A car on a freeway ramp starts at a velocity of 12.0 m/s. If its average acceleration over 8 s is 3.20 m/s2, what is the velocity at the end of that interval?
A. 13.6 m/s
B. 99.2 m/s
C.25.6 m/s
D. 37.6 m/s

The net electric force on the electron placed at x = 0.200 m is 2.67 x 10^-14 N to the right and The net electric force on the electron is again the vector sum of these two forces is 4.32x 10^-14N

1. F1 = k * (q1*qe) / r1^2

F1 = (9.0 x 10^9) * (-4.00 x 10^-9) * (-1.60 x 10^-19) / (0.200)^2

= 7.20 x 10^-14 N (to the right)

F2 = k * (q2*qe) / r2^2

F2 = (9.0 x 10^9) * (-6.50 x 10^-9) * (-1.60 x 10^-19) / (0.600)^2

= 4.53 x 10^-14 N (to the left)

The net electric force on the electron is the vector sum of these two forces:

Fnet = F1 + F2

= (7.20 x 10^-14) + (-4.53 x 10^-14)

= 2.67 x 10^-14 N (to the right)

2. F1 = 7.20 x 10^-14 N (to the right).

The electric force exerted on the electron by the -6.50 nC charge at x = 0.800 m is now given by:

F2 = k * (q2*qe) / r2^2

where r2 = 1.20 - 0.800 = 0.400 m.

F2 = (9.0 x 10^9) * (-6.50 x 10^-9) * (-1.60 x 10^-19) / (0.400)^2

= 2.88 x 10^-14 N (to the left)

The net electric force on the electron is again the vector sum of these two forces:

Fnet = F1 + F2

= (7.20 x 10^-14)+ (2.88 x 10^-14 N) = 4.32x 10^-14N

The electric force is a fundamental concept in physics that describes the attractive or repulsive interaction between electrically charged particles. This force is a fundamental force of nature, meaning that it cannot be explained in terms of other forces.

The electric force is directly proportional to the magnitude of the charges on the particles and inversely proportional to the square of the distance between them. This means that as the charges on the particles increase, the electric force between them also increases. However, as the distance between the particles increases, the electric force decreases.

The electric force plays a crucial role in a wide range of phenomena in physics, including the behavior of electrically charged particles in electric fields, the operation of electric motors and generators, and the behavior of electrically charged particles in the human body.

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Answer:

Explanation:

Greetings!!!

Mass(m)= 1900kg

Acceleration (a)= 6.0m/s²

Force (F)= ?

Firstly, recall Newton's second law.

Substitute known variables into the equation

Solve for Force

If you have any questions tag me on comments

Hope it helps!!!

Answer:

V = 2 π R / T        speed V where T is period

T = 2 π R / V     = 2 π * .2 m / 1.5E5 m/s = 8.38E-6 sec

Period = 8.36 * 10-6 sec

Answer:

its because the modern model of our solar system is much more updated to the Ptolemy's model

A charge of 100 elementary charges is equivalent to (2) 1. 60 times 10^-17 C

A single electron or proton's electric charge is referred to as an elementary charge. It is a fundamental physical constant with a magnitude of approximately 1.602 x 10-19 coulombs (C). Electric charge is quantized using the elementary charge, which is thought to be the smallest amount of electric charge that can exist in nature. The elementary charge is the same for both particles because protons and electrons have the same and opposite charges. The behaviour of atoms and molecules is greatly influenced by their elementary charge, which also determines their electronic structure and affects how they interact with other charged particles in their environment.

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The weight of the crate moved vertically is 40.9 Newton.

To solve this problem, we can use the formula for work done, which is:

Work done = force × displacement

Where force is the weight of the crate, distance is the vertical distance moved.

We can rearrange the formula to solve for the weight of the crate:

Force = work / displacement

Given that;

Plugging in the values, we get:

Force = work / displacement

Force = 450 J / (11 m )

Force = 40.9 N

Therefore, the weight of the crate is 40.9 N.

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The pith balls are having same charge and that is why they are held apart by the force of repulsion. When they both touched by the experimenter's finger they both gets attracted to the finger and comes in contact as in B.

Electrostatic force between two charges are arise when the charged bodies comes in contact. There are both force of attraction and repulsion. The electrostatic force of attraction results from the two unlike charges and the force of repulsion arise between two like charges.

Here, the pith balls are charged alike, hence they will get repelled. Ig they are negatively charged, the electrons will flow from them to the other body in touch.

When the experimenter touch his finger on the charged ball, the finger gets polarized and attracted to the ball , they gets in contact as in figure B.

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Answer: its D yea

Explanation:

If the net external torque acting on the system is zero, the total angular momentum of a system remains constant, i.e. it is conserved

50J work will do to lift it the same distance

How much energy is wasted during a fall?

When an object is falling freely, its velocity rises because of the acceleration caused by gravity. In the instance of a body that is falling freely, the kinetic energy thus rises while the potential energy falls as the height of the object decreases.

When an object is descending at its terminal velocity, the force of gravity and air resistance are equal, and the object no longer accelerates. The amount of labor done is equal to the sum of the object's displacement and the gravitational force. The modification of the object's potential energy brought on by gravity can also be used to calculate it.

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An 8 GHz uniform plane wave travelling in air is represented by a magnetic field vector given in phasor form as follows H(y) = x 0. 015e^-j beta y + z 0. 03e^j(pi - beta y) mA - m^-1 . The total time-averaged power transferred to each eardrum in 1.0 second is 3.972x10^-7 J.

The magnetic field vector for the uniform plane wave can be represented as:

H(y) = x0.015e^(-jβy) + z0.03e^(j(π-βy)) mA/m

where β is the propagation constant, and has units of rad/m.

The wave frequency can be determined from the wavelength λ, which can be calculated using the propagation constant:

λ = 2π/β

The frequency can then be determined using the relation:

f = c/λ

where c is the speed of light in air, which is approximately 3x10^8 m/s.

To find β, we can equate the phase of the x-component of H(y) to the phase of the z-component of H(y):

-jβy = j(π - βy)

Solving for β, we get:

β = π/(2y)

Substituting y = 1/(2β), we get:

β = πy

Substituting this value of β in the expression for H(y), we get:

H(y) = x0.015e^(-jπy) + z0.03e^(jπy) mA/m

To find the electric field vector, we can use the relation:

E(y) = Z0H(y)

where Z0 is the impedance of free space, which has a value of approximately 377 Ω.

Substituting the values of H(y) and Z0, we get:

E(y) = x5.655e^(-jπy) + z11.31e^(jπy) mV/m

The time-averaged power density carried by the wave can be calculated using the relation:

P = 1/2Re(E(y) x H*(y))

where H*(y) is the complex conjugate of H(y).

Substituting the values of E(y) and H(y), we get:

P = 1/2(0.015)(5.655)(cos(πy) + jsin(πy)) + 1/2(0.03)(11.31)(cos(πy) - jsin(πy))

Simplifying, we get:

P = 0.236cos(πy) W/m^2

To find the total time-averaged power transferred to a surface of area A, we can integrate P over the surface:

P_total = ∫∫ P dA

Assuming the surface is perpendicular to the direction of propagation, and has a diameter of 8.4 mm, we get:

A = π(0.0042)^2 = 5.538x10^-5 m^2

Substituting the value of A and integrating P over the surface, we get:

P_total = 0.236∫∫ cos(πy) dA

P_total = 0.236cos(πy)∫∫ dA

P_total = 0.236cos(πy)(5.538x10^-5)

Substituting the value of y = 30 m, we get:

P_total = 0.236cos(πx30)(5.538x10^-5) = 3.972x10^-7 W

Therefore, the total time-averaged power transferred to each eardrum in 1.0 second is 3.972x10^-7 J.

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The biggest celestial event of the decade will likely take place on August 21 when a total solar eclipse crosses the whole continental United States from coast to coast.

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Governments assist in enhancing the infrastructure necessary for companies to flourish and helps business provide the goods and services that people need and want.

What is economics?

Economics is the study of how limited resources are used to create outputs, such as commodities and services, that are then distributed among individuals. Resources serve as the resources for creating outputs. Products and services are created by combining resources. The necessary raw ingredients are provided by land and natural resources. Raw materials are turned into finished products and services by labor.

Businesses perform better when they can effectively transport raw materials to factories and deliver finished goods to plants and markets. Governments assist in enhancing the infrastructure necessary for companies to flourish. Roads, bridges, rail lines, airports, seaports, energy transmission lines, and telecommunications networks are all included in this.

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The maximum speed at which the racket can move is limited by the physical ability of the player.

The speed at which a ball leaves a racket is determined by several factors, including the speed of the racket at impact, the angle of the racket face, and the properties of the ball itself.

The maximum speed at which the racket can move is limited by the physical ability of the player. A player can only swing the racket so fast before they reach their physical limits. Additionally, the angle at which the racket strikes the ball affects the ball's speed. If the racket face is angled too steeply or too shallowly, it can decrease the speed of the ball.

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The swimmer will cover a distance of 818.4 meters in 372 seconds, swimming at speed of 2.2 m/s.

The magnitude of change of its position over time or the magnitude of change of its position per unit of time is called speed.

We use this formula: distance = speed x time

speed is the swimmer's speed, and time is the time she swims for.

Substituting the given values, we get: distance = 2.2 m/s x 372 s

Calculating the product, we obtain:

distance = 818.4 meters

Therefore, the swimmer will cover a distance of 818.4 meters in 372 seconds, swimming at a speed of 2.2 m/s.

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The force required to lift the whale shark is given as 25000 N, and its acceleration is 1.25 m/s^2. We can use Newton's second law of motion, which states that the force (F) applied on an object is equal to the product of its mass (m) and acceleration (a), i.e. F = ma.

Rearranging the equation to solve for the mass, we get:

m = F/a

Substituting the given values, we get:

m = 25000 N / 1.25 m/s^2

m = 20000 kg

Therefore, the mass of the whale shark is approximately 20,000 kg.

The speed of the fluid near the right-hand end of the tube is approximately 10.06 m/s.

Bernoulli's equation is a fundamental principle in fluid mechanics that relates the pressure, velocity, and height of a fluid in a flow. It states that for an incompressible fluid flowing in a steady state through a pipe of varying cross-sectional area, the total energy of the fluid (consisting of pressure energy, kinetic energy, and potential energy) remains constant along any streamline of the flow. Mathematically, the equation is:

P + (1/2)ρv² + ρgh = constant

To find the speed of the fluid near the right-hand end of the tube, we can use the Bernoulli's equation, which relates the pressure and velocity of a fluid in a flow:

P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²

where P1 and v1 are the pressure and velocity of the fluid at the left hand end of the tube (where the pipe is wider), and P2 and v2 are the pressure and velocity at the right-hand end (where the pipe is narrower).

We can redo this equation to solve for v₂:

v₂ = sqrt(2*(P₁-P₂)/ρ + v₁²)

where sqrt denotes the square root.

Using the given values:

A₂/A₁ = 0.46

dP = 27.6 Pa

ρ = 2.93 kg/m³

We can find the pressure at the left hand end using the fact that the pressure is the same at the same height, and the fluid is incompressible, so its density is constant:

P₁ = P₂ + dP = P₂ + 27.6 Pa

The area ratio gives us:

A₂ = 0.46*A₁

Now we need to find v₁. We can use the continuity equation, which states that the mass flow rate (ρAv) is constant in an incompressible fluid:

ρ₁A₁v₁ = ρ₂A₂v₂

where ρ1 is the density of the fluid at the left hand end, which is the same as ρ₂, and A₁ and A₂ are the pipe's cross-sectional areas at the left and right ends, respectively.

Substituting A₂ = 0.46 × A₁ and simplifying, we get:

v₁ = (0.46)² × v₂

Substituting this into the Bernoulli's equation, we get:

P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²

Substituting P₁ = P₂ + 27.6 Pa and v₁ = (0.46)² × v₂, and solving for v₂, we get:

v₂ = √((227.6)/(0.46^2ρ) + (0.46)⁴ × v₂²/ρ)

Simplifying this equation, we get:

v₂= √((227.6)/(0.46^2ρ × (1-0.46⁴)))

Substituting the given values, we get:

v₂ = √((227.6)/(0.46²²°⁹³ × (1-0.46⁴))) = 10.06m/s

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The heat needed for the air to change from 27°C to 400°C is 291 J.

First, calculate the final volume of the air using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Assuming that the pressure remains constant, rearrange the ideal gas law to solve for the final volume:

V₂ = (nRT₂) / P

where T₂ is the final temperature.

Calculate the initial number of moles of air using the ideal gas law with the original conditions:

n = (PV) / RT₁

where T₁ is the initial temperature.

Substituting the given values:

n = (3.0 atm x 5860 cm3) / (0.0821 L atm/mol K x 300 K)

n = 0.72 mol

Now calculate the final volume:

V₂ = (0.72 mol x 0.0821 L atm/mol K x 673 K) / (3.0 atm)

V₂ = 13.47 L

The change in volume is therefore:

ΔV = V₂ - V₁

ΔV = 13.47 L - 5.86 L

ΔV = 7.61 L

To calculate the heat required, use the equation:

q = nCvΔT

where ΔT is the change in temperature.

Substituting the given values:

q = (0.72 mol x 0.177 cal/g °C x (400°C - 27°C))

q = 69.7 cal

Finally, convert this to joules:

q = 69.7 cal x 4.184 J/cal

q = 291 J

Therefore, the amount of heat that must be added to the air is 291 J.

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The complete question is:

For air, Cv= 0.177 cal/g.°C. Suppose that air is confined to a cylinder by a movable piston under a constant pressure of 3.0 atm. How much heat must be added to the air if its temperature is to be changed from 27°C to 400°C? The mass of air in the cylinder is 20 g, and its original volume is 5860 cm.

Answer:

a yellow book

Explanation:

red has the longest wavelength so most wavelength to least wavelength goes in the order- red, orange, yellow, green, blue, indigo, violet

yellow has the longest wavelength in the gvn options thus its the answer

Heat naturally flows from an object that has a high temperature to an object that has a low temperature. Heat can be made to flow in the reverse direction if temperature  is done. A machine can never have an efficiency of fuel . This means that heat energy can never be fully converted into mechanical  energy.

What is temperature ?

The movement of these particles likewise increases with rising temperature. A thermometer or a calorimeter are used to measure temperature.

What is kinetic energy ?

When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and acquires kinetic energy.

Therefore,Heat naturally flows from an object that has a high temperature to an object that has a low temperature. Heat can be made to flow in the reverse direction if temperature  is done. A machine can never have an efficiency of fuel . This means that heat energy can never be fully converted into mechanical  energy.

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Answer:

Explanation:

Before the collision, the lorry has a momentum of:

p1 = m1v1 = 8000 kg * 20 m/s = 160000 kgm/s

where m1 is the mass of the lorry and v1 is its velocity.

The car is initially at rest, so its momentum is:

p2 = m2*v2 = 0

where m2 is the mass of the car and v2 is its velocity.

After the collision, the two vehicles move together with a common velocity v. The total momentum of the system after the collision is:

p = (m1 + m2)*v

where m1 + m2 is the total mass of the system.

By the law of conservation of momentum, the total momentum before and after the collision is the same. So we have:

p1 + p2 = p

Substituting the values we have:

160000 kg*m/s + 0 = (8000 kg + 1000 kg)*v

Simplifying:

v = (160000 kg*m/s) / (9000 kg)

v = 17.78 m/s

Therefore, the velocity of the lorry and car together after the collision is 17.78 m/s.

Answer:

Q. 1 - your mass will vary from planet to planet meaning it can either decrease or increase depending on the gravitational pull of the planet

Q. 2 - jupiter since it has the highest gravitational pull

Q. 3 - moon since its gravitational pull is the least but since the moon isn't a planet it would be mercury

Q. 4 - uranus has the closest gravitational pull than of earth

Q. 5 - here's my version you can write your own if u want to

Ever since I moved to saturn I've always felt bit more heavier than before it felt like my weight had significantly increased I felt a few more kgs heavier I couldn't do much since I could only stay there for a day

That's about it

Force is the influence that causes the stir of an object with mass to change speed, i.e. accelerate.

The equations τ = r Fsinθ show that the torque can be written in three ways. It can be the product of the force, the switch arm and the sine of the angle between them.

Can be the product of the force and the element of the switch arm vertical to the force. It can also be written as the product of the switch arm and the force vertical to the switch arm.

The computation shows that the three dyads are equal. Expressions include

80N)(5.0 m)( sin 37 ∘)).

48N)(5.0 m).

80N)(3.0 m).

Force is an external factor that can change a body's state of rest or motion. It has size and direction. The direction in which the force is applied is known as the force direction, and the force impact is where the force is applied.

Question

Consider the force F = 80N applied to the ray as shown in the figure below. The length of the ray is ℓ = 5.0 m and θ = 37 ∘, so x = 3.0 m and y = 4.0m.

Which of the following statements gives the correct moment generated by the force F → about the point P?

Which of the following expressions gives the correct torque produced by a force about a point?

80 N)(5.0 m).

48 N)(5.0 m)( sin 37 ∘).

80 N.

80 N)(5.0 m)( sin 37 ∘)).

48 N)(5.0 m).

80 N)(4.0 m).

80 N)(3.0 m).

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The rate of acceleration if force is doubled is same, if the objects mass is doubled it is halved, if both the object mass and force are doubled the acceleration will be same , d- acceleration will be quadrupled

Newton's second law of motion states that force is equal to mass multiplied by acceleration: F = m * a, where F is the applied force, m is the object's mass, and an is the acceleration produced.

a- When the force is doubled, the acceleration doubles as well. Using the formula, we get:

F' = 2F

a' = F' / m = (2F) / m = 2F / (2m) = F / m = a

B- If the mass is doubled, the acceleration will be halved. Using the equation, we get:

m' = 2m

a' = F / m' = F / (2m) = a / 2

C- If both the force and the mass are doubled, the acceleration will remain the same. Using the equation, we get:

F' = 2F

m' = 2m

a' = F' / m' = (2F) / (2m) = F / m = a

D- If the force is doubled and the mass is halved, the acceleration will be quadrupled. Using the equation, we get:

F' = 2F

m' = m / 2

a' = F' / m' = (2F) / (m/2) = 4F / m = 4a

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The complete question is:

When a constant force is applied to an object, it accelerates at 6.0 m/s2. What will be the rate of acceleration if

the force doubled?

the object's mass doubled?

Both the force and the mass of the object are doubled?

The force is doubled, but the object's mass is cut in half?

Answer:

the answer is decreases,decreases

Answer:

We can use the formula for the transformer voltage ratio, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage:

Np/Ns = Vp/Vs

where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.

We know that Vp = 220 V and Vs = 140 V, and we are trying to find Ns. We also know that Np = 30, since that is the number of turns in the primary coil. Substituting these values into the formula, we get:

30/Ns = 220/140

Simplifying the right side of the equation, we get:

30/Ns = 11/7

Cross-multiplying, we get:

11Ns = 210

Dividing both sides by 11, we get:

Ns = 19

Therefore, the answer is b.) 19.

The refractive index of the liquid, given that the depth is 4 cm and the coin appears to be 3. 5 cm is 1.2

Refractive index is related to real depth and apparent depth according to the following formula:

Refractive index = Real depth / Apparent depth

With the above formula, we can obtain the refractive index as illustrated below:

Refractive index = Real depth / Apparent depth

Refractive index = 4.2/ 3.5

Refractive index = 1.2

Thus, the refractive index is 1.2

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An atom is said to be electrically neutral when the number of protons and the number of electrons is equal.

Protons are positively charged particles and electrons are negatively charged particles. If atom losses or gains one more electron then it is said to become an ion. Atoms may gain or lose electrons to increase their stability. A neutral atom has no charge. The positive and negative charges cancel out each out and create a balance. Basically for an atom to be electrically neutral it must have exactly one electron for every proton. Protons are present in the nucleus of an atom and electrons revolve around the center of the nucleus.

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