Answer:
5/15 is the probability of choosing a red marble from the box.
Step-by-step explanation:
We know that,
There are 5 red marbles and 10 green marbles in the box.
Divide the number of events by the number of possible outcomes. This will give us the probability.
P(red marble) = P(5)
Possible outcomes
5 red, 10 green -> 15 possibilities
Probability = [tex]\frac{5}{15}[/tex]
Please leave a 'thanks' if this helped!
The required probability of drawing a red marble the 6th time is 1/2.
Given that,
A box contains 10 red marbles and 10 green marbles.
Sampling at random from this box five times without replacement, you have drawn a red marble all five times.
Without replacing any of the marbles.
We have to determine,
What is the probability of drawing a red marble the 6th time?
According to the question,
There are 10 red marbles and 10 green marbles,
The initial condition is to the same state at every step, so the probability to get a red marble is the same in each sampling and is equal to the ratio of the number of red marbles to the total number of samples.
Therefore,
The probability of drawing a red marble the 6th time is,
[tex]P = \dfrac{10}{10+10}\\\\P = \dfrac{10}{20}\\\\P = \dfrac{1}{2}[/tex]
Hence, The required probability of drawing a red marble the 6th time is 1/2.
To know more about Probability click the link given below.
https://brainly.com/question/14210034
What is the value of the expression
below?
675 - (15 - 12)³ ÷ 3
A 216
C 666
B 224
D 678
Plz help
Answer:
675 – (15-12) ³+3
675-3³ +3
675-27+3
651
Step-by-step explanation:
The value of the given expression is 666 which is the correct answer that would be an option (C).
What is the PEMDAS rule?PEMDAS rule states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.
We have been given the expression below as:
675 – (15-12)³ ÷ 3
Using the PEMDAS rule to determine the evaluation of the given expression
⇒ 675 – (15-12)³ ÷ 3
Apply the subtraction operation,
⇒ 675 - (3)³ ÷ 3
⇒ 675 - 27 ÷ 3
⇒ 675 - 27 / 3
Apply the division operation,
⇒ 675 - 9
Apply the subtraction operation,
⇒ 666
Therefore, the value of the given expression would be 666,
Learn more about the PEMDAS rule here :
https://brainly.com/question/20876480
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Graph y=0.4x............................
Answer:
Look at the image below
The Venn diagram shows the results of two events resulting from rolling a number cube.
Answer:
Option B.
Step-by-step explanation:
From the given venn diagram it is clear that
[tex]A={1,2}[/tex]
[tex]B={1,2,3,4,5,6}[/tex]
[tex]A\cap B={1,2}[/tex]
Since the intersection of A and B is non-empty, therefore by conditional probability
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]
[tex]P(B|A)\cdot P(A)=P(A\cap B)[/tex]
[tex]P(A\cap B)=P(B|A)\cdot P(A)[/tex]
Therefore, the correct option is B.
PLEASE HELP!!
Factor the polynomial [tex]x^2+6x+5[/tex]. Your answer can be written as [tex](x+A)(x+B)[/tex] where A
Step-by-step explanation:
[tex]a + b = 6[/tex]
[tex]ab = 1 \times 5 = 5[/tex]
[tex]a = 1 \: \: \: \: \: \: \: \: b = 5[/tex]
[tex]( {x}^{2} + x) + (5x + 5)[/tex]
[tex]x(x + 1) + 5(x + 1)[/tex]
[tex](x + 1)(x + 5)[/tex]
Hope this is correct and helpful
HAVE A GOOD DAY!
According to the graph, what is the domain and range of the function?
Answer:
if its according to the graph but not according to the function then
domain = {x:-4<x<8}
range = {y:y<16}
Identify the two tables which represent quadratic relationships
Answer:
Option (4) and Option (5)
Step-by-step explanation:
By calculating the second difference, if the second difference in a table is equal, table will represent the quadratic relationship.
In the given option, we analyze that table given in Option (4) will represent the quadratic relationship.
x y Ist difference [tex](y_2-y_1)[/tex] IInd difference
0 4 - -
1 -4 -4 - (4) = -8 -
2 -4 -4 - (-4) = 0 0 - (-8) = 8
3 4 4 - (-4) = 8 8 - 0 = 8
Second difference of the terms in y are the same as 8.
Therefore, table of Option (4) represents the quadratic relationship.
Similarly, in Option (5) we will calculate the second difference of y terms.
x y Ist difference IInd difference
0 -4 - -
1 -8 -8 - (-4) = -4 -
2 -10 -10 - (-8) = -2 -2 - (-4) = 2
3 -10 -10 - (-10) = 0 0 - (-2) = 2
Here the second difference is same as 2.
Therefore, table of Option (5) will represent the quadratic relationship.
Answer:
Option 5 is wrong
Step-by-step explanation:
Please give me correct answer and fast answer it if know answer only
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:
[tex]\frac{\sin(A)}{a}=\frac{\sin(B)}{b} =\frac{\sin(C)}{c}[/tex]
Replacing them with the respective variables, we have:
[tex]\frac{\sin(S)}{s} =\frac{\sin(T)}{t} =\frac{\sin(R)}{r}[/tex]
Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for t. Ignore the third term:
[tex]\frac{\sin(20)}{s}=\frac{\\sin(17)}{5}[/tex]
Solve for s, the unknown side. Cross multiply:
[tex]\frac{\sin(20)}{s}=\frac{\sin(17)}{5}\\5\sin(20)=s\sin(17)\\s=\frac{5\sin(20)}{\sin(17)} \\s\approx5.8491\approx5.8[/tex]
Simplifying Rational Expressions: I need answers for both 7 and 8 below. Answers for just one or the other is also fine.
Answer:
1. Option A 2. Option DStep by step explanation
1. [tex] \frac{1}{1 - x} + \frac{x}{ {x}^{2} - 1} [/tex]
Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex] to rewrite the fractions
[tex] - \frac{1}{x - 1} + \frac{x}{(x - 1)(x + 1)} [/tex]
Write all numerators above the Least Common Denominator ( X - 1 ) ( X + 1 )
[tex] \frac{ - (x + 1) + x}{(x - 1)(x + 1)} [/tex]
When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression
[tex] \frac{ - x - 1 + x}{(x - 1)(x + 1)} [/tex]
Using [tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex] , simplify the product
[tex] \frac{ - x - 1 + x}{ {x}^{2} - 1 } [/tex]
Since two opposites add up to zero, remove them from the expression
[tex] \frac{ - 1}{ {x}^{2} - 1} [/tex]
So, Option A is the right option.
___________________________________
2.
[tex] \frac{ {x}^{2} - x - 12}{ {x}^{2} - 16} - \frac{1 - 2x}{x + 4} [/tex]
Write - X as a difference
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{ {x}^{2} - 16 } - \frac{1 - 2x}{x + 4} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor the expression
[tex] \frac{x(x + 3) - 4(x + 3)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor out X+3 from the expression
[tex] \frac{(x + 3)(x - 4)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Reduce the fraction with x-4
[tex] \frac{x + 3}{x + 4} - \frac{1 - 2x}{x + 4} [/tex]
Write all the numerators above the common denominator
[tex] \frac{x + 3 - ( 1- 2x)}{x + 4} [/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \frac{x + 3 - 1 + 2x}{x + 4} [/tex]
Collect like terms
[tex] \frac{3x + 3 - 1}{x + 4} [/tex]
Subtract the numbers
[tex] \frac{3x + 2}{x + 4} [/tex]
Undefined at,
X + 4 = 0
Move constant to R.H.S and change its sign
[tex]x = 0 - 4[/tex]
Calculate
[tex]x = - 4[/tex]
So, the answer is :
[tex] \frac{3x + 2}{x + 4} [/tex] , undefined at X = -4 and 4
Hope this helps..
Best regards!!
Katya has $20.00 to spend at her college bookstore, where all students receive a 20% discount . katya wants to purchase a copy of a book that normally sells for $22.50 plus 10% sales tax. how much dose the book sell for dose katya have enough money bc bc?
Answer:
Katie is correct. You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80
Step-by-step explanation:
Answer.. Plz!! 1rst one .BRAINLIEST!
Answer:
a) [tex]\boxed{4m^2+20m+25}[/tex]
b) [tex]\boxed{m^2-m+\frac{1}{4} }[/tex]
Step-by-step explanation:
a) [tex](2m+5)^2[/tex]
Using formula [tex](a+b)^2 = a^2+2ab+b^2[/tex]
=> [tex](2m)^2 + 2(2m)(5)+(5)^2[/tex]
=> [tex]4m^2+20m+25[/tex]
b) [tex](m-\frac{1}{2} )^2[/tex]
Using Formula [tex](a-b)^2 = a^2-2ab+b^2[/tex]
=> [tex](m)^2 - 2(m)(\frac{1}{2} ) + (\frac{1}{2} )^2[/tex]
=> [tex]m^2-m+\frac{1}{4}[/tex]
Answer:
a) [tex]\boxed{4m^2 + 20m + 25}[/tex]
b) [tex]\boxed{m^2 - m + \frac{1}{4} }[/tex]
Step-by-step explanation:
[tex](2m + 5)^2[/tex]
[tex](2m + 5) (2m + 5)[/tex]
Use FOIL method.
[tex]2m(2m + 5)+5(2m + 5)[/tex]
[tex]4m^2 + 10m + 10m + 25[/tex]
[tex]4m^2 + 20m + 25[/tex]
[tex](m - \frac{1}{2} )^2[/tex]
[tex](m- \frac{1}{2})(m- \frac{1}{2})[/tex]
Use FOIL method.
[tex]m(m- \frac{1}{2})- \frac{1}{2}(m- \frac{1}{2})[/tex]
[tex]m^2- \frac{1}{2} m- \frac{1}{2}m+ \frac{1}{4}[/tex]
[tex]m^2-m+ \frac{1}{4}[/tex]
A school counselor surveyed 90 randomly selected students about thé langages they speak. Of thé students surveyed 16 speak more than one langage fluently. Bases on thèse résults, How many of thé 1800 students at thé school can be expected to speak more than one langage fluently
Answer: 320 students
Step-by-step explanation:
From the question, we are informed that a school counselor surveyed 90 randomly selected students about thé langages they speak and thé students surveyed 16 speak more than one langage fluently. This means that 16/90 speak more than one language.
When 1800 students are surveyed, the number of students that can be expected to speak more than one langage fluently will be:
= 16/90 × 1800
= 16 × 20
= 320 students
You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that the first card is a Heart and the second card is a Spade. Write your answer as a decimal rounded to four places if necessary.
Answer:
The probability that the first card is a Heart and the second card is a Spade is 0.064.
Step-by-step explanation:
A standard deck of 52 cards is shuffled and two cards are drawn without replacement.
The denominations of the cards are as follows:
Spades (S) = 13
Hearts (H) = 13
Diamonds (D) = 13
Clubs (C) = 13
Compute the probability of selecting a Heart first as follows:
[tex]P(H)=\frac{13}{52}=0.25[/tex]
Compute the probability of selecting a Spade second as follows:
[tex]P(S)=\frac{13}{51}=0.255[/tex]
Since the two cards are selected without replacement the second draw is independent of the other.
Then the probability that the first card is a Heart and the second card is a Spade is:
[tex]P(1st\ H\cap 2nd\ S)=P(H)\times P(S)[/tex]
[tex]=0.25\times 0.255\\=0.06375\\\approx 0.064[/tex]
Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.
Problem PageQuestion Two pools are being filled with water. To start, the first pool contains 720 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 19.25 liters per minute. Water is being added to the second pool at a rate of 41.75 liters per minute. After how many minutes will the two pools have the same amount of water? minutes How much water will be in each pool when they have the same amount? liters
Answer:
After 32 minutes the two pools will have the same amount of water.
There will be 1,366 liters in each pool when they have the same amount of water.
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations:
The first pool contains 720 liters of water, and it’s being added at a rate of 19.25 liters per minute.
First Pool = 720 +19.25 m
Where m is the number of minutes.
The second pool is empty, and Water is being added at a rate of 41.75 liters per minute
Second pool = 41.75m
Since both pools must have the same amount of water:
720 +19.25 m = 41.75m
Solving for m:
720 = 41.75m-19.25 m
720 = 22.5m
720/22.5 = m
32 = m
After 32 minutes the two pools will have the same amount of water.
Finally, we replace m=32 on any equation:
41.75m = 41.75 (32) = 1,336 liters
There will be 1,366 liters in each pool when they have the same amount of water.
Feel free to ask for more if needed or if you did not understand something.
PLEASE HELP. I WILL REWARD BRAINLY TO WHO EVER ANSWERS CORRECTLY. (ignore selected answer) Recalling the SAT scores are always expressed as multiples of 10, how many points did you get on the test?
Answer:
C
Step-by-step explanation:
write an equation for the translation of x^2 + y^2 = 49 by 7 units right and 4 units up
Answer:
(x - 7)² + (y - 4)² = 49
Step-by-step explanation:
Given
Equation: x² + y² = 49
Required:
New Equation when translated 7 units right and 4 units up
Taking it one step at a time.
When the equation is translated 7 units right, this implies a negative unit along the x axis.
The equation becomes
(x - 7)² + y² = 49
When the equation is translated 4 units up, this implies a negative unit along the y axis.
(x - 7)² + (y - 4)² = 49
The expression can be further simplified but it's best left in the form of
(x - 7)² + (y - 4)² = 49
Someone pls help me I’m struggling
Answer:
2850
Step-by-step explanation:
We know that only 19% of people prefer the sedans, so we have to find 19% of 15,000. Set up a proportion: [tex]\frac{19}{100}=\frac{x}{15000}[/tex], cross multiply and get 2850.
Answer:
2850 sedans per month
Step-by-step explanation:
19 % want sedans
They expect to sell 15000 cars
Take the number of cars and multiply by the percent sedans
19% * 15000
Change to decimal form
.19*15000
2850
Please can someone help me ASAP
a) [tex]\frac{8}{2}[/tex]
b) [tex]\frac{9}{4}[/tex]
c) [tex]\frac{3}{-1}[/tex]
The shaded rectangle in the diagram consists ofthree squares. (Picture for full question)
Answer: 243 cm²
Step-by-step explanation: If the diameter is 18, the radius is 9. Each square is 9×9, so 81 cm² for each. Multiply: 81×3 = 243
Or take the length times width to get area 27×9= 243
a blue dice and a green dice are rolled. Find the probability that the blue is either 1 or 2 and the green is 1.
Answer:
2
Step-by-step explanation:
green
Answer: 2
Step-by-step explanation:
on a number cube (numbered 1-6) what is the probability of rolling a 3?
Answer:
1
Step-by-step explanation:
There is only one 3 on the cube
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that sport's league? 293 255 264 240 190 295 199 184 293 205 199
Answer:
A.) Mean = 237.9
B.) Median = 240
C.) Mode = 199
D.) Midrange = 239.5
Step-by-step explanation:
The given data are :
293 255 264 240 190 295 199 184 293 205 199
The mean = (sum of X) / f
Where frequency f = 11
X = 293 + 255 + 264 + 240 + 190 + 295 + 199 + 184 + 293 + 205 + 199
X = 2617
Substitute X and f into the formula
Mean = 2617/11
Mean = 237.9 approximately
B.) To get the median, you need to first rearrange the data, then pick the middle number.
184 190 199 199 205 240 255 264 293 293 295
The median = 240
C.) The mode is the highest frequency. That is the most occuring number
Mode = the two most occuring numbers are 199 and 293
D.) Range = highest number - lowest number
But midrange = (highest number + lowest number ) ÷ 2
Highest number = 295
Lowest number = 184
Substitute into the formula
Midrange = (295 + 184)/2
Midrange = 479/2
Midrange = 239.5
Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1 tells us that y '(0) = 1 y(0) = 1 y '(1) = 0 y(1) = 0 Given that the derivative value of y(t) is 3 when t = 2 tells us that y '(3) = 2 y '(0) = 2 y '(2) = 0 y '(2) = 3 (b) Find dy dt = kcos(bt2)·b2t (c) Find the exact values for k and b that satisfy the conditions in part (a). Note: Choose the smallest positive value of b that works.
Answer:
(a). y'(1)=0 and y'(2) = 3
(b). [tex]$y'(t)=kb2t\cos(bt^2)$[/tex]
(c). [tex]$ b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]
Step-by-step explanation:
(a). Let the curve is,
[tex]$y(t)=k \sin (bt^2)$[/tex]
So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value [tex]x_{0}[/tex] which lies in the domain of f where the derivative is 0.
Therefore, y'(1)=0
Also given that the derivative of the function y(t) is 3 at t = 2.
Therefore, y'(2) = 3.
(b).
Given function, [tex]$y(t)=k \sin (bt^2)$[/tex]
Differentiating the above equation with respect to x, we get
[tex]y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)][/tex]
Applying chain rule,
[tex]y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)[/tex]
(c).
Finding the exact values of k and b.
As per the above parts in (a) and (b), the initial conditions are
y'(1) = 0 and y'(2) = 3
And the equations were
[tex]$y(t)=k \sin (bt^2)$[/tex]
[tex]$y'(t)=kb2t\cos (bt^2)$[/tex]
Now putting the initial conditions in the equation y'(1)=0
[tex]$kb2(1)\cos(b(1)^2)=0$[/tex]
2kbcos(b) = 0
cos b = 0 (Since, k and b cannot be zero)
[tex]$b=\frac{\pi}{2}$[/tex]
And
y'(2) = 3
[tex]$\therefore kb2(2)\cos [b(2)^2]=3$[/tex]
[tex]$4kb\cos (4b)=3$[/tex]
[tex]$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$[/tex]
[tex]$2k\pi\cos 2 \pi=3$[/tex]
[tex]2k\pi(1) = 3$[/tex]
[tex]$k=\frac{3}{2\pi}$[/tex]
[tex]$\therefore b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]
The y'(1) =0, y'(2) = 3, and the [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex] and value of b and k are [tex]\pi/2[/tex] and [tex]3/2\pi[/tex] respectively.
It is given that the curve [tex]\rm y(t) = ksin(bt^2)[/tex]
It is required to find the critical point, first derivative, and smallest value of b.
What is a function?It is defined as a special type of relationship and they have a predefined domain and range according to the function.
We have a curve:
[tex]\rm y(t) = ksin(bt^2)[/tex]
Given that the first critical point of y(t) for positive t occurs at t = 1
First, we have to find the first derivative of the function or curve:
[tex]\rm y'(t) = \frac{d}{dt} (ksin(bt^2))[/tex]
[tex]\rm y'(t) = k\times2bt\times cos(bt^2)[/tex] [ using chain rule]
[tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]
y(0) = 0
y'(0) = 0
The critical point is the point where the derivative of the function becomes 0 at that point in the domain of a function.
From the critical point y'(1) = 0 ⇒ [tex]\rm kb2 \ cos(b) =0[/tex]
k and b can not be zero
[tex]\rm cos(b) = 0[/tex]
b = [tex]\rm \frac{\pi}{2}[/tex]
and y'(2) =3
[tex]\rm y'(2) = kb2\times 2 \times cos(b\times2^2) =3\\\\\rm 4kb \ cos(4b) =3[/tex](b =[tex]\rm \frac{\pi}{2}[/tex])
[tex]\rm 4k\frac{\pi}{2} \ cos(4\frac{\pi}{2} ) =3\\\\\rm2 \pi kcos(2\pi) = 3[/tex]
[tex]\rm2 \pi k\times1) = 3\\\rm k = \frac{3}{2\pi}[/tex]
Thus, y'(1) =0, y'(2) = 3, and the [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex] and value of b and k are [tex]\pi/2[/tex] and [tex]3/2\pi[/tex] respectively.
Learn more about the function here:
brainly.com/question/5245372
41 points * please help Write a linear equation - wil give brainlyist to first person
Answer:
C = 38n + 1750; 15,050
Step-by-step explanation:
We know that for each person, there's a fee of 38. That signifies that the n will be after 38. 1,750 is a one-time fee, so that's by itself. Plug it into the equation to get your first answer. Now, solve for b) by writing C = 38(350) + 1750; C = 15,050
Answer:
C = 38n + 1750; 15,050
Step-by-step explanation:
brainlist plzzzzzz
In triangle $ABC$, $AB = BC = 25$ and $AC = 40$. What is $\sin \angle ACB$?
Answer:
Sine angle of <ACB = 38.68°
Step-by-step explanation:
Hello,
To solve this problem, we need a good representation of the sides and the angle.
See attached document for better illustration.
Assuming it's a right angled triangle,
AC = hypothenus
AB = opposite
BC = adjacent
AC = 40
BC = 25
AB = 25
From trigonometric ratios
Sinθ = opposite/ hypothenus
Sinθ = AB / AC
Sinθ = 25 / 40
Sinθ = 0.625
θ = sin⁻¹0.625
θ = 38.68°
Sine angle of <ACB = 38.68°
Pls help I can't understand
Answer:
A
Step-by-step explanation:
This shape is a trapezoid. We can divide into two parts: a triangle and a rectangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
Let A' be the area of the triangle.
● A'= (b*h)/2
b is the base and h is teh heigth.
b= 26-20 = 6 mm
● A'= (6*14)/2 = 42 mm^2
●●●●●●●●●●●●●●●●●●●●●●●●
Let A" be the area of the rectangle.
A"= L*w
L is the length and w is the width.
A"= 14*20
A"= 280 mm^2
■■■■■■■■■■■■■■■■■■■■■■■■■■
Let A be the area of the trapezoid.
A= A'+A"
A= 42+280
A= 322 mm^2
WILL GIVE BRANLIEST AND 20 POINTS!!
List the coordinates of FOUR vertices that create the feasible region on the graph. Submit your answer in the form of FOUR ordered Pairs (x, y)
Step-by-step explanation:
The coordinates of the feasible region are:(In clockwise direction)
(200, 200)
(300, 200)
(500, 0)
(300, 0)
Can somebody please answer as many as possible?
Please and thankyou!
A quadrilateral is 360 degrees
I cant make a shape for any! Please help!
Answer:
Simply subtract the sum of the the three angles given from 360° in order to get the measure of the fourth angle!
Step-by-step explanation:
(Sorry for the spam, making sure these are right) One zero of the polynomial function f(x)=x^3-9x^2+20x is x=0. What are the polynomial function? Choices:
Replace f(x) with 0 and solve for x. We do this because the x intercepts always occur when y = 0. Keep in mind that y = f(x).
f(x)=x^3-9x^2+20x
0=x^3-9x^2+20x
x^3-9x^2+20x = 0
x(x^2-9x+20) = 0 .... factor out GCF x
x(x-5)(x-4) = 0 ... factor the stuff inside
x = 0 or x-5 = 0 or x-4 = 0 ... zero product property
x = 0 or x = 5 or x = 4
The roots or zeros are 0, 5, 4Answer: Choice DIf a number is added to the numerator of StartFraction 11 Over 36 EndFraction and twice the number is added to the denominator of StartFraction 11 Over 36 EndFraction , the resulting fraction is equivalent to one third . Find the number.
Answer:
The number is 3
Step-by-step explanation:
The fraction is 11/36
let
x = no. added to the numerator
2x = no. added to denominator
We have,
x+11/2x+36=1/3
Cross multiply
3(x+11) = (2x + 36)
3x + 33 = 2x + 36
Collect like terms
3x - 2x = 36 - 33
x=3
The number is 3
Check:
3+11/6+36=1/3
14/42=1/3
On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The number b varies directly with the number a. For example b = 2 3/4 when a = -2 3/4 . Which equation represents this direct variation between a and b?
Answer:
b=-a
Step-by-step explanation: