6. What happens to a substance at critical temperatures?
O A. The substance can't change its state, only its temperature.
O B. The substance changes its state if it continues gaining or losing thermal energy.
O C. The substance can't lose any more thermal energy.
O D. The substance changes its state only if it gains thermal energy.

The efficiency of a chemical reaction is measured as a percentage yield, which shows what fraction of the theoretical yield was actually obtained in the laboratory. It is calculated by multiplying by 100% and dividing the theoretical yield (the largest amount of product that can be obtained under perfect conditions) by the actual yield (amount of product obtained in the experiment).

The theoretical yield of CasP₂ from question #6 was calculated to be 0.143 moles.

To calculate the percent yield, we use the formula:

Percent yield = (actual yield/theoretical yield) x 100%

Substituting the given values:

Percent yield = (0.11/0.143) x 100%

Percent yield = 76.92%

Therefore, the percent yield of CasP₂ is 76.92%.

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If a beaker contains 15.6 moles of water, then it  represents 9.39 × 10²⁴ molecules of water, 0.317 moles of PbO contains approximately 1.91 × 10²³ formula units of PbO,  6.01 × 10²⁵ atoms of cesium is equivalent to 99.7 moles of cesium, and 3.54 × 10²¹ molecules of sulfur dioxide represents approximately 5.88 × 10⁻³ moles of sulfur dioxide.

If a beaker contains 15.6 moles of water (H₂O), we can calculate the number of molecules using Avogadro's number, which is approximately 6.022 × 10²³ molecules/mol.

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 15.6 moles × 6.022 × 10²³ molecules/mol

Let's plug in the value and calculate;

Number of molecules = 15.6 moles × 6.022 × 10²³ molecules/mol

Number of molecules ≈ 9.39 × 10²⁴ molecules

So, 15.6 moles of water represents approximately 9.39 × 10²⁴ molecules of water.

The number of formula units of PbO (lead(II) oxide) in 0.317 moles of PbO can be calculated using Avogadro's number, which is approximately 6.022 × 10²³ formula units/mol.

Number of formula units = Number of moles × Avogadro's number

Number of formula units = 0.317 moles × 6.022 × 10²³ formula units/mol

Let's plug in the value and calculate;

Number of formula units = 0.317 moles × 6.022 × 10²³ formula units/mol

Number of formula units ≈ 1.91 × 10²³ formula units

The number of moles of cesium (Cs) equivalent to 6.01 × 10²⁵ atoms of cesium can be calculated using Avogadro's number, which is approximately 6.022 × 10²³ atoms/mol.

Number of moles = Number of atoms / Avogadro's number

Number of moles = 6.01 × 10²⁵ atoms / 6.022 × 10²³ atoms/mol

Let's plug in the value and calculate;

Number of moles = 6.01 × 10²⁵ atoms / 6.022 × 10²³ atoms/mol

Number of moles ≈ 99.7 moles

So, 6.01 × 10²⁵ atoms of cesium is equivalent to approximately 99.7 moles of cesium.

The number of moles represented by 3.54 × 10²¹ molecules of sulfur dioxide (SO₂) can be calculated using Avogadro's number, which is approximately 6.022 × 10²³ molecules/mol.

Number of moles = Number of molecules / Avogadro's number

Number of moles = 3.54 × 10²¹ molecules / 6.022 × 10²³ molecules/mol

Let's plug in the values and calculate;

Number of moles = 3.54 × 10²¹ / 6.022 × 10²³

Number of moles ≈ 5.88 × 10⁻³ moles

So, 3.54 × 10²¹ molecules of sulfur dioxide represents approximately 5.88 × 10⁻³ moles of sulfur dioxide.

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Answer: The oxidation number P in Ca3(PO4)2 is +1

Explanation:

To find the oxidation number of P in Ca3(PO4)2, we need to use the following rules:

The oxidation number of an atom in its elemental form is always 0.

The oxidation number of a monatomic ion is equal to its charge.

The sum of the oxidation numbers of all atoms in a neutral compound is 0.

The sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the charge of the ion.

Let's start with Ca3(PO4)2:

The oxidation number of Ca is +2. This is because Ca is an alkaline earth metal and tends to lose 2 electrons to form a 2+ ion.

The oxidation number of O is -2. This is a common rule for oxygen in most compounds.

We don't know the oxidation number of P yet, so let's call it x.

Now we can use rule 3 to set up an equation:

3(2+) + 2x + 4(-2) = 0

Simplifying, we get:

6 + 2x - 8 = 0

2x - 2 = 0

2x = 2

x = +1

Therefore, the oxidation number of P in Ca3(PO4)2 is +1.

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Under these conditions, the cell potential, Ecell, would be somewhat lower than the usual cell potential, E°cell.

To determine whether the cell potential, Ecell, would be greater than, less than, or equal to the standard cell potential, E°cell, use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where:

Ecell = cell potential under the given conditions

E°cell = standard cell potential

R = gas constant (8.314 J/(mol·K))

T = temperature in Kelvin (25°C = 298 K)

n = number of electrons transferred in the overall cell reaction

F = Faraday constant (96,485 C/mol)

Q = reaction quotient

The balanced equation for the cell reaction is:

2Al(s) + 3Sn₂⁺(aq) → 2Al₃⁺(aq) + 3Sn(s)

The cell reaction involves the transfer of 3 electrons, so n = 3.

At standard conditions (1 M concentration for all species and 25°C), the cell potential, E°cell, can be calculated using the standard reduction potentials for the half-reactions:

Al₃⁺(aq) + 3e- → Al(s) E° = -1.66 V

Sn₂⁺(aq) + 2e- → Sn(s) E° = -0.14 V

E°cell = E°(cathode) - E°(anode) = (-0.14 V) - (-1.66 V) = 1.52 V

To calculate Q, use the given concentrations of Al3+ and Sn2+:

Q = ([Al₃⁺]²/[Sn⁺]³) = (1.90 M)² / (0.25 M)³ = 231.2

Now use the Nernst equation to calculate Ecell under the given conditions:

Ecell = E°cell - (RT/nF)ln(Q)

Ecell = 1.52 V - [(8.314 J/(mol·K))(298 K)/(3 mol)(96,485 C/mol)ln(231.2)]

Ecell = 1.52 V - (0.012 V) = 1.508 V

Therefore, the cell potential, Ecell, under these conditions would be slightly less than the standard cell potential, E°cell. This is because the concentration of Al₃⁺ is higher and the concentration of Sn₂⁺is lower than the standard conditions, which shifts the reaction towards the side with lower concentration of Al₃⁺ and higher concentration of Sn₂⁺. This means that the reaction is not occurring under standard conditions and the Nernst equation must be used to account for the non-standard conditions.

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The balanced thermochemical equation for the reaction of pentane (C5H12) with oxygen gas (O2) to produce water (H2O) and carbon dioxide (CO2) is:

C5H12 (l) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (l) ΔH = -3,510 kJ

The equation is balanced by making sure there are equal numbers of atoms of each element on both the reactant and product sides of the equation. The states of matter are included in the equation to show the physical state of each substance, with (l) indicating a liquid and (g) indicating a gas.

The negative value of enthalpy (ΔH) indicates that this reaction is exothermic, meaning that it releases heat to the surroundings. In other words, the products of the reaction have a lower enthalpy than the reactants. This can be explained by the fact that the bonds formed between carbon and oxygen in CO2 and between hydrogen and oxygen in H2O are stronger than the bonds broken between carbon and hydrogen in C5H12 and between oxygen atoms in O2. The excess energy is released in the form of heat, resulting in a negative value for ΔH.

The friend whose statement I agree with most about the cycling of carbon dioxide and oxygen in the ecosystem is Flynn.

I agree with Flynn's statement about the cycling of carbon dioxide and oxygen in the ecosystem.

Animals do indeed take in oxygen and release carbon dioxide during respiration, while plants take in carbon dioxide and release oxygen during photosynthesis. This process of exchanging gases between plants and animals is known as the carbon cycle, which is crucial for the survival of all living things.

The carbon cycle ensures that there is a balance between the amount of carbon dioxide in the atmosphere and the amount that is used up by living organisms. In addition, the cycling of other nutrients such as nitrogen and phosphorus is also important for the functioning of the ecosystem.

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Alternative fuels are called "green energy" as their wavelengths are in the green part of the EM spectrum. Therefore, the correct option is option A.

Natural resources like sunshine, wind, rain, waves, plants, algae, and geothermal heat are used to produce green energy. These energy sources can be renewed naturally because they are renewable. Fossil fuels, in contrast, take many thousands of years to form & will continue to deplete as they are used.

Furthermore, compared to fossil fuels, which as a byproduct release greenhouse gases that contribute to climate change, renewable energy sources have a significantly smaller negative environmental impact.  Alternative fuels are called "green energy" as their wavelengths are in the green part of the EM spectrum.

Therefore, the correct option is option A.

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The molarity of the solution which contains 0.031 mol of K₂SO₄ in 622 mL of solution is approximately 0.0499 M.

Molarity is commonly used to describe the concentration of solutions in various chemical reactions, including reactions in the laboratory, industry, and everyday life. It is an important concept in chemistry for quantifying the amount of a substance present in a solution and for calculating the amount of reactants needed in chemical reactions.

To calculate the molarity of a solution, we use the formula:

Molarity (M) = moles of solute/volume of solution in liters

Given; moles of K₂SO₄ = 0.031 mol

volume of solution = 622 mL = 622/1000 L = 0.622 L

Plugging these values into the formula;

Molarity (M) = 0.031 mol / 0.622 L ≈ 0.0499 M

Therefore, the molarity of the solution is 0.0499 M

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Alkene is an unsaturated hydrocarbon which contain at least one carbon-carbon double bond. Here butene is an alkene with the chemical formula C₄H₈. The functional group present in alkenes is the double bond.

The structural isomers are those isomers in which the atoms are completely arranged in a different order but have the same molecular formulas. It is also called the constitutional isomers.

Geometric isomers are two or more compounds with the same number and types of atoms and bonds but have different geometries for the atoms.

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a) The solute in solution A is Sodium (Na)

b) The percent concentration of solution A is 4.72 %

Solute is that component of the solution which gets dissolved therefore here sodium is the solute and water is the solvent. Solute is also the minor component of a solution, the component which is present in less amount.

Percent concentration is simply the grams of solute present in 100 grams of a solution.

To calculate the percent concentration, the formula given below could be used

% concentration = [tex]\rm \dfrac{ Mass \ of \ solute}{Mass \ of \ solution} \times 100[/tex]

                           = [tex]\frac{460}{97.4}[/tex]

                           = 4.72 %

Therefore,

a) The solute in solution A is Sodium (Na)

b) The percent concentration of solution A is 4.72 %

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The density, in g/L, of an ideal gas when it is at 1.48 atm and 94.06 °C is 6.67g/L.

The density of an ideal gas can be calculated by dividing the mass of the substance by its volume in litres.

According to this question, the pressure and temperature of the ideal gas is given. The number of moles occupied by the gas can be calculated as follows;

PV = nRT

1.48 × 22.4 = n × 0.0821 × 367.06

33.152 = 30.14n

n = 1.1 moles

mass of gas = 1.1 mol × 145.63g/mol = 160.18g

Density = 160.18g ÷ 22.4L = 6.67g/L

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Answer:  

What is a double replacement reaction? Double replacement reactions—also called double displacement, exchange, or metathesis reactions—occur when parts of two ionic compounds are exchanged, making two new compounds.

Explanation:

The frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz.

The speed of light in a vacuum is given as 3.00 x 10⁸ m/s. The speed of light is also related to the wavelength and frequency of the electromagnetic wave by the equation:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

Rearranging the equation to solve for frequency, we get:

ν = c/λ

Substituting the values given in the problem, we get:

ν = (3.00 x 10⁸ m/s) / (3.7 x 10⁻¹¹ m)

ν = 8.1 x 10 ¹⁸ Hz

Therefore, the frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz, and the correct answer is (A) 8.1 x 10 ¹⁸ Hz.

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The following steps can be used to make a sugar 342g/mol. 0.45 solution in 50ml: 1. Determine the amount of sugar necessary. This may be accomplished by applying the formula mass = molarity x volume.

In this situation, the needed sugar mass is 0.45 x 50 = 22.5 g. 2. Dissolve 50 mL of water in the estimated quantity of sugar. To achieve this, add the sugar to the water in a beaker and swirl until it is completely dissolved.

3. Make sure the solution is exactly 50 ml in volume. This can be accomplished by adding extra water to the solution as needed. 4. The sugar 342g/mol 0.45 solution in 50 ml is now ready for use.

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When we dissolve 123g KBr into 689g of water, the mass percent is 15.1 %.

The mass per cent of a solution is defined as the mass of solute in grams per grams of solution, multiplied by 100 so as to get the mass percentage.

The formula of mass per cent  is expressed as solving for the molar mass and for the mass of each element present in 1 mole of the compound.

The mass of the solution

= mass of solute (KBr) + mass of solvent (water)

= 123 g + 689 g

= 812 g

123 g KBr present in 812 g solution

Let, X be present in  100 g solution

X = 100 g solution x 123 g KBr/812 g solution

   = 15.1 g KBr

   = 15.1 % by mass

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A computer model will benefit a scientist while studying the blood cells for medical research because that would enable the scientist to see how the flow of the blood cells will look like when it is slowed down and the correct option is option B.

Our blood contains a number of blood cells which are suspended in a liquid which is known as plasma. Blood cells are the constituents of blood and are of different types like Red blood cells (RBCs), white blood cells (WBCs), Platelets etc. Plasma contains about 92% water and the most abundant solutes present in it are the plasma proteins and they include globulins, albumins etc.

Computer models help us to observe blood and its components and can provide us more insights and observation into the blood flow as we are able to slow it down as per our convenience.

Thus, the ideal selection is option B.

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The electrolysis of water has the following balanced equation:

[tex]O_2(g) = 2H_2O(l) + 2H_2(g)[/tex]

According to the equation, it takes 2 moles of electrons to generate 1 mole O2.

The Faraday constant, F, which represents the charge carried by 1 mole of electrons, must be used to calculate the amount of charge needed to produce a specific amount of O2. The value of F is 96500 C/mol.

Using the Ideal Gas Law, we must first determine how many moles of O2 are formed from 1.50 L of O2 gas at 25.0 °C and 1.00 atm pressure:

PV = NRT

n = (PV)/(RT) = 1.00 atm/1.50 L/[(0.0821 lat/(molK)](298 K)]

= 0.0607 mol

Therefore, 0.0607 moles of O2 are formed.

We need 2 moles of electrons, or 2 x 0.0607, or 0.1214 moles, because 1 mole of oxygen requires 2 moles of electrons.

Finally, we can use the Faraday constant to determine the required charge:

Q = Nf = 0.1214 mol, 96500 C/mol, or 11700 C

Therefore, 11700 coulombs of charge are needed to produce 1.50 L of oxygen at 25.0 °C and 1.00 atm pressure.

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The pressure in atm, in a 4.00 L tank with 5.15 moles of nitrogen gas at 69.6˚C is 36.18 atm.

According to the ideal gas law,

PV = nRT

Here,                  

Volume (V) = 4.00 L

Number of moles (n) = 5.15 mol

Temperature (T) = 69.6 ˚C = 69.6+273.15 = 342.75 K

Universal gas constant (R) = 0.082 L atm mol-1 K-1

Pressure (P) =  ?

Therefore, mathematically

 P × 4.00 = 5.15 × 0.082 × 342.75

            P  =   [tex]\frac{(5.15)(0.082)(342.75)}{4.00}[/tex]

            P  =   [tex]\frac{144.74}{4.00}[/tex]

            P  =  36.18 atm

The pressure in atm, in a 4.00 L tank with 5.15 moles of nitrogen gas at 69.6˚C is 36.18 atm.

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26.8L is the volume, in liters, of 1.20 mol of C[tex]_3[/tex]H[tex]_8[/tex] gas at STP. A measurement of three-dimensional space is volume.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship.

The volume of an envelope is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the quantity of fluid (liquid or gas) that the container may hold.

Volume = 1.20×22.4

              =26.8L

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There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

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The difference in lengths between the steel and copper bars at 41.0°C is 8.729 mm.

The difference in the lengths of the two bars can be calculated using the linear expansion equation;

ΔL = α × L × ΔT

where; ΔL = Difference in length

α = Coefficient of linear expansion

L = Initial length

ΔT = Change in temperature

Given; Initial length (L) = 1.500 m

Change in temperature (ΔT) = 41.0°C - (-12.0°C) = 53.0°C

The coefficient of linear expansion for steel is typically around 11 x 10⁻⁶ /°C, and for copper, it's around 16 x 10⁻⁶ /°C.

For the steel bar;

α (steel) = 11 x 10⁻⁶ /°C

For the copper bar;

α (copper) = 16 x 10⁻⁶ /°C

Now we can calculate the difference in lengths for both bars.

For the steel bar;

ΔL (steel) = α (steel) × L × ΔT

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C

For the copper bar;

ΔL (copper) = α (copper) × L × ΔT

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C

Converting the length difference from meters to millimeters (1 m = 1000 mm):

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 8.729 mm (rounded to three decimal places)

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 12.168 mm (rounded to three decimal places)

Therefore, the difference in the lengths of the two bars will be 8.729 mm.

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The process used 4.86 moles of hydrogen gas to generate 3.24 moles of ammonia gas.

According to the balanced chemical equation, the stoichiometry of the reaction shows that 3 moles of hydrogen gas (H₂) react with 1 mole of nitrogen gas (N₂) to produce 2 moles of ammonia gas (NH₃).

So, for every 2 moles of NH₃ produced, we need 3 moles of H₂ consumed. Therefore, to determine the moles of H₂ consumed, set up a proportion:

3 moles H₂ / 2 moles NH₃ = x moles H₂ / 3.24 moles NH₃

where x is the number of moles of H₂ consumed.

Solving for x:

x = (3 moles H₂ / 2 moles NH₃) x (3.24 moles NH₃) = 4.86 moles H₂

Therefore, 4.86 moles of hydrogen gas were consumed in the reaction to produce 3.24 moles of ammonia gas.

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It would be easier to communicate information about mass to extraterrestrial civilizations.

Mass and weight are two different concepts that are often used interchangeably in everyday language.

Mass is a measure of the amount of matter in an object and is measured in kilograms (kg) or grams (g). Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is measured in newtons (N).

If we were to communicate with an extraterrestrial civilization, it would be easier to communicate information about mass rather than weight because mass is an intrinsic property of an object that does not depend on gravity.

Therefore, mass would be more universal and easier to understand by extraterrestrial civilizations.

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The number of nitrogen atoms in a container of volume 0.50 dm³ at 0 °C. The pressure of the gas is 101 Pa. is  approximately 1.47 x 10^19 nitrogen atoms in the given container.

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

0.50 dm³ = 0.50 x [tex]10^-^3[/tex] m³

0 °C = 273 K

n = PV/RT

n = (101 Pa)(0.50 x [tex]10^-^3[/tex] m³) / [(8.31 J/mol K)(273 K)]

n = 0.0000244 mol

n = (0.0000244 mol)(6.02 x [tex]10^2^3[/tex]atoms/mol)

n = 1.47 x [tex]10^1^9[/tex] nitrogen atoms

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There are 5.79 x 10²¹ representative particles in 2.62g of the molecular compound.

Determine the number of moles of the molecular compound.

We can use the formula:

moles = mass / molar mass

where mass is 2.62g and molar mass is 273g/mol.

moles = 2.62g / 273g/mol

moles = 0.00961 mol

Use Avogadro's number to convert from moles to representative particles.

We can use the formula:

representative particles = moles x Avogadro's number

where Avogadro's number is 6.022 x 10²³.

representative particles = 0.00961 mol x 6.022 x 10²³

representative particles = 5.79 x 10²¹

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He could improve the model if he place Earth between the moon and the sun.

We know that the solar system is composed of the sun and the planets and we can have a model of the solar system when we get together the sun and the other parts of the solar system as has been done in the model that was put together by Dwight .

Since the model was intended to show the eclipse of the moon then the model can be improved if he place Earth between the moon and the sun in the image of the  model

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The value of K is 4.4 represents the equilibrium position of the reaction under the given conditions.

The equilibrium constant (K) for a reaction is a constant value that relates the concentrations of the reactants and products at equilibrium. For the given reaction, the equilibrium concentrations of SO₂, O₂, and SO₃ are given as [SO₂] = 1.50 M, [O₂] = 1.25 M, and [SO₃] = 3.50 M, respectively.

The equilibrium constant (K) for the reaction can be calculated using the equilibrium concentrations of the reactants and products.

K = [SO₃]²/([SO₂]²[O₂])

K = (3.50)²/[(1.50)²(1.25)]

K = 4.48

Therefore, the equilibrium constant (K) for the reaction is 4.48.

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Answer:

Problem 1:

The osmotic pressure, π, can be calculated using the formula:

π = iMRT

where i represents the van't Hoff factor (the number of particles into which a solute dissociates), M represents the molar concentration, R represents the gas constant (0.082 Latm/molK), and T is the temperature in Kelvin.

The osmotic pressure of pure water is 0. As a result, sea water's osmotic pressure must be equal to the pressure necessary to prevent osmosis.

Assuming that sea water is an ideal solution, the total dissolved ion concentration is 1.13 mol/L. Because each dissolved salt molecule dissociates into two ions, the effective particle concentration is 2.26 mol/L.

Filling in the blanks in the formula:

0.918 atm = (2)(2.26 mol/L)(0.082 Latm/molK)(298 K)

Therefore, a pressure of 0.918 atm must be applied to prevent osmotic flow of pure water into sea water.

Problem 2: Glucose has a molar mass of 180.16 g/mol. The solution contains the following number of moles of glucose:

n = 6.65 g / 180.16 g/mol = 0.0369 mol

The molarity of the solution is:

M = n / V = 0.0369 mol / 0.350 L = 0.105 M

Substituting the values into the formula:

π = iMRT = (1)(0.105 M)(0.082 L·atm/mol·K)(308 K) = 2.74 atm

As a result, the osmotic pressure of the solution is 2.74 atm.

Problem 3:

Following the same procedure as in Problem 2, the molarity of the solution is:

M = n / V = 0.02 mol / 0.450 L = 0.044 M

Substituting the values into the formula:

π = iMRT = (1)(0.044 M)(0.082 L·atm/mol·K)(308 K) = 1.14 atm

As a result, the osmotic pressure of the solution is 1.14 atm.

Problem 4:

The molar mass of propanol is 60.10 g/mol. The number of moles of propanol in the solution is:

n = 11.0 g / 60.10 g/mol = 0.183 mol

The molarity of the solution is:

M = n / V = 0.183 mol / 0.850 L = 0.215 M

Substituting the values into the formula:

π = iMRT = (1)(0.215 M)(0.082 L·atm/mol·K)(298 K) = 4.59 atm

Therefore, the osmotic pressure of the solution is 4.59 atm.

Problem 5:

Following the same procedure as in Problem 2, the molarity of the solution is:

M = n / V = 65 g / (180.16 g/mol × 35 L) = 0.104 M

Substituting the values into the formula:

π = iMRT = (1)(0.104 M)(0.082 L·atm/mol·K)(288 K) = 2.06 atm

Therefore, the osmotic pressure of the solution is 2.06 atm.

0.01 mol/L is the molarity of given solution. 0.002 moles is added to 0.2 L solvent to make desired solution.

The amount of moles of solute found in a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Solutes are simply substances that can be found in solutions because a solution is defined as a homogenous mixture that comprises one or more solutes.

molar mass =342g /mol

number of moles=mass of solute / molar mass

0.45 /342 =0.002 moles

Volume solution =  50 mL / 1000 =0.2 L

M = n / V

M = 0.002 / 0.2

M = 0.01 mol/L

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