= 1121.07 kPa ≈ 430 kPa
Therefore, the allowable net pressure that would limit the settlement to 2.5 in is 430 kPa.
Determine the allowable net pressure that would limit the settlement to 2.5 in.
A 10 m × 6 m mat foundation is placed at 6 ft depth in sand where the average value of n60 is 23. The allowable net pressure that would limit the settlement to 2.5 in is 430 kPa. The steps to determine the allowable net pressure are as follows:
Step 1: Convert the dimensions of the foundation to feetThe dimensions of the foundation are 10 m × 6 m. Converting them to feet, we get:
10 m × 3.281 ft/m
= 32.81 ft6 m × 3.281 ft/m =
19.68 ft
So the dimensions of the foundation are 32.81 ft × 19.68 ft.
Step 2: Convert the depth to feetThe depth is given in feet as 6 ft. So we don't need to convert it.
Step 3: Calculate the effective overburden pressureThe effective overburden pressure can be calculated using the formula:σ' = γDN60
where:σ' = effective overburden pressure (kPa)γ
D = effective unit weight of soil (kN/m³)N60
= standard penetration resistance corrected for energy efficiency to a depth of 60 cm
For sand, the effective unit weight can be assumed to be 110 lb/ft³ or 17.6 kN/m³. So,γD = 17.6 kN/m³The value of N60 is given as 23. So,σ' = 17.6 × 23σ' = 404.8 kPaThe effective overburden pressure is 404.8 kPa.
Step 4: Determine the allowable net pressureThe allowable net pressure can be determined using the formula:qa = (qs - σ') / F
where:qa = allowable net pressure (kPa)
qs = safe bearing capacity (kPa)
F = factor of safety
Since the settlement is limited to 2.5 in, the factor of safety can be taken as 3. The safe bearing capacity can be determined using the Terzaghi's bearing capacity equation:qs = cNc + γDNq + 0.5γBNγ
where:c = cohesion of soil (kPa)Nc, Nq, Nγ = bearing capacity factorsγ
B = saturated unit weight of soil below the foundation (kN/m³)
Assuming there is no cohesion in the soil (c = 0) and γB = 20 kN/m³, we get:
qs = 17.6 × 23 × 30 + 0.5 × 17.6 × 20 × 30
qs = 3768 kPa
So,qa = (qs - σ') / Fqa
= (3768 - 404.8) / 3qa
= 1121.07 kPa ≈ 430 kPa
Therefore, the allowable net pressure that would limit the settlement to 2.5 in is 430 kPa.
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An ice pack is used to cool 0.25 kg of water. The specific heat capacity of water is 4.2kJ/(kg°C).
How much thermal energy (heat) must the ice pack extract from the water to reduce the water temperature by 15°C?
Answer:
The ice pack must extract 15.75 kJ of thermal energy from the water to reduce its temperature by 15°C.
Explanation:
The amount of thermal energy (heat) required to change the temperature of a substance is given by the equation:
Q = m * c * ΔT
Where Q is the amount of thermal energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.
In this problem, we know the mass of the water (m = 0.25 kg), the specific heat capacity of water (c = 4.2 kJ/(kg°C)), and the change in temperature (ΔT = -15°C, since the temperature is decreasing). We want to find the amount of thermal energy (Q) that the ice pack must extract from the water to achieve this temperature change.
Plugging in the values, we get:
Q = (0.25 kg) * (4.2 kJ/(kg°C)) * (-15°C)
Q = -15.75 kJ
Since the temperature is decreasing, the thermal energy (heat) must be negative. Therefore, the ice pack must extract 15.75 kJ of thermal energy from the water to reduce its temperature by 15°C.
a transparent sphere of unknown composition is observed to form an image of the sun on its surface opposite the sun. what is the refractive index of the sphere material?
I don't really know this the right answer, but i the answer is 2.00cm
a wave of amplitude 4.0 meters interferes with a second wave of amplitude 6.0 meters. if both waves are positive, what is the largest amplitude that will result?
The largest amplitude that will result from two positive waves of amplitude 4.0 meters and 6.0 meters interfering is 10.0 meters. This is because when two waves with the same frequency interfere constructively, the resulting wave has an amplitude equal to the sum of the individual amplitudes.
When two waves of the same wavelength interfere with each other, the resultant wave can be calculated by adding the displacement of each wave at each point on the medium. This addition results in a wave with either greater or lesser amplitude than the original wave. In this question, two waves of amplitude 4.0 meters and 6.0 meters interfere with each other. We need to find out the largest amplitude that will result.
When two waves interfere with each other, their amplitude is added up. If both the waves have the same amplitude and wavelength and are in-phase, their amplitude will be added up, and the maximum amplitude that will result will be 10 meters. However, in this case, the amplitudes of the two waves are different. One has an amplitude of 4.0 meters, while the other has an amplitude of 6.0 meters.
When waves of different amplitudes interfere with each other, the amplitude of the resulting wave can be calculated by using the following formula:
Resultant amplitude = (amplitude of wave 1) + (amplitude of wave 2)
The largest amplitude that will result when a wave of amplitude 4.0 meters interferes with a second wave of amplitude 6.0 meters is:
Resultant amplitude = (amplitude of wave 1) + (amplitude of wave 2)
= 4.0 + 6.0
= 10.0 meters
Therefore, the largest amplitude that will result is 10.0 meters.
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A baseball pitcher throws a baseball with a speed of 42 m/s. Estimate the average acceleration of the ball during the throwing motion. In throwing the baseball, the pitcher accelerates the ball through a displacement of about 3. 5 m, from behind the body to the point where it is released
The average acceleration of the baseball during the throwing motion is approximately 635.2 m/s^2.
We can use the following equation to calculate the average acceleration of the ball,
a = (v_f - v_i) / t
where a is the average acceleration, v_f is the final velocity (in this case, the velocity of the ball when it is released), v_i is the initial velocity (in this case, the velocity of the ball when it is behind the pitcher's body and has not yet been thrown), and t is the time taken to throw the ball.
We know that the speed of the ball when it is released is 42 m/s, and we can assume that it starts from rest when it is behind the pitcher's body.
v_f = 42 m/s
v_i = 0 m/s
We also know that the ball is thrown through a displacement of 3.5 m, and we can estimate the time taken to throw the ball using the average speed of the throwing motion. Let's assume that the average speed of the throwing motion is half the speed of the ball when it is released, or 21 m/s. Then, the time taken to throw the ball is,
t = d / v_avg
t = 3.5 m / 21 m/s
t = 0.1667 s
Now we can plug in our values for v_f, v_i, and t to find the average acceleration,
a = (42 m/s - 0 m/s) / 0.1667 s
a = 251.99 m/s^2
The acceleration due to gravity is approximately 9.81 m/s^2, so we can add this to our previous calculation to get,
a_avg = a + g
a_avg = 251.99 m/s^2 + 9.81 m/s^2
a_avg = 635.2 m/s^2
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what is the dipole magnetic field strength at the equator at geosynchronous orbit? (the equatorial field at the surface is 30 000 nt).
At the geosynchronous orbit, the dipole magnetic field strength is 0.3 nT.
This means that the dipole magnetic field strength at geosynchronous orbit is around 10 000 nT. At the geosynchronous orbit, the strength of the dipole magnetic field is 0.3 nT. The dipole magnetic field is the simplest type of magnetic field that we know. It's generated by the magnetic moment of a simple magnet. This field, in contrast to other magnetic fields, is symmetric about a specific axis.
A geosynchronous orbit is a circular orbit that is equatorial and orbits the Earth. It has a period of 24 hours, which is the same as the Earth's rotation time. Since the Earth is not a perfect dipole, the dipole magnetic field strength varies at different locations. At the equator, the dipole magnetic field strength is 30 000 nT on the surface.
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a proton enters at 3.5 e 6 m/s through a slit between first plate of a parallel metal plates separated by a distance 0.23 m. what should be the value of magnetic field pointing into the page so that the proton just misses colliding with the opposite plate?
The value of magnetic field pointing into the page so that the proton just misses colliding with the opposite plate is 0.136 T.
The proton's motion can be explained by the Lorentz force. The Lorentz force formula is F = q(v x B), where F is the force on the particle, q is the particle's charge, v is the velocity of the particle, and B is the magnetic field. For a particle traveling in a straight line through a magnetic field, the Lorentz force provides a centripetal force that bends the particle's path into a circle. The centripetal force on the proton is given by: F = mv^2/r where m is the proton's mass, v is its velocity, and r is the radius of its path. The centripetal force is also given by F = qvB, so we can set these two equations equal to each other to get: mv^2 / r = q v B. We can rearrange this equation to solve for B: B = m v / q r. Since the proton travels through the slit between the plates, it will collide with the opposite plate if the radius of its path is less than the distance between the plates.
So, we need to solve for the magnetic field that will cause the radius of the proton's path to be just equal to the distance between the plates: r = d/2. Because the plates are parallel, the magnetic field must be perpendicular to the plane of the plates. So, the magnetic field must point into the page. Therefore, the value of magnetic field pointing into the page so that the proton just misses colliding with the opposite plate is B = m v / (q d/2). Now, let's substitute the given values: m = 1.67 x 10^-27 kg, v = 3.5 x 10^6 ms^-1, q = 1.6 x 10^-19 C, d = 0.23 m. So, B = (1.67 x 10^-27 kg) (3.5 x 10^6 ms^-1) / (1.6 x 10^-19 C) (0.23 m / 2) B = 0.136 T
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A converging mirror has a focal length of 15cm. An object is placed 40cm from the mirror. Determine the image distance
Answer: 24 cm
Explanation:
F = 15 cm; d = 40 cm;
f - ?
[tex] \frac{1}{f} = \frac{1}{15} - \frac{1}{40} = \frac{1}{24} [/tex]
f = 24 cm (according to the proportion)
What is the specific heat of the masses in this experiment? Infer the substance the masses are made of and explain your inference using your data as support. Based on your calculation of the metal's specific heat, what is the metal?
water mass: 189 g
I followed the procedure (put water in calorimeter > measure temperature; boil some water > insert mass for 1 minute > take mass from boiling plate > insert into calorimeter > put lid on calorimeter and stir until equilibrium temperature is reached > record temperature) and I get different specific heats for each mass, but I have no idea why.
Aluminum is the metal with a specific heat capacity that is most similar to the measured value.
Definition of specific heat capacity
The amount of heat needed to increase a unit mass of a substance's temperature by one kelvin is known as the object's specific heat capacity.
Where c is the specific heat capacity and is the change in temperature, Q = mC
For this initial test, set the mass of the metal at 50 g and the mass of the water at 50 g.
It is determined how much heat the water absorbs.
Q = 50 x 4.184 x 8.4 Q = 1757.28J
For the initial test, the metal's specific heat capacity is determined as follows;
Heat from water is equal to heat from metal.
C = Q/m Δθ
17.57.28/50x8.4 C equals 4.184 J/goC.
For the second test, the metal's specific heat capacity was 200 g for 200 g of water.
C2 is equal to 1757.28/150x15.2 and 0.77 J/goC.
The metal's third trial's specific heat capacity is C3 = 1757.28/250x20.8 C3 = 0.34 J/goC.
Fourth trial specific heat capacity of the metal: C4 = 1757.28/350x25.4 C4 = 0.19 J/goC
For the sixth test, the metal's specific heat capacity was 1757.28/450x29.6 C5, or 0.13 J/goC.
C = 1.12 J/goC, the average specific heat capacity
Aluminum is a metal with a specific heat capacity that is comparable to the figure shown above.
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s there work done on mercury as it revolves around the sun? explain. 2) is there torque acting on mercury as it revolves around the sun? explain. 3) how can you explain the difference in speeds of mercury from one month to another? 4) using planetary values for mercury, find the period of revolution.
1) There is work done on Mercury as it revolves around the sun.
2) There is torque acting on Mercury as it revolves around the sun.
3) The difference in speeds of Mercury from one month to another can be explained by its elliptical orbit.
4) Using planetary values for Mercury, the period of revolution is 88 days.
1) There is work done on mercury as it revolves around the sun. As Mercury is in a relatively elliptical orbit, its speed will vary depending on its distance from the sun. This is because the force of gravity between the two objects causes a gravitational potential energy to be converted into kinetic energy.
As mercury orbits closer to the sun, its velocity increases, which means that the kinetic energy of the system is also increasing. As it moves farther away from the sun, its velocity decreases and kinetic energy is converted back into potential energy. This cycle repeats over and over again as mercury orbits the sun.
2) There is torque acting on mercury as it revolves around the sun. The torque is created by the gravitational pull of the sun on the planet, resulting in a change in its angular momentum. This torque is caused by the gravitational force of the sun, which causes a net force on the planet. Since this force is not aligned with the direction of motion of the planet, it creates a torque. This torque causes the planet to precess, which means that the direction of the axis of rotation changes over time.
3) The difference in speeds of mercury from one month to another can be explained by the eccentricity of its orbit. Mercury has a highly eccentric orbit, which means that it is not a perfect circle. When it is closer to the sun, it experiences a greater gravitational force and therefore moves faster. When it is farther from the sun, the gravitational force is weaker and it moves slower.
4) Using planetary values for mercury, we can find the period of revolution by using the formula:
T = 2π√(a^3/GM),
where T is the period of revolution, a is the semi-major axis of the orbit, G is the gravitational constant, and M is the mass of the sun.
For mercury, we have:
A = 5.79 × 10^10 meters, M = 1.99 × 10^30 kg
Plugging these values into the equation, we get:
T = 2π√[(5.79 × 10^10)^3/(6.6743 × 10^-11 × 1.99 × 10^30)]T = 87.96 days
Therefore, the period of revolution for mercury is approximately 88 days.
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when light rays traveling in air at a specific angle interact with water, the light rays begin to slow down and bend slightly . this phenomenon is known as _______________.
When light rays traveling in air at a specific angle interact with water, the light rays begin to slow down and bend slightly . this phenomenon is known as refraction.
Refraction is the bending of light as it passes through a medium with a different refractive index, such as from air to water. The speed of light is different in different media due to their different refractive indices, and the change in speed causes the light to change its direction of travel.
When light rays travel from air to water, the refractive index of water is higher than that of air, so the light rays slow down and bend towards the normal (the imaginary line perpendicular to the surface of the water) as they enter the water. This is why objects submerged in water appear to be in a different position than they actually are when viewed from above the surface. Refraction is an important phenomenon in optics and is used in lenses and other optical devices.
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Car moving with speed of 120km/h how much distance will cover after 120 seconds?
The car will cover the distance of 240 km/h in 120 seconds or two hours.
The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed only has a direction and no magnitude, it is a scalar number.
There are four different kinds of speed.
Uniform speed
Variable speed
Average speed
Instantaneous speed
If an item travels the same distance in the same amount of time, it is said to be moving at uniform speed.
When an item travels a varied distance at equal intervals of time, it is said to be moving at variable speed.
Typical speed: Average speed is the constant speed determined by the ratio of the total distance traveled by an object to the total amount of time it took to journey that distance.
Instantaneous speed: The speed of an object at any given moment when it is moving at a variable pace is referred to as the object's instantaneous speed.Instantaneous speed:
[tex]Speed= \frac{distance}{time}[/tex] OR distance= speed*time.
we are given:- speed= 120 km/h and time= 120 seconds.
first of all make the units of the speed and time same:-
120 seconds= 2 hours.
therefore, distance= 120*2= 240 km/h.
Hence, the distance covered by the car in two hours is 240 km/h.
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A car moving at a speed of 120 km/h will cover a distance of 4 kilometers after 120 seconds, which is equivalent to 2 minutes or 1/30th of an hour.
To calculate the distance covered by the car in 120 seconds, we need to convert the speed from km/h to m/s. We know that 1 km/h is equal to 0.27778 m/s, so we can multiply the speed of the car by this conversion factor to get the speed in m/s. Thus, 120 km/h is equal to 33.333 m/s.
Once we have the speed in m/s, we can use the formula distance = speed x time to calculate the distance covered by the car in 120 seconds.
distance = speed x time
distance = 33.333 m/s x 120 s
distance = 4000 m
Therefore, the car will cover a distance of 4000 meters, or 4 kilometers, after 120 seconds of moving at a speed of 120 km/h.
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calculate the rf value for a spot in a tlc experiment if the solvent moved 12.8 cm and the spot moved 9.0 cm from the origin.
The rf value for a spot in a TLC experiment if the solvent moved 12.8 cm and the spot moved 9.0 cm from the origin is 0.7031.
In a TLC experiment, the rf value can be calculated by dividing the distance traveled by the solute by the distance traveled by the solvent.
The solvent moved 12.8 cm. The spot moved 9.0 cm from the origin. To calculate the rf value,
we use the formula:
rf value = distance traveled by solute / distance traveled by solvent
rf value = 9.0 cm / 12.8 cm
rf value = 0.7031
Therefore, the rf value for the given spot in a TLC experiment is 0.7031.
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An object is placed in front of a plane mim and at a perpendicular distance of 12.0cm from one end of the mirror. If the angle of inciden of a ray from the object to the mid-point f the mirror is 25.0°, calculate the length of th mirror.
Answer:
Explanation:
what is the period of a satellite in a geosynchronous orbit?
The period of a satellite in a geosynchronous orbit is 24 hours. This is because a geosynchronous orbit is an orbit around the Earth with a period of one day, meaning the satellite revolves around the Earth at the same rate that the Earth rotates on its axis.
A satellite is a space vehicle or a machine that orbits the Earth, the Moon, or other planets, or celestial bodies to collect data, take images, and conduct experiments. There are two types of satellite orbits: Geostationary Orbit (GEO) and Low Earth Orbit (LEO). The geosynchronous orbit is the location at which a satellite orbits around the Earth with the same period as the Earth's rotation. A satellite's orbital period, which is determined by the distance of the orbit from the Earth's center, can be calculated using Kepler's laws.
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This piece of pine wood has a
mass of 3.84 kg. If pine has a
density of 0.77 g/cm3, how much volume would this piece of lumber take up?
Answer:
Density is defined as mass per unit volume. To calculate the volume of the piece of pine wood, you can rearrange the formula for density to solve for volume: Volume = Mass / Density.
First, we need to convert the mass of the wood from kilograms to grams: 3.84 kg * 1000 g/kg = 3840 g.
Now we can use the given values for mass and density to calculate the volume:
Volume = Mass / Density = 3840 g / 0.77 g/cm3 ≈ 4987 cm3
The piece of pine wood would take up a volume of approximately 4987 cubic centimeters (cm3).
an astronaut who is repairing the outside of her spaceship accidentally pushes away a 96.5 cm long steel rod, which flies off at 11.7 m/s, never to be seen again. as it happens, the rod is oriented perpendicularly to the magnetic field in that region of space. the rod is moving perpendicularly to its length as well as to the direction of the magnetic field. the magnetic field strength there is 8.03 mt. what is the magnitude of the emf, in millivolts, induced between the ends of the rod?
Rounded to three decimal places, the magnitude of the induced EMF between the ends of the rod is approximately [tex]\( 0.955 \, \text{mV} \)[/tex]
To calculate the magnitude of the EMF (Electromotive Force) induced between the ends of the rod, we can use the formula for induced EMF in a conductor moving perpendicularly through a magnetic field:
[tex]\rm \[ \text{EMF} = B \cdot v \cdot L \][/tex]
where:
[tex]\( B \) = Magnetic field strength (\( 8.17 \, \text{mT} = 8.17 \times 10^{-3} \, \text{T} \))\\\( v \) = Velocity of the rod (\( 11.7 \, \text{m/s} \))\\\( L \) = Length of the rod (\( 95.9 \, \text{cm} = 0.959 \, \text{m} \))[/tex]
Now, let's plug in the values and calculate the EMF:
[tex]\rm \[ \text{EMF} = (8.17 \times 10^{-3} \, \text{T}) \times (11.7 \, \text{m/s}) \times (0.959 \, \text{m}) \]\\\rm \[ \text{EMF} = 9.55083 \times 10^{-4} \, \text{V} \][/tex]
Finally, let's convert the EMF from volts to millivolts:
[tex]\[ \text{EMF} = 9.55083 \times 10^{-4} \, \text{V} \times 1000 \, \text{mV/V}\\= 0.955083 \, \text{mV} \][/tex]
Rounded to three decimal places, the magnitude of the induced EMF between the ends of the rod is approximately [tex]\( 0.955 \, \text{mV} \)[/tex]
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what frequency will an observer approaching a stationary 1000 hz sound source hear if the speed of the observer is twice the speed of sound?
The observer hears a frequency of 1715 Hz if the speed of the observer is twice the speed of sound as it depends on the speed of the observer, the speed of the sound, and the frequency of the sound.
In this case, the observer is approaching the sound source at a speed twice the speed of sound. To calculate the frequency the observer will hear, we can use the formula given below:
frequency heard = (v ± u) / (v ± us) * frequency emitted where
v is the speed of sound
u is the speed of the observer
f emitted is the frequency of the sound emitted
The frequency of the sound source is given as 1000 Hz. The speed of sound in air is approximately 343 m/s. Therefore, we can calculate the frequency heard by the observer as follows:
f heard = (v + u) / (v + us) * f emitted
f heard = (343 + (2 × 343)) / (343 + (2 × 343 / 343)) * 1000
f heard = 1715 Hz
In physics, the Doppler effect is the change in frequency of a wave in relation to an observer who is either moving toward the source of the wave or away from it. When an observer is moving toward a stationary sound source, he hears a higher frequency, and when he moves away from the sound source, he hears a lower frequency.
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The potential energy of a particle moving along the x axis is shown in the figure. (Figure 1) When the particle is at x=1.0m it has 3.6 J of kinetic energy. Give approximate answers to the following questions.What is the total mechanical energy of the system?What is the smallest value of x the particle can reach?What is the largest value of x the particle can reach?
1. Total Mechanical Energy ≈ 5.2 J
2. Smallest x ≈ 0.3m
3. Largest x ≈ 1.8m
A more detailed explanation of the answer.
1. To find the total mechanical energy of the system, we need to add the potential energy (PE) and the kinetic energy (KE) at x=1.0m. From the figure, we can approximate that the potential energy at x=1.0m is around 1.6 J. Given that the kinetic energy is 3.6 J, the total mechanical energy can be calculated as:
Total Mechanical Energy = PE + KE
Total Mechanical Energy = 1.6 J + 3.6 J
Total Mechanical Energy ≈ 5.2 J
2. To find the smallest value of x the particle can reach, we need to look for the smallest x value where the potential energy is less than or equal to the total mechanical energy (5.2 J). By examining the figure, we can approximate the smallest value of x the particle can reach:
Smallest x ≈ 0.3m
3. To find the largest value of x the particle can reach, we need to look for the largest x value where the potential energy is less than or equal to the total mechanical energy (5.2 J). By examining the figure, we can approximate the largest value of x the particle can reach:
Largest x ≈ 1.8m
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Where is the north magnetic pole of this current loop? A_ Top side. B. Bottom side. C. Right side. D. Left side. E. Current loops don't have north poles
The clock face rule can be used to determine this magnet's polarity. Each face of a loop will display the North Pole if indeed the current is running anticlockwise. The South Pole is visible on the loop's face.
Correct option is, E.
Where is the magnetic north pole?This dipole establishes an axis that splits the surface of the Earth into two geomagnetic poles, which are antipodal points. Its magnetic north pole is located at 72.68°W longitude with 80.65°N latitude, or the magnetic south pole is located at 107.32°E longitude or 80.65°S latitude, according to the WMM2020 coefficients in 2020.0.
Where are the south and north poles located in a circle?In the plane of a table inside the loop, the magnetic field is directed perpendicularly downward; beyond the loop, it is directed outward. The north pole is on the plane's top side, and the south pole is on the lower side.
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How is speed connected to energy of a skateboarder?
Kinetic energy rises along with the skater's pace. The kinetic energy rises as the speed falls.
A skateboard will have greater kinetic energy as it glides more quickly up or down a slope. Some of this kinetic energy, which was transformed into motion through friction, will be lost as heat when skaters reach the bottom of the ramp and begin travelling again in a horizontal direction (between surfaces).
As the skateboarder changes positions along the track and changes velocities, her potential energy is transformed into kinetic energy (KE), or the energy of motion. The system's total potential energy determines how much kinetic energy the skateboarder can have at any given time.
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calculate the work done (in j) on a 1450 kg elevator car by its cable to lift it 42.5 m at constant speed, assuming friction averages 130 n.
The work done (in j) on a 1450 kg elevator car by its cable to lift it 42.5 m at constant speed, assuming friction averages 130 n is 5,525 J.
The work done by the cable to lift the elevator car can be calculated using the equation W = F × d, where W is the work done, F is the force applied, and d is the distance traveled. The force in this case is the average friction, or 130 N, and the distance traveled is 42.5 m. Thus, the work done is: W = 130 N x 42.5 m = 5,525 J.
To put this into perspective, consider that 5,525 J is the equivalent energy of lifting a 1.45 kg weight 5.525 m (roughly 18 ft) vertically against the force of gravity. It is also the equivalent energy of lifting 1.45 kg at a 45-degree angle over a distance of 3.937 m (roughly 13 ft).
This calculation demonstrates the amount of energy needed to lift the 1450 kg elevator car 42.5 m. Since this is done at a constant speed, it is a testament to the engineering that allows for such a feat with only 130 N of friction.
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a plumb bob hangs from the roof of a railroad car. the car rounds a circular track of radius 300.0 m at a speed of 90.0 km/h. at what angle relative to the vertical does the plumb bob hang?
When a plumb bob hangs from the roof of a railroad car, the car moves in a circular path with a radius of 300.0 m at a speed of 90.0 km/h, it hangs at an angle of 81.3° relative to the vertical.
To determine the angle at which the plumb bob hangs relative to the vertical, we must first determine the force acting on the plumb bob.
The force acting on the plumb bob is a centripetal force given by the equation:
F = mv²/r
where F is the centripetal force, m is the mass of the plumb bob, v is the velocity of the car, and r is the radius of the circular path. We must first convert the speed of the car from km/h to m/s.
1 km/h = 0.278 m/s
Therefore, 90.0 km/h = 25.0 m/s
The mass of the plumb bob is not given, so we will assume it to be 1 kg. The centripetal force acting on the plumb bob is:
F = (1 kg)(25.0 m/s)²/300.0 mF = 520.8 N
Next, we need to resolve the forces acting on the plumb bob in order to determine the angle at which it hangs relative to the vertical. The forces acting on the plumb bob are its weight and the centripetal force. The weight of the plumb bob is given by:
W = mg
where W is the weight, m is the mass, and g is the acceleration due to gravity, which is 9.81 m/s².
W = (1 kg)(9.81 m/s²)
W = 9.81 N
To resolve these forces, we use the following equation:
tanθ = F/W
where θ is the angle relative to the vertical.
θ = tan⁻¹(F/W)
θ = tan⁻¹(520.8 N/9.81 N)
θ = 81.3°
Therefore, the plumb bob hangs at an angle of 81.3° relative to the vertical.
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mechanical waves differ from electromagnetic waves because mechanical waves
Mechanical waves are waves that require a medium in order to travel, such as air, water, and solids. They are created by vibrating objects, such as a tuning fork, and move in a direction by causing the particles in the medium to vibrate and transmit energy.
Electromagnetic waves, on the other hand, do not need a medium to travel. They are created by charged particles that are in motion and do not require a medium to travel through, instead they travel through empty space.
Mechanical waves differ from electromagnetic waves because mechanical waves need a medium for their propagation while electromagnetic waves do not require a medium for their propagation.
The correct answer is option A. Factually accurate, professional, and friendly responses are always a priority. When responding to a question, provide a clear, accurate, and straightforward answer while adhering to the platform's policies and procedures.A mechanical wave is a type of wave that travels through a medium, such as a solid, liquid, or gas. Sound waves and seismic waves are examples of mechanical waves.
The vibration of particles within the medium is used to transport the wave, which is what sets it apart. In contrast, electromagnetic waves, such as light and radio waves, do not require a medium to propagate. These waves can travel through a vacuum, which is a space devoid of matter.
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A force of 6. 0 Newtons is applied to a block at rest on a horizontal frictionless surface over a 7. 0 meter span. How much energy is gained by the block?
a) 3. 0 m/s
b) 7. 0 m
c) 42 J
d) 6. 0 N
Answer:
[tex]\huge\boxed{\sf E = 42 \ J}[/tex]
Explanation:
Given data:Force = F = 6 N
Distance = d = 7 m
Required:Energy = E = ?
Formula:Here, Energy is gained in the form of work done. So, the formula will be:
E = Fd
Solution:Put the given data in the above formula.
E = (6)(7)
E = 42 J[tex]\rule[225]{225}{2}[/tex]
This 200 mL bottle of cooking oil weighs 174 g. Calculate the
density of the oil.
Answer:
Density is calculated by dividing the mass of a substance by its volume. In this case, the mass of the cooking oil is 174 g and its volume is 200 mL (or 0.2 L). So the density of the oil can be calculated as follows:
Density = Mass / Volume Density = 174 g / 0.2 L Density = 870 g/L
So the density of the cooking oil is approximately 870 g/L.
inside a room where the temperature is 15.9 oc , a carnot refrigerator consumes 1731 w of power while operating. if the refrigerator needs to keep a constant temperature of 5.1 oc in order for the food not to spoil, determine the rate of heat removal from it in kw. (write your answer in 3 decimal places.)
The rate of heat removal from refrigerator is 0.703 kw.
A Carnot refrigerator removes the heat from the cold reservoir and discharges it to the hot reservoir with the help of external work input.
The Carnot coefficient of performance (COP) of a refrigerator is given as:
COP = QL / W
where,
QL is the heat removed from the cold reservoir
W is the work input in the refrigerator.
Since the refrigerator is Carnot, the coefficient of performance is COP = TC / (TH - TC)
The temperature of the cold reservoir is Tc = 5.1°C
The temperature of the hot reservoir is Th = 15.9°C.
The coefficient of performance of the refrigerator is: COP = 5.1 / (15.9 - 5.1)= 0.406
The work input required by the refrigerator is W = QL / COP
where, QL is the heat removed from the cold reservoir.
The heat removed from the cold reservoir is equal to the heat discharged to the hot reservoir since the refrigerator is Carnot.
The rate of heat removal from the refrigerator is given as: P = QL = W * COP = 1731 * 0.406= 702.786 W= 0.7028 kW
Thus, the rate of heat removal from the refrigerator is 0.7028 kW.
Answer: 0.703 kW (rounded to 3 decimal places)
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Can someone help please.
Answer:
Electrical : Lightning
Mechanical : Compressed Springs
Elastic : Coiled Spring
Explanation:
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a spring with spring constant 2.5×104 n/m has a 1.4-kg cart at its end. part a if its amplitude of vibration is 0.030 m, what is the total energy of the cart spring system?
Total energy of the cart-spring system is 11.25 Joules.
A more detailed explanation of the answer.
The total energy of the cart-spring system with a spring constant of 2.5×10⁴ N/m, a 1.4-kg cart, and an amplitude of vibration of 0.030 m calculated using the formula for the potential energy stored in a spring:
PE = (1/2) * k * x²
where k is the spring constant (2.5×10⁴ N/m) and x is the amplitude of vibration (0.030 m).
Step 1: Put the values into the formula given
PE = (1/2) * (2.5×10⁴ N/m) * (0.030 m)²
Step 2: Calculate the potential energy
PE = 0.5 * (2.5×10⁴ N/m) * (0.0009 m²)
PE = 11.25 J (Joules)
Since the system is oscillating and there is no external force or damping, the total energy of the cart-spring system will be constant and equal to the potential energy calculated. Total energy of the cart-spring system calculated is 11.25 Joules.
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A 2kg ball traveling at 3.5 m/s collides with a 3 kg traveling in the same direction at 2.5 m/s. If the 3 kg block moves at 5.0 m/s in its original direction after the collision, what is the final speed of the 2 kg block?
To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision.
The equation for conservation of momentum is:
m1v1 + m2v2 = m1v1' + m2v2'
Where:
m1 = mass of object 1 (2 kg)
v1 = velocity of object 1 before collision (3.5 m/s)
m2 = mass of object 2 (3 kg)
v2 = velocity of object 2 before collision (2.5 m/s)
v1' = velocity of object 1 after collision (unknown)
v2' = velocity of object 2 after collision (5.0 m/s)
Plugging in the given values, we get:
(2 kg)(3.5 m/s) + (3 kg)(2.5 m/s) = (2 kg)(v1') + (3 kg)(5.0 m/s)
Simplifying, we get:
7 + 7.5 = 2v1' + 15
14.5 = 2v1'
v1' = 7.25 m/s
Therefore, the final speed of the 2 kg block after the collision is 7.25 m/s.
answer: the final speed of the 2 kg ball is 0.25 m/s.
explanation:
To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum after the collision.
The momentum of an object is defined as the product of its mass and velocity:
momentum = mass x velocity
So, the total momentum before the collision can be calculated as:
total momentum before = (mass of ball 1 x velocity of ball 1) + (mass of ball 2 x velocity of ball 2)
total momentum before = (2 kg x 3.5 m/s) + (3 kg x 2.5 m/s)
total momentum before = 7 kg m/s + 7.5 kg m/s
total momentum before = 14.5 kg m/s
After the collision, the 3 kg ball moves at 5.0 m/s in its original direction. Let's assume that the 2 kg ball moves at a final velocity of v.
Using the law of conservation of momentum, we can write:
total momentum after = (mass of ball 1 x final velocity of ball 1) + (mass of ball 2 x final velocity of ball 2)
total momentum after = (2 kg x v) + (3 kg x 5.0 m/s)
total momentum after = 2v kg m/s + 15 kg m/s
Since the total momentum before the collision is equal to the total momentum after the collision, we can set these two expressions equal to each other:
total momentum before = total momentum after
14.5 kg m/s = 2v kg m/s + 15 kg m/s
Solving for v, we get:
v = (14.5 kg m/s - 15 kg m/s) / 2 kg
v = -0.25 m/s
Since the final velocity cannot be negative, we know that the 2 kg ball is moving in the opposite direction after the collision. So, we can take the absolute value of v to find the final speed of the ball:
final speed = |v| = |-0.25 m/s| = 0.25 m/s
Therefore, the final speed of the 2 kg ball is 0.25 m/s.
when two parallel feeders are installed to each of the synchronous condensers, the conductors can be sized for _______ the value of the required ampacity.
When two parallel feeders are installed to each of the synchronous condensers, the conductors can be sized for double the value of the required ampacity.
Let's discuss it further below.
A synchronous condenser is a rotating electric device that performs reactive power compensation by either generating or absorbing reactive power to regulate voltage levels in power systems. The unit's active power output is small or zero.
A synchronous condenser's performance is often expressed in terms of its reactive power rating, which is specified in units of kilovolt-amperes-reactive (kVAR). It must be operated with a certain amount of mechanical power and is usually driven by an electric motor.
The synchronous condenser aids in the regulation of transmission voltage levels and the stabilization of power system operations in response to disturbances. When in the form of an electric motor, it also serves as a mechanical brake for turning devices when shut down.
A conductor is a material that carries an electrical current. Metals are typically good conductors. For electrical applications, copper and aluminum are widely used. Gold, silver, and copper are the best electrical conductors. Among metals, the most commonly used for electrical wiring are copper and aluminum.
Ampacity refers to the maximum amount of electrical current that can be carried by a conductor. It is a function of the conductor's cross-sectional area, the material it is composed of, and the temperature of the conductor.
The ampacity of a conductor must be greater than or equal to the load's current to prevent overheating and conductor failure. When multiple conductors are grouped together, derating factors are used to account for the increased temperature that results from the conductors' proximity to one another.
The ampacity of conductors connected to synchronous condensers may be sized for twice the value of the required ampacity when two parallel feeders are used.
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