Soccer
Enter the ratio of hockey players to soccer players in the form and then as a decimal showing up to four
decimal places. Tell whether the decimal is a terminating or a repeating decimal.
10
The ratio is
The decimal form is
The decimal is terminating
Answer:
Ratio: [tex]=\mathbf{\frac{6}{11}}[/tex]
The decimal form (showing up to four decimal places): 0.5454
The decimal is a repeating decimal i.e 0.54545454..
Step-by-step explanation:
We need to find ratio of hockey players to soccer players
Number of players playing Hockey= 6
Number of players playing Soccer = 11
Ratio: [tex]\frac{Hockey\:Players}{Soccer\:Players} =\mathbf{\frac{6}{11}}[/tex]
The decimal form (showing up to four decimal places): 0.5454
Tell whether the decimal is a terminating or a repeating decimal.
The decimal is a repeating decimal i.e 0.54545454..
What is the next fraction in this sequence? 2/477, 2/159, 2/53, 6/52
Answer:
9/26
Step-by-step explanation:
2/159÷2/477=2/53÷2/159=6/52÷2/53=3
x÷6/52=3
x=18/52
x=9/26
Emily is a pharmacist. She earns $45.80 per hour. If she works on a holiday, she gets paid double the
hourly rate. Last week she worked for 38 hours and 8 of those hours on a holiday. Emily's salary is her only
source of income.
If her net income was $1,783.62, then how much was her payroll tax?
Her payroll tax was $
help me please i need help
Answer: yes they are equivalent
Step-by-step explanation: When you distribute both equations, you end up with 5m-10.
write down the relation between mass and inerti
Answer:
The mass of an object is directly proportional to its inertia.
[tex]m\alpha I[/tex]
Where
m = mass
I = inertia
Step-by-step explanation:
We can first of all start by defining the two key terms present here - mass and inertia.
The mass of an object is the quantity of matter contained in the object.
The inertia of an object is the resistance of an object which is in a state of rest to motion
The mass of an object is directly proportional to its inertia.
The heavier an object is, the more inertia it has. To put things into perspective, you can easily push a bicycle because it does not really have a lot of mass, as opposed to pushing an eighteen-wheeler trailer.
Name a point on this line.
y + 2 = 3(x – 4)
Question 3 options:
(4,-2)
(-2,4)
(2,-4)
(-4,2)
Four positive whole numbers add up to 93
One of the numbers is a multiple of 19
The other three numbers are equal.
Write the four numbers in ascending order.
Answer:
Let the numbers be a, b, c, d
[tex] { \tt{a + b + c + d = 93}}[/tex]
Let a be the multiple of 19, a = 57
And b = c = d
[tex]{ \tt{57+ 3b= 93}} \\ { \tt{3b = 36}} \\ { \tt{b = 12}}[/tex]
[tex]{ \tt{a = 57}} \\ { \tt{b = c = d = 12}} \\ \\ { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{57}}}[/tex]
Answer:
12, 12, 12, 57
Step-by-step explanation:
Given:
Four positive whole numbers add up to 93.One of the numbers is a multiple of 19.The other three numbers are equal.If one of the four numbers is a multiple of 19 and the other three numbers are equal, then the sum of the other three numbers will be a multiple of 3.
Multiples of 19:
19, 38, 57, 76, 95, ...
Subtract each multiple of 19 (that is less than 93) from 93:
⇒ 93 - 19 = 74 → not divisible by 3
⇒ 93 - 38 = 55 → not divisible by 3
⇒ 93 - 57 = 36 → divisible by 3
⇒ 93 - 76 = 17 → not divisible by 3
The only result that is a multiple of 3 is 36.
Therefore, the multiple of 19 is 57.
To find the other three numbers, simply divide the result of the total less the found multiple of 19 by 3:
⇒ (93 - 57) ÷ 3 = 36 ÷ 3 = 12
Therefore, the four numbers in ascending order are:
12, 12, 12, 57
diameter of the circle whose radius is given
a) 3.5cm
During a basketball game, Kevin made a total of 14 shots. Each basketball shot is worth either 2 points or 3 points. Kevin scored a total of 34 points. Let a represent the number of 2 point shots and let y represent the number of 3 point shots.
Answer:
following is the answer for your question this can be done in the manner
What is 4h - 11 = h+ 16
PLEASE HELP IF YOU ANSWER CORRECTLY I WILL GIVE BRAINLYIST (sorry if I spelled it wrong) BUT PLEASE ANSWER FAST!
Answer:
The first option
Step-by-step explanation:
Answer:
1st one
Step-by-step explanation:
Opposite of positive 3 is negative 3.
Step sis need a new dryer. Her thicc ahss couldn't fit
Answer:
HAHAHAHH
Step-by-step explanation:
Write the polynomial in standard form.
8g- 9g3 +4g2 - 10
a. 9g3+4g2 + 8g - 10
B.-10 + 8g + 4g2 -9g3
c. 4g3 -9g2 + 8g - 10
d: 9g3 +4g2 + 8g - 10
Number 3
Simplify: x - 12 +5 - 4x
Answer:
-3x -7
Step-by-step explanation:
Add the numbers:
x-12+ 5-4x
x-7 -4x
Combine like terms:
x-7 -4x
-3x -7
Solution:
-3x -7
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Prove: The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases.
Slopes are equal; therefore, segments are parallel
The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases
How to prove: The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases?From the figure, we have the following coordinates
B = (a, 0)
D = (d, c)
The midpoint of line segment BD is calculated as
BD = 1/2 * (x1 + x2, y1 + y2)
So, we have
BD = 1/2 * (a + d, 0 + c)
This gives
BD = ((a + d)/2, c/2)
Also, we have:
Lines MN and AB are horizontal lines
This means that they have a slope of 0
i.e.
Slope of AB = Slope of MN = 0
Parallel lines have equal slope
Hence, the segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases
Read more about parallel base at
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Select the correct answer.
Which limit does not exist?
Answer:
B
Step-by-step explanation:
(look up limit calculator)
a has a limit
b does not exist
c has a limit
d has a limit
e has a limit
Option D is correct one. Limit doesn't exist for [tex]\lim_{x\to \ 2} \frac{x^{2}-6x +8 }{x-2}[/tex].
When a limit is said to be exist?
The limit of f(x) at x = a is said to be exist if the function approaches the same value from both the sides i.e. LHL =RHL (left hand limit = right hand limit)
According to the question we have,
A. [tex]\lim_{x \to \ 1} \frac{2-x}{x+1}[/tex]
at x =1
LHL = [tex]\lim_{h \to \ 0 } \frac{2- (1-h)}{(1-h)+1}[/tex] = [tex]\frac{1}{2}[/tex]
RHL = [tex]\lim_{h \to \0} \frac{(2-(1+h) }{(1+h)+1)} =\frac{1}{2}[/tex]
Here, RHL = LHL
Hence, limit exist.
B. [tex]\lim_{x \to \ 2} \frac{x^{2} -8}{x-2}[/tex]
at x =2
LHL = [tex]\lim_{h \to \ 0} \frac{(2-h)^{2}-9 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{4+h^{2} -9-4h}{2-h-2}[/tex] = [tex]\lim_{h \to \ 0 }\frac{2h-4}{-1} =\frac{-4}{-1} =4[/tex]
RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -9}{(2+h)-2}[/tex] = [tex]\lim_{h \to \ 0} \frac{4h +4 +h^{2}-9 }{h} = \lim_{h \to \ 0} \frac{2h+4}{1}[/tex]=4
Here, RHL = LHL
Hence, the limit exist.
C. [tex]\lim_{x \to \ 1} (x^{2} -2x-5)[/tex]
at x =1
LHL = [tex]\lim_{h \to \ 0} (( 1-h)^{2} -2(1-h)-5)= \lim_{h \to \ 0} (1 -2-5)=-6[/tex]
RHL = [tex]\lim_{h \to \ 0} ((1+h)^{2} -2(1+h)-5) = (1-2-5)=-6[/tex]
Here, LHL = RHL = -6
Hence, the limits exist.
D. [tex]\lim_{x \to \ 2} \frac{x^{2}-6x + 8 }{x - 2}[/tex]
at x =2
LHL = [tex]\lim_{h \to \0} \frac{(2-h)^{2} -(2-h)+8}{(2-h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}-4h-2+h+8 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{2h-4+1}{1} =-3[/tex]
RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -(2+h) +8}{(2+h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}+4h -2-h+8}{h} = \lim_{h \to \ 0} \frac{2h+4-1}{1} =3[/tex]
Here, RHL≠LHL
Hence, the limit doesn't exist.
E. [tex]\lim_{x \to \ 3} (x^{2} -3x-1)[/tex]
at x = 3
LHL = [tex]\lim_{h \to \ 0} ((3-h)^{2} -3(3-h)-1)[/tex] = [tex]9-9-1=-1[/tex]
RHL= [tex]\lim_{h \to \ 0} ((3+h)^{2} -3(3+h)-1)= 9-9-1 =-1[/tex]
Here, RHL = LHL
Hence, the limit exist.
Learn more about limit here:
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Triangle ABE ~ Triangle CDE. Find the length of altitude for NE.
please help me? :( I really need it!
Answer:
D
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Quinn discovered a recipe for chocolate chip cookies that require 3/4 cups Brown sugar for every 2 cups of flour. How much Brown sugar will she need if she uses 6 1/2 cups of flour?
Answer:
Quinn will need 2 3/4 cups of brown sugar for 6 1/2 cups of flour
Step-by-step explanation:
If you change 3/4 into decimal form you get .75. You then multiply .75 by 3, because 2*3=6, to get 2.25 or 2 1/4. Then add the 1/2, or 2/4, to 2 1/4. You get 2 3/4
Calculate the product below and give your answer in scientific notation.
(3.3 x 10-4) × (8.0 × 10⁰) = ?
X
Answer:
goood luccccccckkkk...
ill give brainlest help please
Answer:
it's c i did this a week ago
WILL GIVE BRAINLIEST IF CORRECT!!
Coco flips a penny, a nickel, and a quarter. Each coin is fair (meaning that heads and tails are equally likely to come up). What is the probability that at least one of the coins comes up heads?
Enter your answer as a fraction in simplified form.
Answer:
7/8
Step-by-step explanation:
Using the binomial distribution, it is found that there is a [tex]\frac{7}{8}[/tex] probability that at least one of the coins comes up heads.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.In this problem:
A coin is fair, hence p = 1/2.Three coins are thrown, hence n = 3.The probability that at least one of the coins comes up heads is given by:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{3,0}.\left(\frac{1}{2}\right)^{0}.\left(\frac{1}{2}\right)^{3} = \frac{1}{8}[/tex]
Then:
[tex]P(X \geq 1) = 1 - P(X = 0) = \frac{8}{8} - \frac{1}{8} = \frac{7}{8}[/tex]
[tex]\frac{7}{8}[/tex] probability that at least one of the coins comes up heads.
More can be learned about the binomial distribution at https://brainly.com/question/24863377
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Find the of the slope of the line through (6,-10) and (4,-8)
Answer:
-1
Step-by-step explanation:
y = mx + c
m is the slope/gradient
to find slope = y2 - y1 / x2 - x1
= -8 - -10 / 4 - 6
m = -1
Which number is prime?
58
74
84
41
you add all the prime numbers between 2 and 33 and then multiply it by itself what you get?
Answer:
24964
Step-by-step explanation:
hope this works : ) - btw this is not including 2 and 33
what 1/4 in index form?
Answer:
Step-by-step explanation:
4^-1
Jose is going to watch a movie in his collection. He has 7 action movies, 12 comedies, and 2 dramas.
He will randomly select one movie. What is the probability that the movie he selects is not an action movie?
Write your answer as a fraction in simplest form.
Answer:
14/21 or 2/3
Step-by-step explanation:
Part A: A graph passes through the points (0, 2), (2, 6), and (3, 12). Does this graph represent a linear function or a non-linear function? Explain your answer in words.
Part B: Write one example of a linear function and one example of a non-linear function. (Use x and y as the variables) (10 points)
Answer:
Step-by-step explanation:
Part A: No. The line would have to be straight in order for the graph to be linear.
Part B:
Linear: y=2x-4.
Nonlinear: y=x^2-6.
(9x +10) (15x-2) solve for x
Answer:
x=2
Step-by-step explanation:
15x-9x = 6x
10+2 = 12
6x=12
x=2
Answer: x=2
Step-by-step explanation:
9x+10 = 15x-2
-9x -9x
____________
10 = 6x-2
+2 +2
__________
12=6x
Divide
x=2
Decide whether the relation is a function:
{(-3, 7), (1, -8), (6, -6), (7-8), (12, 2)}
Answer:
It is a function
Step-by-step explanation:
A function is of the form:
[tex]\left[\begin{array}{c}x_1&x_2&x_3\\-&-&-\\x_n\end{array}\right][/tex] [tex]\left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right][/tex]
Where each of the x values must be distinct.
The x values are referred to as domain while the y values are called range.
Having said that, the given data can be represented as follows:
[tex]\left[\begin{array}{c}-3&1&6\\7&12\end{array}\right][/tex] ----------- [tex]\left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right][/tex]
From the representation above, none of the x values are repeated.
Hence, it is a function