A company has recently been hiring new employees. Today the company has 32% more employees than it did a year ago. If there are currently 69,300 employees, how many employees did the company have a year ago?​

Answers

Answer 1

Answer:

52500

Step-by-step explanation:

Let there be x employees in the previous year

Now, the company has 32% more employees whis is 69300

i.e.

[tex]x + \frac{32}{100} x = 69300\\\\ \implies\frac{132x}{100} = 69300 \\\\\implies 132x = 6930000\\\\\implies x = \frac{6930000}{132}\\[/tex]

⇒ x = 52500

There were 52500 employees in the previous year


Related Questions

Which of the following lists of ordered pairs is a function?

Answers

The list of ordered pairs that is a function is Option D.

What is a Math Function?

A math function is a relationship that assigns a unique output value to each input value. It describes how one quantity depends on another.

Functions are commonly represented using mathematical notation, such as f(x), and they play a fundamental role in various areas of mathematics and its applications.

A  function is a relation in which one input (x-value) is assigned to exactly one output (y-value).

Since option D's x-values do not repeat, then it is a function.

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I don’t understand can I get answers please

Answers

Answer:

c=25

Step-by-step explanation:

Since you are given [tex]x^{2}[/tex]+10x+c

We know that in an equation of [tex]ax^{2}+bx+c[/tex], when a = 1, c can be found by [tex](\frac{b}{2})^{2}[/tex]

So c = [tex](10/2)^{2}[/tex]=[tex]5^{2}[/tex]=25

Si 3,390 kg de plomo ocupan un volumen de 0.3m3. Encuentra la densidad del plomo

Answers

The density of lead is 11.3 kg/m³.

The density of lead can be calculated by using the formula D = M/V, where D represents density, M represents mass and V represents volume. The density of lead is the ratio of the mass of lead to the volume occupied by it.

Density of Lead:

Given that the lead has a mass of 3.390 kg and occupies a volume of 0.3 m³.

Density of Lead (D) = Mass of Lead (M) / Volume of Lead (V)D = 3.390 kg / 0.3 m³D = 11.3 kg/m³

Therefore, the density of lead is 11.3 kg/m³.

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find the inverse of each function

Answers

Answer:

Step-by-step explanation:

Margie's work for adding linear expressions is shown below. After checking her answer with the answer key, she solved it incorrectly.


Given (−2.67b + 11) − (5.38b − 15)
Step 1 −2.67b + 11 + (−5.38b) + 15
Step 2 −2.67b + 5.38b + 11 + 15
Step 3 (−2.67b + 5.38b) + (11 + 15)
Step 4 2.71b + 26


Part A: Identify and explain the first step where Margie made an error. (2 points)

Part B: Explain how to correctly write the expression in fewest terms by correcting the error in Part A. Show all work. (2 points)

Answers

Step-by-step explanation:

Part A: The first step where Margie made an error is Step 1:

−2.67b + 11 + (−5.38b) + 15

The error lies in the addition of the two terms: (−5.38b) + 15. Margie incorrectly added the two terms together instead of subtracting them.

Part B: To correctly write the expression in the fewest terms, we need to correct the error from Part A. The correct step-by-step process is as follows:

Given: (−2.67b + 11) − (5.38b − 15)

Step 1: Distribute the negative sign to the terms inside the second parentheses:

−2.67b + 11 − 5.38b + 15

Step 2: Combine like terms:

(−2.67b − 5.38b) + (11 + 15)

Step 3: Simplify:

−7.05b + 26

Therefore, the correct expression, written in the fewest terms, is −7.05b + 26.

PLEASE I NEED HELP I DONT UNDERSTAND THIS

Answers

the simplified expression would be:

-5p(3r) = -5 * 3 * p * r = -15pr

So, the simplified form of -5p(3r) is -15pr.

two points A and B, due to two spheres X and Y 4.0m apart, that are carrying charges of 72mC and -72mC respectively. Assume constant of proportionality as 9×10^9Nm²/C². Find the electric field strength at points A and B due to each spheres presence​

Answers

Point B: Electric field strength due to sphere X = 2073.6 NC⁻¹ and Electric field strength due to sphere Y = -2073.6 NC⁻¹.

data: Spheres X and Y are 4.0 m apart. The charge on sphere

X = + 72 mC = 72 × 10⁻³ C.

The charge on sphere

Y = -72 mC = -72 × 10⁻³ C.

The constant of proportionality = 9 × 10⁹ Nm²/C².

The formula to calculate the electric field strength due to a point charge is

E = k q / r²

where E is the electric field strength, k is the Coulomb's constant (= 9 × 10⁹ Nm²/C²), q is the magnitude of the charge, and r is the distance from the charge.The electric field due to sphere X at point A is

EaX = [tex]k q / r²where r = 4.0 m, q = + 72 × 10⁻³ CSo, EaX = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaX = 9 × 9 × 2 × 2 × 2 × 2 / 10[/tex]EaX = 2592 / 10EaX = 259.2

NC⁻¹The electric field due to sphere Y at point A is

[tex]EaY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ CSo, EaY = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaY = -9 × 9 × 2 × 2 × 2 × 2 / 10EaY = -2592 / 10EaY = -259.2[/tex]

NC⁻¹The electric field due to sphere X at point B is

[tex]EbX = k q / r²where r = 4.0 m, q = + 72 × 10⁻³ C + 72 × 10⁻³ C = 144 × 10⁻³ C.So, EbX = 9 × 10⁹ × 144 × 10⁻³ / (4.0)²EbX = 9 × 9 × 4 × 4 × 4 × 4 / 10EbX = 20736 / 10EbX = 2073.6[/tex]

NC⁻¹The electric field due to sphere Y at point B is

[tex]EbY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ C - 72 × 10⁻³ C = -144 × 10⁻³ C. So, EbY = 9 × 10⁹ × -144 × 10⁻³ / (4.0)²EbY = -9 × 9 × 4 × 4 × 4 × 4 / 10EbY = -20736 / 10EbY = -2073.6 NC⁻¹[/tex]

Therefore, the electric field strength at points A and B due to each sphere's presence are: Point A: Electric field strength due to sphere X = 259.2 NC⁻¹ and Electric field strength due to sphere Y = -259.2 NC⁻¹.

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Find the indefinite integral. (Use C for the constant of integration.)
1. v + 1/
(2v − 20)^5dv

2. x^2/
x − 5 dx

3. x cos 8x2 dx
4. 176/e^−x + 1 dx
5.

Answers

1. The indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.

2. The indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.

3. The indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.

4. The indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.

1. To find the indefinite integral of (v + 1) / (2v - 20)^5 dv:

Let u = 2v - 20. Then du = 2 dv.

The integral becomes:

(1/2) ∫ (1/u^5) du

Now we can integrate using the power rule:

(1/2) ∫ u^(-5) du

Applying the power rule, we get:

(1/2) * (u^(-4) / -4) + C

= -1 / (8u^4) + C

Substituting back u = 2v - 20:

= -1 / (8(2v - 20)^4) + C

Therefore, the indefinite integral of (v + 1) / (2v - 20)^5 dv is -1 / (8(2v - 20)^4) + C.

2. To find the indefinite integral of x^2 / (x - 5) dx:

We can use polynomial long division to simplify the integrand:

x^2 / (x - 5) = x + 5 + 25 / (x - 5)

Now we can integrate each term separately:

∫ x dx + ∫ (5 dx) + ∫ (25 / (x - 5) dx)

Using the power rule, we get:

(1/2) x^2 + 5x + 25 ln|x - 5| + C

Therefore, the indefinite integral of x^2 / (x - 5) dx is (1/2) x^2 + 5x + 25 ln|x - 5| + C.

3. To find the indefinite integral of x cos(8x^2) dx:

We can use the substitution method. Let u = 8x^2, then du = 16x dx.

The integral becomes:

(1/16) ∫ cos(u) du

Integrating cos(u), we get:

(1/16) sin(u) + C

Substituting back u = 8x^2:

(1/16) sin(8x^2) + C

Therefore, the indefinite integral of x cos(8x^2) dx is (1/16) sin(8x^2) + C.

4. To find the indefinite integral of 176 / e^(-x) + 1 dx:

We can simplify the integrand by multiplying the numerator and denominator by e^x:

176 / e^(-x) + 1 = 176e^x / 1 + e^x

Now we can integrate:

∫ (176e^x / 1 + e^x) dx

Using u-substitution, let u = 1 + e^x, then du = e^x dx:

∫ (176 du / u)

Integrating 176/u, we get:

176 ln|u| + C

Substituting back u = 1 + e^x:

176 ln|1 + e^x| + C

Therefore, the indefinite integral of 176 / e^(-x) + 1 dx is 176 ln|1 + e^x| + C.

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7
What fraction of the shape is shaded?
18 mm
10 mm
12 mm

Answers

The shaded fraction of the shape is 2/3.

To determine the fraction of the shape that is shaded, we need to compare the shaded area to the total area of the shape.

1. Identify the shaded region in the shape. In this case, we have a shape with some part shaded.

2. Calculate the area of the shaded region. Given the dimensions provided, the area of the shaded region is determined by multiplying the length and width of the shaded part. In this case, the dimensions are 18 mm and 10 mm, so the area of the shaded region is (18 mm) × (10 mm) = 180 mm².

3. Calculate the total area of the shape. The total area of the shape is determined by multiplying the length and width of the entire shape. In this case, the dimensions are 18 mm and 12 mm, so the total area of the shape is (18 mm) × (12 mm) = 216 mm².

4. Determine the fraction. To find the fraction, divide the area of the shaded region by the total area of the shape: 180 mm² ÷ 216 mm². Simplifying this fraction gives us 5/6.

5. Convert the fraction to its simplest form. By dividing both the numerator and denominator by their greatest common divisor, we get the simplified fraction: 2/3.

Therefore, the fraction of the shape that is shaded is 2/3.

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according to the general equation probability, if p(A∩B) =3/7 and p(B)= 7/8 , what is P(A\B)?

Answers

The probability of event A occurring given that event B has not occurred (P(A\B)) is 0.

To find P(A\B), we need to calculate the probability of event A occurring given that event B has not occurred. In other words, we want to find the probability of A happening when B does not happen.

The formula to calculate P(A\B) is:

P(A\B) = P(A∩B') / P(B')

Where B' represents the complement of event B, which is the event of B not occurring.

Given that P(A∩B) = 3/7 and P(B) = 7/8, we can find P(A∩B') and P(B') to calculate P(A\B).

To find P(B'), we subtract P(B) from 1, since the sum of the probabilities of an event and its complement is always equal to 1.

P(B') = 1 - P(B)

      = 1 - 7/8

      = 1/8

Now, to find P(A∩B'), we need to subtract P(A∩B) from P(B'):

P(A∩B') = P(B') - P(A∩B)

        = 1/8 - 3/7

        = 7/56 - 24/56

        = -17/56

Since the probability cannot be negative, we can conclude that P(A∩B') is 0.

Finally, we can calculate P(A\B) using the formula:

P(A\B) = P(A∩B') / P(B')

      = 0 / (1/8)

      = 0

Therefore, the probability of event A occurring given that event B has not occurred (P(A\B)) is 0.

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5. Journalise the following transactions:
1. Pater commenced business with 40,000 cash and also brought
into business furniture worth
*5,000; Motor car valued for ₹12,000 and stock worth 20,000.
2. Deposited 15,000 into State Bank of India.
3. Bought goods on credit from Sen ₹9,000
4. Sold goods to Basu on Credit for ₹6,000
5. Bought stationery from Ram Bros. for Cash ₹200
6. Sold goods to Dalal for ₹2,000 for which cash was received.
7. Paid 600 as travelling expenses to Mehta in cash.
8. Patel withdrew for personal use ₹1,000 from the Bank.
9. Withdrew from the Bank ₹3,000 for office use.
10. Paid to Sen by cheque 8,800 in full settlement of his account.
11. Paid ₹400 in cash as freight and clearing charges to Gopal,
12. Received a cheque for ₹6,000 from Basu.

Answers

The journal entries for the given transactions are as follows:

Cash A/c Dr. 40,000

Furniture A/c Dr. 5,000

Motor Car A/c Dr. 12,000

Stock A/c Dr. 20,000

To Capital A/c 77,000

Bank A/c Dr. 15,000

To Cash A/c 15,000

Purchase A/c Dr. 9,000

To Sen's A/c 9,000

Basu's A/c Dr. 6,000

To Sales A/c 6,000

Stationery A/c Dr. 200

To Cash A/c 200

Cash A/c Dr. 2,000

To Dalal's A/c 2,000

Travelling Expenses A/c Dr. 600

To Cash A/c 600

Drawings A/c Dr. 1,000

To Bank A/c 1,000

Cash A/c Dr. 3,000

To Bank A/c 3,000

Sen's A/c Dr. 8,800

To Bank A/c 8,800

Freight and Clearing A/c Dr. 400

To Cash A/c 400

Bank A/c Dr. 6,000

To Basu's A/c 6,000

Journal entries for the given transactions are as follows:

Pater commenced business with 40,000 cash and also brought into business furniture worth ₹5,000; Motor car valued for ₹12,000 and stock worth ₹20,000.

Cash A/c Dr. 40,000

Furniture A/c Dr. 5,000

Motor Car A/c Dr. 12,000

Stock A/c Dr. 20,000

To Capital A/c 77,000

Deposited ₹15,000 into State Bank of India.

Bank A/c Dr. 15,000

To Cash A/c 15,000

Bought goods on credit from Sen for ₹9,000.

Purchase A/c Dr. 9,000

To Sen's A/c 9,000

Sold goods to Basu on Credit for ₹6,000.

Basu's A/c Dr. 6,000

To Sales A/c 6,000

Bought stationery from Ram Bros. for Cash ₹200.

Stationery A/c Dr. 200

To Cash A/c 200

Sold goods to Dalal for ₹2,000 for which cash was received.

Cash A/c Dr. 2,000

To Dalal's A/c 2,000

Paid ₹600 as travelling expenses to Mehta in cash.

Travelling Expenses A/c Dr. 600

To Cash A/c 600

Patel withdrew for personal use ₹1,000 from the Bank.

Drawings A/c Dr. 1,000

To Bank A/c 1,000

Withdrew from the Bank ₹3,000 for office use.

Cash A/c Dr. 3,000

To Bank A/c 3,000

Paid to Sen by cheque ₹8,800 in full settlement of his account.

Sen's A/c Dr. 8,800

To Bank A/c 8,800

Paid ₹400 in cash as freight and clearing charges to Gopal.

Freight and Clearing A/c Dr. 400

To Cash A/c 400

Received a cheque for ₹6,000 from Basu.

Bank A/c Dr. 6,000

To Basu's A/c 6,000

These journal entries represent the various transactions and their effects on different accounts in the accounting system.

They serve as the initial records of the financial activities of the business and provide a basis for further accounting processes such as ledger posting and preparation of financial statements.

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the population in Knox is 42000 and it is declining at a rate of 3.2% per year predict the population to the nearest whole number after 8 years

Answers

The predicted population of Knox, rounded to the nearest whole number, after 8 years is 32,599.

To predict the population of Knox after 8 years, we can use the given information that the population is currently 42,000 and it is declining at a rate of 3.2% per year.

To calculate the population after 8 years, we need to apply the rate of decline for each year. Let's break down the calculation step by step:

Calculate the population after the first year:

Population after 1 year = 42,000 - (3.2% of 42,000)

= 42,000 - (0.032 * 42,000)

= 42,000 - 1,344

= 40,656

Calculate the population after the second year:

Population after 2 years = 40,656 - (3.2% of 40,656)

= 40,656 - (0.032 * 40,656)

= 40,656 - 1,299.71

= 39,356.29

Continue this process for each year up to 8 years, applying the 3.2% rate of decline each time.

After performing these calculations for each year, we arrive at the population after 8 years:

Population after 8 years ≈ 32,599

Therefore, the predicted population of Knox, rounded to the nearest whole number, after 8 years is 32,599.

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Which expression is equivalent to a18a6

Answers

Answer:

[tex]\textsf{B.} \quad a^{12}[/tex]

Step-by-step explanation:

To simplify the given rational expression, we can apply the rule of exponents, which states that when dividing two powers with the same base, we subtract the exponents.

Using this rule:

[tex]\dfrac{a^{18}}{a^{6}}= a^{18-6} = a^{12}[/tex]

Therefore, the given rational expression is equivalent to a¹².

A = –5(6t – 7) + 11. B = 3(x – 5) – 3(x + 5).
B = 8 + 2y – 5(2y – 6) + 4.
C = –5z + 5z(z – 3) – 7(6 – 8z).

Answers

Answer: the answer is 110.8

Step-by-step explanation: add um all up

Please answer ASAP I will brainlist

Answers

The result of the row operation on the matrix is given as follows:

[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

How to apply the row operation to the matrix?

The matrix in this problem is defined as follows:

[tex]\left[\begin{array}{cccc}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The row operation is given as follows:

[tex]R_1 \rightarrow \frac{1}{2}R_1[/tex]

The first row of the matrix is given as follows:

[2 0 0 16]

The meaning of the operation is that every element of the first row of the matrix is divided by two.

Hence the resulting matrix is given as follows:

[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

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HELP PLESSE
The total cost of a lunch is shared among 8 people. the total bill is 55 what is the cost

Answers

Answer: A,

Step-by-step explanation:

8 people, times whatever each person payed will equal to 55$ in total

joan’s finishing time for the bolder boulder 10k race was 1.81 standard deviations faster than the women’s average for her age group. there were 410 women who ran in her age group. assuming a normal distribution, how many women ran faster than joan? (round down your answer to the nearest whole number.)

Answers

To determine the number of women who ran faster than Joan, we need to calculate the percentage of women who were slower than her and then apply that percentage to the total number of women in her age group.

Given that Joan's finishing time was 1.81 standard deviations faster than the women's average for her age group, we can use the properties of a normal distribution to find the corresponding percentage.

Since Joan is faster than the average, her finishing time would fall in the top portion of the distribution. Using a standard normal distribution table or a calculator, we can find the percentage of data below her finishing time. The Z-score associated with 1.81 standard deviations is approximately 0.9641, which corresponds to a percentage of 96.41%.

This means that approximately 96.41% of the women in her age group ran slower than Joan. To find the number of women who ran faster, we subtract this percentage from 100%: 100% - 96.41% = 3.59%.

To determine the number of women, we multiply the percentage by the total number of women in her age group: 3.59% * 410 = 14.709.

Rounding down to the nearest whole number, we can conclude that approximately 14 women ran faster than Joan.

Find the measure of the indicated angle.
20°
161°
61°
73°
H
G
F
73 ° E
195 °

Answers

Answer:

  (c)  61°

Step-by-step explanation:

You want the measure of the external angle formed by a tangent and secant that intercept arcs of 73° and 195° of a circle.

External angle

The measure of the angle at F is half the difference of intercepted arcs HE and EG.

  (195° -73°)/2 = 122°/2 = 61°

The measure of angle F is 61°.

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There are 6 horses in a race. How many ways can the first three positions of the order of the finish occur assume there are no ties

Answers

The number of ways the first three positions of the order of finish can occur in a race with 6 horses and no ties can be calculated using permutation.

Since there are 6 horses competing for the first position, there are 6 possibilities for the first place.

Once the first place is determined, there are 5 remaining horses for the second place, and then 4 remaining horses for the third place.

Therefore, the total number of ways is calculated as follows:

6 (possibilities for first place) × 5 (possibilities for second place) × 4 (possibilities for third place) = 120 ways.

So, there are 120 different ways the first three positions can occur in the race.

determine where there is a minimum or maximum value to the quadratic function. h(t)=-8t^2+4t-1. Find the minimum or maximum value of h

Answers

To determine whether there is a minimum or maximum value to the quadratic function h(t) = -8t² + 4t - 1 and find the minimum or maximum value of h, one has to follow the steps given below. So, the minimum or maximum value of h = -1/2.

Step 1: Write the quadratic function in standard form.

The standard form of a quadratic function is f(x) = ax² + bx + c, where a, b, and c are constants.

h(t) = -8t² + 4t - 1 ... (1)

Step 2: Calculate the axis of symmetry of the parabola.

The axis of symmetry of the parabola is given by x = -b/2a, where a and b are the coefficients of x² and x, respectively. Therefore, the axis of symmetry of the parabola given by h(t) = -8t² + 4t - 1 is given by: t = -b/2a = -4/(2 * (-8)) = 4/16 = 1/4

Step 3: Calculate the vertex of the parabola.

The vertex of the parabola is given by (h, k), where h and k are the coordinates of the vertex. Therefore, the coordinates of the vertex of the parabola given by h(t) = -8t² + 4t - 1 are given by: (1/4, h(1/4))

Substituting t = 1/4 in Equation (1), we have: h(1/4) = -8(1/4)² + 4(1/4) - 1h(1/4) = -8/16 + 4/4 - 1h(1/4) = -1/2 + 1 - 1h(1/4) = -1/2

Therefore, the vertex of the parabola given by h(t) = -8t² + 4t - 1 is given by the point(1/4, -1/2)

Step 4: Determine the nature of the extrema of the functionThe coefficient of the x² term in Equation (1) is -8, which is negative. Therefore, the parabola is downward-facing and the vertex represents a maximum value. Thus, the maximum value of the function h(t) = -8t² + 4t - 1 is given by h(1/4) = -1/2. Answer: Thus, the minimum or maximum value of h = -1/2.

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Solve each equation.
13x+91-30
OX= 7
Ox= 1,-19
O no solution
Ox=7,-13
DONE
Intro
12x+11--13
O no solution
Ox=-7
Ox=-14, 12
OX=-7,6
DONE
ODL
IX+21+4-11
O
X = 5
no solution
Ox=5,-9
Ox=7,-11
DONE

Answers

The solutions to the absolute value equations are:

1. b. x = 1, -19.      2. a. no solution.     3. c. x = 5, -9.

How to Solve Absolute Value Equations?

1. |3x+9| = 30

To solve this equation, we isolate the absolute value expression by considering two cases: 3x+9 = 30 and -(3x+9) = 30. Solving both equations, we find x = 7 and x = -19, respectively. Thus, the answer is b. x = 1, -19.

2. |2x+11| = -13

An absolute value cannot be negative, so there is no solution to this equation. The answer is a. no solution.

3. |x + 2| + 4 = 11

To solve this equation, we isolate the absolute value expression by subtracting 4 from both sides, resulting in |x + 2| = 7. Considering two cases: x + 2 = 7 and -(x + 2) = 7, we solve for x and find x = 5 and x = -9, respectively. Thus, the answer is c. x = 5, -9.

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1/3 : 1/4 ratio as a fraction

Answers

Answer:

4/3

Step-by-step explanation:

1/3:(1/4) = (1/3)/(1/4) = 1/3*4 = 4/3

Afiq. Bala and Chin played a game of marbles. Before the game, Bala had fewer marbles than Afig and Chinhad?
- as many marbles as Bala.
After the game, Balahad lost 20% of his marbles to Chinwhile Afig had lost
3
of his marbles to Chin. Chingained 105 marbles at the end of the
game.
(a)How many marbles didChinhave after the game?
(b)After the game, the 3 children each bought another 40 marbles. How manymarbles did the 3 children have altogether?

Answers

(a) Chin had 93.1 marbles after the game.

(b) The three children had a total of 271.44 marbles altogether.

Let's break down the problem step by step to find the answers:

Initial marbles

Before the game:

Let's assume Afiq had x marbles.

Bala had 1/6 fewer marbles than Afiq, so Bala had (x - 1/6x) marbles.

Chin had 3/5 as many marbles as Bala, so Chin had (3/5)(x - 1/6x) marbles.

After the game

After the game, Bala lost 20% of his marbles to Chin, so he has 80% (or 0.8) of his initial marbles remaining.

Afiq lost 2/3 of his marbles to Chin, so he has 1/3 (or 0.33) of his initial marbles remaining.

Calculating the marbles

(a) How many marbles did Chin have after the game?

To find Chin's marbles after the game, we add the marbles gained from Bala to Chin's initial marbles and the marbles gained from Afiq to Chin's initial marbles.

Chin's marbles = Initial marbles + Marbles gained from Bala + Marbles gained from Afiq

Chin's marbles = (3/5)(x - 1/6x) + 0.8(x - 1/6x) + 0.33x

Chin's marbles = (3/5)(5x/6) + 0.8(5x/6) + 0.33x

Chin's marbles = (3/6)x + (4/6)x + 0.33x

Chin's marbles = (7/6)x + 0.33x

We are given that Chin gained 105 marbles, so we can equate the equation above to 105 and solve for x:

(7/6)x + 0.33x = 105

(7x + 2x) / 6 = 105

9x / 6 = 105

9x = 105 * 6

x = (105 * 6) / 9

x = 70

Substituting the value of x back into the equation for Chin's marbles:

Chin's marbles = (7/6)(70) + 0.33(70)

Chin's marbles = 10(7) + 0.33(70)

Chin's marbles = 70 + 23.1

Chin's marbles ≈ 93.1

Therefore, Chin had approximately 93.1 marbles after the game.

(b) After the game, the 3 children each bought another 40 marbles. To find the total number of marbles the 3 children have altogether, we need to sum up their marbles after the game and the additional 40 marbles for each.

Total marbles = Afiq's marbles + Bala's marbles + Chin's marbles + Additional marbles

Total marbles = 0.33x + 0.8(x - 1/6x) + (7/6)x + 40 + 40 + 40

Total marbles = 0.33(70) + 0.8(70 - 1/6(70)) + (7/6)(70) + 120

Total marbles = 23.1 + 0.8(70 - 11.7) + 81.7 + 120

Total marbles = 23.1 + 0.8 × 58.3 + 201.7

Total marbles = 23.1 + 46.64 + 201.7

Total marbles = 271.44

The three children had a total of 271.44 marbles altogether.

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Question

Afiq. Bala and Chin played a game of marbles. Before the game, Bala had 1/ 6 fewer marbles than Afig and Chinhad 3/5 as many marbles as Bala.

After the game, Balahad lost 20% of his marbles to Chinwhile Afig had lost

2/3 of his marbles to Chin. Chingained 105 marbles at the end of the

game.

(a)How many marbles didChinhave after the game?

(b)After the game, the 3 children each bought another 40 marbles. How manymarbles did the 3 children have altogether?

Ship A receives a distress signal from the northeast, and ship B receives a distress
signal from the same vessel from the west. At what location is the vessel in distress
located? Describe how you arrived at your conclusion using complete sentences. You
must show all work in order to receive credit. (10 points)
3
2
A
NE
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Answers

The vessel in distress is located at (-x, y), with the exact coordinates depending on the specific distances and positions of ships A and B.

To determine the location of the vessel in distress, we can analyze the information given about the distress signals received by ships A and B.

Ship A received a distress signal from the northeast, while Ship B received a distress signal from the west.

Let's consider the compass directions:

Northeast (NE) is a direction that lies between north and east.

West (W) is a direction perpendicular to both north and south.

From this information, we can deduce that the vessel in distress must be located at the intersection of the northeast and west directions.

To find this intersection point, we can draw a diagram or use a coordinate system. Let's assume the origin (0,0) represents the starting point of both ships A and B.

Based on the given information, we know that ship A received a distress signal from the northeast. This means that the vessel in distress must be located in the direction of the positive x-axis (east) and the positive y-axis (north) from the origin.

On the other hand, ship B received a distress signal from the west. This indicates that the vessel in distress must be located in the direction of the negative x-axis (west) from the origin.

Combining these two pieces of information, we can conclude that the vessel in distress is located at the point where the positive y-axis (north) intersects with the negative x-axis (west). In coordinate notation, this point can be represented as (-x, y), where x and y are positive values.

Therefore, the vessel in distress is located at (-x, y), with the exact coordinates depending on the specific distances and positions of ships A and B.

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HELP DUE IN 3 DAYS!!!!! Which symbol should go in the box to make the equation true, and why? (1 point) the fraction two fourths followed by a box followed by the fraction four eighths a >, because the fraction two fourths is equal to the fraction eight eighths. b >, because the fraction two fourths is equal to the fraction six eighths. c =, because the fraction four eighths is equal to the fraction two fourths. d =, because the fraction four eighths is equal to the fraction two halves.

Answers

The correct answer is c) =, because the fraction four eighths is equal to the fraction two fourths.

To determine which symbol should go in the box to make the equation true, let's analyze the fractions given and compare their values.

The fraction "two fourths" can be simplified to "one-half" since both the numerator and denominator can be divided by 2. Therefore, "two fourths" is equal to "one-half."

Now, let's look at the fraction "four eighths." We can simplify this fraction by dividing both the numerator and denominator by 4, which gives us "one-half" as well. So, "four eighths" is also equal to "one-half."

Now, based on the given fractions, we have the equation:

(one-half) [BOX] (one-half)

We need to determine the correct symbol to fill in the box.

Looking at the values of the fractions, we see that both "two fourths" and "four eighths" are equivalent to "one-half." Therefore, the correct symbol to make the equation true is the equality symbol (=).

Hence, the correct answer is:

c) =, because the fraction four eighths is equal to the fraction two fourths.

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NO LINKS!! URGENT HELP PLEASE!!

29. A tree casts a shadow that is 12 feet long. If the tree is 20 feet tall, what is the angle of elevation of the sun? Draw a diagram to represent the situation. Round the answer to the nearest tenth.


30. In ΔABC, m∠A = 75°, m∠B = 50°, and c = 9. Draw ΔABC, then use the Law of Sines to find a. Round final answer to the nearest tenth.

Answers

Answer:

29. 59.06°

30. 10.6

Step-by-step explanation:

29.
By using the Tangent angle rule, we can find the angle of elevation,

We know that

Tan Angle = opposite/adjacent

Tan x=AB/BC

Tan x=20/12

Tan x=5/3

[tex]x=Tan^{- }(\frac{5}{3})[/tex]

x=59.06°

30.

The law of sine is a formula that can be used to find the lengths of the sides of a triangle, or to find the angles of a triangle, when two sides and the angle between them are known. The formula is:

a / sin(A) = b / sin(B) = c / sin(C)

Here taking

a / sin(A) = c / sin(C)

here A=75°, C=180-75-50=55° and c -9 and

we need to find a,

substituting value

a/Sin(75°)=9/Sin(55°)

a=9*Sin(75°)/Sin(55°)

a=10.61

Therefore, the value of a is 10.6

Answer:

Question 29:  Angle of Elevation is ------->  59.0°Question 30: The length of side A in --------> △ABC is approximately 10.3

Step-by-step explanation:Question 29: In this question, we can use the tangent function to solve the problem. We can set the Sun's elevation angle as theta (θ). Then we can get the equation:

        tan (θ) = 20/12, and solve for θ

Solve the problem:We can draw a right triangle with the tree, the shadow, and the Sun.The tree's height is the opposite side, and the length of the shadow is the adjacent side.The angle of the sun's elevation is the angle between the ground and the line from the top of the tree to the sun.We can set the angle of elevation of the sun as theta (θ).

       We then get the equation tan (θ) =  20/12

We can solve for theta (θ) using the equation

        θ = arctan(5/3)

We can use a calculator to find that: Let the angle of elevation =  θ

        Tan θ  =  opp/adj

        Tan θ  = 20/12

         θ  =  Tan^-1 (20/12)

          θ  =  59.03624346 degrees

           θ = 59.0 degrees

Draw the conclusion:

       Hence, the Angle of Elevation is ------->  59.0°

Question 30:    △

       m < C = 180 degrees - m<A - m<B

       m<C  = 180 degrees - 75 degrees  -  50 degrees

Simplify:

      m<C  =  55 degrees

Apply the Law of Sines:

       a/sin A  =  c/sin C

Substitute the values:

       a/sin 75 degrees  =  9/sin 55 degrees

Solve for A:

        a  =  9 * sin 75 degrees/sin 55 degrees

Calculate the value of A:

        a  =  10.3

Draw a conclusion:

Therefore, The length of side A in --------> △ABC is approximately 10.3

Hope this helps you!

Geno read 126 pages in 3 hours. He read the same number of pages each hour for the first 2 hours. Geno read 1.5 times as many pages during the third hour as he did during the first hour.

Answers

Geno read 36 pages during the first and second hour, and 1.5 times that, which is 54 pages, during the third hour.

Let's break down the information given:

Geno read 126 pages in 3 hours.

He read the same number of pages each hour for the first 2 hours.

Geno read 1.5 times as many pages during the third hour as he did during the first hour.

Let's solve this:

Let's assume that Geno read x pages during the first hour.

Since he read the same number of pages each hour for the first 2 hours, he also read x pages during the second hour.

During the third hour, Geno read 1.5 times as many pages as he did during the first hour, which is 1.5x pages.

To find the total number of pages he read, we can add up the pages from each hour: x + x + 1.5x = 126.

Combining like terms, we have 3.5x = 126.

Divide both sides of the equation by 3.5 to solve for x: x = 36.

Therefore, Geno read 36 pages during the first and second hour, and 1.5 times that, which is 54 pages, during the third hour.

In summary, Geno read 36 pages during each of the first two hours and 54 pages during the third hour, for a total of 126 pages in 3 hours.

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Mrs. Rodriquez has 24 students in her class. Ten of the students are boys. Jeff claims that the ratio of boys to girls in this class must be 5:12. What is Jeff’s error and how can he correct it?
Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls to get a ratio of 10:14 or 5:7.
Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls. The ratio would be 14:10 or 7:5.
Jeff did not write the ratio in the correct order. He should have written it as 24:10.
Jeff did not write the ratio in the correct order. He should have written it as 12:5.\

Answers

Step-by-step explanation:

24-10=14. So the girls are 14 the ratio is 10:14 =5:7

please help will give brainliest...........

Answers

A

no, because they are both right triangles and

the one on the left is 88° at the right anglr

Yesterday, Noah ran 2 1/2 miles in 3/5 hour. Emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour. How fast, in miles per hour, did each person run? Who ran the fastest?

Answers

Anna ran the fastest with a speed of approximately 4.67 miles per hour.

To find the speed at which each person ran, we can use the formula: Speed = Distance / Time.

Let's calculate the speed for each person:

Noah:

Distance = 2 1/2 miles

Time = 3/5 hour

Speed = (2 1/2) / (3/5)

= (5/2) / (3/5)

= (5/2) [tex]\times[/tex] (5/3)

= 25/6 ≈ 4.17 miles per hour

Emily:

Distance = 3 3/4 miles

Time = 5/6 hour

Speed = (3 3/4) / (5/6)

= (15/4) / (5/6)

= (15/4) [tex]\times[/tex] (6/5)

= 9/2 = 4.5 miles per hour

Anna:

Distance = 3 1/2 miles

Time = 3/4 hour

Speed = (3 1/2) / (3/4)

= (7/2) / (3/4)

= (7/2) [tex]\times[/tex] (4/3)

= 14/3 ≈ 4.67 miles per hour

Based on the calculations, Noah ran at a speed of approximately 4.17 miles per hour, Emily ran at a speed of 4.5 miles per hour, and Anna ran at a speed of approximately 4.67 miles per hour.

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