A boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. The girl moves in a negative direction with a speed of 3 m/s. What must be the final momentum of the boy?
A. 100 kgm/s
B. 120 kgm/s
C. -120 kgm/s
D. 40 kgm/s

Answers

Answer 1

Answer:

B. 120 kgm/s

Explanation:

The initial momentum of the system is zero since the boy and the girl are at rest. When they push each other apart, the total momentum of the system remains conserved. Since the girl moves in a negative direction, the boy must move in the positive direction with the same momentum to keep the total momentum of the system zero.

Let's assume the final momentum of the boy is p. According to the law of conservation of momentum,

(initial momentum) = (final momentum)

0 = p + (-40 kg)(-3 m/s)

0 = p + 120 kg m/s

p = -120 kg m/s

Therefore, the final momentum of the boy must be 120 kg m/s in the positive direction, which is answer choice B.

Answer 2

Ans

According to the law of conservation of momentum, the total momentum of the system before and after the interaction must be equal. Initially, the momentum of the system is zero since the boy and the girl are at rest. When they push each other, the girl moves in the negative direction with a speed of 3 m/s. Let's assume that the boy moves in the positive direction with a speed of v m/s.

The total initial momentum of the system is:

P_initial = m_boy * 0 + m_girl * 0 = 0

The total final momentum of the system must also be zero since there are no external forces acting on the system. Therefore:

P_final = m_boy * v + m_girl * (-3) = 0

where m_boy = 60 kg, m_girl = 40 kg, and v is the final speed of the boy in m/s.

Solving for v, we get:

60v - 120 = 0

v = 2 m/s

Therefore, the total final momentum of the boy must be:

P_final = m_boy * v = 60 kg * 2 m/s = 120 kg m/s.

So, the total final momentum of the boy must be 120 kg m/s.


Related Questions

During an ultrasound, sound waves are sent by a transducer through muscle tissue at a speed of 1,300 m/s. Some of the sound waves are reflected from a metal fragment 5.0 cm into the muscle tissue. How long did it take the transducer to detect the reflected waves from the metal fragment after they were first emitted?

0.26 seconds
39 seconds
4.6 E−5 seconds
7.7E−5 seconds

Answers

To calculate the time it took for the reflected waves to be detected, we can use the formula:

time = distance / speed

where distance is the round-trip distance traveled by the sound waves (i.e., twice the distance from the transducer to the metal fragment) and speed is the speed of sound in muscle tissue.

The round-trip distance traveled by the sound waves is:

2 * 5.0 cm = 10.0 cm = 0.1 m

The speed of sound in muscle tissue is given as 1,300 m/s.

Therefore, the time it took for the reflected waves to be detected is:

time = distance / speed = 0.1 m / 1,300 m/s = 7.7E−5 seconds

So the answer is 7.7E−5 seconds (option D).
Answer:

(d) 7.7E−5 seconds

To calculate the time it takes for the reflected waves to return to the transducer, we can use the formula:

time = distance / speed

The distance the sound waves travel is twice the depth of the metal fragment, since they have to travel to the fragment and then back to the transducer. Therefore, the distance traveled by the sound waves is:

distance = 2 x 5.0 cm = 0.1 m

The speed of the sound waves in muscle tissue is 1,300 m/s. Therefore, the time taken for the waves to travel this distance is:

time = distance / speed = 0.1 m / 1,300 m/s = 7.7E−5 seconds

Therefore, the transducer takes 7.7E−5 seconds to detect the reflected waves from the metal fragment after they were first emitted.

The correct answer is (d) 7.7E−5 seconds.

Review the ray tracing provided.

A thin lens is located centered over a 14 cm ruler at the 7 cm mark. A black dot is located at 5.5 cm on the left side of the lens and at 8.5 cm on the right side of the lens. An arrow is located at the 6 cm mark. Rays appear to go from the head of the arrow towards the lens, and then extend backwards to the tip of an arrow located at 4 cm.

Which of the following best describes the image?

Inverted, smaller, and real
Upright, smaller, and virtual
Upright, larger, and real
Upright, larger, and virtual

Answers

The best description of the image is (B) upright, smaller, and virtual is correct option.

To determine the characteristics of the image, we can use the thin lens equation:

1/f = 1/do + 1/di

where f is the focal length of the lens, do is the object distance (distance of the object from the lens), and di is the image distance (distance of the image from the lens).

We can also use the magnification equation:

m = -di/do

where m is the magnification.

First, we need to determine the focal length of the lens. We can use the fact that the lens is centered over the 14 cm ruler at the 7 cm mark, which means the lens is 7 cm from both the left and right sides of the ruler. Since the ruler has a total length of 14 cm, the lens must be in the middle, and the distance from the lens to the ruler is 7 cm. Therefore, the lens has a focal length of 7 cm.

Next, we can use the thin lens equation to find the image distance for the arrow located at the 6 cm mark:

1/7 = 1/(6 - 7) + 1/di

di = -7 cm

The negative sign indicates that the image is inverted.

We can also use the magnification equation to find the magnification of the image:

m = -di/do = -(-7)/(-6) = 7/6

The positive magnification indicates that the image is upright.

Finally, we can use the image distance and magnification to determine the characteristics of the image. Since the image distance is negative, the image is virtual. Since the magnification is less than 1, the image is smaller.

Therefore, the best description of the image is upright, smaller, and virtual.

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Answer:

upright, smaller virtual

Explanation:

Before taking a personality test, Jackie sets her mind on growth. How might this affect her understanding of the test?

Choose two anSwers-
1.She will score high in the areas she chooses to.
2.She will respond based on what's best in her desired career path.
3. She will think of the results as an opportunity to find joy.
4. She will identify areas for self- development in her results. ​

Answers

Answer:

The two answers that are likely to be true are:

She will think of the results as an opportunity to find joy.

She will identify areas for self-development in her results.

By setting her mind on growth, Jackie is likely to approach the personality test with a positive and open mindset. This can lead to the following outcomes:

She will think of the results as an opportunity to find joy: Jackie may view the test results as a chance to discover aspects of her personality that bring her joy and satisfaction. She might focus on finding strengths and positive qualities that can contribute to her personal and professional growth.

She will identify areas for self-development in her results: Rather than viewing the test results as fixed labels or limitations, Jackie is likely to see them as valuable feedback for self-improvement. She may actively seek out areas where she can further develop her skills, knowledge, and personality traits to enhance her personal and career growth.

It's important to note that the other options listed in the question (1. She will score high in the areas she chooses to and 2. She will respond based on what's best in her desired career path) are not directly related to having a growth mindset. They suggest a more biased or strategic approach to the test, which may not align with the concept of growth and self-improvement.

Kinetic energy depends only on a system's_
Select all that apply
>
acceleration
height
mass
2
speed
volume

Answers

The answer for the I believe to be mass and speed

Answer: mass and speed

Explanation: Remember kinetic energy equals 1/2mv^2 so it is dependent on mass and velocity which is speed.

1 Consider a ring, sphere and Solidey clinder all with the same mass. They are all held at the top of the inclined Plane which is at 20° to the horizontal. the top of the inclined Plane is 1m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the abjects roll with out slipping and that they are all made from the same material. Assume the coefficient of static friction bin the objects and the plane is 0.3.
A) which shapes have the greater moment of inertia ?
B) workout what order they would get to the bottom of the Slope!
C ) determine the linear acceleration(a)
D) calculate the tangential (linear) Veloci ty of each shapes
E) How long will it take each shape to reach the bottom of the Slope ?
I give you 100 coin please help me


-​

Answers

A) The solid cylinder has the greatest moment of inertia, followed by the ring, and then the sphere.

B) The solid cylinder will reach the bottom of the slope first, followed by the sphere, and then the ring.

C) The linear acceleration of the objects can be calculated using the following formula:

a = g * sin(θ) / (1 + I / mr^2)

where g is the acceleration due to gravity, θ is the angle of the incline, I is the moment of inertia, m is the mass, and r is the radius of the object.

Plugging in the numbers, we get:

a_ring = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 1^2) = 1.09 m/s^2
a_sphere = 9.8 m/s^2 * sin(20°) / (1 + 2 / 1^2) = 0.84 m/s^2
a_cylinder = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 0.5^2) = 1.47 m/s^2

Therefore, the linear accelerations are a_ring = 1.09 m/s^2, a_sphere = 0.84 m/s^2, and a_cylinder = 1.47 m/s^2.

D) The tangential velocity of each object can be calculated using the following formula:

v = a * r

where a is the linear acceleration, and r is the radius of the object.

Plugging in the numbers, we get:

v_ring = 1.09 m/s^2 * 0.5 m = 0.55 m/s
v_sphere = 0.84 m/s^2 * 1 m = 0.84 m/s
v_cylinder = 1.47 m/s^2 * 0.5 m = 0.74 m/s

Therefore, the tangential velocities are v_ring = 0.55 m/s, v_sphere = 0.84 m/s, and v_cylinder = 0.74 m/s.

E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:

t = sqrt(2 * d / a)

where d is the distance traveled, and a is the linear acceleration.

Plugging in the numbers


A) The solid cylinder has the greatest moment of inertia.
B) The order in which the objects would reach the bottom of the slope is: sphere, cylinder, and ring.
C) The linear acceleration of each object is the same and is equal to 0.98 m/s^2.
D) The tangential velocity of the sphere, cylinder, and ring are 2.78 m/s, 3.53 m/s, and 4.24 m/s, respectively.
E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:

time = square root(2h / g)

where h is the height of the slope (1m) and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the numbers, we get:

time for sphere = 0.45 s
time for cylinder = 0.51 s
time for ring = 0.57 s

Therefore, the sphere would reach the bottom first, followed by the cylinder, and then the ring.

What is the difference between analog signal and digital signal. Explained in essay form.

Answers

A continuous signal that changes in frequency and amplitude over time is referred to as an analogue signal. A digital signal one can only take on a small number of values and is commonly represented by 0s and 1s.

Being able to take on any value within a continuous range of values makes it the perfect choice for simulating physical phenomena like temperature, sound, and light. Analogue signals include things like radio waves, vinyl records, and conventional telephone networks. Modern communication and computing systems use digital signals instead of analogue ones because they can be transferred and processed more effectively and are less prone to noise. Computer networks and digital cameras are few examples of digital signals.

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I don’t understand this pls help

Answers

Just try understand it

what is the unit of time not based on a heavenly body

Answers

A week. Hope this is helpful!

Which of the following is the dimension of moment of inertia? (a) ML2 (b) MLT-1 (c) L2T 2 (d) L T-1

Answers

The dimension of the moment of inertia is [tex]ML^2[/tex]. Option A.

What is the moment of inertia?

The moment of inertia represents the resistance of a body to rotational motion. It depends on the body's mass and the distribution of that mass around the axis of rotation.

The formula for the moment of inertia involves mass and distance and is expressed as:

I = mr^2

where

m is the mass of the bodyr is the distance from the axis of rotation.

The dimension of mass is represented by M, and the dimension of distance is represented by L. Therefore, the dimension of moment of inertia is:

Moment of inertia = mass x distance^2 = M x L^2 = [tex]ML^2[/tex].

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calculate the electric field at the centre of a square 60cm on a side if one corneris occupied by a +45uC charge and the other three corners are occupied by -31uC charge

Answers

Answer:

E_total = 1.39 x 10^5 N/C

Explanation:

We can calculate the electric field at the center of the square using the principle of superposition. We will treat each charge as a point charge and calculate the electric field due to each charge, and then add them up vectorially.

Let's assume that the positive charge is located at the bottom-left corner of the square, and the negative charges are located at the other three corners. The distance from the charges to the center of the square is:

r = 60 cm / 2 = 30 cm

The electric field due to a point charge is given by Coulomb's law:

E = k*q / r^2

where k is the Coulomb constant, q is the charge, and r is the distance between the charge and the point where we want to calculate the electric field.

For the positive charge, we have:

E1 = k*q1 / r^2

E1 = (9 x 10^9 Nm^2/C^2)(45 x 10^-6 C) / (0.3 m)^2

E1 = 4.50 x 10^5 N/C

The electric field due to the negative charges is:

E2 = k*q2 / r^2

E2 = (9 x 10^9 Nm^2/C^2)(-31 x 10^-6 C) / (0.3 m)^2

E2 = -3.11 x 10^5 N/C

Since the negative charges are at opposite corners, the direction of the electric field due to each charge cancels out, so we only need to consider the magnitude of the electric field due to the negative charges.

The total electric field at the center of the square is:

E_total = E1 + E2

E_total = 4.50 x 10^5 N/C - 3.11 x 10^5 N/C

E_total = 1.39 x 10^5 N/C

The direction of the electric field at the center of the square is the direction of the net electric field due to the two charges, which is from the positive charge to the negative charges. This direction is along the diagonal of the square, at a 45 degree angle with respect to the sides of the square.

What is the definition of physical activity?
A.
a movement that stimulates your respiratory system
B.
a movement that causes perspiration
C.
a movement that results in the body’s use of energy
D.
a movement that requires little effort

Answers

Answer: The answer is C

Explanation: because I got it correct

C. A movement that results in the body's use of energy.

WHO has defined physical activity as any bodily movement that requires expenditure of energy.

Physical activity includes both exercise as well as integrated activities of one's daily routine.

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What is the current theory about the formation of the solar system?

Responses

About 14 billion years ago, several supernova events scattered all the known elements throughout the galaxy. The magnetic elements were attracted to each other and formed the early celestial bodies that eventually became the planets of the solar system.

About 14 billion years ago, several supernova events scattered all the known elements throughout the galaxy. The magnetic elements were attracted to each other and formed the early celestial bodies that eventually became the planets of the solar system.

A big bang occurred in the solar system as a result of a fusion reaction. All the matter in the solar system that had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies of the solar system were formed.

A big bang occurred in the solar system as a result of a fusion reaction. All the matter in the solar system that had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies of the solar system were formed.

The area of the universe that was to become the solar system went through a period of vast expansion as a result of rapid radioactive decay that left behind clouds of dust and gases. The excess clouds and gases were used to form the various parts of the solar system.

The area of the universe that was to become the solar system went through a period of vast expansion as a result of rapid radioactive decay that left behind clouds of dust and gases. The excess clouds and gases were used to form the various parts of the solar system.

The solar system began as a cloud of dust and gas that condensed, forming a bulging middle and an outer disk. The bulging middle of the cloud became the sun, and the rest of the dust and gas formed the planets, orbiting the sun in the same plane.

Answers

The current theory about the formation of the solar system is that it began as a cloud of dust and gas, known as the solar nebula which is the last response.

What happened to the nebula?

The nebula collapsed under its own gravity, forming a spinning disk with a bulging middle that became the sun. The remaining dust and gas in the disk coalesced into small bodies, which collided and stuck together, forming the planets.

This process, known as accretion, resulted in the four inner planets, which are small and rocky, and the four outer planets, which are large and gas-rich.

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Will the placement of the continents on Earth look different in 100 million years than today?

Answers

Answer:

Yes

Explanation:

Continents is constantly moving, but at very slow rate.

This is due to the movement of the tectonic plate underneath the earth surface.

On average they move about 10 cm per year.

So in 100 million, they will move 10,000 km.

Of course, how the continents looks 100 million years from now will be very different than today.

A is a sphere that is traveling with velocity of (3,7)m/s and had a mass of 5 kg .it collide with sphere B and both particle move together with velocity of (1,4)m/s after the collision. Sphere B has a mass of 4 kg . Find the velocity of B before the collision

Answers

The velocity of sphere B is -1.475 m/s. Which is in opposite direction to the direction of sphere A.

What is velocity?

Velocity is the rate of change of displacement.

To calculate the velocity of sphere B before collision, we use the formula below

Formula:

u = [V(M+m)-Mu']/m................... Equation 1

Where:

u = Velocity of sphere B before collisionV = Velocity of both particles after collisionM = Mass of sphere Am = Mass of sphereu' = Velocity of sphere B before collision

From the question,

Given:

V = 1.4 m/sM = 5 kgm = 4 kgu' = 3.7 m/s

Substitute these values into equation 1

u = [1.4(5+4)-(5×3.7)]/4u = (12.6-18.5)/4u = -5.9/4u = -1.475

Hence, the velocity of sphere B is -1.475 m/s.

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Which word best completes the analogy?

Health-related fitness is to health as skill-related fitness is to _____.
A.
exercise
B.
wellness
C.
performance
D.
fitness

Answers

The word that best completes the analogy Health-related fitness is to health as skill-related fitness is to is option C which is performance.

Performance explained.

In health and fitness, performance refers to an individual's ability to carry out physical activities or exercises with efficiency and effectiveness, which are key components of skill-related fitness. Good performance in health and fitness can be measured by various parameters, such as strength, endurance, flexibility, balance, coordination, and speed. For example, a good performance in running can be measured by the ability to run a certain distance in a shorter time or maintaining a specific pace for a longer time. Similarly, a good performance in weightlifting can be measured by the ability to lift a certain weight with proper form and technique.

In general, good performance in health and fitness is associated with better overall physical health, reduced risk of chronic diseases, and improved quality of life.

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Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.
please help me I give you 50 coins​

Answers

The center of mass of the system can be found by taking the weighted average of the positions of the individual masses.

Let's call the mass at point A M1, the mass at point B M2, the mass at point C M3, and the mass at point D M4.

The x-coordinate of the center of mass is given by:
x_cm = (M1*x1 + M2*x2 + M3*x3 + M4*x4) / (M1 + M2 + M3 + M4)

The y-coordinate of the center of mass is given by:
y_cm = (M1*y1 + M2*y2 + M3*y3 + M4*y4) / (M1 + M2 + M3 + M4)

We know that the distance between any two adjacent corners of the square is 2cm. Therefore, we can say that the coordinates of the four masses are:
M1 = 2kg at (0,0)
M2 = 4kg at (2,0)
M3 = 6kg at (2,2)
M4 = 8kg at (0,2)

Substituting these values into the equations above, we get:
x_cm = (2*0 + 4*2 + 6*2 + 8*0) / (2 + 4 + 6 + 8) = 2
y_cm = (2*0 + 4*0 + 6*2 + 8*2) / (2 + 4 + 6 + 8) = 2

Therefore, the center of mass of the system is located at a distance of 2cm from corner A along the x-axis and 2cm from corner A along the y-axis.

which of the following best describe the weather conditions at location B

Answers

The  best description on  the weather conditions at location  A and B is  :It is warmer at position A than at position B.

Therefore Option (D) is correct

What is meant by weather conditions?

Weather condition is  described as  the regional weather during a defined time period from one up to several weeks describing typical weather phenomena, such as a series of thunderstorm in hot summer, foggy month in autumn or other weather conditions which are typical for a specific region and/or season.

From the given image, a warm front is being shown. Here, the region comprising letter A is the warm zone and the region above the front comprising the letter B indicates a cold zone. The position A forms a low-pressure zone, so it is comparatively warmer than the position B.

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#complete question:

Which of the following statements best describes the weather conditions at positions A and B shown below?

A. It is raining at position A and clear at position B.

B. It is cloudy at position A and clear at position B.

C. It is cooler at position A than at position B.

D. It is warmer at position A than at position B.

1. Choose one from the following countries:
o United States
o United Kingdom
o Australia
o Nepal
o Russia
o Spain
o India
2. Then make research of some laws supporting sexuality and gender in your
chosen country.

Answers

uk

because they have a Sexuality law

The pressure difference between two locations is 0.005 Torr .Which one of the following barometers is preferred to measure the small pressures accurately? (knowing that: Density of mercury = 13600 kg/m³, density water = 1000 kg/m³, density of oil = 800 kg/m³
A-Mercuric barometer
B-Oil-water barometer
C-Water barometer
D-Oil barometer

Answers

Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.

A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.

The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.

To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:

Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.

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Question 11 of 25
In the circuit below, resistors R₁ and R₂ are in parallel. What is the equivalent
1
1
resistance? (R₁ = 30 22,R₂ = 20 2) (
A
+A)
Ptot R₁
S₁
S₂
R₁
S₂ S
ww
R₂
1
R₂₂k

Answers

Answer:

60 ohms

Explanation:

To find the equivalent resistance of two resistors R₁ and R₂ in parallel, we can use the formula:

1/Req = 1/R₁ + 1/R₂

where Req is the equivalent resistance.

Substituting the values given, we get:

1/Req = 1/30 + 1/20

Simplifying, we get:

1/Req = 1/60

Multiplying both sides by Req, we get:

Req = 60 ohms

Therefore, the equivalent resistance of the two resistors R₁ and R₂ in parallel is 60 ohms.

b) A rocket initially moving at v0=3.5 km/s in space fires its engines. The initial mass of rocket is m0=200,000 kg and the final mass of the rocket is m=20,000 kg. If the exhaust velocity is ve=5.2 km/s, calculate the final speed in km/s.

Answers

The final speed of the rocket is -11.8 km/s.

What is the final speed of the rocket?

The final speed of the rocket is calculated by applying the principle of conservation of linear momentum.

m0v0 = mv + (m0 - m)ve

where;

m0 is initial massv0 is the initial speedve is exhaust velocity

The final speed of the rocket is calculated as;

200,000 kg  x 3.5 km/s = 20,000 kg x v + (200,000 kg - 20,000 kg) x 5.2 km/s

700,000 = 20,000v + 936,000

v = -236,000/20,000

v = -11.8 km/s

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A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.

Express ALL parts with appropriate units

Answers

A. Δx = 384,400 km (distance between Earth and Moon)

How to solve

B. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s

C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)

D, E, F. Cannot answer without specified primed frame.

G. Δx for laser beam = 384,400 km

H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s

I. s² for laser beam ≈ 0 km² (light-like separated events)



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Which of the following is not among the uses of dimensional analysis? (a) determination of the Numerical constant (b) to convert one system of unit to another (c) to change the units of derived quantities (d) to test the correctness of an equation

Answers

To convert one system of unit to another  of derived quantities is not a use of dimensional analysis.

What is dimensional analysis?

Checking for consistency in the dimensions on both sides of an equation entails looking at the dimensions of the physical quantities involved in a problem, such as length, mass, time, electric charge, and temperature.

The core tenet of dimensional analysis is that physical quantities, such as length, mass, and time, may be described in terms of their basic dimensions.

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All of the options listed are included in the uses of dimensional analysis.

What is dimensional analysis?

Dimensional analysis is a powerful tool used in physics to:

check the correctness of equations derive new equationsconvert units from one system to anotherdetermine numerical constants that relate physical quantities.

The dimensional analysis involves analyzing the dimensions of physical quantities and using them to establish relationships between them.

By using the principles of dimensional analysis, we can simplify complex physical problems and gain insights into the behavior of physical systems.

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Please answer the correct question and I will give you 50 points
1) Consider a ring, sphere and solid cyclinder all with the same mass. They are all held at the top of an inclined plane which is at 20° to the horizontal. The top of the inclined plane is 1 m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the objects roll without slipping and that they are all made from the same material. Assume the coefficient of static friction between the objects and plane to be 0.3.
A ) calculate the tangential (linear) Velocity of each shapes-
B) determine the linear acceleration(a)
C) which shapes have the greater moment of inertia ?
D) How long will it take each shape to reach the bottom of the Slope ?

E) workout what order they would get to the bottom of the Slope.


Answers

A) The tangential (linear) velocity of each shape is:

For the ring: v = rω = 2.41 m/s.

For the sphere: v = rω = 1.57 m/s.

For the solid cylinder: v = rω = 2.41 m/s.

B) The linear acceleration of each shape is:

For the ring: α = 2gsinθ/(3r(1 + 0.3) + 2R) = 1.191 m/s^2.

For the sphere: α = 2gsinθ/(5r(1 + 0.3)) = 1.176 m/s^2.

For the solid cylinder: α = 2gsinθ/(3r(1 + 0.3) + 2R) = 1.228 m/s^2.

C) The solid cylinder has the greatest moment of inertia.

D) The time taken for each shape to reach the bottom of the slope is:

For the ring: t = 0.576 s.

For the sphere: t = 0.197 s.

For the solid cylinder: t = 0.576 s.

E) The sphere will reach the bottom of the slope first, followed by the ring and the solid cylinder.

Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.

1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)

Answers

The initial common temperature of the water and copper is approximately 2.68°C.

To find the hidden typical temperature of the water and copper, we need to use the norm of protection of energy, which communicates that energy can't be made or obliterated, recently moved or changed beginning with one design then onto the following.

The force lost by the ice as it breaks up is identical to the power obtained by the water and the calorimeter. We can impart this using the recipe:

Q_ice = Q_water + Q_calorimeter

where Q_ice is the force lost by the ice, Q_water is the power procured by the water, and Q_calorimeter is the force gained by the calorimeter.

We can determine the power lost by the ice using the recipe:

Q_ice = m_ice * L_f

where m_ice is the mass of the ice and L_f is the force of blend of water, which is 333 J/g.

Q_ice = (10.0 g) * (333 J/g) = 3330 J

We can sort out the force obtained by the water using the condition:

Q_water = m_water * c * (T_f - T_i)

where m_water is the mass of the water, c is the specific power breaking point of water, which is 4.184 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.

Q_water = (300.0 g) * (4.184 J/g°C) * (18.0°C - T_i)

We can figure the force obtained by the calorimeter using the recipe:

Q_calorimeter = m_calorimeter * c_calorimeter * (T_f - T_i)

where m_calorimeter is the mass of the calorimeter, which is 200.0 g, c_calorimeter is the specific force breaking point of copper, which is 0.385 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.

Q_calorimeter = (200.0 g) * (0.385 J/g°C) * (18.0°C - T_i)

Subbing these circumstances into the norm of conservation of energy, we get:

m_ice * L_f = m_water * c * (T_f - T_i) + m_calorimeter * c_calorimeter * (T_f - T_i)

Tending to for T_i, we get:

T_i = T_f - [(m_ice * L_f)/(m_water * c + m_calorimeter * c_calorimeter)]

T_i = 18.0°C - [(10.0 g) * (333 J/g)/(300.0 g * 4.184 J/g°C + 200.0 g * 0.385 J/g°C)]

T_i = 2.68°C

As needs be, the basic ordinary temperature of the water and copper was 2.68°C (conveyed to three immense figures).

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1) Three masses hang about a 3 meter stick whose fulcrum is at
50cm. A mass of m1=60.0 kg hangs at the 90.0 cm mark, m2= 20.0 kg hangs at the 20.0 cm mark. Find the location of the mass, m3= 10 kg to obtain static equilibrium. If it is not possible to reach equilibrium, then select a new pivot point and draw a new diagram that will allow the system to reach static equilibrium with the same lever arms values as before for all masses.

Answers

The mass m3 should be placed 0.8 m away from the fulcrum to achieve static equilibrium.

Static equilibrium

To achieve static equilibrium, the net torque acting on the system must be zero. The torque is given by the product of the force and the lever arm. Taking the fulcrum as the reference point, we can write:

(m1)(g)(0.9 m - 0.5 m) + (m2)(g)(0.2 m - 0.5 m) + (m3)(g)(x - 0.5 m) = 0

where g is the acceleration due to gravity (9.81 m/s^2) and x is the distance of the mass m3 from the fulcrum.

Simplifying and solving for x, we get:

x = [(m1)(0.9 m - 0.5 m) + (m2)(0.2 m - 0.5 m)] / (m3) + 0.5 m

x = [((60.0 kg)(0.4 m) + (20.0 kg)(-0.3 m))] / (10.0 kg) + 0.5 m

x = 0.8 m

Therefore, the mass m3 should be placed 0.8 m away from the fulcrum to achieve static equilibrium.

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The graph shows how the speed of a car travelling in a straight line changes with time. Which section shows the largest acceleration? speed A B C D time​

Answers

The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.

This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.

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complete question not found in search engine.

graph
shows a variety of moving objects and how their distance is related to time what do these objects have in common

Answers

What is common among all the graphs is that they all show an object that is moving.

What is a graph?

In the distance time graph, we have the distance on the vertical axis and we have the time on the horizontal axis and the shape of the plots may differ depending on the nature of the motion of the objects.

Graphs of distance vs time help us to examine motion by showing how an object has moved over time. All objects shown on a distance vs. time graph are shifting positions over time, regardless of the graph's specific shape or slope, and the graph reveals information about the direction and speed of their motion.

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Two moles of helium gas initially at 268 K
and 0.51 atm are compressed isothermally to
1.5 atm. Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
answer in units m^3

Answers

The final volume of the gas is 1,515.24 m³.

What is the final volume of the gas?

The final volume of the gas is calculated by applying ideal gas law;

PV = nRT

Where;

P is the pressureV is the volumen is the number of molesR is the universal gas constantT is the temperature.

At a constant temperature, we will have the following equation;

P₁V₁ = P₂V₂

V₂ = (P₁V₁) / P₂

V₂ = (0.51 atm)(2 mol)(8.31451 J/K·mol)(268 K) / (1.5 atm)

V₂ = 1,515.24 m³

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A thin beam of light falls on mirror 1 as shown in the diagram below. four P.Q.Rands are placed in front of mirror 1 and mirror 2. Mirror 2 J|||||| RE Nanda wants to find out on which tikely box in the diagram in the beam to fall after reflecting off mirrov 1 and mirrov 2 List the steps that he should Follow in the correct order.​

Answers

The steps assume that the mirrors and boxes are arranged in a simple, two-dimensional configuration.

The steps to be followed

The steps to be followed are;

Determine the angle of incidence of the beam of light on mirror 1. This can be done by drawing a line perpendicular to the mirror at the point where the beam of light hits the mirror and measuring the angle between this line and the incident beam of light.

Use the law of reflection to determine the angle of reflection of the beam of light from mirror 1. This angle will be equal to the angle of incidence.

Use the properties of parallel lines and angles to determine the angle of incidence of the beam of light on mirror 2. This can be done by noting that mirror 2 is parallel to mirror 1 and that the angle of incidence of the beam of light on mirror 2 will be equal to the angle of reflection of the beam of light from mirror 1.

Use the law of reflection again to determine the angle of reflection of the beam of light from mirror 2. This angle will be equal to the angle of incidence of the beam of light on the likely box.

Use the properties of parallel lines and angles again to determine the angle of incidence of the beam of light on each of the boxes in the diagram. The box that has an angle of incidence equal to the angle of reflection of the beam of light from mirror 2 is the likely box where the beam of light will fall.

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