7. A gold bar has a volume of 4.7 cm3 and a density of 19.3 g/cm3. What is its mass? Be sure to show your work and label all units
Answers
Answer:
90.71
Explanation: Just multiply V/D=Mass
Related Questions
Which will most likely be a consequence as fossil fuel reserves are depleted?
Answers
When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?
Similarly, when do (object distance) is very small and less, what does the thin lens equation predict for the value of 1/f?
Please explain your answer properly, especially for the first question. Thank you
Answers
Answer:
1 / f = 1 / o + 1 / i
1 / image distance + 1 / object distance = 1 focal length
If the object distance is large the image will be at about the focal length
The value of 1 / f is fixed for any one particular lense
As the object distance decreases the image must increase
The above equation can also be written as
o i / (i + o) = f or i / (i / o + 1) = f
If for instance o was very large the image would be at the focal length
Please help me with number 4
Answers
Answer:
D
Explanation:
isaac newton discovered that the color white is created when light passes through a prism. t or f?
Answers
Answer:
false
Explanation:
discovered colours of the rainbow
Answer:
False
Explanation:
Have the day you deserve :)
A snake slithered across the sidewalk in between two sign posts. At the first sign post his speed was
1.2 m/s. At the second sign post his speed was 1.2 m/s. This is an example of...
Answers
This is an example of Uniform Speed
EXPLANATION
Uniform Speed => no change in speed
Uniform Accelerations Speed => There is a change in speed, but the acceleration remains the same.
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A car starts from rest and accelerates uniformly over a time of 6.92 seconds for a distance of 163 m. Determine the acceleration of the car. (Round to one decimal place.)
(okay but can someone actually help because if I don't pass this ima fail physics)
Answers
[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\longmapsto 163=0(6.92)+\dfrac{1}{2}a(6.92)[/tex]
[tex]\\ \sf\longmapsto 163=3.46a[/tex]
[tex]\\ \sf\longmapsto a=\dfrac{163}{3.46}[/tex]
[tex]\\ \sf\longmapsto a=47.1m/s^2[/tex]
A car accelerates from 5 m/s to 15 m/s in 5 s. What is its acceleration?
Answers
Answer:
2m/s squared
Explanation:
15-5=10m/s
10m/s divide by 5s
it gives 2m/s squared
In an electron cloud, an electron that is closer from the nucleus has?
Answers
Answer:
It should be less energy
Explanation:
The further away from the nucleus, the more it holds, correct? So those closer to the nucleus hold less electrons. So therefore, the ones that are closer must have more energy than the outer electrons.
Sound waves travel at a speed of 330.0 m/s . How long does it take for the sound of thunder to travel 1.5 km ? (20points)
Answers
4.55 seconds
Step-by-step explanation:-Given, Speed = 330.0 m/s
To find the time, it will take for the sound of thunder to travel 1.5 km, we have to apply the formula for speed :
[tex]speed = \frac{distance}{time} [/tex]
This implies that:-
[tex]time = \frac{distance}{speed} [/tex]
So, Let's get started with the steps -
Step 1- Convert 1.5 km to metres.
[tex]1.5 \: km \: \\ = > \: 1.5 \times 1000 \\ = > 1500 \: m[/tex]
Step 2- Now, to get time, substitute the values you got now in "time=distance/speed"
[tex]t = \frac{1500}{330}[/tex]
[tex] => t = 4.55 \: seconds[/tex]
Therefore, the answer is 4.55 seconds
✍️ By Benjemin360 ☺️
9 The diagram shows a uniform beam PQ. The length of the beam is 3.0 m and its weight is 50 N. The beam is supported on a pivot 1.0 m from end P. A load of weight W is hung from end P and the beam is in equilibrium. What is the value of W ? A 25 N B 50 N C 75 N D 100 N
Answers
equilibrium = 1/1
50 N/x = 1/1
x = 1/1 × 50 N
x = 50 N (B)
#LearnWithEXO
Answer: D 100N
Explanation: Subtract the length of the beam by the pivot and multiply the weight by it.
Question 1 Multiple Choice Worth 2 points)
Which statement best describes the difference between strong nuclear forces and weak nuclear forces?
O Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together
Weak nuclear forces hold bonds between atoms together. Strong nuclear forces hold together the nucleus of an atom.
O Strong nuclear bonds prevent atoms from falling apart. Weak nuclear bonds prevent compounds from falling apart.
Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the nucleus.
Answers
Answer:
Explanation:
The correct answer is: Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms together.
why the things could change the shape of by applying Force for grade 2
Answers
When a force acts on an object, the object may change shape by bending, stretching or compressing - or a combination of all three shape changes. ... Pull an object's ends apart, eg when a rubber band is stretched. Push an object's ends together, eg when an empty drinks can is squashed.
Answer: Its like clay.
Explanation:
When you push down on clay it changes. Boom answered
3. In Figure 2, which object (A, B, or C) has the highest density? Why?
Answers
Answer: C Because it has more dots in the rectangle meaning that if it has more dots than others then it has a higher density according to the model
Explanation:
10 Psychological Tricks That Can Make Your Life Much Easier
1. Look into someone’s eyes when you get a dissatisfactory answer: Sometimes we don’t like the answer to a question that we receive and sometimes we don’t understand it. Instead of repeating the question or asking another, look into the eyes of the person. This will make the person feel under pressure or cornered, and this will force them to further elaborate their thoughts.
2. Stay calm when someone raises their voice to you: Make a strong effort to remain calm. When a loudmouth acts out it’s usually in anger, and our behaviors can sometimes unintentionally provoke that. The feelings of anger usually quickly subside and guilt will set in and usually this person is first to ask for forgiveness.
3. Sit close to the aggressor to avoid attack: If you’re heading into a meeting and you know you’ll be in the room with an aggressive person, you know the discussion may become heated, or you may be subjected to negative criticism, make a point to sit next to that person. You may feel uncomfortable and awkward, but you won’t be the only one. Close proximity is known to make people uncomfortable which will lessen the level of aggression they plan to exercise.
4. Remember everyone’s names if you want to be popular: If you want to be popular with your peers and colleagues, make it a habit to start calling people by their first names when speaking with them. A person feels instantaneously special when you call him or her by their first name.
5. Write down your thoughts when you feel stressed or anxious: We all feel some level of mental stress or anxiety at some point. Write down your thoughts in a journal and then close it up. Believe it or not, you’ll be able to focus on your work more easily because you have now shared your thoughts with someone. When you share them, you will then feel the burden on your mind reduced.
6. Give yourself fewer choices when you can’t make the decision:Some people believe that it’s better to have more choices and more information and actually, they prefer to have more. However, it is actually paralyzing to have too many. There is evidence that shows that having four options at a time is the maximum number we can consider and still make a choice. In order to be an effective decision maker, you should only give yourself a few options at a time. This will allow you time to consider each one while giving you enough space between looking at a new set of options.
7. Right posture can boost confidence: This psychological trick applies to both work and pleasure. It can drastically improve your dating life and help you move up the ladder at work. How can you become confident do you ask? The best way to do this is through your posture. If you allow yourself to take up more space, you’re more likely to feel more confident. This is referred to power language.
8. Surefire way to win in ‘rock, paper, scissors’: This one is definitely intriguing. When you’re about to play this famous game, ask your opponent a random question right before. This typically will throw your confused opponent off and more often than not they will throw up ‘scissors’.
9. Make people feel needed when you ask for help: If you need someone’s help start off with the phrase, ‘I need your help…’ People like to feel needed and they hate feeling guilty. By starting off the conversation with that phrase, you’re more likely to receive the help you need.
10. Warm your hands before shaking hands with others:Did you know that cold hands are linked to distrust? When you’re about to touch someone or shake their hand, make sure that your hands are warm. Warm hands promote a friendly atmosphere.
and those are the ten physiology tricks.
Answers
Answer: Cool! Thanks!
How much work is done when 0.0042C is moved through a potential difference of 12.0V? Use W = qV
A. 2900J
B. 12J
C. 0.00035J
D. 0.050J
Answers
Work done by charge (W) = 0.050 (Approx)
Explanation:
Given:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
A skateboarder flies horizontally off a cement planter. After 3 seconds the skateboarder lands on the ground with a final velocity of −4.5 m/s. Which kinematic equation would be most useful for finding the skateboarder’s initial velocity? (Assume a=−9.8 ms^2)
B
C or E
A
D
Answers
Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:
[tex]v = v_o + a \Delta t[/tex]
A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.
[tex]v = v_o + a \Delta t\\\\v_o = v - a \Delta t = (-4.5 m/s) - (-9.8 m/s^{2} ) \times 3 s = 24.9 m/s[/tex]
Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:
[tex]v = v_o + a \Delta t[/tex]
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Answer:
A
Explanation:
explain the energy transformation processes in an electromagnet
Answers
Answer:
Explanation:
It transfers from mechanical energy, to electrical energy to chemical energy. The energy transformation in an electromagnet is from chemical to electrical to electromagnetic waves. The north poles of two different magnets will attract each other.
To prevent accidental poisoning, you should NOT __________.
A.
mix chemicals in well ventilated areas
B.
follow the instructions on the label
C.
keep materials in unlabeled containers
D.
use chemicals in well ventilated areas
Answers
Answer:
the answer is option c
Explanation:
if we keep materials in unlabelled containers we can mix them up and use 2 dangerous acids to make an explosion
2
Which graph represents the motion of a car that is travelling along a straight road with a uniformly
increasing speed?
A
B.
С
D
o acceleration
acceleration
o displacement
o displacement
Tannie
tume
Answers
Answer:
I know someone that has the answer
Explanation:
A
What a medium-mass star becomes at the end of its life?
Answers
Answer:
What a medium-mass star becomes after a planetary nebula; a very bright, dense mass about the size of the planet Earth. ... The process that generates all of the energy that a star produces. Supernova. A Red Super Giant explodes into this when it runs out of elements to fuse together.
Explanation:
will give correct answer brainliest
In a trial, an expert witness uses the conservation of momentum to demonstrate which initial velocities would give the final states that occurred in the accident. Can using the conservation of momentum be justified in this case? Yes, because momentum is conserved in all collisions. No, momentum is only conserved in elastic collisions which this is not. No, energy is always conserved, but momentum is only sometimes conserved. Yes, because momentum is conserved in inelastic collisions which all car accidents are.
Answers
Yes, because momentum is conserved in all inelastic collisions which all car accidents are
Explanation :
What is law of conservative of momentum
It expresses that In a harmony the underlying force is equivalent to the last energy of the body
What is The mass of a object that has a force of 100_Newtons and acceleration of 25 m/s/s
Answers
Answer:
Yoour MOM
Explanation:
HELP PLZZZZZZZZZZZZZ
Answers
Answer:
A and B and D and C
Explanation:
Answer: I would say (A) (D) and (C)
Explanation: I am doing the same thing in my class as well.
Hope this helped. :-)
Have a wonderful day!!
10. Four forces act on a hot-air balloon, shown from
the side in the figure below. Find the magnitude and
direction of the resultant force on the balloon.
enollsugano
mu
5120 N
1520 N
nomina
coat
950 N
Bideo
bi
biswerwobler
SI
vo
4050 N
Answers
The resultant of the four forces on the balloon is 1,212.35 N at 62⁰.
The given parameters;
Force applied to the north = 5120 NForce applied to the west = 1520 NForce applied to the east = 950 NForce applied to the south = 4050 NThe resultant vertical force is calculated as follows;
[tex]F_y = 5120 \ N - 4050 \ N\\\\F_y = 1,070 \ N[/tex]
The resultant horizontal force is calculated as follows;
[tex]F_x = 1520 \ N - \ 950 \ N\\\\F_x = 570 \ N[/tex]
The resultant of the four forces is calculated as follows;
[tex]F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(1,070)^2 + (570)^2} \\\\F = 1,212.35 \ N[/tex]
The direction of the force is calculated as follows;
[tex]\theta = tan^{-1} (\frac{1070}{570} )\\\\\theta = 62^0[/tex]
Thus, the resultant of the four forces on the balloon is 1,212.35 N at 62⁰.
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Define the words offense and defense in flag football
Answers
Answer: I believe offense is the attacking team and defense is the defending team
Source: I just peeked at dad watching football
El cuerpo de 2kg se suelta de A recorriendo el plano inclinado 60° con la horizontal y de superficie lisa hasta el punto B. Luego recorre el tramo rugoso BC deteniéndose en C. Hallar “L” si se sabe que μ= 0,6.
Answers
El valor de L del tramo rugoso B a C con coeficiente de fricción igual a 0,6, recorrido por el cuerpo de 2 kg cuando se suelta del punto A es 5.00 m.
El valor de L se puede calcular a partir de la definición de trabajo:
[tex]W = F_{\mu}*d[/tex] (1)
En donde:
[tex]F_{\mu}[/tex]: es la fuerza aplicada sobre el cuerpo en el tramo de B a C = fuerza de roce = -μN (el signo menos se debe a que está en dirección opuesta a la del movimiento)
μ: es el coeficiente de roce = 0,6
N: es la normal = mg
m: es la masa del cuerpo = 2 kg
g: es la aceleración debida a la gravedad = 9,81 m/s²
d: es la distancia = L =?
Por otra parte, el trabajo también se define como la diferencia de energía mecánica entre los puntos B y C.
[tex] W = E_{C} - E_{B} [/tex] (2)
Al igualar la ecuación (1) con la (2) tenemos:
[tex]E_{C} - E_{B} = F_{\mu}*d[/tex] (3)
En el punto C, la energía es cero (0) dado que el cuerpo se detiene y en el punto B la energía que tiene el objeto es la cinética:
[tex] E_{B} = \frac{1}{2}mv_{B}^{2} [/tex]
En donde:
[tex]v_{B}[/tex]: es la velocidad del cuerpo en el punto B
La velocidad del cuerpo en el punto B se puede calcular mediante conservación de energía entre los puntos A y B:
[tex] E_{A} = E_{B} [/tex]
En el punto A, el cuerpo tiene energía potencial gravitacional, por lo tanto:
[tex] mgh = \frac{1}{2}mv_{B}^{2} [/tex] (4)
En donde:
h: es la altura = 3 m
Entonces, la velocidad en el punto B es (eq 4):
[tex] v_{B} = \sqrt{\frac{2mgh}{m}} = \sqrt{2*9,81 m/s^{2}*3 m} = 7,67 m/s [/tex]
Ahora, la ecuación (3) queda como sigue:
[tex] 0 - \frac{1}{2}mv_{B}^{2} = -\mu N*L [/tex]
[tex] \frac{1}{2}2 kg*(7.67 m/s)^{2} = 0,6*2 kg*9,81 m/s^{2}*L [/tex]
Resolviendo para L, tenemos:
[tex] L = \frac{\frac{1}{2}2 kg*(7.67 m/s)^{2}}{0,6*2 kg*9,81 m/s^{2}} = 5.00 m [/tex]
Por lo tanto, el valor de L es 5.00 m.
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A 15 kg chunk of ice falls off the top of an iceberg. If the chunk of ice falls 8m to the surface of the water what is its velocity?
Answers
Answer:
When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE = M g H
we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s
NEED HELP!!! 13 POINTS!!!!!!
According to Newton’s first law of physics, which explains what happens to a baseball when it is hit with a bat?
OPTIONS:
A.
The course of the ball cannot be changed as long as it remains in motion.
B.
The ball lacks force or momentum but gets momentum when it hits an unbalanced force.
C.
The ball is an unbalanced force and can only have its course altered by a stationary object.
D.
The ball is traveling at a steady speed until it hits an unbalanced force and changes direction.
PLEASE NO LINKS
Answers
Answer:
Your answer will be D.
The ball is traveling at a steady speed until it hits an unbalanced force and changes direction.
Explanation:
The ball is traveling at a steady speed until it hits an unbalanced force and changes direction. The correct option is D.
Thus, An unbalanced external force acts upon an item, Newton's first law of motion, often known as the law of inertia, asserts that an object at rest will remain at rest and an object in motion will continue to move in the same direction and at the same pace.
When a baseball is struck with a bat, it is originally at rest or moving steadily forward.
The ball experiences an imbalanced force when it is struck by the bat, altering its direction and speed. The bat's application of external force is what causes this shift in motion.
Thus, The ball is traveling at a steady speed until it hits an unbalanced force and changes direction. The correct option is D.
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A projectile is launched with an initial speed of 12 m/s. At its highest point its speed is 6 m/s. What was the launch angle of the projectile?
Answers
We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.
The launch angle of the projectile is 60°.
Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.
Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).
Then we can conclude that the horizontal velocity is equal to 6m/s.
If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:
12m/s*cos(θ) = 6m/s
Now we can solve this for theta.
cos(θ) = (6m/s)/(12 m/s) = 1/2
θ = Acos(1/2) = 60°
The launch angle of the projectile is 60°.
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How much power does it require to do 200 J of work in 5 s?
Answers
Answer:
soln
work done= 200J
Time taken = 5 sec
power=?
We know that,
power=w/t
= 2000/5
= 400W
Explanation:
hopw this will help you