Answer: c
Explanation:
The weight of a cuboid box is 288 N. Find its mass.
Answer:
29.39 kg
Explanation:
From the question,
W = mg...................... Equation 1
Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.
make m the subject of the equation
m = W/g.................. Equation 2
Given: W = 288 N
Constant: g = 9.8 m/s²
Substitute these values into equation 2
m = 288/9.8
m = 29.39 kg
When the number of gas particles at a constant pressure decreases how will the volume of the gas change?
A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together and move together after collision. What is the final velocity of the two-vehicle mass? If Kinetic Energy = 0.5 * m * v^2, calculate the KE before the crash and the KE of the combined vehicles after the crash.
Answer:
Final velocity = 7.677 m/s
KE before crash = 202300 J
KE after crash = 182,702.62 J
Explanation:
We are given;
m1 = 1400 kg
m2 = 4700 kg
u1 = 17 m/s
u2 = 0 m/s
Using formula for inelastic collision, we have;
m1•u1 + m2•u2 = (m1 + m2)v
Where v is final velocity after collision.
Plugging in the relevant values;
(1400 × 17) + (4700 × 0) = (1400 + 1700)v
23800 = 3100v
v = 23800/3100
v = 7.677 m/s
Kinetic energy before crash = ½ × 1400 × 17² = 202300 J
Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J
please help its worth 10 points
no links please!
Answer:
which question
eeeee
help pls
pls
pls
Answer:
hey dream I m your big fan for u I have answered this question The third one is correct.
A house painter stands 3.00 m above the ground on a 5.00-m-long ladder that leans against the wall at a point 4.70 m above the ground. The painter weighs 676 N and the ladder weighs 107 N. Assuming no friction between the house and the upper end of the ladder, find the force of friction that the driveway exerts on the bottom of the ladder. If the force of friction is away from the wall, enter a negative value and if the force of friction is toward the wall, enter a positive value.
Answer:
The force of friction that the driveway exerts on the ladder ≈ -176.03 N
Please see attached force diagram created with MS Visio
Explanation:
The height of the house painter above the ground = 3.00 m
The length of the ladder = 5.00 m
The height above the ground at which the ladder leans on the wall = 4.70 m
The weight of the painter = 676 N
The weight of the ladder = 107 N
The angle of inclination of the ladder, arcsin(4.7/5) ≈ 70.05°
For equilibrium, the sum of moments at a point, ∑M = 0
Taking moment about point A gives;
4.7 × R = 107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5)))
R = (107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5))))/4.7 ≈ 176.03
The reaction force at the top of the ladder, R ≈ 176.03 N
For equilibrium, we have;
The sum of the horizontal forces, ∑Fₓ = 0
The reaction at the top of the ladder, R + The force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] = 0
R + [tex]F_R[/tex] = 0
∴ R = [tex]-F_R[/tex]
R ≈ 176.03 N = [tex]-F_R[/tex]
∴ [tex]F_R[/tex] = -176.03 N
Therefore, the force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] ≈ -176.03 N (acting away from the wall).
Can some one please help me
Answer:
its "up, then down, then up"
Explanation:
In which of the following situations is there acceleration? (There may be more than one correct answer)
a. A car is sitting at a stoplight. The light turns green and the car begins moving.
b. A car maintains a speed of 10 mi/hr as it turns a corner.
c. When a truck approaches a stop light, it begins to slow down.
d. A car travels at 65 mi/hr.
What could be the average human density? Justify?
Answer:
985 kg/m3
Explanation:
The average density of the human body is 985 kg/m3 k g / m 3 , and the typical density of seawater is about 1020 kg/m3 k g / m 3 .
Explanation:
the worldwide human population density is around 7,500,000,000 ÷ 510,000,000 = 14.7 per km2 (38 per sq. mi.). If only the Earth's land area of 150,000,000 km2 (58,000,000 sq. mi.) is taken into account, then human population density is 50 per km2 (129 per sq.
Would the following reaction be endothermic or exothermic? Why?
CH4 + 02 --> CO2 + H2O + Energy
A. Exothermic because energy is a reactant
B. Endothermic because energy is a reactant
C. Endothermic because energy is a product
D. Exothermic because energy is a product
Answer:
D. Exothermic because energy is a product
Explanation:
ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.
EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.
Hence, the correct answer for this question will be:
D. Exothermic because energy is a product
A light bulb has a power output of 80 W and it has been left on for 90 seconds. How much work was done?
7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.
Electricity is the _____________ of electrons, because electrons _____________ from atom to atom.
Electricity is the [tex]\sf{\underline{flow}}[/tex] of electrons, because electrons [tex]\sf{\underline{passes}}[/tex] from atom to atom.
Please help choose one
A B C or D
???
3. What does the difference in force depend on?
Answer:
it depends on the relative masses of the objects.
Explanation:
An electric toy with a resistance of 2.50\,\Omega is operated by a 3.00\,\text{V} battery. (c) How much energy was delivered to the toy [over four hours]?
Answer:
Energy = 51840 J = 51.84 KJ
Explanation:
The electrical energy delivered to the toy can be found out by the following formula:
[tex]Energy = (Power)(time)\\Energy = (VI)(t)\\Enegry = VIt\\[/tex]
where,
V = Voltage = 3 V
R = Resistance = 2.5 Ω
I = Current = V/R (Ohm's Law) = 3 V/2.5 Ω = 1.2 A
t = time = (4 h)(3600 s/1 h) = 14400 s
Therefore,
[tex]Energy = (3\ V)(1.2\ A)(14400\ s)\\[/tex]
Energy = 51840 J = 51.84 KJ
Which of the following statements is true with
regards to Blackbody radiation?
a)
b)
c)
A blackbody emits more energy at longer
wavelengths as it heats up
A blackbody emits energy at all wavelengths
The shape of the blackbody spectrum
depends on what the source is made of
All of the above
None of the above
00)
e)
2. When braking and turning, you use ___?
a. All four wheels of traction
b. Only the outside edge of your tires
c. Split traction
d. Additional traction
Answer:
split traction
Explanation:
how does the input distance of a third-class lever compare to the output distance
Answer:
A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force
What allows a metal to be pounded into a flat shape?
When a ball is being lifted work is being done to it, giving it ______ energy.
IF SOMEONE CAN'T FIND THE ANSWER I WILL COMMIT ARSON PLEASE HELP MEE
Brainliest + random amount of points please help me It's a crossword
Answer:
Freefall
Explanation:
Hi the answer is freefall, hope this helps :)
Help plz for 25 points !! I only have an hour left !
https://forms.office.com/Pages/ResponsePage.aspx?..
Print Management S Show My Homework
worites
10
Calculate the power in resistor X when the voltage across X is 2.1 V and the current in resistor
X is 0.041 A
(2 Points)
Answer:
P = 0.0861 W = 86.1 mW
Explanation:
The electrical power in a resistor is defined as the product of the current passing through that resistor and the voltage across that resistor. Therefore, the formula can be written as follows:
[tex]P = VI[/tex]
where,
P = Power in Resistor X = ?
V = Voltage across resistor X = 2.1 V
I = Current passing through resistor X = 0.041 A
Therefore,
[tex]P = (2.1\ V)(0.041\ A)[/tex]
P = 0.0861 W = 86.1 mW
Figure 1 shows the kinetic energy as a function of time for a 2kg object that is released from rest and falls toward Earth’s surface. Figure 2 shows the kinetic energy as a function of time for a 5kg object that is released from rest and falls toward Earth’s surface. Both objects are released simultaneously from the same height. How much does the gravitational potential energy of the object-object-Earth system change from 0s to 10s ?
a) 400J
b)600 J
c)1000 J
d) 1400J
Answer:
The answer is 1400 J, according to my Physics teacher.
Explanation:
You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)
PLS HELP
According to the theory of spontaneous generation, tadpoles were believed to arise form dead flesh. True or False.
A.
FALSE
B.
TRUE
"This was the idea that non-living objects can give rise to living organisms."
A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone when this fellow, clutching his radio, jumps off. Describe the Doppler Effect heard by (a) a person left behind on the platform and (b) a person down below floating on a rubber raft. In each case, specify (1) whether the frequency is greater or smaller than the frequency produced by the radio, (2) whether the observed frequency is constant, and (3) how the observed frequency changes during the fall, if it does change. Give your reasoning.
Answer:
The Doppler Effect is given by the following relation;
[tex]f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f[/tex]
Where;
f' = The frequency the observer hears
f = Actual frequency of the wave
v = The velocity of the sound wave
[tex]v_o[/tex] = The velocity of the observer
[tex]v_s[/tex] = The velocity of the source
Where the observer is stationary, we have;
(i) When the source is moving in the direction of the observer
[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]
(ii) When the source is receding from the observer, we have;
[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]
Therefore;
(a) A person left behind on the platform
For a person left behind on the platform, we have that the radio source is receding, therefore, we have;
[tex]f' = \left (\dfrac{v }{v + v_s} \right) \times f[/tex]
(1) Given that (v + [tex]v_s[/tex]) > v, therefore, v < (v + [tex]v_s[/tex]), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio
(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity
(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller
(b) A person down below floating on a rubber raft
For the the person down below on the rubber raft, the radio source is advancing
Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;
[tex]f' = \left (\dfrac{v }{v - v_s} \right) \times f[/tex]
(1) Given that (v - [tex]v_s[/tex]) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio
(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity
(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)
Explanation:
The mass of an object is 84 kg. Find its weight on the Earth and the Moon.
Answer:
We would take the mass given, 80 kg, and multiply it times the acceleration of Earth's downward pull on that mass, 9.8 m/s/s. So the weight on Earth is 784 newtons. So the weight of the same 80 kg mass on the moon is 133.28 N.
hi
mass is express in Newtons.
On Earth gravity is 9.807 so wieght would be : 9.807 * 84= 823.79
On the Moon garvity is 1.62 so weight would be : 84 *1.62 = 136.08
what is the difference between storm spotter and storm chaser?
Answer:
this is just a guess
Explanation:
a storm spotter only spots the storm and a storm chaser looks for the storm????
Please solve this worksheet for me It’s very important please don’t write unnecessary things or else I’ll report please help me i request
Answer:
1. 231.25 mL
2. 218.75 kPa
3. 6.21 L
4. 427.5 mL
5. 83.01 mL
6. 307.6 mL
7. 1.15 L
8. 440.4 mL
Explanation:
This questions describes Boyle's law. Using Boyle's law equation to solve the questions as follows:
P1V1 = P2V2
Where;
P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume
Please find the answers to each question as an attachment.
Helppppppl!!!!!!!!!!!
Answer:
I think deposition of C is the oldest deposit