A ball is dropped from the top of a building and hits the street below in 4.25 s. How tall is the building? Show work for brainliest.

Answer:

Three different types of levers exist, depending on where the input force, fulcrum, and load are. A class 1 lever has the fulcrum between the input force and load. A class 2 lever has the load between the fulcrum and input force. A class 3 lever is a lever that has the input force in between the fulcrum and the load.

Explanation:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question

mass = 249 g

volume = final volume of water - initial volume of water

volume = 19 - 15 = 4 mL

We have

[tex]density = \frac{249}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

the answer is D

Explanation:

Just took the test

The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including fairness, honesty and respect.

NCAA stands for National Collegiate Athletic Association. The NCAA is a organization which will be useful for the well being and the success for life long to the college Athelet.

A person who got graduate from high school and completed a minimum of 16 core courses for Division I or II and to earn a minimum required grade-point average in normal core courses and also must earn a qualifying test score on either the ACT or SAT will be eligible to join NCAA.

The NCAA Sportsmanship Award honors a student-athlete who will takes actions in the competitive arena of intercollegiate athletics and who demonstrated one or more of the ideals of sportsmanship, including fairness, civility, honesty, unselfishness, respect and responsibility.

Hence, Option D is the correct answer.

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It is true that the sample of plasma has more energy than the sample of gas. Option D is correct.

Gas is a sample of matter that adopts the shape of the container in which it is housed and develops a uniform density inside the container.

Liquid molecules are more energetic than solid molecules. Further heating will cause the molecules to move so quickly that they won't stick together at all. The gas molecules have the highest energy content.

Although oxygen is a gas that you breathe in, it may also exist in all four other states. The mass of the four oxygen samples is the same, yet they are all in distinct states.

Regarding the relative levels of thermal energy in the samples, statement B is accurate. Regarding the proportional quantities of thermal energy in the samples,

It is true that the sample of plasma has more energy than the sample of gas.

Hence, option D is correct.

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Answer:

Each kilogram of the cannonball has a total energy of 52396.454 joules.

Explanation:

From Principle of Energy Conservation we understand that energy cannot be destroyed nor created, but transformed. In this case non-conservative forces can be neglected, so that total energy of the cannonball ([tex]E[/tex]) is the sum of gravitational potential ([tex]U_{g}[/tex]) and translational kinetic energies ([tex]K[/tex]), all measured in joules. That is:

[tex]E = U_{g}+K[/tex] (Eq. 1)

By applying definitions of gravitational potential and translational kinetic energies, we proceed to expand the expression:

[tex]E = m\cdot g \cdot y + \frac{1}{2} \cdot m \cdot v^{2}[/tex] (Eq. 2)

Where:

[tex]m[/tex] - Mass of the cannonball, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]y[/tex] - Height of the cannonball above ground level, measured in meters.

[tex]v[/tex] - Speed of the cannonball, measured in meters per second.

As we do not know the mass of the cannonball, we must calculated the unit total energy ([tex]e[/tex]), measured in joules per kilogram, whose formula is found by dividing (Eq. 1) by the mass of the cannonball. Then:

[tex]e = g\cdot y + \frac{1}{2}\cdot v^{2}[/tex]

If we know that [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y =122\,m[/tex] and [tex]v = 320\,\frac{m}{s}[/tex], the unit total energy of the cannonball is:

[tex]e = \left(9.807\,\frac{m}{s^{2}}\right)\cdot (122\,m)+\frac{1}{2}\cdot \left(320\,\frac{m}{s} \right)^{2}[/tex]

[tex]e = 52396.454\,\frac{J}{kg}[/tex]

Each kilogram of the cannonball has a total energy of 52396.454 joules.

Answer:

3 miles per hour

Explanation:

15 divided by 5 = 3

Answer:

Let's see what to do buddy...

Explanation:

_________________________________

[tex]a = \frac{60}{ ({ \frac{1}{5}) }^{2} } = \frac{60}{ \frac{1}{25} } = 60 \times 25 \\ \\ a = 15 \times 4 \times 25 = 15 \times 100 \\ a = 1500 \: \frac{m}{ {s}^{2} } [/tex]

_________________________________

The body start from rest which means :

[tex]v(0) = 0[/tex]

_________________________________

In third second means :

t = 2 -----¢ t = 3 -----¢ ∆t = 1

_________________________________

We have this equation to find the distance.

[tex] ∆x = \frac{1}{2} \: a \: {t}^{2} + v(0) \: t \\ [/tex]

_________________________________

[tex]∆x = \frac{1}{2} \times 1500 \times 1 + 0 \times 1 \\ \\ ∆x = 750 + 0 = 750[/tex]

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

Answer:

A that the answer I think I'm not tryna do u bad thi

Explanation:

but try it

Answer:

B

Explanation:

Answer:

Soil will loosen due to vast networks of underground tunnels.

Answer:

1233 N

Explanation:

force=mass×accerelation

Answer:

a) 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b) 3.466 × 10¹¹ N/C

Explanation:

a)

p(r) = -A exp ( - 2r/a₀)

Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV  =  -A  ₀∫^∞ ₀∫^π ₀∫^2π   exp ( - 2r/a₀)r² sinθdrdθd∅

Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e

now using integration by parts;

A = e / πa₀³

p(r) =  - (e / πa₀³) exp (-2r/a₀)

Now Net charge inside a sphere of radius a₀ i.e Qnet is;

= e - (e / πa₀³)  ₀∫^a₀ ₀∫^π ₀∫^2π  r² exp (-2r/a₀)dr

= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b)

Using Gauss's law,

E × 4πa₀ ² = Qnet / ∈₀

E = 4πa₀ ² × Qnet × 1/a₀²

E = 3.466 × 10¹¹ N/C

Answer:

Explanation:

Key point: the vertical motion is free fall, the horizontal motion remains at uniform speed of 100 m/s (because there is no force in the horizontal direction if we neglect air resistance.)

The time of free fall can be calculated first:

h = 1/2 g t^2 => t = sqrt(2 h /g) = sqrt(2 * 300 m / 9.81 s) = 7.82 seconds.

In that time, the horizontal displacement will be

s = v_horizontal * t = 100 m/s * 7.82 s = 782 m.

So the box will land 782 m further than the point it was dropped from (and 300 m lower of course)

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

This is because, in the  ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.

Answer:

C requires the most work and A requires the least work

Answer:

Which scenario requires the most work?

✔ C

Which scenario requires the least work?

✔ A

Answer:

0.65 m

Explanation:

See attachment for calculation

Analysing the question:

We are given that the cat chases a rat on a 1m high table, this means that the height of the cat before falling is 1 m

The horizontal velocity of the cat after sliding off the table will not change in mid-air since there is no force to oppose it

We are given:

height of the cat before falling (h) = 1 m

Distance covered by cat after falling off the edge = 2.3 m

acceleration due to gravity (a) = 9.81 m/s²

initial vertical velocity of the cat (u) = 0 m/s

Since the cat will fall at a constant horizontal velocity, the time taken by the cat to reach the ground times the constant speed of the cat will be equal to the horizontal distance covered by the cat  

[ since time taken to reach the ground = time for which the constant horizontal velocity will be applied]

The above can simply be written as:

time taken by the cat to reach the ground * horizontal velocity = horizontal distance covered

Time taken by the cat to reach the ground:

From the second equation of motion

s = ut + 1/2*at²

replacing the variables with vertical components

1 = (0)(t) + 1/2 * (9.8)(t²)

1 = 4.9t²

t² = 1  / 4.9

t = 1 / √4.9

t = 0.45 seconds

Cat's horizontal velocity when it slid off the table:

Speed of cat = distance travelled / time taken

here, the distance is the horizontal distance covered by the cat after falling off the table

replacing the variables

Speed of the cat = 2.3 / 0.45 = 5.11 m/s

Answer:

Explanation:

The object starts at 0

It moves to - 2

It stops

It then moves to + 6

+6 - 2 = + 4

The new position is 4.

Answer:

The answer is D

Explanation:

Because it is big and can fit the truck.

Answer:

A) q = 7.03 × 10^(-13) C

n ≈ 4388265 electrons

B) q = 1757.8 × 10^(-16) C

n ≈ 1097253 electrons

Explanation:

We are given;

Mass; m = 1.5 × 10^(−8)g = 1.5 × 10^(-11) kg

Speed; v = 50 m/s

Electric Field; E = 8 × 10⁴ N/C

Distance between plates; s = 2 cm = 0.02 m

A) Now, speed = distance/time

So, time(t) = distance/speed = 0.02/50 = 0.0004 s

From Newton's first law of motion, we know that;

d = ut + ½at²

But u is initial velocity and in this case it's zero.

But we are told that a drop is to be deflected by 0.30 mm. So, d = 0.3 × 10^(-3) m

Thus;

0.3 × 10^(-3) = 0 + ½a(0.0004)²

a = 3750 m/s²

Now, we know that force in motion normally can be expressed as;

F = ma

But in electric field, it's;

F = qE

Thus;

qE = ma

So, charge is; q = ma/E

Plugging in the relevant values;

q = (1.5 × 10^(−11) × 3750)/(8 × 10⁴)

q = 7.03 × 10^(-13) C

Now, number of electrons is given by the formula;

n = q/e

Where e is charge on electron with a value of 1.602 × 10^(-19) C/electron

So; n = (7.03 × 10^(-13))/(1.602 × 10^(-19))

n ≈ 4388265 electrons

B) We are told speed is now 25 m/s.

Thus;

time(t) = distance/speed = 0.02/25 = 0.0008 s

From Newton's first law of motion, we know that;

d = ut + ½at²

But u is initial velocity and in this case it's zero.

d remains 0.3 × 10^(-3) m

Thus;

0.3 × 10^(-3) = 0 + ½a(0.0008)²

a = 937.5 m/s²

Now, we know that force in motion normally can be expressed as;

F = ma

But in electric field, it's;

F = qE

Thus;

qE = ma

So, charge is; q = ma/E

Plugging in the relevant values;

q = (1.5 × 10^(−11) × 937.5)/(8 × 10⁴)

q = 1757.8 × 10^(-16) C

Now, number of electrons is given by the formula;

n = q/e

Where e is charge on electron with a value of 1.602 × 10^(-19) C/electron

So; n = (1757.8 × 10^(-16) )/(1.602 × 10^(-19))

n ≈ 1097253 electrons

Answer: 3.5 × 10^3

Explanation:

Answer:

this question requires us to use our knowledge of newton's 1st 2nd and 3rd laws to fill in the blank spaces. the words in bold are the answers to the question

Explanation:

1. You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is greater than the magnitude of your force because of newtons second law

2. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is equal to the magnitude of your force because of newtons second law

3. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is equal to  the magnitude of the normal force from you on the ground because of newtons third law.

4. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is less than the magnitude of your weight because of newtons second law

5. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is equal to the magnitude of the force from you on Worf because of newtons third law

6. You are standing at a place where the ground is level. The magnitude of your weight is equal to the magnitude of the normal force from the ground on you newtons second law

Answer:

24000 kg·m/s

Explanation:

Momentum is Mass x Velocity, so 1200 kg time 20 m/s =  24000 kg-ms/s

The momentum of the car is  24000 Kg•m/s

Momentum is defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the momentum of the car as follow:

Momentum = mass × velocity

Momentum = 1200 × 20

Momentum of car = 24000 Kg•m/s

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Answer:

(a) 9.52

(b) 3.81

Explanation:

Draw a free body diagram of block m.  There are two forces:

Weight mg pulling down, and tension T₁ pulling up.

Draw a free body diagram of block M.  There are two forces:

Weight Mg pulling down, and tension T₂ pulling up.

Draw a free body diagram of the double pulley.  There are two torques:

Tension T₂ pulling counterclockwise at r, and tension T₁ pulling clockwise at R.

Let's assume that M moves down, m moves up, and the pulley rotates counterclockwise.

Sum of forces on block m in the +y direction:

∑F = ma

T₁ − mg = ma₁

T₁ = mg + ma₁

Sum of forces on block M in the -y direction:

∑F = ma

Mg − T₂ = Ma₂

T₂ = Mg − Ma₂

Sum of the torques about the pulley's center in the counterclockwise direction:

∑τ = Iα

T₂ r − T₁ R = (½ m₀ r² + ½ m₀ R²) α

T₂ r − T₁ R = ½ m₀ (r² + R²) α

Substitute:

(Mg − Ma₂) r − (mg + ma₁) R = ½ m₀ (r² + R²) α

The strings don't slip on the pulley, so a₁ = αR and a₂ = αr.

(Mg − Mαr) r − (mg + mαR) R = ½ m₀ (r² + R²) α

Mgr − Mαr² − mgR − mαR² = ½ m₀ (r² + R²) α

g (Mr − mR) − α (Mr² + mR²) = ½ m₀ (r² + R²) α

g (Mr − mR) = [½ m₀ (r² + R²) + Mr² + mR²] α

α = g (Mr − mR) / [½ m₀ (r² + R²) + Mr² + mR²]

α = (10) (9×0.2 − 1×0.5) / (½ (0.5) (0.2² + 0.5²) + 9(0.2)² + 1(0.5)²]

α = 19.0 rad/s²

Therefore:

a₁ = αR = (19.0 rad/s²) (0.5 m) = 9.52 m/s²

a₂ = αr = (19.0 rad/s²) (0.2 m) = 3.81 m/s²

Answer: The answer is B; Electrons move from areas of high to low electric potential

Explanation:

I had this question on a quiz and got it correct.

The required Electrons move from areas of high to low electric potential best describes Jodi’s error. Option B is correct.

Electric current is the flow of electric charge through a material. It is typically expressed in units of amperes (A), which represent the rate at which charge flows through a conductor.

Here,
Jodi's error is in statement 2. Electrons move from areas of high electric potential to areas of low electric potential, not from low to high electric potential. This is because electric potential is a measure of the energy per unit charge, so electrons will naturally flow from areas of higher potential to areas of lower potential to balance out the potential difference.

Thus, the required, Electrons move from areas of high to low electric potential best describes Jodi’s error. Option B is correct.

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I don't see any units of measurement or speed I don't see anything