Answer:
the cats acceleration is 4.25m/s2
52.887 in significant figures
Answer:
There are 5 significant figures in 52.887
5, 2, 8, 8, 7 --> all of these numbers are considered significant.
PLEASE HELP REALLY WOULD APPRECIATE THE HELP;) A positively charged glass rod is bought close to a suspended metal needle. What
can we say about the charge on the needle given that the needle is
a) attracted ?
b) repelled ?
Answer:
Explanation:
attracted
1.what are the types of matter?
2.what are the states of matter?
Answer:
1) Ans= Pure substances and mixtures are the two types of matter.
2)Ans=solid ,liquid and gas are the states of matter
What is it called when a skydiver is no longer accelerating downward?
Explanation:
Once the force of air resistance is as large as the force of gravity, a balance of forces is attained and the skydiver no longer accelerates. The skydiver is said to have reached a terminal velocity.
1. An MR-2 starts from rest and accelerates westward to a speed of 27 m/s in
11.8 seconds.
a) What is its acceleration?
b) What is the displacement it covered?
Answer:
a) 2.28 m/s²
b) 159.86 m
Explanation:
Part A:
u = 0 m/s
v = 27 m/s
t = 11.8 seconds
a = ?
Formula:
v = u + at
=> 27 = 0 + a(11.8)
=> 27 = a(11.8)
=> a(11.8) = 27
=> a = 27/11.8
=> a = 2.28 m/s²
Part B:
s = ?
Formula:
s = (v² - u²)/2a
s = (27² - 0²) /2(2.28)
= 729/4.56
= 159.86 m
intermolecular forces in liquid and solid
the IMF in liquids are weaker due to how far the molecules are apart from each other, whereas the IMF in solids are stronger due to how tightly packed the molecules are together.
a ball is moving with a velocity of 0.5 m/s its velocity is decreasing at the rate of 0.05 m/s² what is its velocity in 5 seconds? how much time will it take from start to stop?what is the distance to travelled by it before stopping?
Answer:
v after 5s = 0.25 m/s, it took 10s to stop, it has traveled 2.5m before stopping
Explanation
We can use the equation of motion with constant acceleration
Given: v0= 0.5 m/s a= -0.05 m/s²
v(5s) = v0 + a×t = 0.25 m/s
Stop => v=0 => v0 + a×t = 0 => t=10s
Distance at t=10s ⇒ x(10) = 0.5×10 + 0.5x(-0.05)x10² = 2.5m
how to determine the volume of a human body
Answer:
Determine the volume of a human body to use the mass and density of water displaced to calculate the volume of the water displaced.
Answer:
According to me the volume of a human body can me determined by means of the displacement method
Explanation:
if you immerse you body in a drum of water of a known volume, the water displaced is equal to your volume
(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where the acceleration due to gravity is 9.82m/s2. What is its new period
I assume this is the motion of the simple pendulum
T = 2π × [tex]\sqrt{\frac{L}{g } }[/tex]
=> [tex]\frac{T1}{T2 }[/tex] = [tex]\sqrt{\frac{g2}{g1} }[/tex]
Given T1= 3s g1= 9.79 g2= 9.82
=> T2 = 3.00459 s
two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both projectile strict the ground at the distance and time interval of both when they are in arir?
Answer:
Yes, if θ = 45°
Explanation:
The scatter plot shows the number of minutes Guya practiced the flute each day in a given week.
How many minutes did Guya practice on Tuesday?
A) 1min
B) 2min
C) 20min
D) 30 min
If the scatter plot shows the number of minutes Guya practiced the flute each day in a given week, then Guya practiced 20 minutes on Tuesday, therefore the correct answer is option C.
What is a scatter plot?A set of dots plotted on a horizontal and vertical axis is known as a scatter plot. Because they may demonstrate the degree of connection, if any, between the values of observed quantities or events, scatter plots are crucial in statistics.
As given in the problem If the scatter plot shows the number of minutes Guya practiced the flute each day in a given week,
The x coordinates is showing the days of practice and the y coordinate is showing the number of minutes he practiced the flute on a given day,
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Question 1 of 10
Rays bend as they pass through a boundary between two media. This is
called:
A. indention.
B. reflection.
C. refraction.
D. diffraction.
A mass of 20kg which moved vertically produced a momentum of 300kg.m/s, how much power was needed to move the mass?
Answer:
Power is 3000 W
Explanation:
Momentum = mass × velocity
[tex]300 = 20 \times v \\ velocity = 15 \: {ms}^{ - 1} [/tex]
For power:
[tex]P = \frac{force \times distance}{time} \\ \\ P = force \times ( \frac{distance}{time} )[/tex]
but distance/time is velocity, so:
[tex]P = force \times velocity[/tex]
but force = mass × acceleration:
[tex]P = (mass \times acceleration) \times velocity \\ P = (20 \times 10) \times 15 \\ P = 3000 \: \: watts[/tex]
[ taken acceleration to be 10 m/s² ]
Electromagnetic waves transport energy.
a. True
b. Fasle
Answer:
a
Explanation:
energy is transferred in electromagnetic waves
Forces is F1(east) and F2 are simultaneously applied to
a 30kg mass. When f2is east , a = 5.0 m/s2 east and
When F2 is west a=10m/s² east - Determine the
Magnitude of f1 and f2
There's a problem with the given information, but I'll get to that later.
Use Newton's second law. When F₂ points east, we have
F₁ + F₂ = (30 kg) (5.0 m/s²) = 150 N
and when F₂ points west, it acts in the opposite direction and
F₁ - F₂ = (30 kg) (10 m/s²) = 300 N
Solve for F₁ and F₂ : we have
(F₁ + F₂) + (F₁ - F₂) = 150 N + 300 N
2F₁ = 450 N
F₁ = 225 N
and
(F₁ + F₂) - (F₁ - F₂) = 150 N - 300 N
2F₂ = -150 N
F₂ = -75 N
But F₁ and F₂ are magnitudes, so they must be positive! Also, it doesn't make sense that when the forces both point east, the mass accelerates less than it does when the forces work against each other. Probably one of the given accelerations are supposed to point west instead of east.
The resistance of a wire depends on
Select one:
O a. the cross-sectional area of the wire.
b. All of the answers are correct.
O c. the temperature of the wire.
O d. the length of the wire.
Answer:
b
Explanation:
because all are factors that determine the resistivity of a material
Question 4 A car of mass 820 kg has a maximum power of 30 kW and moves against a constant resistance of motion to 910 N. Calculate the maximum speed of the car in the following situation; b)Up an incline (hill) of 8.75° to the horizontal?
Answer:
P = W / t = m g s / t = m g v where work by auto = m g s
30 kw = 30000 watts = 30000 J / s
Work wasted = F v as shown above relating work and power
Work done against incline = m g s sin 8.75 and power against incline
= m g v sin 8.75 = 1222 v Joules / sec
power in moving auto = power available - power lost to friction
power in moving auto = 30000 - resistance = 30000 - 910 v
1222 v = 30000 - 910 v
v = 30000 / 2132 = 14 m/s
Note: constant resistance to motion must mean P = W / t = F s / t = F v
Maximum speed will be v = 14.07 m/s
What is power ?Power is defined time rate of doing work or delivering energy.
Work done = Force * displacement
Power = work done / time
= (Force * displacement ) / time
since , displacement / time = velocity
Power = force * (displacement / time ) = force * velocity
Power = mass * acceleration * velocity ( as force = mass * acceleration)
since , car is travelling up in an incline of 8.75° to the horizontal
hence , it will have two components of velocity
vertical component = v sin (theta ) = v sin(8.75°)
horizontal component = v cos (theta)= v cos (8.75°)
Power = m* a * v sin (theta )
= 820 * 9.8 * v *sin (8.75°) ( a = g = 9.8 m[tex]/s^{2}[/tex])
= 1221.472 v
Power lost due to resistance in motion = 910 * velocity = 910 v
Power = Total power - power lost due to resistance in motion
= 30 * [tex]10^{3}[/tex] - 910 v
30 * [tex]10^{3}[/tex] - 910 v = 1221.472 v
v = 14.07 m/s
Maximum speed will be v = 14.07 m/s
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the
four particles form a square of edge
length a 5.00 cm and have charges
q1 10.0 nC, q2 20.0 nC, q3
20.0 nC, and q4 10.0 nC. In unitvector notation, what net electric field
do the particles produce at the square’s
center
Answer:
500 in unitivector notion
What is the correct clases for this drugs
Compazine
heelp me please
Explanation:
Compazine belongs to class of drugs called Antiemetic Agents, Antipsychotics, Phenothiazine.
I need someone smart!
why is the multiverse considered a theory if it has no observational or experimental evidence?
shouldn't it be considered a plausible hypothesis instead, sense it has no evidence but is lickely the case?
Answer:
It is a theory
Explanation:
There’s no form or proof or anything even tho it is a hypothesis it’s common and has no evidence due towards it
state the law of conversation of momentum
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.50 m above the ground and measure that it hits the ground 0.809 s later.
Assuming that the planet has the same density as that of earth (5500 kg/m3), what is the radius of the planet?
Explanation:
By the formula,
[tex]s=ut+\frac12at^2[/tex]
[tex]-3.5=0+\frac12a(0.809)^2[/tex]
[tex]a=-10.659 ms^{-2}[/tex]
where a is the acceleration of objects by gravity.
We also know that by the Law of Gravitation,
[tex]F=-\frac{GMm}{r^2}=ma[/tex]
[tex]a=-\frac{GM}{r^2}[/tex]
The mass of the planet is given by
[tex]M=\rho V=\rho(\frac 43\pi r^3)[/tex]
So
[tex]a=-\frac{G(\rho\frac 43\pi R^3)}{r^2}= - \frac{(6.67 \times 10^{-11})(5500)(\frac43)\pi R^3}{(R+3.5)^2} = -10.659[/tex]
Since R>>3.5, so we approximate
[tex](R+3.5)^2\approx R^2[/tex]
Solving the last equation,
[tex]R=6936.483 km[/tex]
Suppose 2kg of glycerine have a temperature of 30°C. Heat is supplied to a steady rate of 100W. The temperature after 35 minutes is 75°C.
Calculate the specific heat capacity of glycerine.
Answer:
210000.................
The specific heat capacity of glycerine is 2333.3 J/(kg·K).
We can use the formula for heat (Q) absorbed by a substance:
Q = mcΔT
Where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
We know the mass of glycerine (m = 2 kg), the time for which heat is supplied (t = 35 minutes = 2100 seconds), the rate of heat supply (P = 100 W), the initial temperature (T1 = 30°C = 303 K), and the final temperature (T2 = 75°C = 348 K).
First, we need to calculate the total heat absorbed by the glycerine:
Q = Pt
Q = 100 W × 2100 s
Q = 210000 J
Next, we can calculate the change in temperature:
ΔT = T2 - T1
ΔT = 348 K - 303 K
ΔT = 45 K
Finally, we can calculate the specific heat capacity of glycerine:
c = Q/(mΔT)
c = 210000 J/(2 kg × 45 K)
c = 2333.3 J/(kg·K)
Therefore, the specific heat capacity (c) = 2333.3 J/(kg·K).
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Question 3 of 10
According to the law of conservation of energy, which statement must be
true?
A. A system cannot take in additional energy.
B. Potential energy can only change to kinetic energy.
O C. There is only one form of energy.
D. The total energy of a system can decrease only if energy leaves
the system
Answer:
b
Explanation:
the law says that energy can not be created or destroy but can be transform from one energy to another.
What does a food chain show?"
why plant and animal matter break down
O where resources are found in a habitat
O how producers use sunlight to make food energy
O how living things depend on each other for food
Answer:
All
Explanation:
Answer:
3rd = how living things depend on each other for food
As many as _____ neurons throughout the body are involved in the control of behavior
about 1 trillion neurons
What is an electricity?
Explanation:
Electricity is the flow of electrical power or charge.
Write the following as full (decimal) numbers with standard units metric (SI) units:
(For example, 80.2 kA = 80,200 A)
651.9 mm
71 V
910 mg
30.0 ps
22.5 fm
2.00 gigavolts
Answer:
Explanation:
651.9 mm = 0.6519 m
71 V = 71 V
910 mg = 0.000910 kg
30.0 ps = 0.000 000 000 030 0 s
22.5 fm = 0.000 000 000 000 022 5 m
2.00 gigavolts = 2 000 000 000 V
.
An object accelerates from 10 m/s to 30 m/s in 4.0 seconds.
The accelerating force is 150 N.
What is the mass of the object?
Answer:
m=30kg
Explanation:
m=[tex]\frac{F}{a}[/tex] ............(1)
F=150N
a=?
a=[tex]\frac{vf-vi}{t}[/tex]
a=[tex]\frac{30-10}{4}[/tex]
a=[tex]\frac{20}{4}[/tex]
a=5ms^-2
Putting the value of "F" and "a" in eq (1),
m=[tex]\frac{150}{5}[/tex]
m=30kgin the same viewing window. Compare the magnitudes of f (x) and g(x) when x is close to 0. Use the comparison to write a short paragraph explaining why
Answer:
Due to inertia of restttttttrestrestrestrest