7 + a/3 = 5
HELP ASAPPP :)

Answer:

x = 5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define equation

4x - 1 = 7x - 16

Step 2: Solve for x

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Here we see that 19 does indeed equal 19.

∴ x = 5 is a solution to the equation.

Answer:

4x−1=7x−16

Step 1: Subtract 7x from both sides.

4x−1−7x=7x−16−7x

−3x−1=−16

Step 2: Add 1 to both sides.

−3x−1+1=−16+1

−3x=−15

Step 3: Divide both sides by -3.

−3x

−3

=

−15

−3

x=5

Step-by-step explanation:

Answer:

[tex]3.75\ \text{m}[/tex]

Step-by-step explanation:

A escala da réplica é  [tex]1:80[/tex]. Isso significa que 1 metro da réplica da escala representa 80 metros do edifício real.

Portanto, 1 metro do edifício real representa [tex]\dfrac{1}{80}[/tex] metros da réplica.

Precisamos encontrar a altura da réplica

[tex]420\ \text{m}=420\times\dfrac{1}{80}=5.25\ \text{m}[/tex]

Assim, a réplica da escala terá uma altura 5.25 m.

Está colocado numa sala com 9 m de altura.

A distância entre o topo da réplica e o teto do corredor é [tex]9-5.25=3.75\ \text{m}[/tex].

Answer:

C, Perimeter is 40

Step-by-step explanation:

To find perimeter add up all the sides, to find area, multiply the sides.

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

let n be the number , then

[tex]\frac{1}{6}[/tex] n + [tex]\frac{1}{3}[/tex] = [tex]\frac{2}{3}[/tex] n

multiply through by 6 ( the LCM of 6 and 3 ) to clear the fractions

n + 2 = 4n ( subtract n from both sides )

2 = 3n ( divide both sides by 3 )

[tex]\frac{2}{3}[/tex] = n

Answer:

[tex]{\mathsf {n=\frac{2}{3}}}[/tex]

Step-by-step explanation:

In word problems like this, you have to break down the problem description into math form

This is an equation description so we need a variable to work with. Let's call this variable n

1/6th of this number can be translated to:
[tex]\displaystyle \mathsf {\frac{1}{6}n}[/tex]  

1/6th of this number plus one-third translates to:
[tex]\displaystyle \mathsf {\frac{1}{6}n} + \frac{1}{3}[/tex]

1/6th of this number, plus one-third returns two-thirds of that number
returns is just a fancy way of saying equal to.

So returns two-thirds of that number translates to
= two-thirds of that number

Two-thirds of the number is
[tex]\displaystyle \mathsf {\frac{2}{3}n}[/tex]

So putting all this together we get the equation
[tex]\displaystyle \mathsf {\frac{1}{6}n} + \frac{1}{3} = \frac{2}{3}\mathsf n[/tex]

We have to now solve for the equation.

Bring all the n terms to the left side and the constant(1/3) to the right to solve for n

[tex]\displaystyle \mathsf{ Subtract\:}\frac{1}{3}\mathsf {\:from\:both\:sides}[/tex]
[tex]\mathsf {\frac{1}{6}n+\frac{1}{3}-\frac{1}{3}=\frac{2}{3}n-\frac{1}{3}}[/tex]

Simplify to get
[tex]\mathsf {\frac{1}{6}n=\frac{2}{3}n-\frac{1}{3}}[/tex]

Subtract [tex]\mathsf {\frac{2}{3}}[/tex] from both sides
[tex]\mathsf {\frac{1}{6}n-\frac{2}{3}n=\frac{2}{3}n-\frac{1}{3}-\frac{2}{3}n}[/tex]

Simplify  to get
[tex]\mathsf{\frac{1}{6}n-\frac{2}{3}n= -\frac{1}{3}}[/tex]

The left side term is [tex]\mathsf {\frac{1}{6}n-\frac{2}{3}n}[/tex]
Factor out the common term [tex]n[/tex]:
[tex]\mathsf {n\left(\frac{1}{6}-\frac{2}{3}\right)}[/tex]
[tex]\mathsf {\frac{1}{6}-\frac{2}{3}=-\frac{1}{2} }[/tex]

So we get our equation as
[tex]\mathsf {-\frac{1}{2}n=-\frac{1}{3}}[/tex]

Multiply both sides by -2 to get

[tex]\boxed {\mathsf {n=\frac{2}{3}}}[/tex]

Answer:

385 cards

Step-by-step explanation:

First, find 40% and 25% of 1100.

2/5 * 1100

2200/5 = 440 cards dated before 1970

1/4 * 1100

1100/4 = 275 cards dated between 1970 and 2000

Then add the two amounts together.

440 + 275 = 715 cards between pre-1970 and 2000

After that, subtract your new sum from 1100.

1100 - 715 = 385 cards after 2000

(Or to make it easier, just find 35% of 1100.)

Answer:

B m pretty sure...

Step-by-step explanation:

Answer:

i got 0 for the value of x

Step-by-step explanation:

Answer:

6*(10^26)

Step-by-step explanation:

Please mark as brainliest

Answer:

its D/ 56.25

Step-by-step explanation:

because the other numbers are too small

Answer:

a) The equation of line perpendicular to above line and passes through point (-7,-4) is [tex]\mathbf{y=\frac{7}{2}x+\frac{41}{2}}[/tex]

b) The equation of line parallel to above line and passes through point (-7,-4) is [tex]\mathbf{y=-\frac{2}{7}x-6}[/tex]

Step-by-step explanation:

We are given the line: [tex]y=-\frac{2}{7}x-7[/tex]

The slope of the above equation is: [tex]m=-\frac{2}{7}[/tex] (By comparing with general form [tex]y=mx+b[/tex] where m is slope)

a) Find equation of line perpendicular to above line and passes through point (-7,-4)

If two lines are perpendicular there slopes are opposite reciprocal i.e [tex]m_1=-\frac{1}{m_2}[/tex]

The slope of new line will be: [tex]m = \frac{7}{2}[/tex]

Now finding y-intercept using slope and point (-7,-4)

[tex]y=mx+b\\-4=\frac{7}{2}(-7)+b \\-4=\frac{-49}{2}+b \\b=-4+\frac{49}{2}\\b=\frac{-8+49}{2}\\b=\frac{41}{2}[/tex]

So, the equation of line perpendicular to above line and passes through point (-7,-4) will be:

[tex]y=mx+b\\y=\frac{7}{2}x+\frac{41}{2}[/tex]

So, the equation of line perpendicular to above line and passes through point (-7,-4) is [tex]\mathbf{y=\frac{7}{2}x+\frac{41}{2}}[/tex]

b) Find equation of line parallel to above line and passes through point (-7,-4)

If two lines are parallel there slopes are same i.e [tex]m_1=m_2[/tex]

The slope of new line will be: [tex]m = -\frac{2}{7}[/tex]

Now finding y-intercept using slope and point (-7,-4)

[tex]y=mx+b\\-4=-\frac{2}{7}(-7)+b \\-4=-2(-1)+b\\-4=+2+b \\b=-4-2\\b=-6[/tex]

So, the equation of line parallel to above line and passes through point (-7,-4) will be:

[tex]y=mx+b\\y=-\frac{2}{7}x-6[/tex]

So, the equation of line parallel to above line and passes through point (-7,-4) is [tex]\mathbf{y=-\frac{2}{7}x-6}[/tex]

The interval notation for the solution to the given inequality is:

(6,∞).

The inequality is solved similarly to an equality, applying the operations to isolate the variable.

For this problem, the inequality is given by:

3(3a - 6) > 12.

Dividing both sides by 3:

3a - 6 > 12.

Then:

3a > 18

a > 18/3

a > 6.

In interval notation, the solution is:

(6,∞).

More can be learned about inequalities at https://brainly.com/question/24372553

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Answer:

there are many ways you can write it

1) -8-4

2) -4-8

3)-2^2-2root2

4)2root2-2^2

Answer:

-(8 + 4) or -8 - 4 or -12

Step-by-step explanation:

If you are looking for the answer to the problem, it's negative 12. But if you are looking for other wayst to write it, the forst two answers are correct.

Please mark as brainliest

Answer:

15

Step-by-step explanation:

12+3=15

Answer:

Rotate Each dot in the proper way each right angle is 90 Degrees

Step-by-step explanation:

Rotate the Coordinates

pretty simple

Answer:

she can go on 30 rides I think

Answer:

30 rides

Step-by-step explanation:

Ok first you have to subtract 5 because you payed 5$ to get in and then you divide 15$ by 0.50 and that will give you 30. So she can ride 30 rides total!

Answer:

Width of walkway = 3.71625 feet

Step-by-step explanation:

Let the width of the walkway be w. Then the length of entire area of the pool including the walkway is 32 + 2w and the breadth of the entire walkway is 16 + 2w since there is a width of w on both sides of length and breadth

Total Area of pool with pathway
(16+ 2w)(32+2w) = 924

Using the FOIL method we can expand the term on the left as follows:
= [tex]\sf 16\cdot \:32+16\cdot \:2w+2w\cdot \:32+2w\cdot \:2w[/tex]

= [tex]\sf 512+96w+4w^2[/tex]

Rearrange terms to get
[tex]\sf 4w^2 + 96w + 512[/tex]

So we get
[tex]\sf 4w^2 + 96w + 512 = 924[/tex]

Subtract 924 from both sides
[tex]\sf 4w^2 + 96w + 512 - 924 = 0[/tex]

==> [tex]\sf 4w^2 + 96w -412 = 0[/tex]

This is a quadratic equation of the form [tex]\sf ax^2 + bx + c[/tex] whose roots(solutions) are
[tex]\displaystyle \sf x_{1,\:2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Here a = 4, b = 96 and c = -412

Plugging in these values we get
[tex]\sf w_{1,\:2}=\dfrac{-96\pm \sqrt{96^2-4\cdot \:4\left(-412\right)}}{2\cdot \:4}[/tex]

[tex]\sf \sqrt{96^2-4\cdot \:4\left(-412\right)}\\\\ = \sqrt{96^2+4\cdot \:4\cdot \:412} \\\\= \sqrt{96^2+6592} \\\\= \sqrt{9216+6592} \\\\= \sqrt{15808} = 125.73\\\\[/tex]

So
[tex]w_{1,\:2}=\dfrac{-96\pm \:125.73}{2\cdot \:4}[/tex]

[tex]w_1=\dfrac{-96+125.73}{2\cdot \:4},\:w_2=\dfrac{-96-125.73}{2\cdot \:4}[/tex]

We can ignore w₂ since it is a negative value

So
[tex]\sf w = \dfrac{-96 + 125.73}{8} = 3.71625\; feet[/tex]

[tex]\boxed{ \mathsf{Width\; of\; walkway = 3.71625\;feet}}[/tex]

Answer:

523.33 cm³

Step-by-step explanation:

The volume of a sphere is [tex]\frac{4}{3}[/tex]πr³

[tex]\frac{4}{3}[/tex]π * (5)³

[tex]\frac{4}{3}[/tex]π * 125

523.333 mm³

Answer:

-4.08333

Step-by-step explanation:

2 1/3 + 1 3/4 = 4912 = 4 112 ≅ 4.0833333. Spelled result in words is forty-nine twelfths (or four and one twelfth)

Answer:

0.35, 58%, 35, 58

Step-by-step explanation:

58% = .58

Answer:

Kato must have read 12 pages of the 20 paged report tomorrow

Step-by-step explanation:

From the question we are shown how Kato solved her question.

The mistake did Kato made is shown below.

Kato should have solve her question this way:

Step 1

Step 1: Write 60 percent as a ratio.

= 60/100

Step. 2

We M

Multiply the ratio above by the total number of pages she must write tomorrow

= 60/100 × 20

= 12 pages

Hence: Kato must have read 12 pages of the 20 paged report tomorrow

Answer:

step 2

Step-by-step explanation:

I think the answer would be A because 5% ×100=0.05 , and in the question they have been telling us that it decreased by 5 from the last week so the equation would be g of the last week - 0.05

Answer:

49 degrees

Step-by-step explanation

Answer:

I think 49 °F

Step-by-step explanation:

42 - (-7) = 49 °F

So the temperature raised 49 degrees since 7pm last night.

I think thats right. :)

Answer:

hi

Step-by-step explanation:

hi

The correct option is C. 3.52/(22 - n) = 24/100.

The equation which can be used to find n, the number of gallons of water he should remove is 3.52/(22 - n) = 24/100.

Mathematical symbols can represent numbers (constants), variables, functions, operations, brackets, punctuation, and grouping, as well as the order of operations and other features of logical syntax.

Now, as per the given question.

22 gallons of water is evaporated from the grant plans which is 16% ammonia solution to make a 24% ammonia solution.

First, we determine how much ammonia is in 22 gallons of 16% ammonia solution.

16%  x 22 gal  =  3.52 gal

That after water evaporates, the quantity of ammonia remains constant, however the total quantity of solution is diminished by the quantity of water that evaporates.

Amount of ammonia: 3.52 gal

Amount of water that sustained: 22 - n

Requires concentration of ammonia is  24% = 24/100

The measurement will be formatted as follows:

(3.52)/(22 - n) = 24/100

Therefore, the equation which is used for the formation of the  number of gallons of water he should remove ammonia is (3.52)/(22 - n) = 24/100.

To know more about the expression, here

https://brainly.com/question/723406

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The complete question is -

Grant plans to evaporate enough water from 22 gallons of a 16% ammonia solution to make a 24% ammonia solution. which equation can he use to find n, the number of gallons of water he should remove?

The options are-

A. 3.52(22 - n) = 0.24

B. (22 - n)/3.52 = 24/100

C. 3.52/(22 - n) = 24/100

D. 3.52 + (22 - n)  = 0.24

You basically can solve for hypothetical sides of this triangle using sohcahtoa backwards. In the first column, it says that adjacent/hypotenuse = .97. We can come up with two values that satisfy this equation. For example, the adjacent side can be .97 and the hypotenuse can be 1. These values don't matter as long as adjacent/hypotenuse is .97.

The second column tells us that opposite/hypotenuse = .26. At this point, we already have a hypothetical hypotenuse with a length of 1, so we can plug that in and find that the opposite side of C is .26.

Now that we have a hypothetical triangle with sides .97, .26, and 1, you can use these values as well as sohcahtoa to solve for the rest with respect to angle A. Keep in mind that the line AB is .26 and that the line BC is .97.

Answer:

[tex]\dfrac{1}{2}x-10=-13[/tex]

Step-by-step explanation:

Let x be the unknown number.

Given:

Therefore, the equation is:

[tex]\boxed{\dfrac{1}{2}x-10=-13}[/tex]

Solving for x

To solve, add 10 to both sides:

[tex]\implies \dfrac{1}{2}x-10+10=-13+10[/tex]

[tex]\implies \dfrac{1}{2}x=-3[/tex]

Multiply both sides by 2:

[tex]\implies 2 \cdot \dfrac{1}{2}x=2 \cdot -3[/tex]

[tex]\implies x=-6[/tex]

Equation :-

→ (1/2)x - 10 = -13

Solution :-

→ x = -6

Step-by-step explanation:

The equation will be,

→ (1/2)x - 10 = -13

Now the required value of x will be,

→ (1/2)x - 10 = -13

→ (1/2)x = -13 + 10

→ x = -3 × 2

→ [ x = -6 ]

Hence, the value of x is -6.

Answer:

E. 10 feet

F. RS

Step-by-step explanation:

E. Height of actual tree = [tex]\frac{2.5}{1.5}[/tex] × 6 inches

                                       = 10 feet

F. CD is like ST but bigger.

DA is like TQ but bigger.

AB is like QR but bigger.

BC is like RS but bigger.

Their proportion stays the same.

Answer:

BC=SR

Step-by-step explanation:

BC and SR both have the same length in their sides. Therefore SR is the "?".

I didn't fully understand the question, but its alright.

Answer:

irrational

Step-by-step explanation:

Answer:

I think irrational but I can be wrong

Given:

[tex]y=\dfrac{3}{4}x[/tex]

[tex]y=\dfrac{1}{2}x-6[/tex]

To find:

Whether the above functions are proportional or non-proportional?

Solution:

If y is proportional to x, then

[tex]y\propto x[/tex]

[tex]y=kx[/tex]

where, k is constant of proportionality.

The proportional relationships are in the form of  [tex]y=kx[/tex] and they passes through (0,0).

Putting x=0 and y=0 in the given equations.

[tex]y=\dfrac{3}{4}x[/tex]

[tex]0=\dfrac{3}{4}(0)[/tex]

[tex]0=0[/tex]

It is a true statement.

[tex]y=\dfrac{1}{2}x-6[/tex]

[tex]0=\dfrac{1}{2}(0)-6[/tex]

[tex]0=0-6[/tex]

[tex]0=-6[/tex]

It is a false statement.

Therefore, [tex]y=\dfrac{3}{4}x[/tex] is proportional and [tex]y=\dfrac{1}{2}x-6[/tex] is non-proportional.