A 69.0 N object accelerates to the right at 4.5 m/s^2. What is the normal force acting on the object.

Answer:

theyre used to prevent accidental contact with other conductors of electricity, which might result in an unintentional electric current through those other conductors.

Explanation:

Metal cables are conductor of electricity but plastic rubber coating is insulator and can not conduct current. To avoid unnecessary flow of current and safely current transmission,  this material surrounds the metal cable.

Materials that easily permit the flow of electricity are referred to be electrical conductors. Conductivity is the quality of conductors that enables them to conduct electricity.

Insulators are substances that prevent electrons from freely moving from one elemental particle to another. The charge stays in the same spot and does not spread across the surface if we transfer any quantity of charge to such an element at any time.

Copper, aluminum, gold, and silver are a few examples of common conductors. Wood, rubber, plastic, and glass are a few typical insulators.

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Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

Answer:

I think its the last one

Explanation:

The particles always move perpendicular to the direction of the wave.

Answer:

4 m/s

Explanation:

KE =

Velocity of balloon will be 4 m/s.

!! Hope It Helps !!

Answer:

D

Explanation:

by increasing the distance through which force is applied, by changing the direction of force applied or by multiplying force of speed of the energy applied

Answer:

11.85 k

Explanation:

11.85 k

Answer:

Base

Hope this helps! :)

Answer:

true?

Explanation:

Answer:

The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Explanation:

Given;

average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²

distance traveled by the commercial Jet liner, s = 1542 m

The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;

s = ut + ¹/₂at²

where;

u is the initial velocity of the commercial Jet liner = 0

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²

[tex]t = \sqrt{\frac{2s}{a} } \\\\t = \sqrt{\frac{2 \times 1524}{29.4} } \\\\t = 10.18 \ s[/tex]

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Answer:

Work is defined as force thru a distance:   W = F * S

Power is defined as Work per unit time  P = W / t

So we an write:  P = F * S / t  = 2000 N * 50 m / 5 s = 20,000 N-m/s

Since a Joule/sec is equivalent to a Watt

The power required is 20,000 Watts or 20  Kw

Also, you can convert to Hp since 1 Hp = 746 Watts

Answer:

The choice that correctly identifies the volume of water in the graduated cylinder is option B i.e 35 mL

Explanation:

The complete question is

As a part of a laboratory investigation, Emily measured the volume of water in a graduated cylinder. Which of the choices correctly identifies the volume of water in the graduated cylinder? A. 38 mL B. 35 mL C. 37 mL D. 36.5 mL

The image for the question is attached herewith

Solution

The meniscus formed in this figure is a concave figure and in any concave figure the readings are taken from the bottom of the curve at eye level. In the attached image the bottom of the meniscus at the eye level is marked at 35 mL.

Hence the choice that correctly identifies the volume of water in the graduated cylinder is option B i.e 35 mL

Answer:

It is (a) pull because when we are on earth we have gravity and it is pulling us down hope you have a great day!! :)

Explanation:

Answer:

I only know 3 of them so hope this help!

Integrity And Ethics. Simply put, the two principles of integrity and ethics translate into doing the right thing, in...

Respect. Without dedicated employees, a company is nothing. ... Committed employees form the backbone of the entire...

Innovation (Not Imitation). This is crucial if a company wants to be a...

IF YOU HAVE TIME COME AND VISIT TO MY CHANNRL IN YOU TUBE IT CALLED: It'z Jennie AMV! THANKS!

Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

   Therefore, average speed of the trip = [tex]\frac{\text{Total distance covered}}{\text{Total time taken}}[/tex]

    From the graph attached,

   Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

                                           = 90 meters

   Total time taken = 60 seconds

    Average speed = [tex]\frac{90}{60}[/tex]

                               = 1.5 meter per second

2). Velocity is a vector quantity.

    Therefore, average velocity = [tex]\frac{\triangle d}{\triangle t}[/tex]

                                                   = [tex]\frac{d_{60}-d_0}{60-0}[/tex]

                                                   = [tex]\frac{90-0}{60-0}[/tex]

                                                   = 1.5 meter per second                        

Answer:

, pfx = pix + Jx.

Explanation:

The momentum principle tells us that impulse transfers momentum to an object.

If an object has 2 kgm/s of momentum, a 1 kgm/s impulse delivered to the object

increases its momentum to 3 kgm/s. That is, pfx = pix + Jx.

Just as we did with energy, we can represent this “momentum accounting” with a

momentum bar chart. For example, the bar chart of FIGURE 11.6 represents the ball

colliding with a wall in Figure 11.4. Momentum bar charts are a tool for visualizing

an interaction

Answer:

10,000 N

Explanation:

Given that a rocket pushes exhaust 10, 000 N. Without any other forces acting on the rocket, how much force does the rocket go forward?

Solution

Since there is no any other additional forces, according to Newton's 3rd law of motion which state that:

In every action there will be equal and opposite reaction.

The action expelled by the rocket through its exhaust system is of 10000N.

The reactive force will be equal and opposite which will be same -10,000 N

Therefore, the rocket will go forward with a force of magnitude 10,000 N

Answer:

Because in higher altitudes atmospheric pressure is low

Answer:

b. 2.27 N

Explanation:

Fe = (k)(Q1)(Q2) / d²

k ≈ 9 × 10⁹ N m² / C² [Coulomb's Constant] or 8.98 × 10⁹ (nearest hundredth).

q = particle charge [Coulombs; C]

d = distance [Meters; m]

Fe = Electrostatic force [Newtons; N]

________________________________

Fe = (9×10⁹)(3.5 × 10^(-8)(-4.5 × 10^(-6))/(.25)² N =

(9)(3.5)(-4.5) × (10^(9))(10^(-8))(10^(-6) / (.25)² N =

(9)(3.5)(-4.5) × (10^(9 - 8 - 6)) / (.25)² N =

(-141.75) × 10^(-5) / (.0625) N =

141.75 × 10^(-5) / (.0625) N

[opposite direction] =

(1.4175 × 10^(2)) × 10^(-5) / (.0625) N

[opposite direction] =

1.4175 × 10^(-3) / .0625 N

[opposite direction] =

1.4175 × 10^(-3) / 6.25 × 10^(-2) N =

14.175 / 6.25 N [opposite direction] =

2.268 N ≈ 2.27 N [opposite direction].

Answer:

below

Explanation:

that is the procedure above

Answer:

True

Explanation:

Answer:

A. ls sensitive to heat

this is correct answer

I hope it's helpful for you.......

Answer:

Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).

Warm Front. ...

Stationary Front. ...

Occluded Front.

Answer:

Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.

Explanation:PLATO

Answer: The employee must do 11.2308 Joules of work

Explanation:

Work done = force × distance

But  

Force = ma(mass x acceleration due to gravity)

F = 30×9.8

F = 294N

Also distance moved can be found using  the equation  

v² = u² +2gS

1.00 ² = 0.50²+2(9.8)S

1 =0.25+19.6S

1-0.25 =19.6S

0.75=19.6S

S=0.75/19.6

S = 0.0382m

Work done = force × distance = FS

Work done = 294 N X 0.0382m

Workdone =11.2308Nm = 11.2308 Joules

Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,

[tex]W=Fd[/tex]

Here (F) is the magnitude of force and (d) is the distance traveled.

From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,

[tex]W=(ma)d[/tex]

For the gravitational acceleration, it can be written as,

[tex]W=(mg)d\\W=mgd[/tex]

The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.

Thus, the distance traveled by it can be find out using the third law of motion as,

[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]

As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,

[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]

Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

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