Answers
Answer:
156.8 Watts
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 10 kg
Height (h) = 8 m
Time (t) = 5 s
Power (P) =?
Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:
Mass (m) = 10 kg
Height (h) = 8 m
Acceleration due to gravity (g) = 9.8 m/s²
Energy (E) =?
E = mgh
E = 10 × 9. 8 × 8
E = 784 J
Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:
Time (t) = 5 s
Energy (E) = 784 J
Power (P) =?
P = E/t
P = 784 / 5
P = 156.8 Watts
Therefore, the power output of the motor is 156.8 Watts
Related Questions
A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset voltage due to this current is ________.
Answers
Answer:
The value is [tex]V_{os} = 0.001 \ V[/tex]
Explanation:
From the question we are told that
The circuit resistance is [tex]R_1 = 10 \ k \Omega[/tex]
The feedback resistance is [tex]R_f = 220 \ k \Omega[/tex]
The offset current is [tex]I_{os } = 100 \ nA = 100 * 1)^{-9} \ A[/tex]
Generally the offset voltage is mathematically reparented as
[tex]V_{os} = R_f * I_{os}[/tex]
=> [tex]V_{os} = 10 *10^{3}* 100 *10^{-9}[/tex]
=> [tex]V_{os} = 0.001 \ V[/tex]
types of curved mirrors
Answers
Answer:
When the reflecting surface is instead curved, we call it a curved mirror. There are two types of curved mirrors; concave and convex mirror. Curved mirrors whose reflecting surfaces curve inwards are called concave mirrors while those whose reflecting surfaces bulge outwards are called convex mirrors.
Explanation:
*PLEASE HELP*
WILL MARK BRAINLIEST
Light passing through a double slit with
separation d = 6.42x10-5 m creates its
first maximum (m=1) at an angle of
0.396 deg. What is the wavelength of
the light, IN NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)
Answers
Answer:
443.8 nm
Explanation:
mλ = yd/D = d(y/D)
m = 1
d = 6.42 x 10-5 m
θ = 0.396°
y/D = tanθ = tan(0.396°) ≅ 6.912 x 10-3
λ = (6.42 x 10-5 m) tan(0.396°) = (6.42 x 10-5 m)(6.912 x 10-3) ≅ 4.438 x 10-7 m = 443.8 nm
I JUST WANT TO MAKE CLEAR THAT d=6.42*10^-5 NOT d = 6.42x10-5 right?
The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?
Answers
Answer:
2. How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is 0.90 J/gºC? c=0.90J/g. 9 (2 sigs.)
Explanation:
Which
type of energy transformation is taking place when natural gas is used to heat water?
O chemical energy into thermal energy
thermal energy into mechanical energy
mechanical energy into electromagnetic energy
electromagnetic energy into chemical energy
Answers
Answer:
O chemical energy into thermal energy
Hope this helped!!
Answer:
chemical energy into thermal energy
Explanation:
______ is the limiting factor that can keep some people from exercising if they can’t afford to purchase certain types of exercise equipment or pay for activities. Money Understanding Motivation Location Family behaviors
Answers
Answer:
I think it is Location.
Explanation:
If im wrong im sorry
Answer:
Money
Explanation:
______ is the limiting factor that can keep some people from exercising if they (can’t afford) to purchase certain types of exercise equipment or pay for activities.
Says they cant afford it, therefore it would obviously be money
1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic
Answers
51.448 g is the required answer!
A bicyclist travels $4.5\text{ km}$ west, then travels $6.7\text{ km}$ at an angle $27.0^\circ$ South of West.
What is the magnitude of the bicyclist's total displacement?
Answers
Answer:
10.88 km
Explanation:
We shall represent displacement in terms of i , j unit vectors in the direction of east and north .
4.5 km due west
D₁ = - 4.5 i
6.7 km at an angle of 27° south of west
D₂ = - 6.7 cos27 i - 6.7 sin27j
= - 6.7 x .89 i - 6.7 x .45 j
= - 5.96i - 3 j
Total displacement
= D₁ + D₂
= - 4.5 i - 5.96i - 3 j
= -10.46 i - 3j
Magnitude = √ ( 10.46² + 3²)
= √ ( 109.41 + 9)
= √ 118.41
= 10.88 km .
According to the FITT Principle you should exercise how many days ?
Answers
In schematic diagrams, currents are indicated using arrows. What do the arrows indicate? a) the direction of motion of the electrons b) the direction of the current vector c) the direction of motion of the charge carriers d) the direction that positive charge carriers would move e) nothing; they are just a convenient drawing tool
Answers
Answer:
D
Explanation:
The direction that positive charge would move
baseball player hits a line drive estimated to have traveled 145 meters the ball leaves the bat with a horizontal velocity of 40.0 m/s . how much time was the ball in the air
Answers
Answer:
3.63 s
Explanation:
Since distance d = vt where v = velocity and t = time taken to cover the distance.
Now, the baseball traveled a distance of d = 145 m with a horizontal velocity of 40.0 m/s.
So, making t subject of the formula,
t = d/v
Substituting the values of d and v we have
t = 145 m/40.0 m/s
= 3.625 s
≅ 3.63 s
So the time the ball was in the air is 3.63 s
A block of mass 3.20 kg is placed against a horizontal spring of constant k = 865 N/m and pushed so the spring compresses by 0.0650 m. HINT (a) What is the elastic potential energy of the block-spring system (in J)? (b) If the block is now released and the surface is frictionless, calculate the block's speed (in m/s) after leaving the spring. n/s
Answers
Answer:
a) The initial elastic potential energy of the block-spring system is 28.113 joules.
b) The final speed of the block is approximately 4.192 meters per second.
Explanation:
a) By applying Hooke's law and definition of work, we define the elastic potential energy ([tex]U_{g}[/tex]), measured in joules, by the following formula:
[tex]U_{g} = \frac{1}{2}\cdot k\cdot x^{2}[/tex] (1)
Where:
[tex]k[/tex] - Spring constant, measured in newtons per meter.
[tex]x[/tex] - Deformation of the spring, measured in meters.
If we know that [tex]k = 865\,\frac{N}{m}[/tex] and [tex]x = 0.065\,m[/tex], then the elastic potential energy is:
[tex]U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)[/tex]
[tex]U_{g} = 28.113\,J[/tex]
The initial elastic potential energy of the block-spring system is 28.113 joules.
b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:
[tex]U_{g} = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (2)
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]v[/tex] - Final speed, measured in meters per second.
Then, the final speed is cleared:
[tex]v = \sqrt{\frac{2\cdot U_{g}}{m} }[/tex]
If we know that [tex]U_{g} = 28.113\,J[/tex] and [tex]m = 3.20\,kg[/tex], then the final speed of the block is:
[tex]v = \sqrt{\frac{2\cdot (28.113\,J)}{3.20\,kg} }[/tex]
[tex]v \approx 4.192\,\frac{m}{s}[/tex]
The final speed of the block is approximately 4.192 meters per second.
A uniform rod of length L, mass M, is suspended by two thin strings. Which of the following statements is true
regarding the tensions in the strings? Please explain
(a) T2 = 0.8 T1
(b) None of the above
(c) T2 = T1
(d) Not enough information to determine
(e) T2 = 0.6 T1
(f) T2 = 2.5 T1
Answers
Answer:
(d) not enough info
Explanation:
because it doesn't specify where the strings are attached
if it was the two ends of the rod then T1 would be equal to T2
I have a cylinder shaped glass container that is 15 cm tall. It holds 100 cm^3 of nitrogen gas at 1 atm pressure (101.3 kPa) and 22 degrees C. I place a rubber stopper in the top so that no gas can escape. If a 40 N force is required to force the rubber stopper off the top of the flask, what temperature can I heat the nitrogen to with a Bunsen burner before the rubber stopper pops off
Answers
Answer:
T₂ = 469.73 K = 196.73 °C
Explanation:
First we will find the surface area of rubber stop:
[tex]Area = A= \frac{Volume}{Length} \\\\A = \frac{100\ cm^3}{15\ cm}\\\\A = 6.67\ cm^2 = 6.67 \ x\ 10^{-4}\ m^2[/tex]
Now, we will find the final pressure required to remove the rubber stop:
[tex]Final\ Pressure\ = P_{2} = \frac{Force}{Area}+Atmospheric Pressure \\\\P_{2} = \frac{40\ N}{6.67\ x\ 10^{-4}\ m^2} + 101.3 KPa\\\\ P_{2} = 60000\ Pa + 101.3 KPa = 60\ KPa + 101.3 KPa\\\\P_{2} = 161.3\ KPa[/tex]
Now, we use equation of state:
[tex]\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}[/tex]
for constant volume due to rigid cylinder:
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\\T_{2} = \frac{P_{2} T_{1}}{P_{1}}[/tex]
where,
P₁ = initial pressure = 101.3 KPa
P₂ = final pressure = 161.3 KPa
T₁ = Initial Temperature = 22°C = 295 K
T₂ = Final Temperature = ?
Therefore,
[tex]T_{2} = \frac{(161.3\ KPa)(295\ K)}{101.3\ KPa}[/tex]
T₂ = 469.73 K = 196.73 °C
1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
2)Explain how the energy transformations follow the Law of Conservation of energy throughout the skier's path. Must answer in complete sentences.
3)Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answers
Answer:
Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789
The total energy at each point in the path of the skier is constant as the
skier travels down the slope.
1) 1A P.E. = 15,000 J, 1B K.E. = 19,000 J, 1C, P.E. = 0 J2) The mechanical energy of the system is constant3) Energy is given off as heat due to friction such that the total energy of the system is not conserved if friction is experiencedReasons:
1) Given that the total mechanical energy, M.E. is constant, we have;
M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant
M.E. = K.E. + P.E.
At the start, we have;
P.E. = 25,000 J
K.E. = 0 J
Therefore;
M.E. = 25,000 J + 0 J = 25,000 J
At point 1A, we have, K.E = 10,000 J
P.E. = M.E. - K.E.
Therefore;
P.E. = 25,000 - 10,000 = 15,000
The potential energy at point 1A, P.E. = 15,000 J
At point 1B, we have; PE = 6000 J
K.E. = M.E. - P.E.
Therefore;
K.E. = 25,000 J - 6,000 J = 19,000 J
At 1B, K.E. = 19,000 J
At point 1C, we have; K.E. = 25,000 J
Therefore;
P.E. = 25,000 J - 25,000 J = 0 J
At 1C P.E. = 0 J
2) The Law of Conservation of Energy states that the energy in a closed
system is constant.
The energy transformation follows the Law of Conservation of energy
given that the total mechanical energy is constant at all points along the
path.
3) The energy of a system is not conserved when a external force is
applied.
If the skier experiences friction, the force of friction does work to reduce
the speed of the skier, thereby reducing the kinetic energy at a point
downslope, where the potential energy has already been reduced,
resulting in an reduction in the mechanical energy of the system.
Therefore, if the skier experiences friction, the total energy of the system is
not conserved, as energy will be consumed in the work done by friction
which is converted to heat and sound energies.
Learn more about the Law of Conservation of Energy here:
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An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of water. Steam condenses and the lost energy heats the water and container. Use the following data to answer the question below:
Mass of the aluminum container 50 g
Mass of the container and water 250 g
Mass of the water 200 g
Initial temperature of the container and water 20°C
Temperature of the steam 100°C
Final temperature of the container, water, and condensed steam 50°C
Mass of the container, water, and condensed steam 261 g
Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C
Given the data above, determine the total heat energy gained by the container and water.
Answers
Answer:
[tex]Q_a=330 cal[/tex]
[tex]Q_w=6000cal[/tex]
Explanation:
From the question we are told that
Mass of the aluminum container 50 g
Mass of the container and water 250 g
Mass of the water 200 g
Initial temperature of the container and water 20°C
Temperature of the steam 100°C
Final temperature of the container, water, and condensed steam 50°C
Mass of the container, water, and condensed steam 261 g
Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C
a) Heat energy on container
Generally the formula for mathematically solving heat gain
[tex]Q_c=M_c *C_c*( \triangle T)[/tex]
Therefore imputing variables we have
[tex]Q_a=50g *0.22*50-20[/tex]
[tex]Q_a=330 cal[/tex]
b) Heat energy on water
Generally the formula for mathematically solving heat gain
[tex]Q_w=M_w *C_w*( \triangle T)[/tex]
Therefore imputing variables we have
[tex]Q_w=200 *1* 50-204[/tex]
[tex]Q_w=6000cal[/tex]
(a) When the terminals of a 100-V battery are connected to two parallel plates 1 cm apart, what is the electrical field in the region between the plates
Answers
Answer:
The electrical field in the region between the plates is 10,000 V/m.
Explanation:
Given;
potential difference between the two parallel plates, V = 100 V
distance between the two parallel plates, d = 1 cm = 0.01 m
The electrical field in the region between the plates is given as;
E = V / d
where;
E is the electrical field in the region between the plates
E = (100) / (0.01)
E = 10,000 V/m
Therefore, the electrical field in the region between the plates is 10,000 V/m.
How could girls improve their communication skills
Answers
Answer:
////??????????????/
Explanation:
Answer:
As you go talk to her or even before you go talk to her. If that's the case however, start talking to everyone you meet both boys and girls. See, improving your communication with women is easy. Just get a few books on social skills and then go over to talk to all the ladies you see without any hidden agenda.
Explanation:
I really hope this helps your question ^_^
Find the gravitational potential energy of an 85kg person, standing atop Mt. Everest, at an altitude of 8848m. Use sea level as the location for y=0.
Answers
Explanation:
Gravitational potential energy
= mgh
= (85kg)(9.81N/kg)(8848m)
= 7,377,904.8J.
A honeybee is in flight between a flower and its hive. Which of the following statements is true?
A) The bee exerts a force on the Earth equal to the force the Earth exerts on the bee.
B)The Earth exerts a greater force on the bee than the bee exerts on Earth.
C) The bee is in flight, but not in orbit, so there is no force of gravity on it.
D) The bee exerts a greater force on the Earth than the Earth exerts on the bee.
Answers
Answer:
D
Explanation:
The statement i.e. true is option d. The bee exerts a greater force on the Earth than the Earth exerts on the bee.
The Flight that lies between the flower and its hive:When the honeybee is in flight that lies between a flower and its hive.
So here the bee should be exerted a high force on the earth as compared to the earth exerted on the bee.
Therefore, the option d is correct.
And, the rest of the options are wrong.
Learn more about force here: https://brainly.com/question/2566388
Which two statements correctly describe the role of a semiconductor in a
solar cell?
I A. When the semiconductors become charged, current flows from
the negative one to the positive one.
B. The electrons freed from the semiconductors by light exit the cell
and never return.
I C. When photons are absorbed, electrons from the semiconductor
are freed because of the photoelectric effect.
D. When the semiconductors become charged, current flows from
the positive one to the negative one.
Answers
Answer:
It's A and C
Options A and C are correct.
A. When the semiconductors become charged, current flows from the negative one to the positive one
C. When photons are absorbed, electrons from the semiconductor are freed because of the photoelectric effect.
What are semiconductors?Semiconductors are materials with conductivity intermediate between conductors and nonconductors or insulators. Semiconductors may be either compound like gallium arsenide.
(A)When the semiconductors become charged, current flows from the negative one to the positive one
Reason: Current flow in a semiconductor is caused by charge carrier migration in both the conduction and valence bands.
Electrons are mobile charges in the conduction band while holes are mobile charges in the valence band. Drift current occurs in the presence of an electric field,
which creates a net motion of positively charged carriers in the same direction as the field and negatively charged carriers in the opposite direction as a result of the force.
(C)When photons are absorbed, electrons from the semiconductor are free because of the photoelectric effect.
Reason: The photoelectric effect is the creation of a current when the light of a specific frequency strikes a surface, which is commonly metallic or semiconducting.
The current is produced when electrons are jolted out of their stable states by the energy transferred from an incoming photon.
The minimum frequency or energy need indicates the varying energy necessary to release an electron from a specific surface, which varies depending on the atomic configuration of the material.
The outermost electrons in metals are not bonded to each atom which is shared by many atoms. This decentralization is what allows metals to conduct electric currents.
Hence options A and C are correct.
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Three wheels each of radius 1 have their centers at respective verticies of an equilateral triangle of side length 4. A belt is wrapped continuously around the wheels. Find the length of the belt.
Answers
Answer:
L = 6 * ( π + 1 )
Explanation:
The side of the equilateral triangle is 4, and each one of the circles is of radius 1. Then
Triangle vertex A B and C
Trajectory of the belt, beginning in vertex A
1.-First circle A one turn
L₁ = 2*π*1 = 2*π
2.-Length between the circle A and B
L₂ = 2
3.- To wrap this circle we need to wrap the circle and to run the belt through the radius twice. The firs over the side AB and the second over the side BC, therefore
L₃ = 2*π*1 + 2*(1)
L₃ = 2*π + 2
4.-Length between two nearest points of circles B and C is 2 and length of the circle in C is 2*π*1. Then
L₄ = 2 + 2*π
Total length of the belt is:
L = L₁ + L₂ + L₃ + L₄
L = 2*π + 2 + (2*π + 2 ) + ( 2 + 2*π )
L = 6*π + 6
L = 6 * ( π + 1 )
Under which of the following conditions is the magnitude of the average velocity of a particle moving in one dimension smaller than the average speed over some time interval?
Answers
Answer:
A particle moves in the +x direction and then reverses the direction of its velocity
Explanation:
This is illustrated in that when a particle moves in a straight route with no alterations in direction, this will lead to displacement and distance being equal at any point in time during the movement. Thereby the quantity of average speed and average velocity will equal.
On the other hand, should the particle reverses direction, the distance traveled will be greater than it's displacement, thereby, the average speed will be greater than the average velocity.
(PLEASE HELP ASAP) Which chemical equation models the law of conservation of mass?
Answers
Answer:
B.) 3KOH + H3PO4 -> K3PO4 +3H20
Explanation:
:p
Chemical equation models the law of conservation of mass is [tex]3KOH + H_{3} PO_{4}[/tex] → [tex]K_{3} PO_{4} + 3H_{2} O[/tex].
What is Chemical equation?A chemical equation would be a symbol and formula-based symbolic formulation of a chemical reaction.
What is law of conservation of mass?For every system that is closed across all exchanges of matter including energy, the law of conservation of mass, also known as the theory of mass conservation.
The equation [tex]3KOH + H_{3} PO_{4}[/tex] → [tex]K_{3} PO_{4} + 3H_{2} O[/tex]. is balanced hence, it will follow mass of conservation law.
Therefore, the correct answer will be option (B).
To know more about law of conservation of mass and Chemical equation
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Calculate the work done by an applied force of 76.0 N on a crate for the following. (Include the sign of the value in your answer.)
a. The force is exerted horizontally while pushing the crate 5.20 m.
b. The force is exerted at an angle of 41.0
Answers
Answer:
a) 400.4Joules
b) 262.69Joules
Explanation:
Work is said to be done if the force applied to an object cause the object to move through a distance
Workdone = Force × Distance
Given
Force = 76N
Distance= 5.2m
Work done = 77 × 5.2
Work done = 400.4Joules
b) If the force is exerted at an angle of 41°
Work done = Fdsin theta
Work done = 77(5.2)sin41
Work done = 400.4sin41
Work done = 262.69Joules
which of the following is not a risk associated with using legal drugs without medical supervision
Answers
Answer:
paying too much on the black market instead of getting a prescription
Explanation:
i just took the quiz
Answer:
Paying too much on the black market instead of getting a prescription
Explanation:
The rest of the options are risks associated with using legal drugs without medical supervision.
When a punter kicks a football, is he doing any work on the ball while the toe of his foot is in contact with it?
a. Is he doing any work on the ball after it loses contact with his toe?
b. Are any forces doing work on the ball while it is in flight?
Answers
Answer:
a) W=0 b) force of gravity and friction force
Explanation:
a) When the kicker touches the soccer ball, his foot exerts a force on the ball in the same direction of its movement, but the ball is stationary, therefore the displacement of the ball during the very short contact is zero and as the work is the product of force and distance, we conclude that there is no work
W = F. d
d = 0
W = 0
b) When the ball is in flight there is mainly the force of gravity that has a vertical direction and the friction force that opposes the movement at all times
a.He does not do any work on the ball after it loses contact with his toe
b.The force of gravity and friction force doing work on the ball while it is in flight.
What is work?Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depend on the diection of body displaced . if the body is displaced in the same direction of force it will be positive.
While if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will be zero.
a.He does not do any work on the ball after it loses contact with his toe.
When the kicker makes contact with the soccer ball, his foot exerts a force on the ball in the same direction as its movement, but the ball is stationary,
So the displacement of the ball during the very short contact is zero, and since work is the product of force and distance, we conclude that there is no work.
[tex]\rm W= F \times d \\\\ \rm W= F \times 0 \\\\ \rm W=0[/tex]
Hence he does not do any work on the ball after it loses contact with his toe.
b.The force of gravity and friction force doing work on the ball while it is in flight.
When the ball is in flight, there is primarily a vertical force of gravity and a friction force that resists movement at all times.]
Hence the force of gravity and friction force doing work on the ball while it is in flight.
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Do scientific theories have math in them?
Answers
Answer:
Yes of course science has maths
an object accepts a pressure of 2:00 p.m. on the ground object is kept above it then the dead pressure will become Dash
Answers
Correct question is;
An object exerts a pressure of 2 pa on the ground if another object of the same weight is kept above it then the net pressure will become _____
Answer:
4 pa
Explanation:
We know that formula for pressure is;
P = Force/area
Where formula for force is;
F = mg
Thus;
P = mg/A
We are told P = 2 pa
Thus;
mg/A = 2
Now, when we add the same weight, our new Force is;
F_new = mg + mg = 2mg
Area remains the same A.
Thus, net pressure = F_new/A = 2mg/A
From earlier, we saw that mg/A = 2.
Thus;
net pressure = 2mg/A = 2 × 2 = 4 pa
What is the mass of an object accelerated at 2 m/s2 by a net force of 12 N?
Please help I’m struggling !!
Answers
Answer: the answer is 6kg.
Explanation:
Mass= force divided by acceleration, which would be 12 divided by 2.