The empirical formula of the compound is Li₂CO₃
First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses
Lithium Carbon Oxygen
6.25÷6.94 5.40÷12.01 21.60÷16.00
0.9006 0.4496 1.35
Now, divide through by the smallest number of moles, that is, 0.4496
Lithium Carbon Oxygen
0.9006÷0.4496 0.4496÷0.4496 1.35÷0.4496
2 1 3
Hence, the empirical formula of the compound is Li₂CO₃
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Julie blows a bubble. At first, the pressure of the gas in the bubble is 4kPa. The bubble floats into the air and expands. When it gets to the top of a tree the bubble has a pressure of 2kPa and a volume of 3.5m³. Assuming a constant temperature, what was the volume in m³ of the bubble when it was first blown? Give your answer to three significant figures.
Answer:
P V = N R T
P1 V1 = P2 V2 assuming N, R, and T remain constant
V1 = (P2 / P1) V2
V1 = (2 kPa / 4 k Pa) 3.5 m3
V1 = 3.5 m^3 / 2 = 1.75 m^3
some properties of the particles that are sources of electric charge include
Do distance and Gravity have a _____ relationship?
Answer:
proportional...?
Explanation:
not sure if thats correct...
hope this helped tho
try your best!
mark me brianliest :D
Find the number of moles in a 28.0g sample of NH3.
PLS URGENTLY
Answer:
Molar mass of NH3=14+3=17g
[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]
BRAINLIST
A 12 N force is used to extend a spring with a spring constant of 84 N/m. Calculate the extension of the spring.
Answer:
72n
Explanation:
Almost all living things depend on the process of ____________________ to supply them with the energy they need.
A.
photosynthesis
B. heterotroph
11. A box with a mass of 1.0 kg is resting on a horizontal surface and the coefficient of friction between the block and the surface is 0.20. It is accelerated by attaching a 1.5 kg mass, as shown in the diagram. Assume that the pulley is frictionless and that the cord has negligible mass.
a. What is the acceleration of the box? What is the tension?
Answer:
We know that the force pulling the box in the positive x direction has a magnitude of m g sin 30 . Using Newtons Second Law, F = ma , we just need to solve for a :
ma=mgsin30
a=gsin30
=(10m/s2)(0.500)
=5m/s2
Answer:
A force is applied acting to the right. Assume that friction is negligible. Ikg 0.5N. For each question, one or more features of the system.
Explanation:hope this helps
Which object has the most thermal energy?
A. A 6 kg rock at 10°C
B. A 10 kg rock at 10°C
C. A6 kg rock at 15°C
D. A 10 kg rock at 15°C
Answer:
D is the answer
Explanation:
D is the most highest one so
the answer is D
Answer:
10 kg rock at 15 degrees celcius
is the amplitude just 2? Or do I combine all of them and do 6?
Answer:
combine them all
6 m
Explanation:
Imagine a monkey is sitting inside a barrel turned on its side. A cruel elephant pushes the barrel down a hill and the monkey starts to roll inside the barrel. This particular monkey gets motion sickness, and an outside observer has noticed that if the monkey spins more than once per second, the monkey will likely vomit. The barrel rolls perfectly down the slope (without slipping) and the outside observer calculates the angular acceleration of the barrel to be 1.2rad/s2. The barrel has a diameter of 1.5 m.
(a) How long will it take for the monkey to spin fast enough to vomit? (b) How far will the monkey have rolled before vomiting?
(c) How many times will the monkey have made a complete circle before vom- iting?
Hi there!
We can begin by converting "spinning once per second" to angular velocity:
[tex]\frac{1rev}{1s} * \frac{2\pi rad}{1rev} = 2\pi rad/sec[/tex]
(a)
As we are given the angular acceleration, we can calculate the time using the following equation:
ωf = ωi + αt
There is an initial angular velocity of 0 rad/sec, so:
ωf = αt
2π/1.2 = t
t = 5.236 sec
(b)
We can use the following rotational kinematic equation to first solve for the angular displacement:
θ = ωit + 1/2αt²
The initial velocity is 0 rad/sec, so plug in values:
θ = 1/2(1.2)(5.236²)
θ = 16.449 rad
Convert to linear distance using the following:
d = θr
d = 1.5m, so r = 1.5/2 = 0.75m
d = 16.449(0.75) = 12.337m
(c)
Find the amount of revolutions by converting radians to revolutions:
[tex]16.449 rad * \frac{1rev}{2\pi rad} = \large\boxed{2.618 rev}[/tex]
OR, 2.618 times.
For a boiling kettle draw a sankey diagram to show where The energy goes
Answer:
draw the picture / (.) (.) \ Patrick star
The time (t) required to empty a tank varies inversely as the rate (r) of pumping. If a
pump can empty a tank in 3 hours at a rate of 400 gallons per minute, how long will it
take to empty a tank at 600 gallons per minute?
Answer:
T = C / R t = time, C =constant of proportionality, R = rate
180 min = C / 400 gal/min
C = 72000 gal to empty tank
T = 72000 gal / 600 gal/min = 120 min = 2 hrs
Is s=[tex]\frac{Ft^{2} }{2m}[/tex] a correct conversion from a=[tex]\frac{at^{2} }{2}[/tex]?
I just substituted "a" as [tex]\frac{F}{m}[/tex]
Answer:
well your substitution method is correct but make sure to double check the original formula
how many cubic objects of volume 2cm cube can be started in a room of dimension 2m by 3m by 4m
Answer:
12,000,000 boxes
Explanation:
the volume of the room can be found by using the equation for volume of a rectangular box:V=LxWxH
where:
L=2m
W=3m
H=4m
(it doesn't really matter which is which since it is multiplication)
when we multiply our values (2m*3m*4m) we get 24cubic meters
now we need to convert cubic meters to cubic centimeters
each cubic meter is 1,000,000 cubic centimeter we multiply 24 by 1,000,000 and we get: 24,000,000 cubic centimeters (cc)
dividing 24,000,000 by 2 (since each box is 2cc) we get 12,000,000
so, we know we can fit 12,000,000, 2 cubic centimeter boxes in this room
PLEASE PLEASE PLEASE HELP ME!!!
Answer: Levers
Explanation: Levers lifte
the machines arm
A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.
PLEASE ANSWER ASAP!!
Which part of the graph represents how much energy the reactants need to gain to become products? F Potential energy HA Н G Reaction progress
A. H minus F
B. H
C. G
D. F
(NO LINKS)
A cyclist pedals up to the top of a hill.
a) What kind of energy is being used to do work against gravity?
b) State the type of energy the cyclist has when he stops at the top of the hill.
c) When the cyclist moves downhill without pedaling, what type of energy does he gain?
Explanation:
A) kinetic energy
B) potential energy
C) Mechanical energy
a) The motorcyclist rises utilising chemical energy's "mechanical energy" (kinetic and potential energy). b) The cyclist's highest "gravitational potential energy" is transformed into motion downhill. c) When the rider moves downhill, potential energy becomes "kinetic energy." "Kinetic energy" is most vital.
a) "Mechanical energy" is used by the cyclist to ride up the slope. Kinetic and potential energy from an object's motion and position make up mechanical energy. As they pedal, cyclists transform chemical energy from their bodies into mechanical energy. This mechanical energy overcomes gravity as the cyclist climbs. As the cyclist climbs, potential energy accumulates, which is translated into kinetic energy as they descend.
b) At the summit of the slope, the biker has "gravitational potential energy." An object's gravitational potential energy depends on its position in a gravitational field. The biker has gained potential energy by climbing against gravity. At the crest of the hill, the cyclist's kinetic energy is lowest while potential energy is highest. The cyclist's potential energy is ready to be turned into kinetic energy as they descend.
c) Without pedalling, the rider gains "kinetic energy." The cyclist's speed increases as they descend, converting potential energy into kinetic energy. The cyclist's potential energy is turned into kinetic energy by gravity. As the rider descends, their potential energy diminishes but their kinetic energy increases, speeding up their bike. The biker converts potential energy into kinetic energy as he descends, and most of it is converted back at the bottom.
In conclusion, the cyclist climbs the incline using "mechanical energy" from chemical energy. They descend using "gravitational potential energy" at the top. Potential energy becomes "kinetic energy" when the rider descends without pedalling, speeding up the bike. Potential-to-kinetic energy conversion helps the cyclist climb the slope.
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Does a moving charge experiences a force in magnetic field? Explain
please answer this don't go on the one which is choosed coz i bymistakely choosed it
Answer:
(B) B is travelling fastest
Explanation:
slope of xt graph = speed.
Slope of B is greater than a and c.
BRAINLIST PLS
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
Andrew skis down a hill.
Andrew starts from the top of the hill and his speed increases as he goes downhill.
He controls his speed and direction by using his skis.
He brings himself to a stop at the bottom of the hill.
Describe the energy changes that happen between starting and stopping.
Explanation:
gravitational potential energy at the top of the hill, which transforms into kinetic energy as he moves bottom of the hill
that's mean potential energy transfoms into kinetic energy
His potential energy is converted into kinetic energy when his speed increases as he goes downhill.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
Total mechanical energy is s the sum of all the kinetic as well as potential energy stored in the system.
ME = KE + PE
When Andrew skis down a hill then he had stored potential energy due to the height of the hill and his gravitational weight,
Due to the height of the slope and his weight, Andrew had potential energy stored when he skied down it.
As he descended the hill, his speed increased, transforming this potential energy into kinetic energy.
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3. What happens if an object has a negative acceleration?
Answer:
They will go backwards?
Explanation:
If positive they go forward but is negative they go backwards.
The student investigates how the resistance of a thermistor varies with temperature. The student has a power supply, a thermistor, an ammeter, a voltmeter and some connecting leads. Describe an investigation the student could carry out to measure the resistance of a thermistor between –10 °C and 70 °C.
Your answer should include:
1. Any other apparatus the student will need
2. The measurements to be taken
3. How the data should be processed.
(This question is worth 6 marks on my assignment so I just really want to get down the best possible answer for it.)
The characteristics of the thermistors allow to design an experiment to analyze the dependence of resistance with temperature;
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
A Thermitor is an element whose resistance changes with temperature, for example a platinum resistance.
An experiment that we can carry out to measure is to set up the attached circuit where we have:
A DC power supply. A resistor to control the maximum current in the circuit and avoid thermal problems in the thermistor. A thermistor. A thermometer placed next to the thermistor. A source of heat under the thermistor under a glass with ice and water, but without affecting the other elements of the circuit.
Let's start by looking for the current in the circuit.
In thermistors, the resistance for room temperature is given, so if we measure the voltage across the fixed resistor, we can shrink the voltage across the thermistor.
[tex]V_{source} = V_R + V_{therm} \\V_{therm} = V_{source} - V_R \\ i = \frac{V_{therm} }{R_{therm}}[/tex]
This current remains fixed, since the fixed resistance is greater than the resistance of the thermistor throughout the range.
Second step.
Now we can change the temperature that is measured in the thermometer, for each temperature the voltage in the fixed resistance is measured, the resistance in the thermistor is calculated.
[tex]R_{therm} = \frac{V_{source} - V_R}{i}[/tex]
Third step.
We end with a graph of resistance versus temperature of the curve obtained, it is possible to understand the behavior of the resistance of the thermistor with temperature.
In conclusion with the characteristics of thermistors we can design an experiment to analyze the dependence of resistance with temperature:
1) We set up the circuit
2) We look for the current of the circuit and we keep it fixed.
3) We look for the thermistor resistances for each temperature.
4) Plot Resistance versus Temperature.
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More potential energy can be stored by moving against the magnetic force closer to a magnet?
Answer:
if your saying can it? then yes or if you are asking what type of magnetic force then its fr its actual self magnetic force
Explanation:
A ceiling fan is turned on and reaches an angular speed of 120 rev/min in 20 s. It is then turned off and coasts to a stop in an additional 40 s. In the one minute of rotation, through how many revolutions did the fan turn?.
Hi there!
We can first find the angular displacement of the first 20 seconds by finding the angular acceleration.
Begin by converting 120 rev/min to rev/sec:
120 rev/min × 1 min/60 sec = 2 rev/sec
ω = αt
2 = 20α
α = 0.1 rev/sec²
θ = ωit + 1/2αt²
The fan starts from rest, so:
θ = 1/2αt²
θ = 1/2(0.1)(20²) = 20 revolutions
Now, for the next 40 seconds, we can find the fan's deceleration:
ωf = ωi + αt
0 = 2 + αt
-2 = 40α
α = -0.05 rad/sec²
Use the above equation:
θ = ωit + 1/2αt²
θ = 2(40) + 1/2(-0.05)(40²) = 80 - 40 = 40 rev
θ = 4800 - 2400 = 2400 revolutions
Add the two:
θtotal = 20 + 40 = 60 revolutions
what makes us think that the star system cygnus x-1 contains a black hole?
Answer:
Explanation:
What makes us think that the star system Cygnus X-1 contains a black hole? It emits X-rays characteristic of an accretion disk, but the unseen star in the system is too massive to be a neutron star.
A 100 kg roller coaster comes over the first hill at 2 m/sec (vo). The height of the first hill (h) is 20 meters. See roller diagram below.
1) Find the total energy for the roller coaster at the initial point.
2) Find the potential energy at point A using the PE formula.
3) Use the conservation of energy to find the kinetic energy (KE) at point B.
4) Find the potential energy at point C.
5) Use the conservation of energy to find the Kinetic Energy (KE) of the roller coaster at point C.
6) Use the Kinetic Energy from C, find velocity of the roller coaster at point C.
For the 100 kg roller coaster that comes over the first hill of height 20 meters at 2 m/s, we have:
1) The total energy for the roller coaster at the initial point is 19820 J
2) The potential energy at point A is 19620 J
3) The kinetic energy at point B is 10010 J
4) The potential energy at point C is zero
5) The kinetic energy at point C is 19820 J
6) The velocity of the roller coaster at point C is 19.91 m/s
1) The total energy for the roller coaster at the initial point can be found as follows:
[tex] E_{t} = KE_{i} + PE_{i} [/tex]
Where:
KE: is the kinetic energy = (1/2)mv₀²
m: is the mass of the roller coaster = 100 kg
v₀: is the initial velocity = 2 m/s
PE: is the potential energy = mgh
g: is the acceleration due to gravity = 9.81 m/s²
h: is the height = 20 m
The total energy is:
[tex] E_{t} = KE_{i} + PE_{i} = \frac{1}{2}mv_{0}^{2} + mgh = \frac{1}{2}*100 kg*(2 m/s)^{2} + 100 kg*9.81 m/s^{2}*20 m = 19820 J [/tex]
Hence, the total energy for the roller coaster at the initial point is 19820 J.
2) The potential energy at point A is:
[tex] PE_{A} = mgh_{A} = 100 kg*9.81 m/s^{2}*20 m = 19620 J [/tex]
Then, the potential energy at point A is 19620 J.
3) The kinetic energy at point B is the following:
[tex] KE_{A} + PE_{A} = KE_{B} + PE_{B} [/tex]
[tex] KE_{B} = KE_{A} + PE_{A} - PE_{B} [/tex]
Since
[tex] KE_{A} + PE_{A} = KE_{i} + PE_{i} [/tex]
we have:
[tex] KE_{B} = KE_{i} + PE_{i} - PE_{B} = 19820 J - mgh_{B} = 19820 J - 100kg*9.81m/s^{2}*10 m = 10010 J [/tex]
Hence, the kinetic energy at point B is 10010 J.
4) The potential energy at point C is zero because h = 0 meters.
[tex] PE_{C} = mgh = 100 kg*9.81 m/s^{2}*0 m = 0 J [/tex]
5) The kinetic energy of the roller coaster at point C is:
[tex] KE_{i} + PE_{i} = KE_{C} + PE_{C} [/tex]
[tex] KE_{C} = KE_{i} + PE_{i} = 19820 J [/tex]
Therefore, the kinetic energy at point C is 19820 J.
6) The velocity of the roller coaster at point C is given by:
[tex] KE_{C} = \frac{1}{2}mv_{C}^{2} [/tex]
[tex] v_{C} = \sqrt{\frac{2KE_{C}}{m}} = \sqrt{\frac{2*19820 J}{100 kg}} = 19.91 m/s [/tex]
Hence, the velocity of the roller coaster at point C is 19.91 m/s.
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2. Un niño hace girar con la mano una pelota de hule que se encuentra sujeta mediante un cordón de
0.75 m de longitud. Si la pelota da 0.7 vueltas a cada segundo, entonces,
a) ¿Cuál es el periodo de la pelota?
b) ¿Cuál es la velocidad lineal de la pelota?
Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:
a) El periodo de la pelota es 1.43 segundos.
b) La velocidad lineal de la pelota es 3.3 m/s.
a) El periodo de la pelota está dado por:
[tex] T = \frac{2\pi}{\omega} [/tex]
En donde:
ω: es la velocidad angular
Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:
[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]
Entonces, el periodo es:
[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]
b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:
[tex] v = \omega r [/tex]
En donde:
r: es el radio de la circunferencia = longitud del cordón = 0.75 m
[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]
Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.
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What is the equation for density?
O D= m
V
O D= V
-
m
O D= m
O D= { mu?
2