The two blocks have an acceleration of 4.12 m/s^2.
String calculationsTo solve this problem, we need to draw a free-body diagram of both blocks and apply the laws of motion.
Let's assume that the positive x-direction is to the right, and the positive y-direction is upwards.
For the 10 kg block:
The weight force (W) acts downwards and has a magnitude of 10 x 9.8 = 98 N
The force of tension (T) acts upwards and is transmitted through the string from the 5 kg block
The frictional force (f) acts in the opposite direction to the motion and has a magnitude of 20 N
The force applied (F) acts at an angle of 30 degrees with the horizontal
We can resolve the applied force into its x- and y-components:
The x-component of the force (F cos 30) opposes the frictional force
The y-component of the force (F sin 30) opposes the weight force and is balanced by the tension force
Therefore, we can write the following equations of motion for the 10 kg block:
ΣFx = [tex]\sqrt{x}[/tex]T - F cos 30 - f = ma
ΣFy = T - W - F sin 30 = 0
For the 5 kg block:
The weight force (W) acts downwards and has a magnitude of 5 x 9.8 = 49 N
The force of tension (T) acts upwards and is transmitted through the string to the 10 kg block
The frictional force (f) acts in the opposite direction to the motion and has a magnitude of μkN, where μk is the coefficient of kinetic friction and N is the normal force
We can write the following equation of motion for the 5 kg block:
ΣFx =Δ f - T = ma
Now, we can solve for the unknowns.
From the equation ΣFy = T - W - F sin 30 = 0, we get:
T = W + F sin 30
T = 10 x 9.8 + 50 sin 30
T = 109.8 N
From the equation ΣFx = T - F cos 30 - f = ma, we get:
a = (T - F cos 30 - f) / m
a = (109.8 - 50 cos 30 - 20) / 10
a = 2.33 m/s^2
From the equation ΣFx = f - T = ma, we get:
a = √(f - T) / m
a = (0.2 x N - 109.8) / 5
a = -4.96 m/s^2
Since the acceleration of the two blocks is the same (due to the inextensible string), we can equate the two values of acceleration and solve for N:
2.33 = -4.96
N = 73.8 N
Now we can calculate the frictional force on the 5 kg block:
f = √μkN
f = 0.2 x 73.8
f = 14.76 N
Finally, we can use the equation ΣFx = T - F cos 30 - f = ma to find the acceleration:
a = (T - F cos 30 - f) / m
a = (109.8 - 50 cos 30 - 14.76) / 10
a = 4.12 m/s^2
Therefore, the two blocks accelerate to the right with an acceleration of 4.12 m/s^2.
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A sled is pulled upwards on a hill by a horse. (The horse is connected to the sled via a rope). The hill is
inclined at 15°, the horse is pulling with a force of 900 N and the sled (with everything in it) has a mass
of 250 kg. If the coefficient of kinetic friction between the sled and the snow is 0. 10, what is the
acceleration of the sled? Express your answer in m/s2 and input the number only
The acceleration of the sled pulled upwards on a hill by a horse is approximately 2.74 m/s^2.
To solve this problem, we need to first resolve the forces acting on the sled into components parallel and perpendicular to the surface of the hill.
The force of gravity acting on the sled can be resolved into two components:
The force perpendicular to the hill, which is equal to m * g * cos(15°)
The force parallel to the hill, which is equal to m * g * sin(15°)
The force of the horse pulling the sled can also be resolved into two components:
The force perpendicular to the hill, which is equal to F * cos(15°)
The force parallel to the hill, which is equal to F * sin(15°)
Since the sled is being pulled up the hill, the direction of motion is opposite to the direction of the force of friction. Therefore, the force of friction can be written as:
f = -μ * N
The net force acting on the sled is the sum of the forces parallel to the hill, which can be written as:
F_net = F_parallel - f = F * sin(15°) + μ * m * g * cos(15°)
Using Newton's second law, we can write:
F_net = m * a
Substituting the expressions for F_net and f, we get:
F * sin(15°) + μ * m * g * cos(15°) = m * a
Plugging in the given values, we get:
900 * sin(15°) + 0.10 * 250 * 9.81 * cos(15°) = 250 * a
Solving for a, we get:
a = (900 * sin(15°) + 0.10 * 250 * 9.81 * cos(15°)) / 250
a ≈ 2.74 m/s^2
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1. Helen's car ran out of gas and stalled 100 meters from a gas station. Helen knew she could push the car to the gas station. She put her car in neutral and pushed with a force of 40 N. How much work (in Newton meters) did Helen do to get her car to the gas station?
The amount of work (in Newton meters) that Helen did to get her car to the gas station is 4000 Newton meters
How do i determine the amount of work (in Newton meters)?Work done is defined as illustrated by the formula given below:
Work done = force (F) × distance (d)
From the question given above, we were told that:
Force applied (F)= 40 NewtonDistance to gas station (d) = 100 metersWorkdone =?The work done by Helen can be obtained as shown below:
Work done = force (F) × distance (d)
Work done = 40 × 100
Work done = 4000 Newton meters
Thus, it is evident that the work done is 4000 Newton meters
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Three cables are attached to the top of the tower at a. Determine the angle formed by cables ab and ac if the height of the tower is a ___________
The angle formed by cables AB and AC is approximately 72.4 degrees.
b^2 = a^2 + c^2 - 2ac cos A
Since the tower height is given as a = 58m, we can substitute this into the equation:
b^2 = 58^2 + c^2 - 2(58)(c) cos A
Simplifying, we get:
cos A = (c^2 + 58^2 - b^2) / (258c)
Now we can plug in the values given in the problem. Let's say cable AB has a length of 70m and cable AC has a length of 80m. Then we have:
cos A = (80^2 + 58^2 - 70^2) / (25880)
cos A = 0.292
Taking the inverse cosine of this value, we get:
A = 72.4 degrees
A cable is a flexible structure made of one or more long, thin, and strong wires or fibers. Cables are used to transmit forces, motion, or electricity between two points. They are widely used in engineering, construction, transportation, and power generation.
The strength and flexibility of cables depending on the material and structure used in their construction. Steel cables are commonly used for their strength and durability, while synthetic fibers such as nylon and kevlar are used for their flexibility and resistance to corrosion.
Cables are often used in tension, meaning that they are stretched between two points and used to transmit a pulling force. They can also be used in compression, where they are used to resist a pushing force.
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What is the wavelength of a sound wave that has a speed of 680 m/s and a frequency of 220 Hz?
7 What is the wavelength of a sound wave that has a speed of 960 m/s and a frequency of 875 Hz?
What is the wavelength of a sound wave that has a speed of 125 m/s and a frequency of 800 Hz?
9 What is the wave speed of a wave that has a frequency of 25 Hz and a wavelength of 4.0 m?
10 What is the wave speed of a wave that has a frequency of 400 Hz and a wavelength of 0.30 m?
The shift or change in a wave's frequency or wavelength brought on by the proximity of an emitting or reflecting sound source to the receiver. Therefore, the wavelength of the sound wave is 1.10 meters.
What does the Doppler effect look like in practise?You may have noticed that the pitch of a fast-moving siren suddenly decreases as it passes past you. Because the pitch is higher, the siren initially appears to be approaching you. The siren's pitch drops as it moves away from you after passing you. The Doppler effect is being displayed here.
wavelength = speed / frequency
where wavelength is in units of meters, speed is in units of meters per second (m/s), and frequency is in units of Hertz (Hz).
For a sound wave with a speed of 680 m/s and a frequency of 220 Hz:
wavelength = speed / frequency
wavelength = 680 m/s / 220 Hz
wavelength = 3.09 m
Therefore, the wavelength of the sound wave is 3.09 meters.
For a sound wave with a speed of 960 m/s and a frequency of 875 Hz:
wavelength = speed / frequency
wavelength = 960 m/s / 875 Hz
wavelength = 1.10 m
Therefore, the wavelength of the sound wave is 1.10 meters.
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Determine the new differential reading along the inclined leg of the mercury manometer of fig. P2. 62, if the pressure in pipe a is decreased 10 kpa and the pressure in pipe b remains unchanged. The fluid in a has a specific gravity of 0. 9 and the fluid in b is water
The pressure difference between two points in a manometer is given by the difference in the heights of the fluid columns in the two legs of the manometer.
If the pressure in pipe A is decreased by 10 kPa, the height of the fluid column in that leg of the manometer will decrease. The amount of decrease will depend on the specific gravity of the fluid in that leg, as well as the height of the fluid column before the pressure change. Assuming the specific gravity of the fluid in pipe A is 0.9, the decrease in pressure will cause the fluid column to decrease by (10 kPa)/(0.9 * 9.81 m/s^2), or approximately 1.15 meters. The change in the height of the fluid column in the other leg of the manometer will depend on the height of that column and the specific gravity of the fluid in that leg. To determine the new differential reading along the inclined leg of the manometer, we need to calculate the difference in the heights of the two fluid columns after the pressure change. This will be equal to the difference in the heights before the pressure change, minus the 1.15 meter decrease in the height of the fluid column in pipe A.
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HELP! If two objects have 24kg m/s of momentum before they collide. How much momentum do the two objects have afterwards?
if two objects have 24 kg m/s of momentum before they collide, the total momentum of the system after the collision will also be 24 kg m/s.
What is collision ?
In physics, a collision is an event where two or more objects come into contact with each other and exchange energy and/or momentum. Collisions can occur between particles, such as subatomic particles in a particle accelerator, or between macroscopic objects, such as two billiard balls or two cars colliding.There are different types of collisions, which depend on the nature of the interaction between the colliding objects. In elastic collisions, the total kinetic energy of the objects is conserved, while in inelastic collisions, some of the kinetic energy is lost to other forms of energy, such as heat or deformation.If there is no external force acting on a system, the overall momentum of that system stays constant, according to the law of conservation of momentum. As a result, the total momentum of the two items after the collision will equal the pre-collision momentum of the two objects, which is 24 kg m/s.
The combined momentum of the two objects will still be 24 kg m/s if we suppose that they keep together after the impact. The momenta will add up to 24 kg m/s, but they will have distinct magnitudes and directions if, on the other hand, the objects bounce off of each other and move away from the collision in opposing directions.
In order to specifically respond to your query, the overall momentum of Whether the two items stick together or bounce off one another, the combined weight of the two after the contact will be 24 kg m/s.
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b) On the surface of the Earth the spacecraft falls at 9.8 m/s². What is the Spacecraft's
acceleration at this new distance from Earth?
Acceleration due to gravity of the spacecraft at a height of 6400 km from earth's surface is 2.45 m/s²
What is acceleration due to gravity ?The acceleration of an object attained due to the gravitational force acting on it is called acceleration due to gravity.
Here,
The acceleration due to gravity on the surface of earth,
g = GM/R²
Acceleration due to gravity at a height h from earth's surface,
g' = GM/(R + h)²
So, g'/g = R²/(R + h)²
Therefore, g' = gR²/(R + h)²
Here, h = 6400 km = Radius of earth, R
so h = R
Therefore,
g' = gR²/(R + R)²
g' = gR²/4R²
g' = g/4 = 9.8/4
g' = 2.45 m/s²
Hence,
Acceleration due to gravity of the spacecraft at a height of 6400 km from earth's surface is 2.45 m/s²
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Your question was incomplete, but most probably your full question was:
On the surface of the Earth the spacecraft falls at 9.8 m/s². What is the Spacecraft's acceleration at a height 6400 km from Earth?
what is the speed in mph if an object is travelling at 750 m/s?
Answer: The speed of the object in mph is 1680.89 mph
Answer:
1680.89 mph is the speed of an object
please help physics statics.. don't understand how to solve
When Weight of 7294.3 N can be supported by boom if force 7800 is applied on the cable and there is no resultant rotation at point C.
What is Torque ?Torque is defined as force times perpendicular distance from axis of rotation to the point at which force is applied. Torque is denoted by τ and its SI unit is Nm. i.e Torque is given by, τ = F×d sinθ. Torque is vector quantity.
Torque is analogous to force in rotational motion. like there angular velocity ω is analogous linear velocity v. means Torque is a force in rotational motion.
Looking at the answered figure I have resolved forces, there will be no resultant rotation when opposite torques due to opposite horizontal forces gets balanced.
We get,
τ₁ = τ₂
F×d Cos40⁰ = W×d Sin55°
F Cos40° = W Sin55°
W = F×(Cos40°÷Sin55°)
W = F×0.93516
W = 7800 ×0.93516
W = 7294.3 N
Hence Weight that can be supported is 7294.3 N.
b) When we assume that there is no cable, Then
Torque τ = W×d Sin35°
τ = 7294.3×10 Sin35°
τ = 41838.3 Nm
bloom will rotate with 41838.3 Nm torque.
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can i get help please
Answer: Binary fission
Explanation: Bacteria cells split into two using binary fission.
A wooden 40.0 N block is placed on a table. A force of 18.0 N is required to keep the block moving at a constant velocity what is the calculated force on the block
The coefficient of sliding friction is 0.45.
What is meant by friction ?
Friction is defined as a resistive force acting between two surfaces that are in contact and are in relative motion.
Here,
Weight of the force, mg = 40
Kinetic friction, F' = 18 N
F' = μ N
So, coefficient of sliding friction, μ = F'/N
μ = 18/40
μ = 0.45
Hence,
The coefficient of sliding friction is 0.45.
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Your question was incomplete, but most probably your question was,
A wooden 40.0 N block is placed on a table. A force of 18.0 N is required to keep the block moving at a constant velocity what is the coefficient of sliding friction between the table and the block.
A boy cycles continuously through a distance of 1.0km in 5mins Calculate the live range speed?
The computed speed was found to be a number of 3.3333m/s
Computation of Speed, given the distance and timeGiven Data
Speed = ??Distance = 1.0kmTime = 5 minsWe know that the expression for finding speed is given as
Speed = Distance/Time
Converting from km to m we have
m = 1*1000
Distance = 1000m
Converting from 5mins to seconds we have
300 seconds.
Now, Speed = 1000/300
Speed = 3.3333 m/s
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If the diameter of the space station is 770 m, how many revolutions per minute are needed for the "artificial gravity" acceleration to be 9. 80m/s?
To calculate the number of revolutions per minute required to create artificial gravity of 9.80 m/s² in a space station with a diameter of 770 m, we can use the formula for centripetal acceleration: a = (v²)/r
Where a is the centripetal acceleration, v is the velocity of the space station, and r is the radius of the space station. In this case, we want to solve for v, so we can rearrange the formula as: v = sqrt(a * r). Plugging in the given values, we get: v = sqrt(9.80 m/s² * 385 m), v = 62.39 m/s. To convert this to revolutions per minute, we need to know the circumference of the space station, which is: C = 2 * π * r, C = 2 * 3.14 * 385 m, C = 2415.4 m. So the number of revolutions per minute is: rev/min = v / C, rev/min = 62.39 m/s / 2415.4 m/rev * 60 s/min, rev/min = 1.56 rev/min. Therefore, the space station needs to make 1.56 revolutions per minute to create artificial gravity of 9.80 m/s².
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Answer question in the photo
The mass of an object on which force is exerted which displaces 8m of distance and changes its velocity from 0 to 7.18 m/s is m=F/3.22.
What is Newton's second law of motion?
Force(F) applied on the body is mass(m) times its acceleration(a).
i.e. F=ma
according to this equation we get acceleration as
a = F ÷ m this equation says that when we apply more force to the body, more acceleration it gets. When more is the mass of the body, greater force is needed to accelerate with same amount to that less mass.
Given,
Initial velocity u = 0 m/s
final velocity v= 7.18 m/s
Distance s = 8m
According to equation of kinematics,
v²=u²+2as
7.18²=2×8×a
a= 3.22 m/s²
F = ma
F= 3.22×m
m=F÷3.22
if force is given, we can calculate exact mass of an object.
Hence mass of an object is m=F/3.22.
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The AMA of the wedge is 4. If How do the force exerted on the wedge as time as the load.
The AMA (mechanical advantage) of a wedge is given by the ratio of the length of the sloping side of the wedge to its width. If the AMA of the wedge is 4, it means that the length of the sloping side of the wedge is four times its width.
What is the AMA of a wedge?The force exerted on the wedge depends on the load being lifted and the angle of the wedge; as the load increases, the force required to lift it also increases. However, the AMA of the wedge allows for the same load to be lifted with less force.
Force = Load / AMA
Hence, if the AMA of the wedge is 4, it means that the length of the sloping side of the wedge is four times its width.
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a 15000kg locomotive is moving at 12 m/s what is it’s kinetic energy
Answer:
1080000 J
Explanation:
Givens:
m = 15000 kg
v = 12 m/s
[tex]KE=\frac{1}{2} mv^2\\KE=\frac{1}{2} (15000)(12)^2\\KE=1080000 J[/tex]
How much heat does it take to heat 100 g ice of ice from -7C to 0C
890 joules of heat are needed to heat 100 grams of ice from -7°C to 0°C.
Computation of Heat EnergyHeat (in joules) = mass (in grams) x specific heat capacity (in joules/gram °C) x temperature change (in °C)
That is the expression can be clearly represented as
Heat = MC(T1-T2)
Substituting our given Data we have
Heat = 100 g x 2.09 J/g°C x 7°C
Heat = 890 J
A physical feature of matter known as heat capacity or thermal capacity is the quantity of heat that must be applied to an object in order to cause a unit change in temperature. J/K is the metric unit for heat capacity. A broad property is heat capacity.
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What is a valid frame of reference for observing motion if you
are riding on a bus with a friend?
a the bus driver at the front of the bus
b the wastebasket on the bus
c your friend sitting next to you
d objects like trees and houses outside the windows
Answer: D
Explanation:
giving brainly+ points please huuuury
How does a machine, such as a ramp, help make work easier?
A machine can help decrease the input force and the output force.
A machine can help increase the input force and the output force.
A machine can help increase the input force and decrease the output force.
A machine can help decrease the input force and increase the output force.
Answer:
A machine can help decrease the input force and increase the output force.
This is achieved by using a simple machine, such as a ramp, to increase the distance over which the input force is applied. By increasing the distance over which the input force is applied, the amount of force required to move an object is reduced. This is known as mechanical advantage, and it allows a smaller input force to produce a larger output force, making the work easier to do.
For example, if a person needs to lift a heavy object straight up, they would need to apply a large amount of force to lift it. However, if they use a ramp to move the object up a slope, the distance over which the force is applied is increased, making it easier to move the object with less force.
A group of students investigated the relationship between the period of oscillation for a pendulum and the amplitude of the oscillation. Using a lightweight string that was 70.0 cm long and a mass of 1 kg, this group collected and calculated the data shown in the table below.
Amplitude (degrees) Period (s)
10 1.66
10 1.70
10 1.71
10 1.68
10 1.72
35 1.75
35 1.71
35 1.75
35 1.76
35 1.69
Using this information, answer the following questions.
What is the average period of the trials that were conducted with an amplitude of 10 degrees?Answer is units of seconds
What is the average period of the trials that were conducted with an amplitude of 35 degrees?Answer is units of seconds
What would you expect the period to be, based on the relationship given in equation L7.3 of the Experiment 7 handout? Answer is units of seconds
Using this information provided between the relationship between the period of oscillation for a pendulum and the amplitude of the oscillation, the solutions of the given problems are provided below.
What is a pendulum?A body hanging from a fixed point such that it may move back and forth while being pulled by gravity is called a pendulum.
The average period of the trials that were conducted with an amplitude of 10 degrees can be calculated by adding up the period values and dividing by the number of trials:
(1.66 + 1.70 + 1.71 + 1.68 + 1.72) / 5 = 1.69 s (rounded to two decimal places)
The average period of the trials that were conducted with an amplitude of 35 degrees can be calculated similarly:
(1.75 + 1.71 + 1.75 + 1.76 + 1.69) / 5 = 1.73 s (rounded to two decimal places)
Based on the data collected, the average period for an amplitude of 10 degrees is 1.69 s and the average period for an amplitude of 35 degrees is 1.73 s. This suggests that the period does increase with amplitude, consistent with the predicted relationship.
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Explain how a smoke detector works and how the ions create an electric current in the detection chamber.
Answer:
well,,,,, it detecs smok and the smoke its a trigger
Explanation:
A conducting wire of 60cm long is moved at a constant speed of 5m/s perpendicular to a uniform magnetic field. If thr EMF induced in the wire is 2volts, deduce the value of tge magnetic induction
The value of magnetic induction is 0.667 T.
The EMF induced in a conductor traveling through a magnetic field is given by:
EMF = B x L x v
where B is the magnetic induction (measured in Tesla), L is the conductor's length (in meters), and v is its speed (in meters per second)
What we have here is
L = 60 cm = 0.6 m (because the length of the wire is specified in centimeters) (since the length of the wire is given in centimeters)
v = 5 m/s
EMF = 2 V
When these values are inserted into the equation, we obtain the following:
2 V = B x 0.6 m x 5 m/s
Calculating for B, we obtain:
B = 2 V / (0.6 m x 5 m/s) = 0.666... T
Thus, the magnetic induction is 0.667 T, rounded to three significant numbers.
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An astronomer tells you that he has discovered a new planet that he calls Planet X. All he knows about Planet X so far is that it has a very dense atmosphere with a temperature approximately 5 times warmer than that of Earth. What hypothesis can you reasonably make regarding the atmosphere of Planet X? Planet X cannot contain water in any form. The atmosphere of Planet X must not contain any oxygen, so people couldn't live there. The nitrogen cycle does not operate on Planet X in the same way it does on Earth. The atmosphere of Planet X has a higher concentration of greenhouse gases than Earth's does
Based on the information provided by the astronomer, a reasonable hypothesis regarding the atmosphere of Planet X is that it has a higher concentration of greenhouse gases than Earth's atmosphere.
option D.
What is the astronomer's observation?The astronomer's observation that Planet X has a very dense atmosphere and a temperature approximately 5 times warmer than Earth suggests that there may be a significant greenhouse effect taking place.
Greenhouse gases, such as carbon dioxide, water vapor, and methane, trap heat in a planet's atmosphere, which can lead to warming of the planet's surface.
The fact that the astronomer stated that Planet X cannot contain water in any form and must not contain any oxygen suggests that the atmosphere of Planet X is likely very different from Earth's atmosphere.
The nitrogen cycle, which is an essential part of Earth's ecosystem, may not operate on Planet X in the same way, as stated by the astronomer.
However, these statements do not provide direct evidence regarding the concentration of greenhouse gases in Planet X's atmosphere, so the hypothesis regarding the concentration of greenhouse gases is the most reasonable conclusion based on the available information.
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A cannon ball is fired horizontally with a velocity of 50m/s from the top of a cliff 90m high. After how many seconds will it strike the plain at the foot of the cliff? At what distance from the foot of the cliff will it strike? With what velocity will it strike the ground?
Answer: The cannon ball will hit the floor after 4.24 seconds. It will strike at a distance of 212m from the foot of cliff. As the object is travelling with the zero acceleration due to horizontal movement its final velocity will be 50m/s.
A rectangular block of copper metal has a mass of 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, what is the density of copper?
From the dimensions, the volume of the block is 212.52 cm³. Then, the density of the block is its mass divided by the volume, that is 8.92 g/cm³.
What is density ?Density of a substance is the measure of its mass per unit volume. Density of a substance describes how closely its particles are packed. Higher the mass within smaller volume, higher is the density.
given dimensions of the block of copper = 8.4, 5.5 and 4.6 cm
then volume v = l b h
v = 8.4 × 5.5 × 4.6 = 212.52 cm³.
mass = 1896 g
Then, density of the block of copper is determined as follows;
density = mass/volume
d = 1896 g/ 212.52 cm³
= 8.92 g/cm³
Therefore, the density of the copper block is 8.92 g/cm³.
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If vecA= 3 hat i + 4 hat j and vecB= -3 hat i + 7 hat j. Then find vecA * vecB
The cross product of the vector A= 3i + 4j and B= -3i + 7j is found to be -33k.
The vector that are provided to us are vector A and vector B, the value of the vectors are A = 3i + 4j and B = -3i +7j
Now, we have to find the cross products that is given by, R = A X B,
So, we write that,
R = A X B
R = (3i + 4j) X (-3i +7j)
R = -21k - 12k
R = -33k
We have to note here that R is also a vector because the cross product of the two vector is also a vector always but when we do the dot products the resultant is not a vector.
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A caterpillar climbs 1.3 m up a tree, then 0.72 m right, out onto a limb to eat a leaf. What is the magnitude of the resultant displacement of the caterpillar? A 2.2 m , B1.4 m ,C 1.5 m ,D 1.1 m
The magnitude of the resultant displacement of the caterpillar is 1.4m. Therefore, option B is correct.
What is displacement?The change in the position of an object is called displacement, it is the distance between starting and endpoints. It has both magnitude and direction, it is a vector quantity.
If a caterpillar climbs 1.3 m up a tree, then 0.72 m right, the magnitude of resultant displacement is given by:
H² = P² + B²
H² = (1.3)² + (0.72)²
H² = 1.69 + 0.51
H = [tex]\sqrt2.2[/tex]
H = 1.4m
Thus, the magnitude of the resultant displacement of the caterpillar is 1.4m. Therefore, option B is correct.
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A gas of volume 1 l at 10 degree Celsius is heated in such a way that both its volume and pressure become double calculate the final temperature of the gas
Answer:
P V = N R T describes an ideal gas
T2 / T1 = P2 V2 / (P1 * V1) = 4
T1 = 273 + 10 = 283 initial absolute temperature of gas
An experiment modeled the interaction between magnetic force and the change of energy of an object influenced by the
magnetic force. The experiment's researchers observed that the metal wheels of a small car turned as they experienced the
force exerted by a magnetic field, drawing the car closer to the magnet. What energy is being gained by the car? (1 point)
O potential energy
O kinetic energy
O thermal energy
O electrical energy
Swimming in a pool requires that you push back on the water in order to go
forward.
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
Law of Universal Gravitation
Law of Conservation of Momentum
Swimming in a pool requires that you push back on the water in order to go forward is Newton's 3rd Law.
What is Newton's 3rd Law?
Newton's 3rd Law, also known as the law of action and reaction, states that for every action, there is an equal and opposite reaction. This means that if an object A exerts a force on object B, then object B will exert an equal and opposite force on object A.
For example, if you push against a wall, the wall will push back on you with the same force in the opposite direction. This is because every force is a result of an interaction between two objects, and each object exerts an equal and opposite force on the other.
This law is important in understanding how objects interact with each other and is fundamental to many areas of physics, including mechanics, fluid dynamics, and electromagnetism.
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