A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is the magnitude of the current in the other wire

Answers

Answer 1

Answer:

The current is  [tex]I_b = 400 \ A[/tex]

Explanation:

From the question we are told that

    The  length of the segment is  [tex]l = 2.50 \ m[/tex]

     The current is  [tex]I_a = 1000 \ A[/tex]

     The force felt is  [tex]F = 4.0 \ N[/tex]

        The distance of the second wire is  [tex]d = 5.0 \ cm = 0.05 \ m[/tex]

Generally the current on the second wire is mathematically represented as

        [tex]I_b = \frac{2 \pi * r * F }{ l * \mu_o * I_a }[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4 \pi * 10^{-7} \ N/A^2[/tex]

=>      [tex]I_b = \frac{2 * 3.142 * 0.05 * 4 }{ 2.50 * 4\pi *10^{-7} * 1000 }[/tex]

=>      [tex]I_b = 400 \ A[/tex]


Related Questions

How much work, in kilojoules, went into thermal energy produced by friction?

Answers

The question is incomplete. Here is the complete question.

Suppose the mass of a loaded elevator is 1600 kg.

(a) What force, in Newtons, must be supplied by the elveator's cable to produce an acceleration of 0.745 m/s² upwards against a 185N frictional force?

(b) How much work, in joules, is done by the cable in lifting the elevator 21m?

(c) What is the final speed, in meters per second, of the elevator if it starts from rest?

(d) How much work, in kilojoules, went into thermal energy produced by friction?

Answer: (a) F = 1377 N

              (b) W = 28917 J

              (c) v = 5.6 m/s

              (d) W = 3.885 kJ

Explanation:

(a) According to Newton's Second Law: [tex]F_{net}=m.a[/tex], in which, [tex]F_{net}[/tex] is the vetorial sum of all the forces in a system and its unit is [F] = kg.m/s² or newton (N).

In the elevator's case, and assuming going upwards is positive:

[tex]F-F_{f}=m.a[/tex]

F - 185 = 1600(0.745)

F = 1377 N

For an elevator to produce an acceleration of 0.745m/s² upwards, the cables have to supply a force of 1377 newtons.

(b) Work is the energy transferred to an object while is being moved. It is calculated as: W = F.s. Its unit is [W] = N.m or Joule (J)

In the elevator's cable:

W = 1377.21

W = 28917 J

The work done by the elevator's cable is W = 28917 joules.

(c) Acceleration is variation in velocity along time. Since we know the displacement of the elevator:

[tex]v^{2}=v_{0}^{2}+2a\Delta x[/tex]

where:

v₀ is initial velocity, which is this case v₀=0 because it starts from rest;

a is acceleration;

Δx is the displacement

Replacing values:

[tex]v^{2}=2(0.745)(21)[/tex]

[tex]v=\sqrt{31.29}[/tex]

v = 5.6 m/s

Final speed of the elevator is 5.6 m/s.

(d) [tex]W=F_{f}.s[/tex]

W = 185(21)

W = 3885 J

Work transferred into thermal energy because of friction is W = 3.885 kJ.


Q1: An object is in a uniform circular motion. Which of the following statements must be
true?​

Answers

Answer:

it has constant angular velocity

Explanation:

an object moving in a uniform circular motion moves with constant angular velocity about a point

A tennis player on serve tosses a ball straight up. While the ball is in free fall, its acceleration does which of the following?
a. decreasesb. remains constant c. increases then decreasesd. increasese. decreases then increases

Answers

Answer:

acceleration remains constant at g= 9.8m/s²

velocity however ...increases

A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 39.0 cm/scm/s . What are:

a. The amplitude of the subsequent oscillations?
b. The block's speed at the point where x= 0.750 A?

Answers

Answer:

a

 [tex]A = 0.081 \ m[/tex]

b

The value is  [tex]u = 0.2569 \ m/s[/tex]

Explanation:

From the question we are told that

   The mass is  [tex]m = 0.750 \ kg[/tex]

   The spring constant is  [tex]k = 17.5 \ N/m[/tex]

    The instantaneous speed is  [tex]v = 39.0 \ cm/s= 0.39 \ m/s[/tex]

    The position consider is  x =  0.750A  meters from equilibrium point

   

Generally from the law of  energy conservation we have that

        The kinetic energy induced by the hammer  =  The energy stored in the spring

So

          [tex]\frac{1}{2} * m * v^2 = \frac{1}{2} * k * A^2[/tex]

Here a is the amplitude of the subsequent oscillations

=>      [tex]A = \sqrt{\frac{m * v^ 2 }{ k} }[/tex]

=>      [tex]A = \sqrt{\frac{0.750 * 0.39 ^ 2 }{17.5} }[/tex]

=>       [tex]A = 0.081 \ m[/tex]

Generally from the law of  energy conservation we have that

The kinetic energy  by the hammer  =  The energy stored in the spring at the point considered   +   The kinetic energy at the considered point

             [tex]\frac{1}{2} * m * v^2 = \frac{1}{2} * k x^2 + \frac{1}{2} * m * u^2[/tex]

=>          [tex]\frac{1}{2} * 0.750 * 0.39^2 = \frac{1}{2} * 17.5* 0.750(0.081 )^2 + \frac{1}{2} * 0.750 * u^2[/tex]

=>          [tex]u = 0.2569 \ m/s[/tex]

classify the simple machine knife​

Answers

Answer:

Wedge

Explanation:

A knife is used to cut things into pieces or even cut two items apart.

Now, it is classified as a Wedge because a Wedge is defined as a simple machine that is used in pushing two objects apart. Some examples include axes, knives & chisels.

How many hours will it take to fill a cubic vat of 15.7 ft edge length with a liquid that has a density of 1.31 g/mL and is spilling at a rate of 2.30 kg/s

Answers

Answer:

240 s or 4 minutes.

Explanation:

Given that

Volume of the cubic vat is 15.7³ = 3869.893 ft³

Density of the liquid is 1.31 g/mL

For easier calculations, we need to convert the density from g/mL to ft³

conversion factors shall be CUBED in order to do it!

We know that

1 inch = 2.54 cm, and

1 foot = 12 in

This means that

1.31 g/cm³ * 2.54³ cm³/in³ * 12³ in³/ft³

= 37095.069 g/ft³

Lastly,

We use this conversion method

1 second/ 2300 grams * 37095.069 g/ft = 16.13 ft³/s

Bringing down the volume of the cube, we use it to divide, and thus

3869.893 / 16.13 = 240 seconds

240 seconds = 4 minutes

A thin-walled vessel of volume V contains N particles which slowly leak out of a small hole of area A. No particles enter the volume through the hole. Find the time required for the number of particles to decrease to N/2. Express your answer in terms of A, V, and v.

Answers

Answer:

    [tex]\frac{V}{2av}[/tex]

Explanation:

From the question we are told that

Volume V

Contains N particles

Leaks from a small hole of area A

Generally the equation for Flow rate is given as

Volume Flow Rate  [tex]V_r = A * v[/tex]

Mathematically we find the  time taken to flow half way which is given by

          [tex]\frac{(V/2)}{A*v}[/tex]

Therefore the  time taken is

           [tex]\frac{V}{2av}[/tex]

An alpha particle has twice the charge of a beta particle. Why does the former deflect less than the latter when passing between electrically charged plates, assuming they both have the same speed?

Answers

Yes is this old or new did u get this question bro

How does thermal energy change matter?

Answers

Answer:

maxed out

Explanation:

The y-component of the force F which a person exerts on the handle of the box wrench is known to be 70 lb. Determine the x-component and the magnitude of F.

Answers

Answer:

Fx = 121.24lb

F = 140lb

Explanation:

Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.

The y component of the force expressed by the formula:

Fy = Fsintheta

Given the y-component of the force F to bee 70lb

70lb =  Fsintheta

Get magnitude of the force

F = 70/sin theta

F = 70/sin 30

F = 70/0.5

F = 140lb

Get the x-component of the force

Fx = Fcos theta

Fx = 140cos 30

Fx = 140(0.8660)

Fx = 1,212.4lb

Hence the  x-component of the force sis 121.24lb

Note that the angle used was assumed. Other values can as well be used

A car travels 60 km in the first 2 hours and 68 km in the next 2 hours. what is the cars average speed ?

Answers

You have to divide 60 and 68 by 2 and then add them together

What is the frequency of a wave with a wavelength of 36 m and a speed of 12 m/s?
3Hz
O .33HZ
O 432HZ
O 312HZ

Answers

Answer:

312hz

Explanation:

thanks me later

A boy takes his dog for a walk. The dog pulls with 30N of force to the right and the boy pulls backward with 18 N of force.

Net Force = (your answer)
Body Diagram or Explanation = (your answer)

Answers

Answer:

Answer is in photo

Explanation:

The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?

Answers

Answer:

Q = 675 [J]

Explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

[tex]Q=m*C_{p}*(T_{initial}-T_{final})[/tex]

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

[tex]Q=25*0.9*(55-25)\\Q=675 [J][/tex]

A 6 kg cart starting from rest rolls down a hill and at the bottom has a speed of 10 m/s. What is the height of the hill?

Answers

Answer:

h = 5.09 m

Explanation:

Applying the Law of conservation of energy to this situation, we can write:

[tex]Kinetic\ Energy\ Gained\ by\ the\ Cart = Potential\ Energy\ Lost\ by\ the\ Cart\\\frac{1}{2}mv^2 = mgh\\\\h = \frac{v^2}{2g}[/tex]

where,

h = height of the hill = ?

v = speed of cart at the end = 10 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h = \frac{(10\ m/s)^2}{(2)(9.81\ m/s^2)}\\\\[/tex]

h = 5.09 m

Gravitational Potential Energy: You and your friend, who weighs the same as you, want to go to the top of the Eiffel Tower. Your friend takes the elevator straight up. You decide to walk up the spiral stairway, taking longer to do so. Compare the gravitational potential energy of you and your friend, after you both reach the top.

Answers

Answer:

Gravitational Potential Energy of both will be equal

Explanation:

The gravitational potential energy is given by the following formula:

[tex]P.E = mgh[/tex]

where,

P.E = Gravitational Potential Energy

m = mass of object

g = acceleration due to gravity

h = height of object

Therefore, the gravitational potential energy of an object depends only upon the height of the object and its mass.

Since, both masses and the heights achieved by both people is equal. Therefore, their gravitational potential energies will also be equal

Find the vector representing the area of the rectangle with vertices and oriented so that it faces downward. The magnitude of the vector equals the magnitude of the area; the direction is perpendicular to the surface. Since there are two perpendicular directions, we pick one by giving an orientation for the surface

Answers

Answer:

The answer is  "-72 k".

Explanation:

Please find the complete question in the attached file.

Given point:

[tex]A=(0,0,0)\\B=(0,8,0)\\C=(9,8,0)\\D=(9,0,0)[/tex]

[tex]\bar{AB} = (0i+8j+0k)-(0i+0j+0k)= 8j\\\\\bar{AC} = (9i+8j+0k)-(0i+0j+0k)= 9i+8j\\\\[/tex]

Calculating the area:

[tex]Area=\left|\begin{array}{ccc}i&j&k\\0&8&0\\9&8&0\end{array}\right|[/tex]

       [tex]=i[8(0)-8(0)]-j[(0-0)]+k[(0-9(8))]\\\\=i[0-0]-j[(0)]+k[(0-72)]\\\\=i[0]-j[(0)]+k[(-72)]\\\\=-72 \ k[/tex]

16x^2y^2-25a^2b^2
factorize the expression​

Answers

Answer:

(4xy+5ab)(4xy-5ab)

Explanation:

16[tex]x^{2}[/tex][tex]y^{2}[/tex]-25[tex]a^{2}[/tex][tex]b^{2}[/tex]

4^2 is 16 and 5^2 is 25,

Also, (x-a)(x+a) = x^2-a^2

So, this factorized is:

(4xy+5ab)(4xy-5ab)

Hope this helps!

Why do we perform stork stand test

Answers

Answer:

umm  becuase it is a test and you need them

Explanation:

A 1000 kg car moving at 108 km/h jams on its brakes and comes to a stop. How much work was done by friction?

Answers

Answer:

The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]

Explanation:

Given that,

Mass of car = 1000 kg

Initial speed of car =108 km/h =30 m/s

When the car is stop by brakes.

Then, final speed of car will be zero.

We need to calculate the work done by friction

Using formula of work done

[tex]W=\Delta KE[/tex]

[tex]W=K.E_{f}-K.E_{i}[/tex]

[tex]W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{f}^2[/tex]

Put the value of m and v

[tex]W=0-\dfrac{1}{2}\times1000\times(30)^2[/tex]

[tex]W=-450000 \ J[/tex]

[tex]W=-4.5\times10^{5}\ J[/tex]

Hence, The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]

Why is it easier to swim in sea than in a pond or river?

Answers

Answer:

Since sea water contains alot of salt the density of the sea water is higher as to the river water . So it makes it easier to swim in sea water

which items are matter?

Answers

Answer:

which items are matter?

battery , mobile phone

Battery and mobile phone I think cuz they are solid objects.

A raindrop charged to 10 μC experiences electric field of 10,000 V/m from a tip of a tree branch. What is the electric force acting on the raindrop? (1μC= 10^-6C)

a. 0.001 N
b. 100 N
c. 0.1N
d. 0.9 N

Answers

Answer:

(C). The magnitude of electric force acting on the raindrop is 0.1 N.

Explanation:

Given;

charge of the raindrop, Q = 10  μC = 10 x 10⁻⁶ C

electric field strength, E = 10,000 V/m

The electric force acting on the raindrop is given as;

F = EQ

where;

F is the electric force

Substitute the given values and solve for F.

F = (10,000)(10 x 10⁻⁶)

F = 0.1 N

Therefore, the magnitude of electric force acting on the raindrop is 0.1 N.

why water in earthern pot remain cool in summer

Answers

Answer:

The water kept in an earthen pot seeps into the small pores in the pot and evaporates from the surface of the pot. The heat required for evaporation is taken from water inside the pot, thus cooling the water stored inside. This is the reason why on hot summer days water remains cool in earthen pot.

PLEASE MARK ME AS BRAINLIEST

A small object carrying a charge of -4.00 nC is acted upon by a downward force of 24.0 nN when placed at a certain point in an electric field. What are the magnitude and direction of the electric field at the point in question

Answers

Answer:

[tex]E = -6 \ N/C[/tex]

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

Explanation:

From the question we are told that

   The charge on the small object is [tex]Q = -4.00 \ nC = -4.00 *10^{-9} \ C[/tex]

   The force is  [tex]F = 24 \ nN = 24 *10^{-9} \ N[/tex]

    Generally the magnitude of the electric  field is mathematically represented as

       [tex]E = \frac{F}{Q}[/tex]

=>    [tex]E = \frac{ 24 *10^{-9}} {-4 *10^{-9 }}[/tex]

=>     [tex]E = -6 \ N/C[/tex]

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

 

An athlete swings a 5.00-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.800 m at an angular speed of 0.500 rev/s. What are its centripetal acceleration?

Answers

Answer:

0.32m/s2

Explanation:

obtained from a=wr2 where w=anular speed

r-radius

Centripetal acceleration refers to the acceleration experienced by an object moving in a circular path. The centripetal acceleration of the ball is approximately [tex]9.86 m/s^2.[/tex]

Centripetal acceleration is a result of the inward force known as the centripetal force that keeps the object moving in a curved path. This force is necessary to counteract the tendency of the object to move in a straight line tangent to the circle.

To find the centripetal acceleration of the ball, we can use the formula:

centripetal  acceleration = [tex](angular speed)^2 * radius[/tex]

First, let's convert the angular speed from revolutions per second to radians per second. Since 1 revolution is equal to [tex]2\pi[/tex] radians, we have:

angular speed in radians per second = [tex]0.500 rev/s * 2\pi rad/rev[/tex]

angular speed in radians per second =[tex]\pi rad/s[/tex]

Now, we can substitute the values into the formula to calculate the centripetal acceleration:

centripetal acceleration = [tex](\pi rad/s)^2 * 0.800 m[/tex]

centripetal acceleration = [tex]\pi ^2 * 0.800 m[/tex]

Using the approximation[tex]\pi = 3.14[/tex], we can calculate the centripetal acceleration:

centripetal acceleration = [tex](3.14)^2 * 0.800 m[/tex]

centripetal acceleration =[tex]9.86 m/s^2[/tex]

Therefore, the centripetal acceleration of the ball is approximately [tex]9.86 m/s^2.[/tex]

For more details regarding centripetal acceleration, visit:

https://brainly.com/question/17123770

#SPJ2


A circuit with a 12 V battery and lamp has a current of 3 A. What is the resistance of the lamp?

Answers

chicken is the resistance of the lamp

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

The first person with the right answer gets to be a brainlest

In the attachment there is a density column where there is colour

Question: tell me why is the red at the bottom of the density column if it is the least dense

Answers

The most dense thing inside the column is the little star. It's pink, and it's resting on the bottom of the cylinder.

The red part under the star is the solid base that the cylinder is standing in. It's probably wood or plastic, it's not free to move, and it's not involved in the experiment.

Answer: That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what is its velocity after 2 seconds?

Answers

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

Solution,

Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

Here, a = -g

v = u-gt

v = (39.2)-(9.8)(2)

v = 19.6 m/s

So, its velocity after 2 seconds is 19.6 m/s.

How have telescopes changed the way scientists study our Solar System?

Answers

Answer:

Telescopes have changed the way scientists study the Solar System. Before telescopes, people were only able to observe the Universe with their naked eyes. ... If it were not for telescopes, scientists would not be able to detect possible threats to Earth or predict comet's sightings.

Explanation:

400 years ago, before telescopes, our understanding of the universe was very different.

This is what was believed:

We live on a spherical ball orbited by the rest of a finite, spherical universe.

Earth does not move. It is the center of the universe.

Our Sun orbits the Earth, as do all the other planets and the Moon.

The stars are distant objects, always perfect and unchanging.

How did telescopes & associated technologies unlock the secrets of the universe and

help us toward the understanding we have today where Earth is no longer at the center of

the universe? Instead, we know that ours is a small planet orbiting a star in the suburbs

of a large galaxy filled with billions of other stars and planets, surrounded by billions of

other galaxies becoming increasingly ever distant from each other by the expansion of

space.

This is the story of how telescopes continuously changed our understanding of the

universe and our place in it - transforming our view of our universe. And we still have

much more to discover!

2. Before telescopes, we could only use our eyes and a variety of measuring instruments to

plot the positions and movements of objects in the sky to create a limited understanding

of our universe. We had no way to know what these objects actually were and little

evidence for our relationship to the cosmos.

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