Answer: Price-earnings ratio= 22.0
Step-by-step explanation:
Given: A company had a market price of $38.50 per share, earnings per share of $1.75, and dividends per share of $0.90
To find: price-earnings ratio
Required formula: [tex]\text{price-earnings ratio }=\dfrac{\text{ Market Price per Share}}{\text{Earnings Per Share}}[/tex]
Then, Price-earnings ratio = [tex]\dfrac{\$38.50}{\$1.75}[/tex]
⇒Price-earnings ratio = [tex]\dfrac{22}{1}[/tex]
Hence, the price-earnings ratio= 22.0
another pls! lolllllll
Answer:
P = 126; A = 927
Step-by-step explanation:
Enlarging by a scale factor means multiplying each number by the given. 6 x 4.5 = 27; 8 x 4.5 = 36. 2(27) + 2(36) = 126; 27 x 36 = 927.
Answer:
Hey there!
Original Width: 6
New Width: 27
Original Length: 8
New Length: 36
Perimeter: 36+36+27+27, or 126
Area: 36(27), or 972.
Hope this helps :)
Which of the following is a point-slope equation of a line that passes through
the points (5,2) and (-1,-6)?
A. y-2-(X-5)
B. y-2-(X-5)
C. y-2 =(x-5
D. V-2--0-5)
Please, check the options of the question. The point-slope equation needs the slope, m, in the equation.
Answer:
The point-slope equation of the points (5,2) and (-1,-6) is
[tex] \\ y - 2 = \frac{4}{3}(x-5)[/tex] or,
[tex] \\ y + 6 = \frac{4}{3}(x+1)[/tex]
which are the same as
[tex] \\ 3y-4x+14 = 0[/tex] , (which is not a point-slope equation, though)
Step-by-step explanation:
The point-slope equation is given by:
[tex] \\ y - y_{1} = m(x - x_{1})[/tex]
Where m is the slope of the line:
[tex] \\ m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]
Having the points (5,2) and (-1,-6), then
[tex] \\ m = \frac{-6 - 2}{-1 -5}[/tex]
[tex] \\ m = \frac{-8}{-6}[/tex]
[tex] \\ m = \frac{4}{3}[/tex]
Then, the point-slope equation of the points (5,2) and (-1,-6) is
[tex] \\ y - 2 = \frac{4}{3}(x-5)[/tex] or
[tex] \\ y + 6 = \frac{4}{3}(x+1)[/tex]
The below graph represents both lines (they are the same line).
i would like some help thank you :)
Answer:
[tex]\angle AE = 32^{\circ}[/tex]
[tex]\angle EAD = 212^{\circ}[/tex]
[tex]\angle BE = 133^{\circ}[/tex]
[tex]\angle BCE = 227^{\circ}[/tex]
[tex]\angle AED = 180^{\circ}[/tex]
[tex]\angle BD = 79^{\circ}[/tex]
Step-by-step explanation:
The central angle of a circle is equal to 360º, whose formula in this case is:
[tex]\angle AB + \angle BC + \angle CD + \angle DE + \angle EA = 360^{\circ}[/tex]
In addition, the following conditions are known from figure:
[tex]\angle BC = 47^{\circ}[/tex], [tex]\angle DE = 148^{\circ}[/tex]
[tex]\angle DE + \angle EA = 180^{\circ}[/tex]
[tex]\angle CD + \angle DE = 180^{\circ}[/tex]
[tex]\angle AB + \angle BC + \angle CD = 180^{\circ}[/tex]
Now, the system of equations is now solved:
[tex]\angle EA = 180^{\circ}-\angle DE[/tex]
[tex]\angle EA = 180^{\circ}-148^{\circ}[/tex]
[tex]\angle EA = 32^{\circ}[/tex]
[tex]\angle CD = 180^{\circ}-\angle DE[/tex]
[tex]\angle CD = 180^{\circ}-148^{\circ}[/tex]
[tex]\angle CD = 32^{\circ}[/tex]
[tex]\angle AB = 180^{\circ} - \angle BC - \angle CD[/tex]
[tex]\angle AB = 180^{\circ}-47^{\circ}-32^{\circ}[/tex]
[tex]\angle AB = 101^{\circ}[/tex]
The answers are described herein:
[tex]\angle AE = 32^{\circ}[/tex]
[tex]\angle EAD = 212^{\circ}[/tex]
[tex]\angle BE = 133^{\circ}[/tex]
[tex]\angle BCE = 227^{\circ}[/tex]
[tex]\angle AED = 180^{\circ}[/tex]
[tex]\angle BD = 79^{\circ}[/tex]
x=7 what would match this soulotion
Answer:
x = 7
Step-by-step explanation:
7 = 7
It's given
Calculate: 1/(1×3) + 1/(3×5) + ... + 1/(47×49) . Please give explanation
Answer:
4611/11515
Step-by-step explanation:
1/(1×3)- 1 times 3 simply equals 3. so the answer would be 1/3.
1/(3×5)- 3 times 5 simply equals 15. so the answer would be 1/15.
1/(47×49)- 47 times 49 is 2303. so the answer would be 1/2303.
after all this you find the common deonomator. The common denominator is 34545. 34545 divided by 3 equals to 11515 so you muliplty that number by 1/3. 34545 divided by 15 equals to 2303 so you muliplty that number by 1/15.
34545 divided by 2303 equals to 15 so you multiply that number by 1/2303. After adding all that together you get 13833/34545. However after you simplify that number you get 4611/11515
A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit e
A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat?
Answer:
the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat is 0.1
Step-by-step explanation:
We know that probability= number of required outcomes /number of all possible outcome.
From the given information;
the number of required outcome is guessing a 9-digit = 1 outcome
the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.
Since there are only 9-digit that opens the lock;
the probability of a person correctly guessing a 9-digit entry code is
[tex]P =\dfrac{1}{^{10}C_9}[/tex]
[tex]P =\dfrac{1}{\dfrac{10!}{9!1!}}[/tex]
[tex]P =\dfrac{1}{10}[/tex]
P = 0.1
Which linear inequality is represented by the graph?
y > 2x + 2
y ≥ One-halfx + 1
y > 2x + 1
y ≥ One-halfx + 2
Answer: y > 2x + 1
Step-by-step explanation:
In the graph first, we can see two things:
The line is not solid (so the values in the line are not included), and the shaded part is above, so we will be using the symbol:
y > f(x)
Now, in the line we can see that when x = 0, y = 1.
So the linear equation must be something like:
f(x) = a*x + 1
The only one that has an y-intercept equal to 1 is y > 2x + 1
Answer:
C or y>2x +1
Step-by-step explanation:
edge
Historically, the proportion of students entering a university who finished in 4 years or less was 63%. To test whether this proportion has decreased, 114 students were examined and 51% had finished in 4 years or less. To determine whether the proportion of students who finish in 4 year or less has statistically significantly decreased (at the 5% level of signficance), what is the critical value
Answer:
z(c) = - 1,64
We reject the null hypothesis
Step-by-step explanation:
We need to solve a proportion test ( one tail-test ) left test
Normal distribution
p₀ = 63 %
proportion size p = 51 %
sample size n = 114
At 5% level of significance α = 0,05, and with this value we find in z- table z score of z(c) = 1,64 ( critical value )
Test of proportion:
H₀ Null Hypothesis p = p₀
Hₐ Alternate Hypothesis p < p₀
We now compute z(s) as:
z(s) = ( p - p₀ ) / √ p₀q₀/n
z(s) =( 0,51 - 0,63) / √0,63*0,37/114
z(s) = - 0,12 / 0,045
z(s) = - 2,66
We compare z(s) and z(c)
z(s) < z(c) - 2,66 < -1,64
Therefore as z(s) < z(c) z(s) is in the rejection zone we reject the null hypothesis
Y = -4x + 11 , 3x + y = 1
Answer:
(10, -29)
Step-by-step explanation:
I assume you are looking for the solution to this system of equations.
Plug them both into a graphing calculator. The point where they cross is:
(10, -29)
Answer:(10, -29)
Step-by-step explanation:
A national survey of 1000 adult citizens of a nation found that 25% dreaded Valentine's Day. The margin of error for the survey was 3.6 percentage points with 90% confidence. Explain what this means.
Answer:
There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.
Step-by-step explanation:
The summary of the statistics from the information given is ;
At 90% confidence interval, 25% dreaded Valentine's Day and the margin of error for the survey was 3.6 percentage points
SO;
[tex]C.I = \hat p \pm M.O.E[/tex]
[tex]C.I = 0.25 \pm 0.036[/tex]
C.I = (0.25-0.036 , 0.25+0.036)
C.I = (0.214, 0.286)
The 90% confidence interval for the proportion of the adult citizens of the nation that dreaded Valentine’s day is 0.214 and 0.286.
There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.
Triangle ABC has vertices A(-5, -2), B(7, -5), and C(3, 1). Find the coordinates of the intersection of the three altitudes
Answer:
Orthocentre (intersection of altitudes) is at (37/10, 19/5)
Step-by-step explanation:
Given three vertices of a triangle
A(-5, -2)
B(7, -5)
C(3, 1)
Solution A by geometry
Slope AB = (yb-ya) / (xb-xa) = (-5-(-2)) / (7-(-5)) = -3/12 = -1/4
Slope of line normal to AB, nab = -1/(-1/4) = 4
Altitude of AB = line through C normal to AB
(y-yc) = nab(x-xc)
y-1 = (4)(x-3)
y = 4x-11 .........................(1)
Slope BC = (yc-yb) / (xc-yb) = (1-(-5) / (3-7)= 6 / (-4) = -3/2
Slope of line normal to BC, nbc = -1 / (-3/2) = 2/3
Altitude of BC
(y-ya) = nbc(x-xa)
y-(-2) = (2/3)(x-(-5)
y = 2x/3 + 10/3 - 2
y = (2/3)(x+2) ........................(2)
Orthocentre is at the intersection of (1) & (2)
Equate right-hand sides
4x-11 = (2/3)(x+2)
Cross multiply and simplify
12x-33 = 2x+4
10x = 37
x = 37/10 ...................(3)
substitute (3) in (2)
y = (2/3)(37/10+2)
y=(2/3)(57/10)
y = 19/5 ......................(4)
Therefore the orthocentre is at (37/10, 19/5)
Alternative Solution B using vectors
Let the position vectors of the vertices represented by
a = <-5, -2>
b = <7, -5>
c = <3, 1>
and the position vector of the orthocentre, to be found
d = <x,y>
the line perpendicular to BC through A
(a-d).(b-c) = 0 "." is the dot product
expanding
<-5-x,-2-y>.<4,-6> = 0
simplifying
6y-4x-8 = 0 ...................(5)
Similarly, line perpendicular to CA through B
<b-d>.<c-a> = 0
<7-x,-5-y>.<8,3> = 0
Expand and simplify
-3y-8x+41 = 0 ..............(6)
Solve for x, (5) + 2(6)
-20x + 74 = 0
x = 37/10 .............(7)
Substitute (7) in (6)
-3y - 8(37/10) + 41 =0
3y = 114/10
y = 19/5 .............(8)
So orthocentre is at (37/10, 19/5) as in part A.
A sample of 150 CBC students was taken, and each student filled out a
survey. The survey asked students about different aspects of their college
and personal lives. The experimenter taking the survey defined the
following events:
A=The student has children
B = The student is enrolled in at least 12 credits
C = The student works at least 10 hours per week
The student found that 44 students in the sample had children, 73 were
enrolled in at least 12 credits, and 105 were working at least 10 hours per
week. The student also noted that 35 students had children and were
working at least 10 hours per week.
Calculate the probability of the event BC for students in this sample. Round
your answer to four decimal places as necessary.
Answer:
The probability of the event BC
= the probability of B * C = 48.6667% * 70%
= 34.0667%
Step-by-step explanation:
Probability of A, students with children = 44/150 = 29.3333%
Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%
Probability of C, students working at least 10 hours per week = 105/150 = 70%
Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week
= 48.6667% * 70%
= 34.0667%
Determine whether the value given below is from a discrete or continuous data set. In a test of a method of gender selection, 725 couples used the XSORT method and 368 of them had baby girls. Choose the correct answer below. A. The data set is neither continuous nor discrete. B. A continuous data set because there are infinitely many possible values and those values can be counted C. A continuous data set because there are infinitely many possible values and those values cannot be counted D. A discrete data set because there are a finite number of possible values
Answer:
D. A discrete data set because there are a finite number of possible values.
Step-by-step explanation:
Assuming in a test of a method of gender selection, 725 couples used the XSORT method and 368 of them had baby girls. The value given is from a discrete data set because there are a finite number of possible values.
In Mathematics, a discrete data is a data set in which the number of possible values are either finite or countable.
On the other hand, a continuous data is a data set having infinitely many possible values and those values cannot be counted, meaning they are uncountable.
Hence, if 725 couples used the XSORT method and 368 of them had baby girls; this is a discrete data because the values (725 and 368) are finite and can be counted.
−11b+7=40 b= pls help
Answer:
[tex]\boxed{b = -3}[/tex]
Step-by-step explanation:
[tex]\sf -11b+7 = 40\\Subtracting\ 7\ to\ both\ sides\\-11b = 40-7\\-11b = 33\\Dividing\ both\ sides \ by \ -11\\ b = 33/-11\\b = -3[/tex]
Need Answers ASAP!!!!
Answer:
15.9degrees
Step-by-step explanation:
in photo above
Answer:
[tex]\boxed{15.95\°}[/tex]
Step-by-step explanation:
The angle can be found by using trigonometric functions.
tan (θ) = [tex]\frac{opposite}{adjacent}[/tex]
tan (θ) = [tex]\frac{4}{14}[/tex]
θ = [tex]tan^{-1} \frac{4}{14}[/tex]
θ = 15.9453959
θ ≈ 15.95
Why can you not see any answers on brainless tonight? It was working earlier today.
Answer:
I;m wondering the same thing
Step-by-step explanation:
Answer: don’t know maybe a glitch or had something to do with the honor code
Step-by-step explanation:
in the diagram ,a and 46° are complementary angles. It is given that a and b are supplementary angles and the angle conjugate to c is 283°. Calculate the values of a,b,c and d. pleaseeeee answer soonn
Answer:
[tex]a=44^{\circ},b=136^{\circ},c=77^{\circ},d=57^{\circ}[/tex].
Step-by-step explanation:
It is given that a and 46° are complementary angles.
[tex]a+46^{\circ}=90^{\circ}[/tex]
[tex]a=90^{\circ}-46^{\circ}[/tex]
[tex]a=44^{\circ}[/tex]
It is given that a and b are supplementary angles.
[tex]a+b=180^{\circ}[/tex]
[tex]44^{\circ}+b=180^{\circ}[/tex]
[tex]b=180^{\circ}-44^{\circ}[/tex]
[tex]b=136^{\circ}[/tex]
Angle conjugate to c is 283°.
[tex]c+283^{\circ}=360^{\circ}[/tex]
[tex]c=360^{\circ}-283^{\circ}[/tex]
[tex]c=77^{\circ}[/tex]
Sum of all angles at a point is 360 degrees.
[tex]a+b+c+d+46^{\circ}=360^{\circ}[/tex]
[tex]44^{\circ}+136^{\circ}+77^{\circ}+d+46^{\circ}=360^{\circ}[/tex]
[tex]d+303^{\circ}=360^{\circ}[/tex]
[tex]d=360^{\circ}-303^{\circ}[/tex]
[tex]d=57^{\circ}[/tex]
Therefore, [tex]a=44^{\circ},b=136^{\circ},c=77^{\circ},d=57^{\circ}[/tex].
1/6•4•(-1/3)•9•(-1/2)•5
Answer:
Step-by-step explanation:
its 5
1/6 *2 *3 *5=
1/3*3*5=
5
find the locus of a point which moves such that it is equidistant from (a,b) and (b,a)
Answer:
the line y = x
Step-by-step explanation:
(a, b ) and (b, a ) are reflections of each other in the line y = x.
They are therefore both equidistant from the line y = x
a variable with an exponent is a perfect square if the exponent is divisible by____
Answer: 3
Step-by-step explanation:
A web page is accessed at an average of 20 times an hour. Assume that waiting time until the next hit has an exponential distribution. (a.) Determine the rate parameter λ of the distribution of the time until the first hit? (b.) What is the expected time between hits? (c.) What is the probability that t
Answer:
Step-by-step explanation:
Given that :
A web page is accessed at an average of 20 times an hour.
Therefore:
a. he rate parameter λ of the distribution of the time until the first hit = 20
b. What is the expected time between hits?
Let consider E(Y) to be the expected time between the hits; Then :
E(Y) = 1/λ
E(Y) = 1/20
E(Y) = 0.05 hours
E(Y) = 3 minutes
(c.) What is the probability that there will be less than 5 hits in the first hour?
Let consider X which follows Poisson Distribution; Then,
P(X<5) [tex]\sim[/tex] G(∝=5, λ = 20)
For 5 hits ; the expected time will be :
Let 5 hits be X
E(X) = ∝/λ
E(X) = 5/20
E(X) =1/4
E(X) = 0.25 hour
E(X) = 15 minutes
From above ; we will see that it took 15 minutes to get 5 hits; then
[tex]P(\tau \geq 0.25) = \int\limits^{\alpha}_{0.25} \dfrac{\lambda^{\alpha}}{\ulcorner^{\alpha}} t^{a\pha-1} \ e^{-\lambda t} \, dt[/tex]
[tex]P(\tau \geq 0.25) = \int\limits^{5}_{0.25} \dfrac{20^{5}}{\ulcorner^{5}} t^{5-1} \ e^{-20 t} \, dt[/tex]
[tex]\mathbf{P(\tau \geq 0.25) =0.4405}[/tex]
Given: , ∠DAC ≅ ∠BCA Prove: ∆ADC ≅ ∆CBA Look at the proof. Name the postulate you would use to prove the two triangles are congruent. SAS Postulate SSS Postulate AAA Postulate
Answer:
SAS Postulate
Step-by-step explanation:
The contributors to the proof are listed in the left column. They consist of a congruent Side, a congruent Angle, and a congruent Side. The SAS Postulate is an appropriate choice.
URGENT!!!!!! A 5 inch × 7 inch photograph is placed inside a picture frame. Both the length and width of the frame are 2x inches larger than the width and length of the photograph. Which expression represents the perimeter of the frame? REPLY IN COMMENTS PLEASE IM GLITCHING AND CANT SEE ANSWERS
Answer:
the perimeter of the square is just "(5+2x)(2)+(7+2x)(2)
Step-by-step explanation:
Answer:
2 × 10 + 2 × 14
Step-by-step explanation:
The frame is given to have measurements 2 times that of the photograph's measurements. We also know that the photograph is given by dimensions being 5 inch by 7 inch. Therefore the measurements of the frame should be 5 [tex]*[/tex] 2, which = 10 inches, by 7 [tex]*[/tex] 2 = 14 inches.
So the dimensions of the frame are 10 inch × 14 inch. As the frame is present as a rectangle, the perimeter is given by two times both dimensions together. That would be represented by the expression " 2 × 10 inch + 2 × 14 inch. " In other words you can say that the expression is 2 × 10 + 2 × 14 - the expression that represents the perimeter of the frame.
Five thousand dollars is deposited into a savings account at 2.5% interest compounded continuously.
a. What is the formula for A(t), the balance after t years?
b. What differential equation is satisfied by A(t), the balance after t years?
c. How much money will be in the account after 5 years? (Do not round until your final answer. Round your final
answer to the nearest cent as needed.
d. When will the balance reach $7,000? (Do not round until your final answer. Round your final answer to the
nearest tenth as needed.)
Answer:
A). A(t) = P(1+r/n)^(nt)
B). DA/Dt = np(1+r/n)^(t)
C). A(5) =$ 5664.0
D).t = approximately 13.5 years
Step-by-step explanation:
A(t) = P(1+r/n)^(nt)
P = $5000
n= t
r= 2.5%
After five years t = 5
A(t) = P(1+r/n)^(nt)
A(5) = 5000(1+0.025/5)^(5*5)
A(5) = 5000(1+0.005)^(25)
A(5)= 5000(1.005)^(25)
A(5) = 5000(1.132795575)
A(5) = 5663.977875
A(5) =$ 5664.0
When the balance A= $7000
A(t) = P(1+r/n)^(nt)
7000= 5000(1+0.025/n)^(nt)
But n= t
7000= 5000(1+0.025/t)^(t²)
7000/5000= (1+0.025/t)^(t²)
1.4= (1+0.025/t)^(t²)
Using trial and error
t = approximately 13.5 years
Determine if the survey question is biased. If the question is biased, suggest a better wording. How often do you eat fruit during an average week?
1. Is the question biased?
A. Yes, because it influences the respondent into thinking that eating fruit is good for you. A better question would be "Do you think that eating fruit is good for you?"
B. No, because it influences the respondent into thinking that eating fruit is good for you.
C. Yes, because it does not lead the respondent to any particular answer. A better question would be "Why is eating fruit good for you?"
D. No, because it does not lead the respondent to any particular answer.
2. Choose the best question below.
A. Do you think that eating fast food is good for you?
B. Do you think that eating fast food is bad for you?
C. Why is eating fast food bad for you?
D. The original question is not biased.
Answer:
The correct answers are:
1. No, because it does not lead the respondent to any particular answer (D)
2. The original question is not biased (D)
Step-by-step explanation:
In developing survey questions, response biases are tendencies for respondents to respond inaccurately or falsely to a particular question and this largely has to do with the way the questions are framed. Biased questions build preconceived thoughts in the mind of the respondent, increasing the tendency for them to lean towards a particular answer.
In this example, the question "How often do you eat fruit during an average week?" is not biased because it does not suggest to the respondent whether eating fruits is good or bad, it just directs the respondent to a particular number, hence the question is not biased.
STORE'S COST AND LIST PRICE
OF THREE STOVES
Model Store's Cost
List Price
Х
$520
$900
Y
$850
$1,800
Z
$700
$1,200
The chart above shows the store's cost and list price for three models of stoves sold by an appliance store.
During a 20 percent off sale, Gene bought a Model Y stove from this store. How much profit did the store
make on Gene's purchase? (Profit = Price paid - Store's cost)
O $260
O $380
O $590
O $760
Answer: C) $590
Step-by-step explanation:
Gene paid $1800 - $1800(0.2) = $1440 for Model Y
The store paid $850 for Model Y.
The profit was $1440 - $850 = $590
At what point does the line
Y = -1/2 X + 2 intercept the Y-axis?
A. - 1
B. -1/2
C. 1
D. 2
E. -2
Answer:
D. 2
Step-by-step explanation:
The y-intercept is when the graph crosses the y-axis when x = 0. In that case, simply plug in x as 0:
y = -1/2(0) + 2
y = 2
Therefore, the graph crosses the y-axis at 2.
Answer:
D
Step-by-step explanation:
our equation is y= [tex]\frac{-1}{2}[/tex] x +2
-1/2 is the slope 2 is the y-interceptso the answer is 2
if we want to verify our answer we can follow these steps
the y-intercept is given by calculating the image of 0
y= -1/2*0+2 = 2so it's right
I _____ some stuff A)'ve done B)'s do C)'s doing D)'s did E) 've
Answer:
A and E
Step-by-step explanation:
If the answer was A, it would translate to:
I have done some stuff.
If the answer was D, it would translate to:
I have some stuff.
Both of the sentences are grammatically correct, so A and E are the answers.
Incorrect:
B. - I's do some stuff - doesn't make sense
C. - I's doing some stuff - doesn't make sense
D. - I's did some stuff - doesn't make sense
What is the equation of the line with a slope of 4 and a y-intercept of -5?
Answer:
y = 4x -5
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 4x -5
Simplify the expression.
Write your answer without negative exponents. NEED AN ANSWER ASAP
Answer:
[tex]\boxed{\frac{-3b^4 }{a^6 }}[/tex]
Step-by-step explanation:
[tex]\frac{-18a^{-8}b^{-3}}{6a^{-2}b^{-7}}[/tex]
[tex]\frac{-18}{6} \times \frac{a^{-8}}{a^{-2}} \times \frac{b^{-3}}{b^{-7}}[/tex]
[tex]-3 \times \frac{a^{-8}}{a^{-2}} \times \frac{b^{-3}}{b^{-7}}[/tex]
Apply the law of exponents, when dividing exponents with same base, we subtract the exponents.
[tex]-3 \times a^{-8-(-2)} \times b^{-3- (-7)}[/tex]
[tex]-3 \times a^{-8+2} \times b^{-3+7}[/tex]
[tex]-3 \times a^{-6} \times b^{4}[/tex]
[tex]{-3a^{-6}b^{4}}[/tex]
The answer should be without negative exponents.
[tex]a^{-6}=\frac{1}{a^6 }[/tex]
[tex]\frac{-3b^4 }{a^6 }[/tex]
Answer:
[tex] - \frac{3 {b}^{4} }{ {a}^{6} } [/tex]Step-by-step explanation:
[tex] \frac{ - 18 {a}^{ - 8} {b}^{ - 3} }{6 {a}^{ - 2} {b}^{ - 7} } [/tex]
Reduce the fraction with 6
[tex] \frac{ - 3 {a}^{ - 8} {b}^{ - 3} }{ {a}^{ - 2} {b}^{ - 7} } [/tex]
Simplify the expression
[tex] \frac{ - 3 {b}^{4} }{ {a}^{6} } [/tex]
Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b \: } [/tex] to rewrite the fraction
[tex] - \frac{3 {b}^{4} }{ {a}^{6} } [/tex]
Hope this helps...
Best regards!!