a ball is thrown at an original speed of 8.0 m/s at an angle of 35° above the horizontal. if there is no air resistance, what is the speed of the ball when it returns to the same horizontal level?

Answers

Answer 1

The speed of the ball when it returns to the same horizontal level is 8 m/s.

The given parameters;

initial speed of the ball, u = 8 m/sangle of projection, θ = 35⁰

During the motion of a projectile, the speed of the projectile reduces as the projectile moves upwards and eventually becomes zero at the maximum height.

As the projectile moves downwards, the speed of the projectile starts to increase and it will become maximum (equal to the initial speed) before the projectile hits the ground.

Thus, we can conclude that the speed of the ball when it returns to the same horizontal level is 8 m/s.

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Related Questions

The mass of an object is 84 kg. Find its weight on the Earth and the Moon.​

Answers

Answer:

We would take the mass given, 80 kg, and multiply it times the acceleration of Earth's downward pull on that mass, 9.8 m/s/s. So the weight on Earth is 784 newtons. So the weight of the same 80 kg mass on the moon is 133.28 N.

hi

mass is express  in Newtons.

On Earth gravity is  9.807   so  wieght would be :   9.807 * 84= 823.79

On the Moon garvity is  1.62  so weight would be  :  84 *1.62 = 136.08

Please solve this worksheet for me It’s very important please don’t write unnecessary things or else I’ll report please help me i request

Answers

Answer:

1. 231.25 mL

2. 218.75 kPa

3. 6.21 L

4. 427.5 mL

5. 83.01 mL

6. 307.6 mL

7. 1.15 L

Explanation:

Boyle's law equation is used in this questions as follows;

P1V1 = P2V2

Where;

P1 = initial pressure

P2 = final pressure

V1 = initial volume

V2 = final volume

Please find the solutions to each subquestion as an attachment

Help plz for 25 points !! I only have an hour left !

Answers

See the pic for the work!

What allows a metal to be pounded into a flat shape?

Answers

C im pretty sure?.........

A light bulb has a power output of 80 W and it has been left on for 90 seconds. How much work was done?

Answers

7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.

What could be the average human density? Justify?

Answers

Answer:

985 kg/m3

Explanation:

The average density of the human body is 985 kg/m3 k g / m 3 , and the typical density of seawater is about 1020 kg/m3 k g / m 3 .

Explanation:

the worldwide human population density is around 7,500,000,000 ÷ 510,000,000 = 14.7 per km2 (38 per sq. mi.). If only the Earth's land area of 150,000,000 km2 (58,000,000 sq. mi.) is taken into account, then human population density is 50 per km2 (129 per sq.

The weight of a cuboid box is 288 N. Find its mass.​

Answers

Answer:

29.39 kg

Explanation:

From the question,

W = mg...................... Equation 1

Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.

make m the subject of the equation

m = W/g.................. Equation 2

Given: W = 288 N

Constant: g = 9.8 m/s²

Substitute these values into equation 2

m = 288/9.8

m = 29.39 kg

6. A plane took 3.55 hours to complete its flight. If the distance of the flight was 2840 kilometers, at what average speed did the plane travel? Include the correct unit for full credit.

Answers

Answer:

The average speed is 10,082

Explanation:

Do the formula

Distance * time = speed

2840 * 3.55

= 10,082

1.) Cameron loads a wheelbarrow full of dirt. She then holds up both handles and begins to push it across her yard. The push Cameron uses to move the wheelbarrow is an example of
trajectory

motion

dynamics

force

2.) Jeremy is pushing his two children on a set of swings. He gives his daughter a push and she swings about three feet high. Jeremy gives his son the same push, but he only swings about two feet high. What could account for the difference in how high the kids got?

Jeremy's daughter has more mass, so it takes less force to get her into the air.
Jeremy's son has more mass, so it would take more force to reach the same height as his daughter.
Jeremy's son has less mass, so it would take more force to reach the same height as his daughter.
Jeremy's daughter has more mass, so she accelerates faster than his son.

Answers

Answer:

C (Force)

Explanation:

Cmon we should all know dis

Answer:

force and Jeremy's son has more mass

Explanation:

pushing requires force and the son moves less

eeeee
help pls
pls
pls

Answers

Answer:

hey dream I m your big fan for u I have answered this question The third one is correct.

Volleyball took some of its characteristics from handball and tennis

True
False

Answers

Answer:

True Because if we observe carefully we will see that some moves of volleyball are similar to handball and tennis

Please help choose one
A B C or D
???

Answers

I believe the answer is B

This is because in combustion reactions the products are being burned meaning heat increases. Therefore energy is transferred from the fuel to the surroundings.
^^Correct!!!!!!!!!!!!

Which law best describes contact force

A.
second law
B.
third law
C.
law of gravity
D.
first law

Answers

Answer:

b is the answer the third law

Explanation:

B because Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.

https://forms.office.com/Pages/ResponsePage.aspx?..
Print Management S Show My Homework
worites
10
Calculate the power in resistor X when the voltage across X is 2.1 V and the current in resistor
X is 0.041 A
(2 Points)

Answers

Answer:

P = 0.0861 W = 86.1 mW

Explanation:

The electrical power in a resistor is defined as the product of the current passing through that resistor and the voltage across that resistor. Therefore, the formula can be written as follows:

[tex]P = VI[/tex]

where,

P = Power in Resistor X = ?

V = Voltage across resistor X =  2.1 V

I = Current passing through resistor X = 0.041 A

Therefore,

[tex]P = (2.1\ V)(0.041\ A)[/tex]

P = 0.0861 W = 86.1 mW

A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone when this fellow, clutching his radio, jumps off. Describe the Doppler Effect heard by (a) a person left behind on the platform and (b) a person down below floating on a rubber raft. In each case, specify (1) whether the frequency is greater or smaller than the frequency produced by the radio, (2) whether the observed frequency is constant, and (3) how the observed frequency changes during the fall, if it does change. Give your reasoning.

Answers

Answer:

The Doppler Effect is given by the following relation;

[tex]f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f[/tex]

Where;

f' = The frequency the observer hears

f = Actual frequency of the wave

v = The velocity of the sound wave

[tex]v_o[/tex] = The velocity of the observer

[tex]v_s[/tex] = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(ii) When the source is receding from the observer, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]

(1) Given that (v + [tex]v_s[/tex]) > v, therefore, v < (v + [tex]v_s[/tex]), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]

(1) Given that (v - [tex]v_s[/tex]) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

A house painter stands 3.00 m above the ground on a 5.00-m-long ladder that leans against the wall at a point 4.70 m above the ground. The painter weighs 676 N and the ladder weighs 107 N. Assuming no friction between the house and the upper end of the ladder, find the force of friction that the driveway exerts on the bottom of the ladder. If the force of friction is away from the wall, enter a negative value and if the force of friction is toward the wall, enter a positive value.

Answers

Answer:

The force of friction that the driveway exerts on the ladder ≈ -176.03 N

Please see attached force diagram created with MS Visio

Explanation:

The height of the house painter above the ground = 3.00 m

The length of the ladder = 5.00 m

The height above the ground at which the ladder leans on the wall = 4.70 m

The weight of the painter = 676 N

The weight of the ladder = 107 N

The angle of inclination of the ladder, arcsin(4.7/5) ≈ 70.05°

For equilibrium, the sum of moments at a point, ∑M = 0

Taking moment about point A gives;

4.7 × R = 107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5)))

R = (107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5))))/4.7 ≈ 176.03

The reaction force at the top of the ladder, R ≈ 176.03 N

For equilibrium, we have;

The sum of the horizontal forces, ∑Fₓ = 0

The reaction at the top of the ladder, R + The force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] = 0

R + [tex]F_R[/tex] = 0

∴ R = [tex]-F_R[/tex]

R ≈ 176.03 N = [tex]-F_R[/tex]

∴ [tex]F_R[/tex] = -176.03 N

Therefore, the force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] ≈ -176.03 N (acting away from the wall).

Which of the following statements is true with
regards to Blackbody radiation?
a)
b)
c)
A blackbody emits more energy at longer
wavelengths as it heats up
A blackbody emits energy at all wavelengths
The shape of the blackbody spectrum
depends on what the source is made of
All of the above
None of the above
00)
e)​

Answers

I believe that it most likely would be C,

Would the following reaction be endothermic or exothermic? Why?
CH4 + 02 --> CO2 + H2O + Energy
A. Exothermic because energy is a reactant
B. Endothermic because energy is a reactant
C. Endothermic because energy is a product
D. Exothermic because energy is a product

Answers

Answer:

D. Exothermic because energy is a product

Explanation:

ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

Hence, the correct answer for this question will be:

D. Exothermic because energy is a product

In which of the following situations is there acceleration? (There may be more than one correct answer)

a. A car is sitting at a stoplight. The light turns green and the car begins moving.

b. A car maintains a speed of 10 mi/hr as it turns a corner.

c. When a truck approaches a stop light, it begins to slow down.

d. A car travels at 65 mi/hr.

Answers

A is the correct answer because “The light turns green and the car begins moving.”

what is the difference between storm spotter and storm chaser?

Answers

Answer:

this is just a guess

Explanation:

a storm spotter only spots the storm and a storm chaser looks for the storm????

list of places in our bodies where HIV is present

Answers

Answer: The brain

Explanation:

The brain is an ideal reservoir for our bodies. That is the main one.

When a ball is being lifted work is being done to it, giving it ______ energy.

Answers

Kinetic or Potential energy?

Kinetic energy is energy expended
Potential energy of energy stored










***Potential***

Helppppppl!!!!!!!!!!!​

Answers

Answer:

I think deposition of C is the oldest deposit

3. What does the difference in force depend on?

Answers

Answer:

it depends on the relative masses of the objects.

Explanation:

It depends on the mass of an object

Please solve this worksheet for me It’s very important please don’t write unnecessary things or else I’ll report please help me i request

Answers

Answer:

1. 231.25 mL

2. 218.75 kPa

3. 6.21 L

4. 427.5 mL

5. 83.01 mL

6. 307.6 mL

7. 1.15 L

8. 440.4 mL

Explanation:

This questions describes Boyle's law. Using Boyle's law equation to solve the questions as follows:

P1V1 = P2V2

Where;

P1 = initial pressure

P2 = final pressure

V1 = initial volume

V2 = final volume

Please find the answers to each question as an attachment.

The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated

Answers

Answer:

0.37 kg

Explanation:

I'm not a professor myself, but this is how I worked it out:

using the graph, after 100 seconds, the temperature is 100 degrees Celsius.

If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:

4200 = 155000/(m x 100)

If we rearrange and solve for m, we get 0.37 kg.

I'm not sure if I have done this correctly, feel free to correct me.

Hope this helps!

By using the specific heat capacity formula, the  mass of water in the kettle is 0.47 kg

Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C

From the graph;

The initial temperature of the water at time zero is 22 degree Celsius

The final temperature of the water at time 100s is 100 degree Celsius

Change in temperature (T) = 100 - 22 = 78 degree Celsius

To determine the mass of water in the kettle, use the heat energy formula below

E = mcT

Substitute all the parameters into the equation

155000 = 4200 x 78 M

Make M the subject of the formula

M = 155000/327600

M = 0.47 kg

Therefore, the  mass of water in the kettle is 0.47 kg

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2. When braking and turning, you use ___?
a. All four wheels of traction
b. Only the outside edge of your tires
c. Split traction
d. Additional traction

Answers

Answer:

split traction

Explanation:

Can some one please help me

Answers

Answer:

its "up, then down, then up"

Explanation:

Greg can't remember how tall his 9-month-old niece is. He guesses that she is 100 cm tall. Which of the following is true?

Age (months)

Height (cm)

3 61.1
6 67.8
9 72.3
12 76.1



A.
Based on the data, Greg's guess is reasonable.

B.
Based on the data, Greg's guess is not reasonable.

C.
Based on the data, Greg's niece should be around 61.1 cm tall.

D.
Based on the data, Greg's niece should be around 76.1 cm tall.

Answers

Answer:

C

Explanation:

Which of the following actions will decrease the gravitational force between two objects?

Increasing the mass of the objects
Increasing the density of the objects
Increasing the distance between the objects
Increasing the temperature of the objects

Answers

Increasing the distance between the objects

here's the Answer :

=》Increasing the distance between the objects.

since, gravitational force is inversely proportional to the distance between the objects, so if the distance increases the force will decrease.

[tex]gravitational \: force \: \: \dfrac{1}{ \alpha } \: \: distance[/tex]

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