Answer:
375.1 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 15.5 × 24.2
We have the final answer as
375.1 NHope this helps you
Balboa Park in San Diego has an outdoor organ. When the air temperature increases, how does the fundamental frequency of the one of the organ pipes change?
a. increases
b. decreases
c. stays the same
d. is impossible to determine. (The thermal expansion of the pipe is negligible.)
Answer:
a. increases
Explanation:
Outdoor pipe organ is a musical instrument that is used to play music. It produces some soothing notes and is very peaceful to the ears. The organ pipe is the source of sound for the outdoor organ. And the length of the pipe determines the wavelength of the sound. When the air temperature of the surrounding is increased, the fundamental frequency of one of the organ pipes will be increased as the speed of the sound will increased.
My buddy and i are planning to dive at a site at a site where the water and air temperature are near freezing. We plan to dive to 18 meters for 30 minutes. What dive profile would we use when planning our dive
The dive profile used when planning our dive would be 22 metres/70 feet for 30 minutes.
What is diving?
Diving is the sport or activity of swimming for exploring under water.
My buddy and I are planning to dive at a site where the water and air temperature are near freezing. We plan to dive to 18 meters for 30 minutes.
A General rule as printed on the RDP Table and eRDPML is that if someone planning a dive in cold water that might be harmful. Plan the dive assuming the depth is 4 meters/10 feet deeper than actual. For any other information, see the RDP/eRDPML Instructions for Use booklet.
Thus, dive profile used would be 22 metres/70 feet for 30 minutes.
Learn more about diving.
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it takes 10 J of energy to move 2 C of charge from point A to point B. How large is the potential difference between points A and B
Given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.
What is potential difference?Potential difference is simply referred to as work done required to move a charge from point A to point B per unit charge.
It is expressed as;
V = W / q
Given the data in the question;
Work done W = 10JQuantity of charge q = 2CPotential difference V = ?We substitute our values into the exression above.
V = W / q
V = 10J / 2C
V = 5V
Therefore, given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.
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Plants that respond to light are responding
to an:
a. internal stimulus
b. external stimulus
please answer
Answer:
The answer would be a
Explanation:
1) Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Chuck, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, Andrea's tangential speed is which of the following?a) twice Chuck's.b) the same as Chuck's.c) half of Chuck's.d) impossible to determine.2) When the merry go round is rotating at a constant angular speed, Andrea's tangential speed is:______.a) twice Chuck's.b) the same as Chuck's.c) half of Chuck's.d) impossible to determine.
Explanation:
The tangential speed of Andrea is given by :
[tex]v=r\omega[/tex]
Where
r is radius of the circular path
ω is angular speed
The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'
r' = 2r
New angular speed,
[tex]v'=r'\omega'\\\\v'=(2r)\omega\\\\v'=2r\omega\\\\v'=2v[/tex]
New angular speed is twice that of the Chuck's speed.
Suppose that you take a 10 kg mass on the surface of the earth and then place it on the moon. What will
the mass of the object on the moon be?
Answer:
10 kg
Explanation:
The mass of an object does not change even if the amount of gravtiy changes.
A man is pushing a box of mass m along the ground with a force F. The coefficient of kinetic friction between the box and the ground is μk. The box is accelerating, but then the person stops pushing and the box slides to a halt. The person then starts pushing on the box again with a force F, but the box doesn't budge. The maximum coefficient of static friction between the box and the ground is μs. Identify which of the following statements is true?
a. F > μk/μs
b. μk > μs
c. μkmg < F <= μsmg
d. μsmg= F
Answer: Option C.
Explanation:
When the box is moving, he pushes with a force F.
in this case, the coefficient is μk, and the box is accelerating, this means that the net force is not zero, so F is larger than the friction force.
When the box is still, the man pushes again with a force F, but now the box does not move, so there is no acceleration, which means that the net force is zero, then F is not greater than the maximum static friction force.
Now, the friction force between an object of mass M, and a surface with a coefficient of friction μ is: μ*m*g
where g is the gravitational acceleration.
Then, from the first part, we can conclude that:
μk*m*g < F
(the force F is larger than the kinetic friction force)
and from the second part, we know that:
F ≤ μs*m*g
(The force F is not greater than the static friction force)
If we write those two together, we have:
μk*m*g < F ≤ μs*m*g
Then the correct option is c.
1. What is the gravitational force between a 100 kg football player and the Earth at 5.98 x 1024 kg, with a
distance of 6.38 x 106 m?
Answer:
981N
Explanation:
The gravitational force between the football player and the Earth at the given distance is 979.91 N.
The given parameters:
Mass of the player, m = 100 kgMass of the Earth, M = 5.98 x 10²⁴ kgDistance between the bodies, r = 6.38 x 10⁶ mThe gravitational force between the football player and the Earth at the given distance is calculated by applying Newton's law of universal gravitation as follows.
[tex]F = \frac{GmM}{r^2} \\\\F = \frac{6.67 \times 10^{-11} \times 100 \times 5.98 \times 10^{24}}{(6.38 \times ^6)^2} \\\\F = 979.91 \ N[/tex]
Thus, the gravitational force between the football player and the Earth at the given distance is 979.91 N.
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A racing car starts from rest at t=0 and reaches a final speed v at time t. If the acceleration of the car is constant during this time, which of the following statements are true? a) the average speed of the car is v/2; b) the car travels a distance vt; c) the magnitude of the acceleration of the car is v/t; d) the velocity of the car remains constant; or e) none of the statements is true
Answer:
All true statements are shown: a) The average speed of the car is [tex]\frac{v}{2}[/tex], c)The magnitude of the acceleration of the car is [tex]\frac{v}{t}[/tex].
Explanation:
Let prove the validity of each statement:
a) The average speed of the car is [tex]\frac{v}{2}[/tex].
The average speed ([tex]\bar v[/tex]) is defined by the following formula:
[tex]\bar v = \frac{v_{o}+v_{f}}{2}[/tex] (1)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the racing car.
If we know that [tex]v_{o} = 0[/tex] and [tex]v_{f} = v[/tex], then the average speed of the racing car:
[tex]\bar v = \frac{0+v}{2}[/tex]
[tex]\bar v = \frac{v}{2}[/tex]
The statement is true.
b) The car travels a distance [tex]v\cdot t[/tex].
Since the racing car is accelerating uniformly, the distance travelled by the car is represented by the following kinematic formula:
[tex]x - x_{o}=v_{o}\cdot t + \frac{1}{2}\cdot a\cdot t^{2}[/tex] (2)
Where [tex]a[/tex] is the acceleration of the racing car, measured in meters per square second.
The statement is false.
c) The magnitude of the acceleration of the car is [tex]\frac{v}{t}[/tex].
Since the racing car is accelerating uniformly, the velocity of the racing car is represented by the following kinematic formula:
[tex]v_{f} = v_{o}+a\cdot t[/tex] (3)
Then, we clear the acceleration of the expression:
[tex]a = \frac{v_{f}-v_{o}}{t}[/tex]
If we know that [tex]v_{o} = 0[/tex] and [tex]v_{f} = v[/tex], then the acceleration of the car is:
[tex]a = \frac{v-0}{t}[/tex]
[tex]a = \frac{v}{t}[/tex]
The statement is true.
d) The velocity of the car remains constant.
Since the car accelerates uniformly, the vehicle does not travel at constant velocity.
The statement is false.
You notice electric field lines going towards an isolated charged object in a radial manner. What is the sign of the net charge on the object?a. negative.b. positive.c. neutral.
Answer:
The correct answer is a
Explanation:
The electric field is given by the relation
F = q E
where The force is the Coulomb force and q is a positive test charge, therefore the electric field has the same direction as the electric force.
Consequently if the charge is positive the field must go out of the charge, if the charge is negative the electric field must be directed towards the charge.
Consequently, in this exercise we are told that the lines are directed towards the load, therefore the load must have a negative sign.
The correct answer is a
How much force does it take to accelerate a car mass 1750kg at 20m/s
Answer:
The needed force is 35,000 N.
Explanation:
By the second Newton's law, we know that:
F = M*a
Force equals mass times acceleration.
If we know that the mass of the car is 1750kg, then M = 1750kg, and the acceleration is 20 m/s^2, then a = 20m/s^2
We can replace these values in the original equation to find the value of F.
F = 1750kg*20 m/s^2 = 35,000 N
The 1kg rock is tied to a string and swung in a circular path as shown. The 1 meter string is tied to a post, and during the motion, the string has a 30 angle with the post. The rock makes 100 rounds in 1 minute. The centripetal force on the rock is
Answer: 54.8
Explanation:
The centripetal force on the rock moving along the string is 104.66 N.
The given parameters;
the mass of the rock, m = 1 kgangle of inclination of the string, θ = 30⁰angular velocity of the rock, ω = 100 rev/minlength of the string, r = 1 mThe centripetal acceleration of the rock is calculated as follows;
[tex]\omega _f^2 = \omega _i^2 + 2\alpha (\theta)\\\\(100 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} )^2 = 0 + 2\alpha (30 ^0 \times \frac{\pi \ rad}{180^0} )\\\\109.69 = 1.048\alpha \\\\\alpha = \frac{109.69}{1.048} \\\\\alpha =104.66 \ rad/s^2[/tex]
[tex]a_c = \alpha \times r\\\\a_c = 104.66 \times 1 = 104.66 \ m/s^2[/tex]
The centripetal force on the rock is calculated as follows;
[tex]F_c = ma_c[/tex]
[tex]F_c = 104.66 \times 1\\\\F_c = 104.66 \ N[/tex]
Thus, the centripetal force on the rock moving along the string is 104.66 N.
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A 2.0 kg mass on a horizontal spring is pulled back 2.0 cm and released. If, instead, a 0.40 kg mass were used in this same experiment, the total energy of the system would: ________
a. Remain the same.
b. Double.
c. Be half as large.
Answer:
a. Remain the same.
Explanation:
The total energy of the spring mass system is given as
[tex]$E=\frac{1}{2}kx^2 $[/tex]
where k is the spring constant of the spring
x is the compression or expansion of the spring
The energy of the spring mass system is always independent of mass. It does not depends on the mass object attached to the spring.
Therefore, the total energy of the system will remain the same in the experiment when the mass is changes the second time.
Select the correct answer.
What are the units for the spring constant, k?
OA newton meters
OB. newton seconds
OC. newtons/meter
OD. newtons/second
E. newtons/seconds
Does the air in a room or water in a pot have to be at a certain temperature to create convection? Yes or No? and Explain why?
Answer:
Yes
Explanation:
because that temperature creates the bulk movement of molecules due to increase in their kinetic energy
PLEASE HELP ME 20 POINTS Some metals have a molecular structure that makes them good conductors. Explain how understanding this relationship can help engineers make more powerful batteries.
PLEASE I KNOW THE STRUCTURE I JUST NEED HOW BY UNDERSTANDING THE RELATIONSHIP THEY CAN MAKE MORE POWERFUL BATTERIES.
PLEASE IM DYEING HERE I JUST NEED THIS ANSWER I WILL GIVE BRAINLIST AND 5 STARS A HEART WHATEVER JUST PLEASEEEEE.
Answer:
negative plus positive with energy = battery
Explanation:
A tiny water droplet of radius . descends through air from a high building.
Calculate its terminal velocity. Given that for air = × − −− and density of the water = -3
Correct question is;
A tiny water droplet of radius 0.010 cm descends through air from a high building .Calculate its terminal velocity . Given that η of air = 19 × 10^(-6) kg/m.s and density of water ρ = 1000kg/ms
Answer:
1.146 m/s
Explanation:
We are given;
Radius; r = 0.010 cm = 0.01 × 10^(-2) m
η = 19 × 10^(-6) kg/m.s
ρ = 1000 kg/ms
The formula for the terminal velocity is given by;
V_t = 2r²ρg/9η
g is acceleration due to gravity = 9.8 m/s²
Thus;
V_t = (2 × (0.01 × 10^(-2))² × 1000 × 9.8)/(9 × 19 × 10^(-6))
V_t = 1.146 m/s
How is a mesa formed
Mesas form by weathering and erosion of horizontally layered rocks that have been uplifted by tectonic activity. Variations in the ability of different types of rock to resist weathering and erosion cause the weaker types of rocks to be eroded away, leaving the more resistant types of rocks topographically higher than their surroundings. This process is called differential erosion.
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1) A 40 kg girl gets on her 10 kg wagon on level ground with two 5 kg bricks. She throws the bricks horizontally off the back of the wagon one at a time at a speed of 7 m/s relative to herself. a) How fast does she go after throwing the second brick
Answer:
1.4 m/s
Explanation:
Assuming that the system is an isolated one, then we will conserve the linear momentum of the system so as to be able to solve the system for required quantities:
Using the conservation of momentum, we have,
initial momentum = final momentum
P(i) = P(f)
And from the question, we see that the system has no initial momentum
After throwing the first brick we have
(40 + 10 + 5)v2 + 5 * -7 = 0
55v2 - 35 = 0
55v2 = 35
v2 = 35/55
v2 = 0.63 m/s
Now, considering that she conserves momentum when she throws the second brick again, we then say
(40 + 10 + 5) * 0.63 = (40 + 10)v(f) + 5 * -7
55 * 0.63 = 50v(f) - 35
35 = 50v(f) - 35
50v(f) = 35 + 35
50v(f) = 70
v(f) = 70/50
v(f) = 1.4 m/s
Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) and the angle with the vertical is identical (7^o). Find the magnitude of the charge on each sphere. The acceleration of gravity is 9.8 m/s^2 and the value of Coulomb
Answer:
The value is [tex]q = 3.4 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The mass of each sphere is [tex]m_1 = m_2 = m = 0.020 \ kg[/tex]
The length of the string is [tex]l = 0.18 \ m[/tex]
The angle of with the vertical is [tex]\theta = 7^o[/tex]
The acceleration due to gravity is [tex]g = 9.8 \ m/s^2[/tex]
Generally the force acting between the forces is mathematically represented as
[tex]F = T cos \theta = \frac{k* q^2}{ r^2}[/tex]
=> [tex]T cos \theta = \frac{k* q^2}{ r^2}[/tex]
Generally from Pythagoras theorem the radius of the circular curve created by the force is
[tex]r = 2 L sin (\theta )[/tex]
=> [tex]r = 2* 0.180 sin (7)[/tex]
=> [tex]r = 0.043 \ m[/tex]
=> [tex]q = tan \theta * \frac{m * g * r^2 }{k}[/tex]
=> [tex]q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}[/tex]
=> [tex]q = 3.4 *10^{-6} \ C[/tex]
How can music imitate nature?
Answer:
There are at least two ways contemporary music in America has made use of nature by directly making use of the sounds of nature as musical material, or else in works that desire to imitate nature "in its manner of operation." That is, they are constructed the way nature is, they work the way nature works, rather than sounding the way nature sounds.
Explanation:
Deduce the first
equation
of motion matematical method
Answer:
The answer is below
Explanation:
Equation of motion is a term in physics that is used in explaining the characteristics of a physical system concerning its motion while considering the period.
The First Equation of Motion is given as v = u + at
Here, a = acceleration, v = final velocity, u = initial velocity, and t = time
To deduce it algebraically, it is written as
a = (v - u) ÷ t
Therefore, it can be repositioned to => v = u + a * t
What is a
physical
property of
snowflakes?
In a laboratory, it is often convenient to make measurements in centimeters and grams, but SI units are needed for calculations. Convert the following measurements to SI units. (a) 0.92 cm (b) 141.64g kg (c) 15.8 cm3 m3 (d) 63.6 g/cm3 kg/m3
Answer:
(a) 0.92 cm= 0.092 m.
(b) 141.64 g=0.14164 kg.
(c) 15. 8 cm³=0.0000158 m³
(d) 63.6 g/cm³= 63600 kg/m³
Explanation:
The International System of Units, abbreviated S.I., also called the International System of Measurements is a system of measurements in which its units are based on fundamental physical phenomena. The units of the S.I. They are the international reference for the indications of all measuring instruments.
The International System of Units (SI) arose from the need to unify and give coherence to a great variety of unit subsystems.
The International System of Units consists of seven basic units, also called fundamental units, which define the corresponding fundamental physical quantities and which allow any physical quantity to be expressed in terms or as a combination of them. The fundamental physical quantities are complemented by two more physical quantities, called supplementary ones.
By combining the basic units, the other units are obtained, called units derived from the International System, and which allow defining any physical quantity.
(a) The SI unit of length is the meter. Being 1 cm = 0.01 m, then 0.92 cm= 0.092 m.
(b) The SI unit of mass is kg. Being 1 g = 0.001 kg, then 141.64 g=0.14164 kg.
(c) Being 1 cm³ = 0.000001 m³, then 15. 8 cm³=0.0000158 m³
(d) Being 1 g/cm³= 1000 kg/m³, then 63.6 g/cm³= 63600 kg/m³
a body of mass 1kg is made to oscillate on a spring of force constant 16 n/m calculate 1 the angular frequency 2 the frequency of oscillation
Explanation:
Given that,
Mass of a body, m = 1 kg
Force constant, k = 16 N/m
We need to find the angular frequency and the frequency of oscillation.
(a) The angular frequency of a body is given by :
[tex]\omega=\sqrt{\dfrac{k}{m}} \\\\=\omega=\sqrt{\dfrac{16}{1}} \\\\=4\ rad/s[/tex]
(b) The frequency of oscillation is given by :
[tex]f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\=\dfrac{2}{\pi}\ Hz[/tex]
Hence, this is the required solution.
(a) A defibrillator passes 12.0 A of current through the torso of a person for 0.0100 s. How much charge moves
Answer:
0.12C
Explanation:
A defibrillator passes 12A through the torso of an individual
The time is 0.0100
The charge can be calculated as follows
= I × t
= 12 × 0.0100
= 0.12C
Hence the charge is 0.12C
An airplane traveling at half the speed of sound emits a sound of frequency 5.84 kHz. (a) At what frequency does a stationary listener hear the sound as the plane approaches?
Answer:
Stationary listener frequency = 77.68 kHz
Explanation:
Given:
Speed of airplane = 344/2 = 172 m/s
Sound of frequency = 5.84 kHz
Computation:
f0 = fs[(v+v0)/(v-vs)]
f0 = 5.84[(344+0)/(344-172)]
f0 = 5.84[(344)/172]
Stationary listener frequency = 77.68 kHz
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 10.0 min at 75.0 km/h, 6.0 min at 95.0 km/h, and 45.0 min at 40.0 km/h and spends 40.0 min eating lunch and buying gas.(a) Determine the average speed for the trip.
(b) Determine the distance between the initial and final cities along the route.
Answer:
a) v = 0.515 km / min , b) x_total = 52 km
Explanation:
The measured speed is defined by the distance traveled between the time
v = [tex]\frac{\Delta x}{\Delta t}[/tex]
In this case they give us the speed in several time intervals
let's find the distance traveled in each interval
a) Goes at 75 km/h for 10 min
v = [tex]\frac{x}{t}[/tex]x / t
x₁ = v t
let's reduce speed to km / min
v₁ = 75 km / h (1h / 60 min) = 1.25 km / min
the distance traveled in this time is
x₁ = 1.25 10
x₁ = 12.5 km
b) goes to v = 95 km / h for 6 min
v = 95 km / h (1h 60 min) = 1.5833 km / min
the distance traveled is
x₂ = v₂2 t
x₂ = 1.58333 6
x₂ = 9.5 km
c) goes to v = 40 km / h for 45.0 min
v₃ = 40 km / h (1 h / 60min) = 0.6667 km / min
x₃ = 0.6667 45
x₃ = 30 km
d) t = 40 min, stopped
x₄ = 0
A) let's calculate the average speed of the trip
v =[tex]\frac{x_{1}+x_{2}+x_{3}+x_{4} }{t_{1}+t_{2}+t_{3}+t_{4} }[/tex]
v = (12.5 +9.5 +30 +0) / (10 +6 +45 +40)
v = 52/101
v = 0.515 km / min
B) the distance between the two cities is
x_total = x₁ + x₂ + x₃
x_total = 12.5 +9.5 + 30
x_total = 52 km
What does a sound wave’s frequency tell you?
a - the number of vibrations per second an object is making
b - the loudness or softness of the sound from an object
c - the amplitude of the sound wave
d - the type of medium in which the sound is traveling
Answer:
The number of vibrations per second an object is making
Explanation:
We need to find the correct option for a sound wave’s frequency.
Frequency is the number of vibrations per second an object is making. It can be calculated as total no. of vibrations divided by time taken.
Its SI unit is Hertz and it is denoted by Hz.
Hence, the correct option is (a).
Which of the following is a correct equation for total energy?
Total energy = Kinetic energy / potential energy
Total energy = Kinetic energy - potential energy
Total energy = Kinetic energy * potential energy
Total energy = Kinetic energy + potential energy
Answer:
kinetic energy + potential energy
Answer:
D is the correct answer: Total energy = Kinetic energy + potential energy