Answer:
Δϕ = -2.89 x 10^-4 Wb
Explanation:
Given that A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds. What is the magnitude of the total change in the external magnetic flux enclosed by the coil
Let ΔB = Change in magnetic field
A = cross sectional area = 8.5 cm^2
t = time = 12ms
Flux change = Δϕ = (ΔB*A) / t
Δϕ = [(0.02 - 0.06)x(8.5 x 10^-2)^2 ] / 0.012
Δϕ = (-0.04 x 7.225^-3) / 0.012
Δϕ = -2.89 x 10^-4 Wb
Therefore, the magnitude of the total change in the external magnetic flux enclosed by the coil is -2.89 x 10^-4 Wb
What is Newton first law?
Newton's First Law of Motion states "An object continues to be in its state of rest or of uniform motion along a straight line unless acted upon by an unbalanced force".
Can someone help me with these please I would appreciate it
Answer:
7) 5 m/s
8) 1.5 m/s
9) -9 m/s^2
10) 2.2 m/s
11) 5 s
Explanation:
These problems make use of the relations:
a = ∆v/∆t
d = 1/2at^2 . . . . acceleration to/from rest
v^2 = 2ad . . . . . acceleration to/from rest
In each case, choose the formula appropriate to the question, fill in the given values, and solve for what's missing.
__
7) v^2 = 2ad
v = √(2(9.8 m/s^2)(1.5 m)) = √(29.4 m^2/s^2) ≈ 5 m/s
__
8) d = 1/2at^2
a = 2d/t^2 = 2(75 m)/(10 s)^2 = 1.5 m/s^2
__
9) a = ∆v/∆t
a = (-45 m/s)/(5 s) = -9 m/s^2
__
10) a = ∆v/∆t
∆v = a·∆t = (0.09 m/s^2)(10 s) = 0.9 m/s
Vivian's final speed is the initial speed plus the change in speed:
1.3 m/s + 0.9 m/s = 2.2 m/s
__
11) a = ∆v/∆t
∆t = ∆v/a = (0.50 cm/s -0.75 cm/s)/(-0.05 cm/s^2) = -.25/-.05 s = 5 s
What is the objective of playing basagang palayok?the goal what is the goal of playing basang palayok
Answer:
Explanation:
At first glance, it looked like a group of kids-at-heart playing traditional Filipino games under the sun. But up close the games were played by public school teachers staging a unique protest to demand government to prioritize their welfare.
Some 100 members of the Teacher’ Dignity Coalition (TDC) from Metro Manila staged what they called “Palarong Pampista” at the Plaza Miranda in Manila yesterday to demand salary increases this year.
The protest is part of the “Protest de Mayo” launched by TDC earlier this month to call for a P10,000 across-the-board increase in salaries of government teachers and the scrapping of the performance-based bonus of the Aquino government which they described as “deceptive, unfair and divisive.”
During the protest, teachers played traditional fiesta games like Palo Sebo and Basagang Palayok “to demonstrate their sacrifices for the country despite the inadequate compensation from the government.”
TDC National Chairperson Benjo Basas said Palo Sebo and Basagang Palayok were symbols of how the government is treating public school teachers.
Palo Sebo, a popular fiesta game in which contestants climb a greased bamboo in order to get the money prize at the top, is the same as the government’s performance-based bonus or PBB, Basas said.
“It promises a cash prize, but teachers and employees need to fight and pull others down in order to be on top,” he explained.
The Basagang Palayok is also another popular fiesta game where the players’ objective is to hit the hanging pot with prizes. Basas said that in this game, “the player is blindfolded, and like the P10,000 salary increase demand, the prize is uncertain and the players must make all the effort and pass the obstacles.”
Earlier, Education Secretary Armin Luistro said that the Department of Education (DepEd) “recognizes the right of our teachers to raise their concerns publicly.”
“We will not object to any measure that will help public school teachers,” said Luistro. “As long as there is adequate funding, a raise in teachers’ salaries will be welcome,” he said.
However, while DepEd expressed support to the plight of public school teachers for salary increase, Luistro enjoined “certain groups not to take any action that greatly affects the delivery of basic services to our learners.”
TDC, a 30,000-strong group, has set several other unique mass actions until the resumption of classes in June 2 in all public elementary and secondary schools nationwide.
The goal of playing basang palayok is successfully smashes the palayok (clay pot)
basang palayok its a Filipino traditional fun game played during fiestas and birthday parties. For this game the following objects are necesary
Palayok (clay pot) Candies, coins or chocolates Small pieces of colorful paper Flour Rope
Then the palayok is filled with sweets, coins, flour, chocolates and colored paper and later suspended with the rope in the air by trying it on a branch of a tree traditionally a Mango tree.
Then a player will be blindfolded and then spins around close to ten times to disorient him/her. After that, the player will be given a bamboo pole as commonly used to hit the pot.
In that moment, the game starts and the crowd shouts out instructions to the player such as "go straigh, to the left, to the right, stop" and the player get on attempt to hit it hard enough to break the clay pot.
If he/she does not break the pot, another guest at the party gets his/her turn If he breaks it everyone in the crowd goes for the goodiesFinally, the player who successfully smashes the palayok is given a prize.
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Two objects are held close together. When they are released, they move toward one another. Which conclusion is
supported by this evidence?
O The objects are both positively charged.
O The objects are both negatively charged.
O The objects have no charge.
O The objects have opposite charges.
Answer:
they have opposite charges
Your dirty clothes, left on the floor overnight, are there when you wake up in the morning. What type of law is at work ?
Answer:
1st law of motion
Explanation:
it's newton's first law of motion.
Answer:
A C E
Explanation:
You threw a ball straight up into the air at 7.34m/s. How high does the ball go?
Answer:
7.34x
Explanation:
Depends on how long it was in the air. 7.34x, x is how many seconds.
Consider a system consisting of two Einstein solids, A and B, each containing N= 10 oscillators, and sharing a total of q= 20 units of energy. Assume that the two solids areweakly coupled and the total energy is fixed.
Required:
a. How many different macrostates are available to solid A or B?
b. How many different microstates are available to the combined system of A & B?
c. Starting with the exact form for the multiplicity of an Einstein solid, calculate the probability of finding all the energy in solid A, assuming that the system is in thermal equilibrium.
d. Calculate the probability of finding exactly half the energy in solid A.
Answer:Gg
Explanation:
A girl runs 120m due north in 15s. she then runs 80m due east in 12s.What is average speed?
The average speed of the girl is 2.26 m/s.
The average speed is calculated by dividing the total distance traveled by the total time taken. In this case, the girl traveled a total distance of 120 m + 80 m = 200 m. She took a total time of 15 s + 12 s = 27 s to travel this distance.
Therefore, the average speed is:
average speed = total distance / total time
average speed = 200 m / 27 s
average speed = 2.26 m/s
The average speed does not take into account the direction of the motion. The girl traveled in two different directions, so the average speed is not a meaningful measure of her speed.
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What energy movement lasting about 5 to 15 minutes and does not require energy?
Answer:
cause it too powerful lol ;)
HELP PLS
Given the following blackbody curve graph, what color will Star A be?
Blackbody radiation graph for Star A, which has a surface temperature of 5,700 degrees Celsius. At the point where the curve peaks, the wavelength is approximately 550 nanometers, in the middle of the visible light spectrum.
Blue
Red
White
Yellow
Answer:
red I think
Explanation:
it's on red so I googled some of it and the closest was red
Answer:
Red
Explanation:
How fast must a 2.7-g ping-pong ball move in order to have the same kinetic energy as a 145 g baseball moving at 37.0 m/s
Answer:
271.14m/sExplanation:
The kinetic energy of the 145g is
mass= 0.145kg
velocity= 37m/s
KE=1/2mv^2
KE=1/2(0.145*37^2)
KE=1/2(0.145*1369)
KE=1/2(198.505)
KE=198.505/2
KE=99.25J
Now since the kinetic energy of the 2.7g must be 99.25J
mass =2.7g= 0.0027kg
99.25=1/2(0.0027)v^2
99.25=0.00135v^2
99.25/0.00135=v^2
73518.5185185=v^2
v=√73518.5185185
v=271.14m/s
A bowling ball of mas 6.0 kg is released from rest
Answer:
could u give a more longer understanding
A rod of length Lo moves iwth a speed v along the horizontal direction. The rod makes an angle of (θ)0 with respect to the x' axis.
Required:
a. Show that the length of the rod as measured by a stationary observer is L=L0[1-v^2/c^2 cos^2(θ)0].
b. Show that the angle the rod makes iwth the x-axis is given by the expression tan(theta)=tan(θ)0/(1-v^2/c^2)^.5
Answer:
From the question we are told that
The length of the rod is [tex]L_o[/tex]
The speed is v
The angle made by the rod is [tex]\theta[/tex]
Generally the x-component of the rod's length is
[tex]L_x = L_o cos (\theta )[/tex]
Generally the length of the rod along the x-axis as seen by the observer, is mathematically defined by the theory of relativity as
[tex]L_xo = L_x \sqrt{1 - \frac{v^2}{c^2} }[/tex]
=> [tex]L_xo = [L_o cos (\theta )] \sqrt{1 - \frac{v^2}{c^2} }[/tex]
Generally the y-component of the rods length is mathematically represented as
[tex]L_y = L_o sin (\theta)[/tex]
Generally the length of the rod along the y-axis as seen by the observer, is also equivalent to the actual length of the rod along the y-axis i.e [tex]L_y [/tex]
Generally the resultant length of the rod as seen by the observer is mathematically represented as
[tex]L_r = \sqrt{ L_{xo} ^2 + L_y^2}[/tex]
=> [tex]L_r = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}[/tex]
=> [tex]L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}[/tex]
=> [tex]L_r = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}[/tex]
=> [tex]L_r = \sqrt{L_o^2 * cos^2(\theta) [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}[/tex]
=> [tex]L_r = \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }[/tex]
=> [tex]L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]
Hence the length of the rod as measured by a stationary observer is
[tex] L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]
Generally the angle made is mathematically represented
[tex]tan(\theta) = \frac{L_y}{L_x}[/tex]
=> [tex]tan {\theta } = \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }[/tex]
=> [tex]tan(\theta ) = \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }[/tex]
Explanation:
The special relativity relations allow to find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: [tex]L = L_o \sqrt{1 - \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]
b) The angle with respect to the x axis is: [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]
Special relativity studies the motion of bodies with speeds close to the speed of light, with two fundamental assumptions.
The laws of physics are the same in all inertial systems. The speed of light in vacuum has the same value for all inertial systems.
If we assume that the two systems move in the x-axis, the relationship between the components of the length are:
[tex]L_x = L_{ox} \ \sqrt{1- \frac{v^2}{c^2} }[/tex]
[tex]L_y = L_o_y \\L_z = L_{oz}[/tex]
Where the subscript "o" is used for the fixed observed on the rod, that is, it is at rest with respect to the body, v and c are the speed of the system and light, respectively.
a) They indicate that the length of the rod is L₀ and it forms an angle θ with the horizontal.
Let's use trigonometry to find the components of the length of the rod in the system at rest, with respect to it.
sin θ = [tex]\frac{L_{oy}}{L_o}[/tex]
cos θ = [tex]\frac{L_{ox}}{L_o}[/tex]
[tex]L_{oy}[/tex] = L₀ sin θ
L₀ₓ = L₀ cos θ
Let us use the transformation relations of the length of the special relativity rod.
x-axis
[tex]L_x = (L_o cos \theta_o) \ \sqrt{1- \frac{v^2}{c^2} }[/tex]
y-axis
[tex]L_y = L_{o} sin \theta_o[/tex]
The length of the rod with respect to the observer using the Pythagorean theorem is:
L² = [tex]L_x^2 + L_y^2[/tex]
[tex]L^2 = (L_o cos \theta_o\sqrt{1- \frac{v^2}{c^2} })^2 + (L_o sin \theta_o)^2[/tex]
[tex]L_2 = L_o^2 ( cos^2 \theta_o - cos^2 \theta_o \frac{v^2}{c^2} + sin^2\theta_o)[/tex]
[tex]L^2 = L_o^2 ( 1 - \frac{v^2}{c^2} \ cos^2 \theta_o)[/tex]
[tex]L= Lo \sqrt{1- \frac{v^2}{c^2} cos^2 \theta_o}[/tex]
b) the angle with the x-axis measured by the stationary observer is:
[tex]tna \theta = \frac{L_y}{L_x}[/tex]
[tex]tan \ theta = \frac{L_o sin \theta_o}{L_o cos \theta_o \sqrt{1- \frac{v^2}{c^2} } }[/tex]
[tex]tan \theta = \frac{tan \theta_o}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]
In conclusion, using the special relativity relations we can find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: [tex]L = L_o \sqrt{1- \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]
b) The angle to the x axis is: [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]
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Make sure to answer all questions that have not yet been answered Last/First Name (print): PHYS 1440-Section Username ID (XXX9999) WS Analysis A: 1. The voltage difference between the AA and AAA batteries should be quite small. What then might be the difference between them? AXAUUUUUU 2. If we have a resistor labeled brown-black-green-gold, what is the average expected value? Why is it necessary to measure the resistor? Analysis B: 3. What is the average voltage in step 8 of part B? And, when a DC offset is applied, what is the average voltage then? 4. What two values were obtained when calculating the root-mean-square voltage in step 13? How do they compare to the measured value? Which one is correct, and why? (Hint: with an offset Vrms = /DC +
Answer:
hello questions under analysis B are not complete hence I couldn't provide its answers
1)
AA batteries have more electrochemical composition AAA batteries are smaller AA batteries store more charges when compared with AAA batteries2) The average expected value is 1000 k ohms
Explanation:
1) The difference between AA and AAA batteries
some of the differences are
AA batteries have more electrochemical composition AAA batteries are smaller AA batteries store more charges when compared with AAA batteries2) The average expected value is 1000 k ohms
also it is necessary to measure the resistor because the actual value of resistance gotten from measurement is always different from the value obtained from color coding. also note that The last color band indicates the tolerance.
and the resistor given has Gold as its last color band
6.
The minimum value of coefficient of friction (u)
such that block of mass '5 kg' remains at rest is
5 kg
μ
ng
3 kg
(1) 0.3
(3) 0.6
(2) 0.5
(4) 0.4
Answer:
2
Explanation:
It is simple coman sense
Which action would increase the strength of the electric force between the
balloon and the water?
A. Holding a magnet near the stream of water
B. Holding the balloon closer to the stream of water
C. Holding a magnet near the balloon
D. Moving the balloon farther away from the stream of water
Answer:
B
Explanation:
Holding the balloon closer to the stream of water
Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water. Thus, the correct option is B.
What is electric force?The repulsive or attractive interaction between any two charged bodies is called as the electric force. This is similar to any force, the impact and effects on the given body are described through the Newton's laws of motion. The electric force is one of the various forces which act on objects.
Electric force is the attractive force which is present between the electrons (negatively charged bodies) and the nucleus. Here, a positive charge or a negative charge creates a field in the empty space which is around it, and we call that empty space as an electric field.
Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water.
Therefore, the correct option is B.
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Calculate the acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N.
Answer:
3.8 m/s/s^2
Explanation:
The acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N is 3.8 m/s².
What is acceleration due to gravity?The gravitational force is the force by which an object attracts other objects into its centre of mass. The force it exerts depends on the mass of the body and distance between them. Earth attracts every objects on its surface to the ground by gravitational force
The acceleration arises in the body due to the force of gravitation is called acceleration due to gravity (g). It varies from planets to planet. The weight we experience in earth is due to the gravity.
Weight = m g
where m is the mass.
given the mass of an astronaut = 80 kg
weight = 304 N
then g = weight/ mass
= 304 N / 80 Kg = 3.8 m/s²
Therefore, the acceleration due to gravity of the planet is 3.8 m/s².
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Question 1 Water: Start with the Water tab. Note that light areas represent places where the water is high (crests). Dark areas represent low points (troughs). The water drops should already be dripping from the faucet. You can inerease their frequency and amplitude by using the Frequency and Amplitude slider. Using the controls on the far right, you can add measuring tools, add wall, add another faucet, or insert a single-slit or tw0-slit barrier. Part A What kind of wave patterns do you observe in the sink in the top view? I Part B Click on the Show Graph button in the top right corner of the window. The graph shows the moving water level, which is the actual amplitude of the waves. What general mathematical graph function does this look like? What pattern do you observe in the amplitude of these waves? Provide a hypothesis to explain this pattern in the amplitude. I Part C What happens when you increase the frequency of the water drops? What happens to the wavelength of the waves on the surface of water? PLZ ANSWER ALL FOR BRAINLIEST
Answer:
Looks like a cosine function graph. The wave pattern is transversal waves . The faster the amplitude the higher the wave. The force of the drop hitting the water pushes the water down and out causing waves If the water hits from a higher amplitude the waves raise bigger . When you increase the frequency of the water drops the waves move faster but no bigger. When you increase the frequency of the water drops the wave ripples faster .
Explanation:
An answer to part of your question
A transverse wave is the kind of wave pattern I observe in the sink in the top view.
Transverse waves
A transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations
The following are examples of sources, except:
A. written letter
B. interview
C. Table of contents
D. photo
I'm pretty sure your answers are B, D, A
HELP ASAP!!!!!!
Which change will decrease the electric force between two positively charged objects?
1.moving them closer together
2.moving them farther apart
3.adding neutrons
4.removing electrons
Answer:
I think it’s adding neutrons
Explanation:
Plastic is a good conductor of heat. True/ False
Answer:
false because they have no fee electrons
False, it is a poor conductor of heat. They are great insulators though.
For a substance to change from a gas to a liquid what must happen to its particles
A. they must lose enough of their kinetic energy that their motion is influenced by the attractions between them
B. they must gain enough kinetic energy ti allow them to move freely while still being attracted to one another
C. They must lose enough of their kinetic energy so that the attractions between them hold in place as they vibrate
D. They must gain enough kinetic energy to break out of their ridged structure and move independently
For a substance to change from a gas to a liquid, its particles A. must lose enough of their kinetic energy that their motion is influenced by the attractions between them.
We want to know what change takes place when the particles of a substance that goes from gas to liquid. We need to consider that:
In a gas, the particles move freely, with great kinetic energy and the attraction forces between them are negligible.In a liquid, the particles have some degree of movement, although less than in the gas state and the attraction forces are higher.For a substance to change from a gas to a liquid what must happen to its particles:
A. they must lose enough of their kinetic energy so that their motion is influenced by the attractions between them. TRUE. The attraction between the molecules causes them to move less in the liquid state. B. they must gain enough kinetic energy to allow them to move freely while still being attracted to one another. FALSE. Liquids have lower kinetic energies than gases. C. They must lose enough of their kinetic energy so that the attractions between them hold in place as they vibrate. FALSE. Even though they must lose kinetic energy, they still have some left to move rather than just to vibrate. D. They must gain enough kinetic energy to break out of their ridged structure and move independently. FALSE. Liquids have lower kinetic energies than gases.For a substance to change from a gas to a liquid, its particles A. must lose enough of their kinetic energy that their motion is influenced by the attractions between them.
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Answer: A
Explanation:
5. A horizontal force of 10 N is applied to a 1-kg object resting on a frictionless table. How much will the object accelerate?
A. 3.25 m/s2
B. 6.0 m/s2
C. 9.0 m/s2
D. 10 m/s2
Answer:
C
Explanation:
because it is TM
What is the velocity of Car B after collision?
Answer:
30m/s
Explanation:
m1v1=m2v2
12 * 10=4* v2
120/4 =v2
V2=30m/s
If an airplane needs a minimum of 148 m/s to take off, and it accelerates at 3 m/s^2, how long should the runway be so that it can take off at this minimum speed?
Assuming it takes off from rest, the runway should have length x such that
(148 m/s)² - 0² = 2 (3 m/s²) x
which follows from the formula,
v² - u² = 2 a ∆x
(where u is initial speed and v is final speed; the other two's significance should be obvious)
Solve for x :
x = (148 m/s)² / (2 (3 m/s²))
x ≈ 3650.67 m
In a nuclear power plant, the nuclear reaction is kept from going critical by keeping the rate of reaction safe.
How do the control rods figure into this?
A. The control rods absorb the excess heat produced in the reaction.
B. The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.
C. The control rods absorb excess uranium atoms so that the reaction doesn't happen too quickly.
D. The control rods provide additional neutrons to keep the reaction going.
Answer:
B. The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly
Answer:
The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.
Explanation:
I took the test before.
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what is the weight of a 10 kg object on earth
Answer:
100N.
Its 100n. :)
a table is pushed it 15 metre across a room with the force of 50N.what is the work done?
Answer:
W=f*d
= 50 * 15
=750 J
Therefore, the work done is 750 joule( J)
A bird flew to catch a prey and went from 12 m/s to 22 m/s in 2 seconds. What was the magnitude of the bird's acceleration?
Answer: Peregrine falcons are famed for their high-speed, high-altitude stoops. Hunting prey at perhaps the highest speed of any animal places a stooping falcon under extraordinary physical, physiological, and cognitive demands, yet it remains unknown how this behavioural strategy promotes catch success. Because the behavioral aspects of stooping are intimately related to its biomechanical constraints, we address this question through an embodied cognition approach. We model the falcon’s cognition using guidance laws inspired by theory and experiment, and embody this in a physics-based simulation of predator and prey flight. Stooping maximizes catch success against agile prey by minimizing roll inertia and maximizing the aerodynamic forces available for maneuvering but requires a tightly tuned guidance law, and exquisitely precise vision and control.
Explanation:
The graph below was created from the motion of a cart on a ramp. Use the graph to answer the question that follows.
main seconde
What is the acceleration of the object at t4s?