Answer:
The maximum speed is 21.1 m/s
Explanation:
Given that,
Radius of curve = 119 m
Maximum speed = 30 m/s
New radius = 59.5 m
We need to calculate the maximum acceleration
Using formula of acceleration
[tex]a_{c}=\dfrac{v^2}{r}[/tex]
Where, v = maximum speed
r = radius
a = acceleration
Put the value into the formula
[tex]a_{c}=\dfrac{30^2}{119}[/tex]
[tex]a_{c}=7.5\ m/s^2[/tex]
We need to calculate the maximum speed
Using formula of speed
[tex]v_{max}=\sqrt{a\times r}[/tex]
Put the value into the formula
[tex]v_{max}=\sqrt{7.5\times59.5}[/tex]
[tex]v_{max}=21.1\ m/s[/tex]
Hence, The maximum speed is 21.1 m/s
The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including __________. A. fairness B. honesty C. respect D. all of the above
Answer:
the answer is D
Explanation:
Just took the test
The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including fairness, honesty and respect.
What is NCAA?
NCAA stands for National Collegiate Athletic Association. The NCAA is a organization which will be useful for the well being and the success for life long to the college Athelet.
A person who got graduate from high school and completed a minimum of 16 core courses for Division I or II and to earn a minimum required grade-point average in normal core courses and also must earn a qualifying test score on either the ACT or SAT will be eligible to join NCAA.
The NCAA Sportsmanship Award honors a student-athlete who will takes actions in the competitive arena of intercollegiate athletics and who demonstrated one or more of the ideals of sportsmanship, including fairness, civility, honesty, unselfishness, respect and responsibility.
Hence, Option D is the correct answer.
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Average velocity of Mike Phelps swimming 100 m race in the 50 m long pool (2 laps) is approximately equal to
A. 0 m/s
B. 1 m/s
C. 2 m/s
D. 4 m/s
Answer:
I’m really not sur but I think it’s b
Explanation:
An athlete can exercise by making mechanical waves in ropes. What is the
medium of these waves?
A. Energy
B. The rope
C. The athlete
D. Air
Answer:
It would be B. The Rope
Explanation:
I say this because the rope is transferring energy from one location to another. Now, I could be totally wrong on this but I think this is right lol.
Answer:
The answer is B the rope.
Hope this helps <3 ;)
Trently limited
Spiderman's cell phone falls from his pocket while he is surveying the city. His spider senses have
failed him. It takes the phone 3.6s to crash into the pavement below. How high up was Spiderman?
Answer:
h= 63.5 m
Explanation:
Assuming that air resistance is neglectable, and that the phone drops from Spiderman's pocket, we can use the following kinematic equation for the vertical displacement:[tex]\Delta h = \frac{1}2} * g* t^{2} = \frac{1}{2} *(-9.8 m/s2)*(3.6s)^{2} = -63.5 m[/tex]
[tex]\Delta h = y - y{o} = -63.5 m[/tex]Taking as zero level reference the ground level, we get:y₀ = h = 63.5 m
Water inside a tub rises from 15 mL to 19 mL when an object is submerged. If the mass of the object is 249, what's the density of
the object?
O A.6 g/ml
O B. 0.8 g/mL
O C.4g/ml
O D. 0.12 g/mL
Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question
mass = 249 g
volume = final volume of water - initial volume of water
volume = 19 - 15 = 4 mL
We have
[tex]density = \frac{249}{4} \\ [/tex]
We have the final answer as
62.25 g/mLHope this helps you
In this activity, you're going to write a SUMMARY paragraph for this lesson over Measuring and Graphing Motion. In your summary, you will use the following keywords:
Graphs
X axis, Y axis
Motion
Speed
Distance-time graph
Position-time graph
Speed-time graph
Include examples for the types of graphs and how they tell a story about how something moves.
Jodi made a list about electric current to help her study for a test.
1) Movement of electrons is continuous in a current.
2) Electrons move from areas of low to high electric potential.
3) Voltage causes current to flow.
4) Rate at which current flows is measured in amperes.
Which best describes Jodi’s error?
A) The movement of electrons is not always continuous.
B) Electrons move from areas of high to low electric potential.
C) Resistance causes current to flow.
D) The rate at which current flows is measured in ohms.
Answer: The answer is B; Electrons move from areas of high to low electric potential
Explanation:
I had this question on a quiz and got it correct.
The required Electrons move from areas of high to low electric potential best describes Jodi’s error. Option B is correct.
What is electric current?Electric current is the flow of electric charge through a material. It is typically expressed in units of amperes (A), which represent the rate at which charge flows through a conductor.
Here,
Jodi's error is in statement 2. Electrons move from areas of high electric potential to areas of low electric potential, not from low to high electric potential. This is because electric potential is a measure of the energy per unit charge, so electrons will naturally flow from areas of higher potential to areas of lower potential to balance out the potential difference.
Thus, the required, Electrons move from areas of high to low electric potential best describes Jodi’s error. Option B is correct.
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3500 as a power of 10
Answer: 3.5 × 10^3
Explanation:
Select the choice from the list below that most accurately completes the statements below. The first phrase will go in the first blank of the statement and the second phrase will go in the second blank.
A 1: greater than 2: because of Newton's Second Law
B 1: less than 2: because of Newton's Third Law
C 1: equal to 2: because of Newton's Third Law.
D 1: equal to 2: because of Newton's Second Law
E 1: less than 2: because of Newton's Second Law
F 1: greater than 2: because of Newton's Third Law.
You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is _________the magnitude of your force. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is____________the magnitude of your force. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is___________the magnitude of the normal force from you on the ground. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is _____________the magnitude of your weight. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is __________the magnitude of the force from you on Worf. You are standing at a place where the ground is level. The magnitude of your weight is__________the magnitude of the normal force from the ground on you.
Answer:
this question requires us to use our knowledge of newton's 1st 2nd and 3rd laws to fill in the blank spaces. the words in bold are the answers to the question
Explanation:
1. You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is greater than the magnitude of your force because of newtons second law
2. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is equal to the magnitude of your force because of newtons second law
3. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is equal to the magnitude of the normal force from you on the ground because of newtons third law.
4. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is less than the magnitude of your weight because of newtons second law
5. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is equal to the magnitude of the force from you on Worf because of newtons third law
6. You are standing at a place where the ground is level. The magnitude of your weight is equal to the magnitude of the normal force from the ground on you newtons second law
Neutral hydrogen can be modeled as a positive point charge +1.6×10^−19C surrounded by a distribution of negative charge with volume density given by rhoE(r)=−Ae−2r/a0 where a0=0.53×10^−10m is called the Bohr radius, A is a constant such that the total amount of negative charge is −1.6×10^−19C, and e = 2.718 is the base of the natural log.
Required:
a. What is the net charge inside a sphere of radius a0?
b. What is the strength of the electric field at a distance a0 from the nucleus?
Answer:
a) 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b) 3.466 × 10¹¹ N/C
Explanation:
a)
p(r) = -A exp ( - 2r/a₀)
Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV = -A ₀∫^∞ ₀∫^π ₀∫^2π exp ( - 2r/a₀)r² sinθdrdθd∅
Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e
now using integration by parts;
A = e / πa₀³
p(r) = - (e / πa₀³) exp (-2r/a₀)
Now Net charge inside a sphere of radius a₀ i.e Qnet is;
= e - (e / πa₀³) ₀∫^a₀ ₀∫^π ₀∫^2π r² exp (-2r/a₀)dr
= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b)
Using Gauss's law,
E × 4πa₀ ² = Qnet / ∈₀
E = 4πa₀ ² × Qnet × 1/a₀²
E = 3.466 × 10¹¹ N/C
what is the objects final displacement
Answer:
Explanation:
The object starts at 0
It moves to - 2
It stops
It then moves to + 6
+6 - 2 = + 4
The new position is 4.
PLEASE HELP!!
A box falls out of an airplane that is traveling horizontally at 100m/s. The plane is at an altitude of 300m.
Where does the box land relative to where it was dropped from?
Answer:
Explanation:
Key point: the vertical motion is free fall, the horizontal motion remains at uniform speed of 100 m/s (because there is no force in the horizontal direction if we neglect air resistance.)
The time of free fall can be calculated first:
h = 1/2 g t^2 => t = sqrt(2 h /g) = sqrt(2 * 300 m / 9.81 s) = 7.82 seconds.
In that time, the horizontal displacement will be
s = v_horizontal * t = 100 m/s * 7.82 s = 782 m.
So the box will land 782 m further than the point it was dropped from (and 300 m lower of course)
Which of the following is NOT a unit of measurement for speed?
I don't see any units of measurement or speed I don't see anything
A cat chases a mouse across a 1.0 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 2.3 m from the edge of the table. The acceleration of gravity is 9.81 m/s2. What was the cat's speed when it slid off the table? Answer in units of m/s.
Analysing the question:
We are given that the cat chases a rat on a 1m high table, this means that the height of the cat before falling is 1 m
The horizontal velocity of the cat after sliding off the table will not change in mid-air since there is no force to oppose it
We are given:
height of the cat before falling (h) = 1 m
Distance covered by cat after falling off the edge = 2.3 m
acceleration due to gravity (a) = 9.81 m/s²
initial vertical velocity of the cat (u) = 0 m/s
Since the cat will fall at a constant horizontal velocity, the time taken by the cat to reach the ground times the constant speed of the cat will be equal to the horizontal distance covered by the cat
[ since time taken to reach the ground = time for which the constant horizontal velocity will be applied]
The above can simply be written as:
time taken by the cat to reach the ground * horizontal velocity = horizontal distance covered
Time taken by the cat to reach the ground:
From the second equation of motion
s = ut + 1/2*at²
replacing the variables with vertical components
1 = (0)(t) + 1/2 * (9.8)(t²)
1 = 4.9t²
t² = 1 / 4.9
t = 1 / √4.9
t = 0.45 seconds
Cat's horizontal velocity when it slid off the table:
Speed of cat = distance travelled / time taken
here, the distance is the horizontal distance covered by the cat after falling off the table
replacing the variables
Speed of the cat = 2.3 / 0.45 = 5.11 m/s
a 1,200 kg car travels at 20 m/s. what is it’s momentum ?
Answer:
24000 kg·m/s
Explanation:
Momentum is Mass x Velocity, so 1200 kg time 20 m/s = 24000 kg-ms/s
The momentum of the car is 24000 Kg•m/s
Momentum is defined as the product of mass and velocity. Mathematically, it can be expressed as:
Momentum = mass × velocity
With the above formula, we can obtain the momentum of the car as follow:
Mass = 1200 KgVelocity = 20 m/sMomentum =?Momentum = mass × velocity
Momentum = 1200 × 20
Momentum of car = 24000 Kg•m/s
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What does the diameter in meters need to be of a round parachute that the designer has determined needs to have an area of 500 square meters?
PLEASE PROVIDE EXPLANATION
Answer:
(a) 9.52
(b) 3.81
Explanation:
Draw a free body diagram of block m. There are two forces:
Weight mg pulling down, and tension T₁ pulling up.
Draw a free body diagram of block M. There are two forces:
Weight Mg pulling down, and tension T₂ pulling up.
Draw a free body diagram of the double pulley. There are two torques:
Tension T₂ pulling counterclockwise at r, and tension T₁ pulling clockwise at R.
Let's assume that M moves down, m moves up, and the pulley rotates counterclockwise.
Sum of forces on block m in the +y direction:
∑F = ma
T₁ − mg = ma₁
T₁ = mg + ma₁
Sum of forces on block M in the -y direction:
∑F = ma
Mg − T₂ = Ma₂
T₂ = Mg − Ma₂
Sum of the torques about the pulley's center in the counterclockwise direction:
∑τ = Iα
T₂ r − T₁ R = (½ m₀ r² + ½ m₀ R²) α
T₂ r − T₁ R = ½ m₀ (r² + R²) α
Substitute:
(Mg − Ma₂) r − (mg + ma₁) R = ½ m₀ (r² + R²) α
The strings don't slip on the pulley, so a₁ = αR and a₂ = αr.
(Mg − Mαr) r − (mg + mαR) R = ½ m₀ (r² + R²) α
Mgr − Mαr² − mgR − mαR² = ½ m₀ (r² + R²) α
g (Mr − mR) − α (Mr² + mR²) = ½ m₀ (r² + R²) α
g (Mr − mR) = [½ m₀ (r² + R²) + Mr² + mR²] α
α = g (Mr − mR) / [½ m₀ (r² + R²) + Mr² + mR²]
α = (10) (9×0.2 − 1×0.5) / (½ (0.5) (0.2² + 0.5²) + 9(0.2)² + 1(0.5)²]
α = 19.0 rad/s²
Therefore:
a₁ = αR = (19.0 rad/s²) (0.5 m) = 9.52 m/s²
a₂ = αr = (19.0 rad/s²) (0.2 m) = 3.81 m/s²
Which statement accurately describes an objects weight and mass?
Answer: A-p_Ex
Explanation: answer
A body start from rest are moves with uniform acceleration of 60m/1/5^2.what distance does it cover in third second?
Answer:
Let's see what to do buddy...
Explanation:
_________________________________
[tex]a = \frac{60}{ ({ \frac{1}{5}) }^{2} } = \frac{60}{ \frac{1}{25} } = 60 \times 25 \\ \\ a = 15 \times 4 \times 25 = 15 \times 100 \\ a = 1500 \: \frac{m}{ {s}^{2} } [/tex]
_________________________________
The body start from rest which means :
[tex]v(0) = 0[/tex]
_________________________________
In third second means :
t = 2 -----¢ t = 3 -----¢ ∆t = 1
_________________________________
We have this equation to find the distance.
[tex] ∆x = \frac{1}{2} \: a \: {t}^{2} + v(0) \: t \\ [/tex]
_________________________________
[tex]∆x = \frac{1}{2} \times 1500 \times 1 + 0 \times 1 \\ \\ ∆x = 750 + 0 = 750[/tex]
_________________________________
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
you breathe in oxygen gas in air, but oxygen can exist in all four states. Four samples of oxygen have the same mass but are each in a different state. which statement about the relative amounts of thermal energy in the samples is true?
A. The sample of liquid has more energy that the sample of gas.
B. The sample of solid has more energy that the sample of gas.
C. The sample of plasma has less energy than the sample gas.
D. The sample of plasma has more energy than the sample of gas.
PLEASE HELP
It is true that the sample of plasma has more energy than the sample of gas. Option D is correct.
What is gas?Gas is a sample of matter that adopts the shape of the container in which it is housed and develops a uniform density inside the container.
Liquid molecules are more energetic than solid molecules. Further heating will cause the molecules to move so quickly that they won't stick together at all. The gas molecules have the highest energy content.
Although oxygen is a gas that you breathe in, it may also exist in all four other states. The mass of the four oxygen samples is the same, yet they are all in distinct states.
Regarding the relative levels of thermal energy in the samples, statement B is accurate. Regarding the proportional quantities of thermal energy in the samples,
It is true that the sample of plasma has more energy than the sample of gas.
Hence, option D is correct.
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A car has initial velocity of 72 km/hr. It is accelerated at 2m/s2
Calculate the final velocity and distance covered after 3 sec.
What is the distance covered by a car in 3rd second?
Answer:
Vf=78
d=
Explanation:
vf=vi+at
=72+(2)(3)
=78km/hr
d=vit+1/2at^2
=(72)(3)+1/2 (2)(3)^2
=216+9
=225m
1) 26m/s
2) 69 m
Explanation:Hi there !
1)
a = (v₂ - v₁)/t => at = v₂ - v₁ => v₂ = at + v₁
v₁ = 72km/h = 72000m/3600s = 20m/s
v₂ = 2m/s²ₓ3s + 20m/s
= 6m/s + 20m/s
= 26 m/s
2)
d = v₁t + at²/2
= 20m/sₓ3s + 2m/s²ₓ9s²/2
= 60m + 9m
= 69 m
Good luck !
If two vector are perpendicular to each other, how should you add them
Answer:
Using pythagoras theorem
Answer:
use the pythagorean theorem
Explanation:
If a park is 5 miles away what is the average speed you have to maintain to arrive in 15 minutes
Answer:
3 miles per hour
Explanation:
15 divided by 5 = 3
A liquid at rest in a fixed container exerts a force perpendicular to the wall of the container. Two students make claims about the microscopic cause of this force. Student A says that the force exerted by individual molecules as they bounce off the wall is always perpendicular to the wall. Student B says that the molecules may strike the wall at angles that are not perpendicular. Which student is correct and why?A. Student A . If the molecules hit at nonperpendicular angles, there would be a component of force parallel to the wall exerted on them. The net result would be macroscopic motion of the fluid.B. Student A . The molecules in a liquid are in random motion at the microscopic scale, so they move in every direction. Near the wall the molecules collide with each other in such a way that the components of their motion not parallel to the wall cancel.C. Student B . The molecules in a liquid are in random motion at the microscopic scale. For every atom that hits at an angle to one side of perpendicular, there is likely to be another atom hitting at the same speed at the same angle on the other side of perpendicular. On average the nonperpendicular components cancel.D. Student B . The walls of the container cannot move, so near the walls the parallel component of the motion of the molecules is cancelled by the net force the wall exerts on the liquid.
Answer:
C
Explanation:
Given that a liquid at rest in a fixed container exerts a force perpendicular to the wall of the container. Two students make claims about the microscopic cause of this force. Student A says that the force exerted by individual molecules as they bounce off the wall is always perpendicular to the wall. Student B says that the molecules may strike the wall at angles that are not perpendicular. Which student is correct and why?
The correct answer is option C
Student B . The molecules in a liquid are in random motion at the microscopic scale. For every atom that hits at an angle to one side of perpendicular, there is likely to be another atom hitting at the same speed at the same angle on the other side of perpendicular. On average the nonperpendicular components cancel
A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the different levels of biodiversity for the four ecosystems as shown in the table below.
Genetic Diversity Species Diversity Habitat Diversity
Ecosystem A Low Low Medium
Ecosystem B Medium High Medium
Ecosystem C High Low Low
Ecosystem D Medium Low High
Based on the information above, which ecosystem most likely experienced a recent population bottleneck?
Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.
Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.
A
Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
B
Ecosystem C, because its low habitat diversity indicates an increase in available niches.
Ecosystem C, because its low habitat diversity indicates an increase in available niches.
C
Ecosystem D, because its low species diversity indicates that it also has low species evenness.
Answer:
B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
Explanation:
This is because, in the ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.
Frozen food will thaw more quickly when placed under running water than if it
is immersed in water. Why?
Answer:
google answers, i'm not 100% on how to type my own answer
Explanation:
Thaw food submerged under running water at a temperature of 70˚F (21˚C) or lower. The water flow must be strong enough to wash food particles into the overflow drain. In a microwave oven. You can safely thaw food in a microwave oven if the food will be cooked immediately.
The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.
Answer:
The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.
Inkjet printers can be described as either continuous or drop-on-demand. In a continuous inkjet printer, letters are built up by squirting drops of ink at the paper from a rapidly moving nozzle. You are part of an engineering group working on the design of such a printer. Each ink drop will have a mass of 1.5×10−8g. The drops will leave the nozzle and travel toward the paper at 50 m/s in a horizontal direction, passing through a charging unit that gives each drop a positive charge q by removing some electrons from it. The drops will then pass between parallel deflecting plates, 2.0 cm long, where there is a uniform vertical electric field with magnitude 8.0×104N/C. Your team is working on the design of the charging unit that places the charge on the drops.
(a) If a drop is to be deflected 0.30 mm by the time it reaches the end of the deflection plates, what magnitude of charge must be given to the drop? How many electrons must be removed from the drop to give it this charge?
(b) If the unit that produces the stream of drops is redesigned so that it produces drops with a speed of 25 m/s, what q value is needed to achieve the same 0.30-mm deflection?
Answer:
A) q = 7.03 × 10^(-13) C
n ≈ 4388265 electrons
B) q = 1757.8 × 10^(-16) C
n ≈ 1097253 electrons
Explanation:
We are given;
Mass; m = 1.5 × 10^(−8)g = 1.5 × 10^(-11) kg
Speed; v = 50 m/s
Electric Field; E = 8 × 10⁴ N/C
Distance between plates; s = 2 cm = 0.02 m
A) Now, speed = distance/time
So, time(t) = distance/speed = 0.02/50 = 0.0004 s
From Newton's first law of motion, we know that;
d = ut + ½at²
But u is initial velocity and in this case it's zero.
But we are told that a drop is to be deflected by 0.30 mm. So, d = 0.3 × 10^(-3) m
Thus;
0.3 × 10^(-3) = 0 + ½a(0.0004)²
a = 3750 m/s²
Now, we know that force in motion normally can be expressed as;
F = ma
But in electric field, it's;
F = qE
Thus;
qE = ma
So, charge is; q = ma/E
Plugging in the relevant values;
q = (1.5 × 10^(−11) × 3750)/(8 × 10⁴)
q = 7.03 × 10^(-13) C
Now, number of electrons is given by the formula;
n = q/e
Where e is charge on electron with a value of 1.602 × 10^(-19) C/electron
So; n = (7.03 × 10^(-13))/(1.602 × 10^(-19))
n ≈ 4388265 electrons
B) We are told speed is now 25 m/s.
Thus;
time(t) = distance/speed = 0.02/25 = 0.0008 s
From Newton's first law of motion, we know that;
d = ut + ½at²
But u is initial velocity and in this case it's zero.
d remains 0.3 × 10^(-3) m
Thus;
0.3 × 10^(-3) = 0 + ½a(0.0008)²
a = 937.5 m/s²
Now, we know that force in motion normally can be expressed as;
F = ma
But in electric field, it's;
F = qE
Thus;
qE = ma
So, charge is; q = ma/E
Plugging in the relevant values;
q = (1.5 × 10^(−11) × 937.5)/(8 × 10⁴)
q = 1757.8 × 10^(-16) C
Now, number of electrons is given by the formula;
n = q/e
Where e is charge on electron with a value of 1.602 × 10^(-19) C/electron
So; n = (1757.8 × 10^(-16) )/(1.602 × 10^(-19))
n ≈ 1097253 electrons
A box is initially sliding across a level floor at 10 m/s before being subjected to the forces shown below.
Refer to the above information and diagram. What is the sum of forces for this FBD?
Answer:
200m
Explanation:
Guys, please help, I need this answer urgently,
1. Ameylia conducted an experiment using a bar magnet and some paper clips. She divided the magnet into 5 parts, A, B, C, D and E. She put the magnet into a tray of paper clips. She noticed that thepaperclipsmoved towards the different parts of the magnet. She repeated the experiment thrice and recorded her observation in the table below.
Part A: 1st trial = 10 paper clips, 2nd trial=9 paper clips, 3rd trial =9 paper clips
Part B: 1st trial = 3 paper clips, 2nd trial=4 paper clips, 3rd trial =5 paper clips
Part C: 1st trial = 12 paper clips, 2nd trial=11 paper clips, 3rd trial =12 paper clips
Part D: 1st trial = 4 paper clips, 2nd trial=6 paper clips, 3rd trial =6 paper clips
Part E: 1st trial = 12 paper clips, 2nd trial=11 paper clips, 3rd trial =12 paper clips
a) Ameylia's teacher told her that there is a mistake in the results recorded for one part of the magnet. Identifyfor which part of the magnet, A,B,C,D or E is the results recorded wrongly. Give a reason for your answer.
Answer: Help me answer this question please????
How does your education contribute to comunity development