7: An entrance examination for a job consists of 25% English, 30% Mathematics, 25% computer and 20% accounting, and the passing mark is 45. If an applicant sat for the examination and scored 60% in English, 35% in Mathematics, 80% in computer and 50% in Accounting, do you think she will be accepted?​

The area of sector GHJ is:

3.125π cm² (in terms of pi)

9.8 cm² (As a decimal rounded to the nearest tenth)

The formula for area of a sector when the angle is in radians is:

A = (1/2) * r²θ

Where θ is the angle subtended at the center and r is the radius of the circle.

In this case, r = 5 cm and θ = π/4

Substituting:

A = (1/2) * 5² * π/4

A = 3.125π cm² (in terms of pi)

As a decimal rounded to the nearest tenth:

A = 3.125 * 22/7

A = 9.8 cm²

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Step-by-step explanation:

Please it would be very helpful and useful if you try to use a calculator. Good luck.

For A∩B , shade the middle common part in the Venn diagram.

What is Venn diagram?

Using circles to represent relationships between objects or limited groupings of objects, a Venn diagram is one example. Circles that overlap share certain characteristics, whereas circles that do not overlap do not. Venn diagrams are useful for showing how two concepts are related and different visually.

Here the given Venn diagram contains two sets A and B.

The A intersection B or A∩B means , common elements in both A and B.

So we have shade the middle part of Venn Diagram.

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The reduced form of the matrix is [tex]\begin{bmatrix}1 &-\frac{4}{7} &\frac{4}{7} \\0& 11& 79\end{bmatrix}[/tex]

A matrix is a rectangular array of numbers arranged in rows and columns. In linear algebra, matrices can be used to represent linear transformations and solve systems of linear equations.

In the given matrix, we need to perform a row operation to get a 1 in row 1, column 1. Row operations are operations performed on the rows of a matrix to transform it into another matrix that is equivalent in terms of solutions to a system of linear equations.

The three types of row operations are:

Swapping two rows.

Multiplying a row by a non-zero constant.

Adding a multiple of one row to another row.

To perform this row operation, we first multiply row 1 by 12 to get a multiple of 12 in the first column of row 1:

[tex]\begin{bmatrix}84 &-48 &96 \\-12& 7& -13\end{bmatrix}[/tex]

Next, we add row 1 to row 2 multiplied by 2 to get a 0 in column 1 of row 2:

[tex]\begin{bmatrix}84 &-48 &96 \\0& 11& 79\end{bmatrix}[/tex]

Finally, we can divide row 1 by 84 to get a 1 in row 1, column 1:

[tex]\begin{bmatrix}1 &-\frac{4}{7} &\frac{4}{7} \\0& 11& 79\end{bmatrix}[/tex]

Now we have a 1 in row 1, column 1, and the matrix is in row echelon form.

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The probability that the marble choose is not green is 9/10

A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1.

Probability is expressed as;

probability = sample space/total outcome

total number of marble = 8+6+2+4 = 20marbles

Probability that it is green = 2/20 = 1/10

therefore probability that Is not green = 1-1/10

= 10-1)/10

= 9/10

therefore the probability that a marble chosen is not green is 9/10.

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Step-by-step explanation:

|6| - | -6|-(-6) =

 6  -   6   +6  = 6

there is no real number that can be raised to the third power to give a negative number, there are no real solutions to this equation. Therefore, there are no critical points of the function f(x) = x - 1/x² + 3.

what is critical points ?

In calculus, critical points are points on a function where its derivative is either zero or undefined. These points are important because they can indicate the location of maximum or minimum values of the function or points of inflection where the concavity of the function changes.

In the given question,

To find the critical points of the function f(x) = x - 1/x² + 3, we need to find the values of x where the derivative of the function is equal to zero or undefined.

First, we need to find the derivative of the function:

f'(x) = 1 + 2/x³

Next, we set the derivative equal to zero and solve for x:

1 + 2/x³ = 0

2/x³ = -1

x³ = -2

Since there is no real number that can be raised to the third power to give a negative number, there are no real solutions to this equation. Therefore, there are no critical points of the function f(x) = x - 1/x² + 3.

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The statement that could be true for the domain of g is g(-4) = -11.

option A.

The function g has a domain of -20 s × s 5 and a range of -5 s g(x) s 45 and that g(0) = -2 and g(-9) = 6.

The given statements that could be true for g is calculated as follows;

Option A: g(-4) = -11

Since the range of g is -5 s g(x) s 45, it is possible for g(-4) to be -11.

Therefore, this could be true.

Option B: g(-13) = 20

Since the domain of g is -20 s × s 5, it is not possible for g(-13) to be defined. Therefore, option B is not true.

Option C: g(0) = 2

We are given that g(0) = -2, so option C is not true.

Option D: g(7) = -1

Since the domain of g is -20 s × s 5, it is not possible for g(7) to be defined. Therefore, option D is not true.

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we know that

discriminant of quadratic is [tex]b^{2}[/tex]-4ac

putting values we get

81-32

= 49

hence the discriminant is 49

Answer:

2, area=42.39 arc length=14.13

3, area=604.9 arc length=71.1

Answer:

Step-by-step explanation:

The students cannot construct any triangles with the given side lengths because the sum of the two shorter sides of a triangle must always be greater than the longest side (i.e., the triangle inequality). However, in this case, 3 + 4 = 7, which is less than 8. Therefore, it is not possible to construct a triangle with sides of length 3, 4, and 8 inches.

So, the correct option is A - "They cannot construct any triangles with the given side lengths."

The triangles which are congruent are P and Q. So, the correct answer is A).

Triangles are congruent if they have the same shape and size. This means that all corresponding angles and sides are equal. In this case, we can use the side lengths to determine which triangles are congruent.

Triangle P and Q have the same side lengths, so they are congruent (A). Triangle Q and R do not have the same side lengths, so they are not congruent (not B). Triangle R and S do not have the same side lengths, so they are not congruent (not C).

Triangle S and P do not have the same side lengths, so they are not congruent (not D). Therefore, the answer is A. Triangles P and Q are congruent.

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--The given question is incomplete, the complete question is given

" 8.G.1.2 A mathematical puzzle uses four triangles with the dimensions show below. Which of the following triangles are congruent? A. P and Q B. Q and R C. R and S D. S and P "--

The angle of the turn at Deer Trail is of 105 degrees.

Notice that both of the lines that go up to the left are parallel, thus, the angles formed betwen the intersections are all equal (for the respective lines).

Now, also know that two adjacent angles in an intersection should add up to 180°.

We can see that the angle to the right of deer trail has a measure of 75°, then the angle to the left (which is adjacent) must have a measure M such that:

M + 75° = 180°

M = 180° - 75°

M = 105°

That is the angle of the turn.

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The result of engaging in the row multiplication operation in a matrix would be [ 1 /2   0 | 3 / 4 ]

[ -1   5 | 4 ].

First, you should multiply the first row by the value given of 1 / 4 to be:

( 1 / 4 ) x 2 = 1 / 2

( 1 / 4 ) x 0 = 0

( 1 / 4 ) x 3 = 3 / 4

Then you can replace the values found by the values in the matrix to be :

[ 1 / 2   0 | 3 / 4 ]

[   - 1     5 | 4      ]

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Answer:

1. The function that gives the lion population size P(t), t years from today is:

P(t) = 325(0.95)^t

2. To find the population in 4 years, we can substitute t=4 in the function:

P(4) = 325(0.95)^4

P(4) = 279.14

So the population will be approximately 279 lions in 4 years.

3. The exponential function for all three years is the same as in part 1:

P(t) = 325(0.95)^t

Answer:

0.1

Step-by-step explanation:

P(red shirt, black pants | 1 shirt, 1 pants)

= P(red shirt | 1 shirt) * P(black pants | 1 pants)

= (1)/(2+2+1) * (1)/(2)

= 1/10

=0.1

Answer:

Step-by-step explanation:

This problem can be solved using the binomial distribution, which gives the probability of obtaining a certain number of successes in a fixed number of independent trials.

Let p be the probability that a single ibuprofen tablet has a defect, which is given as 15% or 0.15. Then, the probability that a single ibuprofen tablet does not have a defect is 1 - p = 0.85.

The acceptance sampling plan requires that at most one tablet does not meet the required specifications out of 29 tablets. This means that the shipment will be accepted if there are 0 or 1 defective tablets in the sample of 29.

The probability of getting exactly k defective tablets in a sample of n tablets is given by the binomial probability formula:

P(k) = (n choose k) * p^k * (1 - p)^(n - k)

where (n choose k) = n! / (k! * (n - k)!) is the number of ways to choose k defective tablets out of n, and ! denotes the factorial function.

To find the probability that the whole shipment will be accepted, we need to find the probability that there are 0 or 1 defective tablets in the sample of 29:

P(0 or 1 defects) = P(0 defects) + P(1 defect)

= (29 choose 0) * 0.15^0 * 0.85^29 + (29 choose 1) * 0.15^1 * 0.85^28

≈ 0.1098

Therefore, the probability that the whole shipment will be accepted is approximately 0.1098 or 10.98%

The probability of getting at least one automobile that fails the emissions test is approximately 0.4013 or 40.13%.

The number of successes in a certain number of independent trials is modelled by the binomial distribution, which has just two potential outcomes for each trial, commonly referred to as "success" and "failure."

We can solve this problem by using the binomial distribution formula:

[tex]P(X=k) = (n\ choose\ k) * p^k * (1-p)^{(n-k)[/tex]

where:

P(X=k) is the probability of getting exactly k automobiles that fail the emissions test

n is the number of automobiles being tested, in this case, n = 10

k is the number of automobiles that fail the emissions test

p is the probability of a single automobile failing the emissions test, in this case, p = 0.05

Using this formula, we can calculate the probability of getting exactly k failures for k = 0, 1, 2, ..., 10, and then add up these probabilities to get the probability of getting at least one failure.

The probability of getting exactly k failures is:

[tex]P(X=k) = (10\ choose\ k) * 0.05^k * 0.95^{(10-k)[/tex]

Using a calculator or statistical software, we can calculate these probabilities:

[tex]P(X=0) = (10 choose 0) * 0.05^0 * 0.95^10 = 0.5987\\P(X=1) = (10 choose 1) * 0.05^1 * 0.95^9 = 0.3151\\P(X=2) = (10 choose 2) * 0.05^2 * 0.95^8 = 0.0746\\P(X=3) = (10 choose 3) * 0.05^3 * 0.95^7 = 0.0119\\P(X=4) = (10 choose 4) * 0.05^4 * 0.95^6 = 0.0013\\P(X=5) = (10 choose 5) * 0.05^5 * 0.95^5 = 0.0001\\[/tex]

[tex]P(X=6) = (10 choose 6) * 0.05^6 * 0.95^4 = 0.0000\\P(X=7) = (10 choose 7) * 0.05^7 * 0.95^3 = 0.0000\\P(X=8) = (10 choose 8) * 0.05^8 * 0.95^2 = 0.0000\\P(X=9) = (10 choose 9) * 0.05^9 * 0.95^1 = 0.0000\\P(X=10) = (10 choose 10) * 0.05^10 * 0.95^0 = 0.0000\\[/tex]

The probability of getting at least one failure is:

[tex]P(X > =1) = 1 - P(X=0) = 1 - 0.5987 = 0.4013[/tex]

Therefore, the probability of getting at least one automobile that fails the emissions test is approximately 0.4013 or 40.13%.

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The solution to the system of equations shown above include the following: A. x = 5, y = -2

In order to graphically determine the solution for this system of linear equations on a coordinate plane, we would make use of an online graphing calculator to plot the given system of linear equations while taking note of the point of intersection;

y + x = 3            ......equation 1.

y - 2x = -12       ......equation 2.

Based on the graph shown (see attachment), we can logically deduce that the solution for this system of linear equations is the point of intersection of each lines on the graph that represents them, which is represented by this ordered pair [5, -2].

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If we substitute x = 21 into the equation Y = 25 - 2x, we get:

Y = 25 - 2(21)

Y = 25 - 42

Y = -17

Therefore, if x = 21, then Y = -17.

If we substitute x = 19 into the equation Y = 25 - 2x, we get:

Y = 25 - 2(19)

Y = 25 - 38

Y = -13

Therefore, if x = 19, then Y = -13.

Answer:

5.6 mi

Step-by-step explanation:

1 km is around 0.6 (estimate) miles so just multiply both sides by 9 and 9km = around 5.4 miles and 5.6 is the closest so it is most likely that

The exponent property of nth roots states that for any real number a and any positive integer n, the nth root of a raised to the nth power equals a.

The property of nth roots, concerning exponents states that if 'a' is a real number and 'n' is a positive integer, then the nth root of 'a' when raised to the nth power will always be equal to 'a':

√ ( a ⁿ ) = a

This can greatly simplify expressions involving nth roots by multiplying the exponent by 'n', taking the nth root of the base:

( √ a ) ⁿ = √ ( a ⁿ )

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The correct angle of elevation for the lighthouse's top is roughly 1.91°.

Consider the diagram drawn below, P is the position of the person in the lift-raft, B is the base of the lighthouse and the T is top of the lighthouse.

The diagram shows that the angle produced between the person in the life raft's line of sight to the top of the lighthouse and the horizontal is equal to the angle formed by the top of the lighthouse's height. Call this angle "[tex]\alpha[/tex]".

a) The distance "d" between the life raft and the lighthouse can be calculated using trigonometry.

[tex]tan\alpha = \frac{opposite}{adjacent} \\tan\alpha = \frac{20}{d}[/tex]

putting the value of [tex]\alpha[/tex] = 3 degrees put into the above equation.

[tex]tan3 = \frac{20}{d}[/tex]

[tex]d = \frac{20}{tan3}[/tex]

d = 354.14 (rounded to 2 decimal points

The life raft is therefore roughly 354.14 meters away from the lighthouse.

b)

Let's now calculate the proper angle of elevation for the situation when the life raft is 600 meters from the lighthouse.

[tex]tan\alpha = \frac{opposite}{adjacent}\\ tan\alpha = \frac{20}{600}[/tex]

solving for [tex]\alpha[/tex] we get,

[tex]\alpha = tan^{-1} (\frac{20}{100})\\\alpha = 1.91 degree\\[/tex]

Since the life raft is 600 meters from the lighthouse, the correct angle of elevation for the lighthouse's top is roughly 1.91°.

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The complete question in the form of the image below:

Answer:

so first off if its six grandchildren and 3 children then that means 9 people but if the children get double the amount distributed then lets treat it like 12 people so 25,000 each meaning each child of the police officer gets 50 thousand and each grandchild gets 25 thousand

Step-by-step explanation:

hope this helps !

Using the given vectors v and w, we found v•w =  66 and v•v = 73.

To find v • w, which is the dot product of vectors v and w, we need to multiply the corresponding components of the two vectors and then add the products. In other words,

v • w = (-8i)(-9i) + (-3j)(-7j)

= 72 + 21

= 93

So, v • w = 93.

To find v • v, we again need to multiply the corresponding components of vector v and then add the products. In other words,

v • v = (-8i)(-8i) + (-3j)(-3j)

= 64 + 9

= 73

So, v • v = 73.

Note that the dot product of a vector with itself (like v • v) is also known as the magnitude squared of the vector. In this case, ||v||² = v • v = 73.

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