This question is incomplete, the complete question is;
A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?
Molar mass, NH4NO3 80.0 g/mol
Calorimeter Constant 1.23 kJ/°C
Answer:
the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol
Explanation:
Given that;
change in temperature ΔT = 6.12 °C
Calorimeter Constant C = 1.23 kJ/°C
Molar mass, NH4NO3 = 80.0 g/mol
we know that;
Heat gained by the calorimeter (Q1) = Heat lost by the decomposition of NH4NO3 (Q2)
Q1 = C × ΔT
Q1 = (1.23 kJ/K) × (6.12 K) = 7.53 kJ
Q value we get becomes negative since we are talking about reaction and not calorimeter
hence
Q1 = - 7.53 kJ
now
1 g NH4NO3 decomposed, - 7.53 kJ of heat is released
so if 80 g which is 1 mol NH4NO3 decompose, the heat will be;
(80 g/mol x -7.53 kJ) / 1 g = - 602.4 kJ/mol
Therefore the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol
HC1O4 + P4010 ->
H3PO4 + Cl₂O7
How do I balance it?
Answer: watch Video of HC1O4 + P4010 -> H3PO4 + Cl₂o7 How Do I Balance It?
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Explanation: video is called How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)
Play How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)
2:22 minute video
How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)
write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. ammonium sulfate and barium nitrate
Answer:
SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of ammonium sulfate and barium nitrate are mixed.
(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) ⇒ BaSO₄(s) + 2 NH₄NO₃(aq)
The complete ionic equation includes all the ions and insoluble species.
2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and the insoluble species.
SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
Why must scientists always communicate their results
Answer: To Know That They Did Nothing Wrong
Explanation:
For Example, They Maybe Put The Wrong Thing
Or They Made The Different One Instead Of What They Were Supposed To Do
A 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius.what is the molality of the solution in that temprature?
The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.
Given,
Density of the solution = 1.15 g/mL
Molarity of the sulphiric acid = 2.45M
Molar mass of sulphuric acid = 98 g
Density is given as:
[tex]Molarity(\frac{1}{molarity} +\frac{mol.wt}{1000} )\\\\=2.45(\frac{1}{molarity} + \frac{98}{1000} )\\\\(\frac{1}{molarity} = (\frac{1.15}{2.45} + \frac{98}{1000} \\\\(\frac{1}{molarity} = 0.469 - 0.098\\\\(\frac{1}{molarity} = 0.371\\\\Molarity = 2.69m\\\\[/tex]
The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.
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What amount of the excess reagent remains when 0.30 mol NH3 reacts with 0.40 mol O2 to produce NO and H2O? 4NH3 +502 + 4NO + 6H20
(A) 0.10 mol NH,
(B) 0.10 mol
(C) 0.025 mol NH
(D) 0.025 mol O2
Answer: (D) 0.025 mol [tex]O_2[/tex]
Explanation:
The given balanced equation is :
[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]
According to stoichiometry :
4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]
Thus 0.30 moles of ammonia [tex](NH_3)[/tex] reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]
Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.
moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025
Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.
The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2 is 0.025 mole of O2
An excess reagent is a reactant which is left and can keep reacting after whole reaction.
A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.
The chemical equation for the reaction is represented as:
[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]
From the above reaction,
4 moles of ammonia reacts with 5 moles of oxygen molecule;
If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:
[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]
= 0.375 moles of oxygen.
But, we are given that 0.40 moles of oxygen is present.
Therefore, the amount of oxygen in excess is
= 0.40 moles - 0.375 moles
= 0.025 moles of O2
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How many valence electrons are in Sn+2? please answer asap thank you
Answer:
2 electrons
Explanation:
Can sum1 Help please...
Answer:
B
Explanation:
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happy Christmas
What indicator of a chemical reaction could be measured using a thermometer?
Answer:
heat production
Explanation:
A solution has a hydronium or hydrogen ion concentration of 3.16×10^-8M. What is the ph of the solution?
Answer:
7.50Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ {H}^{+} ][/tex]
From the question we have
[tex]pH = - log(3.16 \times {10}^{ - 8} ) \\ = 7.500312...[/tex]
We have the final answer as
7.50Hope this helps you
The image shows the products of a decomposition reaction. The larger, red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.
In this image, there are 6 molecules composed of two red atoms bound together, and 3 molecules composed of two blue atoms bound together.
Determine the empirical formula of the reactant based on these products.
The empirical formula of the compound that decomposes is [tex]N_{2} O[/tex]
What is decomposition?The term decomposition refers to a type of reaction in which a substance is broken down into its components. We know that a compound is composed of atoms. When there is a decomposition reaction, the atoms of the compound break down.
We can see that the products of the decomposition reaction are nitrogen and oxygen. The red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.
We know that nitrous oxide decomposes to give nitrogen and oxygen. Thus the empirical formula of the compound is [tex]N_{2} O[/tex].
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Magnesium is an active metal; it burns in the form of powder, ribbons, and filaments to
provide flashes of brilliant light. Why is it possible to use magnesium in construction?
Explanation:
magnesium can be used for the construction as only when the metal is divided into fine pieces or as a thin sheet, magnesium will burn rapidy.
Select all that are "exact numbers" and therefore have an unlimited number of significant figures
A)
12 inches= 1 foot
B)
60 min= 1 hour
C)
1 pig= 88 kg
D)
my car speed= 55 mi per hour
E)
pie= 3.14
Answer:
b.
i hope is help
20 g of sugar is there than to 150 g of 50 what is the mass of the solution formed
The mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.
The net mass of solution is calculated as the algebraic addition of the mass of the solute which is stirred into the mass of the solvent.
During the formation of solution, the sugar molecules are dissolved into tea in which sugar molecules fitted into the intermolecular spaces present between the water molecules of the tea and form a homogenous mixture.
What is solvent?Solvent is the substance or mixture which present in large amount in the solution.
What is solute?Solute is the substance or mixture which present in small amount in the solution.
Given,
Mass of solute (sugar) = 20g
Mass of solvent (tea) = 150g
Total mass of solution = 20 + 150
= 170g.
Thus we concluded that the mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.
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. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams of ethyl benzene are required to obtain 244 g of benzoic acid
Answer:
530.835 g
Explanation:
First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:
244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acidTheoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.
With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:
2.00 moles benzoic acid * [tex]\frac{1molEthylBenzene}{0.4molBenzoicAcid}[/tex] = 5.00 moles ethyl benzeneFinally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:
5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzeneI need help on part 3b please?
The frequency of a radio wave was measured to be (9.3x10^8) Hz What is the energy of the radio wave in kilojoules (kJ)?
1 Hz = 1 s–1
h = 6.626 x 10-34 J.s
The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.
What is a wave?The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.
Thus;
We know that;
Frequency of the wave = 9.3x10^8 Hz
Plank's constant = 6.626 x 10^-34 J.s
E = hf
E = energy of the wave
h = Plank's constant
f = frequency of the waves
E = 9.3x10^8 Hz * 6.626 x 10^-34 J.s
= 6.2 * 10^-25 J
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In Act IV of Romeo and Juliet, how do the Musicians feel about Peter?A. They are scared of him.
B. They find him annoying.
C. They think he is funny.
D. They feel sorry for him.
Carbon dioxide contains 1,204 ⋅ 10 ²² oxygen atoms. What is the mass of carbon dioxide?
Answer:
879.5616802
Explanation:
(N/Na)*W
How is wavelength measured (Select all that apply. from the trough (bottom) of one wave to the trough of the next wave
from the trough (bottom) of one wave to the crest (top) of the next wave
from the crest (top) of one wave to the crest (top) of the next wave
from the crest (top) of one wave to the trough (bottom) of the next wave
Answer:
The first two
Wavelength is measured from crest to crest. Amplitude is from trough to crest or crest to trough
A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 55.5 g of the compound is burned, 98.9 g of carbon dioxide and 40.5 g of water are collected.
Given that there are 2.25 moles of carbon and 4.50 moles of hydrogen produced in the reaction, calculate the mass of oxygen in the original compound. You will need to subtract the mass of the carbon that ended up in the carbon dioxide and the mass of the hydrogen that ended up in the water from the mass of the original compound.
Answer:
Determining an Empirical Formula from Combustion Data
Explanation:
Step 1: Identify the mass of carbon dioxide and water produced by the combustion.
Step 2: Find how many moles of carbon are in carbon dioxide.
Step 3: Find how many moles of hydrogen are in water.
Round the following number to the nearest hundredth: 4.482?
Answer: 4.48
Explanation: If the last digit in the fractional part of 4.482 is less than 5, then simply remove the last the digit of the fractional part.
What site is located in the structure of tRNA
The structure of tRNA resembles cloverleaf.
tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.
tRNA molecules fold into structure resembling cloverleaf with four important sites:-
•The acceptor stem (3’-CCA) have an amino acid
•The anticodon attaches with the mRNA codon (via complementary base pairing)
•The T arm attaches with the ribosome (via the E, P and A binding sites)
•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).
CCA is codon codes for prolein amino acid in polypeptide chain.
AUG is initiator codon codes for methionine.
UAG, UAA and UGA are stop codons.
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What is one property for each of the chemical substances listed above?
1. Acetic acid-
2. Sodium bicarbonate-
3. Carbon dioxide-
4.Dihydrogen monoxide-
5. Sodium acetate-
6. Calcium chloride-
7. Calcium carbonate-
8. Sodium chloride-
How does the potential energy of a double bond (like oxygen-oxygen) compare to a weak interaction or single bond (like argon-oxygen)?
Answer:
Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.
Explanation:
How are bat forelimbs different from other mammals’ forelimbs?
Answer:
The forelimbs of a bat are different from other mammals as they are modified into wings for the purpose of flying.
The combustion of propane C,H, produces carbon dioxide and steam.
CH,(8) + 50,(8) — 3C0,(8) + 4H2O(1)
How many moles of CO2 are produced when 7.5 mol of propane are burned in an excess of oxygen?
A. 15 mol
B. 23 mol
C. 3.8 mol
D. 2.5 mol
Answer:
23 moles
Explanation:
Given data:
number of moles of propane = 7.5 mol
Number of moles of carbon dioxide produced = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Now we will compare the moles of propane and carbon dioxide.
C₃H₈ : CO₂
1 : 3
7.5 : 3/1×7.5 = 22.5
22.5≅ 23 moles
A reaction vessel contains 4.800 g of CO and 4.800 g of O2. What is the maximum number of moles of CO2 recovered, based on the number of moles of the given reactants?
The maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel would be 0.17 moles.
Stoichiometric calculationThe reaction vessel contains:
4.800 g CO4.800 g [tex]O_2[/tex]The equation of the reaction would be as follows:
[tex]2CO + O_2 --- > 2CO_2[/tex]
The mole ratios of the reactants to the product are as follows:
CO to [tex]CO_2[/tex] = 1:1[tex]O_2[/tex] to [tex]CO_2[/tex] = 1:24.800 g of CO = 4.8/28
= 0.17 moles
4.800 g of [tex]O_2[/tex] = 4.8/32
= 0.15 moles
Since the mole ratio of CO to [tex]O_2[/tex] is 2 to 1, 0.17 of CO is limiting.
The mole ratio of CO to [tex]CO_2[/tex] is 1 to 1. Thus, the equivalent mole of [tex]CO_2[/tex] that can be recovered is also 0.17.
In other words, the maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel is 0.17 moles.
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1. Sketch a periodic table by labeling the s, p, d and f blocks?
s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3
The s-block in the periodic table of elements occupies the alkali metals and alkaline earth metals ,thus known as groups 1 and 2.D block elements are also known as Transition elementsF block elements are divided into two series as lanthanoids and actinoids. This block of elements are referred to as inner transition metals. s and p block elements are together known as representative elementsThus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.
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Which of the following contains as many atoms as 18 g of water, H₂O?
The correct answer is option c) Three moles of sodium, Na.
We know that
18g of H₂O = 1 mol
So, no. of atoms in H₂O = 3 x 6.022 x 10²³
= 1.81 x 10²⁴ atoms(both H&O atoms combined)
Now,
No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³
= 1.2044 x 10²⁴ atoms.
No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³
= 1.2044 × 10²⁴ atoms.
No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³
= 1.2044 × 10²⁴ atoms.
No. of atoms in 3 mol Na = 3 x 6.022 x 10²³
= 1.81 x 10²⁴ Na atoms.
Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.
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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?
a) One mole of hydrogen, H₂
b) Three moles of sodium, Na
c) Two moles of sodium chloride, NaCl
d) Two moles of oxygen, O₂
what is the combined gas law equation
Answer:
\frac {P_{1}V_{1}}{T_{1}}=\frac {P_{2}V_{2}}{T_{2}}
Explanation:
Gay-Lussac's law states that at constant volume, the pressure of a gas is directly proportional to the absolute temperature, P ∝ T at constant V. These three gas laws can be combined into a so-called combined gas law, P 1 V 1 T 1 = P 2 V 2 T 2.