Question 2
4 pts
Astronomers observed that all the planets of the solar system orbit in the same direction. They also use
radioactive dating to calculate the age of meteorites and rocks from the Moon obtaining similar results.
What do these pieces of evidence mean about the formation of the bodies of the solar system?
O All bodies formed at the same time but from different nebulas spinning in different orientations.
O All bodies formed at the same time from the same spinning nebula.
O Different bodies formed at different times and from different nebulas spinning in different orientations.
Different bodies formed at different times but from the same spinning nebula.
The fact that all the planets of the solar system orbit in the same direction and that meteorites and rocks from the Moon have similar ages suggests that all the bodies of the solar system formed at the same time from the same spinning nebula.
This is known as the nebular hypothesis, which is the most widely accepted theory of the formation of the solar system.
According to the nebular hypothesis, the solar system formed from a rotating cloud of gas and dust called the solar nebula. As the nebula rotated, it flattened into a disk, with the Sun forming at the center and the planets forming from the material in the disk. The fact that all the planets orbit in the same direction and that meteorites and rocks from the Moon have similar ages suggests that they all formed from the same disk of material and at the same time.
What is the nebular hypothesis?The nebular hypothesis is the most widely accepted model in the field of cosmogony to explain the formation and evolution of the Solar System (as well as other planetary systems). It suggests that the Solar System formed from a rotating cloud of gas and dust called the solar nebula. As the nebula rotated, it flattened into a disk, with the Sun forming at the center and the planets forming from the material in the disk. The nebular hypothesis was first proposed by Immanuel Kant and later developed by Pierre-Simon Laplace in the 18th century.
The nebular hypothesis is supported by several lines of evidence, including the fact that all the planets of the solar system orbit in the same direction and that meteorites and rocks from the Moon have similar ages. These suggest that all the bodies of the solar system formed at the same time from the same spinning nebula.
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-How did Carver's work impact the lives of farmers in
the South? Describe two ways.
George Washington Carver, an agricultural scientist, had a significant impact on the lives of farmers in the Southern United States. Here are two ways that his work influenced their lives:
Crop Diversification: Carver encouraged farmers to diversify their crops and move away from their dependence on cotton.
Soil Conservation: Carver was a strong advocate for soil conservation and introduced farming practices that helped to conserve soil. He recommended practices such as crop rotation, using cover crops, and adding organic matter to the soil to improve its quality.
Thus, this way, Carver's work impact the lives of farmers in the South.
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a formula that relatively accurately predicts the orbital distances of the first eight major bodies in the solar system and then somewhat predicts the next several is known as
The formula that relatively accurately predicts the orbital distances of the first eight major bodies in the solar system and then somewhat predicts the next several is known as the Titius-Bode law.
Titius-Bode law is a generalization, or rule of thumb, that appears to describe the orbital distances of the planets of the Solar System. The sequence is 0, 3, 6, 12, 24, 48, 96, and 192. The seventh number, 384, is used as a substitute for Jupiter's real mean distance from the Sun, which is 483.6 million miles.The distance from the Sun to the planets in our Solar System follows a regular pattern known as the Titius-Bode law, which predicts the distance of the planet to the Sun based on its position in the sequence.
The Titius-Bode law is named after two eighteenth-century German astronomers, Johann Daniel Titius and Johann Elert Bode. It was initially proposed in 1766 by Titius as an empirical hypothesis, with little explanation of why it should work, and was later refined by Bode in 1778 into a formula, which became known as Bode's law or the Titius-Bode law.
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If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
A. 12. 1 kg
B. 20. 2 kg
C. 28. 8 kg
D. 282 kg
Answer: mass=28.8kg
Power , p =726 watt
displacement, d =36m
time ,t =14s
g=9.8m/s^2
p= (work)/t
p=(mg*d)/t
726=(m*9.8*36)/14
m= 28.8kg
Explanation: when a force causes displacement of the body , work is said to be done on the body. Power is the rate of doing work. Hence here power was applied on a body of certain mass which caused the given displacement of the body in given time.
A progressive wave equation is represented by Y = A sin 2π (0. 15t+0. 1x) calculate the period and wavenumber
The wave's wavenumber equals 0.628 radians per meter.
The given progressive wave equation is represented by Y = A sin 2π(0.15t + 0.1x), where Y is the displacement of the wave at a point in space and time, A is the amplitude of the wave, t is the time, and x is the position of the point along the direction of wave propagation.
The period of a wave is the time it takes for one complete cycle of the wave to occur. In the given equation, the coefficient of t in the argument of the sine function is 0.15. This means that the wave completes one cycle in (1/0.15) = 6.67 seconds.
Therefore, the period of the wave is 6.67 seconds.
The wavenumber of a wave is the number of waves that occur in a given distance. In the given equation, the coefficient of x in the argument of the sine function is 0.1. This means that the wave completes one cycle in a distance of (1/0.1) = 10 meters.
Therefore, the wavenumber of the wave is (2π/10) = 0.628 radians per meter.
In summary, the period of the given wave is 6.67 seconds and the wavenumber is 0.628 radians per meter. These values can be used to calculate other properties of the wave, such as its frequency and velocity, using the relevant formulas.
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why is the momentum conserved in inelastic collisions
explain why the total momentum is always conserved
Answer:
Momentum is the product of mass of a body and its velocity.
Initially before collision and after collision, velocity changes but mass is a constant factor. Therefore, only one term changes by a constant change hence momentum gained initially, and that gained finally is equal
What is the total mass in grams of 0.75 mole of SO2?a. 16 gb. 24 gc. 32 gd. 48 g
To calculate the total mass of 0.75 moles of SO2 is D. 48g .we need to use the molecular mass of SO2.
What is molecular mass?The sum of the atomic masses of all the atoms present in a molecule is known as its molecular mass. The molecular mass of SO2 is calculated by adding the atomic masses of sulfur and oxygen. Sulfur has an atomic mass of 32 g/mol, and oxygen has an atomic mass of 16 g/mol. Therefore, the molecular mass of SO2 can be calculated as follows:1 sulfur atom + 2 oxygen atoms = (1 × 32 g/mol) + (2 × 16 g/mol) = 32 g/mol + 32 g/mol = 64 g/mol Now that we have calculated the molecular mass of SO2, we can use the following formula to calculate the total mass of 0.75 moles of SO2:Total mass of SO2 = Number of moles × Molecular mass Total mass of SO2 = 0.75 mol × 64 g/mol Total mass of SO2 = 48 g Therefore, the total mass of 0.75 moles of SO2 is 48 g Therefore the correct option is D
The complete question is :
What is the total mass in grams of 0.75 mole of SO2?
a. 16 g
b. 24 g
c. 32 g
d. 48 g
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A fundamental frequency
The lowest frequency that a vibrating object or system can produce is referred to as a fundamental frequency. As the first harmonic frequency, it has another name.
How are fundamental frequencies determined?The vocal folds' fundamental frequency reflects their rate of vibration. It can be measured in cycles per second or hertz (Hz). Male conversational fundamental frequencies often vary from 100 to 150 Hz, while female fundamental frequencies typically range from 180 to 250 Hz.
Explain about the fundamental frequency?It is the frequency at which the object or system naturally tends to vibrate when set into motion. The fundamental frequency is also known as the first harmonic frequency, and it is the primary pitch of a sound wave. In musical instruments, the fundamental frequency determines the perceived pitch or note of the sound, while the overtones or harmonics (which are integer multiples of the fundamental frequency) contribute to the timbre or quality of the sound.
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Complete question;- What is a fundamental frequency?
What will this wave look like when it reflects across a free boundary?
The amplitude of the reflected wave is opposite to the amplitude of the original wave.
When a wave reflects across a free boundary, it undergoes a change in direction and amplitude. The reflected wave looks like the original wave, but it's inverted. It means that the reflected wave's crest becomes a trough, and the trough becomes a crest.What is a wave?A wave is a disturbance that travels through space and time, carrying energy without carrying matter along with it. The movement of energy through a body of water, such as the ocean, is a typical example of a wave.A free boundary refers to a boundary that is not restricted. An example of a free boundary is a reflecting surface. When waves reflect off of a free boundary, they bounce back in the opposite direction. The angle of reflection equals the angle of incidence.The wave looks similar to the original wave, but it is inverted or flipped. The crest of the original wave becomes the trough of the reflected wave, and the trough becomes the crest.
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increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: group of answer choices a. overexposed and darker b. underexposed and lighter c. normal exposure and diagnositc d. increasing the kvp does not affect the quality of the film
Increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: "Underexposed and lighter." The correct option is b.
If we increase the kilovoltage on the control panel with all other exposure factors remaining the same, it will result in a film that is underexposed and lighter. The increase in kVp leads to the increase in the penetrating ability of the x-ray beam. It, therefore, increases the number of x-ray photons that reach the film and allows more of the scattered radiation to reach the film.
The underexposure leads to lightening of the image on the film. In addition to this, the increased kilovoltage reduces the contrast of the image. It is due to the fact that the overall density of the image is decreased due to underexposure.
In conclusion, an increase in kVp on the control panel leads to an increase in the number of x-ray photons that reach the film, thereby lightening the image on the film. Also, the image will be underexposed because an increased kilovoltage reduces the contrast of the image. Here, the correct option is b. underexposed and lighter.
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the strongest region of a magnet can be found at ______.
Answer:
Africa
Explanation:
A student is investigating the effect of the size of the current flowing on the strength of an electromagnet
What are the Independant and dependant variables in her investigation?
What is a practical way she could measure the strength of the magnetic field produced by the electromagnet?
What instruments should she use to measure the size of the electric current?
What are the units of the electric current?
Who ever answers this I will give 45 points :)
Answer:
Independent Variable: The size of the current flowing through the wire.
Dependent Variable: The strength of the electromagnetic field produced by the wire.
A practical way to measure the strength of the magnetic field would be to use a compass to determine the direction of the magnetic field lines. As the strength of the magnetic field increases, the compass needle will deflect more from its original position.
To measure the size of the electric current, she could use an ammeter. An ammeter is a device that connects in series with the wire and measures electric current in amperes (A).
The units of electric current are amperes (A), named after André-Marie Ampère, a French physicist who is one of the founders of electrodynamics.
I hope this helps!
One of the most practical way to measure the strength of the magnetic field would be to use a compass to determine the direction of the magnetic field lines. As the strength of the magnetic field increases, the compass needle will deflect more from its original position.
What instruments should she use to measure the size of the electric current?In order to measure the size of the electric current, she could use an ammeter. An ammeter means a device that connects in series with the wire and measures electric current in amperes (A).
What are the units of the electric current?The units of electric current are amperes (A), named after André-Marie Ampère, a French physicist who is one of the founders of electrodynamics.
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11. A vacuum photocell connected to a microammeter is illuminated with light of varying wavelength.
a) Explain why:
i.
A photoelectric current is registered on the microammeter when light of a certain
wavelength is incident on the photocell.
ii. The current is found to increase with the light intensity is increased.
b) When the incident light wavelength is increased, the photoelectric current falls to zero. decre-
Explain why:
ased.
i. The current falls to zero.
ii.
The current would still be zero if the light wavelength is kept the same and the
intensity is increased.
Answer:
a)
i. A photoelectric current is registered on the microammeter when light of a certain wavelength is incident on the photocell because the energy of the incident photons of the light exceeds the work function of the metal surface of the photocell. This causes the photoelectrons to be emitted from the metal surface and a current to be registered on the microammeter.
ii. The current is found to increase with the light intensity is increased because as the intensity of the incident light increases, the number of photons incident on the metal surface also increases. This increases the number of photoelectrons emitted per unit time, resulting in an increase in the photoelectric current.
b)
i. When the incident light wavelength is increased, the photoelectric current falls to zero because as the wavelength of the incident light is increased, the energy of the incident photons decreases. When the energy of the incident photons becomes less than the work function of the metal surface, no photoelectrons are emitted and hence no current is registered on the microammeter.
ii. The current would still be zero if the light wavelength is kept the same and the intensity is increased because the energy of the incident photons is still less than the work function of the metal surface. Increasing the intensity of the incident light only increases the number of photons incident on the metal surface, but does not increase the energy of the individual photons. Hence, no photoelectrons are emitted and no current is registered on the microammeter.
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One force acting on a machine is F = (5. 00N)i + (0. 200N)j. The vector from the origin where the force is applied is R = (1. 50m)i + (2. 00m)j. What is the magnitude and direction of torque produced by force F?
The magnitude of the torque produced by force F is 1.10 N*m, and the direction of the torque is -49.0 degrees below the positive x-axis (clockwise direction).
The problem requires the calculation of the torque produced by a force acting on a machine. To do so, we need to calculate the cross product of the force and the vector from the origin where the force is applied. The magnitude of the torque is the product of the magnitudes of the force and the lever arm (the perpendicular distance from the origin to the line of action of the force). The direction of the torque is determined by the right-hand rule, which states that the direction of the torque is perpendicular to both the force and the lever arm, and follows the right-hand rule. In this case, the torque is in the clockwise direction, or -49.0 degrees below the positive x-axis.
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A very long, uniformly charged cylinder has radius R and linear charge density λ.
- A) Find the cylinder's electric field strength outside the cylinder, r≥R. Give your answer as a multiple of λ/ε0.
- B) Find the cylinder's electric field strength inside the cylinder, r≤R. Give your answer as a multiple of λ/ε0.
Express your answers in terms of some or all of the variables R, r, and the constant π.
A very long, uniformly charged cylinder has radius R and linear charge density λ. The cylinder's electric field strength outside the cylinder (r≥R) is given by E = λ/(2πε0r) (where ε0 is the permittivity of free space) and inside the cylinder (r≤R) is given by E = λr/(2πε0R²).
Given:
Radius of the cylinder, RLinear charge density, λTo find:
Electric field strength outside the cylinder (r≥R)Electric field strength inside the cylinder (r≤R)Electric field strength outside the cylinder (r≥R)The cylinder is very long, so it can be considered an infinitely long cylinder. Thus, the electric field lines are perpendicular to the cylindrical surface of radius R and the magnitude of the electric field E is given by Gauss's law.
Using Gauss's law for the cylindrical surface, we get:
E2πrl = λ/ε0
Where,
l is the length of the cylinder.Rearranging this equation, we get:
E = λ/(2πε0r)
Electric field strength inside the cylinder (r≤R)
Using Gauss's law for a cylindrical surface of radius r (r ≤ R) inside the cylinder, we get:
E(2πrl) = λr/ε0R²
Rearranging this equation, we get:
E = λr/(2πε0R²)
Hence, the electric field strength outside the cylinder (r≥R) is given by E = λ/(2πε0r) and inside the cylinder (r≤R) is given by E = λr/(2πε0R²).
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A block of mass 4.9 kg is sitting on a frictionless ramp with a spring at the bottom that has a spring constant of 560 N/m (refer to the figure). The angle of the ramp with respect to the horizontal is 39. Part A: The block, starting from rest, slides down the ramp a distance 76 cm before hitting the spring. How far in centimeters, is the spring compressed as the block comes to momentary rest? Δx = ___ ?
Part B: After the block comes to rest the spring pushes the block back up the ramp. how fast in meters per second is the block moving right after it comes off the spring?
Part C: What is the change of the gravetational potential energy in joules between the original position of the block at the top of the ramp and the position of the block when the spring is fully compressed?
The spring compressed as the block comes to momentary rest is Δx = 34.5 Cm. The block moving right after it comes off the spring is 3.057 m/s. The change of the gravetational potential energy in joules is -33.4 J.
(a) potential energy gets Converted to Spring energy-
mg(nt 0.16m) Sin 8-1/2x2
= 4.9 x 9.8 (n + 0.76) Sin 39° = 1/2 x 560 x [tex]x^2[/tex]
= 48.02x + 36.4952 x 0.6293=280x^2
= 30.218986x + 22.966 = 280x^2
= 280x^2 -30.218 x - 22.966 =0
= x = 0.345m
= x = 34.5 Cm
(b) Spring energy becomes PE and KE
1/2kn^2 = myx Sin[tex]\theta[/tex] + 1/2 mv^2
1/2 x 560 x (0.345)^2 = 4.9 x 9.8 x 0.345 x Sin 39° + 1/2x4.9 x V2
33.327 = 10.42588 +245 V^2
33.327 - 10.42588 = 245V^2
22.90112= 2.45 v^2
V^2=9.347393918
V=3.057 m/s
(c) Gravitational potential eneepy
change in [tex]G_{PE}[/tex] = mgΔh
=4.9 x 9.8 x -(0.345 + 0.76) Sin [tex]39^o[/tex]
= -33.39 J
= -33.4 J
Potential energy is a form of energy that is stored within an object and can be released when the object undergoes a change in position or configuration. There are different types of potential energy, such as gravitational potential energy, elastic potential energy, and electric potential energy.
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, such as a ball held up high in the air. Electric potential energy is the energy stored in a charged object due to its position in an electric field. The amount of potential energy an object has depends on various factors, such as its mass, height, distance, and the strength of the force field it is in.
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if the ground on a machine is live (hot) and causes an electrical shock, what does this likely mean?
If the ground on a machine is live (hot) and causes an electrical shock, this likely means that there is a fault in the electrical system, such as broken insulation or a short circuit.
A machine's electrical system is malfunctioning if the ground is live and generates an electrical shock. The machine's ground is meant to offer a secure route for electrical current to flow to earth in the event that there is an electrical system malfunction. An electrical conductor is said to be "live" if it is carrying an electrical current. A live ground indicates a hole in the electrical system's insulation that allows electrical current to pass to the ground, posing a serious safety risk. To reduce the risk of electrical shock or electrocution to anybody coming into touch with the equipment, immediate action should be made to shut it down and rectify the problem before future usage.
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which electromagnetic wave has the highest energy photons? responses light that appears green light that appears green x-rays x-rays microwaves microwaves ultraviolet waves
The electromagnetic wave that has the highest energy photons is X-rays.
Photons are energy quanta that make up electromagnetic radiation. They are released when atoms move from high energy states to lower energy states.
Photons come in a variety of wavelengths and energies, with longer wavelengths being less energetic than shorter wavelengths.
Electromagnetic waves are composed of electric and magnetic fields that oscillate perpendicularly to one another as they travel through space. They are transverse waves, which means that their oscillations are perpendicular to the direction of motion.
X-rays are a type of electromagnetic radiation with a high energy level. They have a much shorter wavelength than visible light, and their photons have much more energy than those in visible light.
X-rays can be produced in a variety of ways, including by bombarding a target with high-speed electrons, by nuclear decay, or by synchrotron radiation.
X-rays are widely used in medical imaging, such as radiography and CT scans, as well as in material analysis and crystallography.
However, X-rays can be harmful to living organisms at high doses because they can ionize atoms and cause cellular damage.
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a rpojectile is fired from the ground with an initial speed of 45 m/s at an agnle of 37 above the fround.
a.what is the horizontal component of the initial velocity?
b.what is the vertical component of the initial velocity?
c.what is the velocity of the projectile at 4 seconds? including magnitude and direction
d.what is the maximum height reached by the projectile?
e.what horizontal distance does the projectile travel before hitting the ground>
The projectile's initial velocity is 36.05 metres per second horizontally, 26.98 metres per second vertically, and 38.19 metres per second at an angle of 18.32 degrees below horizontal.
What is the equation for the angle of projection for a projectile at 45° and 45° angles?R equals u2 sin(90+2)g=u2 cos 2g for the angle (45+). Q. The ratio is used to represent the horizontal ranges covered by two projectiles launched from the same location with the same velocity at angles of (45°) and (45°+).
a) The horizontal component of the initial velocity: The formula for calculating the horizontal component of the initial velocity is
Vx = V cosθ
where V is the starting speed and is the projection angle with respect to the horizontal.
By substituting the provided values, we obtain:
Vx = 45 m/s sin 37 o
Vx = 36.05 m/s (rounded to two decimal places) (rounded to two decimal places)
As a result, the starting velocity's horizontal component is 36.05 m/s.
b) The initial velocity's vertical component
The equation Vy = V sin, where V is the starting velocity and is the angle of projection with the horizontal, can be used to calculate the vertical component of the initial velocity.
By substituting the provided values, we obtain:
Vy = 45 m/s sin 37°
Vy = 26.98 m/s (rounded to two decimal places)
Therefore, the vertical component of the initial velocity is 26.98 m/s.
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Three horizontal forces are applied to a medal ring, as shown. One of the forces is 10N, and the second force is 12N at an angle of 100* from the first. Find the third forces such the ring is in equilibrium (i.e,. the sum of the three forces is zero)
Explanation:
Horizontal components:
10 N + 12 cos (-100) = + 7.916 N
Vertical components
0 + 12 sin (-100) = - 11.818 N
To have equilibrium, the third force must be of the same MAGNITUDE and OPPOSITE direction
so Horizontal = - 7.916 N
Vertical = + 11.818 N
Magnitude = sqrt ( -7.916^2 + 11.818^2 ) = 14.22 N
at angle arctan (- 11.818/7.916 ) = 123.8 degrees
What would be a good addition to your community to promote physical activities for people with disabilities?
More pedestrian lights at roadways
Buses equipped with spaces for wheelchairs
More disabled parking spaces at the coffee shops
Accessibility ramps for going into and out of the pool
Most individuals can live an active life through walking, including those with impairments who can move around through the use of assistance equipment. wheelchair-accessible bus vehicles
Why is accessibility crucial for those who are disabled?It is acceptable to claim that everyone in society, including those with disability, benefit from accessibility. Enhancing accessibility results in a higher quality of life, as well as more independence and social integration. Also, it promotes improved health and has a variety of cost-saving benefits.
What are a few wheelchair-accessible examples?While "wheelchair accessible" is a common way to characterise a facility or amenity that helps persons with disabilities, accessibility may also refer to Braille sign, wheelchair access, elevators, sounds at pedestrian crossings, pathway contours, web designing, and other things.
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the speed of sound in water at a temperature of 25°c is 1500 m/s. what is the wavelength of a 300 hz sound wave traveling through water at a temperature of 25°c?
The wavelength of a 300 Hz sound wave traveling through water at a temperature of 25°C is 5 meters.
Given that the speed of sound in water at a temperature of 25°C is 1500 m/s and the frequency of the sound wave is 300 Hz, to find the wavelength of a sound wave traveling through water at a temperature of 25°C, we have to use the following formula.
The wavelength of a sound wave can be calculated using the formula:
wavelength = speed of sound / frequency
Here, the frequency of the sound wave is given as 300 Hz.
Substituting the given values in the formula, we get:
wavelength = 1500 m/s / 300 Hz
wavelength = 5 meters
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to what maximum height, in meters above the compressed position of the spring, can a child jump with the stick using only the maximum elastic potential energy in the spring, if the child and stick have a combined mass of 38 kg?
Answer:
To solve this problem, we can use the conservation of energy principle which states that the total energy in a system remains constant. At the maximum height, all of the elastic potential energy stored in the spring will be converted into gravitational potential energy.
The elastic potential energy stored in the spring can be calculated using the formula:
Ee = (1/2)kx^2
where Ee is the elastic potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
We can determine the spring constant by using Hooke's law, which states that the force exerted by a spring is proportional to its displacement from the equilibrium position:
F = -kx
where F is the force exerted by the spring and x is the displacement.
We can rearrange this equation to get:
k = -F/x
where F is the force exerted by the spring when it is compressed and x is the displacement.
Assuming that the spring is compressed by 0.5 meters and exerts a force of 200 N, we can calculate the spring constant as follows:
k = -200 N / 0.5 m = -400 N/m
Now we can calculate the maximum height that the child can jump using the maximum elastic potential energy stored in the spring:
Ee = Eg
(1/2)kx^2 = mgh
where Eg is the gravitational potential energy, m is the mass of the child and stick, and h is the maximum height.
We can rearrange this equation to solve for h:
h = (1/2)kx^2 / mg
Substituting the values we have:
h = (1/2)(-400 N/m)(0.5 m)^2 / (38 kg)(9.81 m/s^2)
h = 0.255 m
Therefore, the child can jump to a maximum height of 0.255 meters above the compressed position of the spring using only the maximum elastic potential energy in the spring.
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at what height above the surface of the earth would a satellite be orbiting if it was travelling at 7200 m/s?
At 7200 m/s, a satellite would be orbiting at an altitude of approximately 28,800 km above the surface of the Earth.
A satellite is a celestial body that orbits around a planet. Satellites have various forms, including the natural moon or an artificial man-made object that orbits a planet, the Sun, or any other astronomical body.
Satellites are classified based on their usage, location, and orbit. Weather forecasting, GPS, communication, military intelligence, remote sensing, and scientific experiments are just a few of the applications in that satellites are utilized.
The formula to calculate the height of a satellite above the earth is as follows:
[tex]R = [ (G*M*T^2) / 4\pi^2 ] ^(\frac{1}{3} ) - R_E[/tex]
Where R = height of the satellite above the earth's surface.
G = universal gravitational constant, M = mass of the Earth, T = orbital period of satellite, [tex]R_E[/tex] = radius of the earth.
The radius of the earth is 6400 km. In meters, this would be 6,400,000 m.
Therefore, the orbital period of the satellite is,
[tex]T = (2*\pi *r) / v[/tex]
Where r = radius of the orbit, v = velocity of the satellite.
[tex]T = (2*\pi *R_E) / v[/tex]
[tex]T= (2*\pi *6,400,000) / 7200[/tex]
[tex]T= 2,206.43 \ s[/tex]
Now, calculate the height of the satellite:
[tex]R = [ (G*M*T^2) / 4\pi ^2 ] ^(\frac{1}{3} - R_E[/tex]
Substituting known values in the above equation
[tex]R= [ (6.67 * 10^(-11) * 5.97 * 10^(24) * (2,206.43)^2) / (4 * \pi ^2) ] ^(\frac{1}{3} ) - 6,400,000[/tex]
[tex]R = 28,800\ km[/tex]
Thus, the satellite would be orbiting at a height of 28,800 km above the surface of the earth if it was traveling at the speed of 7200 m/s.
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The drawing shows a hot air balloon. The mass of the balloon is 3000kg. 34000N
What is the weight? What is the resultant force on the balloon?
Answer:
Weight =29400N
Resultant force = 4600N upwards
Explanation:
The weight of an object is calculated using the formula:
[tex]W = mg[/tex]
where W = weight (N), m = mass (kg) and g = gravitational field strength (N/kg).
Since the hot air balloon has a mass of 3000kg and the field strength of the Earth is 9.8N/kg, the weight of the balloon is:
[tex]3000kg\times 9.8N/kg = 29400N[/tex]
The second part of your question asks about the resultant force of the hot-air balloon. This can be calculated by subtracting the smaller magnitude of force from the larger magnitude. This means the resultant force is:
[tex]34000N-29400N = 4600N[/tex]
Therefore, the hot-air balloon has a resultant force of 4600N upwards.
Hope this helps!!!
a car of mass 1147 kg (including the driver) turns to the right on a circular arc on flat pavement. if the distance around the quarter circle is 43.6 m and the speed was 13.6 m/s, find the centripetal acceleration and the static friction force on the car tires.
The centripetal acceleration of the car tires is 17.01 m/s². The static friction force on the car tires is 11242.6 μs N
Given,
Mass of car (m) = 1147 kg
Distance around quarter circle (s) = 43.6 m
Speed (v) = 13.6 m/s
The centripetal acceleration is given as
a = v²/r
Where,
v is the velocity of the object around the circle
r is the radius of the circle
Static friction force on the car tires is given by
Ff = μs x N
Where,
μs is the coefficient of static friction
N is the normal force on the object
Steps to calculate Centripetal acceleration
a = v²/rr = s/π = 43.6 m/4 = 10.9 mv = 13.6 m/sa = v²/r = (13.6 m/s)² / 10.9 m= 17.01 m/s²
Therefore, centripetal acceleration is 17.01 m/s².
Steps to calculate the Static Friction force on the car tires
f = μs x N
The normal force N can be calculated by N = mg
where g is the acceleration due to gravity = 9.8 m/s²N = mg = 1147 kg x 9.8 m/s²= 11,242.6 N
Static friction force on the car tires is given by,
Ff = μs x N= μs x (1147 kg x 9.8 m/s²)= 11242.6 μs N
The formula for calculating static friction force on the car tires is
Ff = μs x N.
The normal force N can be determined as follows:
N = mg,
where g is the acceleration due to gravity = 9.8 m/s²N = mg = 1147 kg x 9.8 m/s²= 11,242.6 N
The static friction force on the car tires is:
Ff = μs x N= μs x (1147 kg x 9.8 m/s²)= 11242.6 μs N
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the populist movement in texas organized to address reforms needed to___
The populist movement in Texas organized to address reforms needed to address the economic and political challenges faced by farmers, laborers, and small business owners in the late 19th century.
During this time, the state was undergoing significant economic changes, including the decline of agriculture and the rise of industry, which led to increased economic inequality and political corruption.
The populist movement sought to address these issues through a variety of reforms, including the regulation of railroads, the creation of a graduated income tax, the establishment of a state-owned bank, and the implementation of a secret ballot system. They also advocated for the protection of workers' rights, such as the right to unionize and the establishment of fair labor laws.
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7. How much time would it take a bowling ball dropped from a helicopter to reach a speed of 55 m/sec?
How far will the ball have fallen in that time?
Answer:
Approximately [tex]5.61\; {\rm s}[/tex].
Approximately [tex]154\; {\rm m}[/tex].
(Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], air resistance on the ball is negligible, and that the helicopter was initially stationary.)
Explanation:
Under the assumptions, acceleration of the ball during the fall would be constantly [tex]a = g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the ball; [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] since it is assumed that the helicopter was initially stationary.Let [tex]v[/tex] denote the final velocity of the ball; [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex].Apply the SUVAT equation [tex]t = (v - u) / a[/tex] to find the time it takes for the velocity of the ball to change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &= \frac{55 - 0}{9.81}\; {\rm s} \\ &\approx 5.61\; {\rm s}\end{aligned}[/tex].
Apply the SUVAT equation [tex]x = (v^{2} - u^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] of the ball as its velocity change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \dfrac{55^{2} - 0^{2}}{2\, (9.81)}\; {\rm m} \\ &\approx 154\; {\rm m}\end{aligned}[/tex].
two identical billiard balls collide. the first one is initially traveling at and the second one at . suppose they collide when the center of ball 1 is at the origin and the center of ball 2 is at the point where r is the radius of the balls. what is the final velocity of each ball?
The final velocities of the two identical billiard balls after an elastic collision is equal in magnitude but opposite in direction.
When two identical billiard balls collide elastically with one ball initially traveling at v and the other at -v, their final velocities can be found using the principle of conservation of momentum. Assuming they have equal masses, we can simplify the problem by assuming both balls have equal speeds of v and -v. Applying conservation of momentum, we get [tex]m1v + m2(-v) = m1u1 + m2u[/tex]. Kinetic energy is also conserved, so [tex](1/2)m1v^2 + (1/2)m2(-v)^2 = (1/2)m1u1^2 + (1/2)m2u2^2[/tex]. Solving for the final velocities, we find that both balls have equal magnitudes of v but opposite directions: the first ball moves in the positive x-direction, while the second moves in the negative x-direction.
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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.A) Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.B) Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends.
A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.
A) To find the moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet, we can use the parallel axis theorem. The moment of inertia of a thin rod of length L and mass M can be found to be:
I = mL^2 /12
Now, we need to add the distance between the axis of rotation and the centre of mass. The distance between the two points is L/2. Thus, the moment of inertia is:
I = mL^2/12 + mL^2/4 = mL^2/3
B) To find the moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends, we can use the perpendicular axis theorem. The moment of inertia of the rod can be found to be:
I = mL^2/3
Since the distance between the axis of rotation and the Centre of mass is 0, the moment of inertia remains the same.
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