A bus slows from 10 m/s to a stop in 4 seconds.
What is its change in velocity? what is its acceleration?

Answer:

stainless steel is the material which is non magnetic.

Answer:

1 day

Explanation:

The spinning movement of Earth around its axis is known as Earth's rotation.

The Earth rotates around the Sun in 1 day that is 24 hours but once in every 23 hours, 56 minutes, and 4 seconds with respect to other stars.

According to the Indian astronomer Aryabhata, Earth rotates about its axis daily.

Answer:

Two moles of aluminum chloride [tex](AlCl_3)[/tex] are produced when six miles of hydrogen Chloride [tex](HCl)[/tex] react with plenty of aluminum

Explanation:

6 Moles of [tex]HCl[/tex] will only react with 2 moles of [tex]Al[/tex] irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of [tex]AlCl_3[/tex] and 3 moles of [tex]H_2[/tex] this ratio will also be constant.

So, six moles of hydrogen chloride [tex](HCl)[/tex] will react with plenty of aluminum to produce many 2 moles of aluminum chloride [tex](AlCl_3)[/tex].

Answer:

The value is [tex]T = 122036.2 \ N[/tex]

Explanation:

From the question we are told that

     The mass of the car is  [tex]m = 6526 \ kg[/tex]

      The acceleration  is  [tex]a= 8.9 \ m/s^2[/tex]

Generally the net force applied on the rope is mathematically represented as

          [tex]F_{net} = T - W[/tex]

Here W is the weight of the car which is evaluated as

         [tex]W = m * g[/tex]

=>      [tex]W = 6526 * 9.8[/tex]

=>       [tex]W = 63954.8 \ N[/tex]

Generally the net force can also be mathematically represented as

       [tex]F = m * a[/tex]

So

        [tex]m * a = T - 63954.8[/tex]

=>     [tex]6526 * 8.9 = T - 63954.8[/tex]

=>      [tex]T = 122036.2 \ N[/tex]

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Answer:

See the answers below

Explanation:

We can solve both problems using vector sum.

a)

Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative

[tex]F_{resultant}=100+30-85+900\\F_{resultant}=845[N][/tex]

The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.

[tex]F_{drag}=50[N][/tex]

b)

Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.

[tex]F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN][/tex]

Answer:

(a) 100.38 m

(b) 183.49 m

(c) 6.12 seconds and 12.24 seconds.

Explanation:

Given that a body is thrown vertically upwards with a velocity of 60 m/s.

Assuming that upward direction is positive

So, the initial velocity, u=60 m/s

As the acceleration due to gravity, g=9.81 m/s^2, acts in the downward direction, so

a=-9.81 m/s^2

(a) By using the equation of motion, the displacement of the body after time t=2 seconds, is

[tex]s=ut+\frac 1 2 at^2 \\\\ s=60\times 2 +\frac 1 2 (-9.81)2^2 \\\\[/tex]

s=100.38 m

Hence, the height of the body will be 100.38 m after 2 seconds.

(b) At the maximum height, the velocity of the object is zero, so

v=0.

The maximum height is the displacement of the body where it attains zero velocity.

Using the equation of the motion.

[tex]v^2=u^2+2as \\\\0= 60^2 +2(-9.81)s \\\\s=\frac {3600}{2\times 9.81} \\\\[/tex]

s=183.49 m

Hence, the maximum height of the body is 183.49 m.

(c) Time to reach the maximum height

v=u+at

0=60 +(-9.81)t

t=60/9.81

t=6.12 seconds.

The body will take 6.12 seconds to reach the maximum height.

As the time to reach the maximum height from the initial position is the same as the time to reach the initial position from the maximum height.

So, the total time to returns again to the place where it was launched

= 2 x 6.12 = 12.24 seconds.

The difference between colloid and emulsion is that a colloid can form when any state of matter (solid, liquid or gas) combine with a liquid whereas an emulsion has two liquid components which are immiscible with each other.

Answer:

wrthfnhdghkyulyf

Explanation:

zdfhdfhghdhddddddddddddddddddddd

Answer:

I think the the answer is creating and layout and template style     ( C )

Explanation:

I did it before and i was checking my notes and i wrote that down , Hope this Helps :)

Answer:

The net force acting on the object is 0 N

Explanation:

Newton's Second Law of Forces

The net force acting on a body is proportional to the mass of the object and its acceleration.

The net force can be calculated as the sum of all the force vectors in each rectangular coordinate separately.

The image shows a free body diagram where four forces are acting: two in the vertical direction and two in the horizontal direction.

Note the forces in the vertical direction have the same magnitude and opposite directions, thus the net force is zero in that direction.

Since we are given the acceleration a =0, the net force is also 0, thus the horizontal forces should be in equilibrium.

The applied force of Fapp=10 N is compensated by the friction force whose value is, necessarily Fr=10 N in the opposite direction.

The net force acting on the object is 0 N

Answer:

R = 0.21 Ω

Explanation:

the formula:

R = r x l/A

R = (44 x 10-⁸ Ωm) x 1.5 / (π x (1 x 10-³ m)²)

R = 6.6 x 10-⁷ / 3.14 x 10-⁶

R = 0.21 Ω

Answer:

Answer: B. 49 N

Explanation:

Friction Force

When an object is at rest on a rough surface, it encounters a friction force that opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

[tex]Fr=\mu_k N[/tex]

Where [tex]\mu_k[/tex] is the coefficient of static friction and N is the normal force.  

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

Thus, the friction force is:

[tex]Fr=\mu_k W[/tex]

We are given the coefficient of static friction [tex]\mu_k=0.5[/tex] and the mass of the object m=10 Kg. The minimum force needed to make it start moving is the maximum friction force:

Fr=0.5*10*9.8

Fr = 49 N

Answer: B. 49 N

Answer:

The degree of reflection whether faint or bright you see on the surface of an object is an indication that light particles had hit the surface. Since light is a wave and as part of its characteristics can get reflected. However, the amount of light reflected by a surface is dependent on the smoothness of the surface which can be shiny or dull, it can also be dependent on the nature of the surface which can be glass, water, and so on. So, from the question, you can see a faint reflection on the surface of a shiny plate or cup because of the smoothness of the surface which reflects the lights that hit it from a particular direction at the same angle.

Answer:

parasomnia

Explanation:

Answer

I think it is 112 havent done this in a while but im pretty sure thats it Good luck

Explanation:

Answer:

Francium.

I hope it will be useful.

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

Answer:

4g

I hope it will be useful.

Explanation:

KE = (1/2)*m*v^2

Answer:

they can be unpredictable until you think it

Explanation:

Answer:

D.  A record of all the physical activity you complete in one week.

Explanation:

A "Fitness Log" allows you to keep track of your workout or exercise. Therefore, it is a record of the different workout you've managed to complete within a time frame. It gives you several information such as the type of workout you've completed, its duration and the time of the day it was performed. This makes a person motivated to exercise because he can see his progress. He may also include his mood before and after workout in order to become more mindful in exercising and many other things.

Answer:

the answer is D  i just got the answer right

Explanation:

Explanation:

A boat at sea is being moved by the ocean current at 5 metres/minute directly to the east.

At the same time, it is being moved directly to  the north at 3 metres/minute by a strong wind.

We need to find the magnitude and direction of the boat's overall velocity.

As both velocities are moving perpendicular to each other. The resultant velocity is given by :

[tex]v=\sqrt{5^2+3^2} \\\\=\sqrt{25}\\\\=5\ \text{metres/minute}[/tex]

For direction,

[tex]\tan\theta=\dfrac{v_y}{v_x}\\\\=\dfrac{3}5{}\\\\\theta=\tan^{-1}(\dfrac{3}5{})\\\\=30.96^{\circ}[/tex]

Hence, this is the required solutin.

Answer:

KE 1025J

[tex] \frac{1}{2} m {v}^{2} \\ [/tex]

Explanation:

[tex] \frac{1}{2} \times 82 \times {5}^{2} [/tex]

1025J

Answer:

7.35 seconds

Explanation:

The computation of the time passed prior to the ball reached to the highest point is as follows;

As we know that the acceleration because of gravity on earth is 9.8 m/s

As the ball is thrown directly in an upward direction with a speed of 72 m/s

So, the time passed prior to the ball reached to the highest point is

= 72 ÷ 9.8

= 7.35 seconds

Hence, the above represents the answer

True is the correct answer

Immiscible liquids are those which won't mix to give a single phase. Oil and water are examples of immiscible liquids - one floats on top of the other. It explains the background to steam distillation and looks at a simple way of carrying this out.

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

[tex]f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}[/tex]

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

[tex]Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K[/tex]

For the string in option A, the length, L = 27 cm, n = 3 we have;

[tex]f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K[/tex]

For the string in option B, the length, L = 30 cm, n = 4 we have;

[tex]f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K[/tex]

For the string in option C, the length, L = 30 cm, n = 3 we have;

[tex]f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K[/tex]

For the string in option D, the length, L = 24 cm, n = 4 we have;

[tex]f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K[/tex]

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) [tex]f_D[/tex] 2) [tex]f_B[/tex] 3) [tex]f_A[/tex] 4) [tex]f_C[/tex]

The order of the frequencies is  [tex]f_D>f_B>f_A>f_C[/tex]

The frequency of the standing wave in a string tied at both ends is given by:

[tex]f=\frac{nv}{2L}[/tex]

where n is the mode of frequency

v is the velocity of the wave

and L is the length of the string.

Now the velocity of a wave in a string tied at both ends is given by

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where T is the tension and μ is the mass per unit length.

Since T and μ are the same for all the strings, velocity [tex]v[/tex] will be the same for all.

Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.

[tex]f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}[/tex]

Hence, [tex]f_D>f_B>f_A>f_C[/tex]

Learn more about standing waves:

https://brainly.com/question/1698005?referrer=searchResults

Answer:

A. primary waves

Explanation:

Answer:

Change in velocity = 4 m/s and acceleration = 0.5 m/s²

Explanation:

Given that,

Initial velocity, u = 3 m/s

Final velocity, v = 7 m/s

Time, t = 8 seconds

(a) The change in velocity of a cyclist.

[tex]\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s[/tex]

(b) Acceleration,

[tex]a=\dfrac{\Delta v}{t}\\\\a=\dfrac{4\ m/s}{8\ s}\\\\a=0.5\ m/s^2[/tex]

So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².