Answer:
Each kilogram of the cannonball has a total energy of 52396.454 joules.
Explanation:
From Principle of Energy Conservation we understand that energy cannot be destroyed nor created, but transformed. In this case non-conservative forces can be neglected, so that total energy of the cannonball ([tex]E[/tex]) is the sum of gravitational potential ([tex]U_{g}[/tex]) and translational kinetic energies ([tex]K[/tex]), all measured in joules. That is:
[tex]E = U_{g}+K[/tex] (Eq. 1)
By applying definitions of gravitational potential and translational kinetic energies, we proceed to expand the expression:
[tex]E = m\cdot g \cdot y + \frac{1}{2} \cdot m \cdot v^{2}[/tex] (Eq. 2)
Where:
[tex]m[/tex] - Mass of the cannonball, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]y[/tex] - Height of the cannonball above ground level, measured in meters.
[tex]v[/tex] - Speed of the cannonball, measured in meters per second.
As we do not know the mass of the cannonball, we must calculated the unit total energy ([tex]e[/tex]), measured in joules per kilogram, whose formula is found by dividing (Eq. 1) by the mass of the cannonball. Then:
[tex]e = g\cdot y + \frac{1}{2}\cdot v^{2}[/tex]
If we know that [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y =122\,m[/tex] and [tex]v = 320\,\frac{m}{s}[/tex], the unit total energy of the cannonball is:
[tex]e = \left(9.807\,\frac{m}{s^{2}}\right)\cdot (122\,m)+\frac{1}{2}\cdot \left(320\,\frac{m}{s} \right)^{2}[/tex]
[tex]e = 52396.454\,\frac{J}{kg}[/tex]
Each kilogram of the cannonball has a total energy of 52396.454 joules.
Does voltage remain the same throughout a series circuit
It depends on the circuit. Sometimes it becomes a bit weaker, sometimes it stays the same.
Answer:
In a series circuit, the current that flows through each of the components is the same, and the voltage across the circuit is the sum of the individual voltage drops across each component.
Tension is actually a force that tends to
Answer:
Pull towards itself.
Explanation:
That's what I know.
Tension is a force that tends to pull or stretch an object. A flexible material, like a rope, cable, or string, is used to transmit the force.
A force known as tension has a tendency to pull or stretch an object. When a flexible medium, like a rope, cable, or string, is under strain and supporting an imposed load or weight, it transmits force via the flexible medium.
A rope or cable that is under tension receives equal and opposing forces pulling it in different directions at either end. For instance, the tension in a rope will be the same along its whole length if both ends are pulled with equal effort.
When you use a pulley system to hoist a weight, suspend an object from a rope, or support the weight of traffic on a bridge, tension can be present.
Therefore, Tension is a force that tends to pull or stretch an object.
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Mina finds out that a company is pumping water from an aquifer near her home. What can Mina conclude about the water being pumped? The water being pumped is under a lot of pressure and comes from a confined aquifer. The water being pumped is under a lot of pressure and comes from an unconfined aquifer. The water being pumped is at atmospheric pressure and comes from a confined aquifer. The water being pumped is at atmospheric pressure and comes from an unconfined aquifer.
Answer:
The water being pumped is at atmospheric pressure and comes from an unconfined aquifer.
Answer:
The water being pumped is at atmospheric pressure and comes from an unconfined aquifer.
Explanation:
what are day and night are produced by?
Answer:
Day and night are due to the Earth rotating on its axis, not its orbiting around the sun. The term 'one day' is determined by the time the Earth takes to rotate once on its axis and includes both day time and night time.
Explanation:
Answer:
Day and night are due to the Earth rotating on its axis, not its orbiting around the sun. The term 'one day' is determined by the time the Earth takes to rotate once on its axis and includes both day time and night time.
note:
your welcome and please answer my question its called part 1 math work if you could do that i will give you 40 points
How to call the police?
Answer:
dail 911
tell problem and location
plz mark brainliest
Which would be harder to move: a kilogram of feathers or a kilogram of bricks? Explain your answer.
Answer:
The kilogram (kg) is the SI unit for mass. Not weight.
So when you say « heavier » and mention kg, I would assume you’re talking about mass.
The mass of 1 kg of feathers and 1 kg ok bricks are identical.
And if you want an answer to your question comparing the weight on Earth of those 2 items, in vacuum of one kilogram of feathers would have exactly the same weight as one kilogram of bricks.
Explanation:
Hope this helps! <3
please help quick, i’m timed!
Question 2 (5 points)
What is the speed of sound in water if the wavelength is 2.5 m and the frequency
592 Hz?
What would happen to the frequency if the wavelength increased to 5 m?
Explanation:
v=592×2.5
v=1480m/s
ii) v=1480m/s, wavelength= 5m, f=?
f=1480/5
f=296Hz
A ball tossed vertically upward rises, reaches its highest point, and then falls back to its
starting point. While the ball is rising, what is happening to its speed.
O it is increasing by 10 m/s^2
O it is increasing, but not at a constant rate
it is decreasing by 10 m/s^2
it is decreasing, but not at a constant rate
O it moves with constant speed
Answer:
Third Option: It is decreasing by 10m/s^2
Explanation:
When a ball is thrown in the air, it's fastest velocity occurs just as it leaves its source (e.g. the hand that throws it), and just before it hits the starting point. This is because this is when it has the most kinetic energy which translated into speed. As it rises, it starts to lose kinetic energy as it transforms into gravitational potential energy as the ball is fighting against the force of gravity as it moves further away from the Earth's surface. This means it begins to slow down until its speed is 0, its highest point, before falling and gaining kinetic energy again. Because of this, we can eliminate options 1, 2 and 5 as we know the ball's velocity decreases as it rises.
As the ball rises it's velocity decreases at a constant rate, as the amount of kinetic energy it has is proportional to its height. Therefore, the best option is option 3, as it states it is decreasing and gives a constant deceleration rate.
Hope this helped!
Which method of measurement is most likely to be precise but lacks
accuracy?
A. Measuring the distance across a pond by counting how many
strokes you make as you swim across
B. Measuring time by counting the number of breaths you take as
you do an activity
O C. Measuring your weight with a scale that measures to the nearest
tenth of a kg but adds 2 kg to each measurement
D. Measuring the length of a bus using a tape measure that
measures to the nearest millimeter
Answer:
C
Explanation:
Measuring your weight with a scale that measures to the nearest
tenth of a kg but adds 2 kg to each measurement
Analysis of an accident scene indicates a car was traveling at a velocity of 70.0 mph (31.3 m/s) along the positive x-axis at the instant the brakes were applied and then traveled a distance of 115 m before hitting an obstacle at a velocity of 4.65 m/s. Determine the car's acceleration a (assumed constant) and the time t between applying the brakes and hitting the obstacle. (Assume the car is moving in the positive direction. Indicate the direction with the sign of your answer.)
Answer:
The acceleration of the car is -4.166 m/s²
The time between applying the brakes and hitting the obstacle is 6.4 s
Explanation:
Given;
initial velocity of the car when the brake was applied, u = 31.3 m/s
final velocity of the car after hitting an obstacle, v = 4.65 m/s
distance traveled before stopping, s = 115 m
The acceleration of the car is given by;
v² = u² + 2as
2as = v² - u²
a = (v² - u²) / 2s
a = (4.65² - 31.3²) / (2 x 115)
a = -4.166 m/s²
The time between applying the brakes and hitting the obstacle;
v = u + at
at = v - u
t = (v - u) / a
t = (4.65 - 31.3) / -4.166
t = 6.4 s
At the bifurcation of the femoral artery the pressure is 100 mm Hg. The venous pressure after either the left or right femoral artery is 10 mm Hg. The resistance in the right femoral artery is 1.67 times the resistance through the left femoral artery. The total flow rate just upstream of the bifurcation is 800 mL/min. How does the flow divide into the left and right femoral arteries
Answer:
The values are [tex]I_L = 500.37 \ mL / minutes [/tex]
and [tex]I_r = 299.63 \ mL / minutes [/tex]
Explanation:
From the question we are told that
The pressure at the bifurcation of the femoral artery is [tex]P = 100\ mm\ Hg[/tex]
The pressure at the left or right femoral artery is [tex]P_r = P_l = 10 \ mm \ Hg[/tex]
The resistance in the left femoral artery is [tex]R_L[/tex]
The resistance in the right femoral artery is [tex]R_r = 1.67 R_L[/tex]
The total flow rate is [tex]I = 800 mL/minute[/tex]
The diagram illustrating this question is shown on the first uploaded image
Generally this flow of blood through the artery can be compared to the a circuit as shown on the first uploaded image
Generally the rate at which blood flows through the left femoral artery is mathematically represented as
[tex]I_L = I * \frac{R_r }{R_L + R_r}[/tex]
=> [tex]I_L = 800 * \frac{1.67 R_L }{R_L + 1.67 R_L}[/tex]
=> [tex]I_L = 800 * \frac{1.67 R_L }{2.67 R_L}[/tex]
=> [tex]I_L = 500.37 \ mL / minutes [/tex]
Generally the rate at which blood flows through the right femoral artery is mathematically represented as
[tex]I_r = I * \frac{R_L }{R_L + R_r}[/tex]
=> [tex]I_r = 800 * \frac{R_L }{R_L + 1.67 R_L}[/tex]
=> [tex]I_r = 800 * \frac{ R_L }{2.67 R_L}[/tex]
=> [tex]I_r = 299.63 \ mL / minutes [/tex]
You observe two cars traveling in the same direction on a long, straight section of Highway 5. The red car is moving at a constant vR equal to 34 m/s and the blue car is moving at constant vB equal to 28 m/s. At the moment you fist see them, the blue car is 29.0 m ahead of the red car.
Required:
a. How long after you first see the cars does the red car catch up to the blue car?
b. How far did the red car travel between when you fist saw it and when it caught up to the blue car?
c. Suppose the red car started to accelerate at a rate of a equal to 5/3 m/s^2 just at the moment you saw the cars.
d. How long after that would the red car catch up to the blue car?
Answer:
a) 3.66 s
b) 124.4 m
c) 3.12s
Explanation:
Given that
Speed of the Red Car, v₁ = 34 m/s
Speed of the Blue Car, v₂ = 28 m/s
Distance between the two cars, d = 22 m
The difference between the speed of the cars is: 34 - 28 = 6 m/s
From this, we can deduce that the red car will be catching up to the blue car at a speed of 6 m/s.
1)
If we divide the distance by the difference in speed. This becomes
d/v = 22/6 = 3.66 s. Which means, It takes 3.66 seconds for the red car to meet up with the blue car.
2
From the previous part, we were able to confirm that it took 3.66 seconds for the red car to meet up the blue car. Also, the speed with which it were traveling was travelling at, was constant, so we only need to multiply it by the time from (1) to get the distance.
v = d * t = 34 * 3.66 = 124.4
Therefore the red car travels at 124.4 m before catching up to the blue car.
3
If the red car starts to accelerate the moment we see it, the time it will take, to get to the blue car will be less than what we had gotten. We can find this using one of the equations of motion.
S = ut + ½gt², where
S = 22
u = 6
t = ?
g = 2/3
22 = 6t + 1/3t²
By using the quadratic formula, we find out the two answers listed below
t1 = 3.12 s
t2 = - 21.12 s
We all know that negative time is not possible, so the answer is t1. At 3.12 seconds
A mass of 0.4 kg is dropped from rest in a medium offering a resistance of 0.2|v|, where is measured in meters per second. Acceleration due to gravity is 9.8 m/s^2.
Required:
a. If the mass is dropped from a height of 25 m, find its velocity when it hits the ground.
b. If the mass is to attain a velocity of no more than 8 m/s, find the maximum height fromwhich it can be dropped.
c. Suppose that the resistive force isk|v|, wherevis measured in m/s, andkis constant.If the mass is dropped from a height of 25 m and must hit the ground with a velocity of no more than 8 m/s, determine the coefficient of resistance that is required.
Answer:
A.) 22.12 m/s
B.) 3.27 m
C.) 0.57
Explanation:
Given that a mass of 0.4 kg is dropped from rest in a medium offering a resistance of 0.2|v|, where is measured in meters per second. Acceleration due to gravity is 9.8 m/s^2.
a. If the mass is dropped from a height of 25 m, its initial velocity U will be equal to zero. when it hits the ground, the final velocity V will be:
V^2 = U^2 + 2gH
Substitute g and the height into the formula
V^2 = 2 × 9.8 × 25
V^2 = 490
V = 22.12 m/s
b. If the mass is to attain a velocity of no more than 8 m/s, the maximum height from which it can be dropped will be calculated by using the same formula.
V^2 = U^2 + 2gH
Where V = 8 m/s and U = 0
8^2 = 0 + 2 × 9.8 × H
64 = 19.6H
H = 64/19.6
H = 3.27 m
c. Suppose that the resistive force is k|v|, where v is measured in m/s, and k is constant. If the mass is dropped from a height of 25 m and must hit the ground with a velocity of no more than 8 m/s, determine the coefficient of resistance that is required.
The energy at 25m heigh will be:
E = mgh
E = 0.4 × 9.8 × 25
E = 98 J
1/2mv^2 = 98
1/2 × 0.4 × ( 8 - v )^2 = 98
0.2( 8 - v )^2 = 98
( 8-v)^2 = 98/0.2
( 8 - v )^2 = 490
8 - v = 22.12
v = 22.14 - 8
v = 14.14
Coefficient of resistance required will be 8/ 14.14 = 0.57
The world record for the 100-meter dash is 9.76 s. What is the runner's average speed?
Answer:
mine is 9.75 so take that as you will
Explanation:
Which of the vectors below is the sum of vectors à and b, shown here?
Answer:
B
Explanation:
Answer:
B
Explanation:
Just took the quiz
Which change will decrease the electric force between two positively charged objects?
1.moving them closer together
2.moving them farther apart
3.adding neutrons
4.removing electrons
Answer:
2
Explanation:
Answer:
The answer is B
Explanation:
Q1: An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical force that the objects exert on each other. Use 8.988100 N·m2/C2 for the value of Coulomb's constant. Give your answer to two decimal places.
Answer:
a) F= 0,19 [N] according to problem statement
b) F = 0,19*10⁹ [N] using the right value of K
Explanation:
The force between two electric charges is according to Coulomb´s law is:
F = K * q₁*q₂ / d² where q₁ and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant K = 8,988100*10⁹ N.m²/C². The problem establishes to use K = 8,988100 N.m²/C².
NOTE: To value of is : K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹
Then:
F = 8,988100 * 1,2* 0,36 / (4,5)² [ N*m²/C² ] * [ C*C*/m²]
F = 3,882859/ 20,25 [N]
F= 0,19 [N]
The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies
What is the HORIZONTAL component of a vector with a magnitude of 125 m/s and an angle of 25 degrees?
Answer:
113.29 m/s
Explanation:
I think its this answer choice, hope I'm not too late answering.
A car traveled at a constant velocity of 70 mph from noon to 2:00 pm. At 3:00 pm the velocity of the car was 80 mph; and finally at 4:30 pm the velocity of the car was 40 mph.
Which statement accurately describes the acceleration of the car?
Answer:
Not sure which statements were give to you for this question, but the vehicle's acceleration from noon to 2:00 PM was zero, the vehicle had a positive acceleration between 2:00 pm and 3:00 pm, and the vehicle had a negative acceleration at 4:30 PM.
Explanation:
From 12:00 PM to 2:00 PM, the vehicle traveled at a constant velocity of 70 MPH, meaning there wasn't any change to the speed. The velocity remained the same. An hour later, the velocity of the vehicle increased to 80 MPH, and finally at 4:30 PM, the velocity of the car decreased and was at 40 MPH.
A moving car of mass 500 kg collides with a stationary truck of
mass 1500 kg, and the two vehicles lock together on impact.
The combined velocity of the car and truck after the collision is
20 m/s. What is the velocity of the car before the collision?
Answer:
We are given:
m1 = 500 kg m2 = 1500 kg
v1(initial) = x m/s v2(initial) = 0 m/s
v1(final) = 20 m/s v2(final) = 20m/s
According the the law of conservation of momentum:
m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final)
Plugging the values in this formula:
(500*x) + (1500 * 0) = (500 * 20) + (1500 * 20)
500x = 20(1500 + 500)
500x = 20(2000)
x = 20 * 4
x = 80 m/s
Therefore, the car was initially moving at a velocity of 80 m/s
(15 points) How does change in a roller coasters motion depend on the sum of the forces and the mass of the ride?
the volume of a cube is measured in grams, true or false
Answer: false
Explanation: They are measured by cubic ______. ______ is feet, meters, inches, any way to measure
What does your ecological foot print tell you?
Answer:
How big your foot is. (Big Brain)
Explanation:
A beam of light strikes one face of a window pane with an angle of incidence of 30.0°. The index of refraction of the glass is 1.52. The beam travels through the glass and emerges from a parallel face on the opposite side. Ignore reflections.
Required:
a. Find the angle of refraction for the ray inside the glass.
b. Show that the rays in air on either side of the glass (the incident and emerging rays) are parallel to each other.
(a) The angle of refraction for the ray inside the glass will be 19.26°.
(b) It is proved that the rays in the air on either side of the glass are parallel to each other
What will be the angle of refraction for the ray inside the glass?
When a ray of light passes through a different medium some part of the light gets reflected and some part gets refracted by changing its angle in the different medium this angle is called the angle of refraction and the phenomenon is called refraction of light.
It is given that,
The angle of incidence = 30.0°
Index of reflection of glass = 1.52
(a) For finding the angle of the refraction for the ray inside the glass we will use Snell's Law
[tex]\dfrac{Sini}{Sinr} =\mu[/tex]
Put the value into the formula
[tex]Sinr=\dfrac{Sini}{\mu} =\dfrac{Sin30}{1.52}[/tex]
[tex]r=Sin^{-1}(0.329)[/tex]
[tex]r=19.26^o[/tex]
(b) Now for proof of [tex]Sin\ i =Sin\ e[/tex]
The incident ray and emerging ray are equal then the ray will be parallel.
We need to prove that the rays in the air on either side of the glass are parallel to each other.
Using the formula for emerging ray
[tex]\dfrac{Sin\ e}{Sin\ r} = \mu[/tex]
[tex]Sin\ e=\mu Sin \ r=1.52\times Sin19.26[/tex]
By putting the values in the formula
[tex]e=Sin^{-1}(1.52\times0.3289)[/tex]
[tex]e=30^o[/tex]
Since the incident angle and the emerging angle are equal
[tex]Sin \ i=Sin \ e[/tex]
Thus incident and emerging rays) are parallel to each other.
(a) So the angle of refraction for the ray inside the glass will be 19.26°.
(b) It is proved that the rays in the air on either side of the glass are parallel to each other
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What are the bumps on a gear called?
Answer:
Teeth
Explanation:
The main parts of geards are the base and the teeth. When two wheels are combined and joined by a belt, the larger wheel will rotate more slowly than the smaller wheel, but it will rotate with a greater force. A big wheel with twice the circumference of a small wheel will rotate with twice the force and half the speed of the small wheel.
Gears are connected together in various ways to transmit motion and force. Two connected gears of different sizes will cause one of the gears to turn faster or slower than the other. One gear will also move the force in a different direction than the other.
Gear ratio is the number of teeth on the following gear divided by the number of teeth on the driving gear (the gear inputting the motion).
A low gear ratio = more speed = less force
A high gear ratio = less speed = more force
Please give me brainliest if this helps!
Answer:
Teeth
Explanation:
A man runs 800m due north in 110 seconds followed by 400m due suoth in 90 seconds calculate his average speed and his average velocity
Answer:
Average speed is 6m/s
Average velocity is 5.859m/s
Explanation:
Average speed, s = d/t
d is distant
t is time
speed north is 800m and 110s
speed due south is 400m and 90s
Average speed = (800+400) / (110+90)
= 1200/200
=6m/s
Average velocity V = (v + u)/2
v = final velocity
u = initial velocity
V = (7.273 + 4.444)/2 = 11.717/2
V = 5.859m/s
Explain why the driver's reaction time affects the thinking distance.
Answer:
The thinking distance depends on the reaction time of the driver which could can affected by alcohol, distractions and tiredness. A faster speed increases both thinking distance, increasing the total stopping distance.
I hope this is helpful. Would appreciate if you add me as brainliest.A faster pace extends both the thinking distance and the total stopping distance.
Given that,
To justify, the driver's reaction time affects the thinking distance.
The reaction time of an organism is a measure of how quickly it responds to a signal. The time interval between the presentation of the stimulus and the appearance of the appropriate voluntary response in the subject is defined as the RT.
The thinking distance is determined by the driver's reaction time, which can be influenced by drinking, distractions, and fatigue. A higher speed increases both thinking distance and total stopping distance.
Thus, A faster pace extends both the thinking distance and the total stopping distance.
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Which describes how the spring constant affects the potential energy of an object for a given displacement from an equilibrium position?
A the higher the spring constant, the greater the gravitational potential energy.
B The lower the spring constant, the greater the gravitational potential energy.
C The higher the spring constant, the greater the elastic potential energy.
D The lower the spring constant, the greater the elastic potential energy
Answer:
Based on the answer choices provided, the correct answer is:
C, The higher the spring constant, the greater the elastic potential energy.
Explanation:
The spring constant is best defined as the measure of a spring's resistance to force (in regards to factors such as stretching and compression).
Thus, the higher the spring constant, the stiffer the string - this equates to greater elastic potential energy (think of stretching a rubber band or using it as a slingshot).
Hope this helps!
Answer:
C.) The higher the spring constant, the greater the elastic potential energy.
Explanation:
Particles in a warmer block will have
the particles in the colder block.
kinetic energy and move
than
more / slower
less / slower
less / faster
more / faster
Answer:
more/ faster
Explanation:
I got it right on my test
Particles in a warmer block will have more kinetic energy and move faster than the particles in a colder block option (D) more/ faster is correct.
What is kinetic energy?The energy which an item has as a function of motion is determined by the initial energy. It is described as the effort required to propel a material body from rest to the given velocity.
As we know,
As the temperature rises, the particles' kinetic energy rises and they begin to move more quickly. Particles have higher kinetic energy in gases than in solids.
Thus, particles in a warmer block will have more kinetic energy and move faster than the particles in a colder block option (D) more/ faster is correct.
The question is incomplete.
The complete question is:
Particles in a warmer block will have ________ kinetic energy and move ______than the particles in the colder block.
more / slowerless / slowerless / fastermore / fasterLearn more about kinetic energy here:
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a car with a mass of 2000kg is traveling at a velocity of 50 m/s. the engine supplies a force of 1000N forward.the force of friction is 1000 N backwards. What is the velocity after 5 seconds
Answer:
no
Explanation:
ok