning, without appeal to thoughts or feelings, and that some mental conditions are best treated by altering behaviour patterns.
Given are the applications of the principles of behaviorism.
The statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
Therefore, the statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
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A set of charged plates is
separated by 2.22*10^-4 m. When
5.24*10^-9 C of charge is placed
on the plates, it creates a potential
difference of 240 V. What is the
area of the plates?
(The answer is *10^-4 m^2. Just fill
in the number, not the power.)
Answer:
5.49×10¯⁴ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 2.22×10¯⁴ m
Charge (Q) = 5.24×10¯⁹ C
Potential difference (V) = 240 V
Permittivity of free space (ε₀) = 8.85×10¯¹² F/m
Area (A) =?
Thus, the area of the plate can be obtained as follow:
Q = ε₀AV /d
5.24×10¯⁹ = 8.85×10¯¹² × A × 240 / 2.22×10¯⁴
5.24×10¯⁹ = 2.12×10¯⁹ × A / 2.22×10¯⁴
Cross multiply
2.12×10¯⁹ × A = 5.24×10¯⁹ × 2.22×10¯⁴
Divide both side by 2.12×10¯⁹
A = (5.24×10¯⁹ × 2.22×10¯⁴) / 2.12×10¯⁹
A = 5.49×10¯⁴ m²
Thus, the area of the plates is 5.49×10¯⁴ m².
Answer:
it's actually 5.48
Explanation:
A satellite is a large distance from a planet, and the gravitational force from the planet is the only significant force exerted on the satellite. The satellite begins falling toward the planet, eventually colliding with the surface of the planet. As the satellite falls, what claims is correct about how the force that the planet exerts on the satellite Fps changes and how the force that the satellite exerts on the planet Fsp changes, if at all? What reasoning supports this claim?
Answer:
The answer is "Option A".
Explanation:
Please find the complete question in the attached file.
The strength is equal due to the third law of Newton, and [tex]Fsp = Fps = \frac{Gmsmp}{r^2}\[/tex], therefore the force increases with decreased separation r.
What is the speed of a transverse wave in a rope of length 2 meters and mass 0.06
kg under a tension of 500 nt?
Answer:
16.3 wave speed.
Explanation:
Three point charges q1 = +2 μC, q2 = −3 μC, and q3 = +4 μC are located at the corners of a right angle triangle as shown below. Find the magnitude and direction of the resultant force on q3.
Answer:
Explanation:
4
The magnitude and direction of the resultant force on q3 is;
F_net = 32.2 N in the direction of q3
We are given;
q1 = +2 μC = 2 × 10^(-6) C
q2 = -3 μC = -3 × 10^(-6) C
q3 = +4 μC = 4 × 10^(-6) C
Now,from the given image, charges q1 and q2 attract charge q3.
Formula for force on a charge is;
F = (kq1 * q2)/r²
Where;
k = 9 × 10^(9) N.m²/C²
Thus;
F_y = kq1*q3/(r1)²
We have;
q1 = 2 × 10^(-6) C
r1 = 5 cm = 0.05 m
q3 = 4 × 10^(-6) C
Thus;
F_y = (9 × 10^(9) × 2 × 10^(-6) × 4 × 10^(-6))/(0.05^(2))
F_y = 28.8 N
Similarly;
F_x = kq2*q3/(r2)²
r2 = 5/(tan 30)
r2 = 8.66 cm = 0.0866 m
F_x = (9 × 10^(9) × -3 × 10^(-6) × 4 × 10^(-6))/(0.0866^(2))
F_x = -14.4 N
Thus, magnitude of resultant force is;
F_net = √((28.8)² + (-14.4)²)
F_net = √1,036.8
F_net = 32.2 N
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When the Apollo 11 lunar module Eagle lands on the moon it comes to a stop 10m above the surface of the moon. The last 10m it freely falls to the surface of the Moon.
i) How long does it take for the Eagle to touch down?
ii) What is the velocity of the lunar module when it hits the surface of the moon?
Answer:
i) 3.514 s, ii) 5.692 m/s
Explanation:
i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.
as the equation says for free-falling
h = ut +0.5gt^2
Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)
initial velocity u = 0
10 = 0.5×1.62t^2
t = 3.514 seconds
Therefore, it takes t = 3.514 seconds for the Eagle to touch down.
ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon
v = u + gt
v = 0+ 1.62×3.514
v= 5.692 m/s
Which of the following is a sign of puberty?
A.
intense changes in hormone balance
B.
increased height and strength
C.
development of sexual characteristics
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
state the property of plastic that allows it to become electrostatically charged
(please answers ty)
Answer:
when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.
helpp tyy
Which of the following is a way to make magnets?
heating
freezing
pressure
heating or pressing but heating is most appropriate, so the answer is heating.
The momentum of an object is determined to be 7.2×10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g
The mass of the moving item is referred to as momentum. There is magnitude and direction to momentum. The object has a momentum of 7.2 g-m/s.
What is the momentum of an object?Momentum is a vector quantity that is created during motion by an object's mass and velocity. Thus, momentum will be expressed in units of kg-m/s.
Considering that item has motion. Likewise, 1 kilogram equals 1000 g. Therefore, the momentum will transform into units of grams when we enter the value of 1 kg.
Momentum = 7.2 x 10⁻³ 1000g-m/s
Momentum = 7.2 g-m/s.
Thus, we may deduce that the object's momentum, measured in grams per second, is 7.2 g-m/s.
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The type of heat transfer responsible for your computer leaving your desk very hot after you've used it for awhile?
Answer:
Conduction
Explanation:
Conduction is a process whereby heat is transfer through solid state.
The slope of a velocity time graph will give___
Answer:
THE ANSWER IS ( acceleration of the object )A man drags a 10.0 kg bag of mulch at a constant speed applying a 22.5 N force at a 32-degree angle. What is the friction force acting on the bag?
The
friction
force acting on the bag is 4.36µ.
What is friction force?
The
force
preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
Given,
Force =F=22.5 n
Mass=m= 10 kg
mu=µ=?
(1N= 1kg m/s²)
Gravitational force =g= 9.81 m/s²
As we know,
F= µ*m*g
µ= m*g/F
= 10*9.81/ 22.5
µ= 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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The bag is subject to a friction force of 4.36. A man applies a 22.5 N force at a 32° angle while dragging a 10.0 kilogram bag of mulch at a steady speed.
How much friction is there?Friction refers to the force that resists hard surface, fluid layering, and materials ingredients from gliding past one another. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.
Force = 22.5 N
Mass = 10 kg
⇒ mu = µ (1N= 1kg m/s²)
⇒ g = 9.81 m/s²
As we know, F= µ × m × g
⇒ µ = (m × g)/F
⇒ (10 × 9.81)/ 22.5
⇒ µ = 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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Which of the following correctly describes the order of skin layers from the inside to the outside of the body?
A. dermis, epidermis, hypodermis
B. hypodermis, dermis, epidermis
C. epidermis, hypodermis, dermis
D. hypodermis, epidermis, dermis
Answer:
it is a
Explanation:
dermis,epidermis,hypodermis
Answer:
B. hypodermis, dermis, epidermis
this is because it is inside to outside
hypodermis is deeper tissue, dermis is beneath epidermis, and epidermis is the outermost layer
What is the meaning of the density of states function?
Ans-The density of states function describes the number of states that are available in a system and is essential for determining the carrier concentrations and energy distributions of carriers within a semiconductor.
Answer:
density equal to mass upon volume
simple definition
A single movable pulley is used to lift 4000N load to the height of 50 cm. If the efficiency of the pulley is 75%, Calculate effort distance,effort applied,output work and mechanical advantage.
Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:
Effort Distance = 50 cm
Effort Applied = 5333.33 N
Output work = 2000 J
Mechanical Advantage = 0.75.
When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.
Load (output force) = 4000 N
Height lifted = 50 cm = 0.5 m
Efficiency of the pulley = 75%
Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:
Effort applied (input force) = Load ÷ Efficiency
= 4000 N ÷ 0.75
= 5333.33 N
Output work = Load x Height lifted
= 4000 N x 0.5 m
= 2000 J
Effort distance = Height lifted
= 50 cm
Mechanical advantage = Load ÷ Effort applied
= 4000 N ÷ 5333.33 N
= 0.75
It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.
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A wire with a current of 5.2 A is at an angle of 45° relative to a magnetic field of 0.87 T. What is the force exerted on a 1.2 m length of the wire
Answer:
F = I L X B = I L B sin theta
F = 5.2 * 1.2 * .87 sin 45 = 3.84 N in the direction of (L X B)
Note: L and B must be at right angles for F = I L B
50 POINTS !!!
Three particles of mass 8 kg, 3 kg, and 7 kg are connected by rigid rods of
negligible mass lying along the y axis and are placed at 5 m, -2 m, and -6 m,
respectively as in the figure. The system rotates about the x axis with an angular
speed of 1.65 rad/s.
a) Find the moment of inertia about the x axis. Consider the
masses to be point particles.
b) Find the total rotational energy.
c) Find the linear speed of the top particle of mass 8 kg in the figure.
Answer:
a) I = 464 kg m², b) K = 631 .6 J, c) v = 8.25 m / s
Explanation:
a) the moment of inertia of point particles is
I = ∑ m_i r_i²
in this case
I = 8 5² + 3 (-2) ² + 7 (-6) ²
I = 464 kg m²
b) The kinetic energy is
K = ½ I w²
K = ½ 464 1.65²
K = 631 .6 J
c) linear and angular velocity are related
v = w r
v = 1.65 5
v = 8.25 m / s
8. Jane rides a sled down a slope of angle θ at constant speed v. Determine the coefficient of kinetic friction between the sled and the slope. Neglect air resistance.
(A) μ=gsinθ (B) μ=mgcosθ (C) μ=tanθ (D) μ=gcosθ
Answer:ssssw
Explanation:
What is electronic dispersion theory?
Dispersion in wave theory is the phenomena where a wave's phase velocity changes depending on its frequency. The article can explore different definitions. This is the typical definition for dispersion (waves).
When sinusoidal waves with various wavelengths propagate at various speeds, a wave packet with mixed wavelengths has a tendency to disperse in space. Dispersion in wave theory is the phenomena where a wave's phase velocity changes depending on its frequency.
The article can explore different definitions. This is the typical definition for dispersion (waves).
A full set of approximate solutions to the one-electron Schrödinger equation are found in a three-dimensional atomic lattice that is randomly filled with atoms of different kinds and has, on average, the periodicity of a Bloch wave.
Equations are provided that enable the calculation of each wave's energy, average behavior, absent a phase factor, close to any sort of atom, and damping parameter.
A comparison is made between a periodic lattice with a complicated, energy-dependent potential and a random A-B lattice. The dispersion relation of the system is obtained by solving the eigenvalue problem in this potential using any of the established techniques for periodic potentials.
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