A cube of length 8cm is enlarged with a scale factor of 1 1/2
find the length of the enlargement​

Riya applying mulch in m³/ m² at the rate of 0.25 m³

To calculate the rate of mulch application in m³/m², we need to convert the given rate of 250,000 cm³/m² into m³/m². We can do this by using the conversion factor: 1 m³ = 1,000,000 cm³.

So, 250,000 cm³/m² can be converted to m³/m² as follows:

250,000 cm³/m² × (1 m³/1,000,000 cm³) = 0.25 m³/m²

This means that for every square meter of garden space, Riya is applying 0.25 m³ of mulch.

It's important to note that rate refers to the amount of mulch applied per unit of garden space. In this case, the unit is m². By expressing the rate in m³/m², we're specifying the volume of mulch applied per unit of area.

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Complete Question:

Riya is applying mulch to her garden. She applies it at a rate of 250,000 cm³ of mulch for every m² of garden space. At what rate is Riya applying mulch in m³/ m²?

Okay, so 1/3 is the same as 2/6. So we can compare the triangles as 2/6 to 20/6, with yellow as 2/6 and green as 20/6. So I think the scale factor is ten, because 2/6 x 10/1 will equal 20/6, and 20/6 divided by 10/1 will equal 2/6. Feel free to correct me if I’m wrong though. I’m

The solutions to the equations are;

1) {-2, 1/2}

2) {0, -2}

What is zero product property?

The zero product property is a fundamental property of algebra that states that if the product of two or more factors is equal to zero, then at least one of the factors must be zero. In other words, if a × b = 0, then either a = 0, b = 0, or both a and b are equal to zero.

Using the zero product property;

2x - 1 = 0

x = 1/2

x + 2

x = -2

The solution is;

{-2, 1/2}

Again for x(x + 2) = 0

x = 0

x + 2 = 0

x = -2

The solution is;

{0, -2}

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The number that must be added to both sides of the equation x2 + 12x = 13 so that the method of completing the square can be used to solve the roots is 36. The correct answer is C. 36.

To complete the square, we need to add the square of half the coefficient of the x term to both sides of the equation. In this case, the coefficient of the x term is 12, so half of it is 6. The square of 6 is 36, so we need to add 36 to both sides of the equation. Hence the correct option is C) 36.

The equation then becomes:
x2 + 12x + 36 = 13 + 36

Simplifying the right side of the equation gives us:
x2 + 12x + 36 = 49

Now we can factor the left side of the equation into a perfect square:
(x + 6)2 = 49

From here, we can use the square root property to solve for x:
x + 6 = ±√49

Solving for x gives us:
x = -6 ± 7

So the roots of the equation are x = 1 and x = -13.

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There are 120 different ways to arrange a mother, a father, and their 3 kids in a row.

There are several ways to arrange a mother, a father, and their 3 kids in a row. One way is to use the permutation formula, which is given by:

P = n! / (n - r)!

Where n is the total number of items and r is the number of items to choose from. In this case, n = 5 (mother, father, and 3 kids) and r = 5 (since we are choosing all 5 items).

Plugging in the values into the formula, we get:

P = 5! / (5 - 5)!
P = 5! / 0!
P = 120 / 1
P = 120

Therefore, there are 120 different ways to arrange a mother, a father, and their 3 kids in a row.

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Answer:

How to Fix Congestion?Intersection Improvements Congestion StrategyIntersection ImprovementsPedestrian Connections Congestion StrategyPedestrian ConnectionsParking Management Congestion StrategyParking ManagementManaged (HOV/HOT) Lanes Congestion StrategyManaged (HOV/HOT) LanesLoop Ramps Reducing Left Turns Congestion StrategyLoop Ramps Reducing Left TurnsGrade Separation Congestion StrategyGrade SeparationFlexible Work Hours Congestion StrategyFlexible Work HoursFare Strategies Congestion StrategyFare StrategiesCommuter Rail Congestion StrategyCommuter RailLight-Rail Transit (LRT) Congestion StrategyLight-Rail Transit (LRT)Demand-Response Transit Congestion StrategyDemand-Response TransitLocal Bus Service Congestion StrategyLocal Bus ServiceHeavy Rail Congestion StrategyHeavy RailBottleneck Removal Congestion StrategyBottleneck RemovalAcceleration and Deceleration Lanes Congestion StrategyAcceleration and Deceleration LanesVariable Speed Limits Congestion StrategyVariable Speed LimitsVariable Pricing Congestion StrategyVariable PricingTruck Lane Restrictions Congestion StrategyTruck Lane RestrictionsTruck Incentives & Use Restrictions Congestion StrategyTruck Incentives & Use RestrictionsTrip Reduction Options Congestion StrategyTrip Reduction OptionsTraveler Information Systems Congestion StrategyTraveler Information SystemsTransportation Management Associations Congestion StrategyTransportation Management AssociationsTransit-Oriented Development Congestion StrategyTransit-Oriented DevelopmentTraffic Management Centers Congestion StrategyTraffic Management CentersTemporary Shoulder Use Congestion StrategyTemporary Shoulder UseSmart Growth Design Congestion StrategySmart Growth DesignSignal Operations & Management Congestion StrategySignal Operations & ManagementRoundabouts Congestion StrategyRoundaboutsRoad Weather Management Congestion StrategyRoad Weather ManagementReversible Traffic Lanes Congestion StrategyReversible Traffic LanesRedevelopment & Infill Congestion StrategyRedevelopment & InfillRamp Flow Control Congestion StrategyRamp Flow ControlQueue Warning Congestion StrategyQueue WarningQuadrant Intersections Congestion StrategyQuadrant IntersectionsPay to Drive Off-Peak Congestion StrategyPay to Drive Off-PeakPay-As-You-Drive Auto Insurance Congestion StrategyPay-As-You-Drive Auto InsuranceOne-Way Streets Congestion StrategyOne-Way StreetsMultimodal Transportation Corridors Congestion StrategyMultimodal Transportation CorridorsMultimodal Transportation Centers Congestion StrategyMultimodal Transportation CentersMixed Use Development Congestion StrategyMixed Use DevelopmentMedian U-Turns Congestion StrategyMedian U-TurnsJobs/Housing Balance Congestion StrategyJobs/Housing BalanceIntegrated Corridor Management Congestion StrategyIntegrated Corridor ManagementImproving Street Continuity Congestion StrategyImproving Street ContinuityFreight Rail Improvements Congestion StrategyFreight Rail ImprovementsForm-Based Code Congestion StrategyForm-Based CodeElectronic Toll Collection Systems Congestion StrategyElectronic Toll Collection SystemsDynamic Truck Restrictions Congestion StrategyDynamic Truck RestrictionsDynamic Rerouting Congestion StrategyDynamic ReroutingDiversified Development Patterns Congestion StrategyDiversified Development PatternsDiverging Diamond Interchange Congestion StrategyDiverging Diamond InterchangeContinuous Flow Intersections Congestion StrategyContinuous Flow IntersectionsComplete Streets Congestion StrategyComplete StreetsCompact Development Congestion StrategyCompact DevelopmentCommercial Vehicle Accommodations Congestion StrategyCommercial Vehicle AccommodationsAggressive Incident Clearance Congestion StrategyAggressive Incident ClearanceAdding New Lanes or Roads Congestion StrategyAdding New Lanes or RoadsAccess Management Congestion StrategyAccess ManagementPark-and-Ride Lots Congestion StrategyPark-and-Ride LotsExpress Bus Service Congestion StrategyExpress Bus ServiceDynamic Merge Control Congestion StrategyDynamic Merge ControlCompressed Work Weeks Congestion StrategyCompressed Work WeeksCirculator Bus Transit Congestion StrategyCirculator Bus TransitCarpooling Congestion StrategyCarpoolingBicycle Sharing Congestion StrategyBicycle SharingBicycle and Pedestrian Education Congestion StrategyBicycle and Pedestrian EducationBicycle Lanes Congestion StrategyBicycle LanesAdding New Toll Roads Congestion StrategyAdding New Toll RoadsActive Demand Management Congestion StrategyActive Demand ManagementBus Rapid Transit Congestion StrategyBus Rapid TransitSpecial Event Management Congestion StrategySpecial Event ManagementVanpooling Congestion StrategyVanpoolingTraffic ManagementTravel OptionsSystem ModificationAdditional CapacityConstruction ImprovementsFreightTransitLand Use PlanningActive Traffic ManagementPricing StrategiesBicycle & Pedestrian FacilitiesTechnology

Traffic problems can be solved by implementing various measures such as improving public transportation, promoting carpooling and ridesharing, creating pedestrian-friendly cities, and implementing smarter traffic management systems.

We proceed to explain some actions to solve traffic problems:

Improving public transportation can help reduce the number of cars on the road, thus reducing traffic congestion. This can be done by increasing the number of public buses and trains, as well as improving their reliability and efficiency.Promoting carpooling and ridesharing can also help reduce traffic problems by encouraging people to share rides instead of driving alone. This can be done through incentives such as discounted parking fees for carpoolers and ridesharing apps. Creating pedestrian-friendly cities can also help reduce traffic problems by encouraging people to walk or bike instead of driving. This can be done by implementing bike lanes, pedestrian-only zones, and safer crosswalks. Implementing smarter traffic management systems can help reduce traffic problems by using technology to monitor and control traffic flow. This can be done through the use of sensors, cameras, and smart traffic lights.

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The tangent of <S is 8/15

What is Trigonometry?

Trigonometry is a discipline of mathematics dealing with specific angle functions and their application to calculations. In trigonometry, there are six functions of an angle that are often utilised. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their names and acronyms (csc).

Given:

ST = 68

UT = 60

so, SU = √ST² - UT²

           = √68² - 60²

           = √4624  - 3600

           = √1024

           = 32

So, Tangent of <S = P/ B

tan S = SU / UT

tan S = 32 / 60

tan S = 8/15

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Answer:

-5 - 2sqrt6

Step-by-step explanation:

To simplify (sqrt2+sqrt3)/(sqrt2-sqrt3), we can rationalize the denominator, which involves multiplying both the numerator and denominator by the conjugate of the denominator.

The conjugate of sqrt2-sqrt3 is sqrt2+sqrt3, so we can multiply both the numerator and denominator by sqrt2+sqrt3:

(sqrt2+sqrt3)/(sqrt2-sqrt3) * (sqrt2+sqrt3)/(sqrt2+sqrt3) = ((sqrt2+sqrt3)(sqrt2+sqrt3))/((sqrt2-sqrt3)(sqrt2+sqrt3))

Expanding the numerator and simplifying, we get:

(sqrt2+sqrt3)^2 / (sqrt2^2 - sqrt3^2)

= (2 + 2sqrt2sqrt3 + 3) / (2 - 3)

= (5 + 2sqrt6) / (-1)

= -5 - 2sqrt6

Therefore, (sqrt2+sqrt3)/(sqrt2-sqrt3) simplifies to -5 - 2sqrt6.

The simplest form of the expression (√2 + √3) / (√2 - √3) is - (5 + 2√6).

We have,

To simplify the expression (√2 + √3) / (√2 - √3), we can rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of the denominator.

The conjugate of (√2 - √3) is (√2 + √3).

Multiplying the numerator and denominator by (√2 + √3), we get:

[(√2 + √3) x (√2 + √3)] / [(√2 - √3) x (√2 + √3)]

Expanding both the numerator and denominator:

[(√2 + √3)(√2 + √3)] / [√2 x √2 - √2 x √3 + √3 x √2 - √3 x √3]

Simplifying:

[2 + 2√2√3 + 3] / [2 - 3]

Combining like terms:

[5 + 2√6] / [-1]

Since the denominator is -1, we can multiply both the numerator and denominator by -1 to simplify further:

[5 + 2√6] / 1

Finally, we have:

(5 + 2√6)

Therefore,

The simplest form of the expression (√2 + √3) / (√2 - √3) is - (5 + 2√6).

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The height οf the step is apprοximately 3.106 feet. Thus, οptiοn A is cοrrect.

What is the trigοnοmetry?

Trigοnοmetry is a branch οf mathematics that deals with the relatiοnships between the sides and angles οf triangles.

Tο determine the height οf the step, we need tο use trigοnοmetry. Let's assume that the height οf the step is h feet.

Since the ramp is elevated at an angle οf 15 degrees, we knοw that the sine οf this angle is equal tο the οppοsite side (h) divided by the hypοtenuse (12 feet).

sin(15) = h/12

Tο sοlve fοr h, we can multiply bοth sides by 12:

12 * sin(15) = h

Using a calculatοr, we can apprοximate sin(15) tο be 0.2588. Therefοre:

h ≈ 12 * 0.2588

h ≈ 3.106 feet

Hence, the height οf the step is apprοximately 3.106 feet.

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Complete question:

A 12-foot ramp to be elevated at an angle measuring 15 degrees to be level with a step. Approximately how far from the step should the ramp start?

3.13.911.614.5

Answer:

6

Step-by-step explanation:

simplified and I got 6 because square root of 80 is that

​

√8=√2x2x2

   Im Not Sure If You Needed This Or Not

The answer is value of x when y=25 are 8.33.

The missing variable y varies directly with x, which means that y = kx, where k is a constant.

We can use this equation to find the value of k and then use it to find the value of x when y=25.

First, let's find the value of k:
y = kx
75 = k*25
k = 75/25
k = 3

Now that we know the value of k, we can use it to find the value of x when y=25:
y = kx
25 = 3x
x = 25/3
x = 8.33

Therefore, the value of x when y=25 is 8.33.

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The distance from where you launched the ball to the goal is 52.6 feet.

The goal of this problem is to find the distance x from where you launched the ball to the goal. To do this, we can use the trigonometric function tangent. The tangent of an angle in a right triangle is equal to the opposite side divided by the adjacent side. In this case, the opposite side is the distance from where you scored to the sideline (88.1 feet) and the adjacent side is the distance we are trying to find (x).

So, we can set up the equation:

tan(58.828) = 88.1/x

Next, we can cross multiply to get:

x*tan(58.828) = 88.1

Then, we can divide both sides by tan(58.828) to get:

x = 88.1/tan(58.828)

Using the built-in calculator in the right sidebar, we can plug in the values and make sure the setting is on Deg for degrees. This gives us:

x = 88.1/1.6767

Finally, we can round our answer to the nearest tenth of a foot to get:

x = 52.6 feet

So, the distance from where you launched the ball to the goal is 52.6 feet.

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An EM wave is written line E = E0 sin(kx - ωt) and EM wave equation is written as ∂²E/∂x² = μ₀ε₀∂²E/∂t²

An electromagnetic wave (EM wave) is a type of wave composed of an electric field and a magnetic field that propagate at the speed of light. The equation for an EM wave is given by E = E0 sin(kx - ωt), where E0 is the peak electric field, k is the wavenumber, ω is the angular frequency, x is the position, and t is time.

An ELECTROMAGNETIC WAVE, or EM wave, is a type of wave that travels through space and carries energy from one point to another. EM waves are created when electric and magnetic fields interact with one another. These waves are categorized by their frequency, which determines their energy and their wavelength.

The EM wave equation, also known as the wave equation, is used to describe how EM waves propagate through space. The equation is typically written in the form:

∂²E/∂x² = μ₀ε₀∂²E/∂t²

Where E is the electric field, μ₀ is the permeability of free space, ε₀ is the permittivity of free space, x is the position, and t is the time. This equation shows how the electric field changes over time and space, and is used to predict the behavior of EM waves.

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Two famous structures/ inventions showing angles formed by secants and tangents are: The London Eye and The Eiffel Tower.

1. The London Eye: The London Eye is a giant Ferris wheel located on the South Bank of the River Thames in London. It is a popular tourist attraction and an iconic symbol of London. The London Eye has 32 oval-shaped capsules, each of which can carry up to 25 people. The structure is made up of several secants and tangents, which form angles at various points along the wheel.

2. The Eiffel Tower: The Eiffel Tower is a wrought-iron lattice tower located on the Champ de Mars in Paris, France. It is one of the most recognizable structures in the world and a symbol of France. The Eiffel Tower is made up of several secants and tangents, which form angles at various points along the structure.

Both of these structures are examples of how secants and tangents can be used in the design of famous structures and inventions. These angles play a crucial role in the stability and strength of the structures, allowing them to withstand the weight of the people and objects they hold.

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The standard deviation of the given data set is 825.87.

How to find standard deviation

The standard deviation of a data set is a measure of how spread out the data is from the mean (average) of the data set. It is calculated using the following formula:

Standard Deviation = √(Σ(x - mean)^2 / n)

Where:

- x is each individual data point

- mean is the average of the data set

- n is the number of data points in the data set

- Σ is the sum of all the values

To calculate the standard deviation of the given data set, we first need to calculate the mean:

Mean = (200 + 1200 + 300 + 350 + 500 + 55 + 10 + 500 + 800 + 850 + 1300 + 2000 + 2100 + 340 + 760 + 830 + 2670 + 9 + 3000) / 20 = 833.45

Next, we need to calculate the sum of the squared differences between each data point and the mean:

Σ(x - mean)^2 = (200 - 833.45)^2 + (1200 - 833.45)^2 + ... + (3000 - 833.45)^2 = 1.365E7

Finally, we can calculate the standard deviation:

Standard Deviation = √(1.365E7 / 20) = 825.87

Therefore, the standard deviation of the given data set is 825.87.

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Answers
∠ OKL = 45

∠ MOL = 90

Explanation

All interior angles of a square equal to 90 degrees. All right angles are 90 degrees.

∠ OKL is a right angle (90 degrees) bisected in half, so it is 45.

∠ MOL is an interior angle so it is 90 degrees

We have saved approximately 15% of the total cost.

What is the process to calculate the percentage saved in a sale?

When items are on sale, they are usually offered at a discounted price. The percentage saved is a measure of the amount that a buyer has saved on the original price of the item. The process to calculate the percentage saved in a sale involves determining the original price, the discounted price, and then using a formula to find the percentage saved.

The formula for the percentage saved is:

Percentage saved = (Amount saved / Original price) x 100%

Calculation of  the total amount saved and the percentage saved :

For the paperbacks, the original price is $9 each and we bought four of them, so the total original price is:

$9/book × 4 books = $36

With a 10% discount, the discounted price of each paperback is:

$9/book × 0.10 = $0.90 discount

$9/book - $0.90 discount = $8.10 discounted price

So, the total discounted price for the four paperbacks is:

$8.10/book × 4 books = $32.40

Therefore, we saved:

$36 - $32.40 = $3.60

For the hardbacks, the original price is $20 each and we bought two of them, so the total original price is:

$20/book × 2 books = $40

With a 20% discount, the discounted price of each hardback is:

$20/book × 0.20 = $4 discount

$20/book - $4 discount = $16 discounted price

So, the total discounted price for the two hardbacks is:

$16/book × 2 books = $32

Therefore, we saved:

$40 - $32 = $8

The total original price of all the books is:

$36 + $40 = $76

The total discounted price of all the books is:

$32.40 + $32 = $64.40

Therefore, we saved:

$76 - $64.40 = $11.60

Plugging in the values , we get:

percentage saved = ($11.60 / $76) × 100%

percentage saved ≈ 15%

Therefore, we have saved approximately 15% of the total cost.

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You are a quadratic polynomial, specifically an equation of the form ax² + bx + c = 0, where a is not equal to 0, and one of the terms, c, is negative. The polynomial can be written as ax² - dx + c = 0, where d is the coefficient of the positive term.

A polynomial is an expression that consists of a combination of constants, variables, and exponents. A polynomial with three unlike terms is called a trinomial. A 2nd degree polynomial is also known as a quadratic polynomial.

Based on the given information, the polynomial can be written in the form: ax² + bx + c, where a, b, and c are constants, and x is the variable. Since only one of the terms is negative, either a, b, or c must be negative.

There are several possible answers to this question, as there are multiple combinations of constants that can fit the given criteria. Here are three possible answers:

1. 2x² + 3x - 4
2. -x² + 5x + 6
3. 4x² - 2x + 1

All of these polynomials have three unlike terms, are 2nd degree polynomial, and have only one negative term.

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Answer:

333 ft^2

Step-by-step explanation:

To find the area of the new dance floor, use the trapezoid area formula.

Area of a Trapezoid: [tex]\frac{(base 1+base 2)h}{2}[/tex]

[(18 1/2 + 18 1/2) · 18]/2 - Plug in values

(37x18)/2 - Simplify

333 ft^2 - Solve

The expression when factored by the GCF is 6x(x - 2y + 3y^2)

How to factor the expression by the GCF

From the question, we have the following parameters that can be used in our computation:

6x^2 - 12xy + 18xy^2

The greatest common factor (GCF) of 6x^2, -12xy, and 18xy^2 is 6x, which is the largest number that divides each term evenly.

To factor the polynomial by factoring out the GCF, we can divide each term by 6x to get:

6x^2/6x = x

-12xy/6x = -2y

18xy^2/6x = 3y^2

So the polynomial can be factored as:

6x^2 - 12xy + 18xy^2 = 6x(x - 2y + 3y^2)

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To solve the given linear system, we can use the Gaussian elimination method. This method involves reducing the given matrix to a row echelon form and then solving for the variables using back substitution.

Step 1: Reduce the given matrix to a row echelon form by performing elementary row operations.
\[ \left[\begin{array}{rrr|r} 6 & 2 & -3 & 0 \\ -5 & 3 & 9 & 0 \\ 2 & -7 & -1 & 0 \end{array}\right] \]
We can start by dividing the first row by 6 to get a leading 1:
\[ \left[\begin{array}{rrr|r} 1 & \frac{1}{3} & -\frac{1}{2} & 0 \\ -5 & 3 & 9 & 0 \\ 2 & -7 & -1 & 0 \end{array}\right] \]
Next, we can add 5 times the first row to the second row and subtract 2 times the first row from the third row:
\[ \left[\begin{array}{rrr|r} 1 & \frac{1}{3} & -\frac{1}{2} & 0 \\ 0 & \frac{16}{3} & \frac{17}{2} & 0 \\ 0 & -\frac{23}{3} & 0 & 0 \end{array}\right] \]
Finally, we can multiply the second row by $\frac{3}{16}$ and the third row by $-\frac{3}{23}$ to get a leading 1 in each row:
\[ \left[\begin{array}{rrr|r} 1 & \frac{1}{3} & -\frac{1}{2} & 0 \\ 0 & 1 & \frac{51}{32} & 0 \\ 0 & 1 & 0 & 0 \end{array}\right] \]

Step 2: Use back substitution to solve for the variables.
From the third row, we have:
$x_2 = 0$
Substituting this into the second row gives us:
$x_3 = 0$
And substituting these values into the first row gives us:
$x_1 = 0$
Therefore, the solution to the given linear system is:
$x_1 = 0$, $x_2 = 0$, and $x_3 = 0$

This means that the given linear system has a unique solution at the origin.

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Given vectors are, u = (6,1,6), v = (1,-1,4) and w = (1,4,7) and a vector (23, 10, 23).We need to express (23, 10, 23) as a linear combination of u, v and w.

To find the coefficients, we use matrix notation.
Let A be a matrix containing u, v and w as its column matrices, and X be a matrix containing the coefficients.
Then,AX = B Where A = [u | v | w]X = [a | b | c]B = (23, 10, 23)
Therefore, [u | v | w][a | b | c] = (23, 10, 23)⇒ a(u1) + b(v1) + c(w1) = 23a(6) + b(1) + c(1) = 23⇒ 6a + b + c = 23⇒ a(u2) + b(v2) + c(w2) = 10a(1) - b(1) + c(4) = 10⇒ a - b + 4c = 10⇒ a(u3) + b(v3) + c(w3) = 23a(6) - b(4) + c(7) = 23⇒ 6a - 4b + 7c = 23
The above system of linear equations can be solved using Gaussian elimination method.
The row echelon form of the augmented matrix [A | B] is, [6 1 1 | 23][1 -1 4 | 10][0 0 2 | 9]
The solution is, c = 9/2, b = -3, and a = 1/2.
Therefore, (23, 10, 23) = (1/2)u - 3v + (9/2)w can be written as a linear combination of u, v and w.

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Point c means that Danny spent $80 dollars on tickets for 5 games . then the unit rate can be represented by the point (5, 80) on the graph.

Explain about the rate of change?

The term "rate of change" (ROC) describes the rate at which something evolves over an extended period.

So, it is not the amount of specific features themselves but rather the deceleration or acceleration of changes (— in other words, the rate).Technically speaking, the Price Rate of Change marker calculates the percentage difference in price between the present price and the price from a predetermined number of periods ago.Since it enables investors to identify trends and other trends, rate of change is a crucial financial term.

Danny purchases the same number of tickets for every baseball game he attends during the summer, and the graph below shows how much was spent on the X Games in dollars.

Thus, point c means that Danny spent $80 dollars on tickets for 5 games . then the unit rate can be represented by the point (5, 80) on the graph.

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the complete question is attached.

Answer:

x < 5

Step-by-step explanation:

2x - 3 < x + 2 ≤ 3x + 5

2x - 3 < x + 2 and x + 2 ≤ 5

x < 5 and x ≤ 3

Answer: x < 5

Large corporations often offer better benefits and opportunities for career advancement.

Large corporations often have more resources available for employee training and development.

I would prefer to work for a large corporation for two reasons. First, large corporations often offer better benefits and opportunities for career advancement. Second, large corporations often have more resources available for employee training and development. While working for a small business whose owners I know may provide a more personal and intimate work environment, I believe that the benefits of working for a large corporation outweigh the potential drawbacks.

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That the complex number 5-i is indeed a solution of the equation [tex]x^2-10x+26=0[/tex].

To determine whether the complex number 5-i is a solution of the equation [tex]x^2-10x+26=0[/tex], we can substitute the value of x with the complex number and see if the equation holds true.

Substituting [tex]x = 5-i[/tex] into the equation:

[tex](5-i)^2 - 10(5-i) + 26 = 0[/tex]

Expanding the squared term:

[tex]25 - 10i + i^2 - 50 + 10i + 26 = 0[/tex]

Simplifying the equation:

[tex]25 - 50 + 26 + i^2 = 0[/tex]

Since[tex]i^2 = -1[/tex], we can substitute that value into the equation:

[tex]25 - 50 + 26 - 1 = 0[/tex]

Simplifying further:

[tex]0 = 0[/tex]

Since the equation holds true, we can conclude that the complex number 5-i is indeed a solution of the equation [tex]x^2-10x+26=0[/tex].

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Using midpoints, The length of RY is (9x - 1)/2 cm.

What is the midpoint?

A midpoint is a point that is exactly halfway between two other points. In geometry, the midpoint of a line segment is the point on that line segment that is equidistant from both endpoints.

For example, in a line segment AB, the midpoint M is the point on AB that is equidistant from A and B. In other words, the distance from A to M is the same as the distance from M to B. The midpoint M is located at the exact center of line segment AB, and it divides the segment into two equal parts.

The midpoint can also be thought of as the average of the x-coordinates and y-coordinates of the endpoints. For a line segment with endpoints (x1, y1) and (x2, y2), the midpoint has coordinates:

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Since R is the midpoint of XY, we know that RX = RY.

We are given that XR = 5x+2 cm and XY = 14x+1 cm.

Thus, RX + RY = XY

Substituting RX = RY, we get:

RY + RY = 14x + 1 - (5x + 2)

Simplifying the right side, we get:

RY + RY = 9x - 1

2RY = 9x - 1

RY = (9x - 1)/2

Therefore, the length of RY in cm is (9x - 1)/2.

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The domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).

The function f(x)=(x+3)² is not one-to-one, as it is a quadratic function and has a parabolic shape. However, we can restrict the domain of the function so that it is one-to-one and increasing. One way to do this is to restrict the domain to be greater than or equal to the x-coordinate of the vertex of the parabola. The vertex of the parabola is at (-3, 0), so we can restrict the domain to be x ≥ -3. In interval notation, this is [-3, ∞).

The inverse function of f(x) can be found by switching the x and y values and solving for y. This gives us:

x = (y+3)²

√x = y+3

y = √x - 3

So the inverse function is f⁻¹(x) = √x - 3. The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function. Therefore, the domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).

In summary:

f(x)'s domain: [-3, ∞)

f⁻¹(x)'s domain: [0, ∞)

f(x)'s range: [0, ∞)

f⁻¹(x)'s range: [-3, ∞)

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Answer:

C. Exchange the $100 bill for ten $10 bills.

Since the money is to be divided among 4 people, it is easier to divide it if the money is in equal denominations. Therefore, the first step should be to exchange the $100 bill for ten $10 bills, so that each person can receive an equal share of $25. This way, we can avoid having to deal with different denominations while dividing the money among the four people.

Epidemiology would include option (a), (c), and (d).

Epidemiology is the study of the distribution and determinants of health-related states or events in specified populations, and the application of this study to the control of health problems (JM. A Dictionary of Epidemiology, 2001). According to this definition, Epidemiology would include the following activities:

Option (a): Describing the demographic characteristics of persons with acute aflatoxin poisoning in Chittagong: This activity fits with the definition of Epidemiology because it involves studying the characteristics of a specified population, in this case the demographic characteristics of persons with acute aflatoxin poisoning in Chittagong, in order to better understand the determinants and distribution of the health-related state (acute aflatoxin poisoning).

Option (c): Comparing the family history, amount of exercise, and eating habits of those with and without newly diagnosed diabetes: This activity fits with the definition of Epidemiology because it involves studying the determinants of a health-related state, in this case newly diagnosed diabetes, in order to better understand the distribution and control of this health problem.

Option (d): Recommending that 'Kashundi restaurant' in IUB be closed after implicating it as the source of a hepatitis A outbreak: This activity fits with the definition of Epidemiology because it involves applying the study of the distribution and determinants of health-related states to the control of health problems, in this case the control of a hepatitis A outbreak.

In summary, Epidemiology would include option (a), (c), and (d).

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