A 0.10 g honeybee acquires a charge of 23 pC while flying. The electric field near the surface of the earth is typically 100 N/C, directed downward. What is the ratio of the electric force on the bee to the bee's weight

Explanation:

F = ma

2 N = (10 kg) a

a = 0.2 m/s²

Answer:

The two middle chains are for suspension of the glass surface, while the fours chains at all corners prevents tilting

Explanation:

From the picture, the the frame bearing the glass surface is suspended by the two metal chains at the middle,

While the balance to avoid tilting to either directions is maintained by the four  chains at all corners.

Answer:

The relative velocity of an object A with respect to another object B.

Explanation:

The relative velocity of an object A with respect to another object B is the velocity that object A would appear to have to an observer situated on object B moving along with it.

Answer:

we have to use formula of volume to find volume of a cuboid. ( i.e v = l ×b ×h)

Explanation:

here, let your length of cuboid be x cm, breadth be y cm and height be z cm .

now, formula to find volume of cuboid = length ×

breadth × height.

so, v( volume)= l (length)× b (breadth)× h (height)

or, v= x cm × y cm × z cm

therefore, volume is xyz cm^3..... answer.

hope it helps..

Answer: length times width times height

Explanation:

Answer:

Janaki temple and Pashupatinath Temple are found in Nepal. These structures are religious and they increase the pride of the country through tourism. These temples are important in the country and are mostly visited by tourists.

This also helps to bring in income for the country and also helps by attracting many visitors and a corresponding development of its tourism industry.

Answer:

D. Mars is a long distance away

Answer:

Uniform circular motion

Explanation:

When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.

Answer:

Uniform motion

Explanation:

The motion when a car is moving with constant speed along a curve is an example of uniform motion.

A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.

The curve defines the path of the motion and the speed remains constant.

Answer:

Does more sunlight make rose bushes grow taller?

Explanation:

When conducting a research, the researcher usually poses research questions in order to confirm or disprove the research hypothesis. A research question addresses the key issues and questions that the research project is intended to answer. Good research questions always aim at improving the body of knowledge on the selected topic of the research. Research questions must be narrowed down to specific details of the topic. They must also be testable, they must not be vague.

If I am studying the effect of sunlight on rose bushes, then the question, 'does more sunlight make rose bushes grow taller?' Is apt to the research because it can be tested by exposing various thorn bush plants to varying degrees of sunlight and recording my observation.

Answer:

If rose bushes receive more hours of sunlight each day, they will grow taller.

Explanation:

I just answered it on Apex, and they like to switch up how they word things sometimes.

Answer:

23.67 km / hr

Explanation:

car travels 355 km (d)

duration = 15 hrs  (t)

average speed formula = v = d / t

v = 355 km / 15 hr

v = 23.67 km / hr

Explanation:

Hello, there!!!

Here, your question is asking about the speed and the given are:

distance (s)= 355km

time (t) = 15hrs.

speed (v)=?

now,

we have the formula:

v= s/t

or, v = 335km /15 hrs.

Therefore, the speed of car was 23.67km/hr.

Hope it helps..

Explanation:

potential energy ===> kinetic energy

when an object is stretched there will be a stored energy in it enough to react to the upcoming change

that is the potential energy

similar to a stretched elastic band

kinetic energy is the energy on a moving object

*If a kinetic energy takes place there must gave been a potential energy before*

A catapult is used to fire an object into the air, the potential energy transfers as the elastic potential energy and to the kinetic energy when the catapult is released and stretched.

The potential energy is associated with bodies that are above a reference point, at that reference point the value of potential energy is taken as zero. For example, if an object with a mass M is in a tower that is 140 meters high, its potential energy is defined as the product of the mass of the object by gravity and by the height at which the object is measured from the reference point.

Ep =mgh

When talking about elastic objects such as springs or elastic fibers, it is usually understood that there is an elastic potential energy associated with the constant of the spring. This can be calculated using the following equation:

U ela = 1/2×k×(Dx)²

where:

k = elastic constant of the elastic material [N/m]

Dx = distance stretched or compressed of the elastic material [m]

U = elastic energy [Joules]

So, there are difference between the elastic potential energy and the potential energy.

In a catapult, Initially, energy is stored in the form of potential energy which is later converted into kinetic energy. Potential energy can be stored in the form of elastic potential energy in the case of elastic. It suddenly releases the energy to propel the object into the air.

Learn more about catapult,

https://brainly.com/question/20899342

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Actually Welcome to the Concept of the Current Electricity .

Since we know that, Current is Charge per unit time.

so we get as,

Q = I*t

here, Q = charge, I = current, t = time.

Answer:

Scenario A:  toward object 1

Scenario B: toward object 2

Scenario C:  toward object 1

Scenario D:  toward object 1

Explanation:

The heat transfer will take place for different cases are as follow

A: From skin to lotion

B: From lasagna to plate

C: Lava to ocean water

D: From sidewalk to egg

Heat always flows from a higher temperature body to a low-temperature body. Heat transfer, any or all of several kinds of phenomena, is considered a mechanism, that conveys energy and entropy from one location to another.

The specific mechanisms are usually referred to as convection, thermal radiation, and conduction (see thermal conduction).

Conduction involves the transfer of energy and entropy between adjacent molecules, usually a slow process.

Convection involves the movement of heated fluid, such as air, usually a fairly rapid process.

Radiation refers to the transmission of energy as electromagnetic radiation from its emission at a heated surface to its absorption on another surface, a process requiring no medium to convey the energy

The heat transfer will take place for different cases are as follow

A: From skin to lotion

B: From lasagna to plate

C: Lava to ocean water

D: From sidewalk to egg

To know more about Heat transfer follow

https://brainly.com/question/16055406

Explanation:

It is given that,

Object distance from the mirror, u = -30 cm

Focal length of the mirror, f = +15 cm

Size of the object, h = 7.5 cm

We need to find the image distance and the size of the image.

Mirror's formula, [tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]

v is image distance

[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(15)}-\dfrac{1}{(-30)}\\\\v=10\ cm[/tex]

Let h' is the size of the image. So,

[tex]\dfrac{h'}{h}=\dfrac{-v}{u}\\\\h'=\dfrac{-vh}{u}\\\\h'=\dfrac{-10\times 7.5}{-30}\\\\h'=2.5\ cm[/tex]

So, the image is located at a distance of 10 cm and the size of the image is 2.5 cm.

Answer: It is given that A body weighs 20gf in air and 18. 0gf in water. Hence, the answer X-3 = 7.

When vector contain distance and direction it is also known as displacement .

Explanation:

The kinetic energy of an object is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

m is mass of the object

v is the speed of the object

It is clear from the above relation that the kinetic energy of the object is directly proportional to the product of mass and velocity.

The hypothesis can be :

If the speed of the object increased then its kinetic energy increase because kinetic energy is directly proportional to ist speed.

The kinetic energy of an object is given by :

m is mass of the object

v is the speed of the object

It is clear from the above relation that the kinetic energy of the object is directly proportional to the product of mass and velocity.

The hypothesis can be :

If the speed of the object increased then its kinetic energy increase because kinetic energy is directly proportional to its speed.

Explanation:

The age of the universe is 13.8 billion years.

We know that,

1 billion years = 10⁹ years

So,

[tex]13.8\ \text{billion years}=13.8\times 10^9\ \text{years}[/tex]

We need to convert the age of the universe to the scientific notation.

Since, [tex]1\ \text{year}=3.154\times 10^7\ s[/tex]

So,

[tex]13.8\times 10^9\ \text{years}=13.8\times 10^9\times 3.154 \times 10^7\\\\=4.35\times 10^{17}\ s[/tex]

So, the age of the universe is [tex]4.35\times 10^{17}\ s[/tex].

Answer:

So the universe is approximately 1.34 x 10^10 years old

Explanation:

Edmentum

Answer:

27 m/s

Explanation:

V_final = v_initial + a*t

V_final = 15 + 3 * 4

V_final = 27 m/s

Answer:

The change on the Celsius scale is 27.22 °C.

Explanation:

The conversion of Fahrenheit to Celsius is the following:

[tex]T = \frac{5}{9}(^{\circ} F - 32)[/tex]

So, we need to convert T₁ and T₂ from °F to °C:

[tex]T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C[/tex]

[tex]T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C[/tex]

Hence, the change on the Celsius scale is:

[tex] \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C [/tex]

Therefore, the change on the Celsius scale is 27.22 °C.

I hope it helps you!

Answer:

The deviation of a mirror is equal to twice the angle of incidence.The total angle between the straight-line path and the reflected ray is twice the angle of incidence. This is called the deviation of the light and measures the angle at which the light has strayed from its initial straight-line path.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

Answer:

Explanation:

Law of conservation of momentum is applied in solving collision problem. When two body collides, their momentum after collision can be determined using the law.

The law States that the sum of momentum of two bodies before collision is equal to the sum of their momentum after collision. Before collision, both bodies moves with a different velocity while during some cases, the bodies moves with a common velocity after collision.

Whether they move with or without the same velocity depends on the type of collision that exists between them after the collision. After collision, some object sticks together and move with a common velocity while some doesn't.

If the bodies sticks together after collision, the type of collision that occur is inelastic (energy is not conserved) and if they splits after collision, the type of collision that occur is an elastic collision (energy is conserved).

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities before collision

v1 and v2 be their velocities after collision.

According to the law;

m1u1 + m2u2 = m1v1 + m2v2

Note that momentum = mass × velocity of the body.

Answer:

20 m

Explanation:

Given:

v = 0 m/s

a = -10 m/s²

t = 4 s / 2 = 2 s

Find: Δy

Δy = vt − ½ at²

Δy = (0 m/s) (2 s) − ½ (-10 m/s²) (2 s)²

Δy = 20 m

Answer:D

Explanation:

Apex

Answer:

Using X = sum( x's * mass)/sum( masses)

= [(0)*(6400)+ (-9.5*1000) + (9.5)*(1000) + (9.5)*(1000)]/(6400+1000+1000+1000)

= 1.01 m

Y = sum( y's * mass)/sum( masses)

= [(0)*(6400) + (9.5)*(1000) +(-9.5)*(1000) + (-9.5)*(1000)]/ (6400+1000+1000+1000)

= -1.01 m

Answer:

The tension in string P is 25 N, while that of Q is 85 N.

Explanation:

Considering the conditions for equilibrium,

i. Total upward force = Total downward force

                     [tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N

ii. Taking moment about P,

clockwise moment = anticlockwise moment

110 × (2.5 - 0.8) = [tex]T_{Q}[/tex] × (3 - 0.8)

110 × 1.7 = [tex]T_{Q}[/tex] × 2.2

187 = 2.2[tex]T_{Q}[/tex]

[tex]T_{Q}[/tex] = [tex]\frac{187}{2.2}[/tex]

[tex]T_{Q}[/tex] = 85 N

From the first condition,

[tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N

[tex]T_{P}[/tex] + 85 N = 110 N

[tex]T_{P}[/tex] = 110 - 85

[tex]T_{P}[/tex] 25 N

Therefore, the tension in string P is 25 N while that of Q is 85 N.

Answer:

1)31/3Ω

2)18/31A

3)4.06V

Explanation:

According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below

1/R= 1/R1 + 1/R2

But we know R1= 5 Ω and R2= 10 Ω

1/R= 1/5 + 1/10

R= 10/3 Ω

=3.33 Ω

Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then

Req = 10/3 +7

Req= 31/3 Ω

Therefore, equivalent resistance = 31/3 Ω

According to ohms law we know that V= IR

Then I= V/R

Where I= current

R= resistance

V= voltage

I= 6/(31/3)

I= 18/31A

We can now calculate the voltage accross the resistor which is

V=(18/31)× 7

V=4.06V

Therefore, the voltage accross the 7 ohm resistor is 4.06V

CHECK THE FIQURE AT THE ATTACHMENT

Answer:

yeah this statement is tru

Explanation:

it is because the speed of the bullet is more than the speed of rolling ball .so from this reason we cannot catch a bullet.

A bullet will be moving much faster than a rolling ball. Even seeing a bullet in flight requires it to be extremely low velocity.

Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

[tex]x = x_{o}+v_{o,x} \cdot t[/tex]

[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex]

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial horizontal and vertical position of the projectile, measured in meters.

[tex]v_{o,x}[/tex], [tex]v_{o,y}[/tex] - Initial horizontal and vertical speed of the projectile, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]x[/tex], [tex]y[/tex] - Current horizontal and vertical position of the projectile, measured in meters.

Given that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 80\,m[/tex], [tex]v_{o,x} = 360\,\frac{m}{s}[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the kinematic equations are, respectively:

[tex]x = 360\cdot t[/tex]

[tex]y = 80-4.094\cdot t^{2}[/tex]

(a) If [tex]y = 0\,m[/tex], the time taken for the projectile to reach the water is:

[tex]80 - 4.094\cdot t^{2} = 0[/tex]

[tex]t = \sqrt{\frac{80}{4.094} }\,s[/tex]

[tex]t \approx 4.420\,s[/tex]

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If [tex]t \approx 4.420\,s[/tex], the horizontal scope of the projectile is:

[tex]x = 360\cdot (4.420)[/tex]

[tex]x = 1591.2\,m[/tex]

The horizontal scope of the projectile is 1591.2 meters.

(c) If [tex]t = 2\,s[/tex], the height that remains to descend is:

[tex]y = 80-4.094\cdot (2)^{2}[/tex]

[tex]y = 63.624\,m[/tex]

The remaining height to descend after 2 seconds of being launched is 63.624 meters.