A compound is composed of carbon and hydrogen and has an empirical
formula of CH. The molar mass of the compound is experimentally
determined to be 78.12 g/mol. What is the molecular formula for the
compound?

The enthalpy of the reaction from the bond energy is +102 kJ/mol. Option C

We have to note that the enthalpy would have to do with the energy that ahs been absorbed or the energy that is released in a reaction. We know that if there is a release of energy then we can say that the reaction is exothermic but if we have a case where the energy has been taken in then we can say that the reaction in that case can be said to be exothermic.

We can see that the enthalpy of the reaction can be calculated on the basis of the bond energy when we write;

Energy of bonds that are broken - Energy of bonds that are formed.

[4(410) + 2(496)] - [2(805) + 2(460)]

(1640 + 992) - (1610 + 920)

2632 - 2530

= +102 kJ/mol

Hence, by calculation of the enthalpy bof the reaction, we can see that the reaction would absorb about 102 kJ of heat per mole of the reactant as shown.

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25 grams of a substance is equivalent to 0.0088 moles. To calculate the number of moles, the following equation can be used:

Number of moles = mass (in grams) / molar mass

The molar mass is the mass of 1 mole of a substance and is expressed in grams/mol. It is equal to the sum of the atomic masses of all the atoms in a molecule.

To calculate the number of moles from 25 grams, the molar mass of the substance must be known. Once the molar mass is known, the equation can be used to calculate the number of moles.

For example, if the substance is sodium chloride (NaCl), the molar mass is 58.44 g/mol. Applying the equation above, the number of moles can be calculated as 25 g / 58.44 g/mol = 0.0088 moles.

In conclusion, 25 grams of a substance is equal to 0.0088 moles. The molar mass of the substance must be known to calculate the number of moles from a given mass.  Once the molar mass is known, the equation can be used to calculate the number of molecules.

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One of the lab groups unintentionally left a beaker with 1.00 M1.00 M of NaOH solution out on the lab table over night. The molarity of the solution is 3.00 M after evaporation.

The total moles of solute contained in a given volume of solution is referred to as a solution's molarity. In this case, "M" stands for molarity, "n" is the number of moles of solute present in the solution, and "V" is the volume of solution present in a container. A unique kind of homogenous mixture made up of two or more components is known as a solution in chemistry. A solute, or substance that is dissolved in a solvent, is one of the components of such a mixture.

Moles = 1.00/1/3 Moles = 3.00 M

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Answer:

37 - Rubidium - Rb

Explanation:

In scientific notation, the result of multiplying an integer between 1 and 10 by a power of 10 is written.For instance, 650,000,000 can be represented as 6.5 108 in scientific notation.

Always set the base to 10. The exponent must be an integer that is non-zero, therefore it can either be positive or negative. The absolute value of the coefficient must be less than ten and more than one.

a system of symbols for designating unique items. Example: In mathematics, the symbol "" stands for "infinity." There are many notations in mathematics.

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The triple point of a substance is the temperature and pressure at which all three phases of the substance (solid, liquid, and gas) can coexist in equilibrium.

Point B on the phase diagram is the triple point for Bogusium, represented by the intersection of three lines, which indicates that all three phases can coexist in equilibrium at this point.

1. A triple point of a substance is the temperature and pressure at which all three phases of the substance can coexist in equilibrium.

2. Point B on the phase diagram is the triple point for Bogusium, represented by the intersection of three lines.

3. This indicates that all three phases can coexist in equilibrium at this point.

4. Therefore, the correct statement is that Point B represents the triple point for Bo.

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A measuring stick called meterstick or yardstick.

A meterstick or yardstick is either a foldable ruler or straightedge which is used to measure the length and it is specially common in the construction industry. Meterstick are made up of plastic or A measuring stick called meterstick or yardstick.  

A meterstick or yardstick is either a foldable ruler or straightedge which is used to measure the length and it is specially common in the construction industry. Meterstick are made up of plastic or wood and they often have a metal or plastic joints so that they can be folded together. Metersticks are often rectangular and thin. Metersticks are divided with lines for each millimeter and numerical markings per centimeter. Whereas, yardsticks are often marked with a scale in inches. Measuring stick is also known as ruler. For example: We measure the diameter of a circle with a ruler, and also draw a perfectly straight line using its edge.

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Answer:

5.55 L

Explanation:

This excersise can be solved by the Boyle's law.

This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.

P₁ . V₁  = P₂ . V₂

The law comes from the Ideal Gases Law, in the first term.

P . V = n . R . T  In this case, n . R . T are all constant.

6.35 L . 88.6 kPa = 101.3 kPa . V₂

V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa

V₂ = 5.55 L

It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.

Answer:

Pressure = 29.0 psi

Explanation:

Step 1: Given data

Required pressure in the tires (P): 200 kiloPascal

Step 2: Convert the required pressure in the tires to pounds per square inch (psi)

To convert kPa to psi, we need a conversion factor. In this case, we will use the conversion factor 1 psi = 6.89 kPa.

200 kPa × (1 psi/6.89 kPa) = 29.0 psi

200 kPa is equal to 29.0 psi.

The organocopper and inorganic ion by-products are not shown in this structural formula.

CH3CH=CH2Li

1. The reaction starts with CH3CH2CH2Br, which is a bromoalkane.

2. The bromine atom is replaced by a lithium atom with the help of two equivalents of copper.

3. The resulting product is CH3CH=CH2Li, which is an alkenyllithium compound.

CH3CH=CH2Li

The reaction starts with CH3CH2CH2Br, a bromoalkane. The bromine atom is replaced by a lithium atom with the help of two equivalents of copper. This is done via a nucleophilic substitution reaction, where the copper serves as a Lewis acid to facilitate the reaction. The resulting product is CH3CH=CH2Li, an alkenyllithium compound. This is the major organic product of the reaction and it has an E/Z stereochemistry. The organocopper and inorganic ion by-products are not shown in this structural formula.

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Answer:

467 nm is the answer

Explanation:

IT'S the answer for

Answer:We want the enthalpy associated with the reaction.........

Explanation:

H

3

CCH

2

OH

(

l

)

+

Δ

→

H

3

CCH

2

OH

(

g

)

You have a mass of

50.0

⋅

g

EtOH

, that is assumed to be at

78.3

∘

C

, and the enthalpy of vaporization is calculated by the product:

Δ

H

∘

vaporization

=

50.0

⋅

g

46.07

⋅

g

⋅

m

o

l

−

1

×

38.6

⋅

k

J

⋅

m

o

l

−

1

=

Explanation:

A gas law known as Gay-law Lussac's asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature

A gas law known as Gay-law Lussac's asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. In other words, while the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas.

In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-law Lussac's can be expressed mathematically as follows:

P ∝ T ; P/T = k

Where:

P is the pressure that the gas is applying.

T is the gas's actual temperature, while k is a fixed value.

The tire pressure of a car increases after driving. This is due to the air inside the tires heating up as a result of friction (a contact force) between the tires and the road. Gay-Law Lussac's states that because the air cannot expand because the tires are effectively fixed-volume containers, the pressure rises.

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Rounded to the nearest significant figure, [tex]\rm 1.5 \times 10^{23 }[/tex] molecules are in 0.25 mole of [tex]\rm CO[/tex]. The correct answer is option B.

A mole is defined as the amount of a substance that contains exactly      [tex]\ \rm 6.022 \times 10^{23}[/tex] 'elementary entities' of the given substance.

To calculate the number of molecules in 0.25 mole of CO, we can use Avogadro's number, which is the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately  [tex]\ \rm 6.022 \times 10^{23}[/tex] particles per mole.

Number of molecules = Number of moles x Avogadro's number

Substituting the given values, we get:

Number of molecules = 0.25 mole x [tex]\ \rm 6.022 \times 10^{23}[/tex] molecules/mole

=  [tex]\rm 1.5 \times 10^{23 }[/tex]

Therefore, the number of molecules in 0.25 mole of CO is approximately  [tex]\rm 1.5 \times 10^{23 }[/tex] molecules. Option B is the correct answer.

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Answer:

answer is option 2 hope it helps

The step that must be occurred in the calculation of the enthalpy of the given reaction is option B, reverse the second equation, and change the sign of the enthalpy, then add.

The enthalpy of a reaction is the heat energy absorbed or released by the reaction system. For a reaction, the reaction enthalpy can be calculated using the enthalpies of the component reactions.

Here the overall reaction is the formation of CO and H₂ from C and water. The first step is to reverse the second equation and change sign of enthalpy and double the first equation. Then add them, so that the CO₂ get eliminated.

Then, the resultant equation is halved again. Then divide the third equation by two and its enthalpy value also divided by 2. Then add it to the previous one and we get the net equation and corresponding reaction enthalpy.

Therefore, the step that must occur here is option B.

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Answer:

White color

Explanation:

This compound when heated losses its water of crystallization and become anhydrous copper sulphate

Answer:

its correct answer is 22.4 grams

Answer:

no

Explanation:

The molar mass of H2SO4 is 98.08 g/mol. It is a combination of hydrogen with molecular weight of 1g, sulfur with 32g and oxygen with 16g and the total combination is 2x1+1x32+4x16 = 98g.

Humanity has been aware of oil of vitriol for thousands of years. The chemical name for this material is sulfuric acid, and its molecular formula is H2SO4. It is made up of sulfur, oxygen, and hydrogen molecules. Strong and hygroscopic sulfuric acid (H2SO4) has oxidizing and hygroscopic characteristics. Because it was made by roasting "green vitriol" (iron(II) sulfate) in an iron retort, sulfuric acid was known as "oil of vitriol" by medieval European alchemists. Due to its oily appearance and occurrence in vitreous or glassy substances like ferrous sulphate and alum, it is also known as the "oil of vitriol."

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Answer:

Hydrological plant is a process in which plants needs water to complete the process to produce glucose in the presence of CO2 ,sunlight .plants needs water to survive .

If you perform a melting point test on a metal sample, you would expect to observe that the metal has a relatively high melting point compared to non-metallic materials. This is because of the strong electrostatic forces between the positive nuclei of the metal atoms and the negative electrons, which hold the metal atoms together in a tightly packed lattice structure. As a result, a large amount of energy is required to overcome these forces and melt the metal.

Metal samples are expected to be excellent conductors of heat and electricity when a conductivity test is performed on them. This is because electrons in metallic solids move through the metal fairly easily and are free to move around the lattice structure. This free movement of electrons allows heat and electricity to easily pass through the metal, making it highly conductive.

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Equation I cannot be divided by another factor as it will introduce errors in the equation.

Errors in chemical analysis result when there is a difference between observed value and the true value.If the magnitude of errors is large , it results in decrease in accuracy, reproducibility, and precision.

There are three types of errors:1) random error 2) systematic error 3) human error.The cause of random errors are difficult to quantify while the human errors can be minimized by taking a range of readings to reduce the error.

Errors while measuring boiling point may be human errors while noting down the boiling temperature or instrumental or systematic error if there is a fault in the thermometer.

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As with any laboratory work, adequate facility design, operation, and monitoring, as well as excellent work practices, are necessary to protect laboratory staff against the hazard.

Both degrees of protection are based on the principle of ALARA (as little as reasonably possible) exposure. Electricity Risks By adopting adequate measures, the electrocution dangers of electrically powered instruments, tools, and other equipment are nearly completely minimized, therefore their use in the hazard need not represent a serious risk. You need the correct sort of scales if you want to weigh laboratory samples accurately. To accurately weigh the lab samples, for instance, you may use an analytical balance. The reliability of the weighing device will determine how accurate and precise the findings are.

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To solve this we must be knowing each and every concept related to   ideal gas equation. Therefore, the pressure when the volume is doubled is  3atm.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

rearranging the above equation, we get

P₁V₁= P₂V₂

{ (6atm) (10dm[tex]_3[/tex])}  ={ ( P₂) (20dm[tex]_3[/tex])}

P₂ = 3atm

Therefore, the pressure when the volume is doubled is  3atm.

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Answer: NOT a base

Explanation: i just took the exam and got this one wrong but i donno the correct answer between the last 3 good luck bb

Answer:

A catalyst

Explanation:

Catalysts make reaction faster and speed up the reaction time.

For the homogeneous solution consisting of KCl and H₂O,  the type of forces that are involved is the dipole-dipole forces, the ion-dipole forces dispersion forces, the hydrogen bonding.

In the homogeneous solution if the two compounds are KCl and H₂O, they both polar and the forces involved are dipole - dipole forces and the dispersion forces. the forces present in between the water molecules is the hydrogen bonding. the forces in between the K⁺ and the Cl⁻ present is the ion - dipole forces,

Thus the all the four forces present in the homogeneous solution of the KCl and H₂O that is the dipole-dipole forces, the ion-dipole forces, the dispersion forces, and the hydrogen bonding.

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Diatomic elements are important because they make up a significant portion of the Earth's atmosphere and are crucial for many biological and chemical processes.

Diatomic elements are elements that exist in nature as molecules made up of two atoms of the same element, such as H2, O2, N2, and F2.

A diatomic atom is one that cannot exist on its own. There are no single O atoms floating around in the sky. Because O atoms must exist in pairs, oxygen occurs as O2. These atoms are too unstable to live on their own.

This elements are different from other elemental substances because they are composed of multiple atoms of the same element, rather than a single atom or a mixture of different elements.

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The specific heat capacity of the metal is 35.34 J/g/°C, if the specific heat capacity of the water is 4.18 J/g/°C.

Volume of water = 200 ml

Density of water = 1 gm/ml

So the mass of the water in coffee cup, m₁ = 200×1 = 200 gm

Initial temperature of water, T₁ = 22.1°C

Specific heat capacity of water, S₁ = 4.18 J/g/°C

Mass of the metal, m₂ = 5.1 gm

Initial temperature of the metal, T₂ = 48.6°C

Final combined temperature of both, T = 26.8°C

Let the specific heat capacity of the metal = S₂

Heat gain by the water = heat loss in the metal

S₁ × m₁ × (T-T₁) = S₂ × m₂ × (T₂-T)

4.18 × 200 × (26.8-22.1) = S₂ × 5.1 × (48.6-26.8)

3929.2 = S₂ × 111.18

S₂ = 3929.2/111.18

S₂ = 35.34 J/g/°C

So, the specific heat capacity of the metal is 35.34 J/g/°C.

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The student is to weigh out 94.5g of glycerol in accordance with the provided statement.

Glycerin is a kind of carbohydrate known as a polyol, along with other sugar alcohols including sorbitol and erythritol. Glycerin has a complex taste, but unlike sugar I've already discussed—it is not absorbed by the body as sugar and does not raise blood sugar levels. Glycerol may be safe for short-term treatment when taken orally. Headaches, lightheadedness, bloat, nausea, and diarrhea are possible side effects. Glycerol appears to be safe when used topically. It might result in burning, itching, and redness.

1mL = 1cm³

Quantity = 75mL = 75cm³

1.26 g/cm³ is the density.

Mass = ?

Mass is equal to the product of volume and density.

Mass = 1.26 * 75 = 94.5g

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The complete question is-

A chemistry student needs 75.0 mL of glycerol for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of glycerol is 1.26 g.cm⁻³. Calculate the mass of glycerol the student should weigh out. Be sure your answer has the correct number of significant digits.

22.2 seconds will it take to selectively plate out of the cations current of 5.0 Amperes.

E∘cell=E∘cathode−E∘anode it is the formula for finding out the net cell potential of the electrolytic cell. We can write the cell reaction to solve the problem in the following way

1. Write down the (two half) reactions.

2. Balance the (half) reactions (Mass and Charge):

a. Start with elements other than H and O. b. Balance O by adding water.

c. balance H by adding H+.

d. Balancing charge by adding electrons.

(3. Multiply each half reaction to make the number of electrons equal.

4. Add the reactions and simplify.)

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