A 20 foot ladder is set against the side of a house so that it reaches up 16 feet. If Christian grabs the ladder at its base and pulls it 2 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 14 ft.) Round to the nearest tenth of a foot.

Answers

Answer 1

Answer:

14.2

Step-by-step explanation:

The ladder forms a right angles triangle,

We have,

h=20

p=16

b=x

Using pythogorean theorem,

b=√(20^2-16^2)

√144

b=12

Now,

Since, she pulls it 2 cm,

b=x+2

b=14

p=?

Using pythogorean theorem,

p=√(20^2-14^2)

√204

p=14.2828568571

Rounding  to the nearest tenth,

p=14.2

Answer 2

The side of the ladder will reach up is 14.3 feet.

What is trigonometric Ratios?

"Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. It is with respect to any of its acute angles are known as the trigonometric ratios of that particular angle".

For the given situation,

Hypotenuse, h = 20 feet

Perpendicular, p = 16 feet

Base = b

By Pythagoras theorem,

[tex]h^{2} = p^{2} + b^{2}[/tex]

⇒[tex]20^{2} = 16^{2}+b^{2}[/tex]

⇒[tex]b^{2} = 400-256[/tex]

⇒[tex]b^{2}=144[/tex]

⇒[tex]b=\sqrt{144}[/tex]

⇒[tex]b=12[/tex]

The ladder at the house is pulled 2 feet farther.

So, base = [tex]12+2[/tex]

⇒[tex]b=14[/tex]

Now, the side of the ladder will reach up

[tex]p^{2} = h^{2}-b^{2} \\[/tex]

⇒[tex]p^{2}=20^{2}-14^{2} \\[/tex]

⇒[tex]p^{2}=400-196[/tex]

⇒[tex]p^{2}=204[/tex]

⇒[tex]p=\sqrt{204}[/tex]

⇒[tex]p=14.28[/tex]

⇒[tex]p=14.3[/tex] (rounded off to nearest tenth)

Hence we can conclude that the side of the ladder will reach up is      14.3 feet.

Learn more about trigonometric ratios here

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To learn more on transformation rules: https://brainly.com/question/29088211

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