A 450.0 kg boat experiences two simultaneous forces. The motor exerts a force of 100.0 N to accelerate the boat forward, while an unknown drag force pushes in the opposite direction. The boat accelerates forward at 0.1330 m/s2. Calculate the drag force acting on the boat.

Answers

Answer 1

Answer:

The  drag force is [tex]D = 40.15 \ N[/tex]

Explanation:

From the question we are told that

  The mass is  [tex]m = 450.0 \ kg[/tex]

  The acceleration [tex]a  = 0.133 m/s^2[/tex]

The force due to the motor is  [tex]F_m = 100 \ N[/tex]

Generally the net force acting on the boat is mathematically represented as

    [tex]F = m * a[/tex]

=>  [tex]F = 450.0 * 0.1330[/tex]

=>  [tex]F = 59.85 \ N[/tex]

Generally the drag force acting on the boat is mathematically represented as

     [tex]D = F_m -F[/tex]

=>  [tex]D = 100 - 59.85[/tex]

=>   [tex]D = 40.15 \ N[/tex]

 


Related Questions

What is happening to the heat in freezing?

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Answer:

Heat is released.

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Answer: B (on the rough side)

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Answer: 5g/ml

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Answer:

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Frequency = speed / wavelength
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Answer:

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Answer:

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Answer:

For any given motion, the distance is

Explanation:

Explanation:

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Answer:

a = kL/m

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Here we can use Hooke's Law to find out the force applied on the system. Hooke's Law states that when a spring is stretched by some force, the force applied is directly proportional to the displacement of spring. The formula is given as:

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Answer:

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I got it right when I chose it.

Answer:

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Answer:

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Answer:

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Answer:

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Answers

Answer:

≈ 0.47 m/s²

Explanation:

Hi there !

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Answers

Answer:

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