The vertical force is given as 735.75 N
How to solve for the vertical forceGiven that there is no friction existing between the wall and the ladder, we would have
w - n = 0
w is the weight of thios ladder
while N is the vertical force that acts on it
n = w
the formula for n = mg
this is mass of ladder * the gravitational constant
= 75.0 kg ladder * 9.81
= 735.75 N
written as substituting the weight of the ladder, W = 75.0 kg * 9.81 m/s^2 = 735.75 N
Therefore the vertical force is givem as 735.75 N
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Block A (mass = 5 kg) with an initial velocity of 10 m/s right, collides with block B (mass = 10 kg) which is at rest. The final velocity of B is 6 m/s right. What is the final velocity (magnitude and direction) of A? The surface is frictionless.
The final velocity of block A is -2 m/s to the left ( in the opposite direction of its initial velocity).
What is velocity?Quantity that designates how fast and in what direction a point is moving is known as velocity.
As we know, m_A * v_Ai + m_B * v_Bi = m_A * v_Af + m_B * v_Bf
m_A and m_B are the masses of blocks A and B, v_Ai and v_Bi are their initial velocities, and v_Af and v_Bf are their final velocities.
5 kg * 10 m/s + 10 kg * 0 m/s = 5 kg * v_Af + 10 kg * 6 m/s
50 kgm/s = 5 kg * v_Af + 60 kgm/s
-10 kg*m/s = 5 kg * v_Af
So, v_Af = -2 m/s
Therefore, the final velocity of block A is -2 m/s to the left (i.e., in the opposite direction of its initial velocity).
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A 0.300 kg mass is attached o a 26.6 N/m spring. It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m from equilibrium? ( Unit - J) (It's not 0.144 J)
The potential energy of the mass is 0.0452 J when it is at a distance of
0.0600 m from equilibrium.
How to calculate potential energy?
The potential energy stored in a spring when it is stretched or compressed by a displacement x is given by:
[tex]$PE = \frac{1}{2}kx^2$[/tex]
where k is the spring constant.
In this problem, the spring constant is given as 26.6 N/m, and the displacement of the mass from equilibrium is
[tex](0.120 m - 0.0600 m) = 0.0600 m.[/tex]
Therefore, the potential energy stored in the spring when the mass is at a distance of 0.0600 m from equilibrium is:
[tex]$PE = \frac{1}{2}kx^2 = \frac{1}{2}(26.6 N/m)(0.0600 m)^2 = 0.0452 J$[/tex]
So the potential energy of the mass is 0.0452 J when it is at a distance of 0.0600 m from equilibrium.
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Answer: 0.0479
Explanation: This answer works for Acellus! :D
hope this helps!
A piece of clay flies off a pottery wheel and sticks to a potter walking by.
The initial momentum of the clay was 3.0 kg.
m
and the initial
m
momentum of the potter was -85 kg
kg.
FUSORE
ku
m
PREDME
S
-
What is the final momentum of the artist-clay system immediately after
the collision?
Your answer should have two significant figures.
S
The final momentum of the artist-clay system immediately after collision is -82 kgm/s.
How to calculate final momentum?Assuming that the initial momentum of the clay was 3.0 kgm/s and the initial momentum of the potter was -85 kgm/s, we can use the law of conservation of momentum to find the final momentum of the artist-clay system immediately after the collision:
Initial momentum = Final momentum
(3.0 kgm/s) + (-85 kgm/s) = Final momentum
-82 kg×m/s = Final momentum
Therefore, the final momentum of the artist-clay system immediately after the collision is -82 kgm/s.
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A pulley system is used to lift a 2000 N grand piano a distance of 3 meters. The mover applies 300 N of force in the process. a) Calculate the mechanical advantage of the pulley system. b) How much work does the machine do? c) If the mover pulls 27 meters of rope to lift the piano, how much work does he do? d) What is the efficiency of the pulley system?
a) 7 b) 6000 J c) 8000 J d) 75%
a) 9 b) 3000 J c) 6000 J d) 55%
a) 4 b) 3000 J c) 9000 J d) 85%
a) 14 b) 8000 J c) 6000 J d) 75%
How is it possible for a tree to survive if the inner part is missing?
It is not possible for a tree to survive if the inner part of the tree is missing. This is because, the inner part of the tree is vital for survival and health.
What is a tree?Trees are the plants which carry out the life processes that all plants share on the planet. It is not possible for a tree to survive without the inner part. If the entire inner part is missing, including the heartwood and sapwood, is missing. The inner part of a tree is vital to the survival as well as the health, as it is responsible for the transportation of water, nutrients, and sugars between the root and the leaves.
However, it is possible for a tree to survive if only some part of the inner part is missing. Trees have a remarkable ability to compartmentalize the damage and decay, which means that they can wall off or can isolate the injured or infected parts of the tree for the prevention of the spread of damage to the rest of the tree.
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2. Given the displacement vectors A = 3i-1j+4k, B = 2i+ 3j - 0k. Find the magnitudes of the vectors a) A + 1B b) 2A - B
The magnitudes of the vectors (A+1B) and (2A - B) would be 6.71 and 10.25 respectively
Vector operationa) The vector A + B can be found by adding the corresponding components of A and B:
A + B = (3i - 1j + 4k) + (2i + 3j - 0k) = 5i + 2j + 4k
The magnitude of A + B is:
|A + B| = sqrt((5)^2 + (2)^2 + (4)^2) = sqrt(45) ≈ 6.71
b) The vector 2A - B can be found by multiplying the components of A and B by the appropriate scalar values and then subtracting:
2A - B = 2(3i - 1j + 4k) - (2i + 3j - 0k) = 6i - 2j + 8k - 2i - 3j = 4i - 5j + 8k
The magnitude of 2A - B is:
|2A - B| = sqrt((4)^2 + (-5)^2 + (8)^2) = sqrt(105) ≈ 10.25
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A thin rod with length 4.5 m is sitting with one end at the origin. The rod has a non-uniform density that has a quadratic dependence. You know the density at three points. The density of the rod is 3.0 kg/m at the origin, 11.0 kg/m at the other end of the rod, and 3.0 kg/m halfway in between.
How far from the origin is the center of mass of the rod located?
The density of the rod is 3.0 kg/m at the origin,then the center of mass of the rod is located 2.15 m from the origin.
What is center of mass?The center of mass is the point in an object or system of objects where the mass of the object or system can be considered to be concentrated. In other words, it is the point in which an object or system can be balanced and behaves as if all the mass is concentrated at that point.
Evaluating :To find the center of mass of the rod, we need to integrate the product of the density and position of each infinitesimal element of the rod, divided by the total mass of the rod.
We can express the position of each element as x, where x=0 at the origin and x=4.5 m at the other end of the rod.
Let's start by finding the total mass of the rod. We can divide the rod into two parts: one from the origin to the midpoint, and the other from the midpoint to the other end. The mass of each part can be found by integrating the density over its length:
m₁ = ∫(0 to 2.25) 3x² dx = 15.19 kg
m₂ = ∫(2.25 to 4.5) (22.5x - 45.375) dx
= 95.63 kg
The total mass of the rod is then derived as follows:
m = m₁ + m₂ = 110.82 kg
We can now evaluate the location of the centre of mass. We can express the position of the center of mass as xcm, where x=0 at the origin and x=4.5 m at the other end of the rod.
We can use the formula:
xcm = (1/m) ∫(0 to 4.5) ρ(x) x dx
where (x) represents the density at position x.
We can express the density as a quadratic function of x:
ρ(x) = ax² + bx + c
Using the given values of density at the origin, midpoint, and other end, we can solve for the coefficients a, b, and c:
c = 3
a + b + c = 11/4.5
= 2.44
4a + 2b + c = 3
Solving these equations gives:
a = -1.96 kg/m³
b = 7.33 kg/m²
Now we can plug in the expression for ρ(x) and evaluate the integral:
xcm = (1/m) ∫(0 to 4.5) (-1.96x⁴ + 7.33x³ + 3x) dx
Evaluating this integral gives:
xcm = 2.15 m
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What is the proposed method for plate movement?
The movement of plates is explained by the theory of plate tectonics, which proposes that the Earth's lithosphere (made up of rigid plates) moves slowly over the underlying, more fluid asthenosphere due to the circulation of heat from the Earth's interior
What is Tectonics Plates?
Tectonic plates are large pieces of the Earth's lithosphere (made up of the crust and uppermost part of the mantle) that move around on the underlying asthenosphere, a more fluid layer of the mantle. The lithospheric plates are rigid and brittle, and they move in response to forces generated by the circulation of heat in the Earth's interior. The movement of the plates causes many geological features such as mountains, volcanoes, earthquakes, and oceanic trenches.
There are several major and minor tectonic plates, including the Pacific Plate, the North American Plate, the African Plate, the Eurasian Plate, and the Antarctic Plate. These plates interact with each other at their boundaries, which can be divergent (moving apart), convergent (moving towards each other), or transform (sliding past each other).
The lithospheric plates move apart at divergent boundaries, collide at convergent boundaries, and slide past each other at transform boundaries. These interactions at the boundaries cause many geological features such as volcanoes, mountain ranges, and earthquakes. The plate tectonics theory has been supported by various lines of evidence, including the study of earthquakes, magnetic anomalies, and the distribution of fossils and rocks around the world.
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All of the following describe the region in which an electron is most likely to be found
EXCEPT
orbital
isotope
cloud
path
All of the following describe the region in which an electron is most likely to be found except an isotope. Thus, the correct option is B.
What is an isotope?Isotopes can be defined as the distinct nuclear species of the same element. They have the same atomic number and the position in the periodic table as the main atom, however they differ in number of nucleons due to different numbers of neutrons in their nucleus.
Orbital is a volume of space present within an atom where an electron is most likely to be found. The s-orbitals are spherical in shape.
Cloud is the region present near the nucleus where the probability of finding an atom is highest. Cloud are the region of negative charge.
Path can also be defined as orbital. It is the exact route in which the electrons travel in an atom.
Therefore, the correct option is B.
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very important!!!
A drilling rig performs 5.15∗105 J of work at an average power output of 3940 W. How long does it take the drill to perform this work?
540 s
916 s
244 s
131 s
Answer:131s
Explanation:
time = 5.15*10^5 J / 3940
Suppose a small comet was on a path to collide with Earth. Its density is 0.5 g/cm3 (500 kg/m3 ). Earth’s radius is 6378 km and Earth’s density is about 5500 kg/m3 (5.5 g/cm3 ). At what height would it disintegrate? (3) Hint: the Roche limit = 2.5 [(density of planet)/(density of moon or other object)]1/3 (radius of planet)
The comet will disintegrate at a height of 70,479,900 m.
Comet's height problemTo find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.
Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)
Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:
density of planet = 5500 kg/m^3
density of moon or other object = 500 kg/m^3
radius of planet = 6378 km = 6,378,000 m
Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)
Roche limit = 76,857,900 m
This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.
Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.
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A force, F, acts horizontally on a stationary mass, m, on a horizontal, frictionless surface. After a displacement of one metre, the mass has a velocity v. If a force 2F acts for the same displacement on a mass 1/2m, initially at rest on the same surface, what velocity will the second mass have?
The second mass will have a velocity of v² = 4√F of the force, F. Since the displacement and the force are the same in both cases
What is frictional force?Frictional force is a force that opposes motion between two surfaces in contact. When two surfaces are in contact, there are microscopic irregularities that prevent them from sliding over each other easily. As a result, a force is required to overcome this resistance and move one surface over the other.
The frictional force between two surfaces depends on several factors, including the type of surfaces in contact, the force pressing the surfaces together (normal force), and the presence or absence of lubrication.
According to the work-energy principle, the work done by a force on an object is equal to the change in the object's kinetic energy. This principle can be used to solve the problem.
For the first case, the work done by the force F is:
W = Fd
where d is the displacement of the mass. This work is equal to the change in kinetic energy of the mass:
W = ΔK
where ΔK = (1/2)mv² - 0 is the change in kinetic energy, since the mass starts from rest.
Combining these equations, we get:
Fd = (1/2)mv²
For the second case, the work done by the force 2F is:
W = 2Fd
This work is equal to the change in kinetic energy of the mass:
W = ΔK
where ΔK = (1/2)(1/2)m v₂² - 0 is the change in kinetic energy, since the mass starts from rest.
Combining these equations, we get:
2Fd = (1/4)mv₂²
Solving for v², we get:
v² = √(8Fd/m)
Since the displacement and the force are the same in both cases, we can substitute the first equation into the expression for v²:
v² = √(8F(1 m)/(1/2m))
v² = √(16F)
v² = 4√F
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A washing machine spins its tube at a rate of 1200 rps . if the tube diameter is 35cm . find velocity of the 1 m of the tube
The rotation per second of the spin of the tube is 1200 rps. The diameter of the tube is 35 cm or 0.35 m. Then, its velocity is 1308 m/s.
What is angular velocity ?Angular velocity is a physical quantity that is the rotational analogue of the linear velocity. The angular velocity of an object is the velocity of rotation that is distance covered by one rotation per second.
Given number of rotations = 1200 rotation per second
circumference of the tube = 2 π r = πd
c = 3.14 × 0.35 m = 1.09 m.
It means that, for one rotation, the tube covers a distance of 1.09 m. In one second it spins 1200 times.
Hence, the total distance travelled in one second = 1200/s × 1.09 m = 1308 m/s.
Therefore, the velocity of the 1 m tube is 1308 m/s.
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rr x rr what percentage of offsping will be round?
In a genetic cross Rr x rr the percentage of offspring will be round will be 50% since this trait is associated with the recessive genotype (rr).
What is the recessive genotype in a genetic cross?The recessive genotype in a genetic cross is the proportion of offspring that will be homozygous recessive and therefore will express the recessive trait such as in this case round plants that are produced by the combination of recessive and heterozygous parents.
Therefore, with this data, we can see that recessive genotypes in a genetic cross are generated by the combination of two recessive gametes.
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How can a hockey puck explain the transfer of kinetic energy? **Select all that apply.**
A. Kinetic energy transfers through air when materials are close.
B. Kinetic energy is lost when it transfers between materials.
C. Energy transfers from materials through touch.
D. Kinetic energy can move from one item to another.
How is the kinetic energy of the measured velocity compared to the predicted kinetic energy based on the height of the
release? Explain any possible reason for the discrepancy.
The object's kinetic energy, in contrast to potential energy, is relative to other fixed and moving things that are present inside its immediate vicinity.For instance, if the item is positioned at a higher height, its kinetic energy will be higher.
Why then does kinetic energy drop down as height increases?As height is reduced, potential energy is reduced as well.If height lowers, the kinetic energy for a freefall similarly reduces.That is as a result of the shorter distance to be traveled.
How do height and energy relate to one another?A doubling in height will lead to a doubling in gravitational potential energy since an object's gravitational potential energy is directly proportionate to its height above the zero point.The potential energy of gravity will triple with a tripling of height.
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If a machine is perfect, the mechanical advantage will be ....... the velocity ratio.
greater than
less than
equal to
none of these
Answer:
Equal to
Explanation:
work output is equal to the work input, so the efficiency is equal to 1 ( or 100% ) and the mechanical advantage is numerically equal to the velocity ratio. So, M.A. = V.R.
Approximately how quickly does sound cover 1 kilometre?
a) Instantly
b) 1 second
c) 2 seconds
d) 3 seconds
Answer:
3 second is the answer of your question
What is the mass of an object that requires 15 n to accelerate at a rate of 1. 5 m/s/s?.
Answer:
Explanation:
Force = mass*acceleration
15=mass*5
mass=3kg
Third Law of Motion
For every action, there is an equal and opposite reaction .
I hate physics ! Hope you guys can help !
Answer: NEWTONS FIRST LAW
One's body moves to the side when a car makes a sharp turn.
Tightening of seat belts in a car when it stops quickly.
A ball rolling down a hill will continue to roll unless friction or another force stops it.
If pulled quickly, a tablecloth can be removed from underneath dishes.
NEWTONS SECOND LAW
1· Try to move an object.
2· Pushing a car and a truck.
3· Racing Cars.
4· Rocket launch.
5· Kick the ball.
6· Car crash.
7· Two people walking.
8· Object thrown from a height
Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing on the pedals of your bicycle is the force.
NEWTONS THIRD LAW
Examples
The recoil of a Gun. ...
Swimming. ...
Pushing the Wall. ...
Diving off a Raft. ...
Space Shuttle. ...
Throwing a Ball. ...
Walking. ...
Hammering a Nail.
More items...
Common examples of newton's third law of motion are: A horse pulls a cart, a person walks on the ground, a hammer pushes a nail, and magnets attract paper clips. In all these examples a force is exerted on one object and that force is exerted by another object.
Which of the following cannot used to describe a wave?
a) Frequency
b) Height
c) Speed
d) Wavelength
Answer:
speed
Explanation:
speed
Rank the following systems in order of increasing speed of the corresponding wave. Indicate ties where appropriate.
Answer:
the answer can be A because based on what I know every increasing stars from 1 to the biggers numbers
Please help (50 points and Brainly)
The work done on the ship by the tugboat is calculated as 15,000,000 joules.
What is force?Force can be a push or a pull but always with magnitude and direction.
The work done on the ship is given by the equation as : work = force × distance × cos(Ф)
force is the constant horizontal force applied by tugboat, distance is distance moved by ship, and theta is angle between force and direction of motion of the ship. In this case, Ф is zero because the force is in same direction as the motion of ship.
Thus, we calculate the work done on the ship as: work = 5000 N × 3000 m × cos(0)
work = 15,000,000 joules
Therefore, the work done on the ship by the tugboat is 15,000,000 joules.
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At what angle should a circular road be banked so that a car running at 50 Km/hr be safe to go round the circular turn of 200 m radius?
Angle of 5.61° should be banked so that car running at 50 Km/hr be safe to go round the circular turn of 200 m radius.
What is Banking of Road?The process of raising outer edge of the road over its inner edge through certain angle θ is called as banking of road. Banking of road is nothing but the process of making the angle between the surface of road to horizontal surface of the road. The angle made by this two surfaces is called as angle of banking. Banking of road is done for safe turn at high speed.
Angle of banking is given by the formula,
tanθ = v²÷Rg
Where θ = angle of banking
R = Radius of circular turn
g = acceleration due to gravity
Given,
velocity of the car v = 50km/hr = 13.88 m/s
Radius of the circular orbit = 200 m
From formula,
tanθ = 13.88² ÷ (200×9.8)
tanθ = 0.09829
θ = tan⁻¹(0.09829)
θ = 5.61°
Hence angle must be backed at 5.61° to have safe turn.
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A car whose weight Fw is on an incline that makes an angle theta with the horizontal.How large a perpendicular force does the incline exert on the car
The perpendicular force exerted by the incline on the car is Fw cosθ.
What is normal reaction force ?Normal reaction force is defined as a contact force that is exerted by the surface on an object which is in contact with it. It prevents the object from passing through the surface.
Here,
Weight of the car is Fw
The incline makes an angle θ with the horizontal.
From the figure,
The perpendicular force exerted by the incline, N = Fw cosθ
Hence,
The perpendicular force exerted by the incline on the car is Fw cosθ.
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What is the acceleration on a body that approached the earth and comes within 6
earth radii of the earth’s surface?
The acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2 m/s².
How can we calculate the acceleration of the body?The acceleration of the body can be calculated using the equation-
g = g0 R/(R + H)².
In the question, we have, h = 6R
g = 9.8 x R/(R + 6R)²
By putting in the values and calculating, we get,
g = 0.2 m/s².
What causes a body to accelerate when the earth attracts it?Where g' = Gravitational Acceleration at Height, R = Earth's Radius, and g = Gravitational Acceleration at Earth's Surface. As a result, at a distance of 2R from the earth's surface, the acceleration of a body caused by the earth's attraction is equal to g/9.
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Assume the blue is a string and the orange is a meterstick. At the 50.1 cm mark, is there a pivot? Yes or No. Explain why
25 Point Emergency!!! Absurd answers will cause you're answer, and account, to be reported.
On a certain planet, a 4950 kg rock weighs 22,030 N. If this planet has a radius of 4200 km, what is the mass of the planet?
1.18∗10^24 kg
4.51∗10^24 kg
1.92∗10^25 kg
3.06∗10^25 kg
Answer:
F = G M1 M2 / R^2 attraction between 2 masses
M1 = F R^2 / (G M2)
M1 = 2.20E4 * (4.2E6)^2 / (6.67E-11 * 4.95E3) kg
M1 = 2.2 * 4.2^2 / (6.67 * 4.95) E24
M1 = 1.18E24 kg
Starting from rest, a 32.2 kg child rides a 9.00 kg sled down a frictionless ski slope. At the bottom of the hill, her speed is 6.8 m/s. If the slope makes an angle of 16.9° with respect to the horizontal, how far along the hill did she slide on her sled?
To solve this problem, we can use conservation of energy:
Initial mechanical energy (at the top of the hill) = final mechanical energy (at the bottom of the hill)
Initial mechanical energy = mgh, where m is the total mass of the child and sled, g is the acceleration due to gravity (9.8 m/s^2), and h is the vertical height of the hill. Since the hill makes an angle of 16.9° with respect to the horizontal, we can use trigonometry to find the height:
h = (length of slope) * sin(16.9°)
We don't know the length of the slope, but we can solve for it by using the final speed of the child and sled:
Final mechanical energy = (1/2)mv^2, where v is the final speed of the child and sled.
Setting these equal, we get:
mgh = (1/2)mv^2
Substituting for h and solving for the length of the slope:
(length of slope) = v^2 / (2g*sin(16.9°))
Plugging in the given values:
(length of slope) = (6.8 m/s)^2 / (29.8 m/s^2sin(16.9°)) ≈ 12.5 meters
Therefore, the child and sled slide about 12.5 meters along the slope.
PLEASE HELP EXPERTS
Developing camaraderie, paying attention, and taking part in training are all ways to:
A. Professionally Communication Online
B. Problem solve
C. Avoid making work mistakes
D. Important
E. Vital Functions
E. Vital Functions of a Team. Developing camaraderie is an important part of creating a team atmosphere, as it helps team members to learn to trust and rely on each other.
What is atmosphere ?Atmosphere is the layer of gases that surrounds the Earth. It is composed of roughly 78% nitrogen, 21% oxygen, and 1% other gases, such as argon, carbon dioxide and water vapor. The atmosphere protects the Earth from harmful ultraviolet radiation from the sun, shelters us from extreme temperatures, and creates the air pressure that allows us to breathe. The air we breathe is a mixture of gases, and the atmosphere also contains dust, smoke and other particles.
Paying attention during training helps to ensure that team members have all the necessary information to be able to perform their duties, while taking part in team activities and training helps to strengthen team bonds and create a sense of unity.
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