A coil of wire with a current is called a(n)
a.
insulator.
b.
solenoid.
c.
electromagnet.
d.
galvanometer.

It will take 1.5 seconds for Marissa's car to accelerate from 26. 4 m/s to 28. 6 m/s.

Acceleration can be calculated by looking at the change in velocity over a specific period of time. It is an important concept in physics as it is used to explain the motion of objects in the real world.

Acceleration is a measure of how quickly an object is changing its velocity on average, and it is usually expressed in meters per second squared (m/s2).

This simple calculation of Marissa's car acceleration can be determined by using the formula: Delta speed / Acceleration rate = Time taken.

In this case, that would be 2.2 m/s (28.6-26.4) / 3.6 m/s2

= 0.6 s or 1.5 sec (rounded up).

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A full stop means that there is a complete cessation of the forward movement of the vehicle, or stop with no forward motion.

If two or more automobiles arrive at a four-way stop at the same time, the car to the right shall proceed first. "If two or more automobiles arrive at a four-way stop at the same moment, the car on the right shall proceed first."

Your headlights will allow you to see roughly 400 feet ahead of you. You should travel at a speed that permits you to stop within this distance, which is around 50 miles per hour.

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The number of electrons that move in a circuit where a current of 2.0 A flows for 2.0 minutes will be [tex]1.5X10^2^2[/tex]. The correct option is C.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current.

A current of 2A passes through a wire for 20 minutes. The number of electrons that crossed the cross-section in this period is

Given that,

Current =2A

Time t= 20min = 20×60s

Let,

n and e be the number and charge of electrons in time t.

So,

The total charge, q(say) in the wire is

q = ne

Hence, the current flowing in time t is

I = q/t

I = ne/t

n = It/e

[tex]n=\frac{2(20X60)}{1.6X10^{-19}} \\\\n=\frac{2400}{1.6X10^{-19}}\\\\n=1.5X10^{22}[/tex]

Thus, the answer is [tex]1.5X10^2^2[/tex], means the correct option is C.

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Your question seems incomplete, the missing options are:

[tex]1.5X10^{21}\\\\1.5X10^{20}\\\\1.5X10^{22}\\\\1.5X10^{21}\\\\1.5X10^{23}[/tex]

Answer:

A gallon of water would be a good household object to use for strength training.

Explanation:

Gallon jugs of water typically weigh around 8.3 lbs, which can provide a good amount of resistance for strength training exercises such as bicep curls, shoulder presses, and tricep dips. Additionally, the handle on the jug of water makes it easy to grip and use for various exercises. Cans of soup and boxes of tissues are generally too light to provide enough resistance for strength training, and a paperback book may not be sturdy enough to use for certain exercises.

Two charged particles are located on the x axis.

What are charged particles?

Charged particles are particles that have either a positive or negative electrical charge. These particles can be found in many forms in nature, such as electrons, protons, and ions. These particles are a key component of electricity, and can be used as a source of energy. Charged particles can be found in atoms and molecules, where they interact with other particles and affect their behavior. They can also be found in plasma, a state of matter that is made up of ions and electrons.

1. Start by writing out the equation for the electric field at the origin:

E = (kQ)/r^2

2. Substitute in the values for Q, k, and r, and solve for the unknown charge:

E = (2keQ)/a^2

E = (2k(+Q))/(3a)^2

+Q = (2kE)/(3a)^2

Since the electric field has a magnitude of 2keQ / a2, the unknown charge can be either positive or negative:

+Q = ±(2kE)/(3a)^2

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The original speed of the bullet was 300.6 m/s.

A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.

Given:

mV bi​ +MV wi​ =mV b​ +M Vwf​

where m= mass of bullet =10 g=10^−2 ∣kg

M= mass of wood block =5 kg

V bI​ = initial mass of bullet

Vwi​ = initial mass of wood block and V bf​ =V wf​  

=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V

bi​ = 10 −2 5.01×0.6​ V

bi​ =300.6 m/s

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The average angular acceleration has a value of 0.74 rad/s2.

Applying a force tangential to the rim and in the direction of the instantaneous velocity of the piece of the rim you are applying the force to will most likely increase the angular speed. Reversing the direction of the force will slow down the angular speed.

(rad/s)/s or rad/s2 are the units of angular acceleration. If rises, is a positive number. is negative if it decreases. Remember that the positive direction is counterclockwise and the negative direction is clockwise.

F = m r α . τ=mr2α. τ = m r 2 α

initial rotaton speed=10rad/s

final speed=6.3rad/s

time=5sec.

α=(10-6.3)/5 =.74rad/s

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Answer:

1. Water pump

2. Radiator

3. Thermostat

4. AntiFreeze

5. Bypass Valve

6. Thermo switch

7. Radiator hoses

8. Fan

9. Water Pump Impeller

10. Core

Explanation:

Based on Cooling System Fundamentals, we have the following;

1. Coolant is forced through the engine and other system parts by the WATER PUMP.

2. The RADIATOR transfers engine coolant heat to the outside air.

3. Coolant flow and engine operating temperature are controlled by the THERMOSTAT.

4. ANTIFREEZE is mixed with water to produce the engine coolant.

5. A(n) BYPASS VALVE permits coolant circulation through the engine when the thermostat is closed.

6. The fan switch, or THERMO SWTICH is a temperature-sensitive switch that controls fan motor operation.

7. The engine is connected to the radiator by the RADIATOR HOSES.

8. The FAN draws air through the radiator.

9. A disc with fan-like blades that spins and produces pressure and flow is known as a(n) WATER PUMP IMPELLER

10. The center section of the radiator made up of tubes and cooling fins is called the CORE.

The force of gravitational attraction is 489.18N

                                          [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

Where,

F is the gravitational force between two bodies

m1 is the mass of the first body = 50 Kg

m2 is the mass of the second body = [tex]5.97 * 10^{24} Kg[/tex]

r is the distance between the centres of two bodies = [tex]6.38 * 10^{6} m[/tex]

G = gravitational constant = [tex]6.67 * 10^{-11}[/tex]

Putting these values in above equation we get: F = 489.18N

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When a ball moves with faster velocity, then a greater impulse force is Imparted that causes more flour to spread out.

The momentum of a system remains constant unless the system is acted on by an external force in which case the acceleration of center of mass satisfies. The force on a system of particles is the external force because the internal force is zero.

The external force is equal to the change in momentum of the system and is proportional to the acceleration of the center of mass. For a fixed choice of system, if there are no external forces acting on the system then the momentum of the system is constant is constant.

The external force may be zero in one direction but not others. The component of the system momentum is constant in the direction that the external force is zero. The component of system momentum is not constant in a direction in which external force is not zero.

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Answer: -39200.45 Nm^2/C^2       This is rough work

Explanation:

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.

Hi! Here I will explain the net force of three charges that interacts. Remember that this question can be solved using Coulomb's Law. Coulomb's Law states that the interaction force between two interacted charges will be proportional to the magnitude of the charges that have specific interaction but inversely proportional to the square of the value of the distance between each other. So, with this concept, we can calculate the magnitude of coulomb force with this equation:

[tex] \boxed{\sf{\bold{F = k \cdot \frac{q_1 \cdot q_2}{(r_{12})^2}}}} [/tex]

On this condition, the net force will be felt only by the first charge, so we must define the position of the first charge as a fixed one. So, we can calculate the magnitude of coulomb force concerning the first charge with this equation:

[tex] \boxed{\sf{\bold{\sum F_{q1} = k \cdot (\frac{q_1 \cdot q_2}{(r_{12})^2} + \frac{q_1 \cdot q_3}{(r_{13})^2})}}} [/tex]

With the following condition:

[See the attached image to know how to solve this problem]

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.

If you pound a feather with a hammer, which one feels a greater force always the hammer both feather moves, then it felt the greater force.

What is the force?
Force is an influence that produces a change in the motion of an object. It is measured in units of mass times acceleration, or newtons (N). Force is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to accelerate, decelerate, remain in motion, change direction, or alter shape. Examples of forces include gravity, friction, tension, and magnetism. Forces can also be generated by electrical, thermal, and nuclear energy. All forces are generated by the interaction of two objects and can be balanced or unbalanced. Unbalanced forces will cause an object to move or accelerate and balanced forces will cause an object to remain stationary or in motion at a constant speed.

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For the Direct free kick, the game restarted.

There are two different kinds of free kicks used in soccer: direct and indirect.The term "direct free kick" refers to a kick that can be used as a direct strike.Indirect free kicks require a second touch before the ball can be used as a shot at goal.

If a player attacks an opponent in a way that the referee deems to be irresponsible, reckless, or employing excessive force, the referee will award a direct free kick.jumps, kicks, or makes an attempt to kick.

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According to reports, the biggest meteorite with lunar origin weighs 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, 0.22 m is the compression of the spring.

We can use Hooke's Law to calculate the compression of the spring caused by the meteorite. Hooke's Law states that the force exerted on a spring is directly proportional to the spring's compression or extension.

= F

= k * x

where F is the force (in newtons), k is the spring constant (in N/m), and x is the compression (in meters).

Given the mass of the meteorite is 19 g and the spring constant is 83 N/m, the force exerted on the spring can be calculated as

= F

= (mass of the meteorite) * g

= (19 g) * (9.8 m/s^2)

The compression of the spring can be found by rearranging Hooke's Law and substituting in the force and spring constant

x = F/k

x = (19 * 9.8) / 83

x = 0.22 m

The compression of the spring caused by the meteorite is 0.22 m.

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Given :

A 2kg object is moving with speed 5m/s. then hits a  wall in 0.5s before reversing its direction with a speed of 2m/s.

To Find :

The impulse.

Solution :

Impulse can be calculated by change in momentum :

[tex]I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s[/tex]

Therefore, the impulse is 6 kg m/s.

It would take 5 pounds of force, that is equal force, to stop the ball from rolling because the same amount of force must be used to stop the object.

According to Newton's third law of motion, every action which is occurring in nature has an equal as well as an opposite reaction. For instance, if a particular object A happens to exert a force on another object B, then  object B will also be exerting an equal as well as an opposite force on  object A.

If a particular ball is rolling with 5 pounds of force then the same amount of reaction will be required to bring it to rest. That is, equal force of 5 pounds will be required to stop the ball.

Hence, option D is the correct option.

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Explanation:

the force effect the aeroplane and ship are Gravity and drug

Answer:

The answer is GRAVITY and DRUGS

Explanation:

Hope you have a good day :)

The right response is a hockey puck slides along a horizontal icy frictionless surface and as a car is going along a straight road at a constant pace, according to the motion diagram.

The car is shown in the diagram starting at point a. The arrows remain pointing in the same way. This indicates that the thing is travelling directly forward. The arrows stay stationary at A. This indicates that the thing is travelling continuously.

The speed of the puck is not impacted by friction while it is moving on an ice rink surface. So, it is reasonable to suppose that it is moving at a constant speed before to impact.

The work done is zero only if there is no non-conservative force, such as friction, because the kinetic energy does not vary and the car is going along a straight, horizontal road. The work done will be force into displacement if there is friction.

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Answer:

C. 28.39 gram

Explanation:

Steps:

m = V × ρ

= 34 cubic centimeter × .835 gram/cubic centimeter

= 28.39 gram

The current through the bottom of the wire is 0.415 A and the negative sign of the current indicates that current flows from left to right from the bottom wire.

The current through various parts of the circuit is as shown in figure.

Here we have to calculate the current I_5.

Applying Kirchoff's loop rule on each of the loops in the circuit, Consider the left triangle, for it, we have

[tex]$$\begin{aligned}& \left(I_1\right) 6 \Omega+\left(I_3\right) 12 \Omega-9 \mathrm{~V}=0 \\& \Rightarrow 6 I_1+12 I_3=9 \\& \Rightarrow I_1=\frac{9}{6}-\frac{12}{6} I_3 \\& \Rightarrow I_1=1.5-2 I_3-----(1)\end{aligned}$$[/tex]

For the centre of the triangle, we have

[tex]$$\begin{aligned}& \left(I_4\right) 24 \Omega-\left(I_3\right) 12 \Omega=0 \\& \Rightarrow I_4=\frac{12}{24} I_3 \\& \Rightarrow I_4=\frac{I_3}{2}-----(2)\end{aligned}$$[/tex]

And for the right triangle, we have

[tex]$$\begin{aligned}& \left(I_2\right) 10 \Omega+\left(I_4\right) 24 \Omega-15 \mathrm{~V}=0 \\& \Rightarrow I_2=\frac{15}{10}-\frac{24}{10} I_4 \\& \Rightarrow I_2=1.5-2.4 I_4------(3)\end{aligned}$$[/tex]

The junction rule applied at the left corner gives

I_1  =I_3+I_5

=I_5  =I_1-I_3

=1.5-2 I_3-(I_3)=1.5-3 I_3--------(4)

And applying the junction rule at the right corner,

I_4 =I_2+I_5

I_5 =I_4-I_2

=I_4-(1.5-2.4 I_4)=3.4 I_4-1.5-------(5)

Using equation (2) [tex]$I_4=\frac{I_3}{2}$[/tex], equation (5) can be written as

[tex]$$\begin{aligned}I_5 & =3.4\left(\frac{I_3}{2}\right)-1.5 \\\end{aligned}$$[/tex]==1.7 I_3-1.5

Solving equations (4) and (6), we have

1.5-3 I_3=1.7 I_3-1.5

(1.5+1.5)=(1.7+3.0) I_3

3.0=4.7 I_3

[tex]\Rightarrow I_3=\frac{3.0}{4.7} \mathrm{~A}[/tex]

Hence the current in the bottom wire is given by

[tex]I_5 & =1.7\left(\frac{3.0}{4.7}\right)-1.5 \\[/tex] =1.085-1.5 =-0.415 A

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Answer:

An amp is one C per second. Two minutes is 120 seconds. So current is 10 C/120 sec which is 1/12 th of an Amp.

Given :

An engine creates a 2230 N force that pushes a car forward 58.3 m in 9.40 s.

To Find :

How much power does the engine produce in Watt.

Solution :

We know, Work done is given by :

[tex]W = F.d\\\\W = 2230 \times 58.3 \ J\\\\W = 130009\ J[/tex]

Now, Power is given by :

[tex]Power = \dfrac{Work \ Done}{Time \ Taken}\\\\P = \dfrac{130009}{9.4}\ W\\\\P = 13830.74\ W[/tex]

Therefore, power produced by engine is 13830.74 W.

The kinetic energy would be 96 J, for the car moving at 4m/s and with 3kg mass.

The kinetic energy (Ek) of the toy car is given by Ek = ½ mv2, where m is the mass of the car (3 kg) and v is the velocity (4 m/s). Thus, the kinetic energy of the car is 24 J. If the car were moving twice as fast (8 m/s), the kinetic energy would be 96 J. The units are Joules (J).

Kinetic energy is the energy of a body or system due to its motion. It is the energy that an object has due to its motion. Kinetic energy is equal to one half of the mass of the object multiplied by the square of its velocity.

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Answer:

In my opinion I think the answer is C you don't have to choose C

Answer:

A The additional potential energy the reactants must gain in order toreact

Explanation:

Answer:
For this I believe that your working on Ocean layers in science physics
There are actually 5 ocean zones or layers. (here they are in order)
1. Sunlight zone
2. Twighlight zone
3. Midnight zone
4. Abyssal Zone
5. Hadal zone
As a rephrase of the question I believe you meant to say
What are the marine zones?
Please correct me if wrong!!

Electrical burns can occur in a variety of ways, including arc burns, low voltage burns, high voltage burns, mouth burns, flash burns, and flame burns.

Electric shock, a serious electrical mishap, or a fatal electrical event are all considered electrical incidents.

For the purposes of reporting and analysis, incident definition types let you attribute the appropriate type to safety events. Having only the two types of incidents—Accident and Near Miss—is one strategy.

An occurrence or scenario that has a number of serious repercussions and necessitates the implementation of special measures by one or more emergency responder agencies is referred to as a big incident.

Any electrical incident that results in or has the potential to result in: death or serious bodily harm to a person; significant property damage; or a serious risk to the public safety must be reported, according to the Electrical Safety (General) Regulations of 2019.

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At kelvin temperature T, cylinder A includes n molecule of a gas, and the force exerted by the gas on the cylinder is NkBT/l.

When two bodies interact, it refers to any form of pushing or pulling that one body exerts on the other. A vector quantity, that is. For instance, a person pushes or pulls on something to provide force, such as opening a door.

Contact forces that act at a remove forces are the two different types of forces. Your daily use of force is evident. Basically, pressure and pull are forces.

Formulas,

-P = F/A

-n = n/Na

-PV = nRT

= NKT (R = KNa)

- Volume of cylinder: A* l

F=PA

P = NKbT / V

P = NKbT / A* l

F = NkBT / A * l (A)

Cross out A,

Final, F = NkBT/l.

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