6. How fast is each train traveling (km/h)? Round to the nearest whole number. a) Train A travels 520.4 km in 4.8 h b) Train B travels 72.1 km in 0.8 h​

Answers

Answer 1

Answer: a) To find the speed of Train A, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 520.4 km / 4.8 h

Speed ≈ 108.42 km/h

Rounding to the nearest whole number, we get:

Train A is traveling at 108 km/h (approximately).

b) To find the speed of Train B, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 72.1 km / 0.8 h

Speed ≈ 90.13 km/h

Rounding to the nearest whole number, we get:

Train B is traveling at 90 km/h (approximately).

Step-by-step explanation:


Related Questions

840x - x2 A company's revenue for selling x (thousand) items is given by R(x) = x2 +840 Find the value of x that maximizes the revenue and find the maximum revenue. X= maximum revenue is $ 2

Answers

The value of x that maximizes revenue is x 28.99 and maximum revenue is $1680 (thousand).

The revenue function for a company that sells x (thousand) items is R(x) = x² + 840. To find the value of x that maximizes revenue, we need to differentiate the revenue function, set it equal to zero and solve for x. The maximum revenue can then be calculated by substituting the value of x into the revenue function.

Revenue function: R(x) = x² + 840

To find the value of x that maximizes revenue, we differentiate the revenue function with respect to x:

dR/dx = 2x

Setting this equal to zero, we get:

2x = 0

x = 0

However, this value does not make sense in the context of the problem, as the company cannot sell 0 items. Therefore, we need to consider the critical points of the function, which occur when dR/dx = 0 or is undefined.

dR/dx = 0 when 2x = 0, so x = 0 is a critical point.

dR/dx is undefined when x = ±√840, so these are also critical points.

We can use the second derivative test to determine which critical point corresponds to a maximum. The second derivative of the revenue function is:

d²R/dx² = 2

At x = 0, d²R/dx² = 2 > 0, so this critical point corresponds to a minimum.

At x = ±√840, d²R/dx² = 2 > 0, so these critical points correspond to a minimum.

Therefore, the value of x that maximizes revenue is x = √840 ≈ 28.99 (thousand items).

To find the maximum revenue, we substitute x = √840 into the revenue function:

R(√840) = (√840)² + 840 = 1680

So the maximum revenue is $1680 (thousand).

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A bookstore conducted a survey to see how many books their customers bought in a year. 100 customers were chosen at random. 30% of customers bought 3 books per year, 25% of customers bought 5 books per year, and 45% of customers bought 6 books per year. What was the average number of books bought per year?



Question 1 options:



4. 50




5. 75




4. 85

Answers

The average number of books bought per year by customers in the survey is approximately 4.85 books.

To find the average number of books bought per year, we need to calculate the mean of the data set. We can do this by using the formula:

Average = (Sum of all data points) / (Number of data points)

However, we do not have the actual number of data points. Instead, we have percentages. Therefore, we need to convert the percentages into actual numbers.

Out of 100 customers surveyed:

30% bought 3 books, which is equal to 30/100 x 100 = 30 customers

25% bought 5 books, which is equal to 25/100 x 100 = 25 customers

45% bought 6 books, which is equal to 45/100 x 100 = 45 customers

Now, we can calculate the average number of books bought per year using the formula mentioned earlier:

Average = (30 x 3) + (25 x 5) + (45 x 6) / (30 + 25 + 45)

Simplifying the above equation, we get:

Average = (90 + 125 + 270) / 100

Therefore, the average number of books bought per year is:

Average = 485/100

Average = 4.85 books per year (rounded to two decimal places)

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Si al triple de la edad que tengo, se quita mi edad aumentada en 8 años, tendría 36 años. ¿Qué edad tengo?

Answers

damePor lo tanto, la edad que tienes es de aproximante 14.67 años.

Si al triple de la edad que tengo, se quita mi edad aumentada en 8 años, tendría 36 años. ¿

Podemos plantear este problema como una ecuación algebraica. Si llamamos "x" a la edad que tienes, la ecuación sería:

3x - 8 = 36

Ahora, despejamos la variable "x" para encontrar su valor:

3x = 36 + 8

3x = 44

x = 44/3

.Este resultado nos indica que nuestra edad actual es de aproximadamente 14.67 años. Es importante tener en cuenta que la solución no es un número entero, lo cual puede parecer inusual para una edad, pero es una respuesta matemáticamente correcta según la ecuación planteada en el problema.

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A car with a mass of 1200 kg and traveling 40 m/s east runs into the back of a parked truck with a mass of 2000 kg. After the collision the car and truck do not stick together, but the car is stopped. If momentum is conserved, what would the velocity of the truck be after the collision?

Answers

The velocity of the truck after the collision would be 24 m/s east.

The law of conservation of momentum states that the momentum of a closed system remains constant if no external forces act on it. In this case, we can assume that the car and the truck form a closed system.

The momentum of an object is given by its mass multiplied by its velocity, p = mv. Initially, the momentum of the system is:

p_initial = m_car * v_car + m_truck * v_truck

where m_car and v_car are the mass and velocity of the car, and m_truck and v_truck are the mass and velocity of the truck.

After the collision, the car is stopped, so its velocity is 0. The momentum of the system after the collision is:

p_final = m_car * 0 + m_truck * v'_truck

where v'_truck is the velocity of the truck after the collision.

Since momentum is conserved, we can set p_initial equal to p_final:

m_car * v_car + m_truck * v_truck = m_truck * v'_truck

Solving for v'_truck, we get:

v'_truck = (m_car * v_car + m_truck * v_truck) / m_truck

Substituting the given values, we have:

v'_truck = (1200 kg * 40 m/s + 2000 kg * 0 m/s) / 2000 kg

v'_truck = 24 m/s east

Therefore, the velocity of the truck after the collision would be 24 m/s east.

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Find the directional derivative of f(x, y, z) = 23 – x²y at the point (3,-1, -2) in the direction of the vector v=(-1,-4,-4).

Answers

The directional derivative of f(x, y, z) = z³ – x²y at the point (3,-1, -2) in the direction of the vector v=(-1,-4,-4) is -234/√33.

The function is f(x, y, z) = z³ – x²y

We have to find directional derivative at the point (3, -1, -2)

In the direction vector v = (-1, -4, -4)

The gradient of the function is

∇f(x, y, z) = ∂f/∂x [tex]\hat{i}[/tex] + ∂f/∂y [tex]\hat{j}[/tex] + ∂f/∂z [tex]\hat{k}[/tex]

∇f(x, y, z) = ∂/∂x(z³ – x²y) [tex]\hat{i}[/tex] + ∂/∂y(z³ – x²y) [tex]\hat{j}[/tex] + ∂/∂z(z³ – x²y) [tex]\hat{k}[/tex]

∇f(x, y, z) = -2xy[tex]\hat{i}[/tex] - x²y[tex]\hat{j}[/tex] + 3z²[tex]\hat{k}[/tex]

At the point (3, -1, 4).

∇f(3, -1, 4) = -2(3)(-1)[tex]\hat{i}[/tex] - (3)²(-1)[tex]\hat{j}[/tex] + 3(4)²[tex]\hat{k}[/tex]

∇f(3, -1, 4) = 6[tex]\hat{i}[/tex] + 9[tex]\hat{j}[/tex] + 48[tex]\hat{k}[/tex]

The length of the vector is

|v| = √[(-1)² + (-4)² + (-4)²]

|v| = √[1 + 16 + 16]

|v| = √33

To normalize the vector we have

n = (-√33/33, -4√33/33, -4√33/33)

The directional derivative is

∇f(x, y, z) · n = (6, 9, 48) · (-√33/33, -4√33/33, -4√33/33)

∇f(x, y, z) · n = -6√33/33 - 36√33/33 - 192√33/33

∇f(x, y, z) · n = (-6 - 36 - 192)√33/33

∇f(x, y, z) · n = -234√33/33

∇f(x, y, z) · n = -234/√33

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the perimeter of an isosceles triangle is 12x^2-5x +4 cm find the length of one of its equal sides

Answers

Answer:

4x² - x + 2

--------------------------

Let the equal sides be both marked as ?

Use the perimeter formula to determine one of the equal sides.

P = 2(?) + x(4x - 3)

Substitute the expression for the perimeter and find the value of ?

12x² - 5x + 4 = 2(?) + x(4x - 3)12x² - 5x + 4 = 2(?) + 4x² - 3x2(?) = 12x² - 5x + 4 - 4x² + 3x2(?) = 8x² - 2x + 4? = 4x² - x + 2

Hence the length of each of equal sides is 4x² - x + 2.

This magic grid contains number sequences that increase in steps. What is the missing number? A 16 B 8 C 4 D 12 E 20​

Answers

Answer:

12

Step-by-step explanation:

The numbers increase by 4 on each row.

Adcb is a rectangle. ac = 16 and bd = 2x + 4, find the value of x.

Answers

In a rectangle, the diagonals are equal in length. So we can write the equation: AC = BD or 16 = 2x + 4. Solving for x, we get x = 6.

Jaime is cutting shapes out of cardboard to make a piñata. One of the shapes is shown in a
coordinate grid

c. (0,10)
d. (3,2)
e. (9,0)
f. (3,-2)
g (0,-10)
h. (3,-2)
a. (-9,0)

(it’s the shape of a star)

What is the length of side AB? Round your answer to the nearest tenth of a unit.
Show your work.

Answers

The length of side AB is 6.3 units.

How to find the length of side AB

The length of side AB is solved using the distance formula below

AB = √((x₂ - x₁)² + (y₂ - y₁)²

where

(x₁, y₁) = (-9, 0) and

(x₂, y₂) = (-3, 2).

AB = √((-3 - (-9))² + (2 - 0)²)

AB = √(6² + 2²)

AB = √(40)

AB = 2√(10)

AB = 6.3245

AB = 6.3 to the nearest tenth

Therefore, the length of side AB is 6.3 units.

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The following selected transactions relate to investment activities of ornamental insulation corporation during 2021. the company buys debt securities, not intending to profit from short-term differences in price and not necessarily to hold debt securities to maturity, but to have them available for sale in years when circumstances warrant. ornamental’s fiscal year ends on december 31. no investments were held by ornamental on december 31, 2020.
mar. 31 acquired 6% distribution transformers corporation bonds costing $580,000 at face value.
sep. 1 acquired $1,170,000 of american instruments’ 8% bonds at face value.
sep. 30 received semiannual interest payment on the distribution transformers bonds.
oct. 2 sold the distribution transformers bonds for $623,000.
nov. 1 purchased $1,590,000 of m&d corporation 4% bonds at face value.
dec. 31 recorded any necessary adjusting entry(s) relating to the investments.
the market prices of the investments are:
american instruments bonds $1,102,000
m&d corporation bonds $1,670,000
(hint: interest must be accrued.)
required:
2. indicate any amounts that ornamental insulation would report in its 2021 income statement, 2021 statement of comprehensive income, and 12/31/2021 balance sheet as a result of these investments. include totals for net income, comprehensive income, and retained earnings as a result of these investments.
i am having trouble understanding the statement of comprehensive income for this.
i have net income: $102,2000
other comprehensive income:
reclassification adjustment: $43,000
gain on investments: $55,000
so this part equals (12,000)
than it wants me

Answers

Ornamental Insulation Corporation would report a net income of $1,022,000 and comprehensive income of $1,010,000 resulting from these investments in its 2021 financial statements.

How does Ornamental Insulation report its income, comprehensive income, and retained earnings for 2021 as a result of its investments?

Ornamental Insulation Corporation would report the following amounts in its 2021 income statement, statement of comprehensive income, and balance sheet as a result of the investment activities:

Income Statement:

Interest Income from American Instruments Bonds: $93,600 ($1,170,000 × 8%)

Gain on Sale of Distribution Transformers Bonds: $43,000 ($623,000 - $580,000)

Total Net Income: $136,600 ($93,600 + $43,000)

Statement of Comprehensive Income:

Gain on Investments: $55,000 (This represents the gain on the sale of the distribution transformers bonds and is included in the comprehensive income section.)

Balance Sheet (as of December 31, 2021):

Investments:

American Instruments Bonds: $1,102,000 (market value)

M&D Corporation Bonds: $1,670,000 (face value)

Accumulated Other Comprehensive Income: $55,000 (This represents the gain on investments and is included in the comprehensive income section.)

Retained Earnings: Increase of $136,600 (This represents the net income from the income statement.)

In summary, Ornamental Insulation Corporation would report a net income of $136,600, a comprehensive income of $55,000, and an increase in retained earnings of $136,600 as a result of these investments for the fiscal year 2021.

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During a workout, Kelly spent 10½ minutes and burned a total of 504 calories. How many calories did she burn per minute?\

Answers

Answer:

48 calories per (each) minute.

Step-by- Step

=

Help how do I solve for x???

Answers

The value of x that makes line A and B parallel is 13.

What is the value of x?

Two Angles are Supplementary when they add up to 180 degrees.

From the diagram:

Angle 1 = 9x + 24

Angle 2 = 3x

Angle 1 and angle 2 are supplementary as their sum equals 180 degrees making line A and B parallel.

Hence:

Angle 1 + Angle 2 = 180°

Plug in the values

9x + 24 + 3x = 180

Solve for x

Collect like terms

9x + 3x = 180 - 24

12x = 156

Divide both sides by 12

12x/12 = 156/12

x = 56/12

x = 13

Therefore, the value of x is 13.

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The volume of this rectangular prism is 216 cubic inches. What is the value of L?

Answers

After leveling the sand box, the height of the sand box is 1.57 in

What is volume?

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.

The volume of a cuboid is expressed as;

V = l × w × h

V = 30 × 20 × 5

V = 3000 in³

After leveling, the volume decreases by 1680 in³, therefore the new volume of the sand box is

3000-1680 = 1320

Therefore the new height of the sand is calculated as;

1320 = 30 × 28 × h

1320 = 840h

divide both sides by 840

h = 1320/840

h = 1.57 in

therefore the height of the remaining sand is 1.57

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what’s the coefficients of the polynomials?

Answers

Answer:

The numbers preceding a variable

Step-by-step explanation:

The coefficients are the number before the variable.

Finding Coefficients

All variables are multiplied by some coefficient. Sometimes those coefficients are one or another number. Take the variable 5x. The coefficient is 5. Since 5 is the number that comes before the variable, it is the coefficient. Additionally, the variable x has a coefficient of 1 because x is multiplied by 1.

Polynomial Example

Every variable within a polynomial can have a unique variable. For example, 3x⁶+5x³+2x². The first coefficient is 3, then 5, then 2. Coefficients are simply the constants that a variable is multiplied by. It does not matter what the variable is or the exponent.

(a) Find an equation of the tangent plane to the surface at the given point. z = x2 - y2, (5, 4, 9) X-5 (b) Find a set of symmetric equations for the normal line to the surface at the given point. Х y z 10 -8 -1 y - 4 Z - 9 10 -8 -1 Ox - 5 = y - 4 = Z - 9 X + 5 y + 4 Z +9 10 -8 -1 Ox + 5 = y + 4 = 2 + 9 =

Answers

z - 9 = 10(x - 5) - 8(y - 4) this is the equation of the tangent plane at the point (5, 4, 9). (x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1). These are the symmetric equations for the normal line to the surface at the given point.

(a) To find the equation of the tangent plane to the surface z = x^2 - y^2 at the point (5, 4, 9), we first need to find the partial derivatives with respect to x and y:

∂z/∂x = 2x
∂z/∂y = -2y
Now, we evaluate these at the given points (5, 4, 9):
∂z/∂x(5, 4) = 2(5) = 10
∂z/∂y(5, 4) = -2(4) = -8
Using the tangent plane equation:
z - z₀ = ∂z/∂x (x - x₀) + ∂z/∂y (y - y₀)
Plugging in the values:
z - 9 = 10(x - 5) - 8(y - 4)
This is the equation of the tangent plane at the point (5, 4, 9).

(b) The normal vector to the surface at the given point is given by the gradient vector (∂z/∂x, ∂z/∂y, -1) = (10, -8, -1). To find the symmetric equations for the normal line, we use the point-normal form:
(x - x₀)/a = (y - y₀)/b = (z - z₀)/c
Plugging in the point (5, 4, 9) and the normal vector components (10, -8, -1):
(x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1)
These are the symmetric equations for the normal line to the surface at the given point.


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0. 587. Write this value in


scientific notation.

Answers

. 0.587 in scientific notation is 5.87 x 10^-1.

Find out the scientific notation of the given value?

Scientific notation is a way of writing numbers that are very large or very small in a compact and standardized way. In scientific notation, a number is expressed as a coefficient multiplied by 10 raised to some power.

For example, the number 0.587 can be written in scientific notation as 5.87 x 10^-1. The coefficient 5.87 is obtained by moving the decimal point one place to the right, while the negative exponent -1 indicates that the decimal point has been moved one place to the left, to the tenth place.

Scientific notation is commonly used in scientific and engineering fields where very large or very small numbers are often encountered, and it allows for easier calculation and comparison of these values.

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o produto de dois números é 54 seu MMC é 18 Qual o MDC desse número?
Porfavor explique

Answers

Answer:

o MDC de 6 e 9 é 3.

O produto de dois números é 54 e o seu MMC é 18. Precisamos encontrar o MDC desses dois números.

Primeiro, encontramos os dois números cujo produto é 54: 6 e 9.

Então, fatoramos cada número em seus fatores primos: 6 = 2 x 3 e 9 = 3 x 3.

O MDC de 6 e 9 é o produto dos fatores primos comuns, elevados à menor potência. Neste caso, o único fator primo comum é 3, elevado à primeira potência.

Portanto, o MDC de 6 e 9 é 3.

Veronica has a goal of saving $12,000 for a car. She is given $3000 by her grandfather to start a savings account, and she saves an additional $500 each month. Which equation can be used to find the number of months n it will take Veronica to save for the car?

Answers

Answer:

m= month 12k - 3500= 950 she needs to save for 2 in a half months to get her car

Step-by-step explanation:

1 ml =

a

litres


ii)

b

ml = 1 litre


iii) 1 cl =

c

litres


iv)

d

cl = 1 litre


v) 1 cl =

e

ml


vi)

f

cl = 1 ml

Answers

The corresponding measure of the parameters are;

i. 1ml = 0. 001 liter a.

ii. 1000ml = 1 liter b.

iii. 1 cl = 0. 01 liter c.

iv. 10dcl = 1 liter d.

v. 1cl = 100ml e.

v. 0. 01 cl = 1ml f.

How to determine the values

To convert the factors, we need to know the following conversion rates.

We have;

1 milliliter = 0. 001 liter

1 centiliter = 0. 01 liter

1 deciliter = 0. 1 liter

1 cubic centimeter = 1 millimeter

Hence, the sizes are determined by the corresponding factor.

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Complete question:

Convert the following to their equivalent measurement for each letter

i. 1 ml = a liters

ii) b ml = 1 liters

iii) 1 cl = c liters

iv)d cl = 1 liters

v) 1 cl = e ml

vi) f cl = 1 ml

This is math and I need help.

Answers

The inequality that can be used to determine the number of outfits Jason can purchase while staying within his budget is 68.54 o ≤ 274.16.

Solving the inequality gives:

o ≤ 4

How to find the inequality ?

The total cost of items that Jason spends on :

= 217. 34 + 36. 32 + 12. 18

= $ 265. 85

The amount that Jason has left from the $ 540 is:

= 540 - 265. 85

= $ 274. 16

If each outfit costs $ 68. 54 then the inequality that would help stay in budget is:

68.54 o ≤ 274.16

Solving this, gives:

o ≤ 274. 16 / 68.54

o ≤ 4

In conclusion, Jason can purchase up to 4 biking outfits while staying within his budget.

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Complete the description of a real-world situation that might involve three linear equations in three variables.

you are trying to find the ages of three people. you know the sum of all three ages, the sum of the first two ages and blank (the answer choices are twice the third or the third age squared), and the sum of the first and third ages and blank (the answer choices are twice the second or the square root of the second)
* just to be clear there are two blanks and two possible answer choices for each

Answers

A real-world situation that might involve three linear equations in three variables is trying to determine the ages of three siblings.

Let's call them A, B, and C. We know that the sum of all three ages is a certain value, let's say it's 60. We also know the sum of the first two ages is either twice the third age or the third age squared. For example, if the sum of the first two ages is twice the third age, we could write it as A + B = 2C.

Alternatively, if the sum of the first two ages is the third age squared, we could write it as A + B = C^2. Similarly, we know the sum of the first and third ages is either twice the second age or the square root of the second age. So, we could write it as A + C = 2B or A + C = sqrt(B).

We now have three linear equations in three variables that we can use to solve for the ages of the three siblings. By solving the system of equations, we can find out how old each sibling is.

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A maker of homemade candles makes a scatter plot to show data of the diameter of a candle and the total burn time of the candle. A line of best fit of this data is T = 6. 5d + 11. 8, where T is the total burn time, in hours, and d is the diameter of the candle, in inches. Approximately how long is the total burn time of a candle with a diameter of 0. 5 inch?


answers: A. 2 hours B. 5 hours


C. 10 hours D. 15 hours

Answers

Answer:

The given line of best fit is: T = 6.5d + 11.8

We can use this equation to estimate the total burn time for a candle with a diameter of 0.5 inches:

T = 6.5(0.5) + 11.8

T = 3.25 + 11.8

T = 15.05

So, according to the line of best fit, the total burn time of a candle with a diameter of 0.5 inch would be approximately 15.05 hours.

Therefore, the answer is D. 15 hours.

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There are 90 children in year 6 at woodland junior school


they are split into three classes


class


number n class


27


6m


6p


33


6t


30


each child chose football or netball or hockey.


in 6m, 13 children chose hockey.


the rest of the class were split equally between football and netball.


in 6p, 9 children chose netball


twice as many children chose football as chose hockey


in 6t the ratio of children who chose


football to netball to hockey was 1:2:3


complete this table


class


number in class


football


netball


hockey





27


13


6p


33


6t


30

Answers

In Year 6 at Woodland Junior School, there are 90 children split into three classes of 14, 24, and 12 on the basis of there selection of sports. In 6M, 14 not chose hockey, and the rest of the class was split equally between football and netball. In 6P, 24 not chose netball, 16 chose football, and 8 choose hockey  In 6T, the ratio of football to netball to hockey was 1:2:3. The completed table is shown.

To complete the table, we need to distribute the remaining children who did not choose their sport in each class. Here's how we can calculate it

In 6M, the number of children who did not choose hockey is 27 - 13 = 14.

Since the rest of the class was split equally between football and netball, each of these two sports will have 14/2 = 7 children.

In 6P, the number of children who did not choose netball is 33 - 9 = 24.

Since twice as many children chose football as chose hockey, we can write the number of footballers as 2x, and the number of hockey players as x. Then we have 2x + x + 9 = 33, which gives x = 8. Therefore, we have 16 children who chose football, and 8 children who chose hockey. The number of children who did not choose any of these two sports is 33 - 16 - 8 - 9 = 0.

In 6T, the ratio of children who chose football to netball to hockey was 1:2:3. Let's call the number of children who chose netball as 2x, and the number of children who chose hockey as 3x. Then we have x + 2x + 3x = 30, which gives x = 6. Therefore, we have 6 children who chose football, 12 children who chose netball, and 18 children who chose hockey.

Thus, the completed table is shown.

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A bridge is to be built across a small lake from a gazebo to a dock. The bearing from the gazebo to the dock is S 41° W. From a tree 100 meters from the gazebo, the bearings to the gazebo and the dock are S 74° E and S 28° E, respectively (see figure). Find the distance from the gazebo to the dock

Answers

The distance from the gazebo to the dock is approximately 120.45 meters.

The given problem can be solved using the concept of trigonometry.

let the distance from the gazebo to the dock be "d".

According to the question it is known that the bearing from the gazebo to the dock is S 41° W which means that the angle between the line from the gazebo to the dock and due south is 41°.

Hence the angle between the line from the gazebo to the tree and due south is =(74°-41°) =33°

Similarly, the angle between the line from the dock to the tree and due south is = 28°-x =28°-41°= -13°(As it is to the west of south).

Using the trigonometry law of sines we can write,

d/ sin(41°) = 100/ sin(33°)

d=(100/sin(33°))*sin(41°)

d= 120.45 meters

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Which one is it please help thank you.


The students who attend Memorial High School have a wide variety of extra-curricular activities to choose from in the after-school program. Students are 38% likely to join the dance team; 18% likely to participate in the school play; 42% likely to join the yearbook club; and 64% likely to join the marching band. Many students choose to participate in multiple activities. Students have equal probabilities of being freshmen, sophomores, juniors, or seniors. If Event A = sophomore or junior, what is Event A'?

Answers

Event A' has a probability of 50% (25% for freshmen + 25% for seniors).

To determine Event A', we need to first identify what Event A represents. Event A is the probability that a student is a sophomore or junior. Since students have equal probabilities of being freshmen, sophomores, juniors, or seniors, the probability of Event A is 50% (25% for sophomores + 25% for juniors).
Event A' is the complement of Event A, which means it includes the other two grade levels not included in Event A, in this case, freshmen and seniors. Therefore, Event A' is the probability that a student is a freshman or a senior. Since students have equal probabilities of being in each grade level, Event A' also has a probability of 50% (25% for freshmen + 25% for seniors).

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The parabolas y=x^2 and y=-x^2-4x+6 are graphed below. What are they-values of the solutions to this system of equations

Answers

Answer:

y = 2.25

Step-by-step explanation:

The solutions are the points of intersection of the 2 graphs.

i really need help with someone who really understands pythagorean therom please help i will give away brainliest and a lot of points just please help me and can someone please stop reporting this question

Answers

Answer:

Perry would need to place his ladder 6.63 ft away from the base of the basketball hoop in order to reach the hoop.

Hope this helps!

Step-by-step explanation:

The Pythagorean theorem is [tex]a^{2} +b^{2} =c^{2}[/tex].

It is given that c is 12 and b is 10, so that would be:

[tex]c^{2} -b^{2} =a^{2}[/tex]

[tex]12^{2} -10^{2} =a^{2}[/tex]

144 - 100 = [tex]a^{2}[/tex]

44 = [tex]a^{2}[/tex]

a = [tex]\sqrt{44}[/tex]

a = 6.6332...

( c is the length of the ladder, b is the height of the hoop, and a is the distance between the ladder and the basketball hoop )

Which shows 71. 38 in word form? O A seventy-one thirty-eighths O B. Seventy-one and thirty eighths O c. Seventy-one and thirty-eight tenths D. Seventy-one and thirty-eight hundredths E seventy-one and thirty-eight thousands​

Answers

The number 71.38 can be written in word form as "seventy-one and thirty-eight hundredths." The correct answer is option D.

In decimal notation, the number 71.38 can be broken down into its whole number and decimal parts. The whole number part is 71, and the decimal part is 0.38.

In a decimal number, the digits to the right of the decimal point represent fractions of a whole. Each digit to the right of the decimal point has a place value that is a power of 10.

In word form, the decimal part 0.38 is read as "thirty-eight hundredths." Therefore, when combined with the whole number 71, the correct word form is "Seventy-one and thirty-eight hundredths."

Therefore option D is the correct answer.

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A circle of radius 6 is centred at the origin, as shown.
The tangent to the circle at point P crosses the y-axis at (0, -14).
Work out the coordinates of point P.
Give any decimals in your answer to 1 d.p.

Answers

Answer:

P = (5.4, -2.6)

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

As the given circle has a radius of 6 units and is centred at the origin, the equation of the circle is:

[tex]x^2+y^2=36[/tex]

The formula for the equation of the tangent line to a circle with the equation x² +  y² = a² is:

[tex]\boxed{y = mx \pm a \sqrt{1+ m^2}}[/tex]

where:

m is the slope.a is the radius of the circle.

To find the slope of the equation of the tangent line to the circle that passes through the point (0, -14), substitute a = 6, x = 0 and y = -14 into the formula and solve for m:

[tex]\implies -14 = m(0) \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies -14 = \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies \pm\dfrac{14}{6} =\sqrt{1+ m^2}[/tex]

[tex]\implies \left(\pm\dfrac{14}{6}\right)^2 =1+m^2[/tex]

[tex]\implies m^2= \left(\pm\dfrac{14}{6}\right)^2-1[/tex]

[tex]\implies m^2=\dfrac{40}{9}[/tex]

[tex]\implies \sqrt{m^2}= \sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\dfrac{2\sqrt{10}}{3}[/tex]

The slope-intercept form of a straight line is y = mx + b, where m is the slope and b is the y-intercept.

As the slope of the given tangent line is positive, and the y-intercept is (0, -14), the equation of the tangent line is:

[tex]\boxed{y=\dfrac{2\sqrt{10}}{3}x-14}[/tex]

As point P is the point of intersection of the circle and the tangent line, substitute the tangent line into the equation of the circle and solve for x:

[tex]x^2+\left(\dfrac{2\sqrt{10}}{3}x-14\right)^2=36[/tex]

Expand the brackets:

[tex]x^2 +\dfrac{40}{9}x^2-\dfrac{56\sqrt{10}}{3}x+196=36[/tex]

Subtract 36 from both sides of the equation:

[tex]\dfrac{49}{9}x^2-\dfrac{56\sqrt{10}}{3}x+160=0[/tex]

Multiply both sides of the equation by 9:

[tex]49x^2-168\sqrt{10}x+1440=0[/tex]

Rewrite the equation in the form a² - 2ab + b²:

[tex](7x)^2-2 \cdot 7 \cdot 12\sqrt{10}x+(12\sqrt{10})^2=0[/tex]

Apply the Perfect Square formula: a² - 2ab + b² = (a - b)²

[tex](7x-12\sqrt{10})^2=0[/tex]

Solve for x:

[tex]7x-12\sqrt{10}=0[/tex]

[tex]7x=12\sqrt{10}[/tex]

[tex]x=\dfrac{12\sqrt{10}}{7}[/tex]

To find the y-coordinate of point P, substitute the found value of x into the equation of the tangent line:

[tex]y=\dfrac{2\sqrt{10}}{3}\left(\dfrac{12\sqrt{10}}{7}\right)-14[/tex]

[tex]y=\dfrac{2\sqrt{10}\cdot 12\sqrt{10}}{3\cdot 7}\right)-14[/tex]

[tex]y=\dfrac{240}{21}-14[/tex]

[tex]y=\dfrac{80}{7}-\dfrac{98}{7}[/tex]

[tex]y=-\dfrac{18}{7}[/tex]

Therefore, the exact coordinates of point P are:

[tex]\left(\dfrac{12\sqrt{10}}{7}, -\dfrac{18}{7}\right)[/tex]

The coordinates of point P to 1 decimal place are:

[tex](5.4, -2.6)[/tex]

Several scientists decided to travel to South America each year beginning in 2001 and record the number of insect species they encountered on each trip. The table shows the values coding 2001 as 1, 2002 as 2, and so on. Find the model that best fits the data and identify its corresponding R2 value

Answers

The best-fitting model for the data and its corresponding R2 value need to be calculated.

How to model data?

To find the model that best fits the data and its corresponding R2 value, we would need to perform linear regression analysis on the data. However, since the data table is not provided, we cannot provide an answer to this question.

Linear regression analysis is a statistical method used to model the relationship between two variables. In this case, the variables are the year and the number of insect species encountered on each trip. By analyzing the data, we can determine the equation of the line that best fits the data and the R2 value, which represents the proportion of the variance in the data that is accounted for by the model. A higher R2 value indicates a better fit between the model and the data.

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