Answer:
Explanation:
b) Fg = W = mg = (104 kg)(9.8 m/s²) = 1019.2 N (weight of the box)
Ff = (coeff. friction)(N)
N = normal force = Fg = 1019.2 N
c) coeff. friction = Ff/N = 45 N/1019.2 N = 0.044
d) Fnet = 245 N - 45 N = 200 N
It's hard to draw a free body diagram with the available symbols, but here's a try at it. Just add a box between the arrows!
W
↓
Ff → ← Fapplied
↑
N
50 POINTS !!!
Three particles of mass 8 kg, 3 kg, and 7 kg are connected by rigid rods of
negligible mass lying along the y axis and are placed at 5 m, -2 m, and -6 m,
respectively as in the figure. The system rotates about the x axis with an angular
speed of 1.65 rad/s.
a) Find the moment of inertia about the x axis. Consider the
masses to be point particles.
b) Find the total rotational energy.
c) Find the linear speed of the top particle of mass 8 kg in the figure.
Answer:
a) I = 464 kg m², b) K = 631 .6 J, c) v = 8.25 m / s
Explanation:
a) the moment of inertia of point particles is
I = ∑ m_i r_i²
in this case
I = 8 5² + 3 (-2) ² + 7 (-6) ²
I = 464 kg m²
b) The kinetic energy is
K = ½ I w²
K = ½ 464 1.65²
K = 631 .6 J
c) linear and angular velocity are related
v = w r
v = 1.65 5
v = 8.25 m / s
How important do you think temperature, radiation, and geologic activity are to the habitability in general?
Answer:
Explanation:
All 3 are critical for habitability
A cannonball is launched with an initial speed of 20 m/s. Calculate the maximum height the ball could reach.
Answer:
During its trajectory the cannon ball will have kinetic and potential energy
E = KE + PE
The maximum value of PE will occur when the cannon ball was fired straight up - for other trajectories PE will be less because of translational KE
So E = M g h = 1/2 M v^2 for maximum height
h = v^2 / (2 * g) = 400 / (2 * 9.8) = 20.4 m
When a body is accelerated under water, some of the surrounding water is also accelerated. This makes the body appear to have a larger mass than it actually has. For a sphere at rest this added mass is equal to the mass of one half of the displaced water. Calculate the force necessary to accelerate a 10 kg, 300-mm-diameter sphere which is at rest under water at the acceleration rate of 10 m/s2 in the horizontal direction. Use H2O
Solution :
Mass of the sphere, m = 10 kg
Diameter, D = 300 mm = 0.3 m
Volume of the sphere is [tex]$V=\frac{4}{3} \pi \left(\frac{0.3}{2}\right)^3$[/tex]
[tex]$V=0.01414 \ m^3$[/tex]
So the volume of displaced water, [tex]$V_w=V = 0.01414 \ m^3$[/tex]
Additional mass, [tex]$m_w = \frac{1}{2} \ \rho_w\times v_w$[/tex]
[tex]$=\frac{1}{2} \times 1000 \times 0.01414$[/tex]
[tex]$=7.0686 \ kg$[/tex]
So the total mass, [tex]$M = m_w+m$[/tex]
= 7.0686 + 10
= 17.0686
Force required, F = Ma
[tex]$F=17.0686 \times 10$[/tex]
= 170.686 N
The force that is necessary to accelerate when the acceleration rate of 10 m/s2 in the horizontal direction should be 170.686 N.
How to calculate the force?Since Mass of the sphere, m = 10 kg
Diameter, D = 300 mm = 0.3 m
Now volume of the sphere is
V = 4/π (diameter/3)^3
V = 4/3π(0.3/2)^3
= 0.01414m^3
Now the additional mass is
= 1/2* 1000 * volume
= 1/2 *1000*0.01414
= 7.0686
So, the total mass is
= Additional mass + force
= 7.0686 + 10
= 17.0686
Now the force is
= 17.0686 * 10
= 170.686
Hence, The force that is necessary to accelerate when the acceleration rate of 10 m/s2 in the horizontal direction should be 170.686 N.
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A 30-g bullet traveling horizontally at 300 m/s strikes a 1.0-kg block which is attached to a horizontal spring with a force constant of 2000 N/m and rests on a frictionless horizontal surface. The spring is on the far side of the block and aligned with the direction of travel of the bullet. The bullet becomes embedded in the block and, as a result of the impact, and the block slides against the spring. How far is the spring compressed before it reverses its direction of travel
Answer:
Explanation:
Using law of conservation of momentum during collision , velocity after collision can be found .
common velocity V = m v / ( m + M )
= .030 x 300 / ( .030 + 1 )
V= 8.7378 m /s
The kinetic energy of the bullet and block will be stored as elastic energy
1/2 ( M + m ) V² = 1/2 k A² where k is force constant and A is maximum compression in the spring .
( M + m ) V² = k A²
1.030 x 8.7378² = 2000 x A²
A² = .0393
A= .1982 m .
= 19.82 cm
A satellite is a large distance from a planet, and the gravitational force from the planet is the only significant force exerted on the satellite. The satellite begins falling toward the planet, eventually colliding with the surface of the planet. As the satellite falls, what claims is correct about how the force that the planet exerts on the satellite Fps changes and how the force that the satellite exerts on the planet Fsp changes, if at all? What reasoning supports this claim?
Answer:
The answer is "Option A".
Explanation:
Please find the complete question in the attached file.
The strength is equal due to the third law of Newton, and [tex]Fsp = Fps = \frac{Gmsmp}{r^2}\[/tex], therefore the force increases with decreased separation r.
The momentum of an object is determined to be 7.2×10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g
The mass of the moving item is referred to as momentum. There is magnitude and direction to momentum. The object has a momentum of 7.2 g-m/s.
What is the momentum of an object?Momentum is a vector quantity that is created during motion by an object's mass and velocity. Thus, momentum will be expressed in units of kg-m/s.
Considering that item has motion. Likewise, 1 kilogram equals 1000 g. Therefore, the momentum will transform into units of grams when we enter the value of 1 kg.
Momentum = 7.2 x 10⁻³ 1000g-m/s
Momentum = 7.2 g-m/s.
Thus, we may deduce that the object's momentum, measured in grams per second, is 7.2 g-m/s.
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The type of heat transfer responsible for your computer leaving your desk very hot after you've used it for awhile?
Answer:
Conduction
Explanation:
Conduction is a process whereby heat is transfer through solid state.
how to prepare a trading stock account
Answer:
Opening stock details of raw material, semi-finished goods and finished goods.
Closing stock details of raw material, semi-finished goods, and finished goods.
Total purchases of goods fewer Purchase Returns.
Total sales of goods fewer Sales Returns.
Two equally charged pith ball are 3cm apart in air and repel each other with a force of 4X105N - Comput the charge on each bali-
TheThe charge applied on each ball is 2 X 10∧-9 C.
Define force ?
An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The pitch balls repent each other with force
F= 4 X 10^-5N
Let the charge on each ball be Q.
4 X 10^-5= k(Q)(Q) / (3 X 10^-2)^2
Q^2= 4*10^-5X 9*10^-4 / 9*10^9
Q^2 = 4 X 10^-18
Q= √4 X 10^-18
Q = 2 X 10^-9 C.
Therefore, the charge on each ball is 2X10^-9C.
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Each ball has been charged with 2 X 10⁹ C. When a product is held in electrostatic energy, its properties referred to as electric discharge allows it to feel force.
What is force?A force can compel a heavily armored item to increase or modify overall velocity. A push or a pull is a simple and effective method to explain force. That's because a force has both magnitude and direction it is a dimensionless number.
The pitch balls repent each other with force
F = 4 X 10⁻⁵N
4 X 10⁻⁵ = k(Q)(Q) / (3 X 10⁻²)²
⇒ Q² = 4 × 10⁻⁵ X 9 × 10⁻⁴ / 9 × 10⁹
⇒ Q² = 4 X 10⁻¹⁸
⇒ Q = √4 X 10⁻¹⁸
⇒ Q = 2 X 10⁻⁹ C.
Therefore, the charge on each ball is 2 X 10⁻⁹C.
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How far from the earth must a body be along a line toward the sun so that the sun’s
gravitational pull balances the earth’s? The sun is 9.3 × 107 miles away and its mass is
3.24 × 105 Me.
Answer:
r = 1.63×10^5 mi
Explanation:
Let r = distance of object from earth
Rs = distance between earth and sun
Ms = mass of the sun
= 3.24×10^5 Me (Me = mass of earth)
At a distance R from earth, the force Fs exerted by the sun on the object is equal to the force Fe exerted by the earth on the object. Using Newton's universal law of gravitation,
Fs = Fe
GmMs/(Rs - r)^2 = GmMe/r^2
This simplifies to
Ms/(Rs - r)^2 = Me/r^2
(3.24×10^5 Me)/(Rs - r)^2 = Me/r^2
Taking the reciprocal and then its square root, this simplifies further to
Rs - r = (569.2)r ----> Rs = 570.2r
or
r = Rs/570.2 = (9.3×10^7 mi)/570.2
= 1.63×10^5 mi
The slope of a velocity time graph will give___
Answer:
THE ANSWER IS ( acceleration of the object )8. Jane rides a sled down a slope of angle θ at constant speed v. Determine the coefficient of kinetic friction between the sled and the slope. Neglect air resistance.
(A) μ=gsinθ (B) μ=mgcosθ (C) μ=tanθ (D) μ=gcosθ
Answer:ssssw
Explanation:
What is the speed of a transverse wave in a rope of length 2 meters and mass 0.06
kg under a tension of 500 nt?
Answer:
16.3 wave speed.
Explanation:
A wire with a current of 5.2 A is at an angle of 45° relative to a magnetic field of 0.87 T. What is the force exerted on a 1.2 m length of the wire
Answer:
F = I L X B = I L B sin theta
F = 5.2 * 1.2 * .87 sin 45 = 3.84 N in the direction of (L X B)
Note: L and B must be at right angles for F = I L B
Which would help you perform a basketball skill well with
speed?
True or False? 13. All living things are made of cells 14. All cells have DNA within their nucleus 15. The cell is the basic unit of life in all organisms 16. All cells in a living thing are similar in structure or function 17. Cells must develop from other cells
Answer:
1: True
2: False
3: True
4: False
5: True
What is the meaning of the density of states function?
Ans-The density of states function describes the number of states that are available in a system and is essential for determining the carrier concentrations and energy distributions of carriers within a semiconductor.
Answer:
density equal to mass upon volume
simple definition
True or False question! ⬇⬇ Will give BRAINLIEST!
No matter the medium, light will always bend at the same angle when it passes from one medium to a different medium.
-True
-False
Answer:
the answer can be probably true since light can be refracted
Which situation would deplete freshwater?
Answer:
If freshwater consumption was greater than freshwater renewal.
Explanation:
Similar to another Brainly answer :O
state the property of plastic that allows it to become electrostatically charged
(please answers ty)
Answer:
when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.
define area and give its SI unit
Answer:
area is the space bounded by certain lines, the SI unit of area is m²
area of rectangle =l×w×h
square=l²
Which of the following correctly describes the order of skin layers from the inside to the outside of the body?
A. dermis, epidermis, hypodermis
B. hypodermis, dermis, epidermis
C. epidermis, hypodermis, dermis
D. hypodermis, epidermis, dermis
Answer:
it is a
Explanation:
dermis,epidermis,hypodermis
Answer:
B. hypodermis, dermis, epidermis
this is because it is inside to outside
hypodermis is deeper tissue, dermis is beneath epidermis, and epidermis is the outermost layer
What is electronic dispersion theory?
Dispersion in wave theory is the phenomena where a wave's phase velocity changes depending on its frequency. The article can explore different definitions. This is the typical definition for dispersion (waves).
When sinusoidal waves with various wavelengths propagate at various speeds, a wave packet with mixed wavelengths has a tendency to disperse in space. Dispersion in wave theory is the phenomena where a wave's phase velocity changes depending on its frequency.
The article can explore different definitions. This is the typical definition for dispersion (waves).
A full set of approximate solutions to the one-electron Schrödinger equation are found in a three-dimensional atomic lattice that is randomly filled with atoms of different kinds and has, on average, the periodicity of a Bloch wave.
Equations are provided that enable the calculation of each wave's energy, average behavior, absent a phase factor, close to any sort of atom, and damping parameter.
A comparison is made between a periodic lattice with a complicated, energy-dependent potential and a random A-B lattice. The dispersion relation of the system is obtained by solving the eigenvalue problem in this potential using any of the established techniques for periodic potentials.
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A man drags a 10.0 kg bag of mulch at a constant speed applying a 22.5 N force at a 32-degree angle. What is the friction force acting on the bag?
The
friction
force acting on the bag is 4.36µ.
What is friction force?
The
force
preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
Given,
Force =F=22.5 n
Mass=m= 10 kg
mu=µ=?
(1N= 1kg m/s²)
Gravitational force =g= 9.81 m/s²
As we know,
F= µ*m*g
µ= m*g/F
= 10*9.81/ 22.5
µ= 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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The bag is subject to a friction force of 4.36. A man applies a 22.5 N force at a 32° angle while dragging a 10.0 kilogram bag of mulch at a steady speed.
How much friction is there?Friction refers to the force that resists hard surface, fluid layering, and materials ingredients from gliding past one another. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.
Force = 22.5 N
Mass = 10 kg
⇒ mu = µ (1N= 1kg m/s²)
⇒ g = 9.81 m/s²
As we know, F= µ × m × g
⇒ µ = (m × g)/F
⇒ (10 × 9.81)/ 22.5
⇒ µ = 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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A single movable pulley is used to lift 4000N load to the height of 50 cm. If the efficiency of the pulley is 75%, Calculate effort distance,effort applied,output work and mechanical advantage.
Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:
Effort Distance = 50 cm
Effort Applied = 5333.33 N
Output work = 2000 J
Mechanical Advantage = 0.75.
When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.
Load (output force) = 4000 N
Height lifted = 50 cm = 0.5 m
Efficiency of the pulley = 75%
Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:
Effort applied (input force) = Load ÷ Efficiency
= 4000 N ÷ 0.75
= 5333.33 N
Output work = Load x Height lifted
= 4000 N x 0.5 m
= 2000 J
Effort distance = Height lifted
= 50 cm
Mechanical advantage = Load ÷ Effort applied
= 4000 N ÷ 5333.33 N
= 0.75
It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.
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Which of the following is a way to make magnets?
heating
freezing
pressure
heating or pressing but heating is most appropriate, so the answer is heating.
Three point charges q1 = +2 μC, q2 = −3 μC, and q3 = +4 μC are located at the corners of a right angle triangle as shown below. Find the magnitude and direction of the resultant force on q3.
Answer:
Explanation:
4
The magnitude and direction of the resultant force on q3 is;
F_net = 32.2 N in the direction of q3
We are given;
q1 = +2 μC = 2 × 10^(-6) C
q2 = -3 μC = -3 × 10^(-6) C
q3 = +4 μC = 4 × 10^(-6) C
Now,from the given image, charges q1 and q2 attract charge q3.
Formula for force on a charge is;
F = (kq1 * q2)/r²
Where;
k = 9 × 10^(9) N.m²/C²
Thus;
F_y = kq1*q3/(r1)²
We have;
q1 = 2 × 10^(-6) C
r1 = 5 cm = 0.05 m
q3 = 4 × 10^(-6) C
Thus;
F_y = (9 × 10^(9) × 2 × 10^(-6) × 4 × 10^(-6))/(0.05^(2))
F_y = 28.8 N
Similarly;
F_x = kq2*q3/(r2)²
r2 = 5/(tan 30)
r2 = 8.66 cm = 0.0866 m
F_x = (9 × 10^(9) × -3 × 10^(-6) × 4 × 10^(-6))/(0.0866^(2))
F_x = -14.4 N
Thus, magnitude of resultant force is;
F_net = √((28.8)² + (-14.4)²)
F_net = √1,036.8
F_net = 32.2 N
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The planet Mars has a mass that is 0.11 times Earth’s mass and a radius that is
0.54 times Earth’s radius. a) How much would a 60.0-kg astronaut weigh if
she were to stand on the surface of Mars?
Check the attached image for the question~
Answer:
put the full thin g
Explanation: