Time required for the car to reach a speed of 90 km/h is 4.165 seconds.
To solve for time, use the formula for time, t = d/s which means time equals distance divided by speed.4.165 sec
In light of the posed query,
Initial velocity is 60 km/h, which is 60 x 1000 / 36600, or 16.67 m/s.
90 km/h is equal to 901000/3600, or 25.
2 m/s2 for acceleration, or a.
t = time
We are also asked to determine how long it will take the car to
accelerate to its final speed of 90 km/h.
We are aware,
v = u+at
Given the values we receive,
25 = 16.67 + 2t
2t = 25-16.67
2t = 8.33
t = 8.33/2
t = 4.165 sec
Thus, the car will take 4.165 sec to attain the final velocity of 90 km/h if its acceleration is 2 m/s^2 and initial velocity is of 60 km/h.
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A girl throws a ball vertically upwards. It takes a time of 3.20 s to return to her hand.
Assume air resistance is negligible.
What is the initial speed with which the ball is thrown?
Answer: 15.68ms
Explanation:
From the question, we are informed that it takes a time of 3.20s for the ball to return to her hand.
Then, the time thst will be taken by the ball to reach maximum height will be 1.6s
Let the initial speed be represented by v.
Therefore,
Vf = v - gt
where,
g = 9.8
t = 1.6
Vf = v - gt
0 = v - (9.8 × 1.6)
0 = v - 15.68
v = 15.68ms
=v−gt
⟹0=v−9.8×1.6
⟹v=15.68ms
A car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds. what is its acceleration?
The acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.
What is acceleration?It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
As we know,
The acceleration can be found using the formula:
a = Δv/t
Here a is the acceleration
Δv is the change in linear velocity
t is the time
Δv = 29 - 33
Δv = -4 m/s
t = 10 seconds
a = -4/10
a = -0.4 m/s²
Thus, the acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.
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HELPPP!!! During a soccer game, a player kicks the winning goal. When is work being done by the player?
A) when the ball flies through the air
B) when the player moves toward the ball
C) when the player’s foot is in contact with the ball
D) when the player’s foot continues to move after touching the ball
Answer:
when the player’s foot is in contact with the ball
Explanation:
a car accelerates from rest to 90 kilometre per hour in 10 seconds what is its acceleration in metre per second squared
Answer:2.5 m/s2
Explanation:
Acceleration =v2-v1 ÷ t2-t1 convert 90 km/h to m/s = 90×5/18 = 25 m/s , 25÷10 = 2.5
A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N
Given that,
Mass of a frog, m = 0.5 kg
The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².
To find,
The magnitude of the net force exerted on the frog as it leaps.
Solution,
Let the net force exerted on the frog is given by the formula as follows :
F = ma
Putting the values of m and a to find F as follows :
F = 0.5 kg × 5 m/s²
F = 2.5 N
So, the magnitude of net force is 2.5 N.
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
Given the data in the question;
Mass of frog; [tex]m = 0.5kg[/tex]Acceleration; [tex]a = 5.0m/s^2[/tex]Force Exerted; [tex]F = ?[/tex]
To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:
[tex]F = m * a[/tex]
Where m is mass and a is acceleration
We substitute our given values into the equation
[tex]F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N[/tex]
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
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How does the parallax of a nearby object compare to that of an object farther away?.
If we compare the parallax of a nearby object with an object farther away then we observe that the closer objects have a larger parallax as compared to farther objects.
Parallax refers to the apparent distance of an object and happens in everyday situations.
On a linear surface, when an object is seen from a different viewpoint from a particular distance, it exhibits parallax.
It also occurs due to the change in the viewpoint of an observer.
Parallax is represented by the formula d = p1 where 'd' is parsecs and 'p' is the parallax angle which is calculated in arc seconds.
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A football goalkeeper moves across her goal in a straight line. Her motion is shown on the following graph of horizontal position xxx vs. time ttt. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. What is the average speed of the goalkeeper between the times t=4\text{ s}t=4 st, equals, 4, start text, space, s, end text and t=12\text{ s}t=12 st, equals, 12, start text, space, s, end text? Choose 1 answer: Choose 1 answer: (Choice A) A -0.25\,\dfrac{\text m}{\text s}−0.25 s m minus, 0, point, 25, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice B) B 0.50\,\dfrac{\text m}{\text s}0.50 s m 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice C) C -0.50\,\dfrac{\text m}{\text s}−0.50 s m minus, 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice D) D 0.25\,\dfrac{\text m}{\text s}0.25 s m
Answer:
0.25 m/s
Explanation:
Acceleration cannot be negative.
A plane flew for 2 hours at 467 mph and 5 hours at 536 mph how far did the plane fly in miles?
Answer:
3614
Explanation:
in a slap shot, a hockey player accelerates the puck from a velocity of 5 m/s to 30 m/s in the same direction. if the puck moves over a distance of 10 m during this process, what was the acceleration? group of answer choices
The acceleration of the puck is 43.75 m/s².
The velocity of an object or particle in uniform motion is defined as the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.
The player's puck accelerates from a velocity of 5 m/s to 30 m/s in the same direction.
The player's puck covers a distance of 10 m during that process.
Therefore,
The initial velocity of the puck is u = 5 m/s
The final velocity of the puck is v = 30 m/s
The distance covered during the period is s = 10 m
Using the equation of motion,
v² - u² = 2as
(30)² - (5)² = 2 × a × 10
900 - 25 = 20 × a
875 = 20 × a
a = 875/20
a = 43.75 m/s²
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Two short people are trying to get a 50 kg box moving across the floor. One is quite tall, and the other is quite short, so they can't use the same rope. The shorter person pulls on the rope so it is exactly horizontal to the floor, and uses a force of 170N. The taller person has to hold their rope at a 45 degree angle to the horizontal, and pulls with a force of 200N. What is the acceleration assuming the coefficient of friction is 0.3.
A net impulse delivered to an object always causes a change in the object's
what? A. Energy B. Momentum C. Speed D. mass
Answer:
momentum
Explanation:
The net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
The given problem is based on the concept of net impulse. The magnitude of force acting on any object for very short interval of time is known as impulse. In the given problem, the transfer of impulse can be explained by the impulse - momentum theorem.
As per the impulse-momentum theorem, "The magnitude of force applied for a very short interval of time is equal to the change in linear momentum , such that the magnitude of force is known as impulse. Ans the expression is,[tex]F \times t = \Delta P\\\\I= \Delta P[/tex]
Here, I is the impulse.
Thus, we can conclude that the net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
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A box moves 5m horizontally when force F=10N is applied at an angle 0=30°.
What is the work done?
please help and show your work if you can
Answer:
43.3J
Explanation:
Given parameters:
Force = 10N
Distance = 5m
Angle = 30°
Unknown:
Work done = ?
Solution:
Work done is the force applied to move a body through a particular distance;
Work done = Force x distance cos Ф
Now insert the parameters and solve;
Work done = 10 x 5 cos 30 = 43.3J
PLEASE ANSWER ASAP I will give 30 points
Many scholars and historians see Florence, Italy as the “New Athens” and the center of the Renaissance. Why would Florence receive this title and how did Florence live up to it?
Answer:
Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry
Explanation:
Answer:
Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry
Explanation:
M A particle with positive charge q = 3.20 ×10⁻¹⁹C moves with a velocity →v = (2i + 3j - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (b) What angle does the force vector make with the positive x axis?
The Magnitude of force on the charged particle is -
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.
What is Lorentz Force?The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force.
Mathematically -
|F| = qE + qv x B
According to the question, we have -
q = 3.20 × 10⁻¹⁹C
v = (2i + 3j - k) m/s
B = (2i + 4j + k) T
E = (4i - j - 2k) V
Now, using the formula to calculate Lorentz force -
F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)
F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)
F = q(4i - j - 2k) + 0
F = q(4i - j - 2k)
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
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What is the name of the process that plants use to remove carbon dioxide from the atmosphere?
transpiration
photosynthesis
respiration
decomposition
Answer:
Photosynthesis
Explanation:
It removes carbon naturally.
Answer:
photosynthesis
Explanation:
When two mechanical waves interact and their crests line up, they create constructive interference. True or False?
What part of an experiment contains the data tables and graphs
?
Answer: Review your data. ...
Calculate an average for the different trials of your experiment, if appropriate.
Make sure to clearly label all tables and graphs. ...
Place your independent variable on the x-axis of your graph and the dependent variable on the y-axis.
Hope this helps!!
julie drives 100 mimi to grandmother's house. on the way to grandmother's, julie drives half the distance at 34.0 mphmph and half the distance at 66.0 mphmph . on her return trip, she drives half the time at 34.0 mphmph and half the time at 66.0 mphmph .
The average speed is r=50 mph
What is speed?Teenagers, young adults, and others use the stimulant medication known as "speed" to feel more focused and alert, and occasionally to get euphoric. Several types of speed are also used by some people to suppress their appetite. Different speed types include: Amphetamines (used to treat ADHD, narcolepsy, and depression)
In essence, an object's speed indicates how quickly it is moving. Its velocity reveals how quickly it is moving in a specific direction. In your daily life, you utilize speed measures, but in physics, velocity measurements are more frequently used.
distance=rate*time
total distance=rate*total time
to Grandmother's...
50=34*t
50/34=t
t=25/17 hours for the first 50 miles
50=66*t
50/66=t
t=25/33 hours for the second 50 miles
total distance=50+50=100 miles
total time=25/17+25/33
total time=(825/561)+(425/561)=1250/561 hours
total distance=rate*total time
100=r*(1250/561)
r=(100)(561/1250)
r=56,100/1250
r=5610/125
r=1122/25
r=44.88 mph is the average speed (rounded it is 44.9 mph)
Note: If you are familiar with the simplified form of the harmonic mean you can solve the problem that way. If not, that's okay. You can look it up if you like.
(2*34*66)/(34+66)=4488/100=44.88 again
from Grandmother's house...
because the times are the same you simply add the 2 rates and divide by 2
(34+66)/2=100/2=50 mph is the average speed
d=r*t
100=34*t+66*t (the times are the same, t)
100=100*t
t=1 hour traveling at 34 mph and 1 hour traveling at 66 mph for a total of 2 hours traveling
d=r*t
100=r*2
r=100/2
r=50 mph is the average speed
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Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire is 5.00 A. (c) What would happen if the direction of one current were reversed and doubled?
When the direction of one current is reversed and doubled, the force will be doubled.
The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.
With a distance of 4.00 cm between them, two parallel wires repel one another with a force of 2.00 × 10⁻⁴ N/m. One wire is carrying 5.00 A of current.
I₁ = 5 A
d = 4 cm
F = 2 × 10⁻⁴ N/m
We have, [tex]\frac{F}{L}=\frac{\mu_{0} I_{1}I_{2}}{L}[/tex]
Now, we know the force is directly proportional to the product of the current, and the direction of one current is reversed and doubled.
The force of interaction would become attractive and its magnitude would double as a result of switching the directions of either of the currents and doubling their size.
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1.10 You bring a negatively charged rubber rod close to a grounded
conductor without touching it. Then you disconnect the ground. What is the
sign of the charge on the conductor after you remove the charged rod?
a) negative
b) positive
d) cannot be determined from the
information given
c) no charge
The conductor after disconnected from the ground is positively charged after you remove the rubber rod.
Electrostatic induction is the change in a material's electric charge under the influence of another nearby object that has electric charge. For Electrostatic induction to occur a charged particle is held close (without touching it ) to a uncharged material that is grounded .
So, when the negatively charged rubber rod is brought closer to the grounded conductor which is neutral, a positive charge is induced on the conductor's side which is closer to the rubber rod and a negative charge on the other side which is close to the ground. So the negative charge starts escaping through ground. As it is disconnected from the ground, the conductor becomes positively charged.
Therefore, the conductor is positively charged after you remove the rubber rod.
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Which form of heat transfer transfers both matter(particles) and energy?
Conduction
Convection
Radiation
None of these
QC Two waves simultaneously present on a long string have a phase difference π between them so that a standing wave formed from their combination is described by
y(x,t) = 2Asin( kx + π/2 ) cos( ωt - π/2) (a) Despite the presence of the phase angle π, is it still true that the nodes are one-half wavelength apart? Explain.
The equation of motion of the standing wave, y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2), indicates that it is still true that the nodes are one half the wavelength apart
Therefore;
It is still true that the nodes are one half the wavelength apart What are the nature of standing wave?The equation describing the standing wave formed by the two waves is y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2)
A standing wave is formed when two waves that have equal amplitude and frequency and moving in opposite directions, are combined.
A standing wave can be formed by a wave and its reflection, resulting in a wave where there is no propagation of particles beyond the vibration region.
The fundamental frequency of a standing wave consists of two nodes and an antinode.
The wavelength is the distance between two peaks of one wave, such that two nodes are formed within the span of a wavelength, which makes the distance between nodes being half the wavelength of the wave.
Therefore;
It is still true that the nodes are one half the wavelength apart.
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A forklift was used to lift a 750 kg. oil drum 18 m straight up into the air to store on a shelf. If it does it in 28 seconds, Calculate the work and power exerted by the forklift.
W= J
P= watts
Explanation:
Given parameters:
Mass of forklift = 750kg
Height of lift = 18m
Time taken = 28s
Unknown:
Work done = ?
Power = ?
Solution;
The work done by the forklift is given as:
Work done = mass x acceleration due to gravity x height
Work done = 750 x 9.8 x 18 = 132300J
Power is the rate at which work is done;
Power = [tex]\frac{work done }{time}[/tex]
Insert the parameters and solve;
Power = [tex]\frac{132300}{28}[/tex] = 4725W
Pls do these for me asap
Answer:
Look below!
Explanation:
1) Observation
2) Hypothesis
3) Results
4) Experiment
5) Problem
6) Conclusion
7) Inference
A runner exerts a force of 234 Newtons against the ground while using 1100 Watts of power. How long does it take them to run a distance of 30.0 m?
Answer:
30 seconds
Explanation:
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the magnitude of the electric field(b) 10.0cm
The magnitude of the electric field is 3.65×10^5N/C directed radially outward.
R (radius of the solid sphere) = (10cm)( 1m /100cm) = 0.1m
[tex]Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)=\textcolor{#ff9c8c}{26\times 10^{-6}\;\mathrm{C}}[/tex]
Since [tex]{r=0.1\;\mathrm{m} < R}[/tex], we can use Equation [tex]E&=\dfrac{Qr}{4\pi \epsilon_0 R^3}\tag{5}[/tex] to find the magnitude of the electric field:
Substitute numerical values:
[tex]E&=\dfrac{(26\times 10^{-6})(0.1)}{4\pi (8.8542\times 10^{-12})(0.4)^3}\\ &={3.65\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]
Magnitude generally refers to distance or quantity. In comparison to motion, Magnitude defines the size of an entity or its speed when moving.
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What change would occur if Earth's rate of rotation significantly increased?
a. The day would be longer.
b. The day would be shorter.
c. The year would be longer.
d. The year would be shorter.
Answer:the answer is B The day would be Shorter .
Explanation:its correct I got it right hope this help .
The change that would occur if Earth's rate of rotation significantly increased is that the day would be shorter. The correct option is b.
What is Earth's rotation?The rotation or spin of the Earth is the rotation of the planet Earth around its own axis, as well as changes in the orientation of the rotation axis in space. Earth rotates counterclockwise as seen from the northern polar star Polaris.
Earth rotates because the sun attracts the earth and thus pulls it towards it, and because the earth's revolution around the sun causes it to move away from the sun in the direction of the tangent, causing a rotational force (torque) to act on the earth, causing it to rotate.
The Earth rotates once every 24 hours in relation to the Sun, but once every 23 hours, 56 minutes, and 4 seconds in relation to other distant stars. Because the Earth's rotation slows slightly over time, a day used to be shorter.
Thus, the correct option is b.
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A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops at a time of 0.5 seconds. What is the force on the car?
Answer:
The force = F = -40000 N
Explanation:
Mass m = 1000 kg speed v₁ = 20 m/s speed v₂ = 0 m/s t = 0.5We know that,
Calculating the acceleration
using the formula
a = (v₂ - v₁) / t
= 0 - 20 / 0.5
= -20 / 0.5
= -40 ms⁻²
Thus, acceleration (deceleration) = a = -40 ms⁻²
Note: negative sign gives us an idea the car is slowing down after a collision with the barrier, thus acceleration and velocity are in opposite direction.
We know that
F = ma
= 1000 × -40
= -40000 N
Thus, the force = F = -40000 N
Question 17 (2 points)
A delivery man is told to go 60 miles per hour north to make his delivery on time. These instructions describe the delivery man's (2 points)
a
speed
velocity
ОБ
OC
Od magnitude
acceleration
The correct answer is velocity.
The vector measure of level and direction of motion is known as velocity. The speed at which an object goes in one direction is known as its velocity. Speed may be used to calculate both the speed of the car traveling north on the major highway and the speed of the rocket bursting in space. As you may expect, the vector velocity's scalar size (total value) corresponds to the movement's speed. Speed is the initial exit of a place in terms of time when it comes to computations. A straightforward formula that incorporates measurement, distance, and time can be used to determine speed.
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as you walk to the grocery store you walk 800m north, 600m east and 200m south at a speed of 1m/s. what is your velocity?
According to the question as you walk to the grocery store you walk 800m north, 600m east, and 200m south at a speed of 1m/s. Then your velocity will be ( V = 0.5m/sec )
Velocity is the directional pace of an object in movement as an indication of its price of alternate in function as located from a specific body of reference and as measured by a particular widespread of time.
To find the velocity follow the following steps:
Displacement of 800m north, 600m east, and 200m south from the Cartesian coordination is given as 600[tex]\sqrt{2}[/tex]
Velocity = displacement / time
Therefore time = distance / speed
Time = 800 + 600 + 200 / 1
Time = 1600s
Therefore velocity = 600[tex]\sqrt{2}[/tex] / 1600
Velocity = 0.5m/sec
A Cartesian coordinate gadget in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates, which are the signed distances to the factor from constant perpendicular oriented strains, measured in the equal unit of duration.
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