A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupants of the car appear to weigh 20% more than their normal weight (or their normal weight times 1.2)?

The average speed is r=50 mph

Teenagers, young adults, and others use the stimulant medication known as "speed" to feel more focused and alert, and occasionally to get euphoric. Several types of speed are also used by some people to suppress their appetite. Different speed types include: Amphetamines (used to treat ADHD, narcolepsy, and depression)

In essence, an object's speed indicates how quickly it is moving. Its velocity reveals how quickly it is moving in a specific direction. In your daily life, you utilize speed measures, but in physics, velocity measurements are more frequently used.

distance=rate*time

total distance=rate*total time

to Grandmother's...

50=34*t

50/34=t

t=25/17 hours for the first 50 miles

50=66*t

50/66=t

t=25/33 hours for the second 50 miles

total distance=50+50=100 miles

total time=25/17+25/33

total time=(825/561)+(425/561)=1250/561 hours

total distance=rate*total time

100=r*(1250/561)

r=(100)(561/1250)

r=56,100/1250

r=5610/125

r=1122/25

r=44.88 mph is the average speed (rounded it is 44.9 mph)

Note: If you are familiar with the simplified form of the harmonic mean you can solve the problem that way. If not, that's okay. You can look it up if you like.

(2*34*66)/(34+66)=4488/100=44.88 again

from Grandmother's house...

because the times are the same you simply add the 2 rates and divide by 2

(34+66)/2=100/2=50 mph is the average speed

d=r*t

100=34*t+66*t (the times are the same, t)

100=100*t

t=1 hour traveling at 34 mph and 1 hour traveling at 66 mph for a total of 2 hours traveling

d=r*t

100=r*2

r=100/2

r=50 mph is the average speed

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Explanation:

Given parameters:

Mass of forklift  = 750kg

Height of lift  = 18m

Time taken  = 28s

Unknown:

Work done = ?

Power = ?

Solution;

 The work done by the forklift is given as:

  Work done = mass x acceleration due to gravity x height

   Work done  = 750 x 9.8 x 18  = 132300J

Power is the rate at which work is done;

      Power  = [tex]\frac{work done }{time}[/tex]  

 Insert the parameters and solve;

    Power  = [tex]\frac{132300}{28}[/tex]  = 4725W

Answer:

When something is heated, its atoms vibrate. If one end of a metal bar is heated, the atoms at that end vibrate more than the atoms at the cold end. The vibration spreads along the bar from atom to atom. ... Metals are good conductors of heat.

Explanation:

Explanation:

If acceleration points in the same direction as the velocity, the object will be speeding up. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

The acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.

It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.

As we know,

The acceleration can be found using the formula:

a = Δv/t

Here a is the acceleration

Δv is the change in linear velocity

t is the time

Δv = 29 - 33

Δv = -4 m/s

t = 10 seconds

a = -4/10

a = -0.4 m/s²

Thus, the acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.

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The back end of the rod moved [tex]1.90\ \mathrm{mm}$[/tex] in this time interval.

Given:

Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]

Steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]

Length of the rod, L = 80 cm = 0.800m

The speed of the wave in the rod is

[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]

Hence the time taken by the wave to travel the end of the rod is,

[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]

The velocity of the rod is [tex]$v_r = 12.0\ \mathrm{m/s}$[/tex]

The other end will keep moving after the front end hits the wall until the wave reaches the other end, given the period determined by the above problem.

As a result, before the wave reaches the end of the rod, it has traveled a distance of

[tex]$\Delta L = v_r t = (12.0\ \mathrm{m/s}) (1.58\times\ \mathrm{s}) = 1.90\times 10^{-3}\ \mathrm{m} = 1.90\ \mathrm{mm}$[/tex]

Hence, the [tex]1.90\ \mathrm{mm}$[/tex] at the back end of the rod moved in this time interval.

Young's Modulus is a measurement of the mechanical characteristics of linear elastic solids like rods, wires, and other similar objects. It is also known as the Elastic Modulus or Tensile Modulus. Young's modulus is the most often used measurement of a material's elastic properties; other measurements include bulk modulus and shear modulus. This is so that it can inform us about a material's tensile elasticity (ability to deform along an axis).

The relationship between stress (force per unit area) and strain is described by Young's modulus (proportional deformation in an object). Thomas Young, a British scientist, is honored with the name of the Young's modulus. When a certain load is applied to a solid object, it deforms.

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According to the question as you walk to the grocery store you walk 800m north, 600m east, and 200m south at a speed of 1m/s. Then your velocity will be ( V = 0.5m/sec )

Velocity is the directional pace of an object in movement as an indication of its price of alternate in function as located from a specific body of reference and as measured by a particular widespread of time.

To find the velocity follow the following steps:

Displacement of 800m north, 600m east, and 200m south from the Cartesian coordination is given as 600[tex]\sqrt{2}[/tex]

Velocity = displacement / time

Therefore time = distance / speed

Time = 800 + 600 + 200 / 1

Time = 1600s

Therefore velocity = 600[tex]\sqrt{2}[/tex] / 1600

Velocity = 0.5m/sec

A Cartesian coordinate gadget in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates, which are the signed distances to the factor from constant perpendicular oriented strains, measured in the equal unit of duration.

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Answer:

43.3J

Explanation:

Given parameters:

Force  = 10N

Distance  = 5m

Angle  = 30°

Unknown:

Work done  = ?

Solution:

Work done is the force applied to move a body through a particular distance;

 Work done  = Force x distance cos Ф

Now insert the parameters and solve;

     Work done  = 10  x 5 cos 30 = 43.3J

Answer: A room lined with soft materials that absorb sound.

Explanation:

Just did it :))

The equation of motion of the standing wave, y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2), indicates that it is still true that the nodes are one half the wavelength apart

Therefore;

The equation describing the standing wave formed by the two waves is y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2)

A standing wave is formed when two waves that have equal amplitude and frequency and moving in opposite directions, are combined.

A standing wave can be formed by a wave and its reflection, resulting in a wave where there is no propagation of particles beyond the vibration region.

The fundamental frequency of a standing wave consists of two nodes and an antinode.

The wavelength is the distance between two peaks of one wave, such that two nodes are formed within the span of a wavelength, which makes the distance between nodes being half the wavelength of the wave.

Therefore;

It is still true that the nodes are one half the wavelength apart.

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Answer:

The force = F =  -40000 N

Explanation:

We know that,

Calculating the acceleration

using the formula

a = (v₂ - v₁) / t

   = 0 - 20 / 0.5

  = -20 / 0.5

   = -40 ms⁻²

Thus, acceleration (deceleration) = a = -40 ms⁻²    

Note: negative sign gives us an idea the car is slowing down after a collision with the barrier, thus acceleration and velocity are in opposite direction.

We know that

F = ma

   = 1000 × -40

   = -40000 N

Thus, the force = F = -40000 N

Answer:2.5 m/s2

Explanation:

Acceleration =v2-v1 ÷ t2-t1 convert 90 km/h to m/s = 90×5/18 = 25 m/s , 25÷10 = 2.5

Answer:

momentum

Explanation:

The net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.

The given problem is based on the concept of net impulse. The magnitude of force acting on any object for very short interval of time is known as impulse. In the given problem, the transfer of impulse can be explained by the impulse - momentum theorem.

[tex]F \times t = \Delta P\\\\I= \Delta P[/tex]

Here, I is the impulse.

Thus, we can conclude that the net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.

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Answer:

0.25 m/s

Explanation:

Acceleration cannot be negative.

Answer:

Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry

Explanation:

Answer:

Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry

Explanation:

The force on the bottom of the beaker is 8.31 N.

To calculate the force on the bottom of the beaker we are using the formula,

F = PA

Here we are given,

A = area of the beaker.

To calculate the force we have to calculate the pressure P first.

To calculate the pressure P we are using the formula,

P= ρgh

ρ=  density of water.

g= the acceleration due to gravity.

h=the height of the water.

Now we put the values in the formula, we get,

P= ρgh

Or, P= (1000)×(9.8)×(0.30)

Or, P= 2940 Pa.

From the above calculation we can say that the pressure P= 2940 Pa.

Now we put the values in the force formula,

F=PA

Or, F=  2940×[tex]\pi r^{2}[/tex]

Or, F = 2940×π×(0.03)²

Or, F= 8.31N

From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.

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The acceleration of the puck is 43.75 m/s².

The velocity of an object or particle in uniform motion is defined as the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.

The player's puck accelerates from a velocity of 5 m/s to 30 m/s in the same direction.

The player's puck covers a distance of 10 m during that process.

Therefore,

The initial velocity of the puck is u = 5 m/s

The final velocity of the puck is v = 30 m/s

The distance covered during the period is s = 10 m

Using the equation of motion,

v² - u² = 2as

(30)² - (5)² = 2 × a × 10

900 - 25 = 20 × a

875 = 20 × a

a = 875/20

a = 43.75 m/s²

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Given that,

Mass of a frog, m = 0.5 kg

The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².

To find,

The magnitude of the net force exerted on the frog as it leaps.

Solution,

Let the net force exerted on the frog is given by the formula as follows :

F = ma

Putting the values of m and a to find F as follows :

F = 0.5 kg × 5 m/s²

F = 2.5 N

So, the magnitude of net force is 2.5 N.

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.

Given the data in the question;

Force Exerted; [tex]F = ?[/tex]

To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:

[tex]F = m * a[/tex]

Where m is mass and a is acceleration

We substitute our given values into the equation

[tex]F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N[/tex]

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.  

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Answer:

3614

Explanation:

Answer:

The distance is now 4d

Explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

The acceleration can be calculated by solving for a:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Once we know the acceleration, we can calculate the distance traveled by the block as follows:

[tex]\displaystyle d = vo.t+\frac{at^2}{2}[/tex]

If the block starts from rest, vo=0:

[tex]\displaystyle d = \frac{at^2}{2}[/tex]

Substituting the value of the acceleration:

[tex]\displaystyle d = \frac{\frac{F}{m}t^2}{2}[/tex]

Simplifying:

[tex]\displaystyle d = \frac{Ft^2}{2m}[/tex]

When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:

[tex]\displaystyle a'=\frac{4F}{m}[/tex]

And the distance is now:

[tex]\displaystyle d' = \frac{4Ft^2}{2m}[/tex]

Dividing d'/d:

[tex]\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}[/tex]

Simplifying:

[tex]\displaystyle \frac{d' }{d}=4[/tex]

Thus:

d' = 4d

The distance is now 4d

The conductor after disconnected from the ground is positively charged after you remove the rubber rod.

Electrostatic induction is the change in a material's electric charge under the influence of another nearby object that has electric charge. For Electrostatic induction to occur a charged particle is held close (without touching it ) to a uncharged material that is grounded .

So, when the negatively charged rubber rod is brought closer to the grounded conductor which is neutral, a positive charge is induced on the conductor's side which is closer to the rubber rod and a negative charge on the other side which is close to the ground. So the negative charge starts escaping through ground. As it is disconnected from the ground, the conductor becomes positively charged.  

Therefore, the conductor is positively charged after you remove the rubber rod.

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The Magnitude of force on the charged particle is -

F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k

We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.

The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force.

Mathematically -

|F| = qE + qv x B

According to the question, we have -

q = 3.20 × 10⁻¹⁹C

v = (2i + 3j - k) m/s

B = (2i + 4j + k) T

E = (4i - j - 2k) V

Now, using the formula to calculate Lorentz force -

F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)

F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)

F = q(4i - j - 2k) + 0

F = q(4i - j - 2k)

F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k

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If we compare the parallax of a nearby object with an object farther away then we observe that the closer objects have a larger parallax as compared to farther objects.

Parallax refers to the apparent distance of an object and happens in everyday situations.

On a linear surface, when an object is seen from a different viewpoint from a particular distance, it exhibits parallax.

It also occurs due to the change in the viewpoint of an observer.

Parallax is represented by the formula d = p1 where 'd' is parsecs and 'p' is the parallax angle which is calculated in arc seconds.

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The magnitude of the electric field is 3.65×10^5N/C directed radially outward.

R (radius of the solid sphere) = (10cm)( 1m /100cm) = 0.1m

[tex]Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)=\textcolor{#ff9c8c}{26\times 10^{-6}\;\mathrm{C}}[/tex]

Since [tex]{r=0.1\;\mathrm{m} < R}[/tex], we can use Equation [tex]E&=\dfrac{Qr}{4\pi \epsilon_0 R^3}\tag{5}[/tex] to find the magnitude of the electric field:

Substitute numerical values:

[tex]E&=\dfrac{(26\times 10^{-6})(0.1)}{4\pi (8.8542\times 10^{-12})(0.4)^3}\\ &={3.65\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]

Magnitude generally refers to distance or quantity. In comparison to motion, Magnitude defines the size of an entity or its speed when moving.

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Answer:

C. 2.5 N

Explanation:

The sum of downwards moments equals sum of moments upwards

Downwards moments

Moments= Force*distance

               = [10/100 * 2 ] +[20/100*4]

               =[0.1*2] +[0.2*4]

               =[0.2+0.8]

               = 1.0 N

Equate this answer to upward force ;

1.0 N = 0.4 *U

1/0.4 =U

2.5 N =U