a block of mass 2 kg slides down an inclined plane. the block starts at a vertical height of 3 meter above the bottom of the incline, with a speed of 5 m/s and reaches bottom with 7 m/s how much energy is lost due to friction??

The new angular momentum of the system, if each of the masses were instead a solid sphere 14.5 cm in diameter, is 0.008275 M kg · m² + 111 kg · m²/s. The mass M is unknown, so we cannot provide an exact value. However, we have shown the method to calculate the new angular momentum.

When answering questions on the Brainly platform, it is important to always be factually accurate, professional, and friendly. Additionally, one should be concise and not provide extraneous amounts of detail. Typos or irrelevant parts of the question should be ignored. When using specific terms, such as in the provided student question, one should incorporate those terms into the answer for clarity and accuracy.

The angular momentum of the system about the origin is given by:L = L1 + L2, whereL1 = I1ω1L2 = I2ω2I1 and I2 are moments of inertia and ω1 and ω2 are angular velocities.Let's assume that the rod is massless, and the masses m1 and m2 are concentrated at their ends, so we can write:I1 = m1r1², I2 = m2r2²where r1 = l/2 and r2 = l/2.I1 = (1/3)m1(l/2)² and I2 = (1/3)m2(l/2)²

The total moment of inertia of the system about the pivot point is:I = I1 + I2 = (1/3)(m1 + m2)(l/2)²The angular momentum of the system is:L = (1/3)(m1 + m2)(l/2)²(ω1 + ω2)When the speed of each particle is 6.40 m/s, we haveω1 = v1/r1 = 6.40/(l/2)ω2 = v2/r2 = 6.40/(l/2)So,L = (1/3)(m1 + m2)(l/2)²(2ω1) = (1/3)(m1 + m2)(l/2)²(2ω2)Therefore, L = (1/3)(m1 + m2)(l/2)²(2ω), whereω = ω1 = ω2 = 6.40/(l/2)The angular momentum of the system is L = (1/3)(m1 + m2)(l/2)²(2ω) = (1/3)(4.6 kg)((2.00 m)/2)²(2(6.40 m/s)) = 111 kg · m²/s.

If each of the masses were instead a solid sphere 14.5 cm in diameter, we can calculate the moment of inertia for each sphere. A solid sphere of uniform density has moment of inertia:I = (2/5)MR²where M is the mass of the sphere and R is the radius. Since the diameter is given as 14.5 cm, we have R = 7.25 cm = 0.0725 m. Thus:I = (2/5)M(0.0725 m)²The new moment of inertia for the system will be:I' = I + I + (1/3)(m1 + m2)(l/2)²where I is the moment of inertia of each sphere about its own center of mass.

So,I' = (2/5)M1(0.0725 m)² + (2/5)M2(0.0725 m)² + (1/3)(m1 + m2)(l/2)²We know that each sphere has a diameter of 14.5 cm, so its radius is 7.25 cm or 0.0725 m. Let the mass of each sphere be M. Therefore, I = (2/5)MR² = (2/5)M(0.0725 m)².Substituting the values,I' = 2(2/5)M(0.0725 m)² + (1/3)(4.6 kg)((2.00 m)/2)²= 0.008275 M kg · m² + 111 kg · m²/s

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The horizontal component of the velocity is 10.6 m/s and the vertical component of the velocity is 7.5 m/s.

The horizontal and vertical components of the velocity can be found using the following equations:

Vx = Vcos(θ)

Vy = Vsin(θ)

where V is the initial velocity, θ is the angle of projection, Vx is the horizontal component of the velocity, and Vy is the vertical component of the velocity.

Substituting the given values, we get:

Vx = 13 m/s × cos(35°) = 10.6 m/s

Vy = 13 m/s × sin(35°) = 7.5 m/s

The time of flight can be found using the following equation:

t = 2Vsin(θ) / g

where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

Substituting the given values, we get:

t = 2 × 13 m/s × sin(35°) / 9.8 m/s^2 ≈ 1.9 s

Therefore, the giant snowball is in the air for approximately 1.9 seconds.

The horizontal distance traveled can be found using the following equation:

d = Vx × t

Substituting the values we found earlier, we get:

d = 10.6 m/s × 1.9 s

d ≈ 20.1 m

Therefore, the giant snowball travels approximately 20.1 meters horizontally before hitting the ground.

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Answer:ac = v^2/r

= (5)^2/5=5

Explanation:

The speed of the object is 10 meters/second.

Speed is defined as the rate at which an object covers distance. It is a scalar quantity, which means that it only has a magnitude (i.e., size) and no direction. The SI unit for speed is meters per second (m/s).

To calculate speed, we need to know the distance traveled and the time it took to cover that distance. In this case, we were given that the object traveled 200 meters and took 20 seconds to do so. We then used the formula:

speed = distance / time

To calculate the speed of the object. We divided the distance traveled by the time it took to travel that distance to find the speed.

Substituting the given values into the formula, we get:

speed = 200 meters / 20 seconds

This simplifies to:

speed = 10 meters/second

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The internal resistance of the battery is 0.5 ohms.

The opposition to current flow inside a battery is known as its internal resistance or IR. Ionic resistance and electrical resistance are the two fundamental factors that affect a battery's internal resistance. One of the metrics used to determine a battery's capacity to transport electricity is internal resistance. The battery can handle a sizable quantity of current when the internal resistance value is low. A battery with high internal resistance, on the other hand, can only support a tiny quantity of current.

Given that,

Potential difference (V) = 11 volts

Electromotive force (E) = 12 volts

Current (I) = 2 amps

To find the internal resistance of the battery, we can use the formula:

V = E - Ir

Substituting these values, we obtain:

11 = 12 - 2r

r = 12 - 11 ÷ 2

r = 0.5 ohms.

Therefore, the internal resistance of the battery is 0.5 ohms.

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A  record is a homogeneous collection and an array is a heterogeneous collection.

False. The statement is incorrect.

An array is a homogeneous collection because it contains elements of the same data type. In contrast, a record is a heterogeneous collection because it can contain elements of different data types.

Arrays are data structures that store a collection of elements of the same data type, such as integers or characters. Each element in an array is identified by an index, which represents its position within the array. Since all elements in an array are of the same data type, arrays are considered homogeneous collections.

On the other hand, a record is a data structure that groups together elements of different data types into a single unit, such as a student's name, age, and grade. The elements in a record are referred to as fields or members, and each field can have a different data type. Records are used to represent complex data structures, and they are considered heterogeneous collections.

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When the string breaks at point a, the ball will continue to move in a straight line tangent to the point on the circle where it broke free. The third curve most accurately represents the path the ball will take after the string breaks.

This means that the ball will continue moving in the direction it was moving at the moment the string broke. In the first curve, the ball appears to continue moving in a circle, which is not possible as it has lost its centripetal force.

The second curve shows the ball moving in a straight line in the direction of its velocity at point a, which is the correct direction. However, the curve appears to be too steep as the ball should continue moving in a straight line with constant velocity. The third curve shows the ball moving in a straight line with constant velocity, which is the correct behavior.

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The Coefficient of Friction is 0.861

Let's begin by determining the initial kinetic energy of the Pellet:

K = (1/2)mv^2

K = (1/2)(0.0012 kg)(65 m/s)^2

K = 25.3875 J

Next, we need to determine the final kinetic energy of the pellet:

Kf = (1/2)mvf^2

Since the pellet is lodged in the cheese, it has no final velocity. Therefore, the final kinetic energy is 0.

Now, we can determine the work done by the frictional force:

Wfriction = K - Kf

Wfriction = 25.3875 J - 0

Wfriction = 25.3875 J

Since the cheese slides 25 cm, we know that the work done by the frictional force is equal to the force of friction multiplied by the distance the cheese slides:

Wfriction = Ff * d

25.3875 J = Ff * 0.25 m

Ff = 101.55 N

Finally, we can determine the coefficient of friction:

Ff = μ * N

101.55 N = μ * (0.120 kg * 9.81 m/s^2)

μ = 0.861

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Therefore, the resonant frequency of the LC circuit is approximately 795.8 Hertz..

The resonant frequency of an LC circuit can be calculated using the formula: f = 1 / (2π √(LC))

The given equation relates the resonant frequency (f) in Hertz with the inductance (L) in Henrys and capacitance (C) in Farads.

In this case, the inductance of the circuit is 0.500 mH, which is equivalent to 0.0005 H, and the capacitance is 40.0 μF, which is equivalent to 0.000040 F. Substituting these values into the formula, we get:

f = 1 / (2π √(0.0005 H × 0.000040 F))

f ≈ 795.8 Hz

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Potential V at the other end of the copper wire is 4.82 V.

The resistance of a wire is given by the formula: R = ρL/A

Using the given values:

R = (1.68 x 10^-8 Ωm) x (8 x 10^-3 m) / (0.2 x 10^-6 m^2) = 0.672 Ω

The potential difference (voltage) at the end of the wire can be calculated using Ohm's law: V = IR

I = V/R = 12 V / 1.672 Ω = 7.18 A

Substituting this value of current and the calculated resistance into Ohm's law gives:

V = IR = (7.18 A) x (0.672 Ω) = 4.82 V

Therefore, the potential at the other end of the copper wire is 4.82 V.

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The electric field between two parallel plates is directly proportional to the potential difference between them and inversely proportional to the distance between them. The correct answer is option: b.

We can use the formula E = V/d. In this scenario, the potential difference is 10 V and the electric field is 200 V/m. Solving for d, we get d = V/E = 10 V / 200 V/m = 0.05 m = 50 mm. Therefore, the distance between the plates is 50 mm, which corresponds to option (b). The other options can be eliminated because they either result in an electric field that is too high or too low for the given potential difference. Option b is correct.

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a) Volume = 2.07074454 m^3. b) Heater needs to be on for approximately 45.7 minutes.

The issue gives us the underlying states of an unbending tank containing an immersed fluid fume blend of water at a strain of 100 kPa. The absolute mass of the blend is 5 kg, with just 75.6% of it being fluid. We are approached to decide the volume of the compartment and the time the electric opposition radiator should be turned on until all the water has disintegrated.

To address for the volume of the compartment, we first need to track down the particular volume of the underlying combination. Utilizing the given data that 75.6% of the complete mass is fluid, we can find the mass of the fluid and utilize the steam tables to decide the particular volumes of the immersed fluid and fume at 100 kPa. With this data, we can compute the absolute volume of the combination. The subsequent volume is around 2.07074454 m^3.

To make the opportunity expected for the radiator to disintegrate all the fluid, we can utilize the energy balance condition. We decide the energy expected to disintegrate all the fluid utilizing the particular enthalpy of the immersed fume at 100 kPa and the particular enthalpy of the soaked fluid at 100 kPa. We then, at that point, partition this energy by the force of the radiator, which is a consistent 3.4 kW, to get the time expected for the warmer to disintegrate all the fluid. The subsequent time is roughly 45.7 minutes.

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Answer:

The characteristic of light behavior that best helps explain the photoelectric effect is that light carries particles called photons. When the photons of light strike the metal surface, they transfer their energy to the electrons in the metal, and if the energy of the photons is high enough, they can cause electrons to be emitted from the metal surface. This phenomenon is known as the photoelectric effect, and it was first explained by Albert Einstein in 1905.

To accelerate a 150 g baseball from rest to 30 m/s, the pitcher does 67.5 J of work, transferring energy to the ball.

To compute the work done by the pitcher on the baseball, we can utilize the recipe:

Work = Power x Distance x Cosine(theta)

In any case, since the issue doesn't give us the power or distance, we can utilize an alternate recipe:

Work = 1/2 x Mass x Velocity^2

Here, the mass of the baseball is 150 grams or 0.15 kg, and the last speed is 30 m/s. Accordingly, the work done by the pitcher ready is:

Work = 1/2 x 0.15 kg x (30 m/s)^2 = 67.5 Joules

This implies that the pitcher did 67.5 Joules of work on the baseball to speed up it from rest to 30 m/s. Work is a scalar amount that actions how much energy moved to an item, for this situation, the baseball, because of the utilization of a power. The work done by the pitcher made the baseball gain dynamic energy and move with a specific speed.

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Answer:

The species that has had the largest influence on Earth is undoubtedly humans. Human activity has significantly altered the natural environment, leading to climate change, deforestation, ocean acidification, and many other damaging effects on the planet.

The maximum depth to which the tank can be filled without water spilling over the top during acceleration or deceleration of the truck is approximately 4.57 feet.

To prevent water from spilling over the top of the tank during acceleration or deceleration of the truck, the maximum depth to which the tank can be filled without overflowing needs to be determined.

First, let's convert the dimensions of the tank from feet to inches for consistency:

Length of tank (L) = 24 ft = 24 * 12 inches = 288 inches

Width of tank (W) = 6 ft = 6 * 12 inches = 72 inches

Height of tank (H) = 8 ft = 8 * 12 inches = 96 inches

Next, we can calculate the volume of the tank in cubic inches:

Volume of tank (V) = Length * Width * Height = L * W * H

Plugging in the values:

V = 288 inches * 72 inches * 96 inches = 1,986,048 cubic inches

Now, let's consider the acceleration or deceleration of the truck. The maximum acceleration or deceleration the truck can experience without water spilling over the top of the tank is 9 ft/s^2. Since the tank is open at the top, the water will be subjected to the same acceleration or deceleration as the truck.

To find the maximum depth to which the tank can be filled without water spilling over the top, we need to equate the pressure due to the acceleration or deceleration of the truck to the pressure of the water at the maximum depth.

The pressure due to acceleration or deceleration is given by:

Pressure due to acceleration/deceleration (P) = Density of water (ρ) * Acceleration or deceleration of truck (a) * Height of water (h)

Where:

Density of water (ρ) = 62.43 lb/ft^3 (density of water at room temperature)

Converting the acceleration from feet to inches:

Acceleration or deceleration of truck (a) = 9 ft/s^2 = 9 * 12 inches/s^2 = 108 inches/s^2

Setting the pressure due to acceleration/deceleration equal to the pressure of the water at the maximum depth:

P = ρ * a * h

Solving for the height of water (h):

[tex]h = \frac{P}{(\rho * a)}[/tex]

Plugging in the values:

[tex]h = \frac{P}{(62.43 * 108)}[/tex]

Note: The unit conversion from lb/ft^3 to inches/s^2 is necessary to ensure that all units are consistent.

Now, we need to convert the volume of the tank from cubic inches to cubic feet, since the density of water is given in lb/ft^3:

Volume of tank (V) = 1,986,048 cubic inches = [tex]\frac{1,986,048}{(12^3)}[/tex] cubic feet

Plugging in the value of V and solving for h:

[tex]h = \frac{P}{(\rho * a)} = \frac{(\frac{1,986,048}{(12^3)})}{(62.43*108)}[/tex]

h ≈ 4.57 ft (rounded to two decimal places)

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Two objects have an electrically attractive force between them. The distance between them would have to be separated one hundred times to make the attractive force one hundred times weaker, which is ten times as much.

This attractive force is experienced by two charged particles that have opposite charges. On the other hand, two particles with the same charge experience a repulsive force. The electrical attractive force decreases as the distance between the two objects increases. This is known as Coulomb's law. By this law, the electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of

the distance between them. According to the problem, the electrical attractive force between two objects is 100

times weaker when the objects are separated by a distance ten times greater than their original distance. Therefore, the objects would have to be separated to make the attractive force one hundred times weaker by a distance ten

times as much as their original distance.

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A 70g bullet moving east at 40 m/s strikes a 1.2kg block suspended and becomes embedded in the block. the height to which the bullet-block system rises above its original point is 4.75 m.

The height to which the bullet-block system rises above its original point can be calculated using the law of conservation of energy.

The initial kinetic energy of the bullet is converted into gravitational potential energy of the system when it reaches its highest point.

The initial kinetic energy of the bullet-block system is given by the expression:

(1/2)mv²

where m = 70 g = 0.07 kg (mass of bullet) and v = 40 m/s (velocity of bullet)

Hence, initial kinetic energy of the bullet-block system is:

(1/2)(0.07)(40)² = 56 J

At the highest point of the system, all of the initial kinetic energy is converted into gravitational potential energy. Therefore, the change in potential energy is equal to the initial kinetic energy.

Change in potential energy = initial kinetic energy= 56 J

At the highest point of the system, the potential energy of the system is given by the expression:

mgh

where m = 1.2 kg (mass of block), g = 9.8 m/s² (acceleration due to gravity) and h is the height to which the system rises above its original point.

Substituting the given values in the above expression, we get:

56 = (1.2)(9.8)h

Solving for h, we get:

h = 56 / (1.2 × 9.8)

h = 4.75 m

Therefore, the height to which the bullet-block system rises above its original point is 4.75 m.

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Answer:

If a wave hits one side of a screen where one slit is carved, the wave will diffract through the slit and produce an interference pattern on the other side of the screen. This interference pattern will consist of alternating bright and dark fringes, indicating areas of constructive and destructive interference, respectively. This is known as the single-slit diffraction pattern, which is a characteristic behavior of wave-like phenomena such as light and sound waves. The pattern will become more pronounced as the slit width decreases and the wavelength of the wave increases.

When a wave hits a screen with a single slit, it diffracts, and the diffracted wavefronts interfere with each other, forming a pattern of constructive and destructive interference fringes on the screen that is on the other side of the screen.

This pattern is known as an interference pattern, and it is a characteristic of wave phenomena, such as light and sound. This interference pattern can be observed by placing a detector screen on the other side of the single slit screen. The interference pattern that is observed on the detector screen will have bright and dark fringes, indicating constructive and destructive interference, respectively.

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Answer:

Q = M S ΔT       Mass * specific heat water * change in temp

M = Q / (S * ΔT)

ΔT = (91.3 - 31.8) deg C = 59.5 deg C

M = 6220 KJoules / (1.00 kJ / kg deg C * 59.5 deg C)

M = 105 kg

There will be a maximum of 2n - 1 nodes in a binary tree with n levels. In the case of a binary tree with three levels, the maximum number of nodes is 2^3 - 1 = 7. This implies that the minimum number of nodes in a binary tree with 3 levels is seven (7).

The minimum number of nodes in a binary tree with 3 levels is seven (7).A binary tree is a tree data structure in which each node has no more than two children, which are referred to as the left and right children. The root node is at the top of the binary tree, and each node has a maximum of two child nodes.

The maximum number of nodes on each level is determined by the number of levels in a binary tree.In the first level of a binary tree, there is only one node: the root node. The root node has two children nodes in the second level, and each of those nodes has two children nodes in the third level.  

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In the first scenario, the energy would be conserved in the system of the girl-wall, The correct answer is option c

In the second scenario, the energy would be conserved in the system of the person-trampoline-earth, The correct answer is option c

In the third scenario, the energy would be conserved in the system of the box-ramp-earth, The correct answer is option a

In the fourth scenario, in a realistic scenario, the energy would not be conserved in any of the given systems due to external work done on the system. The correct answer is option e

For the first scenario of a person wearing roller skates, assuming there is no external work done on the system, the system of the girl-wall would be the appropriate system to consider. The energy would not be conserved in any other system, as there would be external work done on the system due to forces acting on the girl, wall, or both. Therefore option c is correct.

For the second scenario of a person jumping on a trampoline, assuming there is no external work done on the system, the appropriate system to consider would be the system of the person-trampoline-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the person, trampoline, and/or Earth. Therefore option c is correct.

For the third scenario of pushing a box up a ramp, assuming there is no external work done on the system, the appropriate system to consider would be the system of the box-ramp-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the box, ramp, and/or Earth. Therefore option a is correct.

For the fourth scenario of two cars colliding and coming to a stop, it is important to note that in a realistic scenario, there would be external work done on the system due to forces such as friction, air resistance, and deformation of the cars.

Therefore, the energy would not be conserved in any of the given systems. However, if the scenario were simplified to only consider idealized, perfectly elastic collisions in a vacuum, then the system of both cars would conserve energy. Therefore option e is correct.

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Answer:

Assuming a Cl ion has a charge of 1.60E-19 coulombs (electronic charge)

150 ma = .15 C/s       charge per second due to 150 ,,a

N = .15 / 1.60E-19 = 9.4E17 ions / sec

Approximately 9.37 × 10^(17) chloride ions pass a cross section of the leg per second when a current of 150 mA is passed through the leg.

When a current of 150 mA (milliamperes) is passed through the leg of a patient, the number of chloride ions that pass a cross section of the leg per second can be calculated using the formula:
Number of ions = (Current × Time) / (Charge of one ion)
First, convert the current from milliamperes to amperes:
150 mA = 0.150 A
Now, use the charge of a chloride ion (Cl-) which is the elementary charge e (approximately 1.602 × 10^(-19) C, where C represents coulombs).
Number of chloride ions = (0.150 A × 1 s) / (1.602 × 10^(-19) C)
Number of chloride ions ≈ 9.37 × 10^(17)
Approximately 9.37 × 10^(17) chloride ions pass a cross section of the leg per second when a current of 150 mA is passed through the leg.

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The relationship between the direction the stage/slide is moved and the direction of movement in the field of view is opposite to each other.

When the stage or slide is moved in one direction, the sample moves in the opposite direction within the field of view. This is due to the fact that light travels through a microscope lens and flips the image. As a result, the image seen in a microscope is inverted and reversed.The microscope's focus knobs and stage adjustments can be used to control the position of a specimen in the field of view. The stage is the platform on which the sample is placed, and the slide is the glass plate on which the sample is placed.When you move the slide, the direction of movement in the field of view is opposite to the direction in which the stage is moved. This is due to the inversion and reversal of the image caused by the microscope lens, which causes the image to appear to be moving in the opposite direction.

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Answer:

We know that momentum (p) of an electron is given by:

p = mv

where m is the mass of the electron and v is its velocity.

The momentum of a photon is given by:

p = h/λ

where h is Planck's constant and λ is the wavelength of the photon.

Given that the momentum of the electron and photon are the same, we can set these two expressions equal to each other:

mv = h/λ

Solving for the velocity of the electron:

v = h/(mλ)

Now, the kinetic energy (K) of the electron can be calculated as:

K = 1/2 mv^2

Substituting the expression for v, we get:

K = h^2/(2mλ^2)

The energy (E) of the photon is given by:

E = hc/λ

where c is the speed of light.

Substituting the given wavelength, we get:

E = hc/66.8 nm

Using the values for Planck's constant (h) and the speed of light (c), we get:

E = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(66.8 x 10^-9 m)

E = 2.977 x 10^-18 J

Therefore, the energy of the photon is much greater than the kinetic energy of the electron.

The energy of a photon that has a wavelength of 66.8 nm is greater than that of an electron that has the same momentum.

Photons are electromagnetic waves, which means that they travel at the speed of light in a vacuum. The energy of a photon is given by the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.When an electron has the same momentum as a photon of wavelength 66.8 nm, its energy is given by the equation E = p^2/2m, where E is the energy of the electron, p is its momentum, and m is its mass. However, the energy of a photon with a wavelength of 66.8 nm is much greater than the energy of an electron with the same momentum.

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The light curve of a variable star, such as an RR Lyrae or Cepheid variable, contains information about the star's intrinsic brightness and its pulsation period.

A graph of a variable star's brightness over time is called a light curve. A variable star's brightness varies over time as a result of a variety of events, such as pulsations, eruptions, or eclipses. The intrinsic brightness of a variable star, such as an RR Lyrae or Cepheid variable, affects its pulsation period. By comparing the apparent brightness of a star to its intrinsic brightness, astronomers may use this connection, also known as the period-luminosity relationship, to calculate the star's distance from the Earth.

A variable star's light curve also provides details about the star's physical characteristics, including its mass, radius, and temperature. Astronomers can discover information about the star's structure and development by examining the light curve's shape and amplitude.

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Answer:

Zero.

Explanation:

Work done by the weight is Zero, since the force and displacement are at right angles to each other.

The velocity of the elevator at the end of the fourth 5-second interval is 0 m/s.

We can use the following kinematic equation to relate the velocity of the elevator to the time elapsed: v = u + at

where v is the final velocity, u is the initial velocity (in this case, u = 0 m/s), a is the acceleration due to gravity (which is acting upward in this case), and t is the time elapsed.

From the graph, we can see that the scale reading (and hence the apparent weight of the student) is constant at 400 N during the first 20 seconds.

This means that the elevator is moving with a constant velocity during this time interval. Therefore, the velocity of the elevator at the end of the fourth 5-second interval (at 20 s) is the same as its initial velocity, which is 0 m/s.

Therefore, the velocity of the elevator at the end of the fourth 5-second interval is 0 m/s.

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Answer:

Radio waves are transmitted from a sender to a receiver.

However, these waves may be modulated.

There are two kinds of modulation:

     AM - amplitude of the electromagnetic waves is slowly changed

      FM - frequency of the electromagnetic waves is slowly modulated

A person's voice is used to modulate the waves as they are sent from the sender to the receiver.

The modulation is converted by the receiver from electromagnetic waves to audio waves.

These audio waves are used to produce an audio signal that can be interpreted by the person using the receiver.

The categories of each predictions based on the energy diagram made by the student are IC, IC, C, C and CBD

Statement (a): IC

When an electron with a kinetic energy of 13.6 eV interacts with this atom, it will cause the electron in the atom to move to a higher energy level.

To move an electron from the -13.6 eV level to the -0.85 eV level would require a photon with an energy of 12.75 eV, not 13.6 eV.

Statement (b): IC

For the electron in the atom at the -13.6 eV level to move to a higher energy level, it needs to absorb a photon with an energy equal to the difference in energy between the two levels.

A photon with an energy of 13 eV is not sufficient to cause the electron to move to a higher energy level.

Statement (c): C

An electron in the atom at the -0.85 eV level can move to the -3.4 eV level by emitting a photon with an energy equal to the difference in energy between the two levels, which is 2.55 eV.

Statement (d): C

An electron at the -1.5 eV can move to the -0.85 eV level if it absorbs a photon with an energy equal to the difference in energy between the two levels, which is 0.65 eV (not 0.75 eV as predicted).

Statement (e): CBD

e) CBD. Electrons in an atom can only absorb photons of specific energies corresponding to the energy differences between the energy levels of the atom.

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