A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.
Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]
Given the following data:
Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:
The forces acting on the ball.In this scenario, there are two (2) forces acting on the bowling ball and these include:
Centripetal forceGravitational forceMathematically, centripetal force is given by this formula:
[tex]F_c = \frac{mv^2}{r}[/tex] .....equation 1.
Mathematically, gravitational force is given by this formula:
[tex]F_g= mg[/tex] ....equation 2.
Where:
m is the mass.g is the acceleration due to gravity.v is the velocity.Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.
Substituting eqn. 3 into eqn. 2, we have:
[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]
At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:
[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]
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how far will a body move in 4sec if uniformly accelerated from rest at the rate of 2m/s2
Answer:
32m
Explanation:
v=u+at
v=0+2×4
v=8m/s
d=vt
d=8×4
d=32m
When an object remains stationary, any forces acting on it must be balanced.
Choose 1 answer:
True
False
A truck slows from a velocity of 34 m/s to a stop in 50 m. What was the
truck's acceleration? *
The acceleration/deceleration of the truck is 11.56 m/s^2
Velocity and acceleration Velocity is the rate of change of displacement of a body.Velocity = change in displacement/ time
Acceleration is the rate of change of velocity with time.Acceleration = change in velocity/ time.
The acceleration, velocity and distance travelled of a body is related by the equation below:
v^2 = u^2 + 2aswhere v is the initial velocity
u is the final velocity
a is the acceleration, and
s is the distance travelled
From the data provided:
v = 0
u = 34 m/s
s = 50 m
a = ?
making a subject of the formula
a = -u^2/2s
a = - 34^2 / 2 × 50
a = -11.56 m/s^2
Therefore, the acceleration/deceleration of the truck is 11.56 m/s^2
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to make slime stretchy is by putting more glue and aclohal then mix it
what is a methane. please answer pysicsssssssssss
Answer:
methane is a gas
Explanation:
in chemistry
Newton
10. Your mass on Earth is 50kg. Planet Xenon has half the gravitational force of Earth. What
are your weight and mass on Planet Xenon?
Given parameters:
Mass on earth = 50kg
Unknown:
Mass on planet Xenon = ?
Weight on planet Xenon = ?
Mass is the amount of matter contained in a particular substance.
Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.
Weight = mass x acceleration due to gravity
Planet Xenon has half the gravitational force of Earth.
This translated gives [tex]\frac{9.8}{2}[/tex] = 4.9m/s²
Now, mass is always the same every where if the amount of matter in a substance does not change.
In this problem, mass = 50kg on planet xenon.
Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N
The weight on Xenon is 245N and the mass is 50kg
Which of the following units is part of the international system of units, or SI?
Answer:
meter, kilogram, second, ampere, Kelvin, candela, and mole.
Explanation:
these are all SI units.
Why is it important for scientists to find better ways to store solar and wind energy?
Answer:
Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.
Explanation:
I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)
It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.
Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.
However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.
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A magician performs in a room with a ceiling, which is 2.70 m above his hands. He throws a ball upwards such that it reaches the ceiling with zero speed. Calculate the initial speed of the ball and the time it takes for it to reach the ceiling. A magician performs in a room with a ceiling, which is 2.70 m above his hands. He throws a ball upwards such that it reaches the ceiling with zero speed. Calculate the initial speed of the ball and the time it takes for it to reach the ceiling.
Answer:
a) v = 7.28 m/s
b) t = 0.74 s
Explanation:
a) The initial speed of the ball can be calculated using the following equation:
[tex] V_{f}^{2} = V_{0}^{2} - 2gh [/tex]
Where:
[tex]V_{f}[/tex] is the final speed = 0
[tex]V_{0}[/tex] is the initial speed =?
g: is the gravity = 9.81 m/s²
h: is the height = 2.70 m
[tex] V_{0} = \sqrt{2gh} = \sqrt{2*9.81 m/s^{2}*2.70 m} = 7.28 m/s [/tex]
Hence, the initial speed of the ball is 7.28 m/s.
b) To find the time that takes the balls to reach the ceiling we can use the next equation:
[tex] V_{f} = V_{0} - gt [/tex]
[tex] t = \frac{V_{0} - V_{f}}{g} = \frac{7.28 m/s}{9.81 m/s^{2}} = 0.74 s [/tex]
Therefore, the time it takes for the ball to reach the ceiling is 0.74 s.
I hope it helps you!
On a drive from your home to town, you
wish to average 60 mph. The distance from
your home to town is 78 miles. However,
at 39 miles (half way), you find you have
averaged only 45 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 60 mph?
Answer in units of mph.
On a drive from your home to town, you wish
to average 33.6 mph. The distance from your
home to town is 90 miles. However, at 45 miles
(half way), you find you have averaged only
25.2 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 33.6 mph?
Answer in units of mph
let the speed be x
total average = 33.6
a driver travels 4.25 km in two minutes. if the driver's initial velocity is 20m/s, what is the acceleration
Recall the definition of average velocity:
average v = ∆x / ∆t
The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is
average v = (4250 m) / (120 s) ≈ 35.4 m/s
Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:
average v = (initial v + final v) / 2
Solve for (final v) :
35.4 m/s = (20 m/s + final v)/2
final v ≈ 50.83 m/s
Recall the definition of average acceleration:
average a = ∆v / ∆t
Solve for a :
a = (50.83 m/s - 20 m/s) / (120 s)
a ≈ 0.257 m/s²
Layer with partially melted material that can flow easily is
Answer:
the mantle.
Explanation:
The mantle is the mostly-solid bulk of Earth's interior. The mantle lies between Earth's dense, super-heated core and its thin outer layer, the crust. It's practically hot lava (Magma) Flowing and causing earthquakes and what not.
Hope this helps :)
Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west end of the corridor, a woman walks a short distance east along the corridor and stops before reaching the water fountain. The distance from her to the fountain is twice the distance she has walked. She then continues walking east, passes the water fountain, and stops 60 m from her first stop. Now the distance from her to the fountain is twice the distance from her to the east end of the corridor. How long is the corridor
Answer:
The corridor's distance is "90 m".
Explanation:
She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1. Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled. Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop. The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.Now,
⇒ [tex]2x + 2y = 60[/tex]
⇒ [tex]x + y = 30[/tex]
The total distance of the corridor will be:
= [tex]x + 2x + 2y + y[/tex]
= [tex]3\times (x + y)[/tex]
= [tex]3\times 30[/tex]
= [tex]90 \ m[/tex]
Which table shows the correct role of each organism in the food chain below?
Algae → Shrimp → Artic Cod → Ringed Seals Polar Bears
Answer:
it is algae- shrimp- artic cod-ringed seals- polar bears
Explanation:
you had it right
Three resistors are connected in series to a 42.1 V battery: R1 = 2.96 Ω, R2 = 7.48 Ω and R3 = 7.42 Ω. Now, as R3 heats up, its resistance increases according to: fraction numerator d R subscript 3 over denominator d t end fraction = 0.552 Ω/s Assume the resistance of the other resistors remain constant. Find fraction numerator d P over denominator d t end fraction , the rate at which the power pulled from the battery is changing in W/s, at the instant R3 = 91.7 Ω. The sign shows whether the power is increasing or decreasing.
Answer:
dP/dt = 26.12 W/s
Explanation:
First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:
dR₃/dt = 0.552 Ω/s
where,
dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω
dt = time interval = ?
Therefore,
84.28 Ω = (0.552 Ω/s)(dt)
dt = (84.28 Ω)/(0.552 Ω/s)
dt = 152.68 s
Now, we find change in power (dP):
dP = V(R₁ + R₂ + dR₃)
dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)
dP = 3987.71 W
Dividing by dt:
dP/dt = 3987.71 W/152.68 s
dP/dt = 26.12 W/s
An object begins at position x = 0 and moves one-dimensionally along the x-axis witļi a velocity v
expressed as a function of time t according to the graph above. At what time does the object pass
through x = 0 again?
Answer:
The answer is "between 20 s and 30 s".
Explanation:
Calculating the value of positive displacement:
[tex]\ (x_{+ve}) = \frac{1}{2} \times 15 \times 20 \\\\[/tex]
[tex]= \frac{1}{2} \times 300 \\\\= 150 \\\\[/tex]
Calculating the value of negative displacement upon the time t:
[tex](x_{-ve}) = \frac{1}{2} \times 5 \times 20- 20(t-20) \\\\[/tex]
[tex]= \frac{1}{2} \times 100- 20t+ 400 \\\\= 50- 20t+ 400 \\\\[/tex]
[tex]\to X= X_{+ve} + X_{-ve} \\\\[/tex]
[tex]\to 150 - 50 -20t+400 =0\\\\\to 100 -20t+400 =0 \\\\\to 500 -20t =0\\\\\to 20t =500 \\\\\to t=\frac{500}{20}\\\\\to t=\frac{50}{2}\\\\\to t= 25[/tex]
That's why its value lie in "between 20 s and 30 s".
Help pls it’s urgent
A car goes 500m in 5 sec. It was moving 10 m/sec to begin with, what is
its final velocity?*
Answer:
v = 190 m/s
Explanation:
Given that,
Initial velocity of a car, u = 10 m/s
Distance, d = 500 m
Time, t = 5 s
We need to find the final velocity of the car. Firstly we can find the acceleration of the car using second equation of motion as follows :
[tex]d=ut+\dfrac{1}{2}at^2\\\\500=10\times 5+\dfrac{a}{2}\times 5^2\\\\500=50+\dfrac{25a}{2}\\\\450=\dfrac{25a}{2}\\\\a=\dfrac{450\times 2}{25}\\\\a=36\ m/s^2[/tex]
let v is the final velocity. using First equation of motion to find a as follows :
v=u+at
v=10+36(5)
v=190 m/s
So, the final velocity of the car is 190 m/s.
As mentioned in problem 1.2 from Chapter 1, if you stand on one leg the load exerted on the hip joint is 2.4 times your body weight. Assuming a simple cylindrical model for the implant, calculate the corresponding stress (in MPa) on a hip implant in a individual with a hip implant with a cross-sectional area of If the hip implant is made of Ti6Al4V (124 GPa elastic modulus), what is the strain for the given loading conditions?
The question is incomplete. Here is the complete question.
As mentioned in problem 1.2 from Chapter 1, if you stand on one leg the load exerted on the hip jpint is 2.4 times your body weight. Assuming a simple cylindrical model for the implant, calculate the corresponding stress (in MPa) on a hip implant in a 175lb individual with a hip implant with cross-sectional area of 5.6cm². If the implant is made of Ti6AI4V (124 GPa elastic modulus), what is the atrain for the given loading conditions?
Answer: σ = 3.336 MPa
Strain = 2.69.[tex]10^{-5}[/tex]
Explanation: Stress is the measurement of how hard a weight works to change a material's shape. Its symbol is σ and is calculated as
[tex]\sigma = \frac{F}{A}[/tex]
where
F is force
A is cross sectional area
For the hip implant, force is 2.4x of an 175lb individual:
F = 2.4 * 175
F = 420lb
As the question is asking for Pa and 1 Pa = 1 N/m², transform lb in Newtons:
F = 420lb * 4.448N/lb
F = 1868 N
And cm² in m²:
A = [tex]5.6.10^{-4}[/tex] m²
Calculating Stress:
[tex]\sigma=\frac{1868}{5.6.10^{-4}}[/tex]
[tex]\sigma=333.6.10^{4}[/tex] Pa
or
σ = 3.336 MPa
Stress on a hip implant of an individual with weight 175lb is 3.336 MPa.
Strain is the measure of the deformation of a material due to a load. It can be calculated as:
strain = [tex]\frac{stress}{modulus}[/tex]
But first, change MPa into GPa:
3.336 MPa = [tex]3.336.10^{-3}[/tex] GPa
strain = [tex]\frac{0.003336}{124}[/tex]
strain = [tex]2.69.10^{-5}[/tex]
Ti6Al4V is a titanium alloy used in implants. So, the strain the alloy does on a hip implant of a 175lb individual is [tex]2.69.10^{-5}[/tex].
the period of a pendulum may be decreased by
Answer:
shortening its length.
The period of a pendulum is not dependent on the mass of the ball, but only on the length of its string. The period of a pendulum may be decreased by shortening the length of pendulum
The shortening of the pendulum length often affect its period. The length of the string do influence the pendulum's period making it to be like the longer the length of the string, the longer the pendulum's period.
A pendulum that has a longer string often has a lower frequency. That is, it will swings back and forth in little times in a given amount of time than when the pendulum is with a shorter string length.
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A book sitting on a table has potential energy because of the gravitational pull of Earth. Which of the following would increase the potential energy of the book? A) Sliding it across the table C) Dropping it on the floor B) Opening it to the middle D) Lifting it to a high shelf
Answer:
D) Lifting it to a high shelf
Explanation:
Potential energy is where energy could be released at any moment. For example, if a cat gets on a tree it's creating potential energy, once that cat jumps from the tree the energy releases. D is the answers because if you set the book in a high shelf, you are only creating more potential energy.
hope I explain my self well enough
cheers man and good luck
Based on what you learn about gravity describe why objects float in outer space
Answer:
Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.
Explanation:
Answer:
they float do to gravity
Explanation:
here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity
Which of the following organisms has an adaptation that will allow it to survive in tundra biome? *
A.)Plants with roots that are short and grows sideways with hairy stems and small leaves.
B.)Plants that have broad leaves to capture sunlight and long roots to penetrate the soil.
C.)Animals with thin fur that allows them to get rid of heat efficiently.
D.)Animals with long tongues for capturing prey and sticky pads for climbing trees.
Answer:
the awnser is A becuse the hair help.
how you brother and sister
What are the Function of stand unit
Answer:
It is called the unit function because it is the identity element for Dirichlet convolution. It may be described as the "indicator function of 1" within the set of positive integers. It is also written as u(n) (not to be confused with μ(n), which generally denotes the Möbius function).
Velocity of an object in projectile motion always increase
True
False
Answer:
I'm pretty sure it's false
Which type of force occurs between two objects at a distance?
A. Applied force
B. Contact force
C. Non-contact force
D. Normal force
If your right you get 100 points & brainliest
Answer:
it has to be b contact forces
Explanation: because the two objects are next to each other but they still have force
Answer:
c
Explanation:
3. When two things are the same temperature:
A. They have the same number of molecules
B. Their molecules stop moving
C. Their molecules move at the same average speed
D. Heat transfer between the two things stops
Answer: D. Heat transfer between the two things stops.
What is the net force required to give an automobile with a mass of 2,100 kg an acceleration of 5.4 m/s^2?
Answer:
Net force = 11340 N
Explanation:
Given that,
Mass of an automobile, m = 2100 kg
Acceleration of the automobile, a = 5.4 m/s²
We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :
[tex]F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N[/tex]
So, the net force is 11340 N.