6. Name each polyhedron that can be contructed using the following nets: a. b. A Squares c. Regular hexagon and isosceles triangles Square and equilateral triangle

Rewriting the quadratic function [tex]\[ f(x)=(x-8)^{2}+7 \][/tex], we obtain as a result, vertex: [tex](8,7)[/tex].

To rewrite the quadratic function in standard form, we need to complete the square. The standard form of a quadratic function is [tex]\[ f(x)=a(x-h)^{2}+k \][/tex] where [tex](h,k)[/tex] is the vertex of the parabola.

Step 1: Separate the constant term from the rest of the equation.
[tex]\[ f(x)=x^{2}-16 x+71 \\\[ f(x)=(x^{2}-16 x)+71 \][/tex]

Step 2: Complete the square by adding and subtracting the square of half the coefficient of the x term inside the parenthesis.
[tex]\[ f(x)=(x^{2}-16 x+64)+71-64 \\\[ f(x)=(x-8)^{2}+7 \][/tex]

Now the equation is in standard form. The vertex of the parabola is (8,7).

Answer: [tex]\[ f(x)=(x-8)^{2}+7 \][/tex], vertex: [tex](8,7)[/tex].

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The required graph represents that the solution to the given inequality x - 8 ≥ -3 is x ≥ 5.

A linear inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

To solve for x:

x - 8 ≥ -3

x ≥ -3 + 8

x ≥ 5

So, the solution is x ≥ 5.

For the graph of the solution, draw a number line and mark a closed circle at 5 since the inequality includes 5. Then, shade to the right of 5 to represent all values of x that satisfy the inequality.

Thus, the required graph represents that the solution to the given inequality is x ≥ 5.

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The inequality of the expression is x + 175 < 1000

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

x + 175 < 1000

Subtract 175 from bith sides

x < 825

Hence, the solution is x < 825

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Option A is correct, Clearly, r needs to be recalculated.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

The correlation coefficient, r, measures the strength and direction of the linear relationship between two variables.

The value of r always falls between -1 and 1, where a negative value indicates a negative correlation (i.e., as one variable increases, the other tends to decrease), and a positive value indicates a positive correlation (i.e., as one variable increases, the other tends to increase).

However, the value of r cannot be less than -1 or greater than 1.

Therefore, a correlation coefficient of -1.91 is not a valid value.

Hence, Option A is correct, Clearly, r needs to be recalculated.

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Even though 2 is not a zero of the polynomial, p(k) = p(2) = 0.

No, 2 is not a zero of the polynomial p(x)=3x^(4)-14x^(3)-9x^(2)+64x-28. To determine p(k), we simply need to plug in the value of k into the polynomial and simplify.

So, p(k) = p(2) = 3(2)^(4) - 14(2)^(3) - 9(2)^(2) + 64(2) - 28

= 3(16) - 14(8) - 9(4) + 128 - 28

= 48 - 112 - 36 + 128 - 28

= 0

Therefore, p(k) = p(2) = 0.

So, even though 2 is not a zero of the polynomial, p(k) = p(2) = 0.

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Answer:

The angles are adjacent and the value of x is 63

Step-by-step explanation:

The point (2, –2) with x-coordinate value 2 and y-coordinate value -2, is not satisfied the equation y = x.

We have an equation, y = x --(1) and point (2,-2). We have to check that point (2, –2) satisfy the equation y = x or not. To check that, we need to put the values of the point in the equation. If the equation satisfies them, the point belong to the line. Substituting the coordinates of the given point, i.e., x = 2 and y = -2, into the defining equation(1), we get, y = x

L.H.S, y = -2

R.H.S, x = 2

but -2 ≠ 2 so, L.H.S ≠ R.H.S

We now see from the above substitution and the resultant calculation that the coordinates (x, y) of the point (2, -2) does not make the equation y = x

Hence, the point ( 2,-2) does not satisfied equation y= x .

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The point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)) so the answer is (C) (5.54, 9).

What is the rate?

In mathematics, the rate is a measure of the change in one quantity with respect to another quantity. It is typically expressed as a ratio between the two quantities.

To find the point of maximum growth rate, we need to find the maximum value of the derivative of the function f(x).

First, we need to find the derivative of f(x):

[tex]f'(x) = (20 * 27e^{(-3x)}) / (1 + 9e^{(-3x)})^2[/tex]

To find the maximum value of f'(x), we set f''(x) = 0, where f''(x) is the second derivative of f(x):

[tex]f''(x) = (20 * 81e^{(-6x)} * (81e^{(-6x)} - 18e^{(-3x)} + 1)) / (1 + 9e^{(-3x)})^3[/tex]

Solving f''(x) = 0, we get:

[tex]81e^{(-6x)} - 18e^{(-3x)} + 1 = 0[/tex]

Letting [tex]y = e^{(-3x)}[/tex], we can rewrite the equation as:

81y² - 18y + 1 = 0

Using the quadratic formula, we get:

y = (18 ± √(18² - 4 * 81)) / (2 * 81) = 0.069 or 0.012

So,  [tex]y = e^{(-3x)}[/tex] = 0.069 or 0.012

Solving for x, we get:

x = ln(0.069) / (-3) ≈ 1.76 or x = ln(0.012) / (-3) ≈ 5.54

Therefore, the point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)).

Now we need to calculate f'(1.76) and f'(5.54) to find the answer.

[tex]f'(1.76) = (20 * 27e^{(-5.28)}) / (1 + 9e^{(-5.28)})^2 = 9.62[/tex]

[tex]f'(5.54) = (20 * 27e^{(-16.62)}) / (1 + 9e^{(-16.62)})^2 = 1.01[/tex]

Rounding these values to the nearest hundredth, we get:

(1.76, 9.62) and (5.54, 1.01)

Therefore, the point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)) so the answer is (C) (5.54, 9).

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Both models assume that the tax expenditures are $5000 on January 1st, 2000.

The accountant is using two different models to estimate the tax expenditures for the small business. Both models assume that the tax expenditures are $5000 on January 1st, 2000. The accountant wants to estimate the tax expenditures, e, in thousands of dollars t years after January 1st, 2000.

Let's call the two models Model 1 and Model 2. Model 1 assumes that the tax expenditures increase by a fixed amount every year. Let's call this fixed amount a. Therefore, the tax expenditures, e, under Model 1 can be represented by the equation:

e = 5000 + at

Model 2 assumes that the tax expenditures increase at a constant percentage rate every year. Let's call this percentage rate r. Therefore, the tax expenditures, e, under Model 2 can be represented by the equation:

e = 5000(1 + r)ˣ

Now, let's substitute t = 0 into both equations to find the value of e on January 1st, 2000.

For Model 1:

e = 5000 + a(0) = 5000

For Model 2:

e = 5000(1 + r)⁰ = 5000

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Suppose 2022 balls are randomly distributed into 100 boxes. Let X be the total number of balls in the first 20 boxes.  P(X = 90) ≈ 0.  VarX = 323.52.

a) To find P(X = 90), we can use the binomial probability formula:

P(X = k) = C(n,k) * p^k * (1-p)^(n-k)

where C(n,k) = n! / (k! * (n-k)!)

In this case, n = 2022, k = 90, p = 20/100 = 0.2

P(X = 90) = C(2022,90) * 0.2^90 * 0.8^(2022-90)

P(X = 90) = 1.19 * 10^(-37)

Therefore, P(X = 90) ≈ 0.


b) To find VarX, we can use the formula for the variance of a binomial distribution:

VarX = n * p * (1-p)

In this case, n = 2022, p = 0.2

VarX = 2022 * 0.2 * 0.8

VarX = 323.52

Therefore, VarX = 323.52.

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Answer:

Step-by-step explanation:

If x represents one day of sales and x=12, then we can substitute that value into the equation to find the total number of pencils sold:

y = 160x

y = 160(12)

y = 1920

So the supply store sold a total of 1920 pencils on the day when x=12.

Taking the given functions, we will obtain the following inverse functions

To find the inverse of each function, we need to switch the x and y values and solve for y. This will give us the inverse function.

1) [tex]y = log5 (4x + 1)[/tex]
Switch x and y:
[tex]x = log5 (4y + 1)[/tex]
Solve for y:
[tex]5^x = 4y + 1\\4y = 5^x - 1\\y = (5^x - 1)/4[/tex]
Inverse function:

2) [tex]y = log3 (2^x + 8)[/tex]
Switch x and y:
[tex]x = log3 (2^y + 8)[/tex]
Solve for y:
[tex]3^x = 2^y + 8\\2^y = 3^x - 8\\y = log2 (3^x - 8)[/tex]
Inverse function: [tex]f^-1(x) = log2 (3^x - 8)[/tex]

3) [tex]y = log4 (-2x + 9)[/tex]
Switch x and y:
[tex]x = log4 (-2y + 9)[/tex]
Solve for y:
[tex]4^x = -2y + 9\\-2y = 4^x - 9\\y = (9 - 4^x)/2[/tex]
Inverse function: [tex]f^-1(x) = (9 - 4^x)/2[/tex]

4) [tex]y = 5^x + 9/2[/tex]
Switch x and y:
[tex]x = 5^y + 9/2[/tex]
Solve for y:
[tex]5^y = x - 9/2\\y = log5 (x - 9/2)[/tex]
Inverse function: [tex]f^-1(x) = log5 (x - 9/2)[/tex]

5) [tex]y = 10^x + 3/ -3[/tex]
Switch x and y:
[tex]x = 10^y + 3/ -3[/tex]
Solve for y:
[tex]10^y = x - 3/ -3\\y = log10 (x - 3/ -3)[/tex]
Inverse function: [tex]f^-1(x) = log10 (x - 3/ -3)[/tex]

6) [tex]y = log5 (-4x + 10)[/tex]
Switch x and y:
[tex]x = log5 (-4y + 10)[/tex]
Solve for y:
[tex]5^x = -4y + 10-4y = 5^x - 10y = (10 - 5^x)/4[/tex]
Inverse function: [tex]f^-1(x) = (10 - 5^x)/4[/tex]

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Chase's likely error is that he added instead of subtracting when finding his location on the number line.

What is the fractions?

A fraction is a way of representing a part of a whole or a ratio between two numbers. It consists of a numerator (top number) and a denominator (bottom number), separated by a line.

If Ellie's house is at 1 1/2 on the number line, and Chase lives 1 1/5 blocks west of Ellie, then the coordinate of Chase's house would be:

1 1/2 - 1 1/5 = 3/2 - 6/5

To subtract these fractions, we need a common denominator, which is 10:

(3/2) * (5/5) - (6/5) * (2/2) = 15/10 - 12/10 = 3/10

So Chase's house is located 3/10 blocks west of Ellie's house on the number line. Therefore, the correct coordinate for Chase's house is:

1 1/2 - 3/10 = 1 2/5

Chase's likely error is that he added instead of subtracting when finding his location on the number line.

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The correct way to name the figure shown is PQ. This figure consists of two perpendicular lines, P and Q, which intersect at a point. The lines are labeled P and Q, so the correct name for the figure is PQ.

Perpendicular lines are those two lines that intersect each other at a 90 degree angle. These lines are also known as orthogonal lines. When two lines intersect at a 90 degree angle, they are said to be perpendicular.

The figure is a basic geometric shape and is used to illustrate the concept of perpendicular lines. In the figure shown, the angle formed by the intersection of the two lines is a right angle, so the lines are perpendicular.

The figure can also be used to illustrate the concept of a transversal. A transversal is a line that intersects two other lines at different points. In the figure, the line PQ is a transversal intersecting the two lines P and Q.

In conclusion, the correct way to name the figure shown is PQ. This figure is used to illustrate the concepts of perpendicular lines, line segments, and transversals.

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As a result, the balance in the account at the end of seven years is, to the closest cent, $116177.20.

The term "amount" in mathematics typically denotes a sum, total, or quantity. It could be a numerical value or some other kind of measurement. Depending on the context, the word "amount" may also be used to refer to quantity, total, sum, volume, or magnitude. \

The term "amount" is used in algebra and calculus to describe the outcome of an operation, such as the amount of change in a function or the quantity of a variable needed to satisfy an equation. In many disciplines, including finance, science, and engineering, the word "amount" is frequently used to refer to quantities or measurements.

given

The amount of money in the account after 7 years can be calculated using the formula V = Pe(rt), where V is the value of a account in t years, P is the principal implementation, e is the base of a natural log, and r is the rate of interest:

V = P*e(rt) = 67700*e(0.077*7)

[tex]V = 67700 * e^{(0.539) (0.539)[/tex]

V = 67700 * 1.716

V = 116177.20

As a result, the balance in the account at the end of seven years is, to the closest cent, $116177.20.

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The slopes are equal, and the equation is showing a proportional relationship.

The slope of a line is a measure of its steepness.

Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).

Proportional relationships are relationships between two variables where their ratios are equivalent.

1) Given that, Δ PQR and  Δ STU are similar triangles, we need to show that they have equal slope,

Line PR is passing by points (-6, 4) and (-8, 7) and the line SU is passing by points (-4, 1) and (0, -5)

Slope = y₂-y₁ / x₂-x₁

Finding the slopes :-

Line PR = 7-4 / -8+6 = -3/2

Line SU = -5-1 / 4 = -6/4 = -3/2

Therefore, we get the slopes equal.

2) Given is an equation, y = 3x/4

The proportionality equation is given by :- y = kx, where k is the proportionality constant,

The given equation is following the proportionality equation, therefore is showing a proportional relationship.

Hence, the slopes are equal, and the equation is showing a proportional relationship.

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Answer: If the ratio is 1:200,000 then the length of the road in centimeters is 800,000 centimeters meaning the conversion of this to kilometers would be 8 kilometers

Step-by-step explanation: every 100k (100,000) cm in kilometers would be 1 kilometer so take that and for the 200,000 times 4 is 800,000 which means the answer is 8 kilometers

________________________________________________________

Answer:

Your answer is Point T

Step-by-step explanation:

Answer:

s

Step-by-step explanation:

a. since it provides the lowest regret value should the demand be high.

b. Expected Monetary Value for Gradual Introduction= $2.8 million. Expected Monetary Value for Concentrated Introduction= $1.5 million
c. EVPI = $1.3 million

a. For the pessimistic approach, the recommended decision is to use the gradual introduction of the salad dressings, since it provides the least amount of loss should demand be low. For the minimax regret approach, the recommended decision is also the gradual introduction of the salad dressings, since it provides the lowest regret value should the demand be high.

b. Using the expected monetary value approach, the optimal decision would be to use the gradual introduction of the salad dressings. This is because the expected monetary value for a gradual introduction is $2.8 million, which is higher than the expected monetary value of $1.5 million for a concentrated introduction.

Expected Monetary Value for Gradual Introduction: 0.7 * $1 million + 0.3 * $4 million = $2.8 million
Expected Monetary Value for Concentrated Introduction: 0.7 * -$5 million + 0.3 * $10 million = $1.5 million

c. The EVPI (Expected Value of Perfect Information) for this problem is $1.3 million, which is calculated by subtracting the expected monetary value from the best case outcome.

Best case outcome: $10 million
Expected Monetary Value: $2.8 million
EVPI: $10 million - $2.8 million = $1.3 million

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Answer:

12

Step-by-step explanation:

12 × 3= 36

36 + 4= 40

so the answer is 12

Answer:

Not true with all numbers!

Step-by-step explanation:

see.Ex.3x3=9+4=13 not 40

Using two-point form, the equation of the line passing through the points A and B is x = 5.

The two-point form of a line is given by:
y - y₁ = [(y₂ - y₁)/(x₂ - x₁)] (x - x₁)
where (x₁, y₁) and (x₂, y₂) are two points on the line.

Given points A(5, 5) and B(5, -5), we can plug in the values into the equation:
y - 5 = [(-5 - 5)/(5 - 5)] (x - 5)

Simplifying the equation gives us:
y - 5 = (-10/0) (x - 5)

Notice that the slope (y₂ - y₁)/(x₂ - x₁) is equal to -10/0(indeterminate). This means that the line is a vertical line passing through x = 5.

The standard form of a line is Ax + By = C. So, the standard form of the equation of the line passing through points A and B is: x = 5.

Therefore, the equation of the line passing through the two points is x = 5.

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The relative frequency of a student being a tenth grader that gets their news from the internet is 0.79.

What is frequency ?

Frequency refers to the number of times that an event or value occurs within a specific period or dataset. It is a measure of how often a particular value or category appears in a set of data. The frequency can be expressed as an absolute count or as a proportion or percentage relative to the total number of observations in the dataset. Frequency is often used in statistical analysis to describe the distribution of data and to calculate various measures of central tendency and variability.

The relative frequency of a student being a tenth grader that gets their news from the internet is given by:

(number of tenth graders who get their news from the internet) / (total number of students)

So, the relative frequency for tenth graders is

34/175 = 0.194

Rounding to the nearest hundredth gives 0.19.

Therefore, the relative frequency of a student being a tenth grader that gets their news from the internet is 0.79.

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The area of the shaded segment of the circle is 5.79 square metre.

The area of a segment is equal to the area of a sector less the triangle-shaped portion.

A=[tex]\frac{1}{2}[/tex](∅-Sin∅)×[tex]r^{2}[/tex]

Every point in the plane of a circle, which is a closed, two-dimensional object, is evenly separated from the centre. All lines that cross the circle join together to produce the line of reflection symmetry. Moreover, every angle has rotational symmetry around the centre.

r=8m

∅=60°

Applying the formula's values, we obtain

A=[tex]\frac{1}{2}[/tex](∅-Sin∅)×[tex]r^{2}[/tex]

A=[tex]\frac{1}{2}[/tex]([tex]\frac{π}{3}[/tex]-Sin60°)×[tex]8^{2}[/tex]

A=5.79

Hence,  the area of the shaded segment of the circle is 5.79 square metre.

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Answer: The Answer is 4

Step-by-step explanation:

1) find the same base of the x² y² n just do the addition normally like this

(7x²y²+4x²y²)-3xy-8xy

so you'll end getting

the final answer

Answer:

12.15 m

Step-by-step explanation:

90 × 13.5 cm × (1 m)/(100 cm) = 12.15 m

Answer: 12.15 m (rounded 12.2)

Step-by-step explanation:

100 cm = 1 m

13.5(90) = 1,215

1215 divided by 100 = 12.15

1808.64  is the area formed by the water pattern if it can spray out 24 feet in any​ direction.

The circle is a rounded shape without any edges or line segments. It has the geometric shape of a closed curve. The distance between the circle's points and its center is fixed. r2 is the area that a circle with radius r encloses. Here, the Greek letter stands for the constant proportion of a circle's circumference to its diameter,

Here, we have

Given: water sprinkler sends water out in a circular pattern. It can spray out 24 feet in any​ direction.

Since the water is being sent out in a circular pattern, the maximum distance at which the water is reaching out will be equal to the radius of the circle as the sprinkler is at the center of the circle.

The area of a circle is given as:

Area = πr²

Radius = 24 feet

Area = 3.14(24)²

Area = 1808.64

Hence, 1808.64  is the area formed by the water pattern if it can spray out 24 feet in any​ direction.

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Answer:

1808.64  is the area formed by the water pattern if it can spray out 24 feet in any​ direction.

What is an area of a circle?

The circle is a rounded shape without any edges or line segments. It has the geometric shape of a closed curve. The distance between the circle's points and its center is fixed. r2 is the area that a circle with radius r encloses. Here, the Greek letter stands for the constant proportion of a circle's circumference to its diameter,

Here, we have

Given: water sprinkler sends water out in a circular pattern. It can spray out 24 feet in any​ direction.

Since the water is being sent out in a circular pattern, the maximum distance at which the water is reaching out will be equal to the radius of the circle as the sprinkler is at the center of the circle.

The area of a circle is given as:

Area = πr²

Radius = 24 feet

Area = 3.14(24)²

Area = 1808.64

Hence, 1808.64  is the area formed by the water pattern if it can spray out 24 feet in any​ direction.

x → -∞, f(x) → 0

x → ∞, f(x) → ∞

As x approaches negative infinity, the value of the exponent 2^x+1 will become very large negative number, approaching zero. Therefore, the function f(x) will approach 5 times zero, which is equal to 0. Thus, we can say:

As x → -∞, f(x) → 0.

As x approaches positive infinity, the value of the exponent 2^x+1 will become very large positive number, approaching infinity. Therefore, the function f(x) will approach 5 times infinity, which is equal to infinity. Thus, we can say:

As x → ∞, f(x) → ∞.

So, the long run behavior of the function f(x)=5(2)^x+1 is that it approaches 0 as x approaches negative infinity and approaches infinity as x approaches positive infinity.

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Answer:

4 number x value is 10 in

5 number x value is 12mi

use formula of h2=p2+b2

The coordinate of P is ( 14/5, 23/5, 28/5)

For the line AB, the direction vectors are

l= 2-1= 1, m=3-1= 2 and n= 4-2= 2

so, the equation of the line AB can be given by

[tex]  \text{$\frac{x-1}{1}$ = $\frac{y-1}{2}$ = $\frac{z-2}{2}$ } [/tex]

let a point be P (x,y,z). lying on the line AB.

coordinate of the general point in AB can be given by

[tex]  \text{$\frac{x-1}{1}$ = $\frac{y-1}{2}$ = $\frac{z-2}{2}$ = t } [/tex]

so, x= t+1, y= 2t+1, z= 2t+2

so, P (x,y,z) can be P (t+1, 2t+1, 2t+2). Another point is C ( 4, 2, 2 ).

the direction ratios of the line CP is

l1= t+1-4 = t-3

m1= 2t+1-2 = 2t-1

n1 = 2t+2-2 = 2t

Dot product of the direction ratios of two orthogonal lines are 0.

so, 1(t-3)+2(2t-1)+2(2t)=0

or, t=9/5

so, x= (9/5)+1 = 14/5

     y= (9/5)*2 + 1= 23/5

     z= (9/5)*2 + 2 = 28/5

so, the coordinate of P is ( 14/5, 23/5, 28/5).

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Answer:

C.

Step-by-step explanation:

Yearly compounding.
y = 2000(1.04)^t

Monthly compounding.

y = 2000(1 + r/12)^(12t)

2000(1.04)^t = 2000(1 + r/12)^(12t)

(1.04)^t = (1 + r/12)^(12t)

(1.04^t)^(1/t) = [(1 + r/12)^(12t)]^(1/t)

1.04 = (1 + r/12)^12

1.04^(1/12) = [(1 + r/12)^12]^(1/12)

1.00327374 = 1 + r/12

y = 2000(1.00327374)^(12t)

Answer: C.