a 3000 kg car with a full load of people, has a kinetic energy of 190,000 J. What would the kinetic energy of the car be if it was moving at the same speed but a different mass of 1500 kg?

Answers

Answer 1

Answer:  15.9 m/s

Explanation:

KE = 1/2(mv^2)

190,000J = 1/2(3000kg)*v^2

1 J = 1 kg*m^2/s^2

190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2

v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))

v^2 = (190,000 kg*m^2/s^2)/(1500kg))

v^2 = 126.6667 m^2/s^2

v = 11.25 mm/s velocity of 3000kg vehicle

With the same kinetic energy, a vehicle of 1500kg would have a different velocity:

190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2

190,000 kg*m^2/s^2 =(750kg)*v^2

v^2 = 253.33 m^2/s^2

v = 15.9 m/s


Related Questions

How do longitudinal waves move

Answers

Answer:

in a direction parallel to the direction that the wave moves

Explanation:

Answer:

parallel to the direction....

Which phrase describes speed? A. A quantity with direction only B.A vector quantity C.A scalar quantity D.A quantity with no units

Answers

Answer:

C. A scalar quantity

Explanation:

Speed does not have a direction. Speed with a direction is known as velocity.Vector quantities are quantities with magnitude and direction. As stated before, speed does not have a direction.Speed has a SI unit of m/s (meters per second).

Therefore, the answer is C.

42. The object in the figure is made of
a material of density 3000 kg/m3.
What is the tension in the rope,
which suspends the object, when
it is completely immersed in
water. The mass of the object is
200 kg.
TO?

Answers

Answerpov:

Explanation:

A car with a velocity of 30 m/s accelerates uniformly at the rate of 2.0 m/s2 for 10 s. What is its final velocity?

Answers

a = (v - u) / t

a - acceleration
v - final velocity
u - initial velocity
t - time taken

2.0 = (v - 30) / 10
v - 30 = 2.0 x 10
v = 20 + 30
v = 50m/s

Can some one help me whith the answer

Answers

Answer :

» B. 6.03 × 10²³ electrons

Explanation :

The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:

1C = 6.24150975⋅10¹e

Q(e) = Q(C) × 6.24150975 × 10¹

Q(e) = 96,500 × 6.24150975 × 10¹

Q(e) = 6.02305690875 × 10²³

which is round off to

6.03 × 10²³ electrons

15. How many neutrons are in the nucleus of an atom that has an atomic mass of 36 and an
atomic number of 25

Answers

13 Neutrons and Mg has 14 Neutrons

why are astronauts weightless in the space station?

Answers

Answer:

Astronauts float around in space because there is no gravity in space. Everyone knows that the farther you get from Earth, the less the gravitational force is. Well, astronauts are so far from the Earth that gravity is so small. This is why NASA calls it microgravity.

Explanation:

sơ đồ tư duy môn địa 10 bài 12

Answers

nd ko ka balo mag anser sina ya doy

An___ is a pure substance that cannot be separated into any other substance

Answers

the answers an element
Element is the answer

what is magnetic force?
i​

Answers

Answer:

The force by which a substance (magnet) attracts a body(metals) towards it is called magnetic force

Answer:

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion. The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.

Explanation:

Hope this helps you. Please mark as brainliest. It helps a lot. :)

A lightbulb uses 2,000 J of energy in 1 min and 20 s. What is the power of the lightbulb?

Answers

Answer:

ga tau gw ah binatang aje

For the time between 5 and 9 seconds, calculate the velocity of the car.

Answers

The car's velocity is 8 m/s at t = 5 seconds. Hope this helped please mark me brainiest! :)

A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flipping the coin gave it a velocity of 10.32 m/s? Please answer in seconds and to the third decimal place.

Answers

It will take the quarter 0.151 seconds to reach the ground.

Given the following data:

Height = 1.45 metersInitial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2} at^2[/tex]

Where:

S is the height or distance covered. u is the initial velocity. a is the acceleration. t is the time measured in seconds.

Substituting the values into the formula, we have;

[tex]1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0[/tex]

The standard form of a quadratic equation is:

[tex]ax^2 + bx + c = 0[/tex]

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]

Substituting the values, we have;

[tex]t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}[/tex]

Time, t = 0.151 seconds.

Therefore, it will take the quarter 0.151 seconds to reach the ground.

Read more: https://brainly.com/question/8898885

3.1 Two waves A and B have frequencies 256 Hz and 1024 Hz respectively have amplitude in ratio 3:1 1.What is their ratio of frequencies? Which wave represents a higher pitch
2.which sound is louder

Answers

Answer:

1. the one with the raito

2. the one that stubbed their toe

Explanation:

on which temperature scale does the average kinetic energy of molecules double when the temperature doubles?

Answers

Answer:

where are the choices i think 100% that is my opinion

What resistance does a 25 W light bulb have if 12.6 V is applied to it?
(3 marks)

Answers

Answer:

Explanation:

W = 25 Watts

V = 12.6 Volts

I = ? I is the current in amperes.

Solution

25 = 12.6 * I

I = 25 / 12.6

I = 1.98 amperes

V = 12.6

I = 1.98

R = ??

V = I * R

12.6 = 1.98 * R

R = 12.6 / 1.98

R = 6.35 ohms

An object is traveling at a constant velocity of 8 m/s when it experiences a constant acceleration of 3.5 m/s2 for a time of 40 s. What will its velocity be after that acceleration? *

Answers

Answer:

140 m/s

Explanation:

v = u + at

v = 8 + 3.5(40) = 140 + 8 = 140


helppppppppppppppppppppppp

Answers

Explanation:

v²= u² + 2as

v= final velocity.

u= initial velocity.

a= acceleration.

s= distance.

what do the tropopause stratopause and mesopause have in common

Answers

Each is a zone of decreasing water vapor content within the atmosphere. ... Each is an interface between two layers of the atmosphere. Each is a point of maximum temperature in its layer of the atmosphere.

Holly is conducting an experiment in which she changes the voltage across a circuit and records the relative brightness of a light bulb in the circuit. She takes notes in the notebook below.


How might these notes be useful?
A.
They could help her teacher to understand what she did in the experiment.

B.
They could help someone interested in conducting the same experiment.

C.
They could help her remember the experiment in the future.

D.
all of these
Reset Submit

Answers

Answer:

all of these

Explanation:

Answer:

D.all of there

Explanation:

A 100 kg physics teacher pushes a 1.0 kg physics textbook across a 222 kg physics demo table. The teacher applies 5.0 N of force to start the book sliding and 4.0 N to keep it sliding at a constant 0.30 m/s across the table.
Sketch a free body diagram showing all the forces acting on the book as the teacher pushes it.
1 . What is the magnitude of the weight of the book?
2. What is the magnitude of the normal force of the table on the book?
4. What is the coefficient of static friction between the book and the table?
5. What is the coefficient of kinetic friction between the book and the table?
6. If the teacher stops pushing the book, what is the magnitude of the net force on the book?
7. What acceleration does the book have after the teacher stopped pushing it?
8. How far does the book slide before coming to rest?

Answers

Answer:

1) 1kg

2) 9.81kg

4) 5N

5) 4N

6) 0N

7) 0N

8) 13

Explanation:

Un avión vuela hacia al norte a una velocidad de 90 m/s, pero un fuerte viento sopla hacia al este a 20 m/s y desvía su rumbo. Realiza los trazos y encuentra el vector resultante.

Answers

La adicion de vectores permite encontrar la repuesta para la velocidad resultante del avión es:

Modulo de la veloicdad  v= 92,2 m/s Dirección de esta veloicdad 12,5º al Norte del Este  

Las magnitudes vectoriales son cantidades tienen modulo y dirección, la velocidad es una de estas magnitudes, por lo tanto deben ser sumada usando álgebra vectorial.

Un sistema de referencia es un sistema desde donde realizar las mediciones, en este caso indican que usemos un sistema de los puntos cardinales.

En el adjunto podemos ver un esquema de los vectores velocidad y su resultante, realicemos el calculo de la resultante por método analíticos

Indican que el valor de la velocidad hacia el Este es vₓ = 20 m/s y la velocidad hacia el Norte es v_y = 90 m/s, por lo tanto, para la magnitud usamos el Teorema de Pitágoras

           [tex]R= \sqrt{v_x^2 + v_y^2}[/tex]

           R = [tex]\sqrt{20^2 + 90^2}[/tex]

          R = 92,2 m/s

Para encontrar la direccion usemos trigonometría

          tan θ = [tex]\frac{v_y}{v_x}[/tex]

          θ = tan⁻¹ [tex]\frac{v_y}{v_x}[/tex]

          θ = tan⁻¹ 20/90

          θ = 12,5º

La dirección se lee 12,5º al Norte del Este

En conclusión usando la suma de vectores  podemos encontrar la repuesta para la velocidad resultante del avión es:

v= 92,2 m/s  con dirección 12,5º al Norte del Este  

Aprender mas aquí:

brainly.com/question/21639180

a. They are measured from the Prime Meridian in a and direction. These lines are known also as

Answers

Answer:

meridians

     Imaginary lines called meridians that measure distances East and West of the Prime Meridian. Longitude is different from latitude. Longitude may also be referred to as meridians. Although they measure the distance from East and West, the lines run in the direction of north and south.

Explanation:

hope this helps you if it does please mark brainiest

What is the difference between thrust and applied force?

Answers

Answer:

Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.

Explanation:

will give correct answer brainliest









Which factors below will increase the momentum of a rolling ball of constant mass m? (Select only the answers that will increase the momentum of the ball.) Moving from a flat surface to moving downhill. Colliding with a ball of much lower mass moving in the opposite direction of the ball. A moving object traveling in the same direction as the ball colliding with it. Rolling uphill onto an inclined surface. Rolling onto a surface with high amounts of friction with the ball.​

Answers

In order to increase the momentum of the ball, you have to increase its speed.

The first and third choices on the list ('A' and 'C') will do that.

The factors that will increase momentum of a rolling ball are:

A. Moving from a flat surface to moving downhill.

C. A moving object traveling in the same direction as the ball colliding with it.

Factors that increase momentum:

The gravitational power of the Earth ready makes the ball speed up, and in this manner pick up speed.

If you increase either mass or velocity, the momentum of the object increases proportionally.

Thus, the factors that increase the momentum of a rolling ball are

A. Moving from a flat surface to moving downhill.

C. A moving object traveling in the same direction as the ball colliding with it.

Find more information about momentum here:

brainly.com/question/402617

( In 1.5s the speed of the jumper increases from zero to 10.5 m/s. Calculate her average acceleration during this time.​

Answers

Answer:

answer 7m/s^2

Explanation:

›»› The Acceleration of jumper = 7 m/s²

Given :

Initial velocity of jumper (u) = 0 m/s

Final velocity of jumper (v) = 10.5 m/s

Time taken by jumper (t) = 1.5 sec

To Find :

Acceleration of jumper (a) = ?

Required Solution :

→ Initial velocity (u) = 0 m/s (because jumper increase from zero)

† From first equation of motion

⇒ v = u + at

⇒ 10.5 = 0 + a × 1.5

⇒ 10.5 = 0 + 1.5a

⇒ 10.5 = 1.5a

⇒ a = 10.5/1.5

⇒ a = 7 m/s²

║Hence, the Acceleration of jumper is 7 m/s².║

\:

Additional Information :

★ First equation of motion :

⪼ v = u + at

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

t is the Time taken in second.

★ Second equation of motion :

⪼ s = ut + ½ at²

Where,

s is the Distance travelled in m.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

★ Third equation of motion :

⪼ v² = u² + 2as

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

s is the Distance travelled in m.

i’m not sure if it’s A or B

Answers

Can you give us the excerpt?

what is atmospheric pressure​

Answers

Answer:

the pressure within the atmosphere of Earth

Explanation:

Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of the earth.

A bus slows down uniformly from 71.2 km/h
to ( km/h in 22.3 s.
How far does it travel before stopping?
Answer in units of m.

Answers

Answer:

1 km = 1,000 meters

Explanation:hey im in 7th grade and even i know that.i sorry but you seem not the smartest.jk thats a good question

A hammer falls from a construction worker's hand 30m above the ground at the same time that a filled soft drink can is projected vertically upward from the ground at a velocity of 24 m/s. Where and when will the two objects meet?

Answers

For harmer:-

initial velocity=u=0m/sAcceleration due to gravity=10m/s^2

Now

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}gt^2[/tex]

[tex]\\ \sf\longmapsto s=0t+\dfrac{1}{2}(10)t^2[/tex]

[tex]\\ \sf\longmapsto s=5t^2\dots(1)[/tex]

For soft drink:-

u=24m/s

[tex]\\ \sf\longmapsto 30-s=(24)t+\dfrac{1}{2}(10)t^2[/tex]

Using eq(1)

[tex]\\ \sf\longmapsto 30-5t^2=24t-5t^2[/tex]

[tex]\\ \sf\longmapsto 24t=30[/tex]

[tex]\\ \sf\longmapsto t=\dfrac{30}{24}[/tex]

[tex]\\ \sf\longmapsto t=1.2s[/tex]

After 1.2s they will meet.

Now

putting t in eq(1)

[tex]\\ \sf\longmapsto s=5t^2=5(1.2)^2=5(1.44)=7.2m[/tex]

At the height of 7.2m they will meet

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