Answer:
Explanation:
CH₃COOH + NaOH = CH₃COONa + H₂O .
.02M
CH₃COOH = CH₃COO⁻ + H⁺
C xC xC
Ka = xC . xC / C = x² C
1.8 x 10⁻⁵ = x² . .02
x² = 9 x 10⁻⁴
x = 3 x 10⁻²
= .03
concentration of H⁺ = xC = .03 . .02
= 6 x 10⁻⁴ M , volume = 45 x 10⁻³ L
moles of H⁺ = 6 X 10⁻⁴ x 45 x 10⁻³
= 270 x 10⁻⁷ moles
= 2.7 x 10⁻⁵ moles
concentration of NaOH = .0200 M , volume = 35 x 10⁻³ L
moles of Na OH = 2 X 10⁻² x 35 x 10⁻³
= 70 x 10⁻⁵ moles
=
NaOH is a strong base so it will dissociate fully .
there will be neutralisation reaction between the two .
Net NaOH remaining = (70 - 2.7 ) x 10⁻⁵ moles
= 67.3 x 10⁻⁵ moles of NaOH
Total volume = 45 + 35 = 80 x 10⁻³
concentration of NaOH after neutralisation.= 67.3 x 10⁻⁵ / 80 x 10⁻³ moles / L
= 8.4125 x 10⁻³ moles / L
OH⁻ = 8.4125 x 10⁻³
H⁺ = 10⁻¹⁴ / 8.4125 x 10⁻³
= 1.1887 x 10⁻¹²
pH = - log ( 1.1887 x 10⁻¹² )
= 12 - log 1.1887
= 12 - .075
= 11.925 .
* Question Completion Status:
QUESTION 1
'What compound represents conjugate base in the following chemical reaction? H2SO4 + H2O HSO4 + H30+
O a. H2SO4
O b. H2O
O c. HSO4
O d. H30+
Answer: b. HSO4-
Explanation:
H2SO4 (sulfuric acid) will donate a hydrogen ion in solution to form H3O+(hydronium). The remaining HSO4- would be the conjugate base of this dissociation.
A conjugate base contains one less H atom and one more - charge than the acid that formed it.
A conjugate acid contains one more H atom and one more + charge than the base that formed it.
The adiabatic saturation and wet-bulb temperatures will be equivalent for atmospheric air when the two are approximately equal at atmospheric temperatures and pressure.
a. True
b. False
Which resulted from the study of chemistry?
A) Alchemy to turn base metals into noble metals
B) The understanding of earth, air, fire, and water as the basic components of matter.
C) A supernatural, mystical view of the world.
D) Discovering the role of oxygen in combustion
question attached ! asap please
Answer:
A. copper is highly water soluble. It will turn into 5 different hydrates as it absorbs more and more water.
b. Glycerol is easily soluble in water, due to the ability of the polyol groups to form hydrogen bonds with water molecules
c. octane is considered to be non-polar, it will not be soluble in water, since water is a polar solvent. This will happen because octane (hydrocarbons in general) contains neither ionic groups, nor polar functional groups that can interact with water molecules.
d. Nitric acid decomposes into water, nitrogen dioxide, and oxygen, forming a brownish yellow solution.
e. Barium carbonate is a white powder. It is insoluble in water and soluble in most acids
Explanation:
A study of the system, 4NH3(g) + 7O2(g) <--> 2N2O4(g) + 6H2O(g), was carried out. A system was prepared with [NH3] = [O2] = 3.60 M as the only components initially. At equilibrium, [N2O4] is 0.600 M. Calculate the equilibrium concentration of NH3(g).
Answer:
The equilbrium concentration of NH₃(g) is 2.4 M
Explanation:
The balanced reaction is:
4 NH₃(g) + 7 O₂(g) ⇔ 2 N₂O₄(g) + 6 H₂O(g)
By stoichiometry of the reaction, 2 moles of N₂O₄ are formed from 4 moles of NH₃.
Considering that the concentration is [tex]concentration=\frac{number of moles}{volume}[/tex] and with a volume of 1 liter, it is possible to apply the following rule of three: if 2 M of N₂O₄ are formed from 4 M of NH₃, 0.6 M of N₂O₄ from what concentration of NH₃ are formed?
[tex]concentration of NH_{3}=\frac{0.6 M of N_{2}O_{3} *4MofNH_{3} }{2 M of N_{2}O_{3} }[/tex]
concentration of NH₃= 1.2 M
By subtracting the moles of NH3 in equilibrium from the moles of NH₃ initially, you will see how many moles of NH₃ were converted and remain in equilibrium: 3.6 M - 1.2 M= 2.4 M
The equilbrium concentration of NH₃(g) is 2.4 M
Which of the following statements is true? a) The rate constant does not depend on the activation energy for a reaction where the products are lower than the reactants. b) A catalyst raises the activation energy of a reaction. c) Rate constants are temperature dependent.
Answer:
Rate constants are temperature dependent.
Explanation:
Reaction rate is used to quantify the rate of chemical reaction. There is a relationship between the reaction rate and the half-life of the reaction and the Gibbs free energy of activation, and the reaction rate is temperature dependent according to the equation.
For a reaction shown below
a A + b B ⇒ c C
The rate of reaction of the reaction is given by
[tex]r = k(T) [A]^{m}[B]^{n}[/tex]
where k(T) is the reaction constant, which is seen to be dependent on the temperature of the reaction.
Also, k(T) is numerically equal to
[tex]k(T) = Ae^{\frac{E_{a} }{RT} }[/tex]
where
r = reaction rate
A = pre exponential factor
[tex]E_{a}[/tex] = Activation energy
R = gas constant
T = temperature
and m and n are experimentally determined partial orders in [A] and [B]
g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Container A has He, container B has Ne, and container C has O2. Which flask contains the largest number of molecules? Group of answer choices
Answer:
The three gases, in the three identical containers, will all have the same number of molecules
Explanation:
If these three gases (Helium He, Neon Ne, and Oxygen [tex]O_{2}[/tex]) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."
Write a balanced equation for: capture of an electron by cadmium-104
Answer:
104 48 Cd + 0 -1 e ---------> 104 47 Ag
Explanation:
In the process of electron capture, the nucleus captures an electron and thus converts a proton into a neutron with the emission of a neutrino. This process increases the Neutron/Proton ratio, the captured electron is usually from the K shell. An electron from a higher energy level now drops down to fill the vacancy in the K shell and characteristic X-ray is emitted. This process usually occurs where the Neutron/proton ratio is very low and the nucleus has insufficient energy to undergo positron emission.
For 104 48 Cd, the balanced equation for K electron capture is;
104 48 Cd + 0 -1 e ---------> 104 47 Ag
Determine the number of moles of the anhydrous salt present after heating, assuming that the contents of the aluminum cup after heating are pure anhydrous KAl(SO 4 ) 2 .
Answer:
0.2 moles, assuming weight of dried salt
Explanation:
In order to determine the number of moles, we need to be aware of the mass of the substance in question.
Assuming the mass of the dehydrated [tex]KAl(SO_{4} )_{2}.H_{2} O[/tex] is 50g.
No. of moles = mass of substance/ molar mass of the substance.
= [tex]\frac{50g}{39+27+32*2+16*4*2\\)g/mol}[/tex]
= 0.2 moles moles.
what energy is required for a reaction to occur?
Answer:
activation energy
Explanation:
Answer:
Activation Energy
Explanation:
Activation Energy is the energy required for a reaction to occur.
16. A metal element and a non-metal element are brought near each other and allowed to react. What's the most likely type of compound
that will form between these two elements?
A. lonic and covalent
B. lonic
C. Covalent
D. Neither, metals and non-metals don't react.
Answer:
B) Ionic
Explanation:
can I get some urgent help please?
Answer:
hi here goes your answer
Explanation:
iv. The lower the PH, the weaker the base
If the heat of combustion for a specific compound is −1380.0 kJ/mol and its molar mass is 44.53 g/mol, how many grams of this compound must you burn to release 822.00 kJ of heat?mass:g
Answer:
Mass = 26.53 g
Explanation:
Heat of combustion = −1380.0 kJ/mol
This means 1 mol of the compound releases 1380 kJ
Molar mass = 44.53 g/mol
This means 1 mol of the compound has a mass of 44.53 g
How many grams would release 822kJ..?
First, we have to obtain the number of moles
1 mol = 1380
x = 822
x = 0.5957 moles
Moles = Mass / Molar mass
Mass = Molar mass * moles
Mass = 44.53 * 0.5957
Mass = 26.53 g
A compound has two elements, A and B with electronegativities of 0.8 and 3.0 respectively. If the compound has a formula of A2B, which statement describes the bonding best? Group of answer choices The compound is largely ionic with A as the anion. The AB bond is largely covalent with a δ- on A. The compound is largely ionic with A as the cation. The AB bond is largely covalent with a δ+ on A.
Answer:
The compound is largely ionic with A as the cation.
Explanation:
A chemical bond is usually formed between two or more elements. A chemical bond may be ionic, covalent or polar covalent depending on the electro negativity difference between the atoms in the bond.
A large electro negativity difference usually implies an ionic bond. As a rule, when the electronegativity difference is greater than 2.0, the bond is considered ionic.
For the compound A2B, the electro negativity difference between the two atoms is about 2.2. This implies that A2B must be an ionic compound in which A is the cation and B is the anion.
since Ag and Cl are in equilibrium with AgCl, find Ksp for agcl from the concentrations. Write the expression for ksp AgCl and determine its value
Answer:
1.69 ×10^-10
Explanation:
Given that the equation for the dissolution of AgCl in water is;
AgCl(s) ⇄Ag^+(aq) + Cl^+(aq)
Also, silver ion and chloride ion are in equilibrium with the undissociated AgCl hence we can write;
Ksp= [Ag+][Cl-]/ [AgCl]
Since the activity of the pure sold is 1, we now have;Ksp= [Ag+][Cl-]
If we know the solubility of AgCl in pure water to be 1.3 x 10^-5 M, from standard tables, and [Ag+]=[Cl-]= 1.3 x 10^-5 M = x
Then;
Ksp= x^2
Ksp= (1.3 x 10^-5)^2
Ksp= 1.69 ×10^-10
When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is
[tex]Ksp = [Ag^{+} ][Cl^{+} ][/tex]
And its value is 1.77 × 10⁻¹⁰.
Let's consider the equation for the solution of AgCl.
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
The molar solubility of AgCl (S) at 25 °C is 1.33 × 10⁻⁵ M. We can use this information to calculate the solubility product (Ksp) through an ICE chart.
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
I 0 0
C +S +S
E S S
The solubility product (Ksp) for AgCl is:
[tex]Ksp = [Ag^{+} ][Cl^{+} ] = S.S = S^{2} = (1.33 \times 10^{-5} )^{2} = 1.77 \times 10^{-10}[/tex]
When Ag⁺ and Cl⁻ are in equilibrium with AgCl, the expression for Ksp is
[tex]Ksp = [Ag^{+} ][Cl^{+} ][/tex]
And its value is 1.77 × 10⁻¹⁰.
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Write the electron configuration for the element titanium, TiTi. Express your answer in order of increasing orbital energy as a string without blank space between orbitals. For example, the electron configuration of LiLi could be entered as 1s^22s^1 or [He]2s^1.
Answer:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d² or [Ar] 3d² 4s²
Explanation:
Electron configuration can basically be referred to as the location of electron; how the electrons are arranged in the orbitals of the atoms.
Following Aufbau principle, electrons are arranged in the following order of orbitals.
1s 2s 2p 3s 3p 4s 3d and so on.
The s can hold a maximum of 2 electrons, p can hold a maximum of 6 electrons and d can hold a maximum of 10 electrons.
Titanium has an atomic number of 22. So the arrangement is given as;
Ti = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²
The short hand notation is given as;
[Ar] 3d² 4s²
The electron configuration of Ti is
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex] or [tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
The electron configuration of an element is the distribution of electrons in atomic orbitals.
According to Aufbau's principle, the orbitals with lower energies are filled before the orbitals with higher energies.
We can know this order, using the diagonal rule (attached image).
The maximum number of electrons in each sublevel is:
s = 2p = 6d = 10f = 14Considering all these facts, and that Titanium has 22 electrons, the electron configuration of Ti is:
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex]
Since [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex] is the electron configuration of Argon, this can also be written as:
[tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
The electron configuration of Ti is
[tex]Ti: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{2}[/tex] or [tex]Ti: [Ar] 4s^{2} 3d^{2}[/tex]
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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. What molarity of sodium acetate will you need to add to the solution
Answer:
Molarity of sodium acetate you will need to add is 0.0324M
Explanation:
Assuming volume of the buffer is 1L.
The pH of a buffer can be determined using Henderson-Hasselbalch equation:
pH = pKa + log [A⁻] / [HA]
Where pKa is pKa of the weak acid, [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid
Replacing for the acetic buffer (pKa = 4.76):
pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]
As you have 0.010 moles of acetic acid in 1L:
[Acetic Acid] = 0.010mol / 1L = 0.010M
And you require a pH of 5.27:
5.27 = 4.76 + log [Sodium Acetate] / [0.010M]
0.51 = log [Sodium Acetate] / [0.010M]
10^0.51 = [Sodium Acetate] / [0.010M]
3.236 = [Sodium Acetate] / [0.010M]
3.236 [0.010M] = [Sodium Acetate]
0.0324M = [Sodium Acetate]
Molarity of sodium acetate you will need to add is 0.0324M
All of the following reactions can be described as displacement reactions except:____________.
a.) Zn(s) + FeCl2(aq) → ZnCl2(aq) + Fe(s).
b.) C6H6(l) + Cl2(g) → C6H5Cl(l) + HCl(g).
c.) 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g).
d.) Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s).
e.) CuSO4(aq) + Fe(s) → Cu(s) + FeSO4(aq).
Answer:
b
Explanation:
The reaction that is not a displacement reaction from all the options is [tex]C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}[/tex]
In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.
Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.
Correct option = b.
The reaction given in Option A is not a displacement reaction. In Displacement reaction functional group of one reactant is replaced by the functional group of the another reactant.
Displacement reaction:
In this reaction functional group of one reactant is replaced by the functional group of the another reactant.
[tex]\bold { Zn(s) + FeCl_2(aq) \rightarrow ZnCl_2(aq) + Fe(s).}[/tex]
In the above reaction Zinc does not any functional group to exchange with iron chloride.
Therefore, the reaction given in Option A is not a displacement reaction.
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what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equation
Answer:
[tex]Cu~+~PtCl_2->Pt~+~CuCl_2[/tex]
Explanation:
In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case [tex]Pt^+^2[/tex]) and the anion is the atom at the right of the name (in this case [tex]Cl^-[/tex]). With this in mind, the formula would be [tex]PtCl_2[/tex].
Now, if we used metallic copper we have to put in the reaction only the copper atom symbol [tex]Cu[/tex]. So, we have as reagents:
[tex]Cu~+~PtCl_2->[/tex]
The question now is: What would be the products? To answer this, we have to remember "single displacement reactions". With a general reaction:
[tex]A~+~BC->AB~+~C[/tex]
With this in mind, the reaction would be:
[tex]Cu~+~PtCl_2->Pt~+~CuCl_2[/tex]
I hope it helps!
Help please.☺️☺️☺️☺️☺️
Answer:
A.∆s>0contribute to spontaneity.
Citra is using the basic permanent wrap method to perm Holly's hair. As Citra divides Holly's hair into panels, how wide should she make them?
Answer:
Citra should make it equal to the length of the rod.
Explanation:
A basic permanent wrap method is a 9 section wrap method in which all the base sections are horizontal, having same length and width of the rod
Basic permanent wrap method causes a uniform curl from the scalp to the end of the hair.
In permanent wrap method, paneling the hair equal to the length will make the will give the same size as the rod.
The length of the rod determines the size of the curl.
Once Holly's hair is divided into panel and make it as wide as the length of the rod, it will curl in the same size as the rod lengths and the hair will perm well.
18. Sucralose contains which two functional groups: (2 points)
A) benzene
B) halogen
C) carboxyl
D) hydroxy!
Answer:
The correct answer is option B and D, that is, halogen (chlorine) and hydroxyl.
Explanation:
An artificial sweetener and sugar substitute is sucralose. It is noncaloric as the majority of the sucralose ingested does not get dissociated within the body. The generation of sucralose takes place by the chlorination of sucrose. It is about 300 to 1000 times sweeter in comparison to sucrose.
The consumption of sucralose is safe for both nondiabetics and diabetics, it is used in various food and beverage components due to non-caloric sweetener characteristics. It does not affect the levels of insulin and does not affect dental health. As it is produced by chlorination of sucrose, thus, the functional groups present in it are a halogen (chlorine) and a hydroxyl.
A sample of N2(g) was collected over water at 25 oC and 730 torr in a container with a volume of 340 mL. The vapor pressure of water at 25 oC is 23.76 torr. What mass of N2 was collected
Answer:
0.36 g of N2.
Explanation:
The following data were obtained from the question:
Temperature (T) = 25 °C
Volume (V) = 340 mL
Measured pressure = 730 torr
Vapour pressure = 23.76 torr
Mass of N2 =..?
First, we shall determine the true pressure of N2. This can be obtained as follow:
Measured pressure = 730 torr
Vapor pressure = 23.76 torr
True pressure =..?
True pressure = measured pressure – vapor pressure
True pressure = 730 – 23.76
True pressure = 706.24 torr.
Converting 706.24 torr to atm, we have:
760 torr = 1 atm
Therefore,
706.24 torr = 706.24 / 760 = 0.929 atm
Next, we shall convert 340 mL to L. This is illustrated below:
1000 mL = 1 L
Therefore,
340 mL = 340/1000 = 0.34 L
Next, we shall convert 25 °C to Kelvin temperature. This is illustrated below:
Temperature (K) = Temperature (°C) + 273
T(K) = T (°C) + 273
T (°C) = 25 °C
T(K) = 25 °C + 273
T (K) = 298 K
Next, we shall determine the number of mole of N2. This can be obtained as follow:
Pressure (P) = 0.929 atm
Volume (V) = 0.34 L
Temperature (T) = 298 K
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =...?
PV = nRT
0.929 x 0.34 = n x 0.0821 x 298
Divide both side by 0.0821 x 298
n = (0.929 x 0.34 ) /(0.0821 x 298)
n = 0.0129 mole
Finally, we shall determine the mass of N2 as shown below:
Mole of N2 = 0.0129 mole
Molar mass of N2 = 2x14 = 28 g/mol
Mass of N2 =.?
Mole = mass /Molar mass
0.0129 = mass of N2/ 28
Cross multiply
Mass of N2 = 0.0129 x 28
Mass of N2 = 0.36 g
Therefore, 0.36 g of N2 was collected.
Answer all to the best of your ability please
Answer:
2–Ethyl–3–methlypentanal.
Explanation:
To name the compound given in the question above, we must observe the following:
1. The functional group of the compound is Alkanal i.e Aldehyde,
—CHO and it is located at carbon 1.
Note: the aldehyde functional group is always at carbon 1 and there will be no need to state it's position in the compound.
2. The longest continuous carbon chain is 5 i.e pentane. But the presence of the functional group will replace the –e at the end of pentane with –al, making the name to the pentanal.
3. The substituents attached are:
a. Ethyl, CH2CH3 at carbon 2.
b. Methyl, CH3 at carbon 3.
4. Combine the above to get the name of the compound.
Therefore, the name of the compound is:
2–Ethyl–3–methlypentanal.
One of these has a negative value for (triangle) H. select the correct one
Answer:
The methane gas burns
Explanation:
The burning of methane gas is a combustion reaction. Combustion is an exothermic process. For all exothermic processes, ∆H is negative.
Combustion reaction involves the evolution of heat. The energy of reactants is greater than the energy of products hence the excess energy is given off in the form of heat leading to a negative value of the enthalpy of reaction, hence the answer.
If you did not use a watch glass to cover your stock iodine solution, and the concentration of iodine decreased over the course of your trials, how would this affect the quality of your data
Answer::
Lower rate of reaction
Explanation:
Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.
This however may not be the case if the iodine in question is catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.
I hope this explanation fits the brief.
Why is the chemical formula Li2H incorrect? Select the correct answer below: A. There should be one lithium, not two. B. There should be one lithium and two hydrogens. C. Lithium does not react with hydrogen. D. There should be three lithiums, not two.
Answer:
There should be one lithium, not two.
Explanation:
Lithium reacts with hydrogen at about 750°C to yield lithium hydride (LiH). LiH is white and powdery in appearance. It releases hydrogen gas when it reacts with water.
The correct formula for Lithium hydride is LiH and not Li2H because both lithium and hydrogen are univalent. Lithium has a valency of +1 while hydrogen has a valency of -1 in lithium hydride. Hydrides are formed between hydrogen and highly electro positive metals. In hydrides, hydrogen is forced to accept an electron from the highly electro positive metal.
What is the percent composition of sulfur in SO2?
OA
32.1 g
(32.1 g + 16.0 g + 16.0 g)
x 100%
32.1 g
O B.
x 100%
(16.0 g + 16.0 g)
O c.
(32.1 g + 16.0 g + 16.0 g)
X 100%
32.1 g
(32.1 g)(6.02 x 102)
O D.
100 g
Answer:
5 .04 percent.
Explanation:
it is also known as sulfur dioxide. so it's 5.0.4 percent.
Your question is incomplete. Read below to find the content.
0.4 % is the percent composition of sulfur in SO2.
How is SO2 prepared from sulfur?In the laboratory, sulfur dioxide is prepared by the reaction of metallic sulfite or a metallic bisulfite with dilute acid. For example, a reaction between the dilute sulphuric acid and sodium sulfite will result in the formation of SO2.
What do you mean by percentage composition?The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. Here, the quantity is measured in terms of grams of the elements present.
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Why was it important to establish the Clean Air Act?
Answer: The Clean Air Act was important because it emphasized cost-effective methods to protect the air; encouraged people to study the effects of dirty air on human health; and created a regulation that makes any activities that pollute the air illegal.
Explanation:
Answer:
Clean Air Act (CAA), U.S. federal law, passed in 1970 and later amended, to prevent air pollution and thereby protect the ozone layer and promote public health. The Clean Air Act (CAA) gave the federal Environmental Protection Agency (EPA) the power it needed to take effective action to fight environmental pollution.
A container is filled with a mixture of helium and oxygen gases. A thermometer in the container indicates that the temperature is 22°C. Which gas molecules have the greater average speed? Group of answer choices
Answer:
Helium
Explanation:
The speed of the molecules in a gas is directly proportional to the temperature of the gas and inversely proportional to molar mass of the gas.
This implies that when the temperature of a sample of gas is increased, the speed of the gas molecules is increased accordingly.
At a given constant temperature, the molar mass of the gas is inversely proportional to its average molecular speed. This means that the greater the molecular mass of the gas the lesser the average speed of its molecules.
Oxygen has a greater molecular mass than helium hence it will have a lesser average molecular speed compared to helium.
The gas molecule which has the greater average speed is: Helium molecules because they are less massive.
Given the following data:
Temperature = 22°CAccording to the kinetic-molecular theory, the average speed of gas molecules (particles) is highly dependent on temperature and the molar mass of a gas.
This ultimately implies that, the average speed of gas molecules (particles) is directly proportional to the absolute temperature of an ideal gas and inversely proportional to molar mass of the gas.
Molar mass of Helium gas = 4.0 g/mol.Molar mass of Oxygen gas = 32.0 g/molAt a constant temperature, the higher the molar mass of a gas, the lower would be its average speed and vice-versa.
Hence, helium molecules would have the greater average speed at a constant temperature of 22°C because it is less massive and has a lower molar mass in comparison with oxygen gas.
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