A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)

Answers

Answer 1

Answer:

T= 0.6 sec

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

[tex]T= 2\pi \sqrt{\frac{m}{k} }[/tex]

Substituting the given data into the expression above we have

[tex]T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6[/tex]

T= 0.6 sec

Answer 2

Answer:

0.607

Explanation:

Trust me


Related Questions

What is the ball's acceleration?

Answers

Answer:

g, downward

Explanation:

It is given that, a baseball is thrown straight upward. The force acting on the stone is force of gravity. It is moving under the action of gravity. We know that the force of gravity always acts in a downward direction.

At the highest point, the velocity of the stone will be equal to 0. It will move will constant acceleration equal to g and it always acts in downward direction.

Hence, the correct option is (e) "downward direction".

WILL MARK AS BRAINLIEST...,.. A constant force vector f =2i cap+3j cap-5k cap acts on a particle and displaces it from (1,2,-3) m to (2,5,-1) m. find the work done by the force .

Answers

Explanation:

Given that,

Force, [tex]F=2i+3j-5k[/tex]

The particle displaces from (1,2,-3) m to (2,5,-1) m.

We need to find the work done by the force. Work done by the force is given by :

W = Fd

It is equal to the dot product of force and displacement.

Displacement from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) or (1, 3, 2) m

Work done,

[tex]W=F{\cdot} d\\\\W=(2i+3j-5k){\cdot} (i+3j+2k)[/tex]

We know that, i.i=j.j=k.k=1

So,

[tex]W=1\ J[/tex]

So, the work done by the force is 1 J.

The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is the kinetic energy of the protons when they are ejected from the cyclotron

Answers

Answer:

1.92 x 10⁻¹²J

Explanation:

The magnetic force from the magnetic field gives the circulating protons gives the particle the necessary centripetal acceleration to keep it orbiting round the circular path. And from Newton's second law of motion, the force(F) is equal to the product of the mass(m) of the proton and the centripetal acceleration(a). i.e

F = ma

Where;

a = [tex]\frac{v^2}{r}[/tex]             [v = linear velocity, r = radius of circular path]

=> F = m[tex]\frac{v^2}{r}[/tex]           ------------(i)

We also know that the magnitude of this magnetic force experienced by the moving charge (proton) in a magnetic field is given by;

F = q v B sin θ       ----------(ii)

Where;

q = charge of the particle

v = velocity of the particle

B = magnetic field

θ = the angle between the velocity and the magnetic field.

Combining equations (i) and (ii) gives

m[tex]\frac{v^2}{r}[/tex] = q v B sin θ           [θ = 90° since the proton is orbiting at the maximum orbital radius]

=> m[tex]\frac{v^2}{r}[/tex] = q v B sin 90°

=> m[tex]\frac{v^2}{r}[/tex] = q v B

Divide both side by v;

=> m[tex]\frac{v}{r}[/tex] = qB

Make v subject of the formula

v = [tex]\frac{qBr}{m}[/tex]

From the question;

B = 1.25T

m = mass of proton = 1.67 x 10⁻²⁷kg

r = 0.40m

q = charge of a proton = 1.6 x 10⁻¹⁹C

Substitute these values into equation(iii) as follows;

v = [tex]\frac{(1.6*10^{-19})(1.25)(0.4)}{(1.67*10^{-27})}[/tex]

v = 4.79 x 10⁷m/s

Now, the kinetic energy, K, is given by;

K = [tex]\frac{1}{2}[/tex]mv²

m = mass of proton

v = velocity of the proton as calculated above

K = [tex]\frac{1}{2}(1.67*10^{-27} * (4.79 * 10^7)^2 )[/tex]

K = 1.92 x 10⁻¹²J

The kinetic energy is 1.92 x 10⁻¹²J

Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continue walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other

Answers

Answer:

Δt=48 s

Explanation:

v: Barry's speed

v.: speed of the walkway

Δx=30 m

Δt1=30 s ,  Δt2=120 s

|Δx1|=|Δx2|

Δx=v*Δt

=> (v+v.)*30=(v-v.)*120

v=v.*5/3

30=(v+v.)*30

=> 30=(5v./3 +v.)*30

v.=3/8 m/s

v=5v./3 , v.=3/8

=> v=5/8 m/s

Δx=v*Δt

30=5/8 *Δt

Δt=48 s

(a) In electron-volts, how much work does an ideal battery with a 17.0 V emf do on an electron that passes through the battery from the positive to the negative terminal? (b) If 3.88 × 1018 electrons pass through each second, what is the power of the battery?

Answers

Answer:

(a) 17.0eV

(b) 10.55W

Explanation:

(a) The amount of work done (W) on an electron by an ideal battery of emf value of V as it moves from the positive to the negative terminal is given by;

W = q x V                 --------(i)

Where;

q = charge on the electron = 1e

From the question;

V = 17.0 V

Substitute the values of q and V into equation (i) as follows;

W = 1e x 17.0

W = 17.0eV

Therefore, the work done in electron volts is 17.0

(b) The power (P) of the battery as some electrons (n) pass through it at time t, is given as;

P = (n q V) / t            --------------(ii)

Where;

n = number of electrons = 3.88 x 10¹⁸

t = 1s

q = 1.6 x 10⁻¹⁹C

V = 17.0V

Substitute these values into equation (ii) as follows;

P = (3.88 x 10¹⁸ x 1.6 x 10⁻¹⁹ x 17.0) / 1

P = 10.55W

Therefore the power of the battery is 10.55W

FORENSIC SCIENCE, PLEASE HELP ASAP Investigators find a hair clasped in the fist of a dead victim. Upon close examination, they realize there is follicular tissue attached to that hair. What could investigators use to prove that the hair in the victim's fist belonged to a specific suspect? A) The medulla. B) Nuclear DNA. C) Mitochondrial DNA. D) Physical comparison.

Answers

Answer:

C) Mitochondrial DNA

Explanation:

Mitochondrial DNA can help forensic scientists in recovering the follicular tissue that is attached to the hair, they can find out the specific suspect from that hair.

Mitochondrial DNA is maternally inherited and enables forensic scientists to trace maternal lineage.

Answer:

Mitochondrial DNA

Explanation:

Mitochondrial DNA should be used to prove that the hair in the victim's fist belonged to a specific suspect. Mitochondrial DNA enables scientists to trace maternal lineage from which it can be known that who is the suspect.

Velocity is a description of an object’s blank

Answers

Change in displacement per unit of time (Ex. 25m/s East)

Velocity is the description of an object's motion from one point to another.

It tells the speed with which the trip is completed, and the direction from the start-point to the end-point.  It tells nothing about any twists, turns, loops, bends, or stops along the way.

Theere is more role of the moon than sun to occur tides in oceans why?

Help​

Answers

Answer:

Because ocean tides are the effect of ocean water responding to a gravitational gradient, the moon plays a larger role in creating tides than does the sun. But the sun's gravitational gradient across the earth is significant and it does contribute to tides as well.

i hope this help i

i try to explain and like i sayed i hope this help u.

Answer:

the moon

Explanation:

ive passed the grade you learned this in

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass , the acceleration of the object is . If the same force acts upon another object whose mass is , what is this object's acceleration 19 4 2

Answers

Answer:

The acceleration of the object is 4 m/s².

Explanation:

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass i.e.

[tex]a=\dfrac{k}{m}[/tex] ...(1)

Let us assume that the question is a certain force acting upon an object with mass 2 kg produces an acceleration of 38 m/s². if the same force acts upon another object whose mass is 19 kg, what would this object's acceleration be

Equation (1) can be written as :

[tex]\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}[/tex]

Here,

a₁ = 38 m/s², a₂ =?, m₁ = 2 kg, m₂ = 19 kg

So,

[tex]\dfrac{38}{a_2}=\dfrac{19}{2}\\\\a_2=4\ m/s^2[/tex]

So, the acceleration of the object is 4 m/s².

Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat = 0.4494 J/g·°C) at 0.00°C, and the two blocks are insulated from the rest of the universe. The final temperature of the two blocks will be:

Answers

Answer:

34.34 °C

Explanation:

From the question,

Heat lost by the silver block = heat gained by the iron block.

cm(x-y) = c'm'(y-z)................... Equation 1

Where c = specific heat capacity of the silver block, m = mass of the silver block, c' = specific heat capacity of the iron, m' = mass of the iron. x = initial temperature of the silver block, z = initial temperature of the iron,  y = final temperature of the mixture.

make y the subject of the equation

y = (cmx+c'm'z)/(cm+c'm')............... Equation 2

Given: c = 50 g, c = 0.2350 J/g·°C, x = 100°C, m' = 50 g, c' = 0.4494 J/g.°C, z = 0°C

Substitute these values into equation 2

y = [(50×0.2350×100)+(50×0.4494×0)]/[(50×0.2350)+(50+0.4494)]

y = 1175/(11.75+22.47)

y = 1175/34.22

y = 34.34 °C

what is the electric force between two points charges when q1=-4e, q2 = +3e, and r = 0.05 m?

Answers

Answer:

Option A. 1.1×10¯²⁴ N

Explanation:

The following data were obtained from the question:

Charge 1 (q1) = - 4e

Charge 2 (q2) = + 3e

Distance apart (r) = 0.05 m

Electric field constant (K) = 9×10⁹ N•m²/C²

Electron (e) = 1.6×10¯¹⁹ C.

Electric Force (F) =..?

Next, we shall determine the value of the two charges.

This is illustrated below:

Charge 1 (q1) = - 4e

Charge 1 (- q1) = 4e

Electron (e) = 1.6×10¯¹⁹ C.

Charge 1 (- q1) = 4 × 1.6×10¯¹⁹ C.

Charge 1 (- q1) = 6.4×10¯¹⁹ C.

Charge 2 (q2) = + 3e

Electron (e) = 1.6×10¯¹⁹ C.

Charge 2 (q2) = 3 × 1.6×10¯¹⁹ C.

Charge 2 (q2) = 4.8×10¯¹⁹ C.

Finally, we shall determine the value of the electric force. This can be obtained as shown below:

Charge 1 (- q1) = 6.4×10¯¹⁹ C.

Charge 2 (q2) = 4.8×10¯¹⁹ C.

Electric field constant (K) = 9×10⁹ N•m²/C².

Distance apart (r) = 0.05 m

Electric Force (F) =..?

F = Kq1q2 /r²

F = (9×10⁹× 6.4×10¯¹⁹× 4.8×10¯¹⁹)/(0.05)²

F = 1.1×10¯²⁴ N

Therefore, the electric force between the two point charge is 1.1×10¯²⁴ N

A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How much will be the focal length of the mirror?

Answers

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

Determine whether or not each of the following statements is true. If a statement is true, prove it. If a statement is false, provide a counterexample and explain how it constitutes a counter-example.
A capacitor consists of two flat, metal plates with unequal areas. Each of the plates starts neutral, and then each plate is connected to a dierent terminal of a battery. After some time, the plates will have excess charge on them, and the magnitude of the excess charge on one plate will equal the magnitude of the excess charge on the other plate.
A. True
B. False
If a wire carries current, then it has a net non-zero charge in it.
A. True
B. False

Answers

Answer:

a)  True    b)  True

Explanation:

a) a capacitor is made up of two flat plates and each one has a charge of the same sign, therefore the statement is true

b) the current is the flow of electrons per unit of time, therefore the charge is not zero, therefore the statement is True

Why does time seem to flow only in one direction?

Answers

Answer:

Time seem to flow only in one direction because if it started to go in backward direction that would break the second law of thermodynamics. We do not find time to be moving in any direction because time is not an object that can move nor is it a force that can move any object.

A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The coefficient of kinetic friction between the box and the floor is 0.23. What is the box's launch speed?

Answers

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

The box's launch speed is 5.8 m/s.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Given in question spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor,

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

The box's launch speed is 5.8 m/s.

To learn more about energy refer to the link:

brainly.com/question/1932868

 #SPJ5

Choose the correct answer/s

Answers

I’m pretty sure it’s 1 and 3 only that are true, hope this helps

refer to the attachment for the explanation

The water tank is kept at some height of the buildings. Why?​

Answers

Answer:

The water is at the top because when the water is stored at the top it does not need as much energy to get it to flow because it will be flowing down and be affected by gravity to make the water pressure.

Answer:

The water is at the top because when the water is stored at the top it does not need as much energy to get it to flow because it will be flowing down and be affected by gravity to make the water pressure.

Explanation:

(blank)a0 is undeniably accepted by scientists all over the world as the primary language of science.

Answers

Answer:

English.

Explanation:

English is undeniably accepted by scientists all over the world as the primary language of science. It is a language spoken all over the world and is also the language of science because it is an official language and can be understood by almost everyone.

Answer:

[tex]\boxed{\mathrm{English}}[/tex]

Explanation:

English is undeniably accepted by scientists all over the world as the primary language of science. The scientific methods and experiments are done by communicating and writing in English. Scientists use English to communicate and share knowledge as English is understood by people from around the world.

Define centre of gravity and centre of Bouyancy

Answers

Answer:

Center of Gravity is the point in a body where the gravitational force may be taken to act.  Center of Buoyancy is the center of gravity for the volume of water which a hull displaces.

To get an idea how big a farad is, suppose you want to make a 1.0-F air-filled parallel-plate capacitor for a circuit you are building. To make it a reasonable size, suppose you limit the plate area to 1.4 cm2 .
Part A
What would the gap have to be between the plates?
Express your answer using two significant figures and include the appropriate units.
Part B
Is this practically achievable?
Is this practically achievable?
a. yes
b. no

Answers

Answer:

The gap between the plates will be 1.2 x 10^-15 m

No, this is not practically achievable.

Explanation:

Capacitance = 1.0 F

area of plate = 1.4 cm^2 = 1.4/10000 m^2 =  m^2

distance = ?

We use the equation

[tex]C[/tex] =  [tex]\frac{A}{d}[/tex]*ε

C is the capacitance

where A is the area

d is the distance of separation of plates

ε is the permeability of free space = 8.854×10^-12 F⋅m−1

substituting values, we have

1 = [tex]\frac{0.00014}{d}[/tex]* 8.854×10^-12

distance between plates = 1.2 x 10^-15 m

This is not practically achievable in real life

car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car makes it one-quarter of the way around the circle before it skids off the track.From these data, determine the coefficient of static friction between the car and the track

Answers

Answer:

0.572

Explanation:

First examine the force of friction at the slipping point where Ff = µsFN = µsmg.

the mass of the car is unknown,

The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.

First the tangential direction

∑Ft =Fft =mat

And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r

Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2

So going backwards and plugging in Ffc =m2atπr/ 2r =πmat

Ff = √(F2ft +F2fc)= matp √(1+π²)

µs = Ff /mg = at /g √(1+π²)=

1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572

Runner 1 has a velocity of 10 m/s west. Runner 2 has a velocity of 7 m/s east. From the frame of reference of runner 2, what is the velocity of runner 1? A.17 m/s east. B.3 m/s east. C.17 m/s west. D.3 m/s west

Answers

Answer:

17 m/s west

Explanation:

Runner 1 has velocity = 10 m/s west

runner 2 has velocity = 7 m/s east

From the frame of reference of runner 2, we can imagine runner 2 as standing still, and runner 1 moving away from him, towards the west with their combined velocity of

velocity = 10 m/s + 7 m/s = 17 m/s west

Answer:

17 m/s west

Explanation:

Hope this helps!

A train travels 120 km at a speed of 60 km/h, makes a stop for 0.5 h, and then travels the next 180 km at a speed of 90 km/h. What is the average speed of the train for this trip? 9th grade level pls FFFFFFFFFFFAAAAAAAAAAASSSSSSSSSSSSSTTTTTTTTTTTTT

Answers

Answer:

average speed =  66.67  km/h

Explanation:

In order to find the average speed of the train, you need to calculate the total distance traveled, divided by the time it took to cover that distance. So for the total distance:

Distance= 120 km + 180 km = 300 km

For the total time we need to add three different quantities, two of which we need to derived based on the information provided:

time for first part of the trip:

[tex]time_1=\frac{D_1}{v_1} =\frac{120}{60} \,h= 2\,h[/tex]

for the time of the stop:

[tex]time_2=0.5\,\,h[/tex]

for the last part of the trip:

[tex]time_3=\frac{180}{90} \,h= 2 \,\,h[/tex]

Which gives a total of 4.5 hours

Then, the average speed is:   300/4.5   km/h = 66.67  km/h

An arrow is launched from P with a speed Vi = 25m / s. Knowing that the target Q is 10 m high, and the arrow reaches it as shown in the figure, we are asked to determine the distance X. (g = 10m / s2).

Answers

Answer:

20 m

Explanation:

Given in the y direction:

Δy = 10 m

v₀ = 25 m/s sin 37° = 15.0 m/s

a = -10 m/s²

Find: t

Δy = v₀ t + ½ at²

10 m = (15.0 m/s) t + ½ (-10 m/s²) t²

10 = 15t − 5t²

2 = 3t − t²

t² − 3t + 2 = 0

(t − 1) (t − 2) = 0

t = 1 or 2

Since the projectile reaches Q before it reaches the peak, we want the lesser time, so t = 1.

Given in the x direction:

v₀ = 25 m/s cos 37° = 20.0 m/s

a = 0 m/s²

t = 1 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (20.0 m/s) (1 s) + ½ (0 m/s²) (1 s)²

Δx = 20 m

Suppose that the sound level of a conversation is initially at an angry 71 dB and then drops to a soothing 54 dB. Assuming that the frequency of the sound is 504 Hz, determine the (a) initial and (b) final sound intensities and the (c) initial and (d) final sound wave amplitudes. Assume the speed of sound is 346 m/s and the air density is 1.21 kg/m3.

Answers

Answer:

Explanation:

In the decibel scale , intensity of sound changes logarithmically as follows

[tex]10log\frac{I}{I_0} =[/tex] Value in decibel scale , the value of I₀ = 10⁻¹² W /m².

Putting the values

[tex]10log\frac{I}{10^{-12}} = 71[/tex]

[tex]log\frac{I}{10^{-12}} = 7.1[/tex]

[tex]\frac{I}{10^{-12}} = 10^{7.1}[/tex]

[tex]I= 10^{-4.9}[/tex] W/m²

Similarly for 54 dB sound intensity can be given as follows

I = 10⁻¹² x [tex]10^{5.4}[/tex]

[tex]I= 10^{-6.6 }[/tex] W / m²

For intensity of sound the relation is as follows

I = 2π²υ²A²ρc where υ is frequency , A is amplitude , ρ is density of air and c is velocity of sound .

Putting the given values for 71 dB

[tex]I= 10^{-4.9}[/tex]  = 2π² x 504²xA²x 1.21 x  346

A² = 60.03 x 10⁻¹⁶

A = 7.74 x 10⁻⁸ m

For 54 dB sound

[tex]10^{-6.6}[/tex] = 2π² x 504²xA²x 1.21 x  346

A² = 1.1978 x 10⁻¹⁶

A = 1.1 x 10⁻⁸ m

4.
An "extreme" pogo stick utilizes a spring whose uncompressed length is 46 cm and whose force constant is 1.4 x 104 N/m. A 60-kg person is jumping on the pogo stick,
compressing the spring to a length of only 5.0 cm at the bottom of their jump. Which is the upward acceleration of the person at the moment the spring reaches its greatest
compression at the bottom of their jump?
6 m 2​

Answers

Answer:

a = 85.9 m / s²

Explanation:

For this exercise we can use Newton's second law in the most compressed part

             F - W = m a

force is the spring elastic force

             F = - k Δx

          k Δx - m g = m a

          a = k/m  Δx - g

         Δx = x₀ -[tex]x_{f}[/tex]

         ΔX = 46 - 5 = 41cm (1m / 100cm) = 0.41  m

let's calculate

          a = 1.4 10⁴/60 0.41 - 9.8

          a = 85.9 m / s²

A car drives at a constant speed of 21 m/s around a circle of radius 100 m.
What is the centripetal acceleration of the car?
O A. 4.8 m/s2
O B. 0.21 m/s2
O C. 3.1 m/s2
O D. 4.4 m/s2

Answers

Answer:

Option D. 4.4 m/s²

Explanation:

The following data were obtained from the question:

Velocity (v) = 21 m/s

Radius (r) = 100 m

Centripetal acceleration (a) =.?

The centripetal acceleration of the car can be obtained as follow:

Centripetal acceleration (a) = Velocity square (v²) / radius (r)

a = v²/r

a = 21²/100

a = 441/100

a = 4.41 ≈ 4.4 m/s²

Therefore, the centripetal acceleration of the car is 4.4 m/s².

Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The P-waves have a speed of about 9 km/s. Estimate the average bulk modulus of Earth's crust given that the density of rock is about 2500 kg/m3

Answers

Answer:

[tex]B=2.025\times 10^{11}\ Pa[/tex]

Explanation:

It is given that,

Speed of P- waves, v = 9 km/s = 9000 m/s

The density of rock is about [tex]2500\ kg/m^3[/tex]

We need to find the average bulk modulus of Earth's crust. Let it is given by B. So,

[tex]v=\sqrt{\dfrac{B}{d}} \\\\B=v^2d\\\\B=(9000)^2\times 2500\\\\B=2.025\times 10^{11}\ Pa[/tex]

So, the bulk modulus of the Earth's crust is [tex]2.025\times 10^{11}\ Pa[/tex].

A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah.

Answers

Answer:

Acceleration(a)=21.60 km/h or 21,600 m/s

Explanation:

Since you have the initial velocity(0, because it starts from rest) and the final velocity 72 km/h or 72,000 m/s. so...

[tex]a=\frac{Vf-Vi}{t}\\ a=\frac{72,000 m/s-0}{2s}\\ a=\frac{72,000 m/s}{2s}\\ a=36,000m/s or 36 km/h[/tex]

define the term 'one solar mass.'

Answers

Answer:

the mass of one sun

Explanation:

its really heavy

Other Questions
PLZ HELP ITS 20 POINTS Using the linear combination method, what is the solution to the system of linear equations 5 x + 3 y = negative 10 and Negative 20 x minus 7 y = 15? (5, 1) (1, 5) (1, 5) (5, 1) Inductance is usually denoted by L and is measured in SI units of henries (also written henrys, and abbreviated H), named after Joseph Henry, a contemporary of Michael Faraday. The EMF E produced in a coil with inductance L is, according to Faraday's law, given byE=LIt.Here I/t characterizes the rate at which the current I through the inductor is changing with time t.Based on the equation given in the introduction, what are the units of inductance L in terms of the units of E, t, and I (respectively volts V, seconds s, and amperes A)?What EMF is produced if a waffle iron that draws 2.5 amperes and has an inductance of 560 millihenries is suddenly unplugged, so the current drops to essentially zero in 0.015 seconds? Given: EG - diameter m arc FG =41, m arc EH =53 Find: mE, mGPF A chemist prepares a solution of barium acetate by measuring out of barium acetate into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits. Name and explain the archetypes illustrated in the myth of Cupid and Psyche. which figurative language comes across most clearly in this excerpt from T.S. EliotThe winter evening settles downWith smell of steaks in passageways.Six o'clock,The burnt-out ends of smoky days.And now a gusty shower wrapsThe grimy scrapsof withered leaves about your feetAnd newspapers from vacant lots;The showers beaton broken blinds and chimney-pots,And at the corner of the streetA lonely cab-horse steams and stamps.And then the lighting of the lamps.D AtronyD B. imagerya repetitionD.hyperboleF.eunhemisml 2020 Edmentum. All rights reserved.O Tyna horn Indicate whether the following changes would cause a shift in the demand curve for Product A and, if so, the direction of the shift.Change Demand curve shift? Direction of shift?Increase in price of complementary product Yes or No Increase, decrease or N/AIncrease in the price of the Product A Yes or No Increase, decrease or N/ALaunch of effective advertising campaign for Product Yes or No Increase, decrease or N/A Il y a _______ fromages la fromagerie. 200 323 237 243 did Spanish empire gain or loose territory in 1600 what music festival is said to have begun the summer of love 3. NowHe senses first responsibilityIn a world of possessions. People will take balls,Balls will be lost always, little boy,And no one buys a ball back. Money is external.He is learning, well behind his desperate eyes,The epistemology of loss...........A. What do balls in the above lines refer to?B. Who is He and what is he learning?C. Explain the following phrases: i. senses first responsibility ii. a world of possessions iii. The epistemology of loss Which of the criteria of Jus in Bello refers to the banning of the use of certain kinds ofwarfare because they are seen as bad in themselves?ProportionalityLegitimate authorityDiscriminationIntrinsically evil means 2.Why was Jefferson alarmed at the bitterness of the debate over the extension of slavery?He realized that the nation would always have slaves.He realized that the South would eventually outlaw slavery without interference.He realized that slavery could cause the nation to split apart.He realized that close friends were becoming enemies over the issue of slavery. "In preparing the direct materials budget for Quan Company, management concludes that required purchases are 64,000 units. If 52,000 direct materials units are required in production and there are 9,000 units of beginning direct materials, what is the desired units of ending direct materials This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so that it is circumscribed about the candy bar. If = 4 cm, what is the smallest diameter of wrapper that will fit the candy bar? The following events occur for The Underwood Corporation during 2021 and 2022, its first two years of operations.June 12, 2021, Provide services to customers on account for $33,800September 17, 2021, Receive $19,000 from customers on accountDecember 31, 2021, Estimate that 40% of accounts receivable at the end of the year will not be received.March 4, 2022, Provide services to customers on account for $48,800May 20, 2022, Receive $10,000 from customers for services provided in 2021.July 2, 2022, Write off the remaining amounts owed from services provided in 2021October 19, 2022, Receive $39,000 from customers for services provided in 2022.December 31, 2022, Estimate that 40% of accounts receivable at the end of the year will not be received.Calculate net accounts receivable at the end of 2021 and 2022.2021 2021Total accounts receivable Less: Allowance for uncollectible acounts Net accounts receivable More involved in day-to-day operations than in planning, ________ supervise employees and coordinate their activities to ensure consistent companywide work. A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 4 and y = 5t3 + 6, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.15 s. Complete each sentence below with the preterite of hacer, querer, or venir as appropriateYo____________las reservaciones ayer How many three-digit numbers can you make if you are not allowed to use any other digits except 1 and 2? (You may use 1 and 2 in a number more than once or not at all!)